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  • Add objects to Arraylist inside loop and get a list of them outside loops

    - by AgusDG
    Im already done with a method to do a shot on a board (bidimensional array). THe shot goes from the bottom to the top, and depending of the direction, it do bounces on the walls to get to the top. The thing is that I did the method to represent the trayectory with an 'x'. Now, I want to add the coordinates x and y of each position of the shot (b [x][y]) to and Arraylist of Objects Position. public Position(int row,int col) { this.row = row; this.col = col; } The thing is that the method uses a for loop and inside if loops, and I'll need to create the objects inside, and get them outside. I did that : public static ArrayList<Position> showTrayectory (char [][] b , int shotDirection, char bubble){ int row = 0, col = 0; ArrayList<Position> aListPos = new ArrayList<Position>(); Position positionsOfShot = new Position(row,col); START = ((RIGHT_WALL)/2) + shotDirection; boolean shotRight = false; if(shotDirection < 0) shotRight = false; else if(shotDirection > 0) shotRight = true; for(int y = BOTTOM,x = START ;y >= 0;y--) { if(!isOut(y,x) && !emptyCell(y,x)) break; if(x <= LEFT_WALL) shotRight = true; if(x >= RIGHT_WALL) shotRight = false; if(!isOut(y,x) && shotRight == true) { positionsOfShot = new Position(y,x); aListPos.add(positionsOfShot); b[y][x] = SHOT; ++x; } if(!isOut(y,x) && shotRight == false){ positionsOfShot = new Position(y,x); aListPos.add(positionsOfShot); b[y][x] = SHOT; --x; } } // The nested for loops below are for showing the positions // But I dont need it that way // I must get the trayectory from an ArrayList and print it from there for(int y=0;y < b.length;y++){ System.out.println(); for(int x=0;x < b[y].length;x++){ System.out.print(" "+b [y][x]+" "); } } System.out.println("\nTrayectory of the shot ["+shotDirection+"]"); System.out.println("Next bubble ["+bubble+"]"); for( Position ii : aListPos){ System.out.println("(" + positionsOfShot.getFila() + "," + positionsOfShot.getColumna()+")"); } return aListPos; } The sentence " b[y][x] = SHOT; " is still there, to see the proper trayectory of the shot (its not needed that way), but what I need, is getting the trayectory in an ArrayList, and print the trayectory from there. All that I get is a wrong position, and repeated during the number of positions the shot goes through. I need some help. I suppose the problem is that Im creating and adding Position Objects inside an ArrayList inside loops, but in a wrong way. I will need you to explain me how to do it properly ; ) Thanks in advance. I'll add the output for you see better what is that above haha *************************** y b y b g r b g o y g a a r y o y y r b y g r r o b o y y g b a r y r o a y y o o r r g r - - - x - - - - - - - - - x - - - - - - - - - x - - - - - - - - - x - - - - - - - - - x - - - - - - - - - x - - - - - - - x - - - - - - - x - - - - - - - x - - - Trayectory of the shot [1] Next bubble [y] (5,3) (5,3) (5,3) (5,3) (5,3) (5,3) (5,3) (5,3) (5,3) Action?

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  • Need to write at beginning of file with PHP

    - by Timothy
    I'm making this program and I'm trying to find out how to write data to the beginning of a file rather than the end. "a"/append only writes to the end, how can I make it write to the beginning? Because "r+" does it but overwrites the previous data. $datab = fopen('database.txt', "r+"); Here is my whole file: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Facebook v0.1</title> <style type="text/css"> #bod{ margin:0 auto; width:800px; border:solid 2px black; } </style> </head> <body> <div id="bod"> <?php $fname = $_REQUEST['fname']; $lname = $_REQUEST['lname']; $comment = $_REQUEST['comment']; $datab = $_REQUEST['datab']; $gfile = $_REQUEST['gfile']; print <<<form <table border="2" style="margin:0 auto;"> <td> <form method="post" action=""> First Name : <input type ="text" name="fname" value=""> <br> Last Name : <input type ="text" name="lname" value=""> <br> Comment : <input type ="text" name="comment" value=""> <br> <input type ="submit" value="Submit"> </form> </td> </table> form; if((!empty($fname)) && (!empty($lname)) && (!empty($comment))){ $form = <<<come <table border='2' width='300px' style="margin:0 auto;"> <tr> <td> <span style="color:blue; font-weight:bold;"> $fname $lname : </span> $comment </td> </tr> </table> come; $datab = fopen('database.txt', "r+"); fputs($datab, $form); fclose($datab); }else if((empty($fname)) && (empty($lname)) && (empty($comment))){ print" please input data"; } // end table $datab = fopen('database.txt', "r"); while (!feof($datab)){ $gfile = fgets($datab); print "$gfile"; }// end of while ?> </div> </body> </html>

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  • Losing data after reading them correct from file

    - by user1388172
    i have the fallowing class of object with a class a data structure which i use in main combined. The ADT(abstract data type) is a linked list. After i read from file the input data and create and object which at print looks just fine after a print. after i push_back() the 3-rd int variable get initializated to 0. So example and code: Example: ex.in: 1 7 31 2 2 2 3 3 3 now i create objects from each line, which at print look as they suppose, but after push_back(): 1 7 0 2 2 0 3 3 0 Class.h: class RAngle { private: int x,y,l,b; public: int solution,prec; RAngle(){ x = y = solution = prec = b = l =0; } RAngle(int i,int j,int k){ x = i; y = j; l = k; solution = 0; prec=0; b=0; } friend ostream& operator << (ostream& out, const RAngle& ra){ out << ra.x << " " << ra.y << " " << ra.l <<endl; return out; } friend istream& operator >>( istream& is, RAngle& ra){ is >> ra.x; is >> ra.y; is >> ra.l; return is ; } }; ADT.h: template <class T> class List { private: struct Elem { T data; Elem* next; }; Elem* first; T pop_front(){ if (first!=NULL) { T aux = first->data; first = first->next; return aux; } T a; return a; } void push_back(T data){ Elem *n = new Elem; n->data = data; n->next = NULL; if (first == NULL) { first = n; return ; } Elem *current; for(current=first;current->next != NULL;current=current->next); current->next = n; } Main.cpp(after i call this function in main which prints object as they suppose to be the x var(from RAngle class) changes to 0 in all cases.) void readData(List <RAngle> &l){ RAngle r; ifstream f_in; f_in.open("ex.in",ios::in); for(int i=0;i<10;++i){ f_in >> r; cout << r; l.push_back(r); }

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  • how to read data from file into array? java

    - by lox
    I need some help reading data from a txt file into my ArrayList. I know the code is pretty messy, but just try to take a look at it. The first part with the creating and putting the ArrayList into the txt file works perfectly. I just need some help at the end in the "marked" area. Sorry if I still have some words in my native language, but I didn't really had the time to translate everything. public class ContAngajat { String username; String password; } public class CreazaCont { // creating the arraylist and putting it into a file public static void ang(String args[]) { ArrayList<ContAngajat> angajati=new ArrayList<ContAngajat>(50); Scanner diskScanner = new Scanner(in); Scanner forn = new Scanner(in); int n; out.print("Introduceti numarul de conturi noi care doriti sa le introduceti: "); n=forn.nextInt(); out.println(); try{ FileWriter fw = new FileWriter("ConturiAngajati.txt", true); for(int i=0; i<n; i++){ ContAngajat cont = new ContAngajat(); out.print("Username: "); cont.username=diskScanner.nextLine(); out.print("Password: "); cont.password=diskScanner.nextLine(); angajati.add(cont); fw.write(cont.username + " "); fw.write(cont.password +"|"); } fw.close(); } catch(IOException ex){ System.out.println("Could not write to file"); System.exit(0); } for (int i=0; i<n; i++) { out.println("username: " + angajati.get(i).username + " password: " +angajati.get(i).password ); } } // HERE I'M TRING TO GET THE ARRAYLIST OUT OF THE FILE public static void RdAng(String args[]) { ArrayList<ContAngajat> angajati=new ArrayList<ContAngajat>(50); ContAngajat cont = new ContAngajat(); int count,i2,i; try{ FileReader fr = new FileReader("ConturiAngajati.txt"); BufferedReader br = new BufferedReader(fr); String line = ""; while((line=br.readLine())!=null) { String[] theline=line.split("|"); count=theline.length; for(i=0;i<theline.length;i++) { String[] theword = theline[i].split(" "); } } for(i2=0;i2<count;i2++) { ContAngajat contrd = new ContAngajat(); // "ERROR" OVER HERE for (int ird=0; ird <theword.length; ird++) { cont.username=theword[0]; cont.password=theword[1]; // they keep telling me "theword cannot be resolved" whenever i try to run this } angajati.add(contrd); } } catch(IOException ex){ System.out.println("Could not read to file"); System.exit(0); } } }

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  • Exit code 3 (not my return value, looking for source)

    - by Kathoz
    Greetings, my program exits with the code 3. No error messages, no exceptions, and the exit is not initiated by my code. The problem occurs when I am trying to read extremely long integer values from a text file (the text file is present and correctly opened, with successful prior reading). I am using very large amounts of memory (in fact, I think that this might be the cause, as I am nearly sure I go over the 2GB per process memory limit). I am also using the GMP (or, rather, MPIR) library to multiply bignums. I am fairly sure that this is not a file I/O problem as I got the same error code on a previous program version that was fully in-memory. System: MS Visual Studio 2008 MS Windows Vista Home Premium x86 MPIR 2.1.0 rc2 4GB RAM Where might this error code originate from? EDIT: this is the procedure that exits with the code void condenseBinSplitFile(const char *sourceFilename, int partCount){ //condense results file into final P and Q std::string tempFilename; std::string inputFilename(sourceFilename); std::string outputFilename(BIN_SPLIT_FILENAME_DATA2); mpz_class *P = new mpz_class(0); mpz_class *Q = new mpz_class(0); mpz_class *PP = new mpz_class(0); mpz_class *QQ = new mpz_class(0); FILE *sourceFile; FILE *resultFile; fpos_t oldPos; int swapCount = 0; while (partCount > 1){ std::cout << partCount << std::endl; sourceFile = fopen(inputFilename.c_str(), "r"); resultFile = fopen(outputFilename.c_str(), "w"); for (int i=0; i<partCount/2; i++){ //Multiplication order: //Get Q, skip P //Get QQ, mul Q and QQ, print Q, delete Q //Jump back to P, get P //Mul P and QQ, delete QQ //Skip QQ, get PP //Mul P and PP, delete P and PP //Get Q, skip P mpz_inp_str(Q->get_mpz_t(), sourceFile, CALC_BASE); fgetpos(sourceFile, &oldPos); skipLine(sourceFile); skipLine(sourceFile); //Get QQ, mul Q and QQ, print Q, delete Q mpz_inp_str(QQ->get_mpz_t(), sourceFile, CALC_BASE); (*Q) *= (*QQ); mpz_out_str(resultFile, CALC_BASE, Q->get_mpz_t()); fputc('\n', resultFile); (*Q) = 0; //Jump back to P, get P fsetpos(sourceFile, &oldPos); mpz_inp_str(P->get_mpz_t(), sourceFile, CALC_BASE); //Mul P and QQ, delete QQ (*P) *= (*QQ); (*QQ) = 0; //Skip QQ, get PP skipLine(sourceFile); skipLine(sourceFile); mpz_inp_str(PP->get_mpz_t(), sourceFile, CALC_BASE); //Mul P and PP, delete PP, print P, delete P (*P) += (*PP); (*PP) = 0; mpz_out_str(resultFile, CALC_BASE, P->get_mpz_t()); fputc('\n', resultFile); (*P) = 0; } partCount /= 2; fclose(sourceFile); fclose(resultFile); //swap filenames tempFilename = inputFilename; inputFilename = outputFilename; outputFilename = tempFilename; swapCount++; } delete P; delete Q; delete PP; delete QQ; remove(BIN_SPLIT_FILENAME_RESULTS); if (swapCount%2 == 0) rename(sourceFilename, BIN_SPLIT_FILENAME_RESULTS); else rename(BIN_SPLIT_FILENAME_DATA2, BIN_SPLIT_FILENAME_RESULTS); }

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  • Java: How to check the random letters from a-z, out of 10 letters minimum 2 letter should be a vowel

    - by kalandar
    I am writing a program to validate the following scenarios: Scenario 1: I am using the Random class from java.util. The random class will generate 10 letters from a-z and within 10 letter, minimum 2 letters must be a vowels. Scenario 2: When the player 1 and player 2 form a word from A-Z, he will score some points. There will be a score for each letter. I have already assigned the values for A-Z. At the end of the game, the system should display a scores for player 1 and player 2. How do i do it? Please help. I will post my code here. Thanks a lot. =========================================== import java.util.Random; import java.util.Scanner; public class FindYourWords { public static void main(String[] args) { Random rand = new Random(); Scanner userInput = new Scanner(System.in); //==================Player object=============================================== Player playerOne = new Player(); playerOne.wordScore = 0; playerOne.choice = "blah"; playerOne.turn = true; Player playerTwo = new Player(); playerTwo.wordScore = 0; playerTwo.choice = "blah"; playerTwo.turn = false; //================== Alphabet ================================================== String[] newChars = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z" }; //values of the 26 alphabets to be used int [] letterScore = {1,3,3,2,1,4,2,4,1,8,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10}; // to assign score to the player1 and player 2 String[] vowel = { "a", "e", "i", "o", "u" }; // values for vowels int vow=0; System.out.println("FINDYOURWORDS\n"); int[] arrayRandom = new int[10]; //int array for word limiter String[] randomLetter = new String[10]; //storing the letters in newChars into this array //=============================================================================== boolean cont = true; while (cont) { if (playerOne.turn) { System.out.print("Letters of Player 1: "); } else if (!playerOne.turn) { System.out.print("Letters of Player 2: "); } for (int i = 0; i < arrayRandom.length; i++) { //running through the array limiter int r = rand.nextInt(newChars.length); //assigning random nums to the array of letters randomLetter[i] = newChars[r]; System.out.print(randomLetter[i]+ " "); } //input section for player System.out.println(""); System.out.println("Enter your word (or '@' to pass or '!' to quit): "); if (playerOne.turn) { playerOne.choice = userInput.next(); System.out.println(playerOne.turn); playerOne.turn = false; } else if (!playerOne.turn){ playerTwo.choice = userInput.next(); System.out.println(playerOne.turn); playerOne.turn = true; } //System.out.println(choice); String[] wordList = FileUtil.readDictFromFile("words.txt"); //Still dunno what this is for if (playerOne.choice.equals("@")) { playerOne.turn = false; } else if (playerTwo.choice.equals("@")) { playerOne.turn = true; } else if (playerOne.choice.equals("!")) { cont = false; } for (int i = 0; i < wordList.length; i++) { //System.out.println(wordList[i]); if (playerOne.choice.equalsIgnoreCase(wordList[i]) || playerTwo.choice.equalsIgnoreCase(wordList[i])){ } } } }}

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  • Create File Speedily From Individual Column

    - by neversaint
    I have a data that looks like this: -1 1:-0.394668 2:-0.794872 3:-1 4:-0.871341 5:0.9365 6:0.75597 1 1:-0.463641 2:-0.897436 3:-1 4:-0.871341 5:0.44378 6:0.121824 1 1:-0.469432 2:-0.897436 3:-1 4:-0.871341 5:0.32668 6:0.302529 -1 1:-0.241547 2:-0.538462 3:-1 4:-0.871341 5:0.9994 6:0.987166 1 1:-0.757233 2:-0.948718 3:-1 4:-0.871341 5:-0.33904 6:0.915401 1 1:-0.167147 2:-0.589744 3:-1 4:-0.871341 5:0.95078 6:0.991566 The first column is class, and next 6 columns are features. I want to create 6 files for individual features. For example feat1_file.txt will contain -1 1:-0.394668 1 1:-0.463641 ... 1 1:-0.757233 1 1:-0.167147 feat2_file.txt will contain -1 2:-0.794872 ... 1 2:-0.589744 and so on. I have a Perl code that does this but it is horribly slow. Is there a way to do it faster? Typically the input files will contain 100K lines. use strict; use Data::Dumper; use Carp; my $input = $ARGV[0] || "myinput.txt"; my $INFILE_file_name = $input; # input file name open ( INFILE, '<', $INFILE_file_name ) or croak "$0 : failed to open input file $INFILE_file_name : $!\n"; my $out1 = $input."_feat_1.txt"; my $out2 = $input."_feat_2.txt"; my $out3 = $input."_feat_3.txt"; my $out4 = $input."_feat_4.txt"; my $out5 = $input."_feat_5.txt"; my $out6 = $input."_feat_6.txt"; unlink($out1); unlink($out2); unlink($out3); unlink($out4); unlink($out5); unlink($out6); print "$out1\n"; while ( <INFILE> ) { chomp; my @els = split(/\s+/,$_); my $lbl = $els[0]; my $OUTFILE1_file_name = $out1; # output file name open ( OUTFILE1, '>>', $OUTFILE1_file_name ) or croak "$0 : failed to open output file $OUTFILE1_file_name : $!\n"; print OUTFILE1 "$lbl $els[1]\n"; close ( OUTFILE1 ); # close output file my $OUTFILE2_file_name = $out2; # output file name open ( OUTFILE2, '>>', $OUTFILE2_file_name ) or croak "$0 : failed to open output file $OUTFILE2_file_name : $!\n"; print OUTFILE2 "$lbl $els[2]\n"; close ( OUTFILE2 ); # close output file # Etc.. until OUTFILE 6 } close (INFILE);

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  • Bash Shell Scripting Errors: ./myDemo: 56: Syntax error: Unterminated quoted string [EDITED]

    - by ???
    Could someone take a look at this code and find out what's wrong with it? #!/bin/sh while : do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls $PWD ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ "$directory = "q" -o "Q" ] then exit 0 fi while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Re-enter the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 fi done printf ls "$directory" ;; b|B) echo "Please specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi while [ ! -f "$file" ] do echo "Usage: \"$file\" must be an ordinary file." echo "Re-enter the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 fi done cp "$file" "$file.bkup" ;; q|Q) exit 0 ;; esac echo done exit 0 There are some syntax errors that I can't figure out. However I should note that on this unix system echo -e doesn't work (don't ask me why I don't know and I don't have any sort of permissions to change it and even if I wouldn't be allowed to) Bash Shell Scripting Error: "./myDemo ./myDemo: line 62: syntax error near unexpected token done' ./myDemo: line 62: " [Edited] EDIT: I fixed the while statement error, however now when I run the script some things still aren't working correctly. It seems that in the b|B) switch statement cp $file $file.bkup doesn't actually copy the file to file.bkup ? In the a|A) switch statement ls "$directory" doesn't print the directory listing for the user to see ? #!/bin/bash while $TRUE do echo " Select one of the following options:" echo " d or D) Display today's date and time" echo " l or L) List the contents of the present working directory" echo " w or W) See who is logged in" echo " p or P) Print the present working directory" echo " a or A) List the contents of a specified directory" echo " b or B) Create a backup copy of an ordinary file" echo " q or Q) Quit this program" echo " Enter your option and hit <Enter>: \c" read option case "$option" in d|D) date ;; l|L) ls pwd ;; w|w) who ;; p|P) pwd ;; a|A) echo "Please specify the directory and hit <Enter>: \c" read directory if [ ! -d "$directory" ] then while [ ! -d "$directory" ] do echo "Usage: "$directory" must be a directory." echo "Specify the directory and hit <Enter>: \c" read directory if [ "$directory" = "q" -o "Q" ] then exit 0 elif [ -d "$directory" ] then ls "$directory" else continue fi done fi ;; b|B) echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ ! -f "$file" ] then while [ ! -f "$file" ] do echo "Usage: "$file" must be an ordinary file." echo "Specify the ordinary file for backup and hit <Enter>: \c" read file if [ "$file" = "q" -o "Q" ] then exit 0 elif [ -f "$file" ] then cp $file $file.bkup fi done fi ;; q|Q) exit 0 ;; esac echo done exit 0 Another thing... is there an editor that I can use to auto-parse code? I.e something similar to NetBeans?

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  • C/PHP: How do I convert the following PHP JSON API script into a C plugin for apache?

    - by TeddyB
    I have a JSON API that I need to provide super fast access to my data through. The JSON API makes a simply query against the database based on the GET parameters provided. I've already optimized my database, so please don't recommend that as an answer. I'm using PHP-APC, which helps PHP by saving the bytecode, BUT - for a JSON API that is being called literally dozens of times per second (as indicated by my logs), I need to reduce the massive RAM consumption PHP is consuming ... as well as rewrite my JSON API in a language that execute much faster than PHP. My code is below. As you can see, is fairly straight forward. <?php define(ALLOWED_HTTP_REFERER, 'example.com'); if ( stristr($_SERVER['HTTP_REFERER'], ALLOWED_HTTP_REFERER) ) { try { $conn_str = DB . ':host=' . DB_HOST . ';dbname=' . DB_NAME; $dbh = new PDO($conn_str, DB_USERNAME, DB_PASSWORD); $params = array(); $sql = 'SELECT homes.home_id, address, city, state, zip FROM homes WHERE homes.display_status = true AND homes.geolat BETWEEN :geolatLowBound AND :geolatHighBound AND homes.geolng BETWEEN :geolngLowBound AND :geolngHighBound'; $params[':geolatLowBound'] = $_GET['geolatLowBound']; $params[':geolatHighBound'] = $_GET['geolatHighBound']; $params[':geolngLowBound'] =$_GET['geolngLowBound']; $params[':geolngHighBound'] = $_GET['geolngHighBound']; if ( isset($_GET['min_price']) && isset($_GET['max_price']) ) { $sql = $sql . ' AND homes.price BETWEEN :min_price AND :max_price '; $params[':min_price'] = $_GET['min_price']; $params[':max_price'] = $_GET['max_price']; } if ( isset($_GET['min_beds']) && isset($_GET['max_beds']) ) { $sql = $sql . ' AND homes.num_of_beds BETWEEN :min_beds AND :max_beds '; $params['min_beds'] = $_GET['min_beds']; $params['max_beds'] = $_GET['max_beds']; } if ( isset($_GET['min_sqft']) && isset($_GET['max_sqft']) ) { $sql = $sql . ' AND homes.sqft BETWEEN :min_sqft AND :max_sqft '; $params['min_sqft'] = $_GET['min_sqft']; $params['max_sqft'] = $_GET['max_sqft']; } $stmt = $dbh->prepare($sql); $stmt->execute($params); $result_set = $stmt->fetchAll(PDO::FETCH_ASSOC); /* output a JSON representation of the home listing data retrieved */ ob_start("ob_gzhandler"); // compress the output header('Content-type: text/javascript'); print "{'homes' : "; array_walk_recursive($result_set, "cleanOutputFromXSS"); print json_encode( $result_set ); print '}'; $dbh = null; } catch (PDOException $e) { die('Unable to retreive home listing information'); } } function cleanOutputFromXSS(&$value) { $value = htmlspecialchars($value, ENT_QUOTES, 'UTF-8'); } ?> How would I begin converting this PHP code over to C, since C is both better on memory management (since you do it yourself) and much, much faster to execute?

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  • How to convet a string to pieces with PHP or regex?

    - by shin
    I have different outputs of $slider['image']and two examples are followings. The first one has and at the beginning and at the end. In the second one, all img tag has and tags. <p><img src="../../assets/images/prints/print2_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageA_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageB_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageC_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageD_600x300.gif" alt="" width="600" height="300"></p> or <p><img src="../../assets/images/prints/print2_600x300.gif" alt="" width="600" height="300"></p><p><img src="../../../assets/images/support_images/imageA_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageB_600x300.gif" alt="" width="600" height="300"></p><p><img src="../../../assets/images/support_images/imageC_600x300.gif" alt="" width="600" height="300"></p><p><img src="../../../assets/images/support_images/imageD_600x300.gif" alt="" width="600" height="300"></p> I need to change this to the following. <li><span>Homepage</span><a href="#"><img alt="" src="assets/images/prints/print2_600x300.gif" /></a></li> <li><span>Content Page</span><a href="#"><img alt="" src="assets/images/support_images/imageA_600x300.gif" /></a></li> <li><span>Dropdown Menu</span><a href="#"><img alt="" src="assets/images/support_images/imageB_600x300.gif" /></a></li> <li><span>Comments List</span><a href="#"><img alt="" src="assets/images/support_images/imageC_600x300.gif" /></a></li> <li><span>Comment Form</span><a href="#"><img alt="" src="assets/images/support_images/imageD_600x300.gif" /></a></li> I assume I may need regex and php (explode, str_replace, foreach)for this but I need some help. I appreciate your inputs and help. Thanks in advance. Full out put. [0] =>; Array ( [id] => 12 [name] => Print 2 [shortdesc] => <p>Print 2 short description</p> [longdesc] => <p>Print 2 long description</p> [thumbnail] => <p><img src="../../assets/images/prints/thumbnails/print2_223x112.gif" alt="" width="223" height="112"></p> [image] =&gt; <p><img src="../../assets/images/prints/print2_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageA_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageB_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageC_600x300.gif" alt="" width="600" height="300"><img src="../../../assets/images/support_images/imageD_600x300.gif" alt="" width="600" height="300"></p> [product_order] => 0 [class] => [grouping] => [status] => active [category_id] => 5 [featured] => front [other_feature] => none [price] => 0.00 )

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  • about getadrrinfo() C++?

    - by Isavel
    I'm reading this book called beej's guide to network programming and there's a part in the book were it provide a sample code which illustrate the use of getaddrinfo(); the book state that the code below "will print the IP addresses for whatever host you specify on the command line" - beej's guide to network programming. now I'm curious and want to try it out and run the code, but I guess the code was develop in UNIX environment and I'm using visual studio 2012 windows 7 OS, and most of the headers was not supported so I did a bit of research and find out that I need to include the winsock.h and ws2_32.lib for windows, for it to get working, fortunately everything compiled no errors, but when I run it using the debugger and put in 'www.google.com' as command argument I was disappointed that it did not print any ipaddress, the output that I got from the console is "getaddrinfo: E" what does the letter E mean? Do I need to configure something out of the debugger? Interestingly I left the command argument blank and the output changed to "usage: showip hostname" Any help would be appreciated. #ifdef _WIN32 #endif #include <sys/types.h> #include <winsock2.h> #include <ws2tcpip.h> #include <iostream> using namespace std; #include <stdio.h> #include <string.h> #include <sys/types.h> #include <winsock.h> #pragma comment(lib, "ws2_32.lib") int main(int argc, char *argv[]) { struct addrinfo hints, *res, *p; int status; char ipstr[INET6_ADDRSTRLEN]; if (argc != 2) { fprintf(stderr,"usage: showip hostname\n"); system("PAUSE"); return 1; } memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; // AF_INET or AF_INET6 to force version hints.ai_socktype = SOCK_STREAM; if ((status = getaddrinfo(argv[1], NULL, &hints, &res)) != 0) { fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(status)); system("PAUSE"); return 2; } printf("IP addresses for %s:\n\n", argv[1]); for(p = res;p != NULL; p = p->ai_next) { void *addr; char *ipver; // get the pointer to the address itself, // different fields in IPv4 and IPv6: if (p->ai_family == AF_INET) { // IPv4 struct sockaddr_in *ipv4 = (struct sockaddr_in *)p->ai_addr; addr = &(ipv4->sin_addr); ipver = "IPv4"; } else { // IPv6 struct sockaddr_in6 *ipv6 = (struct sockaddr_in6 *)p->ai_addr; addr = &(ipv6->sin6_addr); ipver = "IPv6"; } // convert the IP to a string and print it: inet_ntop(p->ai_family, addr, ipstr, sizeof ipstr); printf(" %s: %s\n", ipver, ipstr); } freeaddrinfo(res); // free the linked list system("PAUSE"); return 0; }

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  • Doesn't get the output in Java Database Connectivity

    - by Dooree
    I'm working on Java Database Connectivity through Eclipse IDE. I built a database through Ubuntu Terminal, and I need to connect and work with it. However, when I tried to run the following code, I don't get any error, but the following output is showed, anybody knows why I don't get the output from the code ? //STEP 1. Import required packages import java.sql.*; public class FirstExample { // JDBC driver name and database URL static final String JDBC_DRIVER = "com.mysql.jdbc.Driver"; static final String DB_URL = "jdbc:mysql://localhost/EMP"; // Database credentials static final String USER = "username"; static final String PASS = "password"; public static void main(String[] args) { Connection conn = null; Statement stmt = null; try{ //STEP 2: Register JDBC driver Class.forName("com.mysql.jdbc.Driver"); //STEP 3: Open a connection System.out.println("Connecting to database..."); conn = DriverManager.getConnection(DB_URL,USER,PASS); //STEP 4: Execute a query System.out.println("Creating statement..."); stmt = conn.createStatement(); String sql; sql = "SELECT id, first, last, age FROM Employees"; ResultSet rs = stmt.executeQuery(sql); //STEP 5: Extract data from result set while(rs.next()){ //Retrieve by column name int id = rs.getInt("id"); int age = rs.getInt("age"); String first = rs.getString("first"); String last = rs.getString("last"); //Display values System.out.print("ID: " + id); System.out.print(", Age: " + age); System.out.print(", First: " + first); System.out.println(", Last: " + last); } //STEP 6: Clean-up environment rs.close(); stmt.close(); conn.close(); }catch(SQLException se){ //Handle errors for JDBC se.printStackTrace(); }catch(Exception e){ //Handle errors for Class.forName e.printStackTrace(); }finally{ //finally block used to close resources try{ if(stmt!=null) stmt.close(); }catch(SQLException se2){ }// nothing we can do try{ if(conn!=null) conn.close(); }catch(SQLException se){ se.printStackTrace(); }//end finally try }//end try System.out.println("Goodbye!"); }//end main }//end FirstExample <ConnectionProperties> <PropertyCategory name="Connection/Authentication"> <Property name="user" required="No" default="" sortOrder="-2147483647" since="all"> The user to connect as </Property> <Property name="password" required="No" default="" sortOrder="-2147483646" since="all"> The password to use when connecting </Property> <Property name="socketFactory" required="No" default="com.mysql.jdbc.StandardSocketFactory" sortOrder="4" since="3.0.3"> The name of the class that the driver should use for creating socket connections to the server. This class must implement the interface 'com.mysql.jdbc.SocketFactory' and have public no-args constructor. </Property> <Property name="connectTimeout" required="No" default="0" sortOrder="9" since="3.0.1"> Timeout for socket connect (in milliseconds), with 0 being no timeout. Only works on JDK-1.4 or newer. Defaults to '0'. </Property> ...

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  • Reversing a number in c++

    - by Marcel Bujnowski
    I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. #include<iostream> #include<iomanip> using namespace std; void printSum(int n, bool reverse); int sm(int n); int reverseInt(int n); void printAddTable(int n); int main() { int reverse; int sum=0; int n; cout<<"Enter N value:"<<endl; cin>>n; if(n>0) { reverse = true; printSum( n, reverse); // calls the printSum Method } else { //cout<<"enter positive Number only:"<<endl; } sum = sm(n); //err // calls the sum Method reverse = reverseInt(n); // calls the reverseInt Method cout<<"The reverse value is:"<<reverse; printAddTable(n); // calls the printAddTable Method //getch() } //end of main() void printSum(int n, bool reverse) { int sum=0; // print sum of reverse numbers for(int i=n; i>=1; i--) { sum=sum+i; cout<<i<< " "<<"+"<<" "; } cout<<sum; } int sm(int n) {int sum =0; for(int i=1; i<=n; i++) { sum = sum + i ; cout << endl; cout<<i<<" "<<"+"<<" "<<endl; // print n positive integers cout << endl; } cout<< "Are " <<n<< " positive integers"<<endl; cout<< "Sum is "<<sum <<endl; return sum; } int reverseInt(int n) { int reminder=0; int sum =0; while(n<=0) { reminder = n/10; sum = (sum * 10) + reminder; // it returns the reverse number n = n % 10; } return sum; } void printAddTable(int n) { for(int i=1; i<=n; i++) { cout<<i<<endl; for(int j=1; j<=n; j++) // print n X n add table { cout<<i+j<<endl; } } } {

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  • TFS 2008 Web Access Report 100 record limitation

    - by HosamKamel
    By default TFS 2008 Web Access has the limit of 100 record when you open any query in report mode. Even if you tried to export the query to excel or PDF you will only get first 100 record exported. To overcome this issue, you have to reconfigure this count in the web.config file Navigate to web access files C:\Program Files\Microsoft Visual Studio 2008 Team System Web Access\Wiwa Open web.config modify maxWorkitemsInReportList count to whatever count you need. You need to do modify the same configuration in web.config located here C:\Program Files\Microsoft Visual Studio 2008 Team System Web Access\Web  A full discussion thread exists here Team Foundation Server - Team System Web Access

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  • Download the ‘Getting Started with Ubuntu 12.10' Manual for Free

    - by Asian Angel
    Today is the official release date for Ubuntu’s latest version, so why not download the manual to go with it? This free manual is available to view online or download as a 145 page PDF file to best suits your needs. The home page for the manual will display a large Download Button, but the best option is to click on the Alternative Download Options link. Clicking on the Alternative Download Options link will let you select the language version you want, choose a system version, and let you download the manual directly or view it online. What To Do If You Get a Virus on Your Computer Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked HTG Explains: What is the Windows Page File and Should You Disable It?

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  • Cloning A Database On The Same Server Using Rman Duplicate From Active Database

    - by alejandro.vargas
    To clone a database using Rman we used to require an existing Rman backup, on 11g we can clone databases using the "from active" database option. In this case we do not require an existing backup, the active datafiles will be used as the source for the clone. In order to clone with the source database open it must be on archivelog mode. Otherwise we can make the clone mounting the source database, as shown in this example. These are the steps required to complete the clone: Configure The Network Create A Password File For The New Database Create An Init.Ora For The New Database Create The Admin Directory For The New Database Shutdown And Startup Mount The Source Database Startup Nomount The New Database Connect To The Target (Source) And Auxiliary (New Clone) Databases Using Rman Execute The Duplicate Command Remove The Old Pfile Check The New Database A step by step example is provided on this file: rman-duplicate-from-active-database.pdf

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  • OBIEE 11.1.1 - OBIEE 11g Full Sample App on VMware Player 4

    - by user809526
    The Full Sample App is designed to run on Virtual Box. Let's describe how to run it on VMware Player 4. Open Virtualization Format Tool http://communities.vmware.com/community/vmtn/server/vsphere/automationtools/ovf VMware Player Documentation https://www.vmware.com/support/pubs/player_pubs.html Full Sample App Deployment Guide sampleapp107-vbimage-deployguide-453583.pdf INSTALL VMplayer 4.0.0 as root LINUX # sh VMware-Player-4.0.0-471780.x86_64.bundle (A new VM is not needed and can be deleted later after that installation is completed. "I will install OS later" - blank hard disk Guest: linux, Red Hat Enterprise Linux 5-64bits => rename to RHEL target: eg /a/root/vmware/ Max disk size: 5 GB (will be deleted) Disk: Single file Dummy RHEL.vmk, RHEL.vmdk is generated. "Delete VM from Disk" in VM Player.) Copy Full Sample App files to target /a/root/vmware/ WARNING: Select a target eg /a/root/vmware/ with lots of free space, 95 GB. Check checksums (md5sum). Please do it! ff85c7eacf7fb8c382e98da875e879e1  Sampleapp_v107_GA-disk1.vmdk 973258cb3c7d64ab03ae853278cf2233  Sampleapp_v107_GA-disk2.vmdk e576be16e36d810479736bfb15d050f5  Sampleapp_v107_GA-disk3.vmdk 3455df77279e53e07d5fee6712f1597d  Sampleapp_v107_GA-disk4.vmdk OVF FILE   Sampleapp_v107_GA.ovf CONVERSION $ cd /a/root/vmware/ LINUX $ /usr/bin/ovftool -tt=ovf --compress=1 -dm=monolithicSparse Sampleapp_v107_GA.ovf .  [dot] Opening OVF source: Sampleapp_v107_GA.ovf Warning: No manifest file Opening OVF target: . Writing OVF package: Sampleapp_v107_GA/Sampleapp_v107_GA.ovf Disk Transfer Completed                   Completed successfully WINDOWS CYGWIN $ /cygdrive/c/VMwarePlayer/OVFTool/ovftool.exe -tt=ovf --compress=1 -dm=monolithicSparse Sampleapp_v107_GA.ovf .  [dot] Opening OVF source: Sampleapp_v107_GA.ovf Warning: No manifest file Opening OVF target: . Writing OVF package: Sampleapp_v107_GA\Sampleapp_v107_GA.ovf Disk Transfer Completed Completed successfully /a/root/vmware$ du -sk 49095328    .   [50 GB already occupied] IMPORT - First start of VM Player 4: /usr/bin/vmplayer "Open a Virtual Machine" Browse to /a/root/vmware/Sampleapp_v107_GA/Sampleapp_v107_GA.ovf [the new generated .ovf] "Import Virtual Machine" dialog Name: Sampleapp_v107_GA Location: /a/root/vmware/Sampleapp_v107_GA/storage [was /home/tdubois/vmware/Sampleapp_v107_GA] "Import" "The import failed because /a/root/vmware/Sampleapp_v107_GA/Sampleapp_v107_GA.ovf did not pass OVF specification conformance or virtual hardware compliance checks. Click Retry to relax OVF specification..." "Retry" ; Long import /a/root/vmware/Sampleapp_v107_GA/storage/Sampleapp_v107_GA.vmx and new .vmdk files are created. /a/root/vmware$ du -sk 95551384    .   [95 GB occupied] Full Sample App GUEST SETUP "Edit VM settings" min 3GB, 2+ processors, network bridged. For OBIEE + Essbase testing use 8 GB RAM hardware. At first time lauch of Full Sample App, leave OEL booting for several minutes undisturbed. Problem with X display server may occur [/usr/bin/Xorg ; man Xorg]. "Failed to start the X server.... Would you like to view the X server output to diagnose the problem?" "No" [tab key] "Would you like to try to configure the X server? Note that you will need the root password for this." "Yes" [oracle] X Display Settings 800x600 saved in /etc/X11/xorg.conf "Trying to restart the X server" Login as root/oracle in guest OEL. In guest OEL, Virtual Machine > Install VMware Tools... Extract archive VMwareTools-8.8.0-471268.tar.gz all files in writable local directory eg /root In Terminal run Perl script # cd /root/vmware-tools-distrib ; ./vmware-install.pl [keep all default answers] Set keyboard layout System > Preferences > Keyboard > Layouts Restart X server eg System > Log Out root... , relogin Modify X resolution System > Preferences > Screen Resolution Full Sample App OEL login: oracle/oracle ; root/oracle [default US keyboard layout] Credentials are described in the 'sampleapp107-vbimage-deployguide-453583.pdf' The large files in /a/root/vmware/ /a/root/vmware/Sampleapp_v107_GA/ may be removed. FAILURE REMARK: Adding the 4 original Sampleapp_v107_GA-disks[1234].vmdk to VM Player does NOT work as described below. "Edit VM settings" "Remove" "Hard Disk" "Edit VM settings" "Add" "Hard Disk" "Next" "Use an existing virtual disk" "Browse" "Finish" "Keep existing format" "Ok" for each 4 disks settings one by one. Start VM Player 4. "You do not have write access to a partition" Allow all Sampleapp_v107 OEL linux launches. OEL stalls silently after 'Checking filesystems'.

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  • EBS + 11g Database Upgrade Best Practices Whitepaper Available

    - by Steven Chan
    I returned from OAUG/Collaborate with a cold and multiple overlapping development crises.  Fun.  Now that those are (mostly) out of the way, it's time to get back to clearing out my article backlog.  Premier Support for the 10gR2 database ends in July 2010.  If you haven't already started planning your 11g database upgrade, we recommend that you start soon.  We have certified both the 11gR1 (11.1.0.7) and 11gR2 (11.2.0.1) databases with Oracle E-Business Suite; see this blog's Certification summary to links to articles with the details.Our Applications Performance Group has reminded me that they have a whitepaper loaded with practical tips intended to make your 11g database upgrade easier.  No vacuous marketing rhetoric here -- this is strictly written for DBAs.  A must-read if you haven't already upgraded to either 11gR1 or 11gR2, and highly recommended even if you have.  You can download this whitepaper here:Upgrade to 11g Performance Best Practices (PDF, 184K)

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  • Daisies and Rye Swaying in the Summer Wind Wallpaper

    - by Asian Angel
    Flowers [DesktopNexus] Latest Features How-To Geek ETC Should You Delete Windows 7 Service Pack Backup Files to Save Space? What Can Super Mario Teach Us About Graphics Technology? Windows 7 Service Pack 1 is Released: But Should You Install It? How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) Reclaim Vertical UI Space by Moving Your Tabs to the Side in Firefox Wind and Water: Puzzle Battles – An Awesome Game for Linux and Windows How Star Wars Changed the World [Infographic] Tabs Visual Manager Adds Thumbnailed Tab Switching to Chrome Daisies and Rye Swaying in the Summer Wind Wallpaper Read On Phone Pushes Data from Your Desktop to the Appropriate Android App

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  • New Whitepaper: Advanced Compression 11gR1 Benchmarks with EBS 12

    - by Steven Chan
    In my opinion, if there's any reason to upgrade an E-Business Suite environment to the 11gR1 or 11gR2 database, it's the Advanced Compression database option.  Oracle Advanced Compression was introduced in Oracle Database 11g, and allows you to compress structured data (numbers, characters) as well as unstructured data (documents, spreadsheets, XML and other files).  It provides enhanced compression for database backups and also includes network compression for faster synchronization with standby databases.In other words, the promise of Advanced Compression is that it can make your E-Business Suite database smaller and faster.  But how well does it actually deliver on that promise?Apps 12 + Advanced Compression Benchmarks now availableThree of my colleagues, Uday Moogala, Lester Gutierrez, and Andy Tremayne, have been benchmarking Oracle E-Business Suite Release 12 with Advanced Compression 11gR1.  They've just released a detailed whitepaper with their benchmarking results and recommendations.This whitepaper is available in two locations:Oracle E-Business Suite Release 12.1 with Oracle Database 11g Advanced Compression (Note 1110648.1) (requires My Oracle Support access)Oracle E-Business Suite Release 12.1 with Oracle Database 11g Advanced Compression (Applications Benchmark website, PDF, 500K)

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  • SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Complete Downloadable List – Day 0 of 31

    - by pinaldave
    This blog post is running list of the blog posts in the series of Interview Questions and Answers. At the end of the 31st day of the month, a FREE PDF will be posted here which can be downloadable for offline review. Please scroll below to see latest post for the day. SQL SERVER – Interview Questions and Answers – Frequently Asked Questions – Introduction – Day 1 of 31 In this very first blog post – various aspect of the interview questions and answers are discussed. Some people like the subject for their helpful hints and thought provoking subject, and others dislike these posts because they feel it is nothing more than cheating.  I’d like to discuss the pros and cons of a Question and Answer format here. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Documentation, SQL Download, SQL Interview Questions and Answers, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Download Free PowerShell Quick Reference Guides from Microsoft

    - by Akemi Iwaya
    Are you just getting started with learning PowerShell or tired of looking up less frequently used commands? Then this terrific set of PowerShell quick reference guides from Microsoft is just what you need! The first guide focuses on commonly-used Windows PowerShell commands and is available in a single .doc format document. The other guides are available as a set (six files) in .pdf format and focus on: tips, shortcuts, and common operations in Windows PowerShell 3.0, Windows PowerShell Workflow, Windows PowerShell ISE, Windows PowerShell Web Access, Server Manager for Windows Server 2012, WinRM, WMI, and WS-Man. Keep in mind that you can select all the guides or just the ones you need to download for the PowerShell 3.0 set. Windows PowerShell Quick Reference [Microsoft] Windows PowerShell 3.0 and Server Manager Quick Reference Guides [Microsoft] [via The Windows Club here and here]     

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  • Microsoft Press Weekend Deal 26/May/2012 - Microsoft® Manual of Style, 4th Edition

    - by TATWORTH
    At http://shop.oreilly.com/product/0790145305770.do?code=MSDEAL, Microsoft Press are offering the Microsoft® Manual of Style, 4th Edition as a PDF for 50% off using the MSDEAL code."Maximize the impact and precision of your message! Now in its fourth edition, the Microsoft Manual of Style provides essential guidance to content creators, journalists, technical writers, editors, and everyone else who writes about computer technology. Direct from the Editorial Style Board at Microsoft—you get a comprehensive glossary of both general technology terms and those specific to Microsoft; clear, concise usage and style guidelines with helpful examples and alternatives; guidance on grammar, tone, and voice; and best practices for writing content for the web, optimizing for accessibility, and communicating to a worldwide audience. Fully updated and optimized for ease of use, the Microsoft Manual of Style is designed to help you communicate clearly, consistently, and accurately about technical topics—across a range of audiences and media." There is a sample chapter for free download at the above link

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  • Microsoft Presss Free E-Book - 12/April/2012 - Introducing Microsoft® SQL Server® 2012

    - by TATWORTH
    At http://shop.oreilly.com/product/0790145342201.do, I have spotted a free e-book "Introducing Microsoft® SQL Server® 2012 ". There is no indication as to how long this will be available for free, so I suggest get it ASAP. It is available in a number of other electronic formats besides PDF."Introducing Microsoft® SQL Server® 2012 explores the exciting enhancements and new capabilities engineered into SQL Server, ranging from improvements in operation to those in reporting and management. This book is for anyone who has an interest in SQL Server 2012 and wants to understand its capabilities, including database administrators, application developers, and technical decision makers."

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  • Website Vulnerabilities

    - by Ben Griswold
    The folks at the Open Web Application Security Project publish a list of the top 10 vulnerabilities. In a recent CodeBrew I provided a quick overview of them all and spent a good amount of time focusing on the most prevalent vulnerability, Cross Site Scripting (XSS).  I gave an overview of XSS, stepped through a quick demo (sorry vulnerable site), reviewed the three XSS variations and talked a bit about how to protect one’s site.  References and reading materials were also included in the presentation and, look at that, they are provided here too. Open Web Application Security Project The OWASP Top Ten Vulnerabilities (pdf) OWASP List of Vulnerabilities The 56 Geeks Project by Scott Johnson ha.ckers.org OWASP XSS Prevention Cheat Sheet Wikipedia Is XSS Solvable?, Don Ankney The Anatomy of Cross Site Scripting, Gavin Zuchlinski

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