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  • Python sort strings started with digits

    - by vlad
    I have the next list: a = ['1th Word', 'Another Word', '10th Word'] print a.sort() >>> ['10th Word', '1th Word', 'Another Word'] But I need: ['1th Word', '10th Word','Another Word'] Is there an easy way to do this? I tried: r = re.compile(r'(\d+)') def sort_by_number(s): m = r.match(s) return m.group(0) x.sort(key=sort_by_number) But some strings do not have numbers and this leads to an errors. Thanks.

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  • Inject Rows into Silverlight DataGrid

    - by Stephan
    Does anyone know of a way to inject rows into a Silverlight DataGrid? I need a way to add totals rows after every 6 entries. The totals are for all rows above the summary row, not just the previous six. I've tried doing it with grouping but that only shows the totals for the group and displays the totals rows above the actual rows. I would prefer to use a DataGrid for this if possible, but all solutions are welcome.

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  • Subversion with Apache and permissions issues

    - by djechelon
    Hello, I have setup an SVN repository for use with Apache 2 via svnadmin create command and appropriate vhost configuration. I found that, in order to correctly use the repository, this must be owned by wwwrun user (or www group) or chmodded to 777. I would like to ask if it's possible to explicitly tell Apache to impersonate another user when serving requests to a certain path (from vhost.conf), like with suphp extension, so I won't mess with permissions once I create a repository. Thank you in advance

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  • how to bind parameters correctly in example below in mysqli?

    - by user1421767
    In old mysql code, I had a query below which worked perfectly which is below: $questioncontent = (isset($_GET['questioncontent'])) ? $_GET['questioncontent'] : ''; $searchquestion = $questioncontent; $terms = explode(" ", $searchquestion); $questionquery = " SELECT q.QuestionId, q.QuestionContent, o.OptionType, an.Answer, r.ReplyType, FROM Answer an INNER JOIN Question q ON q.AnswerId = an.AnswerId JOIN Reply r ON q.ReplyId = r.ReplyId JOIN Option_Table o ON q.OptionId = o.OptionId WHERE "; foreach ($terms as $each) { $i++; if ($i == 1){ $questionquery .= "q.QuestionContent LIKE `%$each%` "; } else { $questionquery .= "OR q.QuestionContent LIKE `%$each%` "; } } $questionquery .= "GROUP BY q.QuestionId, q.SessionId ORDER BY "; $i = 0; foreach ($terms as $each) { $i++; if ($i != 1) $questionquery .= "+"; $questionquery .= "IF(q.QuestionContent LIKE `%$each%` ,1,0)"; } $questionquery .= " DESC "; But since that old mysql is fading away that people are saying to use PDO or mysqli (Can't use PDO because of version of php I have currently got), I tried changing my code to mysqli, but this is giving me problems. In the code below I have left out the bind_params command, my question is that how do I bind the parameters in the query below? It needs to be able to bind multiple $each because the user is able to type in multiple terms, and each $each is classed as a term. Below is current mysqli code on the same query: $questioncontent = (isset($_GET['questioncontent'])) ? $_GET['questioncontent'] : ''; $searchquestion = $questioncontent; $terms = explode(" ", $searchquestion); $questionquery = " SELECT q.QuestionId, q.QuestionContent, o.OptionType, an.Answer, r.ReplyType, FROM Answer an INNER JOIN Question q ON q.AnswerId = an.AnswerId JOIN Reply r ON q.ReplyId = r.ReplyId JOIN Option_Table o ON q.OptionId = o.OptionId WHERE "; foreach ($terms as $each) { $i++; if ($i == 1){ $questionquery .= "q.QuestionContent LIKE ? "; } else { $questionquery .= "OR q.QuestionContent LIKE ? "; } } $questionquery .= "GROUP BY q.QuestionId, q.SessionId ORDER BY "; $i = 0; foreach ($terms as $each) { $i++; if ($i != 1) $questionquery .= "+"; $questionquery .= "IF(q.QuestionContent LIKE ? ,1,0)"; } $questionquery .= " DESC "; $stmt=$mysqli->prepare($questionquery); $stmt->execute(); $stmt->bind_result($dbQuestionId,$dbQuestionContent,$dbOptionType,$dbAnswer,$dbReplyType); $questionnum = $stmt->num_rows();

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  • Can get Sum() working in Northwind example

    - by Vince
    Hi, The following code is generating a runtime error and I have no idea why. from o in Orders group o by o.Employee into employeeOrders select new { employeeOrders.Key.EmployeeID, employeeOrders.Key.FirstName, Orders = from eord in employeeOrders orderby eord.OrderID select new { eord.OrderID, eord.OrderDate, OrderTotal=eord.OrderDetails.Sum (od => od.UnitPrice) } } The error is Member access 'System.Decimal UnitPrice' of 'LINQPad.User.OrderDetails' not legal on type 'LINQPad.User.Orders Thanks in advance

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  • Optimize SELECT DISTINCT CONCAT query in MySQL

    - by L. Cosio
    Hello! I'm running this query: SELECT DISTINCT CONCAT(ALFA_CLAVE, FECHA_NACI) FROM listado GROUP BY ALFA_CLAVE HAVING count(CONCAT(ALFA_CLAVE, FECHA_NACI)) > 1 Is there any way to optimize it? Queries are taking 2-3 hours on a table with 850,000 rows. Adding an index to ALFA_CLAVE and FECHA_NACI would work? Thanks in advanced

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  • What is your reporting tool of choice?

    - by jms
    Every project invariably needs some type of reporting functionality. From a foreach loop in your language of choice to a full blow BI platform. To get the job done what tools, widgets, platforms has the group used with success, frustration and failure?

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  • Equivalent of Oracle’s RowID in MySQL

    - by echo
    is there an equivalent of oracle's rowid in mysql? delete from my_table where rowid not in (select max(rowid) from my_table group by field1,field2) I want to make a mysql equivalent of this query!!! What i'm trying to do is, : The my_table has no primary key.. i'm trying to delete the duplicate values and impose a primary key (composite of field1, field2)..!!

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  • Need help with 2 MySql Queries. Join vs Subqueries.

    - by BugBusterX
    I have 2 tables: user: id, name message: sender_id, receiver_id, message, read_at, created_at There are 2 results I need to retrieve and I'm trying to find the best solution. I have included queries that I'm using in the very end. I need to retrieve a list of users, and also with each user have information available whether there are any unread messages from each user (them as sender, me as receiver) and whether or not there are any read messages between us ( they send I'm receiver or I send they are receivers) I need Same as above, but only those members where there has been any messaging between us, sorted by unread first, then by last message received. Can you advise please? Should this be done with joins or subqueries? In first case I do not need the count, I just need to know whether or not there is at least one unread message. I'm posting code and my current queries, please have a look when you get a chance: BTW, everything is the way I want in fist query. My concern is: In second query I would like to order by messages.created_at, but I dont think I can do that with grouping? And also I dont know if this approach is the most optimized and fast. CREATE TABLE `user` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `user` VALUES (1,'User 1'),(2,'User 2'),(3,'User 3'),(4,'User 4'),(5,'User 5'); CREATE TABLE `message` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `sender_id` bigint(20) DEFAULT NULL, `receiver_id` bigint(20) DEFAULT NULL, `message` text, `read_at` datetime DEFAULT NULL, `created_at` datetime NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `message` VALUES (1,3,1,'Messge',NULL,'2010-10-10 10:10:10'),(2,1,4,'Hey','2010-10-10 10:10:12','2010-10-10 10:10:11'),(3,4,1,'Hello','2010-10-10 10:10:19','2010-10-10 10:10:15'),(4,1,4,'Again','2010-10-10 10:10:25','2010-10-10 10:10:21'),(5,3,1,'Hiii',NULL,'2010-10-10 10:10:21'); SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) GROUP BY u.id SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) where m.id IS NOT NULL GROUP BY u.id

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  • how to fast compute distance between high dimension vectors

    - by chyojn
    assume there are three group of high dimension vectors: {a_1, a_2, ..., a_N}, {b_1, b_2, ... , b_N}, {c_1, c_2, ..., c_N}. each of my vector can be represented as: x = a_i + b_j + c_k, where 1 <=i, j, k <= N. then the vector is encoded as (i, j, k) wich is then can be decoded as x = a_i + b_j + c_k. my question is, if there are two vector: x = (i_1, j_1, k_1), y = (i_2, j_2, k_2), is there a method to compute the euclidian distance of these two vector without decode x and y.

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  • How to track folder permission event?

    - by Sushant
    Hi, This is about folder level permissions. We have a document library with break inheritance. While adding folders, sub folders through code, again we coded for break inheritance. Now the requirement is, when a user/group is added to subfolder permission list, we need to track this event. Which sharepoint event do we use and on what level. Please help.

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  • Selecting from a Large Table SQL 2005

    - by Eugene
    I have a SQL table it has more than 1000000 rows, and I need to select with the query as you can see below: SELECT DISTINCT TOP (200) COUNT(1) AS COUNT, KEYWORD FROM QUERIES WITH(NOLOCK) WHERE KEYWORD LIKE '%Something%' GROUP BY KEYWORD ORDER BY 'COUNT' DESC Could you please tell me how can I optimize it to speed up the execution process? Thank you for useful answers.

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  • T-SQL Subquery Question

    - by Nick
    Hi, i have two queries. For each tuple of query1 i want to run query2. i dont want to use cursors. i tried several approaches using subqueries. query1: select distinct category, Count(category) as CategoryCount from mytable group by category query2: select top 3 Text, Title, Category from mytable where Category = '1' Category = '1' is a sample. the value should come from query1

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  • mysql :ordering table with day names

    - by Meko
    Hi.I am trying to get day of names with and correct order like Monday ,Tuesday.. But in my table I have records that after Monday comes Friday or I have Thursday between two Tuesday .I want to order them like Monday ,Monday ,Tuesday ,Tuesday, Wednesday so on .But I don`t want to group them. I used this query but it does not make order select Day_Name from mydb.schedule where Room_NO=(510) And Week_NO =(1) it outputs Monday Monday Tuesday Wednesday Wednesday Tuesday Thursday Thursday Thursday how can I correct it?

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • Dealing with whitespace in SVN?

    - by Eric the Red
    All of the SVN shops I've worked in have a strict rule - replace all tabs with spaces, to avoid whitespace conflicts and variations of tabs in different editors. Is this a very common standard? Does it really make a huge difference, and is it worth the trouble to push this standard to a group of developers new to SVN?

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  • checkboxes jquery

    - by mazhar
    <% foreach (var i in (IEnumerable)ViewData["Group"]) { % " / <%= i.vcr_GroupName % <% foreach (var ik in (IEnumerable)ViewData["Feature"]) { % " / <%= ik.vcr_FeaturesName % <% } % <% } % I have created this now the thing is that when I click on any parent with parentid=0 .all its child should automatically be clicked with parentid 0 but not viceversa.How would I do it in jquery? (Like i CLICK ON SOME FEATURE Manage User its child Add user ,edit and delete user should be clicked automatically ) but if i click on add user nothing should happened

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  • What is the result of this SQL query?

    - by Martin
    I'm working on a mock exam paper at the moment, however I have no set of correct answers and I'm not sure what the correct answer of this SQL query is. Given a table: foo, bar a , 1 b , 3 a , 2 c , 1 and the query: SELECT foo, sum(bar) FROM table GROUP BY foo The two ways I can see this going are either: a 3 a 3 b 3 c 1 or a 3 b 3 c 1 Thanks.

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  • How to enumerate returned rows in SQL?

    - by SilentGhost
    I was wondering if it would be possible to enumerate returned rows. Not according to any column content but just yielding a sequential integer index. E.g. select ?, count(*) as usercount from users group by age would return something along the lines: 1 12 2 78 3 4 4 42

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  • scope equivalent in rails 2.3.x?

    - by Jacob Relkin
    Is there a way to generate a group of routes under an admin scope without having to create a new physical directory (like namespace requires you to). I know that in Rails 3 there is a scope method on the route mapper, and this appears to do what I want, but apparently it doesn't exist in Rails 2.3.x My goal is to have a route like this: "/admin/products" map to "app/controllers/products_controller, not "app/controllers/admin/products_controller". Is there any way to accomplish this in Rails 2.3.x?

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  • Doubt in stored procedure in asp.net

    - by Surya sasidhar
    hi, i am writing a sotreprocedure displaying month and year it is working but it is not coming in a order descending order can u help me my procedure like below... ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end result will come like this March 2010 January 2010 February 2010 but it is not in a order (desc) can u help me

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  • Magento - How to select mysql rows by max value?

    - by Damodar Bashyal
    mysql> SELECT * FROM `log_customer` WHERE `customer_id` = 224 LIMIT 0, 30; +--------+------------+-------------+---------------------+-----------+----------+ | log_id | visitor_id | customer_id | login_at | logout_at | store_id | +--------+------------+-------------+---------------------+-----------+----------+ | 817 | 50139 | 224 | 2011-03-21 23:56:56 | NULL | 1 | | 830 | 52317 | 224 | 2011-03-27 23:43:54 | NULL | 1 | | 1371 | 136549 | 224 | 2011-11-16 04:33:51 | NULL | 1 | | 1495 | 164024 | 224 | 2012-02-08 01:05:48 | NULL | 1 | | 2130 | 281854 | 224 | 2012-11-13 23:44:13 | NULL | 1 | +--------+------------+-------------+---------------------+-----------+----------+ 5 rows in set (0.00 sec) mysql> SELECT * FROM `customer_entity` WHERE `entity_id` = 224; +-----------+----------------+---------------------------+----------+---------------------+---------------------+ | entity_id | entity_type_id | email | group_id | created_at | updated_at | +-----------+----------------+---------------------------+----------+---------------------+---------------------+ | 224 | 1 | [email protected] | 3 | 2011-03-21 04:59:17 | 2012-11-13 23:46:23 | +-----------+----------------+---------------------------+----------+--------------+----------+-----------------+ 1 row in set (0.00 sec) How can i search for customers who hasn't logged in for last 10 months and their account has not been updated for last 10 months. I tried below but failed. $collection = Mage::getModel('customer/customer')->getCollection(); $collection->getSelect()->joinRight(array('l'=>'log_customer'), "customer_id=entity_id AND MAX(l.login_at) <= '" . date('Y-m-d H:i:s', strtotime('10 months ago')) . "'")->group('e.entity_id'); $collection->addAttributeToSelect('*'); $collection->addFieldToFilter('updated_at', array( 'lt' => date('Y-m-d H:i:s', strtotime('10 months ago')), 'datetime'=>true, )); $collection->addAttributeToFilter('group_id', array( 'neq' => 5, )); Above tables have one customer for reference. I have no idea how to use MAX() on joins. Thanks UPDATE: This seems returning correct data, but I would like to do magento way using resource collection, so i don't need to do load customer again on for loop. $read = Mage::getSingleton('core/resource')->getConnection('core_read'); $sql = "select * from ( select e.*,l.login_at from customer_entity as e left join log_customer as l on l.customer_id=e.entity_id group by e.entity_id order by l.login_at desc ) as l where ( l.login_at <= '".date('Y-m-d H:i:s', strtotime('10 months ago'))."' or ( l.created_at <= '".date('Y-m-d H:i:s', strtotime('10 months ago'))."' and l.login_at is NULL ) ) and group_id != 5"; $result = $read->fetchAll($sql); I have loaded full shell script to github https://github.com/dbashyal/Magento-ecommerce-Shell-Scripts/blob/master/shell/suspendCustomers.php

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