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  • Resource allocation and automatic deallocation

    - by nabulke
    In my application I got many instances of class CDbaOciNotifier. They all share a pointer to only one instance of class OCIEnv. What I like to achieve is that allocation and deallocation of the resource class OCIEnv will be handled automatically inside class CDbaOciNotifier. The desired behaviour is, with the first instance of class CDbaOciNotifier the environment will be created, after that all following notifiers use that same environment. With the destruction of the last notifier, the environment will be destroyed too (call to custom deleter). What I've got so far (using a static factory method to create notifiers): #pragma once #include <string> #include <memory> #include "boost\noncopyable.hpp" class CDbaOciNotifier : private boost::noncopyable { public: virtual ~CDbaOciNotifier(void); static std::auto_ptr<CDbaOciNotifier> createNotifier(const std::string &tnsName, const std::string &user, const std::string &password); private: CDbaOciNotifier(OCIEnv* envhp); // All notifiers share one environment static OCIEnv* m_ENVHP; // Custom deleter static void freeEnvironment(OCIEnv *env); OCIEnv* m_envhp; }; CPP: #include "DbaOciNotifier.h" using namespace std; OCIEnv* CDbaOciNotifier::m_ENVHP = 0; CDbaOciNotifier::~CDbaOciNotifier(void) { } CDbaOciNotifier::CDbaOciNotifier(OCIEnv* envhp) :m_envhp(envhp) { } void CDbaOciNotifier::freeEnvironment(OCIEnv *env) { OCIHandleFree((dvoid *) env, (ub4) OCI_HTYPE_ENV); *env = null; } auto_ptr<CDbaOciNotifier> CDbaOciNotifier::createNotifier(const string &tnsName, const string &user, const string &password) { if(!m_ENVHP) { OCIEnvCreate( (OCIEnv **) &m_ENVHP, OCI_EVENTS|OCI_OBJECT, (dvoid *)0, (dvoid * (*)(dvoid *, size_t)) 0, (dvoid * (*)(dvoid *, dvoid *, size_t))0, (void (*)(dvoid *, dvoid *)) 0, (size_t) 0, (dvoid **) 0 ); } //shared_ptr<OCIEnv> spEnvhp(m_ENVHP, freeEnvironment); ...got so far... return auto_ptr<CDbaOciNotifier>(new CDbaOciNotifier(m_ENVHP)); } I'd like to avoid counting references (notifiers) myself, and use something like shared_ptr. Do you see an easy solution to my problem?

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  • Why is this ajax call being made even though it shouldn't be

    - by user2921557
    i have this validation script im working on but cant see why im having an issue. You can see that i have a check = false / true, check before it runs the ajax call. However, even if a field is empty and check is set to false, it is still running the call. so: // JavaScript - Update Password AJAX $(document).ready(function () { // When the form is submitted $('.updatepasswordform').submit(function () { var check = true; // Get the values var password1 = $("input[name=password1]").val(); var password2 = $("input[name=password2]").val(); var newpassword = $("input[name=newpassword]").val(); /* Password Validation */ // If fields are empty if (password1 === '') { check = false; $("input[name=password1]").css('border', 'solid 2px red'); } // If fields are empty if (password2 === '') { check = false; $("input[name=password2]").css('border', 'solid 2px red'); } // If fields are empty if (newpassword === '') { check = false; $("input[name=newpassword]").css('border', 'solid 2px red'); } if (check = true) { $.ajax({ type: "POST", url: "process/updatepassword.php", data: $(".updatepasswordform").serialize(), dataType: "json", success: function (response) { /* Checks for database validation, removed for space saving */ } }); } return false; }); });

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  • Properly handling NSURLConnection errors

    - by Cal S
    Hi, I have a simple form interface set up that send username and password information to a server: (working) NSString *postData = [NSString stringWithFormat:@"user=%@&pass=%@",[self urlEncodeValue:sysUsername],[self urlEncodeValue:password]]; NSLog(@"Post data -> %@", postData); /// NSData* postVariables = [postData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest* request = [[[NSMutableURLRequest alloc] init] autorelease]; NSString* postLength = [NSString stringWithFormat:@"%d", [postVariables length]]; NSURL* postUrl = [NSURL URLWithString:@"http://localhost/~csmith/cocoa/test.php"]; [request setURL:postUrl]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody: postVariables]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:NULL error:NULL]; NSLog(@"Post data SENT & returned -> %@", returnData); How do I handle connection errors such as no internet connection, firewall, etc. Also, does this method use the system-wide proxy settings? Many of my users are behind a proxy. Thanks a lot!

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  • Rails: Duplicate functionality across controllers? A humble plea.

    - by Alex
    So I'm working with authlogic, and I'm trying to duplicate the login functionality to the welcome page, so that you can log in by restful url or by just going to the main page. No, I don't know if we'll keep that feature, but I want to test it out anyway. Here's the error message: RuntimeError in Welcome#index Called id for nil, which would mistakenly be 4 -- if you really wanted the id of nil, use object_id The code is below. Basically, what's happening is the index view (the first code snippet) is sending the information from the form to the create method of user_sessions controller. At this point, in theory, it create should just pick up, but it doesn't. PLEASE help. Please. I've been doing this for about 8 hours. I checked Google. I checked IRC. I checked every book I could find. You don't even have to answer, I can to the grunt work if you just point me in the right direction. <% form_for @user_session, :url => user_sessions_path do |f| %> <%= f.text_field :email %><br /> <%= f.password_field :password %> <%= submit_tag 'Login' %> <% end %> class ApplicationController < ActionController::Base helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # Scrub sensitive parameters from your log # filter_parameter_logging :password helper_method :current_user_session, :current_user before_filter :new_session_object protected def new_session_object unless current_user @user_session = UserSession.new(params[:user_session]) end end private def current_user_session return @current_user_session if defined?(@current_user_session) @current_user_session = UserSession.find end def current_user return @current_user if defined?(@current_user) @current_user = current_user_session && current_user_session.record end end

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  • Difficulty Inserting from HTML form into MySQL (created in Workbench)

    - by Chaya Cooper
    I created a MySQL database in Workbench 5.2.35 for purposes of storing and using information submitted in html forms but I'm having difficulty inserting records from the html form. The relevant SQL script was saved as Demo2.sql, the schema is C2F, and the table is customer_info. I wasn't sure if that was the problem, so I tried replacing the database name (Demo2) with the schema name, but that didn't work either. My html file includes: form action="insert.php" method="post" The insert.php file states: ?php $con = mysql_connect("localhost","root","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Demo2", $con); $sql="INSERT INTO customer_info(fname, lname, user, password, reminder, answer) VALUES ('$_POST[fname]','$_POST[lname]','$_POST[user]','$_POST[password]','$_POST[reminder]','$_POST[answer]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ? I've also tried INSERT INTO c2f.customer_info(fname, lname, etc. and INSERT INTO 'c2f'.'customer_info'

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • make java plugin use the browser certificates

    - by Shalom938
    We have a java applet that communicates with a spring application running on tomcat and using spring's http invoker. We want to secure the applet using ssl with client authentication, we have a jsp page for login, after successful login the applet loads. The jsp page is secured with ssl, when the applet loads the http invoker inside the applet is doing a second handshake apparently not related to the browser handshake, OK, I don't mind that, but I want the java plugin to use browser certificates and client certificates but its not, I have to load the client certificate to the java plugin also using the java ControlPanel, and if my server's certificate is self signed then I have to load the server certificate also to the java ControlPanel and to the nrowser. Another thing is when the applet starts loading the java plugin pops a dialog asking for the client keystore password, I would like to avoid that. So to conclude: I would like the java plugin to use the browser's trusted certificates and client certificates, and to avoid the keystore password dialog that pops up. I have googled for it for two days and can't find any clue of how to accomplish that. I will appreciate any help. I'm using jdk 1.6.0 u23 and firefox 3.6.13.

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  • How to enforce jsf to create new instance of bean instead of throwing NullPointerException?

    - by Roman
    I'm almost sure that I do something wrong and thus the question's title is a bit incorrect. I have a form with several fields for creating a new User-objects (fields like login, password, birthday etc). And I have 2 buttons - Cancel and Create. I didn't finish Create yet :) , but when I press Cancel I see NullPointerException. Here is simplified code: <f:view> <h:form> <h:panelGroup layout="block"> <h:inputText id="add_login" value="#{userSupport.user.login}"/> <h:inputSecret id="add_password" value="#{userSupport.user.password}"/> <h:inputText id="add_name" value="#{userSupport.user.name}"/> <h:inputText id="add_surname" value="#{userSupport.user.surname}"/> <h:commandButton value="Cancel" action="cancel"/> </h:panelGroup> </h:form> </f:view> UserSupport class has field user with getter and setter and some other methods. It's a Spring bean with Session scope. When I press cancel, I see NPE because jsf tries to save values from inputs in user-object, but user-object is null. What is the correct way of doing this?

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  • Replacing mysql user authentication with openid

    - by David
    So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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  • Paypal Sandbox 2014 Non US test account Sign Up proper link

    - by Flood Gravemind
    Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • Variable wont echo

    - by jonnnnnnnnnie
    I have the following code, where the var $username doesn't echo, when you type in a value. //TODO: SET AUTH TOKEN as random hash, save in session $auth_token = rand(); if (isset($_POST['action']) && $_POST['action'] == 'Login') { $errors = array(); //USED TO BUILD UP ARRAY OF ERRORS WHICH ARE THEN ECHOED $username = $_POST['username']; if ($username = '') { $errors['username'] = 'Username is required'; } echo $username; // var_dump($username) returns string 0 } require_once 'login_form.html.php'; ?> login_form is this: <form method="POST" action=""> <input type="hidden" name="auth_token" value="<?php echo $auth_token ?>"> Username: <input type="text" name="username"> Password: <input type="password" name="password1"> <input type="submit" name="action" value="Login"> </form> The auth token part isn't important, it just when I type in a value in username textbox and press the login button, the username wont echo, var_dump returns string (0) and print_r is just blank.

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  • Shell script for generating HTML out put

    - by user1638016
    The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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  • Display error message at top of form

    - by moustafa
    Hello, I'm trying to get the following error to show when some once presses the submit button and has not filled in the required field/s. My PHP code is. <?php require_once("includes/database.php"); require_once("includes/functions.php"); if(isset($_POST['full_name'])) { $required = array('full_name','user_name','email','pwd','pwd2'); $missing = array(); $validation = array( 'full_name' => 'Please provide your full name', 'user_name' => 'Please provide your username', 'email' => 'Please provide your valid email address', 'pwd' => 'Please provide your password', 'pwd2' => 'Please confirm your password', 'userdup' => 'Username already registered', 'emaildup' => 'Email address already registered', 'mismatch' => 'Passwords do not match' ); //Sanitise and clean function $full_name = escape($_POST['full_name']); $user_name = escape($_POST['user_name']); $email = escape($_POST['email']); $pwd = escape($_POST['pwd']); $pwd2 = escape($_POST['pwd2']); foreach($_POST as $key => $value) { $value = trim($value); if(empty($value) && in_array($key,$required)) { array_push($missing,$key); } else { ${$key} = escape($value); } }

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  • I have data about deadlocks, but I can't understand why they occur (MS SQL/ASP.NET MVC)

    - by Alex
    I am receiving a lot of deadlocks in my big web application. http://stackoverflow.com/questions/2941233/how-to-automatically-re-run-deadlocked-transaction-asp-net-mvc-sql-server Here I wanted to re-run deadlocked transactions, but I was told to get rid of the deadlocks - it's much better, than trying to catch the deadlocks. So I spent the whole day with SQL profiler, setting the tracing keys etc. And this is what I got. There's a Users table. I have a very high usable page with the following query (it's not the only query, but it's the one that causes troubles) UPDATE Users SET views = views + 1 WHERE ID IN (SELECT AuthorID FROM Articles WHERE ArticleID = @ArticleID) And then there's the following query in ALL pages: User = DB.Users.SingleOrDefault(u => u.Password == password && u.Name == username); That's where I get User from cookies. Very often a deadlock occurs and this second LINQ TO SQL query is chosen as a victim, so it's not run, and users of my site see an error screen. I read a lot about deadlocks... And I don't understand why this is causing a deadlock. So obviously both of this queries run very often. At least once a second. Maybe even more often (300-400 users online). So they can be run at the same time very easily, but why does it cause a deadlock? Please help. Thank you

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  • Access to SQL Server 2005 from a non-domain machine using Windows authentication

    - by user304582
    Hi, I have a Windows domain within which a machine is running SQL Server 2005 and which is configured to support only Windows authentication. I would like to run a C# client application on a machine on the same network, but which is NOT on the domain, and access a database on the SQL Server 2005 instance. I thought that it would be a simple matter of doing something like this: string connectionString = "Data Source=server;Initial Catalog=database;User Id=domain\user;Password=password"; SqlConnection connection = new SqlConnection(connectionString); connection.Open(); However, this fails: the client-side error is: System.Data.SqlClient.SqlException: Login failed for user 'domain\user' and the server-side error is: Error 18456, Severity 14, State 5 I have tried various things including setting integrated security to true and false, and \ instead of \ in the User Id, but without success. In general, I know that it possible to connect to the SQL Server 2005 instance from a non-domain machine (for example, I am working with a Linux-based application which happily does this), but I don't seem to be able to work out how to do it from a Windows machine. Help would be appreciated! Thanks, Martin

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  • Windows Phone 7.1.1 Ping

    - by Matt
    I am writing an app to connect to a third party application using REST web services. I have a configuration page that asks for an IP, Port, User Name & Password, currently it just blindly assumes you enter the correct details and attempts a connection. I want to create a test routine that goes through and checks off the following steps when setting up the config information Is the IP/Hostname correct (using ping or something) Is the Port correct Is the Username & Password correct then displays the results on screen as it's going so that if it can't connect to the service it's easier to identify where the issue is. To achieve step 1 I would like to use Ping or some equivalent that does not rely on a particular port being open. So I can eliminate dodgy DNS or a typo in the IP/Hostname. I understand from previous questions asked that ping wasn't possible in 7.0 but with Mango the sockets classes have been added in, is it possible now, if so how? If it still isn't possible is there a different way I can achieve step 1?

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  • Centering form elements with left alignment

    - by user1766797
    I would like to center the elements in my form without moving the text or buttons from being aligned on the left. So it would look like this: The bottom square is supposed to be a button. I want it centered, but the <center> tag moves the text and button so they're centered to the input box. Here is my code: <form action="login.php" method="post"> <div class="aside"> <div id="center"> Username:<br> <input type="text" name="username"><br> Password:<br> <input type="password" name="passwor"><br> <input type="submit" class="button" name="submit" value="Login"><br><br> </div> </div> </form> and the css: #center{ width: 250px; margin-left: auto; margin-right: auto; float: center; } div.aside { margin-left: 15px; margin-top: 10px; width: 250px; background: #f5f5f5; border: 1px solid #e9e9e9; line-height: 150%; } div.aside .button{ padding:3px; width: 50px; margin-top: 3px; background-color: #00A1E6; border: 1px solid #0184BC; text-decoration:none; color: #ffffff; text-align: center; -webkit-appearance: none; }

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  • deployd authentification using jquery ajax

    - by user2507987
    I have installed deployd in my debian 7.0.0 64 bit, I have also succesfully installed mongodb in it, I have create some collection and user collection in deployd dashboard, then using user guide how to connect and query the table in deployd, I choose jquery ajax to log in to deployd from my localhost site and after login success I try to get/post some data, but somehow deployd return access denied. I have create collection name it people, and then at the GET, POST, PUT Event I have write this code : cancelUnless(me, "You are not logged in", 401); then using this ajax code, I try to login and POST new people data: $(document).ready(function(){ /* Create query for username and password for login */ var request = new Object; request.username = 'myusername'; request.password = 'mypassword'; submitaddress = "http://myipaddress:myport/users/login"; $.ajax({ type: "POST", url: submitaddress, data: request, cache: false, success: function(data){ var returndata = eval(data); /* After Login success try to post people data */ if (returndata){ var request2 = new Object; request2.name = 'People Name'; submitaddress2 = "http://myipaddress:myport/people"; $.ajax({ type: "POST", url: submitaddress2, data: request2, cache: false, success: function(){ } }) } } } }); }) The login process success, it's return session id and my user id, but after login success and I try to POST people data it's return "You are not logged in", can anyone help me, what is the correct way to login to deployd using jquery from other website(cross domain)?

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  • Codeigniter xss_clean dilemma

    - by Henson
    I know this question has been asked over and over again, but I still haven't found the perfect answer for my liking, so here it goes again... I've been reading lots and lots polarizing comments about CI's xss_filter. Basically majority says that it's bad. Can someone elaborate how it's bad, or at least give 1 most probable scenario where it can be exploited? I've looked at the security class in CI 2.1 and I think it's pretty good as it doesn't allow malicious strings like document.cookie, document.write, etc. If the site has basically non-html presentation, is it safe to use global xss_filter (or if it's REALLY affecting performance that much, use it on per form post basis) before inserting to database ? I've been reading about pros and cons about whether to escape on input/output with majority says that we should escape on output only. But then again, why allow strings like <a href="javascript:stealCookie()">Click Me</a> to be saved in the database at all? The one thing I don't like is javascript: and such will be converted to [removed]. Can I extend the CI's security core $_never_allowed_str arrays so that the never allowed strings return empty rather than [removed]. The best reasonable wrongdoing example of this I've read is if a user has password of javascript:123 it will be cleaned into [removed]123 which means string like this document.write123 will also pass as the user's password. Then again, what is the odds of that to happen and even if it happens, I can't think of any real harm that can do to the site. Thanks

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  • Codeigniter : database configuration

    - by nppCods
    I am beginner for CI so don’t have good knowledge. My problem is: I am not using any database. All the records are fetched from JSON. Therefore I don’t think I need to configure database… As said by CI, it doesn’t necessarily ask for database. So my database.php configuration is : $active_group = ‘default’; $active_record = FALSE; $db[‘default’][‘hostname’] = ‘’; $db[‘default’][‘username’] = ‘’; $db[‘default’][‘password’] = ‘’; $db[‘default’][‘database’] = ‘’; $db[‘default’][‘dbdriver’] = ‘mysql’; $db[‘default’][‘dbprefix’] = ‘’; $db[‘default’][‘pconnect’] = TRUE; $db[‘default’][‘db_debug’] = TRUE; $db[‘default’][‘cache_on’] = FALSE; $db[‘default’][‘cachedir’] = ‘’; $db[‘default’][‘char_set’] = ‘utf8’; $db[‘default’][‘dbcollat’] = ‘utf8_general_ci’; $db[‘default’][‘swap_pre’] = ‘’; $db[‘default’][‘autoinit’] = TRUE; $db[‘default’][‘stricton’] = FALSE; It works in my local system but doesn’t work in live server. I am so surprised. Then I provided hostname, username, password and dbdriver, it works. My question is that, is that necessary to provide all the details if I am not using database? Thank you for your suggestion.

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  • using IntentExatras with Alarm Manager

    - by Ashwin
    I want to know if this code will work(I cannot try it out right now. Moreover, I have a few doubts that have to be cleared). Intent intent = new Intent(context, AlarmReceiver.class); intent.putExtra("user",global.getUsername()); intent.puExtra("password",global.getPassword); PendingIntent sender = PendingIntent.getBroadcast(context, 192837, intent, PendingIntent.FLAG_UPDATE_CURRENT); // Get the AlarmManager service Log.v("inside log_run", "new service started"); AlarmManager am = (AlarmManager) getSystemService(ALARM_SERVICE); am.setRepeating(AlarmManager.RTC_WAKEUP, IMMEDIATELY,60000,sender); finish(); As you can see, this code starts an AlarmManager with setRepeating(). If you see the intent(actually the pending intent) passed on to the BroadcastReceiver, there are two extras that are passed on. These are global variables that live as long as the Application is running. But this AlarmManager is meant to be run in the background (that is application will be alive only for the first few calls of the o fthe alrmamanager to the broadcast recevier) My Question Will AlarmManager make a copy of the global variables(the username and password) and maintain this copy to be passed along with the intent? Because, these values will be used in the broadcast receiver.

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  • How to make cakePHP retreive the data represented by a foreign key?

    - by XL
    Greetings cake experts, I have a question that I think would really help a lot of people getting started with cakePHP. I have a feeling it will be easy for some of you, but it is quite challenging to me. I have a simple database with multiple tables. I can't figure out how to make cakePHP display the values associated with a foreign key in an index view. Or create a view where the fields of my choice (the ones that make sense to users like location name - not location_id can be updated or viewed on a single page). I have created an example at http://lovecats.cakeapp.com that illustrate the question. If you look at the page and click the "list cats", you will notice that it shows the location_id field from the locations table. You will also notice that when you click "add cats", you must choose a location_id from the locations table. This is the automagic way that cakePHP builds the app. I want this to be the field location_name. The database is setup so that the table cats has a foreign key called location_id that has a relationship to a table called locations. This is my problem: I want these pages to display the location_name instead of the location_id. If you want to login to the application, you can go to http://cakeapp.com/sqldesigners/sql/lovecats and the password 'password' to look at the db relationships, etc. How do I have a page that shows the fields that I want? And is it possible to create a page that updates fields from all of the tables at once? This is the slice of cake that I have been trying to figure out and this would REALLY get me over a hump. You can download the app and sql from the above url.

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  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

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  • Remove a ReactiveCocoa signal from a control

    - by dbarros
    If I assign a signal to a property of a control: RAC(self.loginButton.enabled) = [RACSignal combineLatest:@[ self.usernameTextField.rac_textSignal, self.passwordTextField.rac_textSignal ] reduce:^(NSString* username, NSString* password) { return @(username.length > 0 && password.length > 0); }]; But then wanted to assign a different RACSignal to enabled, how can I clear any existing one before doing so? If I try and set it a second time, I get an exception like the following: 2013-10-29 16:54:50.623 myApp[3688:c07] *** Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Signal <RACSignal: 0x975e9e0> name: +combineLatest: ( "<RACSignal: 0x975d600> name: <UITextField: 0x10f2c420> -rac_textSignal", "<RACSignal: 0x975de30> name: <UITextField: 0x10f306e0> -rac_textSignal" ) reduce: is already bound to key path "self.loginButton.enabled" on object <LoginViewController: 0x10f264e0>, adding signal <RACSignal: 0x9763500> name: +combineLatest: ( "<RACSignal: 0x97624f0> name: <UITextField: 0x10f2c420> -rac_textSignal", "<RACSignal: 0x97629e0> name: <UITextField: 0x10f306e0> -rac_textSignal" ) reduce: is undefined behavior'

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