Why do all procedures have to be defined before the compiler sees them?
- by incrediman
For example, take a look at this code (from tspl4):
(define proc1
(lambda (x y)
(proc2 y x)))
If I run this as my program in scheme...
#!r6rs
(import (rnrs))
(define proc1
(lambda (x y)
(proc2 y x)))
I get this error:
expand: unbound identifier in module in: proc2
...This code works fine though:
#!r6rs
(import (rnrs))
(define proc2
+)
(define proc1
(lambda (x y)
(proc2 y x)))
(display (proc1 2 3)) ;output: 5
