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  • How to bring a modal to the front of the page using bootstrap?

    - by sharataka
    I am trying to implement a modal using bootstrap. When I click on the button the screen fades and the modal appears, but it appears behind the images in and is unreadable for the user. How do I bring the modal forward? <div class ="container-fluid"> <div class = "row-fluid"> <div class = "span2"> <!-- Modal --> <div class="modal hide fade" id="myModal"> <div class="modal-header"> <a class="close" data-dismiss="modal">×</a> <h3>Modal header</h3> </div> <div class="modal-body"> <p>One fine body…</p> </div> <div class="modal-footer"> <a href="#" class="btn">Close</a> <a href="#" class="btn btn-primary">Save changes</a> </div> </div> <a data-toggle="modal" href="#myModal" class="btn btn-primary">Launch demo modal</a> </div> <div class = "span8"> #a lot of images in this div </div> </div> </div>

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  • pagination in css/php

    - by fusion
    two questions: --1-- it displays all the number of pages. but i'd like it to display as: << Prev . . 3 4 [5] 6 7 . . Next --2-- when i hover on the current page no, it should change color or increase the font-size, but when i modify the css of a:hover, all the page nos change color or size instead of the one which i'm pointing to. also, when modifying a:active, nothing happens. this is my paging code in php: $self = $_SERVER['PHP_SELF']; $limit = 2; //Number of results per page $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> <div class="searchmain"> <?php //Create and print the Navigation bar $nav=""; $next = $page+1; $prev = $page-1; if($page > 1) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a></span>"; $first = "<span class=\"searchpage\"><a onclick=\"showPage('','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a></span>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<span class=\"searchpage\">$i</span>"; }else{ $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a></span>"; } } if($page < $numpages) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a></span>"; $last = "<span class=\"searchpage\"><a onclick=\"showPage('','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a></span>"; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo $first . $nav . $last; ?> </div> and this is how it displays currently: css: .searchmain { margin:30px; text-align: center; } .searchpage { border: solid 1px #ddd; background: #fff; text-align:left; font-size: 16px; padding:9px 12px; color: #FEBE33; margin-left:2px; } .searchpage a{ text-decoration: none; color: #808080; } .searchpage a:hover { color: #FEBE33; border-color: #036; text-decoration: none; } .searchpage a:visited { color: #808080; }

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  • Polymorphic associations in CakePHP2

    - by Joseph
    I have 3 models, Page , Course and Content Page and Course contain meta data and Content contains HTML content. Page and Course both hasMany Content Content belongsTo Page and Course To avoid having page_id and course_id fields in Content (because I want this to scale to more than just 2 models) I am looking at using Polymorphic Associations. I started by using the Polymorphic Behavior in the Bakery but it is generating waaay too many SQL queries for my liking and it's also throwing an "Illegal Offset" error which I don't know how to fix (it was written in 2008 and nobody seems to have referred to it recently so perhaps the error is due to it not having been designed for Cake 2?) Anyway, I've found that I can almost do everything I need by hardcoding the associations in the models as such: Page Model CREATE TABLE `pages` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Page extends AppModel { var $name = 'Page'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page'), ) ); } ?> Course Model CREATE TABLE `courses` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Course extends AppModel { var $name = 'Course'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course'), ) ); } ?> Content model CREATE TABLE IF NOT EXISTS `contents` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `class` varchar(30) COLLATE utf8_unicode_ci NOT NULL, `foreign_id` int(11) unsigned NOT NULL, `title` varchar(100) COLLATE utf8_unicode_ci NOT NULL, `content` text COLLATE utf8_unicode_ci NOT NULL, `created` datetime DEFAULT NULL, `modified` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) <?php class Content extends AppModel { var $name = 'Content'; var $belongsTo = array( 'Page' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page') ), 'Course' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course') ) ); } ?> The good thing is that $this->Content->find('first') only generates a single SQL query instead of 3 (as was the case with the Polymorphic Behavior) but the problem is that the dataset returned includes both of the belongsTo models, whereas it should only really return the one that exists. Here's how the returned data looks: array( 'Content' => array( 'id' => '1', 'class' => 'Course', 'foreign_id' => '1', 'title' => 'something about this course', 'content' => 'The content here', 'created' => null, 'modified' => null ), 'Page' => array( 'id' => null, 'title' => null, 'slug' => null, 'created' => null, 'updated' => null ), 'Course' => array( 'id' => '1', 'title' => 'Course name', 'slug' => 'name-of-the-course', 'created' => '2012-10-11 00:00:00', 'updated' => '2012-10-11 00:00:00' ) ) I only want it to return one of either Page or Course depending on which one is specified in Content.class UPDATE: Combining the Page and Course models would seem like the obvious solution to this problem but the schemas I have shown above are just shown for the purpose of this question. The actual schemas are actually very different in terms of their fields and the each have a different number of associations with other models too. UPDATE 2 Here is the query that results from running $this->Content->find('first'); : SELECT `Content`.`id`, `Content`.`class`, `Content`.`foreign_id`, `Content`.`title`, `Content`.`slug`, `Content`.`content`, `Content`.`created`, `Content`.`modified`, `Page`.`id`, `Page`.`title`, `Page`.`slug`, `Page`.`created`, `Page`.`updated`, `Course`.`id`, `Course`.`title`, `Course`.`slug`, `Course`.`created`, `Course`.`updated` FROM `cakedb`.`contents` AS `Content` LEFT JOIN `cakedb`.`pages` AS `Page` ON (`Content`.`foreign_id` = `Page`.`id` AND `Content`.`class` = 'Page') LEFT JOIN `cakedb`.`courses` AS `Course` ON (`Content`.`foreign_id` = `Course`.`id` AND `Content`.`class` = 'Course') WHERE 1 = 1 LIMIT 1

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  • How can I stop cURL from outputting the contents of the page it loads into the browser?

    - by Rob
    I currently use curl_multi_* to connect to a few sites. Its only sending a few $_GET variables to start a script, but it outputs the html from the sites to the browser. I want to stop this. I already use a short timeout, but sometimes the scripts start fast, and I don't want to set the timeout any lower, in case it causes it not to connect. So how can I stop the output to the browser from cURL?

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  • Give me better idea to do Marquee tag in asp.net page.

    - by Ayyappan.Anbalagan
    The bellow code working, but i don’t know it the write way or not? <td align="center" style=" height:50px; width:100%; background-color:Red;width:10%;"> <div id="divremview" > <marquee behavior="scroll" direction="up"> <div id="div1"><asp:Label ID="Label1" runat="server" Text="Label">Hi</asp:Label></div> </marquee> </div> </td> Also it not in center alignment. As usual it in left alignment

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  • Sharepoint 2007 : Saving Form data with page redirection using custom parameters.

    - by Deepu
    HI Experts, After saving the form data I would like to REDIRECT to different pages based on the @Status value using the input type button. <input type="button" value="Save" name="btnSave" id="btnSave" onclick="{ddwrt:GenFireServerEvent('_commit;_redirect={*Confirm.aspx?ID=1}')};" /* if @Status == "Draft" url = "draft.aspx ? ID = " @ID else if @Status == "Save" url = "save.aspx ? ID = " @ID else url = "confirm.aspx ? ID = " @ID Here @ID and @Status are share point list column names Now I have hard-coded the url Confirm.aspx?ID=4. But I want to check the status value using XSLT condition and set different URL name with @ID value.. How do I achieve this.. any help would be appreciated.. thanks deepu

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  • Is there a way to dynamically define how an image appear in a page or in certain layout?

    - by Starx
    For so many time, I have encountered problems with managing image having abnormally long height or width. If I fixed their height and widht, they will appear streched? If I fixed their width, and if the height of the image is very long then also it will mess up the overall website. If I fixed their height, and if the width of the image is very long then also it will mess up the overall website. The images I save in the local drive are saved maintaining the ratio? Let say user decides to upload image 1(height)*32(width). When he uploads this image, the script is made to resize the user uploaded image to height:1000px(just an example) So the resulting image in 1000px(height)*32000(widht), you see now the image is abnormally large. Now while displaying this image in a box of 1000px * 1000px, what is the best way to display this image?

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  • How can I make visual studio 2010 deploy (or FTP upload) a page on save?

    - by Isa
    Just started using Visual Studio 2010, moved over from Netbeans. I kinda liked the Netbeans upload on save functionality, which was useful in development environments when one is constantly making small changes and testing them. As soon as you saved a file, it would be synced to the FTP server. Is it possible to do this in VS? I'm pretty sure there is a way, using a macro of some sort, and having it run on every save? However I have no idea how to implement it... Maybe even a keyboard shortcut to deploy the current working file would be nice.

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  • How are you supposed to layout a page in VS2010 without using tables?

    - by CrustyApple
    I have been using .NET since beta and HTML since the days of HotDog pro & notepad, using table layout of course. I am FINALLY ready to use only div, li, CSS for the layout, but my question is, what is the proper way to layout pages in VS2010? When i use table layout its simple and i can visually see what im creating and where the elements are, such as the sample below - how should I do this using div's, etc in VS2010? <table width="300" border="0" cellpadding="5"> <tr> <td><img src="http://assets.devx.com/MS_Azure/azuremcau.jpg" alt="blah" width="70" height="70" /></td> <td><h2>This is some text to the right of the picture...</h2></td> </tr> <tr> <td colspan="2">Here some text underneath</td> </tr> </table>

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  • Is it possible to serve an ASPX page without it setting a cookie on your browser?

    - by Django Reinhardt
    Hi, we're in the process of trying to speed up the performance of our website by serving static content from a cookieless domain. That seems to be going well, but I have a new question: I know that it's "static content" that we're talking about when serving it from a cookieless domain, but we also have static content being served by ASPX pages, specifically images. For example: domain.com/resizeImages.aspx?src=images/image123.jpg&width=400&height=400 Pretty standard stuff, and although it's being served by managed code, it's still a static image. So my question is: Is it ok to serve the resizeImages.aspx image from our cookieless/static domain? And if so, how do I go about stopping ASP.NET from setting a ANONYMOUSASPX cookie every time I try? Thanks for any help!

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • How do I get rid of the space between <img> elements in a row in a html page?

    - by Aperture
    I'm displaying 3 <img> in a row like this: <div style="width: 950px"> <img src='/UploadedImages/86.jpg' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> <img src='/UploadedImages/85.jpg' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> <img src='/UploadedImages/84.gif' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> </div> As you can see I have thin black borders around the images. My problem is that there are white spaces about 5px wide between the borders of neighbouring images and I have set the margin to be 0px but it does not work. So what is happening here?

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  • How can I close a SimpleModal dialog when the user clicks the Back button?

    - by Wally Hartshorn
    When a user clicks on a button or link, I use the SimpleModal jQuery plugin to display a dialog to overlay the entire page, preventing the user from clicking another button or link during the delay before the next page loads. (I'd like to avoid this, but that's an issue for another day.) After the next page displays, if the user clicks the Back button, the previous page still has the SimpleModal overlay displayed, preventing them from using the page. This is a problem. How can I cause the SimpleModal dialog to close automatically either when the leaves the page or when the user clicks the Back button to return to the page? I tried this without success: $("body").unload(function() { $.modal.close(); }); Thanks! Wally

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  • How can I load a web page inside of a jQuery dialog box?

    - by kielie
    Hi, I am designing a wordpress template, and I would like to use jQuery ui to display each of the calendar links in a dialog box, when they are clicked. What I want, is when someone clicks on a link in the wordpress calendar, the content will load in the dialog box, and display over the calendar. I would appreciate any help on this, thanx in advance!

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  • How to remove back button action while page is loading.

    - by user133611
    Hi All In my project i have a list when select on a item it will take to next controller using PushViewController. When i go there i will get data using libxml parser. But when i am clicking on the back button while loading it is showing exception. So i want to disable back button action till loading of data is completed how can i handle it. Thank You

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  • Using the filename for GET data and making the PHP page output as a JPG extension?

    - by Rob
    Alright, currently I'm using GD to create a PNG image that logs a few different things, depending on the GET data, for example: http://example.com/file.php?do=this will log one thing while http://example.com/file.php?do=that will log another thing. However, I'd like to do it without GET data, so instead http://example.com/dothis.php will log one thing, and http://example.com/dothat.php will log the other. But on top of that, I'd also like to make it accessible via the JPG file extension. I've seen this done but I can't figure out how. So that way http://example.com/dothis.JPG will log one thing, while http://example.com/dothat.JPG logs the other. The logging part is simple, of course. I simple need to know how to use filenames in place of the GET data and how to set the php file to be accessible via a jpg file extension.

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