Search Results

Search found 5233 results on 210 pages for 'a records'.

Page 24/210 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

  • Lucene Search Returning Extra, Undesired Records

    - by Brandon
    I have a Lucene index that contains a field called 'Name'. I escape all special characters before inserting a value into my index using QueryParser.Escape(value). In my example I have 2 documents with the following names respectively: Test Test (Test) They get inserted into my index as such (I can confirm this using Luke): [test] [test] [\(test\)] I insert these values as TOKENIZED and using the StandardAnalyzer. When I perform a search, I use the QueryParser.Escape(searchString) against my search string input to escape special characters and then use the QueryParser with my 'Name' field and the StandardAnalyzer to perform my search. When I perform a search for 'Test', I get back both documents in my index (as expected). However, when I perform a search for 'Test (Test)', I am getting back both documents still. I realize that in both examples it matches on the 'test' term in the index, but I am confused in my 2nd example why it would not just pull back the document with the value of 'Test (Test)' because my search should create two terms: [test] and [\(test\)] I would imagine it would perform some sort of boolean operator where BOTH terms must match in that situation so I would get back just one record. Is there something I am missing or a trick to make the search behave as desired?

    Read the article

  • How to relate keywords to records - Many to Many

    - by webworm
    Hi All, I am looking for suggestions on database design for a sample jobs listing application. I have many jobs that I would like to associate various keywords with. Each job can have multiple keywords. I would like to store the keywords in a seperate table instead of in a field within the Job table so as to avoid mispellings in keywords. What is the best way to relate keywords to the jobs? I was thinking of using an intermediary table that would have a many to many relationship linking keywords to jobs. Is this the best way to go or should I just have a field in the Job table that contains multiple keywords? Thanks for any suggestions.

    Read the article

  • Django: getting the list of related records for a list of objects

    - by Silver Light
    Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

    Read the article

  • How do I use a named_scope to filter records in my model

    - by kibyegon
    I have a model "Product" with a "description" field. Now I want to have a link in the index page that when clicked will show all products where the description is blank (empty). In the model I have defined a named_scope like this named_scope :no_description, :conditions => { :description => "" } I have checked that the named_scope works by calling Product.no_description.count on the console. As far as I know, the controller is then supposed to handle the filter request from the link on the "index" action but be able to distinguish it from the default which is view all products. def index @products = Product.all ... My problem is getting the controller handle the different request, what route to setup for the link on the view and the actual link on the view. Hope I explained my problem.

    Read the article

  • getting active records to display as a plist

    - by phil swenson
    I'm trying to get a list of active record results to display as a plist for being consumed by the iphone. I'm using the plist gem v 3.0. My model is called Post. And I want Post.all (or any array or Posts) to display correctly as a Plist. I have it working fine for one Post instance: [http://pastie.org/580902][1] that is correct, what I would expect. To get that behavior I had to do this: class Post < ActiveRecord::Base def to_plist attributes.to_plist end end However, when I do a Post.all, I can't get it to display what I want. Here is what happens: http://pastie.org/580909 I get marshalling. I want output more like this: [http://pastie.org/580914][2] I suppose I could just iterate the result set and append the plist strings. But seems ugly, I'm sure there is a more elegant way to do this. I am rusty on Ruby right now, so the elegant way isn't obvious to me. Seems like I should be able to override ActiveRecord and make result-sets that pull back more than one record take the ActiveRecord::Base to_plist and make another to_plist implementation. In rails, this would go in environment.rb, right?

    Read the article

  • Create ImageButton programatically depending on local database records

    - by user2507920
    As i described in title, i have a local db in sqlite. I want to create ImageButton parametrically. How many times is local database loop executing? Please see code below : RelativeLayout outerRelativeLayout = (RelativeLayout)findViewById(R.id.relativeLayout2_making_dynamically); db.open(); Cursor c = db.getAllLocal_Job_Data(); if(c!=null){ if(c.moveToFirst()){ do { RelativeLayout innerRelativeLayout = new RelativeLayout(CalendarActivity.this); innerRelativeLayout.setGravity(Gravity.CENTER); ImageButton imgBtn = new ImageButton(CalendarActivity.this); imgBtn.setBackgroundResource(R.drawable.color_001); RelativeLayout.LayoutParams imageViewParams = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); imgBtn.setLayoutParams(imageViewParams); // Adding the textView to the inner RelativeLayout as a child innerRelativeLayout.addView(imgBtn, new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); outerRelativeLayout.addView(innerRelativeLayout, new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); } while (c.moveToNext()); } } db.close(); But when i run the project, i can see only one button created there. I think there are many buttons but here image button is creating on last created image button. I think i should use android:layout_toRightOf with previous created button but i cant find how to place it here. I have tried some ideas but it did not change any thing. So please anybody has any idea to solve my problem then please share it with me.

    Read the article

  • New records added to DataGridView aren't displayed

    - by Ross
    I have a custom Order class, groups of which are stored in List<Order> and a DataGridView. I think the problem is in my implementation so here's how I'm using it: In the form enclosing DataGridView (as OrdersDataGrid): public partial class MainForm : Form { public static List<Order> Orders; public MainForm() { // code to populate Orders with values, otherwise sets Orders to new List<Order>(); OrdersDataGrid.DataSource = Orders; } Then in another form that adds an Order: // Save event public void Save(object sender, EventArgs e) { Order order = BuildOrder(); // method that constructs an order object from form data MainForm.Orders.Add(order); } From what I can tell from the console this is added successfully. I thought the DataGrid would be updated automatically after this since Orders has changed - is there something I'm missing? The DataGrid accepts the class since it generates columns from the members.

    Read the article

  • Finding records when using has_many through associations

    - by winter sun
    I have two models, Worker and Project, and they are connected with has_many through association. I manage to find all the projects which are related to a specific worker by writing the following code: worker=Worker.find_by_id("some_id") worker.projects but I want the projects that I get to be only active projects (in the project model I have a status field) I tried to do something like worker.projects(:status_id=>'active') but it didn’t work for me. Can somebody tell me how I can do this?

    Read the article

  • Ruby on Rails: create records for multiple models with one form and one submit

    - by notblakeshelton
    I have a 3 models: quote, customer, and item. Each quote has one customer and one item. I would like to create a new quote, a new customer, and a new item in their respective tables when I press the submit button. I have looked at other questions and railscasts and either they don't work for my situation or I don't know how to implement them. I also want my index page to be the page where I can create everything. quote.rb class Quote < ActiveRecord::Base attr_accessible :quote_number has_one :customer has_one :item end customer.rb class Customer < ActiveRecord::Base #unsure of what to put here #a customer can have multiple quotes, so would i use: has_many :quotes #<----? end item.rb class Item < ActiveRecord::Base #also unsure about this #each item can also be in multiple quotes quotes_controller.rb class QuotesController < ApplicationController def index @quote = Quote.new @customer = Customer.new @item = item.new end def create @quote = Quote.new(params[:quote]) @quote.save @customer = Customer.new(params[:customer]) @customer.save @item = Item.new(params[:item]) @item.save end end items_controller.rb class ItemsController < ApplicationController def index end def new @item = Item.new end def create @item = Item.new(params[:item]) @item.save end end customers_controller.rb class CustomersController < ApplicationController def index end def new @customer = Customer.new end def create @customer = Customer.new(params[:customer]) @customer.save end end quotes/index.html.erb <%= form_for @quote do |f| %> <%= f.fields_for @customer do |builder| %> <%= label_tag :firstname %> <%= builder.text_field :firstname %> <%= label_tag :lastname %> <%= builder.text_field :lastname %> <% end %> <%= f.fields_for @item do |builder| %> <%= label_tag :name %> <%= builder.text_field :name %> <%= label_tag :description %> <%= builder.text_field :description %> <% end %> <%= label_tag :quote_number %> <%= f.text_field :quote_number %> <%= f.submit %> <% end %> When I try submitting that I get an error: Can't mass-assign protected attributes: item, customer So to try and fix it I updated the attr_accessible in quote.rb to include :item, :customer but then I get this error: Item(#) expected, got ActiveSupport::HashWithIndifferentAccess(#) Any help would be greatly appreciated.

    Read the article

  • Rails creating and updating 2 model records simultaneously

    - by LearnRails
    I have 2 tables product and history product table id name type price location 1 abc electronics $200 aisle1 history table id product_id status 1 1 price changed from $200 to $180 Whenever the product price or location is updated by a user by hitting the update button, 1) the changes should be automatically be reflected in the history status column without the user having to enter that manually. if the price is updated from 200 to 180 then a new history row will be created with new id and the status column will say ' price changed from $200 to $180' if the location is updated from aisle1 to aisle 2 then status displays ' loc changed from ailse1 to aisle 2' I tried to @product = Product.new(params[:product]) @history= History.new(params[:history]) if @product.save @history.new(attributes) == I am not sure of whether this approach is correct I would really appreciate if someone could tell me how the history can be automatically updated in this case.

    Read the article

  • How to handle un-assigned records

    - by Mico
    I have this PHP page where the user can select and un-select items. The interface looks like this: Now I'm using these code, when the user hit the save changes button: foreach( $value as $al_id ){ //al_id is actually location id //check if a record exists //if location were assigned and leave it as is $assigned_count = $this->AssignedLoc->checkIfAssigned( $tab_user_id, $al_id ); if( $assigned_count == 0 ){ //else if not, insert this new record $this->insertAssigned( $tab_user_id, $company_id, $al_id ); } } Now my question is, how do I delete the un assigned locations? For example in the screenshot above, there are 4 assigned locations, if I'm gonna remove (or unassign) "Mercury Morong" and "GP Hagonoy" from the assigned locations, only two must remain. What are the possible solutions using PHP? Thanks for any help!

    Read the article

  • Query to check the consistency of records

    - by orunner
    I have four tables TableA: id1 id2 id3 value TableB: id1 desc TableC: id2 desc TableD: id3 desc What I need to do is to check if all combinations of id1 id2 id3 from table B C and D exist in the TableA. In other words, table A should contain all possible combinations of id1 id2 and id3 which are stored in the other three tables.

    Read the article

  • How can I select the required records?

    - by simple
    Tables: Product: [id, name, brand_id, is_published] Brand: [id, name, is_published] Awards: [id, name] ProductAwards [product_id, award_id] How do I select the list of PUBLISHED brands along with the number of AWARDS of brand's products that are Published. I am cool with all the part except issuing the "is_published" restriction when counting Awards. I hope this is clear; can anyone just suggest where to dig?

    Read the article

  • Finding records within a 5 min time interval in SQL

    - by Mellonjollie
    I have a table with over 100,000 rows that contain the following columns: ID, Time, and Boolean. The time column tracks time down to the second. I need a query that will find all instances of Boolean = 1 for every 5 minute interval of time from the start of the table to the end, then group the count by time interval. The table represents 4 hours of data, so I should get 48 rows of results. I'm using MS SQL Server. I've tried a few approaches, but the time interval logic is giving me a hard time.

    Read the article

  • Can't import clojure records

    - by Zubair
    I have created a record like this: (defrecord User [user-id email]) :but when I try to access it from another name-space I get the error: (User. "name" "email") java.lang.IllegalArgumentException: Unable to resolve classname: User It works when I do: (oe.model.modelcore.User. "name" "email") : I know I will need to import the Java class, but is there any way for clojure to do this automatically when I do: (use 'oe.model.modelcore :reload)

    Read the article

  • Duplicate / Copy records in the same MySQL table

    - by Digits
    I have been looking for a while now but I can not find an easy solution for my problem. I would like to duplicate a record in a table, but of course, the unique primary key needs to be updated. I have this query: INSERT INTO invoices SELECT * FROM invoices AS iv WHERE iv.ID=XXXXX ON DUPLICATE KEY UPDATE ID = (SELECT MAX(ID)+1 FROM invoices) the problem is that this just changes the ID of the row instead of copying the row. Does anybody know how to fix this ? Thank you verrry much, Digits //edit: I would like to do this without typing all the field names because the field names can change over time.

    Read the article

  • Selecting records in SQL that have the minimum value for that record based on another field

    - by Ryan
    I have a set of data, and while the number of fields and tables it joins with is quite complex, I believe I can distill my problem down using the required fields/tables here for illustration regarding this particular problem. I have three tables: ClientData, Sources, Prices Here is what my current query looks like before selecting the minimum value: select c.RecordID, c.Description, s.Source, p.Price, p.Type, p.Weight from ClientData c inner join Sources s ON c.RecordID = s.RecordID inner join Prices p ON s.SourceID = p.SourceID This produces the following result: RecordID Description Source Price Type Weight ============================================================= 001002003 ABC Common Stock Vendor 1 104.5 Close 1 001002003 ABC Common Stock Vendor 1 103 Bid 2 001002003 ABC Common Stock Vendor 2 106 Close 1 001002003 ABC Common Stock Vendor 2 100 Unknwn 0 111222333 DEF Preferred Stk Vendor 3 80 Bid 2 111222333 DEF Preferred Stk Vendor 3 82 Mid 3 111222333 DEF Preferred Stk Vendor 2 81 Ask 4 What I am trying to do is display prices that belong to the same record which have the minimum non-zero weight for that record (so the weight must be greater than 0, but it has to be the minimum from amongst the remaining weights). So in the above example, for record 001002003 I would want to show the close prices from Vendor 1 and Vendor 2 because they both have a weight of 1 (the minimum weight for that record). But for 111222333 I would want to show just the bid price from Vendor 3 because its weight of 2 is the minimum, non-zero for that record. The result that I'm after would like like: RecordID Description Source Price Type Weight ============================================================= 001002003 ABC Common Stock Vendor 1 104.5 Close 1 001002003 ABC Common Stock Vendor 2 106 Close 1 111222333 DEF Preferred Stk Vendor 3 80 Bid 2 Any ideas on how to achieve this? EDIT: This is for SQL Compact Edition.

    Read the article

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >