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  • Displaying data from mutliple arrays with codeigniter

    - by Craig Ward
    I am trying to display results from a database where the results are contained in three tables. How do I echo out the results? $p- works, but $img- or $branch- doesn't. What am I doing wrong? Example code is below Sample controller: $p_id = $this-uri-segment(3); $this-load-model('One_model'); $data['prop'] = $this-One_model-get_details($p_id); $data['img'] = $this-One-get_images($p_id); $this-load-model('Two_model'); $data['branch'] = $this-Two_model-get_details($p_id); $this-load-view('a_test_view', $data); A Sample View <?php foreach ($property as $p):?> <p><?php echo $p->SUMMARY; ?></p> <p>We have <?php echo "$img->num_photos"; ?> photos</p> <p>Branch is <?php echo $branch->name; ?>. Telephone <?php echo $branch->tel; ?></p> <ul> <li><?php echo $p->FEATURE1; ?></li> <li><?php echo $p->FEATURE2; ?></li> <li><?php echo $p->FEATURE3; ?></li> <li><?php echo $p->FEATURE4; ?></li> <li><?php echo $p->FEATURE5; ?></li> <li><?php echo $p->FEATURE6; ?></li> <li><?php echo $p->FEATURE7; ?></li> <li><?php echo $p->FEATURE8; ?></li> <li><?php echo $p->FEATURE9; ?></li> <li><?php echo $p->FEATURE10; ?></li> </ul> <?php endforeach; ?>

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  • Codeigniter Template library, add_js() method

    - by Karl
    using This Template Library when i try and use the add_js() function it errors out. I add the regions $_scripts to the template header file but when i load the page it says undefined variable _scripts. any thoughts? changed <?= $_scripts ?> to <?= (isset($_scripts)) ? $_scripts : “”; ?> and obviously i lose the error but the js file still isnt loading. I did an echo at each step though the add_js() method and the output is correct. I also did an output of $this-js and they both had the corret output. So it gets through the get_js method fine and sets the class variable fine but i dont get anything added to the actual page.

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  • PHP/codeigniter - use of exit()

    - by Patrick
    I have a few pages that require login, so all controllers that link to these pages start with $this->checkSession(); //...rest of the code CheckSession should verify the session is still live, otherwise display a message and stop the execution of the rest of the code in the controller: function checkSession() { if (!$this->session->userdata('is_logged_in')) { //the session has expired! $data['main'] = 'confirmation_message'; $data['title'] = "Session expired"; $this->load->vars($data); $this->load->view('template'); exit(); } } . I was expecting these instructions to happen in sequence, but I only get a blank page. How can I make sure exit() gets executed only after all views are loaded?

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  • Write permissions with Codeigniter + Simplepie

    - by Malachi
    I am trying to create a simple RSS parser using the two frameworks. However I am getting PHPerrors when trying to write to my cache directory: set_cache_location(APPPATH.'cache/rss'); I am running windows 7 with XAMPP using the latest version of Simplepie from github error: A PHP Error was encountered Severity: User Warning Message: C:\xampp\htdocs\geekurls/system/application/cache/rss is not writeable. Make sure you've set the correct relative or absolute path, and that the location is server-writable. Filename: libraries/simplepie.php Line Number: 1732

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  • CodeIgniter Validation in Library does not accept callback.

    - by Lukas Oppermann
    Hey guys, my problem is the following: I am writing a login library. This library has a function _validation() and this uses the validation library to validate the data. With using normal validation methods it works just fine, but using a callback function just does not work. It is not called. I call it like this. $this->CI->form_validation->set_rules('user', 'Username', 'required|callback__check_user'); The functions name is _check_user and it uses the username _check_user($user). The function itself works fine and I can also call it in the class ($this-_check_user('username')) with a working result. I am guessing, there might be a problem because I am not workin in a controller so I have a CI instance $this-CI instead of just the original instance $this- Does anyone have a clue how to fix this? Thanks in advance.

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  • Codeigniter Write_file Question

    - by Brad
    I am writing to a txt file to back up certain posts. Here is my simple code $this->path = APPPATH . "post_backups/"; $string = $this->input->post('post'); $post_title = $this->input->post('post_title'); $this->file = $this->path . $post_title."txt"; write_file($this->file, $string); $this->index(); Every thing works fine except this $this->file = $this->path . $post_title."txt"; I am trying to name my file with the title of the post IE: title.txt. What I am getting it s this "titletxt". How should the $post_title . "txt" be written to provide txt as an extension? Thanks

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  • Order by Domain Extension Name using CodeIgniter Active Record Class

    - by allan
    $extension = “SUBSTRING_INDEX(domain_name, ‘.’, -1)”; $this->db->order_by($extension, “asc”); It says: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘asc LIMIT 50’ at line 44 But its working when I didn’t used the $this-db-order_by Active Record Class such as this one: $this-db-query(“SELECT * FROM domain ORDER BY SUBSTRING_INDEX(domain_name, ‘.’, -1)”); Anyone please help me. Thanks.

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  • Validating forms with regex in codeigniter

    - by Alex
    How can I validate a form using regex in codeiginiter. I'd like to check the input against: ^([0-1][0-9]|[2][0-3]):([0-5][0-9])$ I'm assuming the best way is in some sort of callback. I tried a bunch of ideas on the web but I can't seem to get any working.

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  • Codeigniter: simple form function

    - by Kevin Brown
    I'm stuck writing a simple form...I feel dumb. Here's my controller: function welcome_message(){ //Update welcome message $id = $this->session->userdata('id'); $profile['welcome_message'] = $this->input->post('welcome_message'); $this->db->update('be_user_profiles',$profile, array('user_id' => $id)); } And the html: <?php print form_open('home/welcome_message')?> <input type="checkbox" value="0" checked="false">Don't show me this again</input> <p> <input class="button submit" type="submit" class="close-box" value="Close" /> </p> <?php print form_close()?> Edit I simply need it to submit to a private function and return to the home page (page submitted from).

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  • codeIgniter: pass parameter to a select query from previous query

    - by krike
    I'm creating a little management tool for the browser game travian. So I select all the villages from the database and I want to display some content that's unique to each of the villages. But in order to query for those unique details I need to pass the id of the village. How should I do this? this is my code (controller): function members_area() { global $site_title; $this->load->model('membership_model'); if($this->membership_model->get_villages()) { $data['rows'] = $this->membership_model->get_villages(); $id = 1;//this should be dynamic, but how? if($this->membership_model->get_tasks($id)): $data['tasks'] = $this->membership_model->get_tasks($id); endif; } $data['title'] = $site_title." | Your account"; $data['main_content'] = 'account'; $this->load->view('template', $data); } and this is the 2 functions I'm using in the model: function get_villages() { $q = $this->db->get('villages'); if($q->num_rows() > 0) { foreach ($q->result() as $row) { $data[] = $row; } return $data; } } function get_tasks($id) { $this->db->select('name'); $this->db->from('tasks'); $this->db->where('villageid', $id); $q = $this->db->get(); if($q->num_rows() > 0) { foreach ($q->result() as $task) { $data[] = $task; } return $data; } } and of course the view: <?php foreach($rows as $r) : ?> <div class="village"> <h3><?php echo $r->name; ?></h3> <ul> <?php foreach($tasks as $task): ?> <li><?php echo $task->name; ?></li> <?php endforeach; ?> </ul> <?php echo anchor('site/add_village/'.$r->id.'', '+ add new task'); ?> </div> <?php endforeach; ?> ps: please do not remove the comment in the first block of code!

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  • Sending emails with CodeIgniter in a local XAMPP server

    - by KeyStroke
    Hi, I'm trying to send emails through localhost (XAMPP Windows 1.7.3 installation), but I've been trying for hours with no success. This is the last code I tried: $config = Array( 'protocol' => 'smtp', 'smtp_host' => 'ssl://smtp.gmail.com', 'smtp_port' => 465, 'smtp_user' => '[email protected]', 'smtp_pass' => 'mypassword', ); $this->load->library('email', $config); $this->email->set_newline("\r\n"); $this->email->from('[email protected]', 'My Name'); $this->email->to('[email protected]'); $this->email->subject('Email Test'); $this->email->message('Testing the email class.'); if($this->email->send()) { echo 'Your email was sent.'; } else { show_error($this->email->print_debugger()); } Whenever I tried to load this the page shows that it's loading but nothing happens. Is there anything I need to setup in my server to insure email delivery? I messed with php.ini and sendmail's config a bit with no luck. And openSSL isn't available in case that matters. Any idea what's wrong?

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  • CodeIgniter Error Log Info + Errors

    - by fatnjazzy
    Hi, IS there a way to save in the log, Info + Errors without debug? Howcome debug level apears with info? If i want to log info "Account id 4345 was deleted by Admin", why do i need to see all of these: DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Hooks Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 URI Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Router Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Output Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Input Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Global POST and COOKIE data sanitized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Loader Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/safe_charge.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/web_fx.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: loadutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: objectsutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: logutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: password_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Database Driver Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 cURL Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Account MX_Controller Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/pending_account_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/proccess_accounts_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/web_fx_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_account_type_spreads.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_accounts.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized Thanks

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  • Im having trouble getting SWFUplader to play ball in my codeigniter application

    - by Purplefish32
    I have this peice of code in my handler.js, I'm getting the correct serverData value throught ajax, ( Well it's echoed correctly un the alert box) but no matter what, i just cant seem to enter either of the 'if' blocks. I have double checked the type and it is a string. Something is definetly funky. function uploadSuccess(file, serverData) { try { var progress = new FileProgress(file, this.customSettings.progressTarget); alert(serverData); if(serverData == "uploadSuccess") { progress.setComplete(); progress.setStatus("Completed"); progress.toggleCancel(false); } if(serverData == "uploadError") { progress.setError(); progress.toggleCancel(false); progress.setStatus("Error: X"); progress.toggleCancel(false); } } catch (ex) { this.debug(ex); } }

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  • PHP/Codeigniter processing a list with javascript

    - by user270797
    I have a list of items that the user can select. I want it to be more user friendly than standard checkboxes so I have seperate div's each with a unique id. When user clicks an item, I use javascript to display a tick on top of that item and change the style to show that it is highlighted. Im trying to work out how I can pass the list of id's when the form is submitted. Remember, if the user unticks an item, it should be removed from the list, I was thinking of using comma seperated values in a hidden text field but couldnt work out how to remove items from the start of the list if they were deselected

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  • Seperate Configuration files for each user in codeigniter

    - by Dileep Dil
    is it possible to make Config files for each and every users? Currently i have a Config file named Siteconfig.php for global configuration. Now a user registered,so that i need a configuration file for that user. I have a BANNER ,user uploads images to the server and select some images for that banner. I want to store the names of the images in the configuration file,i know that database is another way. is there any wrong with this ? or is it possible to do this ? Thank you.

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  • Codeigniter view file looping query

    - by user2505513
    Right, I'm unsure about how to code my view file to generate following query results WITHOUT compromising the principles of mvc. Query in model: SELECT * FROM events GROUP BY country, area ORDER BY country, area View: <?php if (isset($query)):?> <?php foreach ($query as $row):?> <h2><?=$row->country?></h2> <h3><?=$row->area?></h3> <?php endforeach;?> <?php endif;?> I want the results to display: England North South West - utilising the GROUP BY parameter As opposed to: England North England South England West Has anybody any advice as to how to achieve this?

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  • CodeIgniter Form Validation

    - by mmcglynn
    I am trying to set up validation on a simple contact form that is created using the form helper. No validation at all occurs. What is wrong? In the code below, the “good” keyword always shows, regardless of what is entered into the form, and the saved values set via set_value are never shown. Controller // Contact function contact() { $data['pageTitle'] = "Contact"; $data['bodyId'] = "contact"; $this->load->library('form_validation'); $config_rules = array ('email' => 'required','message' => 'required'); $this->form_validation->set_rules($config_rules); if ($this->form_validation->run() == FALSE) { echo "bad"; $data['include'] = "v_contact"; $this->load->view('v_template',$data); } else { echo "good"; $data['include'] = "v_contact"; $this->load->view('v_template',$data); } } View echo validation_errors(); echo form_open('events/contact'); // name echo form_label('Name', 'name'); $data = array ( 'name' => 'name', 'id' => 'name', 'maxlength' => '64', 'size' => '40', 'value' => set_value('name') ); echo form_input($data) . "\n<br />"; // email address echo form_label('Email Address', 'email'); $data = array ( 'name' => 'email', 'id' => 'email', 'maxlength' => '64', 'size' => '40', 'value' => set_value('email') ); echo form_input($data) . "\n<br />"; // message echo form_label('Message', 'message'); $data = array ( 'name' => 'message', 'id' => 'message', 'rows' => '8', 'cols' => '35', 'value' => set_value('message') ); echo form_textarea($data) . "\n<br />"; echo form_submit('mysubmit', 'Send Message'); echo form_close();

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  • Codeigniter: Pass data to library funciton

    - by Kevin Brown
    I need my function to do one of two things based on the method variable, but I don't know how to get it done... My controller: function survey($method) { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data); } Library function: function survey_form($container,$method) { if($method == 1){ $this->CI->load->view($container,$data); } if($method == 2){ Do stuff... }

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  • Codeigniter: Controller URI with Library

    - by Kevin Brown
    I have a working controller and library function, but I now need to pass a URI segment to the library for decision making, and I'm stuck. Controller: function survey($method) { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); //Convert the db Object to a row array $data['manager'] = $data['member']->row(); $manager_id = $data['manager']->manager_id; $data['manager'] = $this->home_model->getUser($manager_id); $data['manager'] = $data['manager']->row(); if ($data['manager']->credits == '0') { flashMsg('warning',"You can't complete the assessment until your manager has purchased credit."); redirect('home','location'); } elseif ($data['manager']->test_complete == '3'){ flashMsg('warning',"You already completed the Assessment."); redirect('home','location'); } else{ $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data); } } Library: function survey_form($container) { if($method ==1){ $id = $this->CI->session->userdata('id'); // Setup fields for($i=1;$i<18;$i++){ $fields["a_".$i] = 'Question '.$i; } for($i=1;$i<17;$i++){ $fields["b_".$i] = 'Question '.$i; } $fields["company_name"] = "Company Name"; $fields['company_address'] = "company_address"; $fields['company_phone'] = "company_phone"; $fields['company_state'] = "company_state"; $fields['company_city'] = "company_city"; $fields['company_zip'] = "company_zip"; $fields['job_title'] = "job_title"; $fields['job_type'] = "job_type"; $fields['job_time'] = "job_time"; $fields['department'] = "department"; $fields['supervisor'] = "supervisor"; $fields['vision'] = "vision"; $fields['height'] = "height"; $fields['weight'] = "weight"; $fields['hand_dominance'] = "hand_dominance"; $fields['areas_of_fatigue'] = "areas_of_fatigue"; $fields['injury_review'] = "injury_review"; $fields['job_positive'] = "job_positive"; $fields['risk_factors'] = "risk_factors"; $fields['job_improvement_short'] = "job_improvement_short"; $fields['job_improvement_long'] = "job_improvement_long"; $fields["c_1"] = "Near Lift"; $fields["c_2"] = "Middle Lift"; $fields["c_3"] = "Far Lift"; $this->CI->validation->set_fields($fields); // Set Rules for($i=1;$i<18;$i++){ $rules["a_".$i]= 'hour|integer|max_length[2]'; } for($i=1;$i<17;$i++){ $rules["b_".$i]= 'hour|integer|max_length[2]'; } // Setup form default values $this->CI->validation->set_rules($rules); if ( $this->CI->validation->run() === FALSE ) { // Output any errors $this->CI->validation->output_errors(); } else { // Submit form $this->_submit(); } // Modify form, first load $this->CI->db->from('be_user_profiles'); $this->CI->db->where('user_id' , $id); $user = $this->CI->db->get(); $this->CI->db->from('be_survey'); $this->CI->db->where('user_id' , $id); $survey = $this->CI->db->get(); $user = array_merge($user->row_array(),$survey->row_array()); $this->CI->validation->set_default_value($user); // Display page $data['user'] = $user; $data['header'] = 'Risk Assessment Survey'; $data['page'] = $this->CI->config->item('backendpro_template_public') . 'form_survey'; $this->CI->load->view($container,$data); } else{ redirect('home','location'); } } My library function doesn't know what to do with Method...and I'm confused. Does it have something to do with instances in my library?

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  • if statement inside array : codeigniter

    - by ahmad
    Hello , I have this function to edit all fields that come from the form and its works fine .. function editRow($tableName,$id) { $fieldsData = $this->db->field_data($tableName); $data = array(); foreach ($fieldsData as $key => $field) { $data[ $field->name ] = $this->input->post($field->name); } $this->db->where('id', $id); $this->db->update($tableName, $data); } now I want to add a condition for Password field , if the field is empty keep the old password , I did some thing like that : function editRow($tableName,$id) { $fieldsData = $this->db->field_data($tableName); $data = array(); foreach ($fieldsData as $key => $field) { if ($data[ $field->name ] == 'password' && $this->input->post('password') == '' ) { $data[ 'password' ] => $this->input->post('hide_password'), //'password' => $this->input->post('hide_password'), } else { $data[ $field->name ] => $this->input->post($field->name) } } $this->db->where('id', $id); $this->db->update($tableName, $data); } but I get error ( Parse error: syntax error, unexpected T_DOUBLE_ARROW in ... ) Html , some thing like this : <input type="text" name="password" value=""> <input type="hidden" name="hide_password" value="$row->$password" /> umm , any help ? thanks ..

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  • Load a model in a Codeigniter library

    - by ci
    Hello, people! I have this piece of code: class MY_Language extends CI_Language { function MY_Language() { parent::CI_Language(); $CI =& get_instance(); $CI->load->model('language_model'); $languages = $this->language_model->get_languages(); print_r($languages); } } But I keep getting "Fatal error: Call to undefined function get_instance() in C:\xampp\htdocs\application\libraries\MY_Language.php on line 44". Any ideas? Thanks in advance!

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