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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • TinyMCE: Looking for line count solution.

    - by Thariama
    I am looking for a plugin or code with a functionality like the "line count" or "line number" in common editors. The line number usually is shown on the left border of the editors content. Anyone got an idea how to do it with TinyMCE? Example: line number | content line number one number two 3. one line skipped (three is empty) 5. contents end

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  • MATLAB : search and count (?)

    - by Arkapravo
    Some MATLAB help needed ! I have an set of 1s and 0s, I need to find how many 1s and how many 0s. (i.e. x = [ 1 1 0 0 0 0 0 1 0 0 1 1 ....] ) . I was looking at some search and count inbuilt function, however I have not been successful.

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  • Finding the count of characters and numbers in a string

    - by Aspirant
    Hi I have a table test as below NAME --------- abc1234 XYZ12789 a12X8b78Y9c5Z I try to find out the count of number of numbers and characters in the string as select name,length(replace(translate(lower(name),'abcdefghijklmnopqrstuvwxyz',' '),' ','')) as char_count, length(replace(translate(name,'1234567890',' '),' ','')) as num_count from test6; Its executing fine giving the output NAME CHAR_COUNT NUM_COUNT abc1234 4 3 XYZ12789 5 3 a12X8b78Y9c5Z 7 6 But my question is there any option by not giving the abcdefghijklmnopqrstuvwxyz and 1234567890 manually

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  • to count specific things within a c++ code

    - by ace
    i know this connects to my original question but i put it here so it is seen by people afresh. after passing each line of the code into a string, how can i count the following things: --the number of standalone functions and member functions per class --the number of lines per function?

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  • Count of Sums possibly using group_by

    - by Daniel Johnson
    Say you have a user table and an order table which references user (user has_many orders) and contains an item count field. How could you efficiently ask "how many uses ordered how many items?" That is, to generate something along the lines of: Number of users | sum of items ------------------------------- 5 users | 1 item 4 users | 5 items 1 user | 7 items Thanks in advance.

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  • How to Count tickets as DateWise

    - by user560716
    I have a query regarding my report, the report format is as under **Date** **Received** **Closed** **Pending** 12/01/10 1000 900 100 12/02/10 2000 1000 1000 12/03/10 1500 1300 200 The above report shows the Help Desk tickets Received, Closed, Pending Count as date wise. How can I create a dynamic SQL query to show above result? Received Tickets is calculated on SubmitedDate Closed Tickets is calculated on ClosedDate with status "Closed" same for Pending Tickets whose status is "Pending". Please provide me the idea or some sample SQL queries.

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  • How to count NULL values in MySQL?

    - by abbr
    I want to know how can i find all the values that are NULL in the MySQL database for example I'm trying to display all the users who don't have an average yet. Here is the MySQL code. SELECT COUNT(average) as num FROM users WHERE user_id = '$user_id' AND average IS_NULL

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  • linq group by with count

    - by snorlaks
    Hello, Im trying to write query in linq Select UserId, UserNumber FROM User where UserNumber in (Select UserNumber FROM User group by UserNumber having Count(UserId) = 1) Aby hints ?

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  • SQL top + count() confusion

    - by vasin
    I've got the following table: patients id name diagnosis_id What I need to do is get all the patients with N most popular diagnosis. And I'm getting nothing using this query: SELECT name FROM patients WHERE diagnosis_id IN (SELECT TOP(5) COUNT(diagnosis_id) FROM patients GROUP BY diagnosis_id ORDER BY diagnosis_id) How to fix it?

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  • Wordpress > Custom wp-archives list by year and category with post count in sidebar

    - by David
    So I have been trying to add a custom sidebar archives section to this Wordpress Theme. I am trying to get two separate yearly archive sections, one for category A and one for category B. I need to get a post count and display it as well, to the left of "articles". This is the format I have been trying to get in the sidebar: Category 1 2010 - 5 articles 2009 - 4 articles 2008 - 6 articles 2007 - 5 articles Category 2 2010 - 8 articles 2009 - 3 articles 2008 - 7 articles 2007 - 5 articles This code is pulling the yearly archive, but the links to the yearly archives do not filter by category. However, if Category 1 does not have posts in 2008, 2008 would not show. So I feel like I am really close, but there is something wrong here in the code. I have also been unsuccessful in pulling the post count for the year/category either. Here is what I get: Category 1 2010 - articles (these links all take you to the general yearly archive page, not category specific) 2009 - articles 2007 - articles Category 2 2010 - articles 2009 - articles 2008 - articles 2007 - articles Here is are the functions I am using in my functions.php file, any idea what I am doing wrong? <?php function company_below_sidebar() { global $cat; ?> <div id="press"> <h2>Press</h2> <ul><?php $cat = '1'; wp_get_archives('type=yearly') ?></ul> </div> <div id="news"> <h2>News</h2> <ul><?php $cat = '4'; wp_get_archives('type=yearly') ?></ul> </div> <?php } add_action('thematic_betweenmainasides', 'company_below_sidebar'); function customarchives_join( $x ) { global $wpdb; return $x . " INNER JOIN $wpdb->term_relationships ON ($wpdb->posts.ID = $wpdb- >term_relationships.object_id) INNER JOIN $wpdb->term_taxonomy ON ($wpdb->term_relationships.term_taxonomy_id = $wpdb->term_taxonomy.term_taxonomy_id)"; } function customarchives_where( $x ) { global $wpdb; global $cat; return $x . " AND $wpdb->term_taxonomy.taxonomy = 'category' AND $wpdb->term_taxonomy.term_id IN ($cat)"; } add_filter( 'getarchives_where', 'customarchives_where' ); add_filter( 'getarchives_join', 'customarchives_join' ); function company_monthly_archive_flexible($input) { // Get URL from $input preg_match('(((f|ht){1}tp://)[-a-zA-Z0-9@:%_\+.~#?&;//=]+)', $input, $matches); $url = $matches[0]; // Get content from $input (without the tags) $content = trim(strip_tags($input)); // Seperate each date element and put it in an array $dates = explode(" ", $content); // Get year $year = $dates[0]; // Customize output format $format = "<li><a href='$url'><b>$year -</b> articles</a></li>\n"; echo $format; } add_filter('get_archives_link','company_monthly_archive_flexible'); ?>

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  • Linq2XML: Get the count of elements where candidate has won2

    - by user287798
    I had an XML Document in the format below <Pronvice_Data> <Pronvice>PronviceA</Pronvice> <Registered_Voters>115852</Registered_Voters> <Sam_Kea>100</Sam_Kea> <Jeje>500</Jeje> <John_Doe>400</John_Doe> </Pronvice_Data> <Pronvice_Data> <Pronvice>PronviceA</Pronvice> <Registered_Voters>25852</Registered_Voters> <Sam_Kea>200</Sam_Kea> <Jeje>100</Jeje> <John_Doe>300</John_Doe> </Pronvice_Data> <Pronvice_Data> <Pronvice>PronviceC</Pronvice> <Registered_Voters>317684</Registered_Voters> <Sam_Kea>1000</Sam_Kea> <Jeje>1200</Jeje> <John_Doe>190</John_Doe> </Pronvice_Data> As suggested by help here,I used the code below to give me this format below C# Code: void Main() { XDocument xmlVectors2 = XDocument.Load(@"C:\\Province_Data.xml"); var elemList= from elem in xmlVectors2.Descendants("Province_Data") where elem.Elements().Count() > 1 select elem; foreach(XElement element in elemList) { XElement elem1= new XElement("Candidates", new XElement(element.Element("Sam_Kea").Name), new XElement(element.Element("Jeje").Name), new XElement(element.Element("John_Doe").Name) ); XElement elem2 = new XElement("Provinces", new XAttribute("Province", (string)element.Element("Province").Value), new XAttribute("Registered_Voters",element.Element("Registered_Voters").Value), new XElement ("Candidate", new XAttribute("Name",element.Element("Sam_Kea").Name), new XAttribute("Votes",element.Element("Sam_Kea").Value) ), new XElement ("Candidate", new XAttribute("Name",element.Element("Jeje").Name), new XAttribute("Votes",element.Element("Jeje").Value) ), new XElement ("Candidate", new XAttribute("Name",element.Element("John_Doe").Name), new XAttribute("Votes",element.Element("John_Doe").Value) )); } } New Format: <root> <Candidates> <Sam_Kea/> <Jeje/> <John_Doe/> </Candidates> <Provinces> <Province name='ProvinceA' Registered_Voters='115852'> <Candidate name='Sam_Kea' votes='100'/> <Candidate name='Jeje' votes='500'/> <Candidate name='John_Doe' votes='400'/> </Province> <Province name='ProvinceB' Registered_Voters='25852'> <Candidate name='Sam_Kea' votes='200'/> <Candidate name='Jeje' votes='100'/> <Candidate name='John_Doe' votes='300'/> </Province> <Province name='ProvinceC' Registered_Voters='317684'> <Candidate name='Sam_Kea' votes='1000'/> <Candidate name='Jeje' votes='1200'/> <Candidate name='John_Doe' votes='190'/> </Province> </Provinces> </root> How can i use the "foreach" in in my code to get the result in this link. http://stackoverflow.com/questions/2396203/get-the-count-of-elements-where-candidate-has-won

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  • OpenOffice Calc: How can I count the number of different items with data pilot?

    - by manu
    Hi all, I have a rather long spreadsheet with historical information of issues solved by some user on a colaborative environment. The spreadsheet have the following (relevant) columns date, week no., project, author id, etc... The week no. is calculated from the date, is basically the year concatenated with the week number within that year; for instance, both 2009-02-18 and 2009-02-20 yield the week number 200908 - the 8th week of year 2009; and 2009-02-23 yields 200909 - the 9th week of year 2009. I need to count how many different users (given by author id) contributed to some project, on a weekly basis. I have setup a data pilot with the week as Row Field, the project as the Column Field, and count-author as the Data Field. However, this counts the author id as different instances. This is not what I need. I need to count how many different users contributed to each project on a weekly basis. I expect to get something like: projects week Project1 Project2 Project3 200901 10 2 200902 2 7 Each inner cell containing how many different users contributed. With the count-author configuration, what I get is how many contributions (total) got the project on that week. Is there a way to tell OpenOffice Calc to do what I want?

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  • KVM guest io is much slower than host io: is that normal?

    - by Evolver
    I have a Qemu-KVM host system setup on CentOS 6.3. Four 1TB SATA HDDs working in Software RAID10. Guest CentOS 6.3 is installed on separate LVM. People say that they see guest performance almost equal to host performance, but I don't see that. My i/o tests are showing 30-70% slower performance on guest than on host system. I tried to change scheduler (set elevator=deadline on host and elevator=noop on guest), set blkio.weight to 1000 in cgroup, change io to virtio... But none of these changes gave me any significant results. This is a guest .xml config part: <disk type='file' device='disk'> <driver name='qemu' type='raw'/> <source file='/dev/vgkvmnode/lv2'/> <target dev='vda' bus='virtio'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x05' function='0x0'/> </disk> There are my tests: Host system: iozone test # iozone -a -i0 -i1 -i2 -s8G -r64k random random KB reclen write rewrite read reread read write 8388608 64 189930 197436 266786 267254 28644 66642 dd read test: one process and then four simultaneous processes # dd if=/dev/vgkvmnode/lv2 of=/dev/null bs=1M count=1024 iflag=direct 1073741824 bytes (1.1 GB) copied, 4.23044 s, 254 MB/s # dd if=/dev/vgkvmnode/lv2 of=/dev/null bs=1M count=1024 iflag=direct skip=1024 & dd if=/dev/vgkvmnode/lv2 of=/dev/null bs=1M count=1024 iflag=direct skip=2048 & dd if=/dev/vgkvmnode/lv2 of=/dev/null bs=1M count=1024 iflag=direct skip=3072 & dd if=/dev/vgkvmnode/lv2 of=/dev/null bs=1M count=1024 iflag=direct skip=4096 1073741824 bytes (1.1 GB) copied, 14.4528 s, 74.3 MB/s 1073741824 bytes (1.1 GB) copied, 14.562 s, 73.7 MB/s 1073741824 bytes (1.1 GB) copied, 14.6341 s, 73.4 MB/s 1073741824 bytes (1.1 GB) copied, 14.7006 s, 73.0 MB/s dd write test: one process and then four simultaneous processes # dd if=/dev/zero of=test bs=1M count=1024 oflag=direct 1073741824 bytes (1.1 GB) copied, 6.2039 s, 173 MB/s # dd if=/dev/zero of=test bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test2 bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test3 bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test4 bs=1M count=1024 oflag=direct 1073741824 bytes (1.1 GB) copied, 32.7173 s, 32.8 MB/s 1073741824 bytes (1.1 GB) copied, 32.8868 s, 32.6 MB/s 1073741824 bytes (1.1 GB) copied, 32.9097 s, 32.6 MB/s 1073741824 bytes (1.1 GB) copied, 32.9688 s, 32.6 MB/s Guest system: iozone test # iozone -a -i0 -i1 -i2 -s512M -r64k random random KB reclen write rewrite read reread read write 524288 64 93374 154596 141193 149865 21394 46264 dd read test: one process and then four simultaneous processes # dd if=/dev/mapper/VolGroup-lv_home of=/dev/null bs=1M count=1024 iflag=direct skip=1024 1073741824 bytes (1.1 GB) copied, 5.04356 s, 213 MB/s # dd if=/dev/mapper/VolGroup-lv_home of=/dev/null bs=1M count=1024 iflag=direct skip=1024 & dd if=/dev/mapper/VolGroup-lv_home of=/dev/null bs=1M count=1024 iflag=direct skip=2048 & dd if=/dev/mapper/VolGroup-lv_home of=/dev/null bs=1M count=1024 iflag=direct skip=3072 & dd if=/dev/mapper/VolGroup-lv_home of=/dev/null bs=1M count=1024 iflag=direct skip=4096 1073741824 bytes (1.1 GB) copied, 24.7348 s, 43.4 MB/s 1073741824 bytes (1.1 GB) copied, 24.7378 s, 43.4 MB/s 1073741824 bytes (1.1 GB) copied, 24.7408 s, 43.4 MB/s 1073741824 bytes (1.1 GB) copied, 24.744 s, 43.4 MB/s dd write test: one process and then four simultaneous processes # dd if=/dev/zero of=test bs=1M count=1024 oflag=direct 1073741824 bytes (1.1 GB) copied, 10.415 s, 103 MB/s # dd if=/dev/zero of=test bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test2 bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test3 bs=1M count=1024 oflag=direct & dd if=/dev/zero of=test4 bs=1M count=1024 oflag=direct 1073741824 bytes (1.1 GB) copied, 49.8874 s, 21.5 MB/s 1073741824 bytes (1.1 GB) copied, 49.8608 s, 21.5 MB/s 1073741824 bytes (1.1 GB) copied, 49.8693 s, 21.5 MB/s 1073741824 bytes (1.1 GB) copied, 49.9427 s, 21.5 MB/s I wonder is that normal situation or did I missed something?

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  • LINQ: GroupBy with maximum count in each group

    - by polarbear2k
    Hi, I have a list of duplicate numbers: Enumerable.Range(1,3).Select(o => Enumerable.Repeat(o, 3)).SelectMany(o => o) // {1,1,1,2,2,2,3,3,3} I group them and get quantity of occurance: Enumerable.Range(1,3).Select(o => Enumerable.Repeat(o, 3)).SelectMany(o => o) .GroupBy(o => o).Select(o => new { Qty = o.Count(), Num = o.Key }) Qty Num 3 1 3 2 3 3 What I really need is to limit the quantity per group to some number. If the limit is 2 the result for the above grouping would be: Qty Num 2 1 1 1 2 2 1 2 2 3 1 3 So, if Qty = 10 and limit is 4, the result is 3 rows (4, 4, 2). The Qty of each number is not equal like in example. The specified Qty limit is the same for whole list (doesn't differ based on number). Thanks

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  • In JPA 2, using a CriteriaQuery, how to count results

    - by seanizer
    I am rather new to JPA 2 and it's CriteriaBuilder / CriteriaQuery API: http://java.sun.com/javaee/6/docs/api/javax/persistence/criteria/CriteriaQuery.html http://java.sun.com/javaee/6/docs/tutorial/doc/gjivm.html I would like to count the results of a CriteriaQuery without actually retrieving them. Is that possible, I did not find any such method, the only way would be to do this: CriteriaBuilder cb = entityManager.getCriteriaBuilder(); CriteriaQuery<MyEntity> cq = cb .createQuery(MyEntityclass); // initialize predicates here return entityManager.createQuery(cq).getResultList().size(); And that can't be the proper way to do it... Is there a solution?

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  • How to calculate line count for project

    - by sixtyfootersdude
    I am taking a software engineering class right now. Our assignment is to evaluate Mozilla's Thunderbird. Our assignment is to evaluate the size of Thunderbird. One metric that we need to use is the number of lines of code in the project. (Lines of code meaning not including comments or new lines). Is there a standard way to find the number of lines or am I better off just cracking out a script to do this? I think that I could do something like this: # remove all comments find -name *.java | \ sed "/\/*/,\*\// s/.*//g | \ # remove multiline comments sed s/\/\///g # remove single line comments # count not empty lines find -name *.java | grep -c "<character>" But I would need to do that for each file type. It seems like there should be some utility that does that already. (something mac/unix compatible would be preferable).

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  • Python - retrieving info from a syslog file

    - by Johnny
    Ive been asked to do a program using python for an assignment. Ive been given a syslog file and I have to find things out about it How do I find out how many attempts were made to login to the root account? Any advice would be highly appreciated as Im very new to python an completely lost!

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  • MS-Access 2007 Time Online Report

    - by Daniel
    I have the following data in my database: MemberID | DateTime ------------------------------------- 1 | 31/03/2010 3:45:49 PM 2 | 31/03/2010 3:55:29 PM 1 | 31/03/2010 4:45:49 PM Every time a user is authenticated or un-authenticated this log appears in the database. What I want to be able to do is total the time for a given user and date. Member 1 was online for 1 hour and 37 minutes. I would like to do this with sql as a report in access 2007 if anyone could help, that would be appreciated. Cheers, Daniel

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