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  • django-mptt fields showing up twice, breaking SQL

    - by Dominic Rodger
    I'm using django-mptt to manage a simple CMS, with a model called Page, which looks like this (most presumably irrelevant fields removed): class Page(mptt.Model, BaseModel): title = models.CharField(max_length = 20) slug = AutoSlugField(populate_from = 'title') contents = models.TextField() parent = models.ForeignKey('self', null=True, blank=True, related_name='children', help_text = u'The page this page lives under.') removed fields are called attachments, headline_image, nav_override, and published All works fine using SQLite, but when I use MySQL and try and add a Page using the admin (or using ModelForms and the save() method), I get this: ProgrammingError at /admin/mycms/page/add/ (1110, "Column 'level' specified twice") where the SQL generated is: 'INSERT INTO `kaleo_page` (`title`, `slug`, `contents`, `nav_override`, `parent_id`, `published`, `headline_image_id`, `lft`, `rght`, `tree_id`, `level`, `lft`, `rght`, `tree_id`, `level`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)' for some reason I'm getting the django-mptt fields (lft, rght, tree_id and level) twice. It works in SQLite presumably because SQLite is more forgiving about what it accepts than MySQL. get_all_field_names() also shows them twice: >>> Page._meta.get_all_field_names() ['attachments', 'children', 'contents', 'headline_image', 'id', 'level', 'lft', 'nav_override', 'parent', 'published', 'rght', 'slug', 'title', 'tree_id'] Which is presumably why the SQL is bad. What could I have done that would result in those fields appearing twice in get_all_field_names()?

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  • Django forms, inheritance and order of form fields

    - by Hannson
    I'm using Django forms in my website and would like to control the order of the fields. Here's how I define my forms: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): name = forms.CharField() The name is immutable and should only be listed when the entity is created. I use inheritance to add consistency and DRY principles. What happens which is not erroneous, in fact totally expected, is that the name field is listed last in the view/html but I'd like the name field to be on top of summary and description. I do realize that I could easily fix it by copying summary and description into create_form and loose the inheritance but I'd like to know if this is possible. Why? Imagine you've got 100 fields in edit_form and have to add 10 fields on the top in create_form - copying and maintaining the two forms wouldn't look so sexy then. (This is not my case, I'm just making up an example) So, how can I override this behavior? Edit: Apparently there's no proper way to do this without going through nasty hacks (fiddling with .field attribute). The .field attribute is a SortedDict (one of Django's internal datastructures) which doesn't provide any way to reorder key:value pairs. It does how-ever provide a way to insert items at a given index but that would move the items from the class members and into the constructor. This method would work, but make the code less readable. The only other way I see fit is to modify the framework itself which is less-than-optimal in most situations. In short the code would become something like this: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): def __init__(self,*args,**kwargs): forms.Form.__init__(self,*args,**kwargs) self.fields.insert(0,'name',forms.CharField()) That shut me up :)

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  • How can I filter these Django records?

    - by mipadi
    I have a set of Django models as shown in the following diagram (the names of the reverse relationships are shown in the yellow bubbles): In each relationship, a Person may have 0 or more of the items. Additionally, the slug field is (unfortunately) not unique; multiple Person records may have the same slug fields. Essentially these records are duplicates. I want to obtain a list of all records that meet the following criteria: All duplicate records (that is, having the same slug) with at least one Entry OR at least one Audio OR at least one Episode OR at least one Article. So far, I have the following query: Person.objects.values('slug').annotate(num_records=Count('slug')).filter(num_records__gt=1) This groups all records by slug, then adds a num_records attribute that says how many records have that slug, but the additional filtering is not performed (and I don't even know if this would work right anyway, since, given a set of duplicate records, one may have, e.g., and Entry and the other may have an Article). In a nutshell, I want to find all duplicate records and collapse them, along with their associated models, into one record. What's the best way to do this with Django?

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  • Order in many to many relation in Django model

    - by Pietro Speroni
    I am writing a small website to store the papers I have written. The relation papers<- author is important, but the order of the name of the authors (which one is First Author, which one is second order, and so on) is also important. I am just learning Django so I don't know much. In any case so far I have done: from django.db import models class author(models.Model): Name = models.CharField(max_length=60) URLField = models.URLField(verify_exists=True, null=True, blank=True) def __unicode__(self): return self.Name class topic(models.Model): TopicName = models.CharField(max_length=60) def __unicode__(self): return self.TopicName class publication(models.Model): Title = models.CharField(max_length=100) Authors = models.ManyToManyField(author, null=True, blank=True) Content = models.TextField() Notes = models.TextField(blank=True) Abstract = models.TextField(blank=True) pub_date = models.DateField('date published') TimeInsertion = models.DateTimeField(auto_now=True) URLField = models.URLField(verify_exists=True,null=True, blank=True) Topic = models.ManyToManyField(topic, null=True, blank=True) def __unicode__(self): return self.Title This work fine in the sense that I now can define who the authors are. But I cannot order them. How should I do that? Of course I could add a series of relations: first author, second author,... but it would be ugly, and would not be flexible. Any better idea? Thanks

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  • Django filters - Using an AllValuesFilter (with a LinkWidget) on a ManyToManyField

    - by magnetix
    This is my first Stack Overflow question, so please let me know if I do anything wrong. I wish to create an AllValues filter on a ManyToMany field using the wonderful django-filters application. Basically, I want to create a filter that looks like it does in the Admin, so I also want to use the LinkWidget too. Unfortunately, I get an error (Invalid field name: 'operator') if I try this the standard way: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class SignFilter(LinkOrderFilterSet): operator = django_filters.AllValuesFilter(widget=django_filters.widgets.LinkWidget) class Meta: model = Sign fields = ['operator'] I got around this by creating my own filter with the many to many relationship hard coded: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class MyFilter(django_filters.ChoiceFilter): @property def field(self): cd = {} for row in self.model.objects.all(): orgs = row.operator.select_related().values() for org in orgs: cd[org['id']] = org['name'] choices = zip(cd.keys(), cd.values()) list.sort(choices, key=lambda x:(x[1], x[0])) self.extra['choices'] = choices return super(AllValuesFilter, self).field class SignFilter(LinkOrderFilterSet): operator = MyFilter(widget=django_filters.widgets.LinkWidget) I am new to Python and Django. Can someone think of a more generic/elegant way of doing this?

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  • Django 1.1 template question

    - by Bovril
    Hi All, I'm a little stuck trying to get my head around a django template. I have 2 objects, a cluster and a node I would like a simple page that lists... [Cluster 1] [associated node 1] [associated node 2] [associated node 3] [Cluster 2] [associated node 4] [associated node 5] [associated node 6] I've been using Django for about 2 days so if i've missed the point, please be gentle :) Models - class Node(models.Model): name = models.CharField(max_length=30) description = models.TextField() cluster = models.ForeignKey(Cluster) def __unicode__(self): return self.name class Cluster(models.Model): name = models.CharField(max_length=30) description = models.TextField() def __unicode__(self): return self.name Views - def DSAList(request): clusterlist = Cluster.objects.all() nodelist = Node.objects.all() t = loader.get_template('dsalist.html') v = Context({ 'CLUSTERLIST' : clusterlist, 'NODELIST' : nodelist, }) return HttpResponse(t.render(v)) Template - <body> <TABLE> {% for cluster in CLUSTERLIST %} <tr> <TD>{{ cluster.name }}</TD> {% for node in NODELIST %} {% if node.cluster.id == cluster.id %} <tr> <TD>{{ node.name }}</TD> </tr> {% endif %} {% endfor %} </tr> {% endfor %} </TABLE> </body> Any ideas ?

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  • django dynamically deduce SITE_ID according to the domain

    - by dcrodjer
    I am trying to develop a site which will render multiple customized sites according to the domain name (subdomain to be more precise). My all the domain names are redirected to the So for each site there will be a corresponding model which defines how the site should look (SITE - SITE_SETTINGS) What will be the best way to utilize the django sites framework to get the SITE_ID of the current site from the domain name instead of hard-coding it in the settings files (django sites documentation) and run database queries, render the views accordingly? If using multiple settings file is my only option can this (wsgi script handle domain name) be done? Update So finally, following lukes answer, what I will do is define a custom middleware which makes the views available with the important vars required according to the domain. And as far as sitemaps and comments is concerned, I will have to customize sitemaps app and a custom sites model on which the other models of sites will be based. And since the comments system is based on the hard-coded sitemap ID I can use it just as is on the models (models will already be filtered according to the site based on my sites framework) though the permalink feature will have to be customized. So a lot of customization. Please suggest if I am going wrong anywhere in this because I have to ensure that the features of the project are optimized. Thanks!

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  • Django sub-applications & module structure

    - by Rob Golding
    I am developing a Django application, which is a large system that requires multiple sub-applications to keep things neat. Therefore, I have a top level directory that is a Django app (as it has an empty models.py file), and multiple subdirectories, which are also applications in themselves. The reason I have laid my application out in this way is because the sub-applications are separated, but they would never be used on their own, outside the parent application. It therefore makes no sense to distribute them separately. When installing my application, the settings file has to include something like this: INSTALLED_APPS = ( ... 'myapp', 'myapp.subapp1', 'myapp.subapp2', ... ) ...which is obviously suboptimal. This also has the slightly nasty result of requiring that all the sub-applications are referred to by their "inner" name (i.e. subapp1, subapp2 etc.). For example, if I want to reset the database tables for subapp1, I have to type: python manage.py reset subapp1 This is annoying, especially because I have a sub-app called core - which is likely to conflict with another application's name when my application is installed in a user's project. Am I doing this completely wrongly, or is there away to force these "inner" apps to be referred to by their full name?

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  • Django Model Formset Pre-Filled Value Problem

    - by user552377
    Hi, i'm trying to use model formsets with Django. When i load forms template, i see that it's filled-up with previous values. Is there a caching mechanism that i should stop, or what? Thanks for your help, here is my code: models.py class FooModel( models.Model ): a_field = models.FloatField() b_field = models.FloatField() def __unicode__( self ): return self.a_field forms.py from django.forms.models import modelformset_factory FooFormSet = modelformset_factory(FooModel) views.py def foo_func(request): if request.method == 'POST': formset = FooFormSet(request.POST, request.FILES, prefix='foo_prefix' ) if formset.is_valid(): formset.save() return HttpResponseRedirect( '/true/' ) else: return HttpResponseRedirect( '/false/' ) else: formset = FooFormSet(prefix='foo_prefix') variables = RequestContext( request , { 'formset':formset , } ) return render_to_response('footemplate.html' , variables ) template: <form method="post" action="."> {% csrf_token %} <input type="submit" value="Submit" /> <table id="FormsetTable" border="0" cellpadding="0" cellspacing="0"> <tbody> {% for form in formset.forms %} <tr> <td>{{ form.a_field }}</td> <td>{{ form.b_field }}</td> </tr> {% endfor %} </tbody> </table> {{ formset.management_form }} </form>

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  • Django: Create custom template tag -> ImportError

    - by Alexander Scholz
    I'm sorry to ask this again, but I tried several solutions from stack overflow and some tutorials and I couldn't create a custom template tag yet. All I get is ImportError: No module named test_tag when I try to start the server via python manage.py runserver. I created a very basic template tag (found here: django templatetag?) like so: My folder structure: demo manage.py test __init__.py settings.py urls.py ... templatetags __init__.py test_tag.py test_tag.py: from django import template register = template.Library() @register.simple_tag def test_tag(input): if "foo" == input: return "foo" if "bar" == input: return "bar" if "baz" == input: return "baz" return "" index.html: {% load test_tag %} <html> <head> ... </head> <body> {% cms_toolbar %} {% foobarbaz "bar" %} {% foobarbaz "elephant" %} {% foobarbaz "foo" %} </body> </html> and my settings.py: INSTALLED_APPS = ( ... 'test_tag', ... ) Please let me know if you need further information from my settings.py and what I did wrong so I can't even start my server. (If I delete 'test_tag' from installed apps I can start the server but I get the error that test_tag is not known, of course). Thanks

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  • Performance Problems with Django's F() Object

    - by JayhawksFan93
    Has anyone else noticed performance issues using Django's F() object? I am running Windows XP SP3 and developing against the Django trunk. A snippet of the models I'm using and the query I'm building are below. When I have the F() object in place, each call to a QuerySet method (e.g. filter, exclude, order_by, distinct, etc.) takes approximately 2 seconds, but when I comment out the F() clause the calls are sub-second. I had a co-worker test it on his Ubuntu machine, and he is not experiencing the same performance issues I am with the F() clause. Anyone else seeing this behavior? class Move (models.Model): state_meaning = models.CharField( max_length=16, db_index=True, blank=True, default='' ) drop = models.ForeignKey( Org, db_index=True, null=False, default=1, related_name='as_move_drop' ) class Split(models.Model): state_meaning = models.CharField( max_length=16, db_index=True, blank=True, default='' ) move = models.ForeignKey( Move, related_name='splits' ) pickup = models.ForeignKey( Org, db_index=True, null=False, default=1, related_name='as_split_pickup' ) pickup_date = models.DateField( null=True, default=None ) drop = models.ForeignKey( Org, db_index=True, null=False, default=1, related_name='as_split_drop' ) drop_date = models.DateField( null=True, default=None, db_index=True ) def get_splits(begin_date, end_date): qs = Split.objects \ .filter(state_meaning__in=['INPROGRESS','FULFILLED'], drop=F('move__drop'), # <<< the line in question pickup_date__lte=end_date) elapsed = timer.clock() - start print 'qs1 took %.3f' % elapsed start = timer.clock() qs = qs.filter(Q(drop_date__gte=begin_date) | Q(drop_date__isnull=True)) elapsed = timer.clock() - start print 'qs2 took %.3f' % elapsed start = timer.clock() qs = qs.exclude(move__state_meaning='UNFULFILLED') elapsed = timer.clock() - start print 'qs3 took %.3f' % elapsed start = timer.clock() qs = qs.order_by('pickup_date', 'drop_date') elapsed = timer.clock() - start print 'qs7 took %.3f' % elapsed start = timer.clock() qs = qs.distinct() elapsed = timer.clock() - start print 'qs8 took %.3f' % elapsed

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  • Django Save Incomplete Progress on Form

    - by jimbob
    I have a django webapp with multiple users logging in and fill in a form. Some users may start filling in a form and lack some required data (e.g., a grant #) needed to validate the form (and before we can start working on it). I want them to be able to fill out the form and have an option to save the partial info (so another day they can log back in and complete it) or submit the full info undergoing validation. Currently I'm using ModelForm for all the forms I use, and the Model has constraints to ensure valid data (e.g., the grant # has to be unique). However, I want them to be able to save this intermediary data without undergoing any validation. The solution I've thought of seems rather inelegant and un-django-ey: create a "Save Partial Form" button that saves the POST dictionary converts it to a shelf file and create a "SavedPartialForm" model connecting the user to partial forms saved in the shelf. Does this seem sensible? Is there a better way to save the POST dict directly into the db? Or is an add-on module that does this partial-save of a form (which seems to be a fairly common activity with webforms)? My biggest concern with my method is I want to eventually be able to do this form-autosave automatically (say every 10 minutes) in some ajax/jquery method without actually pressing a button and sending the POST request (e.g., so the user isn't redirected off the page when autosave is triggered). I'm not that familiar with jquery and am wondering if it would be possible to do this.

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  • Modifying Django's pre_save/post_save Data

    - by Rodrogo
    Hi, I'm having a hard time to grasp this post_save/pre_save signals from django. What happens is that my model has a field called status and when a entry to this model is added/saved, it's status must be changed accordingly with some condition. My model looks like this: class Ticket(models.Model): (...) status = models.CharField(max_length=1,choices=OFFERT_STATUS, default='O') And my signal handler, configured for pre_save: def ticket_handler(sender, **kwargs): ticket = kwargs['instance'] (...) if someOtherCondition: ticket.status = 'C' Now, what happens if I put aticket.save() just bellow this last line if statement is a huge iteration black hole, since this action calls the signal itself. And this problem happens in both pre_save and post_save. Well... I guess that the capability of altering a entry before (or even after) saving it is pretty common in django's universe. So, what I'm doing wrong here? Is the Signals the wrong approach or I'm missing something else here? Also, would it be possible to, once this pre_save/post_save function is triggered, to access another model's instance and change a specific row entry on that? Thanks

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  • Evaluating Django Chained QuerySets Locally

    - by jnadro52
    Hello All: I am hoping someone can help me out with a quick question I have regarding chaining Django querysets. I am noticing a slow down because I am evaluating many data points in the database to create data trends. I was wondering if there was a way to have the chained filters evaluated locally instead of hitting the database. Here is a (crude) example: pastries = Bakery.objects.filter(productType='pastry') # <--- will obviously always hit DB, when evaluated cannoli = pastries.filter(specificType='cannoli') # <--- can this be evaluated locally instead of hitting the DB when evaluated, as long as pastries was evaluated? I have checked the docs and I do not see anything specifying this, so I guess it's not possible, but I wanted to check with the 'braintrust' first ;-). BTW - I know that I can do this myself by implementing some methods to loop through these datapoints and evaluate the criteria, but there are so many datapoints that my deadline does not permit me manually implementing this. Thanks in advance.

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  • Planet feed aggregator for django

    - by marcog
    We are looking for a way to integrate a feed aggregator (planet) into a Django site. Ideally, the planet should integrate as part of a page of the site as a whole, rather than a standalone page like all other plants I've seen. We could use an iframe, but then style won't match. The best way might be something that just returns a raw list of last N feed items, which we then insert into a template. Does anyone have any suggestions of how we can achieve this?

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  • Django as Python extension?

    - by NoobDev4iPhone
    I come from php community and just started learning Python. I have to create server-side scripts that manipulate databases, files, and send emails. Some of it I found hard to do in python, comparing to php, like sending emails and querying databases. Where in php you have functions like mysql_query(), or email(), in python you have to write whole bunch of code. Recently I found Django, and my question is: is it a good framework for network-oriented scripts, instead of using it as a web-framework?

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  • How to run Django 1.3/1.4 on uWSGI on nginx on EC2 (Apache2 works)

    - by Tadeck
    I am posting a question on behalf of my administrator. Basically he wants to set up Django app (made on Django 1.3, but will be moving to Django 1.4, so it should not really matter which one of these two will work, I hope) on WSGI on nginx, installed on Amazon EC2. The app runs correctly when Django's development server is used (with ./manage.py runserver 0.0.0.0:8080 for example), also Apache works correctly. The only problem is with nginx and it looks there is something else wrong with nginx / WSGI or Django configuration. His description is as follows: Server has been configured according to many tutorials, but unfortunately Nginx and uWSGI still do not work with application. ProjectName.py: import os, sys, wsgi os.environ.setdefault("DJANGO_SETTINGS_MODULE", "ProjectName.settings") from django.core.wsgi import get_wsgi_application application = get_wsgi_application() I run uWSGI by comand: uwsgi -x /etc/uwsgi/apps-enabled/projectname.xml XML file: <uwsgi> <chdir>/home/projectname</chdir> <pythonpath>/usr/local/lib/python2.7</pythonpath> <socket>127.0.0.1:8001</socket> <daemonize>/var/log/uwsgi/proJectname.log</daemonize> <processes>1</processes> <uid>33</uid> <gid>33</gid> <enable-threads/> <master/> <vacuum/> <harakiri>120</harakiri> <max-requests>5000</max-requests> <vhost/> </uwsgi> In logs from uWSGI: *** no app loaded. going in full dynamic mode *** In logs from Nginx: XXX.com [pid: XXX|app: -1|req: -1/1] XXX.XXX.XXX.XXX () {48 vars in 989 bytes} [Date] GET / => generated 46 bytes in 77 m secs (HTTP/1.1 500) 2 headers in 63 bytes (0 switches on core 0) added /usr/lib/python2.7/ to pythonpath. Traceback (most recent call last): File "./ProjectName.py", line 26, in <module> from django.core.wsgi import get_wsgi_application ImportError: No module named wsgi unable to load app SCRIPT_NAME=XXX.com| Example tutorials that were used: http://projects.unbit.it/uwsgi/wiki/RunOnNginx https://docs.djangoproject.com/en/1.4/howto/deployment/wsgi/ Do you have any idea what has been done incorrectly, or what should be done to make Django work on uWSGI on nginx on EC2?

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  • Deploying Django App with Nginx, Apache, mod_wsgi

    - by JCWong
    I have a django app which can run locally using the standard development environment. I want to now move this to EC2 for production. The django documentation suggests running with apache and mod_wsgi, and using nginx for loading static files. I am running Ubuntu 12.04 on an Ec2 box. My Django app, "ddt", contains a subdirectory "apache" with ddt.wsgi import os, sys apache_configuration= os.path.dirname(__file__) project = os.path.dirname(apache_configuration) workspace = os.path.dirname(project) sys.path.append(workspace) sys.path.append('/usr/lib/python2.7/site-packages/django/') sys.path.append('/home/jeffrey/www/ddt/') os.environ['DJANGO_SETTINGS_MODULE'] = 'ddt.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I have mod_wsgi installed from apt. My apache/httpd.conf contains NameVirtualHost *:8080 WSGIScriptAlias / /home/jeffrey/www/ddt/apache/ddt.wsgi WSGIPythonPath /home/jeffrey/www/ddt <Directory /home/jeffrey/www/ddt/apache/> <Files ddt.wsgi> Order deny,allow Allow from all </Files> </Directory> Under apache2/sites-enabled <VirtualHost *:8080> ServerName www.mysite.com ServerAlias mysite.com <Directory /home/jeffrey/www/ddt/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/jeffrey/www/ddt/logs/apache_error.log CustomLog /home/jeffrey/www/ddt/logs/apache_access.log combined WSGIDaemonProcess datadriventrading.com user=www-data group=www-data threads=25 WSGIProcessGroup datadriventrading.com WSGIScriptAlias / /home/jeffrey/www/ddt/apache/ddt.wsgi </VirtualHost> If I am correct, these 3 files above should correctly allow my django app to run on port 8080. I have the following nginx/proxy.conf file proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; Under nginx/sites-enabled server { listen 80; server_name www.mysite.com mysite.com; access_log /home/jeffrey/www/ddt/logs/nginx_access.log; error_log /home/jeffrey/www/ddt/logs/nginx_error.log; location / { proxy_pass http://127.0.0.1:8080; include /etc/nginx/proxy.conf; } location /media/ { root /home/jeffrey/www/ddt/; } } If I am correct these two files should setup nginx to take requests on the HTTP port 80, but then direct requests to apache which is running the django app on port 8080. If i go to mysite.com, all I see is Welcome to Nginx! Any advice for how to debug this?

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  • Nginx error page using django master page

    - by user835199
    I am using python django to develop a web app and using nginx and gunicorn as servers. I need to define nginx error page (for error codes like 500, 501 etc), but i want to keep the layout same as that in other site pages. For site pages, i use the include functionality of django but in this case, since django won't preprocess the page, i need to create a pure html page. Is there a way to reuse the master page that i created in django for creating this error page?

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  • installing snippets

    - by Sevenearths
    How do I install snippets in django? (specifically this) I have the file /{project}/snippets/EnforceLoginMiddleware.py and I have tried any number of permutations inside MIDDLEWARE_CLASSES to load it as well as googling django snippets install to no avail :( Any help would be grateful :) PS(Why can't I find any documentation or examples on the installation of snippets. Maybe I'm just a bad googler)

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  • django custom command and cron

    - by Hellnar
    Hello I want my customly made django command to be executed every minute, however it seems like python /path/to/project/myapp/manage.py mycommand doesn't seem to work while at the directory python manage.py mycommand works perfectly. How can I achieve this ? I use /etc/crontab with: ****** root python /path/to/project/myapp/manage.py mycommand

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  • Django admin, hide a model

    - by Hellnar
    Hello At the root page of the admin site where registered models appear, I want to hide several models that are registered to the Django admin. If I directly unregister those, I am not able to add new records as the add new symbol "+" dissapears. How can this be done ?

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  • How to detect Browser type in Django ?

    - by AlgoMan
    How can i detect which browser type the client is using. I have a problem where i have to ask people to use different browser (Firefox) instead of IE. How can i get this information. I know http request has this information (Header). How will i get the navigator.appName from the view.py in the Django framework ?

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  • How do I get django comments to join on auth_user

    - by AlexH
    I'm using the django comments framework, and when I list the comments I want to include some of the information stored in auth_user. However, I find I need an extra query for each comment to get the user info. I tried using select_related() when I pull the comments, but this doesn't help. Is there a reason that it's not joining the auth_user table, and is there any way to force it to?

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  • access django session from a decorator

    - by ed1t
    I have a decorator that I use for my views @valid_session from django.http import Http404 def valid_session(the_func): """ function to check if the user has a valid session """ def _decorated(*args, **kwargs): if ## check if username is in the request.session: raise Http404('not logged in.') else: return the_func(*args, **kwargs) return _decorated I would like to access my session in my decoartor. When user is logged in, I put the username in my session.

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