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  • Django: Data corrupted after loading? (possible programmer error)

    - by Rosarch
    I may be loading data the wrong way. excerpt of data.json: { "pk": "1", "model": "myapp.Course", "fields": { "name": "Introduction to Web Design", "requiredFor": [9], "offeringSchool": 1, "pre_reqs": [], "offeredIn": [1, 5, 9] } }, I run python manage.py loaddata -v2 data: Installed 36 object(s) from 1 fixture(s) Then, I go to check the above object using the Django shell: >>> info = Course.objects.filter(id=1) >>> info.get().pre_reqs.all() [<Course: Intermediate Web Programming>] # WRONG! There should be no pre-reqs >>> from django.core import serializers >>> serializers.serialize("json", info) '[{"pk": 1, "model": "Apollo.course", "fields": {"pre_reqs": [11], "offeredIn": [1, 5, 9], "offeringSchool": 1, "name": "Introduction to Web Design", "requiredFor": [9]}}]' The serialized output of the model is not the same as the input that was given to loaddata. The output has a non-empty pre_req list, whereas the input's pre_reqs field is empty. What am I doing wrong?

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  • Sorting related objects in the Django Admin form interface

    - by Carver
    I am looking to sort the related objects that show up when editing an object using the admin form. So for example, I would like to take the following object: class Person(models.Model): first_name = models.CharField( ... ) last_name = models.CharField( ... ) hero = models.ForeignKey( 'self', null=True, blank=True ) and edit the first name, last name and hero using the admin interface. I want to sort the objects as they show up in the drop down by last name, first name (ascending). How do I do that? Context I'm using Django v1.1. I started by looking for help in the django admin docs, but didn't find the solution As you can see in the example, the foreign key is pointing to itself, but I expect it would be the same as pointing to a different model object. Bonus points for being able to filter the related objects, too (eg~ only allow selecting a hero with the same first name)

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  • Django m2m adding field in the secondary table

    - by dana
    I have a model in wich i'm using m2m Django ORM feature, in order to create an aditional table to hold my 'classrom members'. My problem is: the membership to a classroom must be accepted by the invited one, so i need a boolean field :1=accepted, 0=refused/unseen yet. How can i include this boolean variable in the aditionally generated classroom_membership (and NOT in the primary created Classroom table)? class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) #domain = models.EnumField() members = models.ManyToManyField(User,related_name="list of invited members") Thanks in advance!!

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  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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  • CSS Zebra Stripe a Specific Table tr:nth-child(even)

    - by BillR
    I want to zebra stripe only select tables using. I do not want to use jQuery for this. tbody tr:nth-child(even) td, tbody tr.even td {background:#e5ecf9;} When I put that in a css file it affects all tables on all pages that call the same stylesheet. What I would like to do is selectively apply it to specific tables. I have tried this, but it doesn't work. // in stylesheet .zebra_stripe{ tbody tr:nth-child(even) td, tbody tr.even td {background:#e5ecf9;} } // in html <table class="zebra_even"> <colgroup> <col class="width_10em" /> <col class="width_15em" /> </colgroup> <tr> <td>Odd row nice and clear.</td> <td>Some Stuff</td> </tr> <tr> <td>Even row nice and clear but it should be shaded.</td> <td>Some Stuff</td> </tr> </table> And this: <table> <colgroup> <col class="width_10em" /> <col class="width_15em" /> </colgroup> <tbody class="zebra_even"> The stylesheet works as it is properly formatting other elements of the html. Can someone help me with an answer to this problem? Thanks.

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  • Getting a KeyError in DB backend of django-digest

    - by rtmie
    I have just started to integrate django_digest into my app. As a start I have added the @httpdigest decorator to one of my views. If I try to connect to it I get a KeyError exception thrown in django_digest/backend/db.py . Depending on which db I configure I get a different KeyError in a different location. I am using Django 1.2.1, with MySql (also tested with sqlite). I am using the default values for all the settings options. As far as I can see I have followed all instructions but am struggling all day with this. I am using the repository versions of django-digest and python-digest. Any steer would be greatly appreciated. Tracebacks for sqlite and mysql below: with sqlite: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 248, in __call__ signals.request_finished.send(sender=self.__class__) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/dispatch/dispatcher.py", line 162, in send response = receiver(signal=self, sender=sender, **named) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 16, in close_connection _connection.close() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 186, in close if self.settings_dict['NAME'] != ":memory:": KeyError: 'NAME' with mysql: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 142, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 166, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 80, in get_response response = middleware_method(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/middleware.py", line 13, in process_request if (not self._authenticator.authenticate(request) and File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/__init__.py", line 86, in authenticate partial_digest = self._account_storage.get_partial_digest(digest_response.username) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 97, in get_partial_digest cursor = get_connection().cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/__init__.py", line 75, in cursor cursor = self._cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/mysql/base.py", line 281, in _cursor if settings_dict['USER']: KeyError: 'USER'

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  • Google App Engine with local Django 1.1 gets Intermittent Failures

    - by Jon Watte
    I'm using the Windows Launcher development environment for Google App Engine. I have downloaded Django 1.1.2 source, and un-tarrred the "django" subdirectory to live within my application directory (a peer of app.yaml) At the top of each .py source file, I do this: import settings import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' In my file settings.py (which lives at the root of the app directory, as well), I do this: DEBUG = True TEMPLATE_DIRS = ('html') INSTALLED_APPS = ('filters') import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' from google.appengine.dist import use_library use_library('django', '1.1') from django.template import loader Yes, this looks a bit like overkill, doesn't it? I only use django.template. I don't explicitly use any other part of django. However, intermittently I get one of two errors: 1) Django complains that DJANGO_SETTINGS_MODULE is not defined. 2) Django complains that common.html (a template I'm extending in other templates) doesn't exist. 95% of the time, these errors are not encountered, and they randomly just start happening. Once in that state, the local server seems "wedged" and re-booting it generally fixes it. What's causing this to happen, and what can I do about it? How can I even debug it? Here is the traceback from the error: Traceback (most recent call last): File "C:\code\kwbudget\edit_budget.py", line 34, in get self.response.out.write(t.render(template.Context(values))) File "C:\code\kwbudget\django\template\__init__.py", line 165, in render return self.nodelist.render(context) File "C:\code\kwbudget\django\template\__init__.py", line 784, in render bits.append(self.render_node(node, context)) File "C:\code\kwbudget\django\template\__init__.py", line 797, in render_node return node.render(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 71, in render compiled_parent = self.get_parent(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 66, in get_parent raise TemplateSyntaxError, "Template %r cannot be extended, because it doesn't exist" % parent TemplateSyntaxError: Template u'common.html' cannot be extended, because it doesn't exist And edit_budget.py starts with exactly the lines that I included up top. All templates live in a directory named "html" in my root directory, and "html/common.html" exists. I know the template engine finds them, because I start out with "html/edit_budget.html" which extends common.html. It looks as if the settings module somehow isn't applied (because that's what adds html to the search path for templates).

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  • add table row before or after a table row of known ID

    - by Perpetualcoder
    In a table like this: <table> <!-- Insert Row of bun here --> <tr id="meat"> <td>Hamburger</td> </tr/> <!-- Insert Row of bun here --> </table> function AddBefore(rowId){} function AddAfter(rowId){} I need to create methods without using jquery..i am familiar with append after and append before in jquery.. but i am stuck with using palin js.

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  • Django adminsite customize search_fields query

    - by dArignac
    Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

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  • problem in below table:i had table inside table .my inner table contains some text.

    - by Ayyappan.Anbalagan
    Heading ## <tr style=" width:500px; float:left;"> <td style="border: thin ridge #008000; text-align:left;" align="left"; > <table class="" style=" border: 1px solid #800000; width:200px; float:left; height: 200px;"> <tr> <td>&nbsp;stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow&nbsp; </td> </tr> </table> stackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow stackoverflowstackoverflow statackoverflow sta</td> </tr> </table>

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  • django & postgres linux hosting (with SSH access) recommendations

    - by Justin Grant
    We're looking for a good place to host our custom Django app (a fork of OSQA) and its postgresql backend. Requirements include: Linux Python 2.6 or (ideally) Python 2.7 Django 1.2 Postgres 8.4 or later DB backup/restore handled by the hoster, not us OS & dev-platform-stack patching/maintenance handled by the hoster, not us SSH access (so we can pull source code from GitHub, so we can install python eggs, etc.) ability to set up cron jobs (e.g. to send out dail email updates) ability to send up to 10K emails/day good performance (not ganged up with a zillion other sites on one CPU, not starved for RAM) FTP or SCP access to web logs dedicated public IP SSL support Costs under $1000/month for a relatively small site (<5M pageviews/month) Good customer service We already have a prototype site running on EC2 on top of a Bitnami DjangoStack. The problem is that we have to patch the OS, patch postgres, etc. We'd really prefer a platform-as-a-service (PaaS) offering, like Heroku offers for Rails apps, where all we need to worry about is deploying our code instead of worrying about system software patching and maintenance. Google App Engine is closest to what we're looking for, but they don't offer relational DB access (not yet at least). Anyone have a recommendation?

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  • Django running on Apache+WSGI and apache SSL proxying

    - by Lessfoe
    Hi all, I'm trying to rewrite all requests for my Django server running on apache+WSGI ( inside my local network) and configured as the WSGI's wiki how to, except that I set a virtualhost for it. The server which from I want to rewrite requests is another apache server listening on port 80. I can manage it to work well if I don't try to enable SSL connection as the required way to connect. But I need all requests to Django server encrypted with SSL so I generally used this directive to achieve this ( on my public webserver ): Alias /dirname "/var/www/dirname" SSLVerifyClient none SSLOptions +FakeBasicAuth SSLRequireSSL AuthName "stuff name" AuthType Basic AuthUserFile /etc/httpd/djangoserver.passwd require valid-user # redirect all request to django.test:80 RewriteEngine On RewriteRule (.*)$ http://django.test/$1 [P] This configuration works if I try to load a specific page trough the external server from my browser. It is not working clicking my django application urls ( even tough the url seems correct when I put my mouse over). The url my public server is trying to serve use http ( instead of https ) and the directory "dirname" I specified on my apache configuration disappear, so it says that the page was not found. I think it depends on Django and its WSGI handler . Does anybody went trough my same problem? PS: I have already tried to modify the WSGI script . I'm Using Django 1.0.3, Apache 2.2 on a Fedora10 (inside), Apache 2.2 on the public server. Thanks in advance for your help. Fab

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  • 'NoneType' object has no attribute 'day'

    - by Asinox
    Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, thanks guys sorry with my English

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  • Returning user data for forms that have errors in when using ModelForms

    - by Sevenearths
    forms.py from django.forms import ModelForm from client.models import ClientDetails, ClientAddress, ClientPhone from snippets.UKPhoneNumberForm import UKPhoneNumberField class ClientDetailsForm(ModelForm): class Meta: model = ClientDetails class ClientAddressForm(ModelForm): class Meta: model = ClientAddress class ClientPhoneForm(ModelForm): number = UKPhoneNumberField() class Meta: model = ClientPhone views.py from django.shortcuts import render_to_response, redirect from django.template import RequestContext from client.forms import ClientDetailsForm, ClientAddressForm, ClientPhoneForm def new_client_view(request): formDetails = ClientDetailsForm(initial={'marital_status':'u'}) formAddress = ClientAddressForm() formHomePhone = ClientPhoneForm(initial={'phone_type':'home'}) formWorkPhone = ClientPhoneForm(initial={'phone_type':'work'}) formMobilePhone = ClientPhoneForm(initial={'phone_type':'mobi'}) return render_to_response('client/new_client.html', {'formDetails': formDetails, 'formAddress': formAddress, 'formHomePhone': formHomePhone, 'formWorkPhone': formWorkPhone, 'formMobilePhone': formMobilePhone}, context_instance=RequestContext(request)) (the new_client.html is nothing special) How should I write views.py so that if the user's data raises an error, instead of showing them the form again with the errors in but none of their original data, it shows them the form again with the errors AND their original data?

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  • in django admin, can we have a multiple select based on choices

    - by Rasiel
    http://docs.djangoproject.com/en/dev/ref/models/fields/#choices i've read through the documentation and this implies using a database table for dynamic data, however it states choices is meant for static data that doesn't change much, if ever. so what if i want to use choices, but have it select multiple because the data i'm using is quite static, e.g days of the week. is there anyway to achieve this without a database table?

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  • Select distinct values from a table field

    - by alj
    I'm struggling getting my head around the Django's ORM. What I want to do is get a list of distinct values within a field on my table .... the equivalent of one of the following: SELECT DISTINCT myfieldname FROM mytable (or alternatively) SELECT myfieldname FROM mytable GROUP BY myfieldname I'd at least like to do it the Django way before resorting to raw sql.

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  • jquery: remove table row while iterating through table rows

    - by deostroll
    #exceptions is a html table. I try to run the code below, but it doesn't remove the table row. $('#exceptions').find('tr').each(function(){ var flag=false; var val = 'excalibur'; $(this).find('td').each(function(){ if($(this).text().toLowerCase() == val) flag = true; }); if(flag) $(this).parent().remove($(this)); }); What is the correct way to do it?

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  • Update (ajax) only part of table without affecting whole table

    - by ile
    <table width="100%" border="0" cellspacing="0" cellpadding="0" class="list"> <tr> <th><a href="#" class="sortby">Full Name</a></th> <th><a href="#" class="sortby">City</a></th> <th><a href="#" class="sortby">Country</a></th> <th><a href="#" class="sortby">Status</a></th> <th><a href="#" class="sortby">Education</a></th> <th><a href="#" class="sortby">Tasks</a></th> </tr> <div class="dynamicData"> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </tr> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </div> </table> The idea is to update table rows when clicking on link with clasl "sortby" which is part of th table tag. I tried inserting div but this doesn't work. Separating this in two tables is not good solution because witdh in both tables cell are not following each other. Any other solution? Thanks

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  • SQL SERVER – Not Possible – Delete From Multiple Table – Update Multiple Table in Single Statement

    - by pinaldave
    There are two questions which I get every single day multiple times. In my gmail, I have created standard canned reply for them. Let us see the questions here. I want to delete from multiple table in a single statement how will I do it? I want to update multiple table in a single statement how will I do it? The answer is – No, You cannot and you should not. SQL Server does not support deleting or updating from two tables in a single update. If you want to delete or update two different tables – you may want to write two different delete or update statements for it. This method has many issues – from the consistency of the data to SQL syntax. Now here is the real reason for this blog post – yesterday I was asked this question again and I replied my canned answer saying it is not possible and it should not be any way implemented that day. In the response to my reply I was pointed out to my own blog post where user suggested that I had previously mentioned this is possible and with demo example. Let us go over my conversation – you may find it interesting. Let us call the user DJ. DJ: Pinal, can we delete multiple table in a single statement or with single delete statement? Pinal: No, you cannot and you should not. DJ: Oh okey, if that is the case, why do you suggest to do that? Pinal: (baffled) I am not suggesting that. I am rather suggesting that it is not possible and it should not be possible. DJ: Hmm… but in that case why did you blog about it earlier? Pinal: (What?) No, I did not. I am pretty confident. DJ: Well, I am confident as well. You did. Pinal: In that case, it is my word against your word. Isn’t it? DJ: I have proof. Do you want to see it that you suggest it is possible? Pinal: Yes, I will be delighted too. (After 10 Minutes) DJ: Here are not one but two of your blog posts which talks about it - SQL SERVER – Curious Case of Disappearing Rows – ON UPDATE CASCADE and ON DELETE CASCADE – Part 1 of 2 SQL SERVER – Curious Case of Disappearing Rows – ON UPDATE CASCADE and ON DELETE CASCADE – T-SQL Example – Part 2 of 2 Pinal: Oh! DJ: I know I was correct. Pinal: Well, oh man, I did not mean there what you mean here. DJ: I did not understand can you explain it further. Pinal: Here we go. The example in the other blog is the example of the cascading delete or cascading update. I think you may want to understand the concept of the foreign keys and cascading update/delete. The concept of cascading exists to maintain data integrity. If there primary keys get deleted the update or delete reflects on the foreign key table to maintain the key integrity and data consistency. SQL Server follows ANSI Entry SQL with regard to referential integrity between PrimaryKey and ForeignKey columns which requires the inserting, updating, and deleting of data in related tables to be restricted to values that preserve the integrity. This is all together different concept than deleting multiple values in a single statement. When I hear that someone wants to delete or update multiple table in a single statement what I assume is something very similar to following. DELETE/UPDATE Table 1 (cols) Table 2 (cols) VALUES … which is not valid statement/syntax as well it is not ASNI standards as well. I guess, after this discussion with DJ, I realize I need to do a blog post so I can add the link to this blog post in my canned answer. Well, it was a fun conversation with DJ and I hope it the message is very clear now. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Foreign keys in django admin list display

    - by Olivier
    If a django model contains a foreign key field, and if that field is shown in list mode, then it shows up as text, instead of displaying a link to the foreign object. Is it possible to automatically display all foreign keys as links instead of flat text? (of course it is possible to do that on a field by field basis, but is there a general method?) Example: class Author(models.Model): ... class Post(models.Model): author = models.ForeignKey(Author) Now I choose a ModelAdmin such that the author shows up in list mode: class PostAdmin(admin.ModelAdmin): list_display = [..., 'author',...] Now in list mode, the author field will just use the __unicode__ method of the Author class to display the author. On the top of that I would like a link pointing to the url of the corresponding author in the admin site. Is that possible? Manual method: For the sake of completeness, I add the manual method. It would be to add a method author_link in the PostAdmin class: def author_link(self, item): return '<a href="../some/path/%d">%s</a>' % (item.id, unicode(item)) author_link.allow_tags = True That will work for that particular field but that is not what I want. I want a general method to achieve the same effect. (One of the problems is how to figure out automatically the path to an object in the django admin site.)

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  • Re-ordering child nodes in django-MPTT

    - by Dominic Rodger
    I'm using Ben Firshman's fork of django-MPTT (hat tip to Daniel Roseman for the recommendation). I've got stuck trying to re-order nodes which share a common parent. I've got a list of primary keys, like this: ids = [5, 9, 7, 3] All of these nodes have a parent, say with primary key 1. At present, these nodes are ordered [5, 3, 9, 7], how can I re-order them to [5, 9, 7, 3]? I've tried something like this: last_m = MyModel.get(pk = ids.pop(0)) last_m.move_to(last_m.parent, position='first-child') for id in ids: m = MyModel.get(pk = id) m.move_to(last_m, position='right') Which I'd expect to do what I want, per the docs on move_to, but it doesn't seem to change anything. Sometimes it seems to move the first item in ids to be the first child of its parent, sometimes it doesn't. Am I right in my reading of the docs for move_to that calling move_to on a node n with position=right and a target which is a sibling of n will move n to immediately after the target? It's possible I've screwed up my models table in trying to figure this out, so maybe the code above is actually right. It's also possible there's a much more elegant way of doing this (perhaps one that doesn't involve O(n) selects and O(n) updates). Have I misunderstood something? Bonus question: is there a way of forcing django-MPTT to rebuild lft and rght values for all instances of a given model?

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  • django-mptt fields showing up twice, breaking SQL

    - by Dominic Rodger
    I'm using django-mptt to manage a simple CMS, with a model called Page, which looks like this (most presumably irrelevant fields removed): class Page(mptt.Model, BaseModel): title = models.CharField(max_length = 20) slug = AutoSlugField(populate_from = 'title') contents = models.TextField() parent = models.ForeignKey('self', null=True, blank=True, related_name='children', help_text = u'The page this page lives under.') removed fields are called attachments, headline_image, nav_override, and published All works fine using SQLite, but when I use MySQL and try and add a Page using the admin (or using ModelForms and the save() method), I get this: ProgrammingError at /admin/mycms/page/add/ (1110, "Column 'level' specified twice") where the SQL generated is: 'INSERT INTO `kaleo_page` (`title`, `slug`, `contents`, `nav_override`, `parent_id`, `published`, `headline_image_id`, `lft`, `rght`, `tree_id`, `level`, `lft`, `rght`, `tree_id`, `level`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)' for some reason I'm getting the django-mptt fields (lft, rght, tree_id and level) twice. It works in SQLite presumably because SQLite is more forgiving about what it accepts than MySQL. get_all_field_names() also shows them twice: >>> Page._meta.get_all_field_names() ['attachments', 'children', 'contents', 'headline_image', 'id', 'level', 'lft', 'nav_override', 'parent', 'published', 'rght', 'slug', 'title', 'tree_id'] Which is presumably why the SQL is bad. What could I have done that would result in those fields appearing twice in get_all_field_names()?

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  • GAE formpreview

    - by Niklas R
    I'm trying to enable form preview with Google App Engine. Getting the following error message I suspect being mistaken somewhere: ... handler = handler_class() TypeError: __call__() takes at least 2 arguments (1 given) Can you tell what's wrong with my attempt? Here is some of the code. from django.contrib.formtools.preview import FormPreview class AFormPreview(FormPreview): def done(self, request, cleaned_data): # Do something with the cleaned_data, then redirect # to a "success" page. self.response.out.write('Done!') class AForm(djangoforms.ModelForm): text = forms.CharField(widget=forms.Textarea(attrs={'rows':'11','cols':'70','class':'foo'}),label=_("content").capitalize()) def clean(self): cleaned_data = self.clean_data name = cleaned_data.get("name") if not name: raise forms.ValidationError("No name.") # Always return the full collection of cleaned data. return cleaned_data class Meta: model = A fields = ['category','currency','price','title','phonenumber','postaladress','name','text','email'] #change the order ... ('/aformpreview/([^/]*)', AFormPreview(AForm)), UPDATE: Here's a complete app where the preview is not working. Any ideas are most welcome: import cgi from google.appengine.api import users from google.appengine.ext import db from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext.db import djangoforms class Item(db.Model): name = db.StringProperty() quantity = db.IntegerProperty(default=1) target_price = db.FloatProperty() priority = db.StringProperty(default='Medium',choices=[ 'High', 'Medium', 'Low']) entry_time = db.DateTimeProperty(auto_now_add=True) added_by = db.UserProperty() class ItemForm(djangoforms.ModelForm): class Meta: model = Item exclude = ['added_by'] from django.contrib.formtools.preview import FormPreview class ItemFormPreview(FormPreview): def done(self, request, cleaned_data): # Do something with the cleaned_data, then redirect # to a "success" page. return HttpResponseRedirect('/') class MainPage(webapp.RequestHandler): def get(self): self.response.out.write('<html><body>' '<form method="POST" ' 'action="/">' '<table>') # This generates our shopping list form and writes it in the response self.response.out.write(ItemForm()) self.response.out.write('</table>' '<input type="submit">' '</form></body></html>') def post(self): data = ItemForm(data=self.request.POST) if data.is_valid(): # Save the data, and redirect to the view page entity = data.save(commit=False) entity.added_by = users.get_current_user() entity.put() self.redirect('/items.html') else: # Reprint the form self.response.out.write('<html><body>' '<form method="POST" ' 'action="/">' '<table>') self.response.out.write(data) self.response.out.write('</table>' '<input type="submit">' '</form></body></html>') class ItemPage(webapp.RequestHandler): def get(self): query = db.GqlQuery("SELECT * FROM Item ORDER BY name") for item in query: self.response.out.write('<a href="/edit?id=%d">Edit</a> - ' % item.key().id()) self.response.out.write("%s - Need to buy %d, cost $%0.2f each<br>" % (item.name, item.quantity, item.target_price)) class EditPage(webapp.RequestHandler): def get(self): id = int(self.request.get('id')) item = Item.get(db.Key.from_path('Item', id)) self.response.out.write('<html><body>' '<form method="POST" ' 'action="/edit">' '<table>') self.response.out.write(ItemForm(instance=item)) self.response.out.write('</table>' '<input type="hidden" name="_id" value="%s">' '<input type="submit">' '</form></body></html>' % id) def post(self): id = int(self.request.get('_id')) item = Item.get(db.Key.from_path('Item', id)) data = ItemForm(data=self.request.POST, instance=item) if data.is_valid(): # Save the data, and redirect to the view page entity = data.save(commit=False) entity.added_by = users.get_current_user() entity.put() self.redirect('/items.html') else: # Reprint the form self.response.out.write('<html><body>' '<form method="POST" ' 'action="/edit">' '<table>') self.response.out.write(data) self.response.out.write('</table>' '<input type="hidden" name="_id" value="%s">' '<input type="submit">' '</form></body></html>' % id) def main(): application = webapp.WSGIApplication( [('/', MainPage), ('/edit', EditPage), ('/items.html', ItemPage), ('/itemformpreview', ItemFormPreview(ItemForm)), ], debug=True) run_wsgi_app(application)

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  • Django forms, inheritance and order of form fields

    - by Hannson
    I'm using Django forms in my website and would like to control the order of the fields. Here's how I define my forms: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): name = forms.CharField() The name is immutable and should only be listed when the entity is created. I use inheritance to add consistency and DRY principles. What happens which is not erroneous, in fact totally expected, is that the name field is listed last in the view/html but I'd like the name field to be on top of summary and description. I do realize that I could easily fix it by copying summary and description into create_form and loose the inheritance but I'd like to know if this is possible. Why? Imagine you've got 100 fields in edit_form and have to add 10 fields on the top in create_form - copying and maintaining the two forms wouldn't look so sexy then. (This is not my case, I'm just making up an example) So, how can I override this behavior? Edit: Apparently there's no proper way to do this without going through nasty hacks (fiddling with .field attribute). The .field attribute is a SortedDict (one of Django's internal datastructures) which doesn't provide any way to reorder key:value pairs. It does how-ever provide a way to insert items at a given index but that would move the items from the class members and into the constructor. This method would work, but make the code less readable. The only other way I see fit is to modify the framework itself which is less-than-optimal in most situations. In short the code would become something like this: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): def __init__(self,*args,**kwargs): forms.Form.__init__(self,*args,**kwargs) self.fields.insert(0,'name',forms.CharField()) That shut me up :)

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  • How can I filter these Django records?

    - by mipadi
    I have a set of Django models as shown in the following diagram (the names of the reverse relationships are shown in the yellow bubbles): In each relationship, a Person may have 0 or more of the items. Additionally, the slug field is (unfortunately) not unique; multiple Person records may have the same slug fields. Essentially these records are duplicates. I want to obtain a list of all records that meet the following criteria: All duplicate records (that is, having the same slug) with at least one Entry OR at least one Audio OR at least one Episode OR at least one Article. So far, I have the following query: Person.objects.values('slug').annotate(num_records=Count('slug')).filter(num_records__gt=1) This groups all records by slug, then adds a num_records attribute that says how many records have that slug, but the additional filtering is not performed (and I don't even know if this would work right anyway, since, given a set of duplicate records, one may have, e.g., and Entry and the other may have an Article). In a nutshell, I want to find all duplicate records and collapse them, along with their associated models, into one record. What's the best way to do this with Django?

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