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  • PHP SASL(PECL) sasl_server_init(app) works with CLI but not with ApacheModule

    - by ZokRadonh
    I have written a simple auth script so that Webusers can type in their username and password and my PHP script verifies them by SASL. The SASL Library is initialized by php function sasl_server_init("phpfoo"). So phpfoo.conf in /etc/sasl2/ is used. phpfoo.conf: pwcheck_method: saslauthd mech_list: PLAIN LOGIN log_level: 9 So the SASL library now tries to connect to saslauthd process by socket. saslauthd command line looks like this: /usr/sbin/saslauthd -r -V -a pam -n 5 So saslauthd uses PAM to authenticate. In the php script I have created sasl connection by sasl_server_new("php", null, "myRealm"); The first argument is the servicename. So PAM uses the file /etc/pam.d/php to see for further authentication information. /etc/pam.d/php: auth required pam_mysql.so try_first_pass=0 config_file=/etc/pam.d/mysqlconf.nss account required pam_permit.so session required pam_permit.so mysqlconf.nss has all information that is needed for a useful MySQL Query to user table. All of this works perfectly when I run the script by command line. php ssasl.php But when I call the same script via webbrowser(php apache module) I get an -20 return code (SASL_NOUSER). In /var/log/messages there is May 18 15:27:12 hostname httpd2-prefork: unable to open Berkeley db /etc/sasldb2: No such file or directory I do not have anything with a Berkeley db for authentication with SASL. I think authentication using /etc/sasldb2 is the default setting. In my opinion it does not read my phpfoo.conf file. For some reason the php-apache-module ignores the parameter in sasl_server_init("phpfoo"). My first thought was that there is a permission issue. So back in shell: su -s /bin/bash wwwrun php ssasl.php "Authentication successful". - No file-permission issue. In the source of the sasl-php-extension we can find: PHP_FUNCTION(sasl_server_init) { char *name; int name_len; if (zend_parse_parameters(1 TSRMLS_CC, "s", &name, &name_len) == FAILURE) { return; } if (sasl_server_init(NULL, name) != SASL_OK) { RETURN_FALSE; } RETURN_TRUE; } This is a simple pass through of the string. Are there any differences between the PHP CLI and PHP ApacheModule version that I am not aware of? Anyway, there are some interesting log entries when I run PHP in CLI mode: May 18 15:44:48 hostname php: SQL engine 'mysql' not supported May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sqlite May 18 15:44:48 hostname php: sql_select option missing May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sql Those lines are followed by lines of saslauthd and PAM which results in authentication success.(I do not get any of them in ApacheModule mode) Looks like that he is trying auxprop pwcheck before saslauthd. I have no other .conf file in /etc/sasl2. When I change the parameter of sasl_server_init to something other then I get the same error in CLI mode as in ApacheModule mode.

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  • Does PHP have job control like bash does?

    - by Andrew
    Hello, does PHP support something like ampersand in bash (forking)? Let's say I wanted to use cURL on 2 web pages concurrently, so script doesn't have to wait before first cURL command finnishes, how could one achieve that in PHP? Something like this in bash: curl www.google.com & curl www.yahoo.com & wait

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  • Problems with CGI wrapper for PHP

    - by user205878
    I'm having a bugger of a time with a CGI wrapper for PHP. I know very little about CGI and PHP as CGI. Here's what I know about the system: Solaris 10 on a 386 Suhosin PHP normally running as CGI, with cgiwrap (http://cgiwrap.sourceforge.net/). I am not able to find an example wrapper.cgi on the server to look at. Shared hosting (virtual host), so I don't have access to Apache config. But the admins are not helpful. Switching hosts is not an option. Options directive cannot be overridden in .htaccess (ExecCGI, for example). .htaccess: AddHandler php-handler .php Action php-handler "/bin/test.cgi" ~/public_html/bin/test.cgi: #!/usr/bin/sh # Without these 2 lines, I get an Internal Server Error echo "Content-type: text/html" echo "" exec "/path/to/php-cgi" 'foo.php'; /bin/foo.php: <?php echo "this is foo.php!"; Output of http://mysite.com/bin/test.cgi: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; Output of http:/ /mysite.com/anypage.php: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; The things I note are: PHP is being executed, as noted by the X-Powered-By ... header. The source of /bin/test.cgi is output in the results. No matter what I put as the second argument of exec, it isn't passed to the php binary. I've tried '-i' to get phpinfo, '-v' to get the version... When I execute test.cgi via the shell, I get the expected results (the argument is passed to php, and it is reflected in the output). Any ideas about how to get this to work? UPDATE It appears that the reason the source of the test.cgi was appearing was due to errors. Anytime fatal error occurred, either within the cgi itself or with the command being executed by exec, it would cause the source of the cgi to appear. Within test.cgi, I can get the proper output with exec "/path/to/php-cgi" -h (I get the same thing as I would from CLI).

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  • PHP WAMP install php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • PHP WAMP instal php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • PHP: Set max_file_uploads for one file rather than php.ini

    - by Jenkz
    Like many variables in PHP using ini_set() on a page doesn't actually work. I've recently upgraded my PHP version and found that my multiple image uploader is now capped. After 3 hours of frustration, I've found that my new PHP install has the new "max_file_uploads" parameter set to "20". So only the first 7 images get uploaded (each is in three sizes, 7*3=21). I can now change my php.ini value of "max_file_uploads" to 300, but I'd rather not do that side wide. Is there any way to set that value just for a single file (upload.php)? Could a .htaccess file be used for this?

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  • Using PHP with the default Mac Apache + PHP installation

    - by Juan Medín
    Hi, I'm starting to unravel the mysteries of PHP and I configured the pre-installed Snow Leopard PHP and activated the Apache server in the system preferences. So far so good: it works if you put a PHP file in your ~/Sites directory. Since I've my projects in a code/projects directory I created a symbolic link from the ~/Sites dir to the code/projects/one-project/php-dir and bang!, a 403 error: access forbidden. I've been changing the permissions of the dirs to 777, but no luck. Is anyone using the default Snow Leoapard configuration for PHP development and if so, how do you link to your codebase? Thanks in advance, Juan

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  • PHP/Javascript - get php variable within javascript

    - by McNabbToSkins
    I have run into an interesting problem. I am currently developing php page and need to access a php variable within the javascript onload. $(document).ready(function() { var temp = <?php $page_id ?> } is this valid? I know that this might seem weird and not be allowed but I am developing a page that has two popup windows. The windows are created using the same view template and there is no way to distinguish between each other. If I stored a hidden value on the page with information unique to the page like so <input type="hidden" value="<?php $page_id ?> id="page_id" /> if there are two views open at the same time there is no way for me to get a unique page id like so var temp = $("#page_id").val(); Because there are two views witht he same input id that is not unique. Long story short is it valid to reference a php variable in the javascript.

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  • Getting php tips and tutorials as daily emails to improve the knowledge in php programming

    - by Sourabh
    Hi Thanks for your time. This question is related to php programming but not a programming question.I have a young team of php (LAMP + javascript) programmers.I want them to learn better coding and keep themselves updated with the latest advancements in web domain. I was thinking if there was any web site which send daily emails about php questions / problems/ solutions to common problems/ tips which will practically help the people to spend 10-15 minutes daily and enjoy the learning.This will also kind of automate the habit of self learning on daily basis. There are lots of PHP forums and php tutorials website, I tried to google but I did not find any website which does what I am looking for. Please let me know if you know such website.If you have any other ideas to achieve the goal are also welcome. -Sourabh

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  • Error with global variable in php not extending to included php file

    - by phileaton
    I have an html file that calls has a php section in the header like so: $page = basename($_SERVER['PHP_SELF']); Now further down in the html file I have a included footer like so: <?php include("footer.php"); ?> In this script I am referencing the $page variable, but it doesn't find it. I tried echoing the variable and nothing happened. When I place the basename() code in the footer.php file though, it handled it fine. I'd like to be efficient with the coding, so how can I get the footer.php file to get that $page variable? Is there a better way to do this than including the $page variable twice?

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  • Editing PHP using PHP (admin center)

    - by Alec Smart
    Hello, Am developing an admin center where I can edit configuration files (written in PHP). I do NOT want to store these values in a mySQL table (for various reasons). So say my config.php has contents like: <?php $option1 = 1; $option2 = 2; $option4 = 5; $option7 = array('test','a','b',c'); ?> Now say in one of the admin pages I will only be changing a few values like option2 or option4 etc. Any ideas on what would be the best way to go about this. I know one option is to read the PHP file completely and write parts of it using REGEX. Any way to make this more efficent? I don't want the config.php file to break because of some error on the user's end. Any ideas on how to ensure that it works?

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  • jqGrid custom formatter

    - by great_llama
    For one of the columns in my jqGrid, I'm providing a custom formatter function. I'm providing some special cases, but if those conditions aren't met, I'd like to resort to using the built-in date formatter utility method. It doesn't seem that I'm getting the right combination of $.extend() to create the options that method is expecting. My colModel for this column: { name:'expires', index:'7', width:90, align:"right", resizable: false, formatter: expireFormat, formatoptions: {srcformat:"l, F d, Y g:i:s A",newformat:"n/j/Y"} }, And an example of what I'm trying to do function expireFormat(cellValue, opts, rowObject) { if (cellValue == null || cellValue == 1451520000) { // a specific date that should show as blank return ''; } else { // here is where I'd like to just call the $.fmatter.util.DateFormat var dt = new Date(cellValue * 1000); var op = $.extend({},opts.date); if(!isUndefined(opts.colModel.formatoptions)) { op = $.extend({},op,opts.colModel.formatoptions); } return $.fmatter.util.DateFormat(op.srcformat,dt,op.newformat,op); } } (An exception is being thrown in the guts of that DateFormat method, looks like where it's trying to read into a masks property of the options that get passed in) EDIT: The $.extend that put everything in the place it needed was getting it from that global property where the i18n library set it, $.jgrid.formatter.date. var op = $.extend({}, $.jgrid.formatter.date); if(!isUndefined(opts.colModel.formatoptions)) { op = $.extend({}, op, opts.colModel.formatoptions); } return $.fmatter.util.DateFormat(op.srcformat,dt.toLocaleString(),op.newformat,op);

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  • jqGrid dynamic select option

    - by Jo
    I'm creating a jqgrid with drop down columns and I'm using cell editing. I need the options of the drop down columns to change dynamically and I've tried implementing this by setting the column to be: { name: "AccountLookup", index: "AccountLookup", width: 90, editable: true, resizable: true, edittype: "select", formatter: "select" }, and then in the beforeCellEdit event I have: beforeEditCell: function(id, name, val, iRow, iCol) { if(name=='AccountLookup') { var listdata = GetLookupValues(id, name); if (listdata == null) listdata = "1:1"; jQuery("#grid").setColProp(name, { editoptions: { value: listdata.toString()} }) } }, GetLookupValues just returns a string in the format "1:One;2:Two" etc. That works fine however the options are populated one click behind - ie i click on AccountID in row 1, and the dropdown is empty, however when I then click on AccountID in row 3 the options I set in the row 1 click are shown in the row 3 click. And so on. So always one click behind. Is there another way of achieving what I need? Bacially the dropdown options displayed are always changing and I need to load them as user enters the cell for editing. Perhaps I can somehow get at the select control in the beforeEditCell event and manually enter its values instead of using the setColProp call? If so could I get an example of doing that please? Another thing - if the dropdown is empty and a user doesn't cancel the cell edit, the grid script throws an error. I'm using clientarray editing if that makes a difference. Greatly appreciate any help. Regards, Jo

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  • Problem with jqGrid in Internet Explorer 8

    - by Dave Swersky
    I have developed an ASP.NET MVC (version 2 RC) application with a ton of jqGrids. It's working like a champ in Firefox, but I've discovered a problem in IE8. The "Main View" grids can be filtered by a search box or one of a few dropdowns above the grid. I use some javascript to reset the url for the grid, then trigger a reload, thusly: function filterByName(filter) { if (filter == 'All') { $('#list').setGridParam({ url: 'Application/GetApplications' }); $('#list').trigger("reloadGrid"); } else { $('#list').setGridParam({ url: 'Application/GetAppByName/' + filter + '/' }); $('#list').trigger("reloadGrid"); } } This works like magic in Firefox, but I'm getting an HTTP 400 Bad Request when I do this in IE8. The IE8 client-side debugger is like flint and tinder compared to Firebug's flamethrower, so I'm not having much luck figuring out why it breaks in IE8. Has anyone seen this? Also, the jqGrid "trigger" method here is swallowing the AJAX exception. Is there a way to get it to bubble up so I can get to the exception details? UPDATE: The problem was with the syntax in my "onchange" event for the dropdowns. I was using: onchange="filterByMnemonic($('#drpMnemonic')[0].value); Which Firefox apparently doesn't mind but IE sees that as nuthin'. This, however, works in both browsers: onchange = "filterByMnemonic($('#drpMnemonic > option:selected').attr('value'));"

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  • jqGrid local data manipulation; problem with row ids when deleting and adding new rows

    - by Sam
    I'm using jqGrid as a client side grid input, allowing the user to input multiple records before POSTing all the data back at once. I'm having a problem where if the user has added a few records (say 3 ) the id's for the records will be 1,2,3. if the user deletes record 2, you're left with 1 and 3 for the id of the records. When the user now adds a new records, jqGrid assigns that records the id 3 again since it just seems to count the total records and increments it by one for the new record. This causes problems when selecting rows as now the row id's are 1, 3 and 3. Does anyone know how to access the row ids of records as I could probably use the afterSubmit event and reassign the row id's increasing from 1. ( so after i delete row id 2, this will set the other row id's to 1 and 2) Any other suggestions to solve this problem? Thanks edit I've solved this with the following code for the delete navGrid button }).navGrid('#pager', {add:true, del:true, refresh:false, search:false}, { ... }, ##edit parameters { ... }, ##add parameters {reloadAfterSubmit:false, clearAfterAdd:false, afterComplete: function () { ## clear and readd the row data so the row ids are sequential var savedData= $("#inputgrid").jqGrid('getRowData'); $("#inputgrid").jqGrid('clearGridData'); $("#inputgrid").jqGrid('addRowData', 'rn', savedData); } } ##delete parameters ); Basically just saving the grid data and then re-adding it so that the rowids are sequential again. For some reason it causes the row numbers down the left side to go start from 2 instead of one. Edit this was solved by using the latest jqGrid code in GitHub (27th April 2010)

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  • jqGrid > datatype : "local" > get and save (at once) all edited cells of a column ?

    - by Qualliarys
    Hi, i have a grid with a datatype = "local". The data are an array as follows : var mydata = [{id:1,valeur:"a_value",designation:"a_designation"}, {id:2,...}, ...]; The second column (named valeur) is the only editable column of the grid (editable:true set in colModel) In the pager of the grid, i have 2 buttons. One to edit all cells (at once) of the column named valeur: $("#mygrid").jqGrid('navButtonAdd','#pager',{caption:"Edit values", onClickButton:function(){ var ids = $('#mygrid').jqGrid('getDataIDs'); for(var i=0;i<ids.length+1;i++){ $('#mygrid').jqGrid('editRow',ids[i],true);} }}); and another one to save (at once) all the changes of the edited cells: $("#mygrid").jqGrid('navButtonAdd','#pager',{caption:"Save changes", onClickButton:function(){var ids = $('#mygrid').jqGrid('getDataIDs'); for(var i=0;i<ids.length+1;i++){ ... ??? ... }}}); when i use : var rd = $("#mygrid").jqGrid('getRowData',ids[i]); alert("valeur="+rd.valeur); for each display i get something like that: valeur=< input class="editable" role="textbox" name="valeur" id="1_valeur" style="width: 98%;" type="text" ... So, when cells are in edition mode, all rd.valeur are an input text tag ! when they are not, i get the initials values of the cells ! How to get and save all changes of this column (all cells in edition mode)?

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • How to directly send *.php.html files to browser without passing throught PHP? (Apache)

    - by Cédric Girard
    Hi, on my Apache/PHP server, file test.php.html is parsed by PHP, while test.html is not. PHPDOC create a lot of *.php.html files, with a XML header wich is a pain for PHP parser, but how to tell Apache not to pass *.php.html file to PHP and just send back the file to browser? My php.conf file <IfModule prefork.c> LoadModule php5_module modules/libphp5.so </IfModule> <IfModule worker.c> LoadModule php5_module modules/libphp5-zts.so </IfModule> AddHandler php5-script .php AddType text/html .php What can I do? Thanks, Bests regards Cédric

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  • Apache 2.0.55/PHP 5.3.5 Hangs

    - by Rushyo
    Recently inherited a Windows 2k3 server running XAMPP, including ancient copies of PHP, MySQL and Apache. I'm attempting to install a second, up-to-date PHP installation on the machine so I can reference that in future instead of XAMPP's old one. Apache starts up with this new PHP installation happily. Unfortunately, when Apache references the new PHP install, whenever I try a view a page (even a non-PHP page) it hangs. The server simply doesn't respond to any HTTP request - it doesn't crash either. It just sits there with the connection open. There are no errors/warnings/notices in either the PHP or Apache logs. I've pretty much ruled out PHP's extensions (by process of systematic elimination) and most of the INI settings. I've tried reinstalling PHP from scratch. The PHP installation is PHP 5.3.5 x86 thread-safe compiled w/ VC6. The Apache installation is Apache 2.0.55. Anyone encountered similar behaviour?

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  • phpMyAdmin causes php-fpm worker to restart (502 Bad Gateway)

    - by rndbit
    I am trying to set up a test site for myself. Everything works fine except phpMyAdmin. php installation loads my test site scripts, they work fine, however trying to load phpMyAdmin i get 502 Bad Gateway error. Judging from logs (that are not too helpful) it seems that php-fpm worker is crashing each time phpmyadmin is being accessed. No clue how or why.. Does anyone have any idea? nginx log: *3 recv() failed (104: Connection reset by peer) while reading response header from upstream, And php-fpm log: [07-Jun-2012 14:19:51] WARNING: [pool www] child 32179 exited on signal 11 (SIGSEGV) after 3.217902 seconds from start [07-Jun-2012 14:19:51] NOTICE: [pool www] child 32351 started My nginx conf: user nginx; worker_processes 1; error_log /var/log/nginx/error.log; pid /var/run/nginx.pid; events { worker_connections 1024; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; access_log /var/log/nginx/access.log main; sendfile on; keepalive_timeout 65; fastcgi_buffers 8 16k; fastcgi_buffer_size 32k; include /etc/nginx/conf.d/*.conf; server { listen 443 ssl; listen 80; server_name testsite.net www.testsite.net; ssl on; ssl_certificate /var/www/html/admin/ssl/certificate.pem; ssl_certificate_key /var/www/html/admin/ssl/privatekey.pem; ssl_session_timeout 1m; ssl_protocols SSLv2 SSLv3 TLSv1; ssl_ciphers HIGH:!aNULL:!MD5:!kEDH; ssl_prefer_server_ciphers on; access_log off; location ~ \.php$ { root /var/www/html; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include /etc/nginx/fastcgi_params; } location / { root /var/www/html; index index.php; } } } php.ini is standard, with cgi.fix_pathinfo=0 php-fpm.conf: include=/etc/php-fpm.d/*.conf [global] pid = /var/run/php-fpm/php-fpm.pid error_log = /var/log/php-fpm/error.log log_level = notice php-fpm.d/www.conf: [www] listen = 127.0.0.1:9000 listen.allowed_clients = 127.0.0.1 user = nginx group = nginx pm = dynamic pm.max_children = 10 pm.start_servers = 1 pm.min_spare_servers = 1 pm.max_spare_servers = 10 slowlog = /var/log/php-fpm/www-slow.log php_flag[display_errors] = on php_admin_value[error_log] = /var/log/php-fpm/www-error.log php_admin_flag[log_errors] = on

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • Where is php executable on Ubuntu?

    - by user601L
    I have installed apache and php. I know php works as I have tested a simple php file on apache server. I'm writing a simple webserver which should be able to process php files. So what I want to do is once I get a request for a php file, something like 'exec php test.php' and get the output and pass it to the client. As I'm not much into Ubuntu, I don't know where is the php executable (should be in \bin right?) to do it. But there is no php file inside \bin or \usr\bin. When I run 'which php' it shows nothing. How do I do this?

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  • APC on PHP 5.4 does not seem to be installed after installation

    - by Burning the Codeigniter
    I've recently upgraded to PHP 5.4 from 5.3.6, I did the command apt-get upgrade php5 with the custom PHP 5.4 repo which I added to the apt-get repositories, now that I upgraded, I restarted php-fastcgi and php5-fpm the APC does not seem to be installed with it after I did pecl install apc it seems to configure and install with the details below: Configuring for: PHP Api Version: 20090626 Zend Module Api No: 20090626 Zend Extension Api No: 220090626 But in my phpinfo() I get this: PHP API 20100412 PHP Extension 20100525 Zend Extension 220100525 Which I don't understand, how can I configure PECL to install with PHP 5.4 with my version, my installation with apc.so is stored to /usr/lib/php5/20090626/ however in /usr/lib/php5/ I have two PHP versions: 20090626 20100525 How can I remove either one and leave PHP 5.4 and manage it to install apc in the correct PHP version? I'm running Ubuntu 11.04 on my server. I need help on this please.

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