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• wmic output well formed xml on remote queries

  - by Mervin

  I want to use the WMI command line tool (wmic) to get information about windows computers on the network and output it as valid xml. However, I can't seem to find the right way to do this as the outputted xml currently contains invalid tokens for which I think I should use the /TRANSLATE:basicxml switch. The command: wmic /NODE:"tech-demo" /IMPLEVEL:Impersonate /USER:MyUser /PASSWORD:MyPassword /PRIVILEGES:DISABLE /AUTHLEVEL:Pkt /AUTHORITY:"ntlmdomain:companydomain.local" PATH Win32_LogicalDisk GET * /FORMAT:rawxml This command runs but returns invalid xml tokens ('<' and '' I think? edit: it appears to fail parsing at ‹) When I add the translate switch I get the message: Can not use credentials for local connections a bit strange that it tries to query the local pc when I add the switch.. Help would be greatly appreciated.

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• Consume an XML Feed with PowerPoint 2010

  - by Matt Schweers

  Hi there. I'm looking for a way to consume an XML feed from a web-service directly into PowerPoint 2010. I found the LiveWeb plugin (http://skp.mvps.org/liveweb.htm) for PowerPoint that, while pretty cool, really only pulls in actual web content in a way that feels more like an iframe. Ideally, I would like to consume raw XML web service/feed with PowerPoint, parse it, and stylize the results. Is this possible? Even reading from a static XML file would be a good start.

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• How to Read XML and Generate SQL Insert

  - by hackerkatt

  I am trying to write a VB Script to read a XML file (downloaded daily) and insert the information into a MSSQL DB. The content of the XML is a list if CDRs (Call Data Records). I need to parse the file and insert the cdr's into a table. I'm a Ruby,Perl,PHP,Javascript,SQL,... programer. But I've really never written any VB Script. I've done some googling and find a number of examples on how to generate XML from a SQL Query, but not the reverse. Any help/suggestions would be greatly appreciated. Thank you!

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• Android app crashes when I change the default xml layout file to another

  - by mib1413456

  I am currently just starting to learn android development and have created a basic "Hello world" app that uses "activity_main.xml" for the default layout. I tried to create a new layout xml file called "new_layout.xml" with a text view, a text field and a button and did the following changes in the MainActivity.java file: setContentView(R.layout.new_layout); I did nothing else expect for adding a new_layout.xml in the res/layout folder, I have tried restarting and cleaning the project but nothing. Below is my activity_main.xml file, new_layout.xml file and MainActivity.java activity_main.xml: <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:id="@+id/container" android:layout_width="match_parent" android:layout_height="match_parent" tools:context="org.example.androidsdk.demo.MainActivity" tools:ignore="MergeRootFrame" /> new_layout.xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal" > <TextView android:id="@+id/textView1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="TextView" /> <EditText android:id="@+id/editText1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_weight="1" android:ems="10" > <requestFocus /> </EditText> <Button android:id="@+id/button1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Button" /> MainActivity.java file package org.example.androidsdk.demo; import android.app.Activity; import android.app.ActionBar; import android.app.Fragment; import android.os.Bundle; import android.view.LayoutInflater; import android.view.Menu; import android.view.MenuItem; import android.view.View; import android.view.ViewGroup; import android.os.Build; public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.new_layout); if (savedInstanceState == null) { getFragmentManager().beginTransaction() .add(R.id.container, new PlaceholderFragment()) .commit(); } } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } @Override public boolean onOptionsItemSelected(MenuItem item) { // Handle action bar item clicks here. The action bar will // automatically handle clicks on the Home/Up button, so long // as you specify a parent activity in AndroidManifest.xml. int id = item.getItemId(); if (id == R.id.action_settings) { return true; } return super.onOptionsItemSelected(item); } /** * A placeholder fragment containing a simple view. */ public static class PlaceholderFragment extends Fragment { public PlaceholderFragment() { } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { View rootView = inflater.inflate(R.layout.fragment_main, container, false); return rootView; } } }

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• Is it possible to use .properties files in web.xml in conjunction with contextConfigLocation paramet

  - by Vladimir

  Here is part of my web.xml: <context-param> <param-name>contextConfigLocation</param-name> <param-value> classpath:application-config.xml </param-value> </context-param> application-config.xml uses property placeholder: <context:property-placeholder location="classpath:properties/db.properties"/> Is it possible somehow to define which properties file to use in web.xml rather than in application-config.xml?

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• How to select visibility of specific worksheet at the opening of Excel using Spreadsheet XML

  - by user211607

  Hi, I am getting spreadsheet xml from a code logic (Flex Grids to spreadsheet xml). I have 3 worksheets (A, B, C) in that spreadsheet xml. I am opening this spreadsheet xml in Excel. I want to view worksheet B when I am opening the spreadhseet xml in Excel. Is there any tag/code, I need to add so that worksheet B will be visible at initial? I can add that code in code logic Thanks ... Atul

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• Print XML file and download it

  - by Pankaj

  I am create xml using serialization and trying to print them using this code string xmlDate = xml.GetXML(); string name = string.Format("{0}_HighEST", ProjectName); Response.AddHeader("Content-disposition", "attachment; filename=\"" + name + "_HighEST.xml\""); Response.ContentType = string.Format("application/.xml", name); how can assign my xmldata to Response so that data will write on downloaded xml?

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• Parsing secure entries XML file with jquery

  - by user573131

  Apologies if this is elementary. I'm primarily a front end designer/dev. I have webform through a form service called wufoo. Wufoo generates a lovely XML (or json) file that can be grabed and parsed. I'm trying to grab the entries xml feed that is associated with the form and parse it via jquery to show who has entered. Im using the following code (which works with a local xml file). http://bostonwebsitemakeover.com/2/test <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"></script> <script> $(document).ready(function () { $.ajax({ type: "GET", url: "people.xml", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("Entry").each(function () { $(".main").append('<div class="entry">' + $(this).find("Field1").text() + ' ' + $(this).find("Field2").text() + ' http://twitter.com/' + $(this).find("Field17").text() + '</div>'); $(".entry").fadeIn(1000); }); } </script> My XML file contains the following: <?xml version="1.0"?> <Entries> <Entry> <EntryId>1</EntryId> <Field1>Meaghan</Field1> <Field2>Severson</Field2> <Field17/> </Entry> <Entry> <EntryId>2</EntryId> <Field1>Michael</Field1> <Field2>Flint</Field2> <Field17>michaelflint</Field17> </Entry> <Entry> <EntryId>3</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> <Entry> <EntryId>4</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> </Entries> I'm wondering how I would do this with the xml file hosted on the wufoo (which is https) So I guess Im asking how do I authenticate the feed via jquery? Or do i need to do this via json? Could someone explain how?

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• Which XML library for what purposes?

  - by John Mee

  A search for "python" and "xml" returns a variety of libraries for combining the two. This list probably faulty: xml.dom xml.etree xml.sax xml.parsers.expat PyXML beautifulsoup? HTMLParser htmllib sgmllib Be nice if someone can offer a quick summary of when to use which, and why.

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• How to replace invalid characters in XML using Javascript or PhP

  - by Raind

  Hi, Need help here for the following: Running PhP, javascript, MySQL, XML. 1) Retrieving file from MySQL and stored it onto XML file. 2) Use javascript function to load XML file (that stored those data). 3) It produces invalid characters in XML file. STEP 1 : Sample of the code in PhP - Loading MySQL DB to store data onto XML file $file= fopen("MapDeals2.xml", "w"); $_xml ="\n"; $_xml .="\n"; while($row1_ThisWeek = mysql_fetch_array($result1_ThisWeek)) { $rRName = $row1_ThisWeek['Retailer_Name']; $rRAddress = $row1_ThisWeek['Retailer_Address1']; $rRAddressPostCode = $row1_ThisWeek['Retailer_AddressPostCode1']; } $_xml .= "<DEAL>\n"; $_xml .= "<DealDescription>" . $d_Description . "</DealDescription>\n"; $_xml .= "<DealURL>" . $d_URL . "</DealURL>\n"; $_xml .= "<DealRName>" . $rRName . "</DealRName>\n"; $_xml .= "<DealRAddress>" . $rRAddress . "</DealRAddress>\n"; $_xml .= "<DealRPostCode>" . $rRAddressPostCode . "</DealRPostCode>\n"; $_xml .= "</DEAL>\n"; } } $_xml .="\n"; fwrite($file, $_xml); fclose($file); STEP 2 : Sample of the code in Javscript - Loading XML file xhttp.open("GET","Test2.xml", false); xhttp.send(""); xmlDoc=xhttp.responseXML; var x=xmlDoc.getElementsByTagName("Employee"); parser = new DOMParser(); xmlDoc = parser.parseFromString("MapDeals2.xml", "text/xml"); for (i=0;i"; . . . } Is there a solution for the above? Looking forward to hear from you soon. Cheers

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• Jquery query XML document where clause

  - by user578406

  I have an XML document that I want to search a specific date and get information for just that date. My XML looks like this: <month id="01"> <day id="1"> <eitem type="dayinfo"> <caption> <text lang="cy">f. 3 r.</text> <text lang="en">f. 3 r.</text> </caption> <ref href="link" id="3"/> <thumb href="link" id="3"/> </eitem> </day> <day id="7"> <eitem type="dayinfo"> <caption> <text lang="cy">f. 5 v.</text> <text lang="en">f. 5 v.</text> </caption> <ref href="link" id="4"/> <thumb href="link" id="4"/> </eitem> </day> <day id="28"> <eitem type="dayinfo2"> <caption id="1"> <text lang="cy">test</text> <text lang="en">test2</text> </caption> <ref href="link" id="1"/> <thumb href="link" id="1"/> </eitem> </day> <day id="28"> <eitem type="dayinfo"> <caption> <text lang="cy">f. 14 v.</text> <text lang="en">f. 14 v.</text> </caption> <ref href="link" id="20"/> <thumb href="link" id="20"/> </eitem> </day> </month> My Jquery looks like this: $(xml).find('month[id=01]').each(function() { $(xml).find("day").each(function() { var day = $(this).attr('id'); alert(day); }); }); In the XML example above I only shown one month, however there are many more. In my JQuery I've tried to do 'Where month = 1' and get all the days info for that month, however that JQuery brings back days for every month. How do I do a where clause with JQuery/JavaScript on a XML document? thanks.

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• How to get the content of two xml tags even when they have another xml tags inside them (PHP-XML)

  - by Harry

  In simple terms, let's suppose you have the following xml structure: <TEXT>Well, I need some help as you <CUSTOMTAG>can</CUSTOMTAG> see.</TEXT> When extracting the text of this node in PHP with strip_tags(), I am not getting the content of tags. First step: What I want to do, is to extract and thus have the following string: "Well, I need some help as you can see." Second step: I would also like to convert the <CUSTOMTAG> and </CUSTOMTAG> to something else, like <e> and </e> for example, and finally have the following string: "Well, I need some help as you <e>can</e> see." I would appreciate only tested and working code. Thanks in advance! Kind Regards

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• Large File Upload in SharePoint 2010

  - by Sahil Malik

  Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). Okay this is a big BIG B-I-G problem. And with SP2010 it’s going to be more prominent, because atleast at the server side, SharePoint can support large files much much better than SharePoint 2007 ever did. The issue with very large files being uploaded through any browser based API are - Reliably transferring gigabyte or bigger files without breakages over a protocol like HTTP, which is better suited for tiny transfers like images and text. Not killing your browser because it has to load all that in memory Not killing your web server because All that you upload through HTTP post, first gets streamed into IIS Memory, w3wp.exe memory before the ENTIRE FILE finishes uploading .. before it is stored. Which means, You cannot show an accurate and live progress bar of the upload, IIS gives you no such accurate metric of an upload. All the counters it gives you are approximate. Your w3wp.exe eats up all server memory – 4GB of it, for a 4GB upload. A thread is kept busy for the entire duration of the upload, thereby greatly limiting your web server’s capability to serve newer requests. Kills effective load balancing. Not killing your content database because, As you are uploading a very large file, that large file gets written sequentially into the DB, and therefore for a very large file very severely impacts the database performance. I had put together another video showing RBS usage in SharePoint 2010. I talked about many practical ramifications of using RBS in SharePoint in that video. Note that enabling large file support will never ever be a point and click job, simply because there are too many questions one needs to ask, and too many things one needs to plan for. However, one part that will remain common across all large file upload scenarios, in SharePoint or outside of SharePoint is to do it efficiently while not killing the web server. In this video, I describe using the Telerik Silverlight Upload control with SharePoint 2010 to enable efficient large file uploads in SharePoint. Presenting .. The video Comment on the article ....

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• How to spread XML Sitemaps over several webservers behind AWS loadbalancer?

  - by Jurik

  We have a web portal with almost a million products and way more other urls. I wrote a script that checks database. If there is a new url needed or an old one update, this script will update/create the XML Sitemaps. But we have several servers behind the load balancer at our rented AWS space. Further this script checks database for each url if there was an update so that it updates the appropriate xml file too. My question is how to spread those XML Sitemaps over all webservers behind this AWS load balancer? Our approaches/ideas: we could just generate them on one server with a cron job and copy them to the other servers, but this could be difficult because of automatic raising numbers of servers and so on. we put them on our S3 - but this one is not avaible thru our domain, so I guess google will have a problem with it I let my script run on every webserver but change it in a way that it will generate each time all xml files if they do not exist. But then I would have conflicts with updated URLs in my database, where I saved timestamp of last changed value of every url Is there another - better - solution that I do not know? Are there any special services by amazon for such cases?

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• Usage of Document() function in XSLT 1.0

  - by infant programmer

  I am triggering the transformation using a .NET code, unless I add "EnableDocumentFunction" property to the XSL-Setting, the program throws error saying .. "Usage of Document() function is prohibited", Actually the program is not editable and a kind of read-only .. is it possible to edit the XSL code itself so that I can use document() function?? The sample XSL and XMLs are Here: Sample XML : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" > <xsl:output method="xml" indent="yes"/> <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> <xsl:variable name="State_Code_Trn"> <State In="California" Out="CA"/> <State In="CA" Out="CA"/> <State In="Texas" Out="TX"/> <State In="TX" Out="TX"/> </xsl:variable> <xsl:template name="testing" match="test_node"> <xsl:variable name="test_val"> <xsl:value-of select="."/> </xsl:variable> <xsl:element name="{name()}"> <xsl:choose> <xsl:when test="document('')/*/xsl:variable[@name='State_Code_Trn'] /State[@In=$test_val]"> <xsl:value-of select="document('')/*/xsl:variable[@name='State_Code_Trn'] /State[@In=$test_val]/@Out"/> </xsl:when> <xsl:otherwise> <xsl:text>Other</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:element> </xsl:template> </xsl:stylesheet> And the sample XML : <?xml version="1.0" encoding="utf-8"?> <root> <test_node>California</test_node> <test_node>CA</test_node> <test_node> CA</test_node> <test_node>Texas</test_node> <test_node>TX</test_node> <test_node>CAA</test_node> <test_node></test_node> </root>

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• XMl to XHTML using XSL with namespace

  - by user256007

  How to handle XML Elements with namespace in an XSL. Here goes my XML Document <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xml" href="wpanel.xsl" ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:bong="http://bong/glob/wpanel" xml:lang="en" lang="en"> <head> <title> Transitional DTD XHTML Example </title> <link rel="stylesheet" type="text/css" href="wpanel.css" /> </head> <body> <bong:QButton text="Submit"></bong:QButton> <bong:QButton text="Reset"></bong:QButton> </body> </html> and My XSL goes here <?xml version="1.0" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:bong="http://bong/glob/wpanel" xmlns:fn="http://www.w3.org/2005/xpath-functions" > <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" /> <xsl:template match="*|@*"> <xsl:copy> <xsl:apply-templates select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <xsl:template match="processing-instruction()|comment()"> <xsl:copy>.</xsl:copy> </xsl:template> I want to copy the elements without bong namespace as it is But transform those using the bong namespace. I think there will be an xsl element or attribute for that.I've serched the net. but haven't found yet. Thank You.

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• Validation using JAXB and Stax to marshal XML document

  - by bajafresh4life

  I have created an XML schema (foo.xsd) and used xjc to create my binding classes for JAXB. Let's say the root element is "collection" and I am writing N "document" objects, which are complex types. Because I plan to write out large XML files, I am using Stax to write out the "collection" root element, and JAXB to marshal document subtrees using Marshaller.marshal(JAXBElement, XMLEventWriter). This is the approach recommended by jaxb's unofficial user's guide: https://jaxb.dev.java.net/guide/Different_ways_of_marshalling.html#Marshalling_into_a_subtree My question is, how can I validate the XML while it's being marshalled? If I bind a schema to the JAXB marshaller (using Marshaller.setSchema()), I get validation errors because I am only marshalling a subtree (it's complaining that it's not seeing the "collection" root element"). I suppose what I really want to do is bind a schema to the Stax XMLEventWriter or something like that. Any comments on this overall approach would be helpful. Basically I want to be able to use JAXB to marshal and unmarshal large XML documents without running out of memory, so if there's a better way to do this let me know.

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• Parsing XML via jQuery, nested loops

  - by Coughlin

  I am using jQuery to parse XML on my page using $.ajax(). My code block is below and I can get this working to display say each result on the XML file, but I am having trouble because each section can have MORE THAN ONE and im trying to print ALL grades that belong to ONE STUDENT. Here is an example of the XML. <student num="505"> <name gender="male">Al Einstein</name> <course cid="1">60</course> <course cid="2">60</course> <course cid="3">40</course> <course cid="4">55</course> <comments>Lucky if he makes it to lab, hopeless.</comments> </student> Where you see the I am trying to get the results to print the grades for EACH student in each course. Any ideas on what I would do? Thanks, Ryan $.ajax({ type: "GET", url: "final_exam.xml", dataType: "xml", success: function(xml) { var student_list = $('#student-list'); $(xml).find('student').each(function(){ $(xml).find('course').each(function(){ gradeArray = $(this).text(); console.log(gradeArray); }); var name = $(this).find("name").text(); var grade = $(this).find("course").text(); var cid = $(this).find("course").attr("cid"); //console.log(cid); student_list.append("<tr><td>"+name+"</td><td>"+cid+"</td><td>"+grade+"</td></tr>"); }); } });

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• Java+DOM: How do I convert a DOM tree without namespaces to a namespace-aware DOM tree?

  - by java.is.for.desktop

  Hello, everyone! I receive a Document (DOM tree) from a certain API (not in JDK). Sadly, this Document is not namespace-aware. As far as I know DOM, once generated, namespace-awareness can't be "added" afterwards. When converting this Document using a Transformer to a string, the XML is correct. Elements have xmlns:... attributes and name prefixes. But from the DOM point of view, there are no namespaces and no prefixes. I need to be able to convert this Document into a new Document which is namespace-aware. Yes, I could do this by just converting it to a string and back to DOM with namespaces enabled. But: nodes of the original tree have user-objects set. Converting to string and back would make a mapping of these user-objects to the new Document very complicated, if not impossible. So I really need a way to convert non-namespace DOM to namespace DOM. Are there any more-or-less straightforward solutions for this? Worst case (what I'm hoping to avoid) would be to manually iterate through old Document tree and create new namespace-aware Node for each old Node. Doing so, one had to manually "parse" namespace prefixes, watch out for xmlns-attributes, and maintain a mapping between prefixes and namespace-URIs. Lots of things to go wrong.

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• XML::LibXML::XPathContext - Question

  - by sid_com

  This script works with and without XPathContext. Why should I use it with XPathContext? #!/usr/bin/env perl use warnings; use strict; use XML::LibXML; use 5.012; my $parser = XML::LibXML->new; my $doc = $parser->parse_string(<<EOT); <?xml version="1.0"?> <xml> Text im Dokument <element id="myID" name="myname" style="old" /> <object objid="001" objname="Object1" /> <element id="002" name="myname" /> </xml> EOT #/ # without XPathContext my $nodes = $doc->findnodes( '/xml/element[@id=002]' ); # with XPathContext #my $root = $doc->documentElement; #my $xc = XML::LibXML::XPathContext->new( $root ); #my $nodes = $xc->findnodes( '/xml/element[@id=002]' ); for my $node ( $nodes->get_nodelist ) { say "Node: ", $node->nodeName; print "Attribute: "; print $_->getName, '=', $_->getValue, ' ' for $node->attributes; say ""; }

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• Update element values using xml.dom.minidom

  - by amnesia-55

  Hello, I have an XML structure which looks similar to: <Store> <foo> <book> <isbn>123456</isbn> </book> <title>XYZ</title> <checkout>no</checkout> </foo> <bar> <book> <isbn>7890</isbn> </book> <title>XYZ2</title> <checkout>yes</checkout> </bar> </Store> Using xml.dom.minidom only (restrictions) i would like to 1)traverse through the XML file 2)Search/Get for particular element, depending on its parent Example: checkout element for author1, isbn for author2 3)Change/Set that element's value 4)Write the new XML structure to a file Can anyone help here? Thank you! UPDATE: This is what i have done till now import xml.dom.minidom checkout = "yes" def getLoneChild(node, tagname): assert ((node is not None) and (tagname is not None)) elem = node.getElementsByTagName(tagname) if ((elem is None) or (len(elem) != 1)): return None return elem def getLoneLeaf(node, tagname): assert ((node is not None) and (tagname is not None)) elem = node.getElementsByTagName(tagname) if ((elem is None) or (len(elem) != 1)): return None leaf = elem[0].firstChild if (leaf is None): return None return leaf.data def setcheckout(node, tagname): assert ((node is not None) and (tagname is not None)) child = getLoneChild(node, 'foo') Check = getLoneLeaf(child[0],'checkout') Check = tagname return Check doc = xml.dom.minidom.parse('test.xml') root = doc.getElementsByTagName('Store')[0] output = setcheckout(root, checkout) tmp_config = '/tmp/tmp_config.xml' fw = open(tmp_config, 'w') fw.write(doc.toxml()) fw.close()

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• Problem with XML encoding of database contents with Latin characters

  - by user89691

  I have an ASP Access database that contains strings in various European languages. The database was populated prior by agents in the respective countries. It contains entries with accented etc characters as you would expect. If I open the database with MS Access these characters show up fine. For example the the German equivalent of "Open" shows as "Öffnen" (hopefully you can see an "O" with 2 dots above it!). I have ASP code that reads the database and returns records in XML. The text is passed to XMLEncode to construct the XML, but that only seems to deal with the 5 specials like "<", "&", etc. If I dump the XML the accented characters are unchanged. <English>Open</English> <German>Öffnen</German> If I look at the raw packets with Wireshark I see that the "Ö" byte is hex D6, which appears to be it's decimal Unicode and ISO 8859-1 value. The problem starts when I try to parse the XML in client-side JS. I get: "An invalid character was found in text content" from IE. FF and Chrome happily accept the XML without hiccup but the browser shows the "Ö" character as a diamond with a question mark inside. http://www.validome.org/xml/validate/ reports "encoding error." http://www.w3schools.com/dom/dom_validate.asp thinks it is fine. The XML is UTF-8 encoded. What do I need to do to have IE accept my XML without complaint? What do I need to do to have browsers display the stuff correctly?

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• Writing Russian in XML

  - by zavié

  Hi, I am writing a Xml Tag Renamer class with Java which reads in a XML, renames the tags and write them back into another XML file using DocumentBuilderFactory and TransformerFactory (text nodes are preserved). It worked fine before with German and English texts, until today, when I tried to rename a XML file with russian text. Instead of the source texts I got ????? in the newly created XML file. I've tried setting Encoding Any idea how to correct this? Thanks! PS. Strings were correct before entering TransformerFactory, as I checked in the debugger. I've tried setting OutputKeys.ENCODING to UTF-8 and ISO-8859-5. None of them helped. The Transformer part: // Output the XML // Set up a transformer TransformerFactory transFactory = TransformerFactory.newInstance(); Transformer transformer = transFactory.newTransformer(); transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no"); // Fix to a bug about indent in transformer transformer.setOutputProperty ("{http://xml.apache.org/xslt}indent-amount", "4"); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); // TODO encoding parameter transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8"); // Create string from xml tree StringWriter sw = new StringWriter(); StreamResult result = new StreamResult(sw); DOMSource source = new DOMSource(doc); transformer.transform(source, result); String xmlString = sw.toString(); xmlString.replaceAll("\n", System.getProperty("line.separator")); // Write to file BufferedWriter output = new BufferedWriter(new FileWriter(outputPath)); output.write(xmlString); output.close();

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• LaTeX book class: Twosided document with wrong margins

  - by fgysin

  I am trying to write my thesis in latex... Cannot get the layout straight though :? I'm using the following document class: \documentclass[11pt,a4paper,twoside,openright]{book} My problem is: on the odd numbered pages there is a big margin right, and a small margin left - it should be the other way round... (for binding & stuff) I am a little puzzled by this - am I just to stupid to see the obvious? The odd page numbers appear on the 'right' page of a bound document, so there needs to be a larger margin left for bindin. Right? Why does LaTeX not behave like this? Here is the full code to produce a small Tex file that shows my problem: \documentclass[11pt,a4paper,twoside,openright]{book} \begin{document} \chapter{blah} Lorem ipsum ius et accumsan tractatos, aliquip deterruisset cu usu. Ea soleat eirmod nostrud eum, est ceteros similique ad, at mea tempor petentium. At decore neglegentur quo, ea ius doming dictas facilis, duo ut porro nostrum suavitate. \end{document}

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• Flash AS3 load file xml

  - by Elias

  Hello, I'm just trying to load an xml file witch can be anywere in the hdd, this is what I have done to browse it, but later when I'm trying to load the file it would only look in the same path of the swf file here is the code package { import flash.display.Sprite; import flash.events.; import flash.net.; public class cargadorXML extends Sprite { public var cuadro:Sprite = new Sprite(); public var file:FileReference; public var req:URLRequest; public var xml:XML; public var xmlLoader:URLLoader = new URLLoader(); public function cargadorXML() { cuadro.graphics.beginFill(0xFF0000); cuadro.graphics.drawRoundRect(0,0,100,100,10); cuadro.graphics.endFill(); cuadro.addEventListener(MouseEvent.CLICK,browser); addChild(cuadro); } public function browser(e:Event) { file = new FileReference(); file.addEventListener(Event.SELECT,bien); file.browse(); } public function bien(e:Event) { xmlLoader.addEventListener(Event.COMPLETE, loadXML); req=new URLRequest(file.name); xmlLoader.load(req); } public function loadXML(e:Event) { xml=new XML(e.target.data); //xml.name=file.name; trace(xml); } } } when I open a xml file that isnt it the same directory as the swf, it gives me an unfound file error. is there anything I can do? cause for example for mp3 there is an especial class for loading the file, see http://www.flexiblefactory.co.uk/flexible/?p=46 thanks

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