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  • SQL Select syntax error

    - by Odette
    hi guys thanks for your help yesterday. I am now trying to incorporate the query from yesterday into an existing query so I can show the highest itemcode's reporting group in the existing query..but I have a syntax error somewhere at my Select statement. ERROR: Keyword SELECT not expected. I have tried putting brackets at every possible place but still no go..can you please help? (ps-this whole query has been giving me nightmares!) WITH CALC1 AS (SELECT OTQUOT, OTIT01 AS ITEMS, ROUND(OQCQ01 * OVRC01,2) AS COST FROM @[email protected] WHERE OTIT01 < '' UNION ALL SELECT OTQUOT, OTIT02 AS ITEMS, ROUND(OQCQ02 * OVRC02,2) AS COST FROM @[email protected] WHERE OTIT02 < '' UNION ALL SELECT OTQUOT, OTIT03 AS ITEMS, ROUND(OQCQ03 * OVRC03,2) AS COST FROM @[email protected] WHERE OTIT03 < '' UNION ALL SELECT OTQUOT, OTIT04 AS ITEMS, ROUND(OQCQ04 * OVRC04,2) AS COST FROM @[email protected] WHERE OTIT04 < '' UNION ALL SELECT OTQUOT, OTIT05 AS ITEMS, ROUND(OQCQ05 * OVRC05,2) AS COST FROM @[email protected] WHERE OTIT05 < '' UNION ALL SELECT OTQUOT, OTIT06 AS ITEMS, ROUND(OQCQ06 * OVRC06,2) AS COST FROM @[email protected] WHERE OTIT06 < '' UNION ALL SELECT OTQUOT, OTIT07 AS ITEMS, ROUND(OQCQ07 * OVRC07,2) AS COST FROM @[email protected] WHERE OTIT07 < '' UNION ALL SELECT OTQUOT, OTIT08 AS ITEMS, ROUND(OQCQ08 * OVRC08,2) AS COST FROM @[email protected] WHERE OTIT08 < '' UNION ALL SELECT OTQUOT, OTIT09 AS ITEMS, ROUND(OQCQ09 * OVRC09,2) AS COST FROM @[email protected] WHERE OTIT09 < '' UNION ALL SELECT OTQUOT, OTIT10 AS ITEMS, ROUND(OQCQ10 * OVRC10,2) AS COST FROM @[email protected] WHERE OTIT10 < '' ) (SELECT OTQUOT, DESC FROM ( SELECT OTQUOT, ITEMS, B.IXRPGP AS GROUP, C.OTRDSC AS DESC, COST, ROW_NUMBER() OVER (ORDER BY COST DESC) AS RN FROM CALC1 AS A INNER JOIN @[email protected] AS B ON (A.ITEMS = B.IKITMC) INNER JOIN DATAGRP.GDSGRP AS C ON (B.IXRPGP = C.OKRPGP) ) T WHERE T.RN = 1) SELECT A.OKPBRN, A.OCAREA, A.OTCCDE, A.OTCNAM, A.OTSMAN, A.OKPBRN||A.OAPNUM AS OTQUOT, A.OTONUM, A.OTCAD1, A.OTCAD2, A.OTCAD3, A.OTPCDE, A.OTDEL1, A.OTDEL2, A.OTDEL3, CHAR(DATE(CASE WHEN SUBSTR(A.ODOQDT,5,4) = '0000' THEN '0001' ELSE SUBSTR(A.ODOQDT,5,4) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,4,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,3,2) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,1,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,1,2) END), ISO) AS ODOQDT_CCYYMMDD, CHAR(DATE(CASE WHEN SUBSTR(A.ODDELD,7,2) = '' THEN '0001' ELSE '20'||SUBSTR(A.ODDELD,7,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,4,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,4,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,1,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,1,2) END), ISO) AS ODDELD_CCYYMMDD, B.DESC, A.OVQTVL FROM @[email protected] AS A INNER JOIN CALC1 AS B ON (A.OKPBRN||A.OAPNUM = B.OTQUOT) WHERE A.OKPBRN = '@OKPBRN@' AND A.OTCCDE NOT LIKE '*DEP%' AND CHAR(DATE(CASE WHEN SUBSTR(A.ODOQDT,5,4) = '0000' THEN '0001' ELSE SUBSTR (A.ODOQDT,5,4) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,4,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,3,2) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,1,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,1,2) END), ISO) = CHAR(CURDATE() - 3 MONTH, ISO) AND A.OCQF01 = '0' AND A.OCQF02 = '0' AND A.OCQF04 = '0' AND A.OCQF05 = '0' AND A.OCQF06 = '0' AND A.OCQF07 = '0' AND A.OCQF08 = '0' AND A.OCQF09 = '0' AND A.OCQF10 = '1' AND A.OTCGRP LIKE 'S/%' ORDER BY A.OTSMAN ASC, A.OVQTVL DESC, CHAR(DATE(CASE WHEN SUBSTR(A.ODDELD,7,2) = '' THEN '0001' ELSE '20'||SUBSTR(A.ODDELD,7,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,4,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,4,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,1,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,1,2) END),ISO) ASC

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  • AJAX Generated Select Won't Redirect

    - by James
    So, basically I have this select / drop down menu that I use AJAX to retrieve and create, though when an option is selected (so onChange) I want it to redirect! Though, this still isn't working, I don't get any errors thrown when trying, and tried to do alert() debug methods yet the alerts don't get called. jquery $("#schoolMenu").change(function() { option = $("#schoolMenu option:selected").text(); alert(option); if(option != "- Please Select -") { window.location = "http://www.itmustbecollege.com/pics/pics-from-"+$("#schoolMenu option:selected").val(); } }); This is what is used to call the AJAX // // Populate Schools // $("#state").change(function() { option = $("#state option:selected").text(); if($(this).attr("class") == "menu") { if(option != "- Please Select -") { $.ajax({ type: "GET", url: "/includes/functions.php", data: "f=school&p="+option+"&m=yes", success: function(msg) { $("#fSchool").html("<p style=\"margin-left: 20px;\">Select School:</p>"+ msg); $("#fSchool").show(); $("#school").focus(); } }); } else { $("#fSchool").html(""); $("#fSchool").hide(); } } else { if(option != "- Please Select -") { $.ajax({ type: "GET", url: "/includes/functions.php", data: "f=school&p="+option, success: function(msg) { $("#fSchool").html(msg); $("#fSchool").show(); $("#school").focus(); } }); } else { $("#fSchool").html(""); $("#fSchool").hide(); } } }); It loads perfectly, if you look at http://www.itmustbecollege.com/quotes/ on that bar where you can do "sort by" of Popular | Newest | Category | School if you hover over school a dropdown comes up, select any country and another one appears, though when that is changed nothing happens. here is the PHP for that second drop down // Get College List function getCollege($state, $m = "no", $l = "no") { // Displays Schools if($m == "yes") { $options = '<select id="schoolMenu" name="school"><option value="select" selected="selected">- Please Select -</option>'; } else if($l == "yes" || $l == "yes2") { $options = ''; } else { $options = '<select name="school"><option value="select" selected="selected">- Please Select -</option>'; } $listArray = split("\|\\\\", $list); for($i=0; $i < count($listArray); $i++) { if($m == "yes") { $options .= '<option value="'. trim(titleReplace($listArray[$i])) .'">'. trim($listArray[$i]) .'</option>'; } else if($l == "yes") { $options .= '<li><a href="/quotes/quotes-from-'. titleReplace($listArray[$i]) .'" title="'. trim($listArray[$i]) .' Quotes">'. trim($listArray[$i]) .'</a></li>'; } else if($l == "yes2") { $options .= '<li><a href="/pics/pics-from-'. titleReplace($listArray[$i]) .'" title="'. trim($listArray[$i]) .' Pictures">'. trim($listArray[$i]) .'</a></li>'; } else { $options .= '<option value="'. trim($listArray[$i]) .'">'. trim($listArray[$i]) .'</option>'; } } echo $options .='</select>'; return false; } any help would be great! EDIT: Also, the way I have those drop downs coming for the menus is a bit weird and when you hover over any other "sort by" link they disappear, this is a problem with the "sort by school" because the first select box shows the list up, and if you go and select a school then somehow float over another link it disappears, any help on how to delay that or fix that minor problem?

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  • How can I select values from different rows depending on the most recent entry date, all for the sam

    - by user321185
    Basically I have a table which is used to hold employee work wear details. It is formed of the columns: EmployeeID, CostCentre, AssociateLevel, IssueDate, TrouserSize, TrouserLength, TopSize & ShoeSize. An employee can be assigned a pair of trousers, a top and shoes at the same time or only one or two pieces of clothing. As we all know peoples sizes and employee levels can change which is why I need help really. Different types of employees (associatelevels) require different colours of clothing but you can ignore this part. Everytime an employee receives an item of clothing a new row will be inserted into the table with an input date. I need to be able to select the most recent clothes size for each item of clothing for each employee. It is not necessary for all the columns to hold values because an employee could receive trousers or poloshirts at different times in the year. So for example if employee '54664LSS' was given a pair of 'XL' trousers and a 'L' top on 24/03/11 but then received a 'M' top on 26/05/10. The input of these items would be help on two different rows obviously. So if I wanted to select the most recent clothing for each clothes category. Then the values of the 'M' sized top and the 'L' sized trousers would need to be returned. Any help would be greatly appreciated as I'm pretty stuck :(. Thanks.

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  • Conditionally Summing the same Column multiple times in a single select statement?

    - by btollett
    I have a single table that shows employee deployments, for various types of deployment, in a given location for each month: ID | Location_ID | Date | NumEmployees | DeploymentType_ID As an example, a few records might be: 1 | L1 | 12/2010 | 7 | 1 (=Permanent) 2 | L1 | 12/2010 | 2 | 2 (=Temp) 3 | L1 | 12/2010 | 1 | 3 (=Support) 4 | L1 | 01/2011 | 4 | 1 5 | L1 | 01/2011 | 2 | 2 6 | L1 | 01/2011 | 1 | 3 7 | L2 | 12/2010 | 6 | 1 8 | L2 | 01/2011 | 6 | 1 9 | L2 | 12/2010 | 3 | 2 What I need to do is sum the various types of people by date, such that the results look something like this: Date | Total Perm | Total Temp | Total Supp 12/2010 | 13 | 5 | 1 01/2011 | 10 | 2 | 1 Currently, I've created a separate query for each deployment type that looks like this: SELECT Date, SUM(NumEmployees) AS "Total Permanent" FROM tblDeployment WHERE DeploymentType_ID=1 GROUP BY Date; We'll call that query qSumPermDeployments. Then, I'm using a couple of joins to combine the queries: SELECT qSumPermDeployments.Date, qSumPermDeployments.["Total Permanent"] AS "Permanent" qSumTempDeployments.["Total Temp"] AS "Temp" qSumSupportDeployments.["Total Support"] AS Support FROM (qSumPermDeployments LEFT JOIN qSumTempDeployments ON qSumPermDeployments.Date = qSumTempDeployments.Date) LEFT JOIN qSumSupportDeployments ON qSumPermDeployments.Date = qSumSupportDeployments.Date; Note that I'm currently constructing that final query under the assumption that a location will only have temp or support employees if they also have permanent employees. Thus, I can create the joins using the permanent employee results as the base table. Given all of the data I currently have, that assumption holds up, but ideally I'd like to move away from that assumption. So finally, my question. Is there a way to simplify this down to a single query or is it best to separate it out into multiple queries - if for no other reason that readability.

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  • how to diffrentiate between same field names of two tables in a select query??

    - by developer
    i have more than two tables in my database and all of them contains same field names like table A table B table C field1 field1 field1 field2 field2 field2 field3 field3 field3 . . . . . . . . . . . . I have to write a SELECT query which gets almost all same fields from these 3 tables.Iam using something like this :- select a.field1,a.field2,a.field3,b.field1,b.field2,b.field3,c.field1,c.field2,c.field3 from table A as a, table B as b,table C as c where so and so. but when i print field1's value it gives me the last table values. How can i get all the values of three tables with the same field names??? do i have to write individual query for every table OR there is any ways of fetching them all in a single query????

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  • Using a variable derived from a drop-down list as the column name in a select statement ... Access DB

    - by user1459698
    I'm working with the world's worst DB that was already here so don't blame me for that. So, here's what I have so far ... module = txtModule.value presstype = txtPressType.value SQL_query = "SELECT * FROM tbl_spareparts WHERE '"& module &"' <> '""' AND '"& module &"' = '"& presstype &"' AND Manufacturer = '"& txtsrch.value &"' ORDER BY SAP_Part_No" Set rsData = conn.Execute(SQL_query) This brings up the following SQL statement: SELECT * FROM tbl_spareparts WHERE 'Banyan_Module' <> '"' AND 'Banyan_Module' = 'PB' AND Manufacturer = 'Tester' ORDER BY SAP_Part_No Is there any way I can use the module variable as a column name - obviously the ''s around the column name are causing an error. This is really bothering me. BTW, I'm writing this in VBScript inside a .HTA application page as it has to run locally on tech PCs. Thanks. R.

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  • Eclipse won't let me select a Windows share as Workspace

    - by Android Eve
    Environment: Ubuntu 10.04 (64-bit), Eclipse Helios 3.6 (64-bit), Android 2.3 SDK + ADT. All works great, but I can only select a workspace that's on the local system. Eclipse won't let me select shared folder on a Samba server. Ubuntu's URI for this share is of the form: smb://[email protected]/sandbox/workspace But even if I typed this manually into the edit box, Eclipse won't accept it. I don't have this problem with Eclipse 3.6 on Windows. Is there a workaround to solve this?

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  • Automatically select headphones when plugged in

    - by Joachim Pileborg
    When I plug headphones into my desktop computer, they are not automatically selected for output, instead all sound still goes through my S/PDIF output to the stereo. The headphones alternative is added in the sound settings, and I have to manually select it as output device. $ cat /proc/asound/pcm 00-00: ALC898 Analog : ALC898 Analog : playback 1 : capture 1 00-01: ALC898 Digital : ALC898 Digital : playback 1 00-02: ALC898 Analog : ALC898 Analog : capture 2 I have done a Google search, as well as search askubuntu.com, but none of the answers in the hits I found seems to help. Also, after listening with the headphones and then unplug them, the previous output is not automatically selected, so I have no sound at all then. I have to manually select the correct output in the settings.

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  • Boot-up hangs unless I manually select the kernel in the bootloader

    - by The Photon
    In my stock Ubuntu install (forgot which critter its named for, about one year old), I am able to boot up normally only if I manually select the kernel in the bootloader (Grub). If I step away and it boots from the default, the system will hang with the word "Ubuntu" on a graphics screen and a few white/red blinking dots beneath it. umb@digdug:~$ uname -a Linux digdug 2.6.32-42-generic #95-Ubuntu SMP Wed Jul 25 15:57:54 UTC 2012 i686 GNU/Linux Synaptics says I have 'grub-pc' version 1.98-1ubuntu-13 installed. My grub.cfg does have default="0" which I would expect to make the default be the first kernel shown in the selection screen. The system is a laptop with an i7 processor, and I have had trouble with some kernels not being able to boot at all in the past, and power management is not working perfectly, but I have not had problems booting the latest kernel (2.6.32-42) if I select it manually in Grub. Any idea what is going on here and how can I fix it so that I can re-boot unattended?

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  • how to change dolphin's select region of a file/folder (in detail view mode)

    - by Daniel
    Since nautilus has removed the dual pane. So I turn to dolphin. I am wondering how to change the default select behavior in detail view mode? Now to select a file/folder, my cursor has to hover over that file/folder and then the left click will take effect, but I much prefer the nautilus way, that is as long as your cursor is in the same row of that file/folder, left click picks up that item. This I think is more robust for user selection, it is faster. Any ideas how to achieve this in dolphin?

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  • Link my tag on other website search

    - by kresna kurdang
    This is my search code <div id="search"> <form method="get" action="http://www.other-website.com/search"> <input type="hidden" name="f" value=""> <input type="text" placeholder="Temukan informasi, komunitas & produk yang kamu cari disini" accesskey="s" name="q"> <input type="submit" value="Search"> </form> </div> This is the tag code (display only text "do not link") <?php $posttags = get_the_tags(); if ($posttags) { foreach($posttags as $tag) { echo $tag->name . ' '; } } ?> The code can apply well on the website, but I have to enter text to the search. I just want to place my tag on that search text so my question is How to make fixed word(my tag) automatically placed on search or where I must place the tag code, the search result is mytag linked on @www.other-website.com/search so user do not have to type? I want to search my tag on other website search

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  • How to select parent row only if has at least one child?

    - by Matt McCormick
    I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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  • Select statement that combines similar rows with certain ids?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data

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  • Why can't I SELECT a parent field that doesn't have a child?

    - by myaccount
    (rest_branches) is the table of restaurants. (phone_numbers) is another table which contains the restaurants phone_numbers, and it has a field called (branch_id) which references the restaurant id. When I try: SELECT * FROM rest_branches NATURAL JOIN phone_numbers I only get the restaurants which have a phone_number. What should I do to get all restaurants even if they don't have a phone number?

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  • [MYSQL] select statement that combines similar rows with certain ids ?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data id domain_id warehouse_id wh_product_id quantity 2 1 2 2 84 3 1 1 3 221 4 1 3 3 0 5 1 1 3 14 6 1 1 2 73 7 1 1 1 123

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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