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  • How do I create a user history?

    - by ggfan
    I want to create a user history function that allows shows users what they done. ex: commented on an ad, posted an ad, voted on an ad, etc. How exactly do I do this? I was thinking about... in my site, when they log in it stores their user_id ($_SESSION['user_id']) so I guess whenever an user posts an ad(postad.php), comments(comment.php), I would just store in a database table "userhistory" what they did based on whenever or not their user_id was activate. When they comment, I store the user_id in the comment dbc table, so I'll also store it in the "userhistory" table. And then I would just queries all the rows in the dbc for the user to show it Any steps/improvements I can make? :)

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  • Storing user settings in table - how?

    - by Mdillion
    I have settings for the user about 200 settings, these include notice settings and tracing settings from user activities on objects. The problem is how to store it in the DB? Should each setting be a row or a column? If colunm then table will have 200 colunms. If row then about 3 colunms but 200 rows per user x even 10 million users = not good. So how else can i store all these settings? NOTE: these settings are a mix of text entry and FK lookups to other tables. Thanks.

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  • Django admin panel doesn't work after modify default user model.

    - by damienix
    I was trying to extend user profile. I founded a few solutions, but the most recommended was to create new user class containing foreign key to original django.contrib.auth.models.User class. I did it with this so i have in models.py: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) website_url = models.URLField(verify_exists=False) and in my admin.py from django.contrib import admin from someapp.models import * from django.contrib.auth.admin import UserAdmin # Define an inline admin descriptor for UserProfile model class UserProfileInline(admin.TabularInline): model = UserProfile fk_name = 'user' max_num = 1 # Define a new UserAdmin class class MyUserAdmin(UserAdmin): inlines = [UserProfileInline, ] # Re-register UserAdmin admin.site.unregister(User) admin.site.register(User, MyUserAdmin) And now when I'm trying to create/edit user in admin panel i have an error: "Unknown column 'content_userprofile.id' in 'field list'" where content is my appname. I was trying to add line AUTH_PROFILE_MODULE = 'content.UserProfile' to my settings.py but with no effect. How to tell panel admin to know how to correctly display fields in user form?

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  • It's not just “Single Sign-on” by Steve Knott (aurionPro SENA)

    - by Greg Jensen
    It is true that Oracle Enterprise Single Sign-on (Oracle ESSO) started out as purely an application single sign-on tool but as we have seen in the previous articles in this series the product has matured into a suite of tools that can do more than just automated single sign-on and can also provide rapidly deployed, cost effective solution to many demanding password management problems. In the last article of this series I would like to discuss three cases where customers faced password scenarios that required more than just single sign-on and how some of the less well known tools in the Oracle ESSO suite “kitbag” helped solve these challenges. Case #1 One of the issues often faced by our customers is how to keep their applications compliant. I had a client who liked the idea of automated single sign-on for most of his applications but had a key requirement to actually increase the security for one specific SOX application. For the SOX application he wanted to secure access by using two-factor authentication with a smartcard. The problem was that the application did not support two-factor authentication. The solution was to use a feature from the Oracle ESSO suite called authentication manager. This feature enables you to have multiple authentication methods for the same user which in this case was a smartcard and the Windows password.  Within authentication manager each authenticator can be configured with a security grade so we gave the smartcard a high grade and the Windows password a normal grade. Security grading in Oracle ESSO can be configured on a per application basis so we set the SOX application to require the higher grade smartcard authenticator. The end result for the user was that they enjoyed automated single sign-on for most of the applications apart from the SOX application. When the SOX application was launched, the user was required by ESSO to present their smartcard before being given access to the application. Case #2 Another example solving compliance issues was in the case of a large energy company who had a number of core billing applications. New regulations required that users change their password regularly and use a complex password. The problem facing the customer was that the core billing applications did not have any native user password change functionality. The customer could not replace the core applications because of the cost and time required to re-develop them. With a reputation for innovation aurionPro SENA were approached to provide a solution to this problem using Oracle ESSO. Oracle ESSO has a password expiry feature that can be triggered periodically based on the timestamp of the users’ last password creation therefore our strategy here was to leverage this feature to provide the password change experience. The trigger can launch an application change password event however in this scenario there was no native change password feature that could be launched therefore a “dummy” change password screen was created that could imitate the missing change password function and connect to the application database on behalf of the user. Oracle ESSO was configured to trigger a change password event every 60 days. After this period if the user launched the application Oracle ESSO would detect the logon screen and invoke the password expiry feature. Oracle ESSO would trigger the “dummy screen,” detect it automatically as the application change password screen and insert a complex password on behalf of the user. After the password event had completed the user was logged on to the application with their new password. All this was provided at a fraction of the cost of re-developing the core applications. Case #3 Recent popular initiatives such as the BYOD and working from home schemes bring with them many challenges in administering “unmanaged machines” and sometimes “unmanageable users.” In a recent case, a client had a dispersed community of casual contractors who worked for the business using their own laptops to access applications. To improve security the around password management the security goal was to provision the passwords directly to these contractors. In a previous article we saw how Oracle ESSO has the capability to provision passwords through Provisioning Gateway but the challenge in this scenario was how to get the Oracle ESSO agent to the casual contractor on an unmanaged machine. The answer was to use another tool in the suite, Oracle ESSO Anywhere. This component can compile the normal Oracle ESSO functionality into a deployment package that can be made available from a website in a similar way to a streamed application. The ESSO Anywhere agent does not actually install into the registry or program files but runs in a folder within the user’s profile therefore no local administrator rights are required for installation. The ESSO Anywhere package can also be configured to stay persistent or disable itself at the end of the user’s session. In this case the user just needed to be told where the website package was located and download the package. Once the download was complete the agent started automatically and the user was provided with single sign-on to their applications without ever knowing the application passwords. Finally, as we have seen in these series Oracle ESSO not only has great utilities in its own tool box but also has direct integration with Oracle Privileged Account Manager, Oracle Identity Manager and Oracle Access Manager. Integrated together with these tools provides a complete and complementary platform to address even the most complex identity and access management requirements. So what next for Oracle ESSO? “Agentless ESSO available in the cloud” – but that will be a subject for a future Oracle ESSO series!                                                                                                                               

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  • How do I reinstate my admin user privileges to global read/write

    - by Matt
    I am running Ubuntu 12.04 LTS. I only have the one user which I created when I installed Ubuntu. Everything has been fine - love it - until I updated a software package recently from the command line using sudo (not gksudo). I was having a little bother which did not make sense to me and in a fluff changed my user read/write privileges through the GUI (not even clear how I got there!). After restart I was stuck in a login loop - using the right login password but kept getting looped back to the login and could only login as Guest. I could still login with my user/password via ctrl + alt + f1 Eventually I was able to login again at start up. Not sure exactly what it was I changed that worked but it was one of/or a combination of installing latest security updates, changing login manager from LightDM to DGM and back again, removing the ICE/Xauthority and chown user. Current dilemma is my primary admin user privileges were read only. In the command line ls -ls /home/user returned this value: drwx------ 48 username username 20480 I have since changed this using sudo chmod 0755 /home/username (from my limited understanding 755 should return my user privileges to their original read/write glory). ls -ld /home/user currently shows my user privileges as: drwxr-xr-x 48 username username 20480 I still seem to have only read access permissions. I've been through lots of threads (and the help file) that talk about creating new users/groups permissions etc. but specific info on returning my existing global/admin/primary users privileges to what they were when I first created that user - baffling me. I feel this is something really simple I'm just not getting it. Please help! sudo mount /dev/sda1 on / type ext4 (rw,errors=remount-ro) proc on /proc type proc (rw,noexec,nosuid,nodev) sysfs on /proc type sysfs (rw,noexec,nosuid,nodev) none on /sys/fs/fuse/connections type fusect1 (rw) none on /sys/kernel/debug type debugfs (rw) none on /sys/kernel/security type securityfs (rw) udev on /dev type devtmpfs (rw,mode=07pe tmpfs55) devpts on /dev/pts type devpts (rw,noexec,nosuid,gid=5,mode=0620) tmpfs on /run type tmpfs (rw,noexec,nosuid,size=10%,mode=0755) none on /run/lock type tmpfs (rw, ,nosuid,nodev,size=5242880 none on /run/shm type tmpfs (rw,nosuid,nodev) gvfs-fuse-daemon on /home/meng/.gvfs type fuse.gvfs-fuse-daemon (rw,nosuid,nodev,user=meng) none on /tmp/guest-1R2Fi5 type tmpsf (rw,mode=700)

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  • Single Responsibility Principle Implementation

    - by Mike S
    In my spare time, I've been designing a CMS in order to learn more about actual software design and architecture, etc. Going through the SOLID principles, I already notice that ideas like "MVC", "DRY", and "KISS", pretty much fall right into place. That said, I'm still having problems deciding if one of two implementations is the best choice when it comes to the Single Responsibility Principle. Implementation #1: class User getName getPassword getEmail // etc... class UserManager create read update delete class Session start stop class Login main class Logout main class Register main The idea behind this implementation is that all user-based actions are separated out into different classes (creating a possible case of the aptly-named Ravioli Code), but following the SRP to a "tee", almost literally. But then I thought that it was a bit much, and came up with this next implementation class UserView extends View getLogin //Returns the html for the login screen getShortLogin //Returns the html for an inline login bar getLogout //Returns the html for a logout button getRegister //Returns the html for a register page // etc... as needed class UserModel extends DataModel implements IDataModel // Implements no new methods yet, outside of the interface methods // Haven't figured out anything special to go here at the moment // All CRUD operations are handled by DataModel // through methods implemented by the interface class UserControl extends Control implements IControl login logout register startSession stopSession class User extends DataObject getName getPassword getEmail // etc... This is obviously still very organized, and still very "single responsibility". The User class is a data object that I can manipulate data on and then pass to the UserModel to save it to the database. All the user data rendering (what the user will see) is handled by UserView and it's methods, and all the user actions are in one space in UserControl (plus some automated stuff required by the CMS to keep a user logged in or to ensure that they stay out.) I personally can't think of anything wrong with this implementation either. In my personal feelings I feel that both are effectively correct, but I can't decide which one would be easier to maintain and extend as life goes on (despite leaning towards Implementation #1.) So what about you guys? What are your opinions on this? Which one is better? What basics (or otherwise, nuances) of that principle have I missed in either design?

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  • How can I transfer a user state of a win7 machine that won't boot?

    - by askvictor
    I have a windows 7 machine that won't boot completely, even in safe mode. I want to re-image the machine using a generic software image, but would like to keep the user data (including settings etc) that are on there ala Windows Easy Transfer. I can mount the hard disk on another machine - can I use Easy Transfer to transfer the user state of an account on the non-booted OS? Or do I need explore USMT?

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  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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  • Why do I get Detached Entity exception when upgrading Spring Boot 1.1.4 to 1.1.5

    - by mmeany
    On updating Spring Boot from 1.1.4 to 1.1.5 a simple web application started generating detached entity exceptions. Specifically, a post authentication inteceptor that bumped number of visits was causing the problem. A quick check of loaded dependencies showed that Spring Data has been updated from 1.6.1 to 1.6.2 and a further check of the change log shows a couple of issues relating to optimistic locking, version fields and JPA issues that have been fixed. Well I am using a version field and it starts out as Null following recommendation to not set in the specification. I have produced a very simple test scenario where I get detached entity exceptions if the version field starts as null or zero. If I create an entity with version 1 however then I do not get these exceptions. Is this expected behaviour or is there still something amiss? Below is the test scenario I have for this condition. In the scenario the service layer that has been annotated @Transactional. Each test case makes multiple calls to the service layer - the tests are working with detached entities as this is the scenario I am working with in the full blown application. The test case comprises four tests: Test 1 - versionNullCausesAnExceptionOnUpdate() In this test the version field in the detached object is Null. This is how I would usually create the object prior to passing to the service. This test fails with a Detached Entity exception. I would have expected this test to pass. If there is a flaw in the test then the rest of the scenario is probably moot. Test 2 - versionZeroCausesExceptionOnUpdate() In this test I have set the version to value Long(0L). This is an edge case test and included because I found reference to Zero values being used for version field in the Spring Data change log. This test fails with a Detached Entity exception. Of interest simply because the following two tests pass leaving this as an anomaly. Test 3 - versionOneDoesNotCausesExceptionOnUpdate() In this test the version field is set to value Long(1L). Not something I would usually do, but considering the notes in the Spring Data change log I decided to give it a go. This test passes. Would not usually set the version field, but this looks like a work-around until I figure out why the first test is failing. Test 4 - versionOneDoesNotCausesExceptionWithMultipleUpdates() Encouraged by the result of test 3 I pushed the scenario a step further and perform multiple updates on the entity that started life with a version of Long(1L). This test passes. Reinforcement that this may be a useable work-around. The entity: package com.mvmlabs.domain; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; import javax.persistence.Version; @Entity @Table(name="user_details") public class User { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Version private Long version; @Column(nullable = false, unique = true) private String username; @Column(nullable = false) private Integer numberOfVisits; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public Long getVersion() { return version; } public void setVersion(Long version) { this.version = version; } public Integer getNumberOfVisits() { return numberOfVisits == null ? 0 : numberOfVisits; } public void setNumberOfVisits(Integer numberOfVisits) { this.numberOfVisits = numberOfVisits; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } The repository: package com.mvmlabs.dao; import org.springframework.data.repository.CrudRepository; import com.mvmlabs.domain.User; public interface UserDao extends CrudRepository<User, Long>{ } The service interface: package com.mvmlabs.service; import com.mvmlabs.domain.User; public interface UserService { User save(User user); User loadUser(Long id); User registerVisit(User user); } The service implementation: package com.mvmlabs.service; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Propagation; import org.springframework.transaction.annotation.Transactional; import org.springframework.transaction.support.TransactionSynchronizationManager; import com.mvmlabs.dao.UserDao; import com.mvmlabs.domain.User; @Service @Transactional(propagation=Propagation.REQUIRED, readOnly=false) public class UserServiceJpaImpl implements UserService { @Autowired private UserDao userDao; @Transactional(readOnly=true) @Override public User loadUser(Long id) { return userDao.findOne(id); } @Override public User registerVisit(User user) { user.setNumberOfVisits(user.getNumberOfVisits() + 1); return userDao.save(user); } @Override public User save(User user) { return userDao.save(user); } } The application class: package com.mvmlabs; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.EnableAutoConfiguration; import org.springframework.context.annotation.ComponentScan; import org.springframework.context.annotation.Configuration; @Configuration @ComponentScan @EnableAutoConfiguration public class Application { public static void main(String[] args) { SpringApplication.run(Application.class, args); } } The POM: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mvmlabs</groupId> <artifactId>jpa-issue</artifactId> <version>0.0.1-SNAPSHOT</version> <packaging>jar</packaging> <name>spring-boot-jpa-issue</name> <description>JPA Issue between spring boot 1.1.4 and 1.1.5</description> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.1.5.RELEASE</version> <relativePath /> <!-- lookup parent from repository --> </parent> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-data-jpa</artifactId> </dependency> <dependency> <groupId>org.hsqldb</groupId> <artifactId>hsqldb</artifactId> <scope>runtime</scope> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-test</artifactId> <scope>test</scope> </dependency> </dependencies> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <start-class>com.mvmlabs.Application</start-class> <java.version>1.7</java.version> </properties> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </plugin> </plugins> </build> </project> The application properties: spring.jpa.hibernate.ddl-auto: create spring.jpa.hibernate.naming_strategy: org.hibernate.cfg.ImprovedNamingStrategy spring.jpa.database: HSQL spring.jpa.show-sql: true spring.datasource.url=jdbc:hsqldb:file:./target/testdb spring.datasource.username=sa spring.datasource.password= spring.datasource.driverClassName=org.hsqldb.jdbcDriver The test case: package com.mvmlabs; import org.junit.Assert; import org.junit.Test; import org.junit.runner.RunWith; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.boot.test.SpringApplicationConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import com.mvmlabs.domain.User; import com.mvmlabs.service.UserService; @RunWith(SpringJUnit4ClassRunner.class) @SpringApplicationConfiguration(classes = Application.class) public class ApplicationTests { @Autowired UserService userService; @Test public void versionNullCausesAnExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Null"); user.setNumberOfVisits(0); user.setVersion(null); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionZeroCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Zero"); user.setNumberOfVisits(0); user.setVersion(0L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version One"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(2L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionWithMultipleUpdates() throws Exception { User user = new User(); user.setUsername("Version One Multiple"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); user = userService.registerVisit(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(3), user.getNumberOfVisits()); Assert.assertEquals(new Long(4L), user.getVersion()); } } The first two tests fail with detached entity exception. The last two tests pass as expected. Now change Spring Boot version to 1.1.4 and rerun, all tests pass. Are my expectations wrong? Edit: This code saved to GitHub at https://github.com/mmeany/spring-boot-detached-entity-issue

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Couldn't drop privileges: User is missing UID (see mail_uid setting)

    - by drecute
    I'm hoping I can use some help. I'm configuring dovecot_ldap, but I can't seem to be able to get dovecot to authenticate the ldap user. Below is my config and log info: hosts = 192.168.128.45:3268 dn = cn=Administrator,cn=Users,dc=company,dc=example,dc=com dnpass = "passwd" auth_bind = yes ldap_version = 3 base = dc=company, dc=example, dc=com user_attrs = sAMAccountName=home=/var/vmail/example.com/%$,uid=1001,gid=1001 user_filter = (&(sAMAccountName=%Ln)) pass_filter = (&(ObjectClass=person)(sAMAccountName=%u)) dovecot.conf # 2.0.19: /etc/dovecot/dovecot.conf # OS: Linux 3.2.0-33-generic x86_64 Ubuntu 12.04 LTS auth_mechanisms = plain login auth_realms = example.com auth_verbose = yes disable_plaintext_auth = no mail_access_groups = mail mail_location = mbox:~/mail:INBOX=/var/mail/%u mail_privileged_group = mail passdb { driver = pam } passdb { driver = passwd } passdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } passdb { args = scheme=CRYPT username_format=%u /etc/dovecot/users driver = passwd-file } protocols = " imap pop3" service auth { unix_listener /var/spool/postfix/private/auth { group = postfix mode = 0660 user = postfix } } service imap-login { inet_listener imap { port = 143 } inet_listener imaps { port = 993 ssl = yes } } ssl_cert = </etc/ssl/certs/dovecot.pem ssl_key = </etc/ssl/private/dovecot.pem userdb { driver = passwd } userdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } userdb { args = username_format=%u /etc/dovecot/users driver = passwd-file } protocol imap { imap_client_workarounds = tb-extra-mailbox-sep imap_logout_format = bytes=%i/%o mail_plugins = } mail.log Nov 29 10:51:44 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:44 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1892, TLS Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:46 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:46 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1894, TLS Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:48 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:48 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:51:54 mail postfix/smtpd[1880]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1879]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1887]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1886]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: idle timeout -- exiting Nov 29 10:51:56 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:56 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:52:04 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:06 mail dovecot: imap-login: Disconnected (auth failed, 3 attempts): user=<[email protected]>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, TLS Thank you for looking into this.

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  • How to migrate user settings and data to new machine?

    - by torbengb
    I'm new to Ubuntu and recently started using it on my PC. I'm going to replace that PC with a new machine. I want to transfer my data and settings to the nettop. What aspects should I consider? Obviously I want to move my data over. What things am I missing if I only copy the entire home folder? This is a home pc (not corporate) so user rights and other security issues are not a concern, except that the files should be accessible on the new machine! Please take into account that the new machine is a nettop that doesn't have an optical drive and doesn't allow me to hook the old SATA disk into it, so any data transfer must be handled via home network (I can have both the old and the new machine turned on and connected to the home LAN) and I have an USB thumbdrive with limited capacity (2GB). This sounds like it might limit the general applicability, but it would in fact make it more general. I'll make this a wiki topic because there could be several "right" answers. Update: Or so I thought. I don't see a choice for that.

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  • "log on as a batch job" user rights removed by what GPO?

    - by LarsH
    I am not much of a server administrator, but get my feet wet when I have to. Right now I'm running some COTS software on a Windows 2008 Server machine. The software installer creates a few user accounts for running its processes, and then gives those users the right to "log on as a batch job". Every so often (e.g. yesterday at 2:52pm and this morning at 7:50am), those rights disappear. The software then stops working. I can verify that the user rights are gone by using secedit /export /cfg e:\temp\uraExp.inf /areas USER_RIGHTS and I have a script that does this every 30 seconds and logs the results with a timestamp, so I know when the rights disappear. What I see from the export is that in the "good" state, i.e. after I install the software and it's working correctly, the line for SeBatchLogonRight from the secedit export includes the user accounts created by the software. But every few hours (sometimes more), those user accounts are removed from that line. The same thing can be seen by using the GUI tool Local Security Policy > Security Settings > Local Policies > User Rights Assignment > Log on as a batch job: in the "good" state, that policy includes the needed user accounts, and in the bad state, the policy does not. Based on the above-mentioned logging script and the timestamps at which the user rights are being removed, I can see clearly that some GPOs are causing the change. The GPO Operational log shows GPOs being processed at exactly the right times. E.g.: Starting Registry Extension Processing. List of applicable GPOs: (Changes were detected.) Local Group Policy I have run GPOs on demand using gpupdate /force, and was able to verify that this caused the User Rights to be removed. We have looked over local group policies till our eyes are crossed, trying to figure out which one might be stripping these User Rights to "log on as a batch job." We have not configured any local group policies on this machine, that we know of; so is there a default local group policy that might typically do such a thing? Are there typical domain policies that would do this? I have been working with our IT staff colleagues to troubleshoot the problem, but none of them are really GPO experts... They wear many hats, and they do what they need to do in order to keep most things running. Any suggestions would be greatly appreciated!

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  • Simulating user activities on a GMail page

    - by Vitaliy
    I create a program that simulates me browsing to gmail, entering the user name and password and clicking the submit button. All this with C#. I would appreciate two kinds of answers: One that tells how to do this programaticaly. Since I may be interested in automating more sophisticated user activities. On that tells me about a program that already does that. Thanks!!

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  • How to detect user agent in WCF web service

    - by Kangkan
    How can I detect the user agent in a web service? My web service is implemented using a WCF webservice with basicHTTPBinding. It will be a post from some SOAP clients. I wish to know the user-agent from the clients. I shall like to see some sample code for this.

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  • Django: How to get current user in admin forms

    - by lazerscience
    In Django's ModelAdmin I need to display forms customized according to the permissions an user has. Is there a way of getting the current user object into the form class, so that i can customize the form in its __init__ method? I think saving the current request in a thread local would be a possibility but this would be my last resort think I'm thinking it is a bad design approach....

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  • Best practices for custom http user-agent strings?

    - by Noufal Ibrahim
    I'm developing an application that communicates with an internal web service using HTTP. Are there any "best practices" for custom user-agent strings so that I can put a nice one in my app? It's a Python library and the lower transport is Python's own httplib. Should the user-agent string say that or something else?

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  • How do you test the usability of your user interfaces

    - by Martin
    How do you test the usability of the user interfaces of your applications - be they web or desktop? Do you just throw it all together and then tweak it based on user experience once the application is live? Or do you pass it to a specific usability team for testing prior to release? We are a small software house, but I am interested in the best practices of how to measure usability. Any help appreciated.

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  • Django microblog showing a logged in user only his posts

    - by dana
    i have a miniblog application, with a class named New(refering to a new post), having a foreign key to an user(who has posted the entry). above i have a method that displays all the posts from all the users. I'd like to show to the logged in user, only his posts How can i do it? Thanks in advance! def paginate(request): paginator = New.objects.all() return render_to_response('news/newform.html', { 'object_list': paginator, }, context_instance=RequestContext(request))

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  • Writing user stories for internal technical tasks

    - by John Nolan
    I am attempting to manage my projects a little better so I am looking at attempting to apply some of (eventually all) the features of scrum. Looking at user stories specifically the high level format seems to be: As a User I can Feature Description or Artifact is Doing Something How would I write "Upgrade the Database"? Is it simply Upgrade the Database? I think I am being thrown off as there is no specific actor/customer and that the customer is the IT department.

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  • User accounts in Symfony?

    - by gruner
    I'm new to Symfony. Is my understanding correct that the User class is actually for controlling sessions? But is there built-in login and account creation? I'm not finding it. But if there's an admin backend generator, how can it function without user logins?

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