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  • Mysql join two tables and add column values

    - by Mike
    My knowledge of mysql is not very in depth. If I have two tables that for example look like this: Table1 Date v1 v2 v3 05/01/2010 26 abc 45 05/02/2010 31 def 25 05/03/2010 50 ghi 46 Table2 Date v1 v2 v3 05/01/2010 42 jkl 15 05/02/2010 28 mno 14 05/03/2010 12 pqr 64 How can I join them in a query by their date and have the sum of table1.v1 and table2.v1 and also have the sum of table1.v3 and table2.v3. V2 should be ignored.

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  • SQL Images in different tables

    - by Adonis L
    I am storing images in a SQL database , right now I have images being stored in separate tables depending on the object the images belong to, is there any reason ( performance etc..) why I should keep it this way and not store all images in the same table?

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  • inserted in multiple tables of database at a time

    - by rajkumari
    can we work with multiple tables of database with same connection object of database at same time . suppose i have inserted value in table 1 and at same time also inserted value in table 2 of data base with same object of data base connection. I am using sqlite database in code and getting database locked exception while commit() .

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  • Splitting tables by field to optimize MySQL?

    - by AK
    Do splitting fields into multiple tables ever yield faster queries? Consider the following two scenarios: Table1 ----------- int PersonID text Value1 float Value2 or Table1 ----------- int PersonID text Value1 Table2 ----------- int PersonID float Value2 If Value1 and Value2 are always being displayed together, I imagine Table1 is always faster because the second schema would require two SELECT statements. But are there any situations where you would choose the second? If the number of records were expected to be really large?

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  • MySql Join using 4 tables

    - by Ionut Flavius Pogacian
    I have 4 tables and i want to join them and extarct 4 values. I wrote the followig MySql Query, but it does not work. select `a`.`id`,`a`.`page` xpage,`a`.`action`, `b`.`header` xheader, `b`.`page_id`, `c`.`content` xcontent,`b`.`page_id`, `d`.`footer` xfooter,`d`.`page_id` join `header` b on `a`.`id`=`b`.`page_id` join `content` c on `a`.`id`=`c`.`page_id` and `a`.`id`=`d`.`page_id` join `footer` d on `a`.`id`=`d`.`page_id` where `a`.`page`='main'

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  • Good design of mapping Java Domain objects to Tables (using Hibernate)

    - by M. McKenzie
    Hey guys, I have a question that is more in the realm of design, than implementation. I'm also happy for anyone to point out resources for the answer and I'll gladly, research for myself. Highly simplified Java and SQL: Say I have a business domain POJO called 'Picture' with three attributes. class Picture int idPicture String fileName long size Say I have another business domain POJO called "Item" with 3 attributes Class Item int idItem String itemName ArrayList itemPictures These would be a normal simple relationship. You could say that 'Picture' object, will never exist outside an 'Item' object. Assume a picture belongs only to a specific item, but that an item can have multiple pictures Now - using good database design (3rd Normal Form), we know that we should put items and pictures in their own tables. Here is what I assume would be correct. table Item int idItem (primary key) String itemName table Picture int idPicture (primary key) varchar(45) fileName long size int idItem (foreign key) Here is my question: If you are making Hibernate mapping files for these objects. In the data design, your Picture table needs a column to refer to the Item, so that a foreign key relation can be maintained. However,in your business domain objects - your Picture does not hold a reference/attribute to the idItem - and does not need to know it. A java Picture instance is always instantiated inside an Item instance. If you want to know the Item that the Picture belongs to you are already in the correct scope. Call myItem.getIdItem() and myItem.getItemPictures(),and you have the two pieces of information you need. I know that Hibernate tools have a generator that can auto make your POJO's from looking at your database. My problem stems from the fact that I planned out the data design for this experiment/project first. Then when I went to make the domain java objects, I realized that good design dictated that the objects hold other objects in a nested way. This is obviously different from the way that a database schema is - where all objects(tables) are flat and hold no other complex types within them. What is a good way to reconcile this? Would you: (A) Make the hibernate mapping files so that Picture.hbm.xml has a mapping to the POJO parent's idItem Field (if it's even possible) (B) Add an int attribute in the Picture class to refer to the idItem and set it at instantiation, thus simplifying the hbm.xml mapping file by having all table fields as local attributes in the class (C) Fix the database design because it is wrong, dork. I'd truly appreciate any feedback

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  • SQL Server Compact Edition - Create Database Tables

    - by Lennie De Villiers
    Hi, I got it right to create a SQL Server CE database table using the code below: string connectionString = "DataSource=\"test.sdf\"; Password=\"mypassword\""; SqlCeEngine en = new SqlCeEngine(connectionString); en.CreateDatabase(); But how do I create my database tables and insert data? I've got the SQL created statements stored in the application Resource location.

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  • Entity Data Model Wizzard not creating tables in EDMX file

    - by Shawn
    I'm trying the database first approach by creating an ADO.NET Entity Data Model using the Wizard with the Adventureworks2012 DB. Testing DB connection works, and the connection string is added to the App.Config. I'm selecting all the tables except the ones marked as (dbo) AWBuildVersion, DatabaseLog, and ErrorLog. When the Wizard finishes the .edmx file is blank, and if I view the file in XML view the EntityContainer is empty. I'm using VS 2010 & .NET Framework 4.0

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  • update query with join on two tables

    - by dba_query
    I have customer and address tables. query: select * from addresses a, customers b where a.id = b.id returns 474 records For these records, I'd like to add the id of customer table into cid of address table. Example: If for the first record the id of customer is 9 and id of address is also 9 then i'd like to insert 9 into cid column of address table. I tried: update addresses a, customers b set a.cid = b.id where a.id = b.id but this does not seem to work.

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  • Compare Tables in different databases with ADO.Net 3.5

    - by MicMit
    I need to compare tables with the same names in different databases ( Sql Server 2008 ). How using C# code and ADO.Net to identify additions, deletions, updates. Is DataReader going to work in this scenario without stored procedures ? DataReader seems to be suitable for single database connection, or am I missing something ?

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  • Problems writing a query to join two tables

    - by Psyche
    Hello, I'm working on a script which purpose is to grant site users access to different sections of the site menu. For this I have created two tables, "menu" and "rights": menu - id - section_name rights - id - menu_id (references column id from menu table) - user_id (references column id from users table) How can a query be written in order to get all menu sections and mark the ones where a given user has access. I'm using PHP and Postgres. Thank you.

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  • Complex query with two tables and multilpe data and price ranges

    - by TiuTalk
    Let's suppose that I have these tables: [ properties ] id (INT, PK) name (VARCHAR) [ properties_prices ] id (INT, PK) property_id (INT, FK) date_begin (DATE) date_end (DATE) price_per_day (DECIMAL) price_per_week (DECIMAL) price_per_month (DECIMAL) And my visitor runs a search like: List the first 10 (pagination) properties where the price per day (price_per_day field) is between 10 and 100 on the period for 1st may until 31 december I know thats a huge query, and I need to paginate the results, so I must do all the calculation and login in only one query... that's why i'm here! :)

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  • how to fetch data from multiple tables MySQL

    - by faisal
    hi all, I am looking some help in php+MySQL+jquery I have 2 tables table1 table 1 have 4 colume (id, title, desc, thumb_img) tabel2 table 2 have 3 colume(id, table1id, img) I just want to compare 2 table with the value of $_get['QS']; and show the records from both (title, desc, img) Looking forward for the help.:)

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  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • MS access refusing to combine two tables?

    - by Mahmoud
    hey everyone i have an access 2007 database where i have 2 tables one is exp_cash and exp_cheque each are link to exp_cat, where exp_cat contains categories list where exp_cash contains id,cat_id,exp_date,exp_amount,exp_note same thing in exp_cheque where when i came to combine them nothing in result unless i remove the cat_name from my query i used a simple query which is SELECT DISTINCT exp_cat.cat_name, exp_cash.exp_amount, exp_cheque.exp_amount FROM (exp_cat INNER JOIN exp_cash ON exp_cat.ID = exp_cash.exp_cat_id) INNER JOIN exp_cheque ON exp_cat.ID = exp_cheque.exp_cat_id;

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