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  • Bizarre Son of Suckerfish ie6/ie7 problem - 2 letters from right-most dropdown menu also appearing o

    - by Kevin Burke
    I'm interning for an NGO in India and trying to fix their website, including updating their menu so it's not the last item on the page to load, and it's centered on the screen. Everything works well enough but when I try out my new menu in IE6, I get this weird error where the content below the menu is padded an extra 30px or so and the material in the right-most drop down appears on the far left of the screen, always visible. When I drop down the rightmost link ("Publications") the content appears both in the correct location and in the same spot on the far left of the screen, and changes color when I hover as well. It's tough to describe, so it would probably be best if you took a look: visit http://sevamandir.org/a30/aboutus.htm in your IE6/IE7 browser to see for yourself. I really appreciate your help. Also I'm using a 1000px wide monitor, if there's more hijinks going on outside that space I'd like to know about that too. I took a look at the problem again and it's even weirder than I thought. Only two letters of the bottom-most drop down menu item are shown, no matter how many items are in the left-most drop down menu. When I delete the left-most drop down menu, the bottom item from the next left-most item shows up in the same space. The padding between the menu and the content is always the same. When I hover over the real menu item, the two letters on the left hand side change color to match the hover color. Unfortunately many people that visit our website are using old browsers so IE6 support is pretty crucial, this problem is really weird though, and I would appreciate some help. I uploaded a file with the entire style.css sheet in the and HTML code below, at http://sevamandir.org/a30/aboutus.htm. Here's the relevant code: in the html head: <script> sfHover = function() { var sfEls = document.getElementById("nav").getElementsByTagName("LI"); for (var i=0; i<sfEls.length; i++) { sfEls[i].onmouseover=function() { this.className+=" sfhover"; } sfEls[i].onmouseout=function() { this.className=this.className.replace(new RegExp(" sfhover\\b"), ""); } } } if (window.attachEvent) window.attachEvent("onload", sfHover); </script> text surrounding the menu - the menu is simply <ul id="nav"><li></li></ul> etc. <!--begin catchphrase--> <div style="float:left; height:27px; width:520px; margin:0px; font:16px Arial, Helvetica, sans-serif; font-weight:bold; color:#769841;"> Transforming lives through democratic &amp; participatory development </div> <?php include("menu.php"); ?> </div><!-- end header --> <!--begin main text div--> <div id="maincontent"> Relevant menu CSS: #nav, #nav ul { font:bold 11px Verdana, sans-serif; float: left; width: 980px; list-style: none; line-height: 1; background: white; font-weight: bold; padding: 0; border: solid #769841; border-width: 0; margin: 0 0 1em 0; } #nav a { display: block; width: 140px; /*this is the total width of the upper menu*/ w\idth: 120px; /*this is the width less horizontal padding */ padding: 5px 10px 5px 10px; /*horiz padding is the 2nd & 4th items here - goes Top Right Bottom Left */ color: #ffffff; background:#b6791e; text-decoration: none; } #nav a.daddy { background: url(rightarrow2.gif) center right no-repeat; } #nav li { float: left; padding: 0; width: 140px; /*this needs to be updated to match top #nav a */ background:#b6791e; } #nav li:hover, #nav li a:hover, #nav li:hover a { background:#769841; } #nav li:hover li a { background:#ffffff; color:#769841; } #nav li ul { position: absolute; left: -999em; height: auto; width: 14.4em; w\idth: 13.9em; font-weight: bold; border-width: 0.25em; /*green border around dropdown menu*/ margin: 0; } #nav li ul a { background:#ffffff; color:#769841; } #nav li li { padding-right: 1em; width: 13em; background:#ffffff; } #nav li ul a { width: 13em; w\idth: 9em; } #nav li ul ul { margin: -1.75em 0 0 14em; } #nav li:hover ul ul, #nav li:hover ul ul ul, #nav li.sfhover ul ul, #nav li.sfhover ul ul ul { left: -999em; } #nav li:hover ul, #nav li li:hover ul, #nav li li li:hover ul, #nav li.sfhover ul, #nav li li.sfhover ul, #nav li li li.sfhover ul { left: auto; } #nav li:hover, #nav li.sfhover, { background: #769841; color:#ffe400; } #nav li a:hover, #nav li li a:hover, #nav li:hover li:hover, #nav li.sfhover a:hover { background: #769841; color:#ffe400; }

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  • Using multiple aggregate functions in an algebraic expression in (ANSI) SQL statement

    - by morpheous
    I have the following aggregate functions (AGG FUNCs): foo(), foobar(), fredstats(), barneystats(). I want to know if I can use multiple AGG FUNCs in an algebraic expression. This may seem a strange/simplistic question for seasoned SQL developers - however, the but the reason I ask is that so far, all AGG FUNCs examples I have seen are of the simplistic variety e.g. max(salary) < 100, rather than using the AGG FUNCs in an expression which involves using multiple AGG FUNCs in an expression (like agg_func1() agg_func2()). The information below should help clarify further. Given tables with the following schemas: CREATE TABLE item (id int, length float, weight float); CREATE TABLE item_info (item_id, name varchar(32)); # Is it legal (ANSI) SQL to write queries of this format ? SELECT id, name, foo, foobar, fredstats FROM A, B (SELECT id, foo(123) as foo, foobar('red') as foobar, fredstats('weight') as fredstats FROM item GROUP BY id HAVING [ALGEBRAIC EXPRESSION] ORDER BY id AS A), item_info AS B WHERE item.id = B.id Where: ALGEBRAIC EXPRESSION is the type of expression that can be used in a WHERE clause - for example: ((foo(x) < foobar(y)) AND foobar(y) IN (1,2,3)) OR (fredstats(x) <> 0)) I am using PostgreSQL as the db, but I would prefer to use ANSI SQL wherever possible. Assuming it is legal to include AGG FUNCS in the way I have done above, I'd like to know: Is there a more efficient way to write the above query ? Is there any way I can speed up the query in terms of a judicious choice of indexes on the tables item and item_info ? Is there a performance hit of using AGG FUNCs in an algebraic expression like I am (i.e. an expression involving the output of aggregate functions rather than constants? Can the expression also include 'scaled' AGG FUNC? (for example: 2*foo(123) < -3*foobar(456) ) - will scaling (i.e. multiplying an AGG FUNC by a number have an effect on performance?) How can I write the query above using INNER JOINS instead?

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  • Drawing tree diagram in ASP.Net MVC

    - by Ivan Crojach Karacic
    I am creating an web application for my tae kwon do club. People are able to register online for a tournament. After the registration deadline the web application generates a dendrogram. Something like this: I am wondering now how to draw it. Because of the fact that there are my weight and age categories i have to draw them dynamicly for each group. What is the easiest way to draw this inside a MVC view?

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  • Problem with CSS on Wordpress

    - by Tdasads
    Hi there! I'm trying to code my sidebar.php but it breaks and goes all the way down below the posts PHP: <!-- begin sidebar --> <div id="menu"> <?php /* Widgetized sidebar, if you have the plugin installed. */ if ( !function_exists('dynamic_sidebar') || !dynamic_sidebar() ) : ?> <label for="s">SEARCH</label> <form id="searchform" method="get" action="#"> <div> <input type="text" name="s" id="s" size="15" /> <br /> <input type="submit" value="TYPE HERE_" /> </div> </form> <div class="bg-sidebar"> <h2>MOST READ</h2> <ul> <li><a href="javascript:void(0);">Worth A Thousand Words</a></li> <li><a href="javascript:void(0);">Feed Your Head</a></li> <li><a href="javascript:void(0);">Aliquam tempus, eros commodo porta pretium</a></li> <li><a href="javascript:void(0);">Pellentesque quis libero dui</a></li> <li><a href="javascript:void(0);">Lorem ipsum dolor sit amet</a></li> </ul> <h2>RECENT POSTS</h2> <ul> <li><a href="javascript:void(0);">Worth A Thousand Words</a></li> <li><a href="javascript:void(0);">Feed Your Head</a></li> <li><a href="javascript:void(0);">Aliquam tempus, eros commodo porta pretium</a></li> <li><a href="javascript:void(0);">Pellentesque quis libero dui</a></li> <li><a href="javascript:void(0);">Lorem ipsum dolor sit amet</a></li> </ul> <h2>ARCHIVE</h2> <ul> <li> <?php wp_get_archives('type=monthly'); ?> </li> </ul> <h2>LINKS</h2> <ul> <li><a href="http://www.t.com">t</a></li> <li><a href="http://www.tt.com">tt</a></li> </ul> </div> <?php endif; ?> </div> CSS: * { margin: 0; padding: 0; } body, input { font-family: "Trebuchet MS"; font-size: 12px; } .move { clear: both; height: 0; float: none !important; } body { background: url(images/bg.gif); width: 991px; position: absolute; top: 0; left: 50%; margin: 0 0 0 -495px; padding: 0 0 71px 0; } a { text-decoration: none; } li { list-style: none; } img { border: 0; } #searchform { float: left; width: 366px; height: 27px; } #searchform * { float: left;} #searchform label { width:75px; height: 26px; border: solid 1px #ab0000; border-width: 1px 1px 0 0; text-align: center; line-height: 25px; font-weight: bold; font-size: 18px; color: #ab0000; background: white; } #searchform p { border-bottom: solid 1px #ab0000; width: 290px; height: 25px; } #searchform input { border: 0; margin: 6px 0 0 10px; display: inline; width: 234px; font-weight: bold; color: #999999; background: transparent; outline: none; height: 16px; } #searchform button { background: url(images/btn_vai.gif); width: 34px; height: 24px; border: 0; margin: 0 0 2px 0; float: right; } #menu { width: 366px; height: 40px; float: left; margin: 1px 0 0 0; } .bg-sidebar { background: white; width: 366px; padding: 50px 0 0 0; } #menu h2 { color: #ab0000; font-size: 18px; line-height: 18px; padding: 0 0 10px 15px; } #menu ul { border-top: solid 1px #d5d5d5; padding: 0 0 38px 0; } #menu li { border-bottom: solid 1px #f3f2f2; line-height: 30px; font-size: 13px; font-weight: bold; padding: 0 0 0 24px; } #menu li a { color: black; } Can somebody help me out on this one?

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  • Dijkstras Algorithm exaplination java

    - by alchemey89
    Hi, I have found an implementation for dijkstras algorithm on the internet and was wondering if someone could help me understand how the code works. Many thanks private int nr_points=0; private int[][]Cost; private int []mask; private void dijkstraTSP() { if(nr_points==0)return; //algorithm=new String("Dijkstra"); nod1=new Vector(); nod2=new Vector(); weight=new Vector(); mask=new int[nr_points]; //initialise mask with zeros (mask[x]=1 means the vertex is marked as used) for(int i=0;i<nr_points;i++)mask[i]=0; //Dijkstra: int []dd=new int[nr_points]; int []pre=new int[nr_points]; int []path=new int[nr_points+1]; int init_vert=0,pos_in_path=0,new_vert=0; //initialise the vectors for(int i=0;i<nr_points;i++) { dd[i]=Cost[init_vert][i]; pre[i]=init_vert; path[i]=-1; } pre[init_vert]=0; path[0]=init_vert; pos_in_path++; mask[init_vert]=1; for(int k=0;k<nr_points-1;k++) { //find min. cost in dd for(int j=0;j<nr_points;j++) if(dd[j]!=0 && mask[j]==0){new_vert=j; break;} for(int j=0;j<nr_points;j++) if(dd[j]<dd[new_vert] && mask[j]==0 && dd[j]!=0)new_vert=j; mask[new_vert]=1; path[pos_in_path]=new_vert; pos_in_path++; for(int j=0;j<nr_points;j++) { if(mask[j]==0) { if(dd[j]>dd[new_vert]+Cost[new_vert][j]) { dd[j]=dd[new_vert]+Cost[new_vert][j]; } } } } //Close the cycle path[nr_points]=init_vert; //Save the solution in 3 vectors (for graphical purposes) for(int i=0;i<nr_points;i++) { nod1.addElement(path[i]); nod2.addElement(path[i+1]); weight.addElement(Cost[path[i]][path[i+1]]); } }

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  • Java OCR package

    - by pstanton
    what is the best OCR package you've used with java? I need to parse mainly numbers in a single font and am looking for a well architected, lite weight library to use. thanks.

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  • Jquery image preview thumbnail doesn't seem to work....

    - by Pandiya Chendur
    I just tried the tooltip like this Easy image preview... But i cant get it to work.... I used this, <style> body { margin:0; padding:40px; background:#fff; font:80% Arial, Helvetica, sans-serif; color:#555; line-height:180%; } h1{ font-size:180%; font-weight:normal; color:#555; } h2{ clear:both; font-size:160%; font-weight:normal; color:#555; margin:0; padding:.5em 0; } a{ text-decoration:none; color:#f30; } p{ clear:both; margin:0; padding:.5em 0; } pre{ display:block; font:100% "Courier New", Courier, monospace; padding:10px; border:1px solid #bae2f0; background:#e3f4f9; margin:.5em 0; overflow:auto; width:800px; } img{border:none;} ul,li{ margin:0; padding:0; } li{ list-style:none; float:left; display:inline; margin-right:10px; } /* */ #preview{ position:absolute; border:1px solid #ccc; background:#333; padding:5px; display:none; color:#fff; } /* */ </style> <script type="text/javascript" src="jquery.js"></script> <ul> <li> <a href="Images/4.jpg" class="preview" title="Lake and a mountain"> <img src="Images/4s.jpg" alt="gallery thumbnail" /> </a> </li> </ul> and included style... Nothing happens when i hover over the anchor tag....

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  • What is the average color of a star?

    - by RCIX
    I am trying to procedurally generate point stars to create a starfield background for my game. I want to weight the color production based on an average star's real color. Can anyone point me in the direction of this sort of data?

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  • Information Gain and Entropy

    - by dhorn
    I recently read this question regarding information gain and entropy. I think I have a semi-decent grasp on the main idea, but I'm curious as what to do with situations such as follows: If we have a bag of 7 coins, 1 of which is heavier than the others, and 1 of which is lighter than the others, and we know the heavier coin + the lighter coin is the same as 2 normal coins, what is the information gain associated with picking two random coins and weighing them against each other? Our goal here is to identify the two odd coins. I've been thinking this problem over for a while, and can't frame it correctly in a decision tree, or any other way for that matter. Any help? EDIT: I understand the formula for entropy and the formula for information gain. What I don't understand is how to frame this problem in a decision tree format. EDIT 2: Here is where I'm at so far: Assuming we pick two coins and they both end up weighing the same, we can assume our new chances of picking H+L come out to 1/5 * 1/4 = 1/20 , easy enough. Assuming we pick two coins and the left side is heavier. There are three different cases where this can occur: HM: Which gives us 1/2 chance of picking H and a 1/4 chance of picking L: 1/8 HL: 1/2 chance of picking high, 1/1 chance of picking low: 1/1 ML: 1/2 chance of picking low, 1/4 chance of picking high: 1/8 However, the odds of us picking HM are 1/7 * 5/6 which is 5/42 The odds of us picking HL are 1/7 * 1/6 which is 1/42 And the odds of us picking ML are 1/7 * 5/6 which is 5/42 If we weight the overall probabilities with these odds, we are given: (1/8) * (5/42) + (1/1) * (1/42) + (1/8) * (5/42) = 3/56. The same holds true for option B. option A = 3/56 option B = 3/56 option C = 1/20 However, option C should be weighted heavier because there is a 5/7 * 4/6 chance to pick two mediums. So I'm assuming from here I weight THOSE odds. I am pretty sure I've messed up somewhere along the way, but I think I'm on the right path! EDIT 3: More stuff. Assuming the scale is unbalanced, the odds are (10/11) that only one of the coins is the H or L coin, and (1/11) that both coins are H/L Therefore we can conclude: (10 / 11) * (1/2 * 1/5) and (1 / 11) * (1/2) EDIT 4: Going to go ahead and say that it is a total 4/42 increase.

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  • Facebook Graph API With iPhone SDK

    - by Tom G
    Hi, Has anyone been able to implement Facebooks Graph API in a native iPhone Application? The documentation is pretty sparse when it comes to iPhone integration, but the calls to get users information looks a lot more light weight than the previous method of using FBConnect. So i would like to use it. I have seen a few posts about but none explain you you would implement the login button as we did previously with FBConnect? If any one has achieved this or can offer me any pointers that would be brilliant Thanks Tom

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  • A two way minimum spanning tree of a directed graph

    - by mvid
    Given a directed graph with weighted edges, what algorithm can be used to give a sub-graph that has minimum weight, but allows movement from any vertex to any other vertex in the graph (under the assumption that paths between any two vertices always exist). Does such an algorithm exist?

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  • HTTPService resultFormat, how to choose

    - by tag
    HTTPService has a property resultFormat which can be set to any of the following: array e4x flashvars object text xml I looked at the documentation to understand the difference, but still couldn't understand when to use each. I'm looking for the lightest weight of all of them. P.S. I'm consuming output from my own server, so can change the output format as needed to make it compatible with each.

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  • embedded Italic, bold fonts don't look the same in flex as in Windows...

    - by Mark
    ...unless they're something like "Times New Roman" or some other established font with a fully designed italic and bold, presumably in seperate files. Let me explain what I mean (though why no one has commented on this before I have no idea.) Numerous, numerous fonts do not have a seperate file for italic and bold, and in fact to the best of my knowledge don't even have italic and bold defined as such. But if you install them on windows (for example) and then use them in an app, You can still make use of italic and bold with those fonts. For italic, and oblique angle is just given to it, presumably by Windows, and it looks the same in all Windows apps, and the bold is just given a heavier weight. OK, well here's the problem: if you embed a font like that in a Flex app, as a "SystemFont" the italic and bold will not look the same as they do in Windows. Specifically, the oblique angle is invariably much less than in Windows (i.e the italic slant is much less) and the bold version is not bold enough. I vaguely recall thinking that there was some flex mechanism to assign custom oblique angles for italic (and weight for bold) but now can't recall what it is. Does anyone know the correct established way to do this. The following is actually a seperate (but related) font question (in case anyone is expert in all this.) Its rather a lengthy question and can be skipped, but its something that's plagued me for a long time. I mention above embedding as a "SystemFont", so iow something like this: package fonts { import flash.display.Sprite; public class FLW_Script_I extends Sprite { [Embed(systemFont='FLW Script', fontName='FLW Script', fontStyle='italic', fntWeight='normal', mimeType='application/x-font-truetype')] public var wrFont:Class; } } The other alternative to SystemFont for embedding, is "Source" followed by the name of an actual font file. If you try to embed one of the aformentioned single file fonts as a Source file (as opposed to SystemFont) and specify fontStyle='italic', then the mxmlc compiler will return an error and say there is no italic info in the font file. So up to now I have only been embedding these fonts as "SystemFont". The problem is, flex uses two different font compilers internally for Source embedding and SystemFont embedding. For source font embeds it uses the "Batik" compiler and for SystemFont, the JRE (Java Runtime) font compiler. Well actually the Batik is considered a superior compiler and generally produces better looking fonts. And also if you mix normal fonts compiled with Batik and italic compiled with JRE, sometimes the line spacing is different for the two, and it doesn't look right. So does anyone have an idea how to get mxmlc to do italic and bold for these single file fonts when embedding as "Source". Would there be a way using C++ or whatever to construct an "italic" font file from the SystemFont for such a font in windows.

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  • appendTo() inside $.each in jquery seems to cause flicker....

    - by Pandiya Chendur
    appendTo() causes flicker when it is inside $.each.... $.each(jsob.Table, function(i, employee) { $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').appendTo('#ResultsDiv'); }); Right now i am appending every new div to #ResultsDiv inside$.each is it good/bad to do so... If it is bad What can be done to make my divs appendTo() after the loop so that i it wont flicker.... EDIT:(based on answer) var divs = ''; $.each(jsob.Table, function(i, employee) { divs += '<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>'; }); $("#ResultsDiv").append(divs); But that too doesn't stop the flicker...

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  • Updating form values with javascript

    - by shinjuo
    I have a page that I made that is going to be used for retrieving shipping rates from UPS by entering the weight and zip. Everything works fine but what I want to add to it is the ability for the user to choose something on a form and have it update the value in a different form box. I think this is done with javascript. Any suggestions will help.

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  • Dijkstra's Algorithm explanation java

    - by alchemey89
    Hi, I have found an implementation for dijkstras algorithm on the internet and was wondering if someone could help me understand how the code works. Many thanks private int nr_points=0; private int[][]Cost; private int []mask; private void dijkstraTSP() { if(nr_points==0)return; //algorithm=new String("Dijkstra"); nod1=new Vector(); nod2=new Vector(); weight=new Vector(); mask=new int[nr_points]; //initialise mask with zeros (mask[x]=1 means the vertex is marked as used) for(int i=0;i<nr_points;i++)mask[i]=0; //Dijkstra: int []dd=new int[nr_points]; int []pre=new int[nr_points]; int []path=new int[nr_points+1]; int init_vert=0,pos_in_path=0,new_vert=0; //initialise the vectors for(int i=0;i<nr_points;i++) { dd[i]=Cost[init_vert][i]; pre[i]=init_vert; path[i]=-1; } pre[init_vert]=0; path[0]=init_vert; pos_in_path++; mask[init_vert]=1; for(int k=0;k<nr_points-1;k++) { //find min. cost in dd for(int j=0;j<nr_points;j++) if(dd[j]!=0 && mask[j]==0){new_vert=j; break;} for(int j=0;j<nr_points;j++) if(dd[j]<dd[new_vert] && mask[j]==0 && dd[j]!=0)new_vert=j; mask[new_vert]=1; path[pos_in_path]=new_vert; pos_in_path++; for(int j=0;j<nr_points;j++) { if(mask[j]==0) { if(dd[j]>dd[new_vert]+Cost[new_vert][j]) { dd[j]=dd[new_vert]+Cost[new_vert][j]; } } } } //Close the cycle path[nr_points]=init_vert; //Save the solution in 3 vectors (for graphical purposes) for(int i=0;i<nr_points;i++) { nod1.addElement(path[i]); nod2.addElement(path[i+1]); weight.addElement(Cost[path[i]][path[i+1]]); } }

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  • Would anybody mind taking a look at my XML structure?

    - by Bill H
    I am relatively new to this but I was hoping somebody could offer up a good critique of this XML structure I put together. I am not looking for anything in depth but rather if somebody notices anything inherently wrong with the structure (or any tips to make it better) I'd greatly appreciate it. We have a large amount of products that we wholesale out and our customers were looking for a data feed to incorporate our products into their websites. <product modified=""> <id></id> <title></title> <description></description> <upc></upc> <quantity></quantity> <images> <image width="" height=""></image> <image width="" height=""></image> <image width="" height=""></image> </images> <category> <name></name> <subcategory></subcategory> </category> <sale expiration="">yes</sale> <msrp></msrp> <cube></cube> <weight></weight> <pricing> <tier> <pack><pack> <price></price> </tier> <tier> <pack><pack> <price></price> </tier> <tier> <pack><pack> <price></price> </tier> </pricing> </product> We sell in 3 different pack sizes hence the pricing node.

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  • Writing user agents to control Internet access

    - by gipsy
    Ho will I go about writing a light weight agent to be installed on machines (windows to begin with) that controls Internet access Also these agents need to communicate to central server over the Internet. What areas of technology I should start reading/learning in order to develop it myself?

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  • Cucumber and Silverlight 4

    - by weijiajun
    So I am wondering if anyone is familiar or has done any work with cucumber and Silverlight. I currently have a template directory and build file that will create RSpec tests using Bacon (light weight RSpec). I have been looking into SpecFlow and Cuke2Nuke but almost everything I have seen works with general .net code not silverlight code. Thanks.

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  • Problem on a Floyd-Warshall implementation using c++

    - by Henrique
    I've got a assignment for my college, already implemented Dijkstra and Bellman-Ford sucessfully, but i'm on trouble on this one. Everything looks fine, but it's not giving me the correct answer. Here's the code: void FloydWarshall() { //Also assume that n is the number of vertices and edgeCost(i,i) = 0 int path[500][500]; /* A 2-dimensional matrix. At each step in the algorithm, path[i][j] is the shortest path from i to j using intermediate vertices (1..k-1). Each path[i][j] is initialized to edgeCost(i,j) or infinity if there is no edge between i and j. */ for(int i = 0 ; i <= nvertices ; i++) for(int j = 0 ; j <= nvertices ; j++) path[i][j] = INFINITY; for(int j = 0 ; j < narestas ; j++) //narestas = number of edges { path[arestas[j]->v1][arestas[j]->v2] = arestas[j]->peso; //peso = weight of the edge (aresta = edge) path[arestas[j]->v2][arestas[j]->v1] = arestas[j]->peso; } for(int i = 0 ; i <= nvertices ; i++) //path(i, i) = 0 path[i][i] = 0; //test print, it's working fine //printf("\n\n\nResultado FloydWarshall:\n"); //for(int i = 1 ; i <= nvertices ; i++) // printf("distancia ao vertice %d: %d\n", i, path[1][i]); //heres the problem, it messes up, and even a edge who costs 4, and the minimum is 4, it prints 2. //for k = 1 to n for(int k = 1 ; k <= nvertices ; k++) //for i = 1 to n for(int i = 1 ; i <= nvertices ; i++) //for j := 1 to n for(int j = 1 ; j <= nvertices ; j++) if(path[i][j] > path[i][k] + path[k][j]) path[i][j] = path[i][k] + path[k][j]; printf("\n\n\nResultado FloydWarshall:\n"); for(int i = 1 ; i <= nvertices ; i++) printf("distancia ao vertice %d: %d\n", i, path[1][i]); } im using this graph example i've made: 6 7 1 2 4 1 5 1 2 3 1 2 5 2 5 6 3 6 4 6 3 4 2 means we have 6 vertices (1 to 6), and 7 edges (1,2) with weight 4... etc.. If anyone need more info, i'm up to giving it, just tired of looking at this code and not finding an error.

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