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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • how to decorate the error message

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • What could cause xmlrpclib.ResponseError: ResponseError() ?

    - by Tom
    Hi, I am experimenting with XML-RPC. I have the following server script (python): from SimpleXMLRPCServer import SimpleXMLRPCServer server = SimpleXMLRPCServer(('localhost', 9000)) def return_input(someinput): return someinput server.register_function(return_input) try: print 'ctrl-c to stop server' server.serve_forever() except KeyboardInterrupt: print 'stopping' and the following client script: import xmlrpclib server = xmlrpclib.ServerProxy('http://www.example.com/pathto/xmlrpcTester2.py') print server.return_input('some input') I have tested this locally and it works fine. All it does it spit out the input fron the client script, which is right. However, when I try to do it on a remote server I get the following error: Traceback (most recent call last): File "client.py", line 4, in <module> print server.return_input('some input') File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1199, in __call__ return self.__send(self.__name, args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1489, in __request verbose=self.__verbose File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1253, in request return self._parse_response(h.getfile(), sock) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1392, in _parse_response return u.close() File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 836, in close raise ResponseError() xmlrpclib.ResponseError: ResponseError() Any ideas what could cause this? Thanks in advance for your help.

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  • Managing hosts and iptables in scalable architecture

    - by hakunin
    Let's say I have a load balancer in front of 3 app servers. Let's say I also have these services available at certain IPs: Postgres server Redis server ElasticSearch server Memcached server 1 Memcached server 2 Memcached server 3 So that's 6 nodes at 6 different IP addresses. Naturally, every one of my 3 app servers needs to talk to these 6 servers above. Then, to make it a bit funkier, I also have 3 worker servers. And each worker also talks to the above 6 servers, but thankfully workers and apps never need to talk to each other. Now's the kicker. Everything is on Digital Ocean VPS. What that means is: you have no private network, no private IPs. You only have separate, random IP address on each machine. You can't mask them or anything. So in order to build a secure environment I would have to configure some iptables. For example: Open app servers be accessed by load balancer server Open redis, ES, PG, and each memcached servers to be accessed by each app's IP and each worker's IP This means that every time I add an app or worker I have to also reconfigure iptables in those above 6 servers to welcome the new app or worker. Is there a way to simplify this type of setup? I was thinking — what if there was a gateway machine between apps/workers and the above 6 machines. This way all the interaction would always happen via the gateway server, and when I add a new app or worker I wouldn't need to teach the 6 servers to let it in. If I went this route, then I'd hope a small 512mb server could handle that perhaps, and there wouldn't be almost any overhead. Or would there? Please help with best way to handle this situation. I would appreciate an answer as concrete as possible. I don't think this is too specific, because this general architecture is very common, and Digital Ocean is becoming increasingly popular. A concrete solution here would be much appreciated by many.

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  • How to check whether user is login in web application?

    - by Morgan Cheng
    I want to learn the whole details of web application authentication. So, I decided to write a CodeIgniter authentication library from scratch. Now, I have to make design decision about how to determine whether one user is login. Basically, after user input username & password pair. A cookie is set for this session, following navigations in the web application will not require username & password. The server side will check whether the session cookie is valid to determine whether current user is login. The question is: how to determine whether cookie is valid cookie issued from server side? I can image the most simple way is to have the cookie value stored in session status as well. For each HTTP request, compare the value from cookie and the value from server session. (Since CodeIgniter session library store session variables in cookies, it is not applicable without some tweak.) This method requires storage in server side. For huge web application that is deployed in multiple datacenters. It is possible that user input username & password when browsing in one datacenter, while he/she access the web application in another datacenter later. The expected behavior is that user just input username & password once. As a result, all datacenters should be able to access the session status. That is possible not applicable even the session status is stored in external storage such as database. I tried Google. I login Google with Asian proxy which is supposed to direct me to datacenters in Asian. Then I switch to North American proxy which should direct me to datacenters in North America. It recognize my login without asking username and password again. So, is there any way to determine whether user is login without server side session status?

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  • Jquery Append() and remove() element

    - by BandonRandon
    Hi, I have a form where I'm dynamically adding the ability to upload files with the append function but I would also like to be able to remove unused fields. Here is the html markup <span class="inputname">Project Images: <a href="#" class="add_project_file"><img src="images/add_small.gif" border="0"></a></span> <span class="project_images"> <input name="upload_project_images[]" type="file" /><br/> </span> Right now if they click on the "add" gif a new row is added with this jquery $('a.add_project_file').click(function() { $(".project_images").append('<input name="upload_project_images[]" type="file" class="new_project_image" /> <a href="#" class="remove_project_file" border="2"><img src="images/delete.gif"></a><br/>'); return false; }); To remove the input box i've tried to add the class "remove_project_file" then add this function. $('a.remove_project_file').click(function() { $('.project_images').remove(); return false;}); I think there should be a much easier way to do this. Maybe i need to use the $(this) function for the remove. Another possible solution would be to expand the "add project file" to do both adding and removing fields. Any of you JQuery wizards have any ideas that would be great

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  • Submit button on nested form submits the outer form in IE7

    - by Mike Christensen
    I have the following code on my Home.aspx page: <form id="frmJump" method="post" action="Views/ViewsHome.aspx"> <input name="JumpProject" /><input type="submit" value="Go" /> </form> However, when I click the "Go" button, the page posts back to Home.aspx rather than going to ViewsHome.aspx. I even tried adding some script to force the form to submit: <input name="JumpProject" onkeypress="if(event.keyCode == 13) { this.form.submit(); return false; }" /> But still even if I press ENTER, the Home.aspx page is reloaded. The only thing I can see that might be borking things is this form is actually a child form of the main POSTBACK form that ASP.NET injects into the page. I'm sure there's something stupid I'm missing and this post will get 800 downvotes instantly banishing me back into the n00b realm, but perhaps I haven't gotten enough sleep lately and I'm missing something stupid. This is on IE7 and an ASP.NET 4.0 backend. I also have jQuery libraries loaded on the page incase jQuery can improve this somehow. Thanks!

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  • Is it possible to fix photos that are taken blurred

    - by Ieyasu Sawada
    I took pictures with a digital camera and I didn't notice that the blur setting is on so the pictures that were taken were all blurred. The camera has no edit feature. Is it still possible to fix it using photoshop? I followed this tutorial on youtube: http://www.youtube.com/watch?v=SpWDihBHRqM which uses photoshop but no luck. As much as possible I want to see the output that is close to a picture that is taken without the blur setting on.

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  • Creating DOM elements on the fly - check if the data is not harmful

    - by user313353
    I already posted a question closely related to the this one. I watched the Mix10 video with P. Haacked and S. Hanselman. I am building an AJAX-powered site whose input forms are created on the fly. All the code to accomplish this is done within a script tag or a javascript file. For example the following DOM elements are created when the page loads and are wrapped into an existing div defined in a view: $('#myform').append('); $('#myform').append(''); When I click the submit button I need to get the values of the input form whose id is 'Name': $("#Name").val() and then I return a Json object: { Name: name }; For this kind of scenario there is no way to use Html.Encode() or AntiXss.HtmlEncode() on the client-side. The only way to check if the input is not harmful is done on the server-side (via a service layer). This seems a limitation. All is fine if and only if a view has a set of predefined inputs. When it is time to create them on the fly, the situation is different. Have you thought of that situation guys? Thanks for the attention you have put on this. Roland Brussels, Belgium

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  • hy i dont get the check value in check box?

    - by udaya
    Hi I have a check box when check that check box the id corresponding to the check box is placed on a text box ... but when there is only single value in the database i cant get the check value why? here is my code <? if(isset($AcceptFriend)) {?> <form action="<?=site_url()?>friends/Accept_Friend" name="orderform" id="orderform" method="post" style="background:#CCCC99"> <input type="text" name="chId" id="chId" > <table border="0" height="50%" id="chkbox" width="50%" > <tr> <? foreach($AcceptFriend as $row) {?> <tr> <td>Name</td><td><?=$row['dFrindName'].'</br>';?></td> <td> <input type="checkbox" name="checkId" id="checkId" value="<? echo $row['dMemberId']; ?>" onClick="get_check_value()" ></td> </tr> <? }}?> </tr> <tr> <td width="10px"><input type="submit" name="submit" id="submit" class="buttn" value="AcceptFriend"></td></tr> </table> </form> This is the script i am using function get_check_value() { var c_value = ""; for (var i=0; i < document.orderform.checkId.length; i++) { if (document.orderform.checkId[i].checked) { c_value = c_value + document.orderform.checkId[i].value + "\n"; } } alert(c_value); document.getElementById('chId').value= c_value; }

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  • How to link different Servlet together?

    - by Harry Pham
    First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

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  • How do i select all text nodes using XSL?

    - by user323719
    I want to get the generate-id(.) of all the text nodes after node and before node . I am looking for some generic XSL and not tightly coupled to the sample input pattern mentioned below. For any input pattern i want to get the ids of all the text nodes between node and . Sample input for better understanding: <a> <b> <c> This is first text node </c> </b> <d> <e> This is my second text node </e> <f> This is my <m/>third text node </f> <g> One more text node </g> <h> <i> This is my fourth text node </i> </h> <j> This is my fifth <n/>text node </j> <k> <l> This is my sixth text node </l> </k> </d> </a> Expected output: Generate id of the text nodes with values "third text node ", "One more text node", "This is my fourth text node", "This is my fifth" which lie inbetween nodes <m/> and <n/> Please give your ideas.

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  • jquery closest dl element

    - by Sebastiaan
    HTML: <dl id="feature-list"> <dt id="basic" class="category-name"> <dd id="basic-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox1" type="checkbox"> </div> </div> </dd> <dt id="options" class="category-name"> <dd id="options-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox2" type="checkbox"> </div> </div> </dd> </dl> JQUERY $('input').change(function () { var value = $(this).closest("dt"); //do something with value.id }); $(this).closest("dt") returns the checkbox instead of <dt id="(category)" class="category-name"> I tried $(this).closest(.category-name), $(this).closest("dt").find(.category-name)

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  • Terminate function on System.in .. possible?

    - by Ronald
    I am currently working on a project where I have to make an agent to interact with a server. Each 50ms, the server will receive the last thing I outputted to System.out and send me a new set of lines as a 'state' through the System.in printstream to analyze and send my next message to System.out. Also, if the server receives multiple outputs from me, it only regards the most recent one. .. As for my question: My program originally constructed a tree and then analyzed each leaf node to see which would be optimal, and then waited around for the next input, but I can recursively do a deeper tree search that would make my output 'better' (and again and again to keep returning a better result). Using this and the fact that if the server receives multiple outputs, it only takes the most recent one, I could do each level, print my result and start the next level. But here comes my problem... I can't be stuck in some complex algorithm while I am supposed to receiving the next input as I will then miss it. So I was wondering if there is a way to cancel anything else I am doing when I receive something via System.in and then go back to the beginning of the function and start the search again with the new set of input (and rinse and repeat..) I hope this all makes sense, Thank ye all

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  • Generating wildcard SSL certificate

    - by Xiè Jìléi
    I can make a single SSL certificate for several different domain names: www1.example.com www2.example.com www3.example.com But *.example.com doesn't work. How can I make a single SSL certificate for all sub domains within .example.com? P.S. Here is the extension part of the generated certificate: X509v3 extensions: X509v3 Basic Constraints: CA:FALSE X509v3 Key Usage: Digital Signature, Non Repudiation, Key Encipherment X509v3 Subject Alternative Name: DNS:*.example.com It's simply not matched by any sub-domain under example.com by the browser.

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  • i5+SSD or i7+HDD gives better performance [closed]

    - by Cas Sakal
    Which performs better for developers on a notebook(running VS.NET, SQL Server, no gaming); (A) i5 540M + SSD (Intel) or (B) i7 720M + 7200 RPM HDD (Western Digital) In short, I want to ask whether the performance difference between i5 540M and i7 720M can be compensated via using solid state drive instead of using a hard drive? Thank you, cas

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  • Load some data from database and hide it somewhere in a web page

    - by kwokwai
    Hi all, I am trying to load some data (which may be up to a few thousands words) from the database, and store the data somewhere in a html web page for comparing the data input by users. I am thinking to load the data to a Textarea under Div tag and hide the the data: <Div id="reference" style="Display:none;"> <textarea rows="2" cols="20" id="database"> html, htm, php, asp, jsp, aspx, ctp, thtml, xml, xsl... </textarea> </Div> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type="text" name="data" id="data"> </div> </td> </tr> </table> <script> $(document).ready(function(){ //comparing the data loaded from database with the user's input if($("#data").val()==$("#database").val()) {alert("error");} }); </script> I am not sure if this is the best way to do it, so could you give me some advice and suggest your methods please.

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  • JSP JPA Form: how to insert value in a path variable

    - by kajarigd
    I have the following code snippet in a jsp file: <hr> <form:form commandName="newTicketSale" id="reg" action="transactionResult.htm"> <h3>Buy Movie Tickets:</h3> <form:label path="movieName">Movie Name:</form:label> <form:input path="movieName" /> <form:errors class="invalid" path="movieName" /> <form:label path="ticketPrice">Ticket Price:</form:label> <form:input path="ticketPrice" /> <form:errors class="invalid" path="ticketPrice" /> <input type="submit"> <br><br> </form:form> I am using JPA tags in this jsp. Now, in the commandName "newTicketSale" there is another parameter called userId. In the jsp file itself I need to insert value ${name} in userId, so that in the Controller file when I am doing @Valid @ModelAttribute("newTicketSale") MovieTicket newTicket I can retrieve the value ${name} when I am doing newTicket.getUserId(). I don't know how to do this. Please help! Thanks in advance!

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  • Jquery toggle event is messing with checkbox value

    - by John McCollum
    Hi all, I'm using Jquery's toggle event to do some stuff when a user clicks a checkbox, like this: $('input#myId').toggle( function(){ //do stuff }, function(){ //do other stuff } ); The problem is that the checkbox isn't being ticked when I click on the checkbox. (All the stuff I've put into the toggle event is working properly.) I've tried the following: $('input#myId').attr('checked', 'checked'); and $(this).attr('checked', 'checked'); and even simply return true; But nothing is working. Can anyone tell me where I'm going wrong? Edit - thanks to all who replied. Dreas' answer very nearly worked for me, except for the part that checked the attribute. This works perfectly (although it's a bit hacky) $('input#myInput').change(function () { if(!$(this).hasClass("checked")) { //do stuff if the checkbox isn't checked $(this).addClass("checked"); return; } //do stuff if the checkbox isn't checked $(this).removeClass('checked'); }); Thanks again to all who replied.

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • PHP - uninitialized array offset

    - by kimmothy16
    Hey everyone, I am using PHP to create a form with an array of fields. Basically you can add an unlimited number of 'people' to the form and each person has a first name, last name, and phone number. The form requires that you add a phone number for the first person only. If you leave the phone number field blank on any others, the handler file is supposed to be programmed to use the phone number from the first person. So, my fields are: person[] - a hidden field with a value that is this person's primary key. fname[] - an input field lname[] - an input field phone[] - an input field my form handler looks like this: $people = $_POST['person'] $counter = 0; foreach($people as $person): if(phone[$counter] == '') { // use $phone[0]'s phone number } else { // use $phone[$counter] number } $counter = $counter + 1; endforeach; PHP doesn't like this though, it is throwing me an Notice: Uninitialized string offset error. I debugged it by running the is_array function on people, fname, lname, and phone and it returns true to being an array. I can also manually echo out $phone[2], etc. and get the correct value. I've also ran is_int on the $counter variable and it returned true, so I'm unsure why this isn't working as intended? Any help would be great!

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  • android httpurlconnection [closed]

    - by user620451
    hi im new android developer i am trying to login to my asterisk server passing my username and password it works good but when i am trying to request anther url to the server after login i get access denied and i now the problem because the login connection has disconnected so i want a way to request to urls the first one is login to the server and the second is to do something else after login please help and thx anyway this is a part of my code i want to request this 2 url url1="http://192.168.1.7:8088/rawman?action=login&username=admin&secret=admin" url2="http://192.168.1.5:8088/rawman?action=updateconfig&reload=yes&srcfilename=users.conf&dstfilename=users.conf&Action-000000=newcat&Cat-000000=6001&Var-000000=&Value-000000=" public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); tv1 = (TextView) this.findViewById(R.id.display); ed1 = (EditText) this.findViewById(R.id.editText); bt1 = (Button) this.findViewById(R.id.submit); bt1.setOnClickListener(new OnClickListener() { public void onClick(View view) { { try{ ServerRequest(url1); ServerRequest(url2); } catch(Exception e) { Log.v("Exception", "Exception:"+e.getMessage()); } } } }); } public String ServerRequest(String serverString) throws MalformedURLException, IOException { String newFeed=serverString; StringBuilder response = new StringBuilder(); Log.v("server","server url:"+newFeed); URL url = new URL(newFeed); HttpURLConnection httpconn = (HttpURLConnection) url.openConnection(); if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK) { BufferedReader input = new BufferedReader( new InputStreamReader(httpconn.getInputStream()), 8192); String strLine = null; while ((strLine = input.readLine()) != null) { response.append(strLine); } input.close(); } tv1.settext(response); return response.toString(); }

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  • How can I determine the sector size on an external hard drive?

    - by sigint
    Hard drives are transitioning from 512 byte to 4096 byte sector sizes, and it looks like Windows XP won't support these newer drives without additional software (such as WDalign from Western Digital) My question is: how does this affect external hard drives? I'll be buying a 1TB USB external drive, and it'll be plugged into a mix of Windows 7 and XP machines. Is there an easy way to tell what the sector size on an external hard drive is?

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