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  • javascript return function's data as a file

    - by Dennis
    I have a function in javascript called "dumpData" which I call from a button on an html page as **onlick="dumpData(dbControl);"* What it does is return an xml file of the settings (to an alert box right now). I want to return it to the user as a file download. Is there a way to create a button when click will open a file download box and ask the user to save or open it? (sorta of like right-clicking and save target as)... Or can it be sent to a php file and use export();? Not sure how I would send a long string like that to php and have it simple send it back as a file download. Dennis

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  • C#/MonoDevelop: GTK MessageDialogs require a doubleclick to close - why?

    - by Connel
    I'm a newbie programmer writting a program in MonoDevelop in C# and have a porblem with my gtk MessageDialogs. The close button on the window boarders of my GTK Message dialogues require a double click to actually close them. The close button on the dialogue its self works fine. Could someone please tell me how I can fix this below is the code: if (fchDestination.CurrentFolder == fchTarget.CurrentFolder) { MessageDialog msdSame = new MessageDialog(this, DialogFlags.Modal, MessageType.Error, ButtonsType.Close, "Destination directory cannot be the same as the target directory"); msdSame.Title="Error"; if ((ResponseType) msdSame.Run() == ResponseType.Close) { msdSame.Destroy(); } return; } if (fchTarget.CurrentFolder.StartsWith(fchDestination.CurrentFolder)) { MessageDialog msdContains = new MessageDialog(this, DialogFlags.Modal, MessageType.Error, ButtonsType.Close, "error"); msdContains.Title="Error"; if ((ResponseType) msdContains.Run() == ResponseType.Close) { msdContains.Destroy(); } return; }

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  • (C# - windows forms) changing properties of controls that were added at runtime

    - by user257412
    I have a form in which several buttons are added at runtime via a 'for' method public Form() { for (int i = 0 ... ) Button b = new Button() b.text = (string) i ; etc.. etc.. } . now i wish to change the text property of the buttons on a certain event. How can this be accomplished? I have tried a few things but none worked.. since the buttons variables are inside the method , they are not available outside. Thanks

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  • How to do this layout? (Link on Image)

    - by Spredzy
    Hi all, I was wondering how to obtain this result : http://img718.imageshack.us/img718/6173/screenshot20100411at126.png This is what I tried : <RelativeLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:background="#CCCCCC" android:orientation="horizontal" android:layout_weight="0"> <Button android:id="@+id/btn_cancel" android:text="@string/cancel" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_margin="5px" android:gravity="left" /> <Button android:id="@+id/btn_save" android:text="@string/save" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_margin="5px" android:layout_toRightOf="@id/btn_cancel" android:gravity="right"/> </RelativeLayout> I tried to play with the layout_width properties and setting them up to fill parents both of them but did not work, if anyone has an idea ... Thank you !

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  • Have problems designing input and output for a calculator app

    - by zoul
    Hello! I am writing a button calculator. I have the code split into model, view and a controller. The model knows nothing about formatting, it is only concerned with numbers. All formatting is done in the view. The model gets its input as keypresses, each keypress is a part of an enum: typedef enum { kButtonUnknown = 0, kButtonMemoryClear = 100, kButtonMemoryPlus = 112, kButtonMemoryMinus = 109, kButtonMemoryRecall = 114, kButtonClear = 99, … }; When the user presses a button (say 1), the model receives a button code (kButtonNum1), adds the corresponding number to a string input buffer ("1") and updates the numeric output value (1.0). The controller then passes the numeric output value to the view that formats it (1). This is all plain, simple and clean, but does not really work. The problem is that when user enters a part of a number (say 0.00, going to enter 0.001), the input does not survive the way through model to view and the display says 0 instead of 0.00. I know why this happens ("0.00"::string parses to 0::double and that gets formatted as 0). What I don’t know is how to design the calculator so that the code stays clean and simple and the numbers will show up on screen exactly as the user types them. I’ve already come with some kind of solution, but that’s essentially a hack and breaks the beautiful and simple flow from the calculator model to the display. Ideas? Current solution keeps track of the calculator state. If the calculator is building a number, I take the calculator input buffer (a string) and directly set the display contents (also a string). Otherwise I take the proper path, ie. take the numeric calculator output, pass it to the view as a double and the view uses its internal formatter to create a string for the display. Example input: input | display | mode ------+---------+------------ 0 | 0 | from string 0. | 0. | from string 0.0 | 0.0 | from string 0.0+ | 0 | from number This is ugly. (1) The calculator has to expose its input buffer and state. (2) The view has to expose its display and allow setting its contents directly using a string. (3) I have to duplicate some of the formatting code to format the string I got from the calculator input buffer. If user enters 12345.000, I have to display 12,345.000 and therefore I’ve got to have a commification code for strings. Yuck.

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  • Sync a WinForm with DatagridView

    - by Ruben Trancoso
    I have a Form with a DataGridView which DataSource is a BindingSource to a table. This view will have a single row selection and a button to delete, edit the current selected row in a popup Form and a insert button that will use the same Form as well. My question is how can I sync the pop Form with the current row? I tryied to use the RowStateChanged event to get and store the current selected Row to be used in the Form but I coudnt. After the event I get the row that was selected before. Other thing I dont understand yet in C# how to have a single recordSet and know wich is the current record even if its a new being inserted in a way that once in the Form all data being entered will show up at the same time in the DataGridView.

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  • Android popup style activity which sits on top of any other apps

    - by RenegadeAndy
    What I want to create is a popup style application. I have a service in the background - something arrives on the queue and i want an activity to start to inform the user - very very similar to the functionality of SMSPopup app. So I have the code where something arrives on the queue and it calls my activity. However for some reason the activity always shows on top of the originally started activity instead of just appearing on the main desktop of the android device. As an example: I have the main activity which is shown when the application is run I have the service which checks queue I have a popup activity. When i start the main activity it starts the service - I can now close this. I then have something on the queue and it creates the popup activity which launches the main activity with the popup on top of it :S How do I stop this and have it behave as i want... The popup class is : package com.andy.tabletsms.work; import com.andy.tabletsms.tablet.R; import android.app.Activity; import android.content.Context; import android.content.Intent; import android.os.Bundle; import android.view.Gravity; import android.view.LayoutInflater; import android.view.View; import android.view.View.OnClickListener; import android.view.ViewGroup; import android.widget.Button; import android.widget.PopupWindow; import android.widget.TextView; import android.widget.Toast; public class SMSPopup extends Activity implements OnClickListener{ public static String msg; @Override public void onCreate(Bundle bundle){ super.onCreate(bundle); // Toast.makeText(getApplicationContext(), msg, Toast.LENGTH_LONG).show(); this.setContentView(R.layout.popup); TextView tv = (TextView)findViewById(R.id.txtLbl); Intent intent = getIntent(); if (intent != null){ Bundle bb = intent.getExtras(); if (bb != null){ msg = bb.getString("com.andy.tabletsms.message"); } } if(msg == null){ msg = "LOLOLOL"; } tv.setText(msg); Button b = (Button)findViewById(R.id.closeBtn); b.setOnClickListener(this); } @Override public void onClick(View v) { this.finish(); } } and I call the activity from a broadcast receiver which checks the queue every 30 seconds or so : if(main.msgs.size()0){ Intent testActivityIntent = new Intent(context.getApplicationContext(), com.andy.tabletsms.work.SMSPopup.class); testActivityIntent.putExtra("com.andy.tabletsms.message", main.msgs.get(0)); testActivityIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); context.startActivity(testActivityIntent); } The layout is here : http://pastebin.com/F25u6wdM

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  • How can I disable multiple links with jQuery?

    - by Samantha J
    I have the following HTML: <a title="Login" data-href="/MyAccount/Access/Login" data-title="Admin" data-entity="n/a" id="loginLink" class="nav-button dialogLink"><b>Login</b></a> <a title="Register" data-href="/MyAccount/Access/Register" data-title="Admin" data-entity="n/a" id="registerLink" class="nav-button dialogLink"><b>Register</b></a> When a user clicks on the #loginLink or #registerLink I would like to disable the link and call a dialog script. I created the following function: $("#loginLink, #registerLink") .click(function () { $('#loginLink').prop('disabled', true); $('#registerLink').prop('disabled', true); dialog(this); }); It calls the dialog correctly but doesn't disable the links and if I click the buttons more than once it calls up more than one dialog box. Is there something I am doing wrong? I can't see why it would not work.

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  • How do I use SLIDE instead of FADE in a YUI Menu animation?

    - by Avry
    I'm using the following configuration for a menu that is attached to a button: var srchTypeMenuConfig = { shadow: false, effect: { effect: YAHOO.widget.ContainerEffect.FADE, duration: .25 } }; I get a nice fade in and out for my menu when I click on the button; I'd rather have it slide in and out though. I replace YAHOO.widget.ContainerEffect.FADE with YAHOO.widget.ContainerEffect.SLIDE and the menu doesn't appear. Is there a way for me to get YUI to give me the slide effect? Here's what I've done so far: 1) Looked at the examples. 2) Looked at some effects examples from DavGlass' blog. 3) Searched the forums for 'ContainerEffect.SLIDE'. 4) Searched SO for 'ContainerEffect.SLIDE [YUI]'. I haven't found any helpful information. I suspect that I need to add something to my configuration, but I don't understand why fade would work but slide doesn't.

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  • How can I include additional markup within a 'Content' inner property of an ASP.Net WebControl?

    - by GenericTypeTea
    I've searched the site and I cannot find a solution for my problem, so apologies if it's already been answered (I'm sure someone must have asked this before). I have written a jQuery Popup window that I've packaged up as a WebControl and IScriptControl. The last step is to be able to write the markup within the tags of my control. I've used the InnerProperty attribute a few times, but only for including lists of strongly typed classes. Here's my property on the WebControl: [PersistenceMode(PersistenceMode.InnerProperty)] [DesignerSerializationVisibility(DesignerSerializationVisibility.Content)] public something??? Content { get { if (_content == null) { _content = new something???(); } return _content; } } private something??? _content; Here's the HTML Markup of what I'm after: <ctr:WebPopup runat="server" ID="win_Test" Hidden="false" Width="100px" Height="100px" Modal="true" WindowCaption="Test Window" CssClass="window"> <Content> <div style="display:none;"> <asp:Button runat="server" ID="Button1" OnClick="Button1_Click" /> </div> <%--Etc--%> <%--Etc--%> </Content> </ctr:WebPopup> Unfortunately I don't know what type my Content property should be. I basically need to replicate the UpdatePanel's ContentTemplate. EDIT: So the following allows a Template container to be automatically created, but no controls show up, what's wrong with what I'm doing? [PersistenceMode(PersistenceMode.InnerProperty)] [DesignerSerializationVisibility(DesignerSerializationVisibility.Content)] public ITemplate Content { get { return _content; } set { _content = value; } } private ITemplate _content; EDIT2: Overriding the CreateChildControls allows the controls within the ITemplate to be rendered: protected override void CreateChildControls() { if (this.Content != null) { this.Controls.Clear(); this.Content.InstantiateIn(this); } base.CreateChildControls(); } Unfortunately I cannot now access the controls within the ITemplate from the codebehind file on the file. I.e. if I put a button within my mark as so: <ctr:WebPopup runat="server" ID="win_StatusFilter"> <Content> <asp:Button runat="server" ID="btn_Test" Text="Cannot access this from code behind?" /> </Content> </ctr:WebPopup> I then cannot access btn_Test from the code behind: protected void Page_Load(object sender, EventArgs e) { btn_Test.Text = "btn_Test is not present in Intellisense and is not accessible to the page. It does, however, render correctly."; }

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  • Opening Another Xib form an Xib

    - by Goods
    Not a Noob as yesterday, but still green. I have been playing around with the code that Elisabeth Robson has put together HERE. I have a UITabbarcontoller and a IUNavigationController they seem to work fine. I have a UITableviewController to which I loads my NSMutable array. The user clicks a cell and didSelectRowAtIndexPath xib is loaded onto the stack. I put a 'Learn More' button on the current xib(BookDetailView). I've tried a few approaches to load a newer xib when the 'Learn More' button is pressed but have failed. Ive Tried IBAction and Pushing the Newer xib to the top. Do I need to create another view controller? Thanks for looking.

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  • How do I open android built in downloads app?

    - by user1502829
    So I'm downloading stuff and it gets put into the built in downloads app since thats how the download manager works. I just want to the user to click a button which opens the built in downloads app. Heres my try: btnDownloads.setOnClickListener(new Button.OnClickListener(){ public void onClick(View v) { PackageManager pakMan=MainActivity.context.getPackageManager(); Log.d("bebr", "Making pak"); if(pakMan!=null){ Intent downloadsIntent=new Intent(Intent.ACTION_MAIN).addCategory(Intent.CATEGORY_LAUNCHER).setComponent(new ComponentName("com.android.downloads","com.android.downlods.Downloads")); ResolveInfo resolved=pakMan.resolveActivity(downloadsIntent, PackageManager.MATCH_DEFAULT_ONLY); Log.d("bebr","Resolving"); if(resolved!=null){ Log.d("bebr", "Starting"); startActivity(downloadsIntent); } } } });

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  • how to maintain a Presistent state of an app in Android?

    - by androidbase Praveen
    hi all, i am working on my App. in between i pressed the Home button on the device. my app will go to the background tasks. After that i long press the home button it will show my app as a persistent state. i.e where and what i had done in my app. But i click my app in the directory window it restarts my app. i want to do if my app is in the background tasks it will wake up else it will start. how to achieve that? Any Idea?

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  • Form submits correctly in Chrome/FF, but fails altogether in IE/Safari

    - by culov
    I have a form with a css submit button. When a the submit button is clicked, i call a function that executes: document.forms["request"].onsubmit(); What should happen, then, is that the onsubmit method ought to be triggered. This works properly in Chrome/FF, but for some reason IE/Safari will bypass the onsubmit function and simply add the parameter "address=" onto the url as if it were submitting the form and ignoring the onsubmit function. Heres the code for the form: <form id="request" method="get" onsubmit="addLocation(this.address.value); return false;"> <br> <label style="position:relative;left:5px;" for="address">Enter an intersection or address: </label> <br> <br> <input style="height:35px; width:300px;position:relative;bottom:1px;left:10px;" id="address" name="address" class="required address"/> <a style="float:right;right:120px;position:relative;" class="button" onclick="submit();"> <span>Submit Request </span> </a> </form> and what follows are some relevant js functions: function addLocation(address) { if (geocoder) { geocoder.getLocations(address, function (point) { if (!point) { alert(address + " not found"); } else { if (point.Placemark[0].address != submittedString) { submittedString = point.Placemark[0].address; addRow(point.Placemark[0].address); req = "addrequest?truck=" + "coolhaus&address=" + point.Placemark[0].address; alert(req); addRequest(req); request.onreadystatechange = function () {} } } }); } } function addRequest(req) { try { request = new XMLHttpRequest(); } catch (e) { try { request = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) { alert("XMLHttpRequest error: " + e); } } request.open("GET", req, true); request.send(null); return request; } You can test the form here: http://la.truxmap.com/request?id=grillmastersla Thanks so much!

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  • how to submit a form without losing values already selected at the same form

    - by kawtousse
    Hi everyone, I am using jstl with dropdown lists. When i click submit button i success the specification but values int dropdownlists are reinitialized. So I want to submit form without loosing the values already selected in the form because I need to stay always at the same level in the form.To be more clear, user choose a value from ddl and click edit button to show other options and fill them at the same form without loosing what he has selected. I have tried to deal like that... <form action="myjsp.jsp" method="post"> <input type="Submit" value="Edit"> ...but it doesn't work. Thank you for your help.

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  • Uibutton events

    - by Raju
    //My Button code --------------------------------------------------------------------------------------------------- UIButton *ticketButtonObj=[[ticketButton alloc]initWithFrame:CGRectMake(0.0f, 115.0f, 500.0f, 40.0f) ; int col=10; [ticketButtonObj addTarget:self action:@selector(ShowNumber:) forControlEvents:UIControlEventTouchUpInside]; [self.window addSubview:ticketButtonObj]; -(void) ShowNumber:(id)sender{ // here i want to get the Value of Col } in the above code when i pressed the button.. i want print the value of col variable in ShowNumber method .. how it is ? pls Help me ... thanks and regards... by raju

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  • Is there any way that an export-to-Excel function can be scalable?

    - by MusiGenesis
    Summary: ASP.Net website with a couple hundred users. Data is exported to Excel files which can be relatively large (~5 MB). In the pilot phase (just a few users), we are already seeing occasional errors on the server in the exporting method. Here's the stack trace: System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. --- System.OutOfMemoryException: Exception of type 'System.OutOfMemoryException' was thrown. at System.IO.MemoryStream.set_Capacity(Int32 value) at System.IO.MemoryStream.EnsureCapacity(Int32 value) at System.IO.MemoryStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Packaging.TrackingMemoryStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Packaging.SparseMemoryStream.WriteAndCollapseBlocks(Byte[ ] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Packaging.SparseMemoryStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Packaging.CompressEmulationStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Packaging.CompressStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Zip.ProgressiveCrcCalculatingStream.Write(Byte[] buffer, Int32 offset, Int32 count) at MS.Internal.IO.Zip.ZipIOModeEnforcingStream.Write(Byte[] buffer, Int32 offset, Int32 count) at System.IO.StreamWriter.Flush(Boolean flushStream, Boolean flushEncoder) at System.IO.StreamWriter.Write(String value) at System.Xml.XmlTextEncoder.Write(String text) at System.Xml.XmlTextWriter.WriteString(String text) at System.Xml.XmlText.WriteTo(XmlWriter w) at System.Xml.XmlAttribute.WriteContentTo(XmlWriter w) at System.Xml.XmlAttribute.WriteTo(XmlWriter w) at System.Xml.XmlElement.WriteTo(XmlWriter w) at System.Xml.XmlElement.WriteContentTo(XmlWriter w) at System.Xml.XmlElement.WriteTo(XmlWriter w) at System.Xml.XmlElement.WriteContentTo(XmlWriter w) at System.Xml.XmlElement.WriteTo(XmlWriter w) at System.Xml.XmlElement.WriteContentTo(XmlWriter w) at System.Xml.XmlElement.WriteTo(XmlWriter w) at System.Xml.XmlDocument.WriteContentTo(XmlWriter xw) at System.Xml.XmlDocument.WriteTo(XmlWriter w) at System.Xml.XmlDocument.Save(Stream outStream) at OfficeOpenXml.ExcelWorksheet.Save() in C:\temp\XXXXXXXXXX\ExcelPackage\ExcelWorksheet.cs:line 605 at OfficeOpenXml.ExcelWorkbook.Save() in C:\temp\XXXXXXXXXX\ExcelPackage\ExcelWorkbook.cs:line 439 at OfficeOpenXml.ExcelPackage.Save() in C:\temp\XXXXXXXXXX\ExcelPackage\ExcelPackage.cs:line 348 at Framework.Exporting.Business.ExcelExport.BuildReport(HttpContext context) at WebUserControl.BtnXLS_Click(Object sender, EventArgs e) in C:\TEMP\XXXXXXXXXX\XXXXXXXXXX\OneList\UserControls\TicketReportExporter. ascx.cs:line 108 at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.Rai sePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) --- End of inner exception stack trace --- at System.Web.UI.Page.HandleError(Exception e) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest() at System.Web.UI.Page.ProcessRequestWithNoAssert(HttpContext context) at System.Web.UI.Page.ProcessRequest(HttpContext context) at ASP.XXXXXXXXXXX_aspx.ProcessRequest(HttpContext context) in c:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\Temporary ASP.NET Files\XXXX\cdf32a52\d1a5eabd\App_Web_enxdwlks.1.cs:line 0 at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpAppli cation.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) Even aside from this particular problem, in general exporting to Excel requires the instantiation of huge Excel objects on the server for each request, which I've always assumed to mean disqualifies Excel for "serious" work on a highly-loaded server. Is there any general way to export to Excel in a "light-weight" manner? Would simply streaming the data into a CSV file work for this?

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  • IPhone UIView:Is it possible to enable userinteraction only on subviews?

    - by Syg
    Hi guys, I created a viewcontroller that displays a button which is used to slide a view onto the screen. The idea is to place for instance three such viewcontrollers onscreen, resulting in three buttons at the bottom of the screen providing navigation. The viewcontrollers get stacked, so to the top one is now overlaying the other views and therefore the other buttons. Only the top viewcontroller's button is working in this situation, where I would like all three of them to be clickable. I tried disabling userinteraction on the view and enabling it on the buttons only, but it looks like the superview settings overrule the subview settings. Any ideas?

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  • Jquery Clear / reset .Queue() ?

    - by Wes
    I have the following code that triggers two functions whenever a button is clicked. However it only fires the functions once. If i click it again, it does nothing. I need to reset this queue so it fires the functions everytime I click the button. Also, I'm only doing this so I can delay the functions from be fired 1000ms - is there another way to do this? $('#play').click(function() { // other code.. $(this).delay(1000).queue(function(){ countHourly(); countFlights() }); });

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  • Cocoa-Binding : Submit changes manually?

    - by Holli
    Hello in my application I have a NSTableView bound to an ArrayController (arrangedObjects). I also have a Details-View (just some textfields) bound to the same Controller (selection). Now every time I edit a textfield the changes are automatically send to the ArrayController and the Table changes as well. How can I avoid this? What I want is a "Submit-Button". Changes on the data should only be send to the controller when I press the button and not automatically every time I do an edit.

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  • i cannot see movie playing in iphone simulator

    - by Neelam Roy
    Hi, i have created a application that plays movie on button click..my application is running without any warning or error. But i am not able to see the movie don't know why? I have added the Media player framework and also imported the #import in viewController.h my button action code is as follow... -(IBAction)playMyMovie:(id)sender{ NSBundle *bundle =[NSBundle mainBundle]; NSString *moviePath = [bundle pathForResource:@"jumps" ofType:@"mov"]; NSURL *movieURL = [[NSURL fileURLWithPath:moviePath] retain]; MPMoviePlayerController *theMovie =[[MPMoviePlayerController alloc] initWithContentURL:movieURL]; theMovie.scalingMode = MPMovieScalingModeAspectFill; [theMovie play]; } Please tell me what i am missing..

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  • Using Jquery.Form Plugin + MultiFile to automatically upload a single file

    - by Alan Neal
    I wanted to find a way to upload a single file*, in the background, have it start automatically after file selection, and not require a flash uploader, so I am trying to use two great mechanisms (jQuery.Form and JQuery MultiFile) together. I haven't succeeded, but I'm pretty sure it's because I'm missing something fundamental. Just using MultiFile, I define the form as follows... <form id="photoForm" action="image.php" method="post" enctype="multipart/form-data"> The file input button is defined as... <input id="photoButton" "name="sourceFile" class="photoButton max-1 accept-jpg" type="file"> And the Javascript is... $('#photoButton').MultiFile({ afterFileSelect: function(){ document.getElementById("photoForm").submit(); } }); This works perfectly. As soon as the user selects a single file, MultiFile submits the form to the server. If instead of using MultiFile, as shown above, let's say I include a Submit button along with the JQuery Form plugin defined as follows... var options = { success: respondToUpload }; $('#photoForm').ajaxForm(options); ... this also works perfectly. When the Submit button is clicked, the form is uploaded in the background. What I don't know how to do is get these two to work together. If I use Javascript to submit the form (as shown in the MultiFile example above), the form is submitted but the JQuery.Form function is not called, so the form does not get submitted in the background. I thought that maybe I needed to change the form registration as follows... $('#photoForm').submit(function() { $('#photoForm').ajaxForm(options); }); ...but that didn't solve the problem. The same is true when I tried .ajaxSubmit instead of .ajaxForm. What am I missing? BTW: I know it might sound strange to use MultiFile for single-file uploads, but the idea is that the number of files will be dynamic based on the user's account. So, I'm starting with one but the number changes depending on conditions.

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