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  • how do simple SQLAlchemy relationships work?

    - by Carson Myers
    I'm no database expert -- I just know the basics, really. I've picked up SQLAlchemy for a small project, and I'm using the declarative base configuration rather than the "normal" way. This way seems a lot simpler. However, while setting up my database schema, I realized I don't understand some database relationship concepts. If I had a many-to-one relationship before, for example, articles by authors (where each article could be written by only a single author), I would put an author_id field in my articles column. But SQLAlchemy has this ForeignKey object, and a relationship function with a backref kwarg, and I have no idea what any of it MEANS. I'm scared to find out what a many-to-many relationship with an intermediate table looks like (when I need additional data about each relationship). Can someone demystify this for me? Right now I'm setting up to allow openID auth for my application. So I've got this: from __init__ import Base from sqlalchemy.schema import Column from sqlalchemy.types import Integer, String class Users(Base): __tablename__ = 'users' id = Column(Integer, primary_key=True) username = Column(String, unique=True) email = Column(String) password = Column(String) salt = Column(String) class OpenID(Base): __tablename__ = 'openid' url = Column(String, primary_key=True) user_id = #? I think the ? should be replaced by Column(Integer, ForeignKey('users.id')), but I'm not sure -- and do I need to put openids = relationship("OpenID", backref="users") in the Users class? Why? What does it do? What is a backref?

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  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

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  • http-post request for a long String in iOS

    - by onkar
    I am looking to send a very long String, which is an image that is encoded into a String. I need to send that information using POST method. I have implemented the same in Android using key-value pair, I need to implement the same in iOS using key-value pair. Please help me with useful resources/approach. EDIT 1 What have I tried [dictionnary setObject:@"admin" forKey:@"username"]; [dictionnary setObject:@"123123" forKey:@"password"]; NSError *error = nil; NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dictionnary options:kNilOptions error:&error]; NSString *urlString = @"MY CALL URL"; NSURL *url = [NSURL URLWithString:urlString]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; [request setHTTPBody:jsonData]; NSURLResponse *response = NULL; NSError *requestError = NULL; NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&requestError]; NSLog(@"response is obtained"); NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding] ; NSLog(@"%@", responseString); EDIT 2 Error I am getting Request Error Error Domain=kCFErrorDomainCFNetwork Code=303 "The operation couldn’t be completed. (kCFErrorDomainCFNetwork error 303.)" UserInfo=0x7ba0120 {NSErrorFailingURLKey=http://yahoo.com/, NSErrorFailingURLStringKey=http://yahoo.com/}

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  • Can a C# method chain be "too long"?

    - by ccornet
    Not in terms of readability, naturally, since you can always arrange the separate methods into separate lines. Rather, is it dangerous, for any reason, to chain an excessively large number of methods together? I use method chaining primarily to save space on declaring individual one-use variables, and traditionally using return methods instead of methods that modify the caller. Except for string methods, those I kinda chain mercilessly. In any case, I worry sometimes about the impact of using exceptionally long method chains all in one line. Let's say I need to update the value of one item based on someone's username. Unfortunately, the shortest method to retrieve the correct user looks something like the following. SPWeb web = GetWorkflowWeb(); SPList list2 = web.Lists["Wars"]; SPListItem item2 = list2.GetItemById(3); SPListItem item3 = item2.GetItemFromLookup("Armies", "Allied Army"); SPUser user2 = item2.GetSPUser("Commander"); SPUser user3 = user2.GetAssociate("Spouse"); string username2 = user3.Name; item1["Contact"] = username2; Everything with a 2 or 3 lasts for only one call, so I might condense it as the following (which also lets me get rid of a would-be-superfluous 1): SPWeb web = GetWorkflowWeb(); item["Contact"] = web.Lists["Armies"] .GetItemById(3) .GetItemFromLookup("Armies", "Allied Army") .GetSPUser("Commander") .GetAssociate("Spouse") .Name; Admittedly, it looks a lot longer when it is all in one line and when you have int.Parse(ddlArmy.SelectedValue.CutBefore(";#", false)) instead of 3. Nevertheless, this is one of the average lengths of these chains, and I can easily foresee some of exceptionally longer counts. Excluding readability, is there anything I should be worried about for these 10+ method chains? Or is there no harm in using really really long method chains?

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  • "NT AUTHORITY\ANONYMOUS LOGON" error in Windows 7 (ASP.NET & Web Service)

    - by Tony_Henrich
    I have an asp.net web app which works fine in Windows XP machine in a domain. I am porting it to a Windows 7 stand alone machine. The app uses a web service which makes a call to sql server. The web server (IIS 7.5) and SQL Server are on the same stand alone machine. I enabled Windows authentication for the website and web service. The web service uses a trusted connection connection string. The web service credentials uses System.Net.CredentialCache.DefaultCredentials. I noticed username, password and domainname are blank after the call! The webservice and web site use an application pool with identity "Network Service". I am getting an exception "NT AUTHORITY\ANONYMOUS LOGON" in the database call in the web service. I am assuming it's related to the blank credentials. I am expecting ASPNET user to be the security token to the database. Why is this not happening? (Usually this happens when sql server and web server are on two different machines in a domain, delegation & double hopping, but in my case everything is on a dev box)

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  • Java to C# code converter

    - by acadia
    Hello, Are there any converters available that converts Java code to C#? I need to convert the below code into C# String token = new String(""); URL url1 =new URL( "http", domain, Integer.valueOf(portnum), "/Workplace/setCredentials?op=getUserToken&userId="+username+"&password="+password +"&verify=true"); URLConnection conn1=url1.openConnection(); ((HttpURLConnection)conn1).setRequestMethod("POST"); InputStream contentFileUrlStream = conn1.getInputStream(); BufferedReader br = new BufferedReader(new InputStreamReader(contentFileUrlStream)); token=br.readLine(); String encodedAPIToken = URLEncoder.encode(token); String doubleEncodedAPIToken ="ut=" + encodedAPIToken;//.substring(0, encodedAPIToken.length()-1); //String doubleEncodedAPIToken ="ut=" + URLEncoder.encode(encodedAPIToken); //String userToken = "ut=" + URLEncoder.encode(token, "UTF-8"); //URLEncoder.encode(token); String vsId = "vsId=" + URLEncoder.encode(docId.substring(5, docId.length()), "UTF-8"); url="http://" + domain + ":" + portnum + "/Workplace/getContent?objectStoreName=RMROS&objectType=document&" + vsId + "&" +doubleEncodedAPIToken; String vsId = "vsId=" + URLEncoder.encode(docId.substring(5, docId.length()), "UTF-8"); url="http://" + domain + ":" + portnum + "/Workplace/getContent?objectStoreName=RMROS&objectType=document&" + vsId + "&" +doubleEncodedAPIToken; Thanks in advance

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  • MySQL LEFT JOIN, INNER JOIN etc, complicated query, PHP + MySQL for a forum

    - by Sven Eriksson
    So I've got a little forum I'm trying to get data for, there are 4 tables, forum, forum_posts, forum_threads and users. What i'm trying to do is to get the latest post for each forum and giving the user a sneak peek of that post, i want to get the number of posts and number of threads in each forum aswell. Also, i want to do this in one query. So here's what i came up with: SELECT lfx_forum_posts.*, lfx_forum.*, COUNT(lfx_forum_posts.pid) as posts_count, lfx_users.username, lfx_users.uid, lfx_forum_threads.tid, lfx_forum_threads.parent_forum as t_parent, lfx_forum_threads.text as t_text, COUNT(lfx_forum_threads.tid) as thread_count FROM lfx_forum LEFT JOIN (lfx_forum_threads INNER JOIN (lfx_forum_posts INNER JOIN lfx_users ON lfx_users.uid = lfx_forum_posts.author) ON lfx_forum_threads.tid = lfx_forum_posts.parent_thread AND lfx_forum_posts.pid = (SELECT MAX(lfx_forum_posts.pid) FROM lfx_forum_posts WHERE lfx_forum_posts.parent_forum = lfx_forum.fid GROUP BY lfx_forum_posts.parent_forum) ) ON lfx_forum.fid = lfx_forum_posts.parent_forum GROUP BY lfx_forum.fid ORDER BY lfx_forum.fid ASC This get the latest post in each forum and gives me a sneakpeek of it, the problem is that lfx_forum_posts.pid = (SELECT MAX(lfx_forum_posts.pid) FROM lfx_forum_posts WHERE lfx_forum_posts.parent_forum = lfx_forum.fid GROUP BY lfx_forum_posts.parent_forum) Makes my COUNT(lfx_forum_posts.pid) go to one (aswell as the COUNT(lfx_forum_threads.tid) which isn't how i would like it to work. My question is: is there some somewhat easy way to make it show the correct number and at the same time fetch the correct post info (the latest one that is)? If something is unclear please tell and i'll try to explain my issue further, it's my first time posting something here.

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  • How can I change the back button function in navigation toolbar?

    - by jackrobert
    I have developed a simple web application using JSP. It has a login page which contains username, password fields and sumbit button. It has a logout page which contains a link to the login page. And there are some pages like page1, page2, page3, page4, etc. Normal workflow is the following: After login comes page1. Then click some action and it will go to page2. Then click some action and it will go to page3. Then click some action and it will go to page4. So now I am in page4. Now click back button in navigation toolbar in browser, generally go to previous page (page3). But my requirement is, if you click back button in navigation toolbar from any page in the application, then you should go to logout page. For example: if you are in page4 and press the back button, then you should go to logout page and not to page3. How to achieve this? Is it anyway possible? Maybe with Javascript?

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  • how to hide ssh expect user/password

    - by raindrop18
    my perl cgi script I have the password/user on clear text and want to hide it or the user enter the credential interactively.is that possible? here is my code. please any help!! i am very new for perl. #!/usr/local/bin/expect ####################################################################################################### # Input: It will handle two arguments -> a device and a show command. ####################################################################################################### # ######### Start of Script ###################### # #### Set up Timeouts - Debugging Variables log_user 0 set timeout 10 set userid "USER" set password "PASS" # ############## Get two arguments - (1) Device (2) Command to be executed set device [lindex $argv 0] set command [lindex $argv 1] spawn /usr/local/bin/ssh -l $userid $device match_max [expr 32 * 1024] expect { -re "RSA key fingerprint" {send "yes\r"} timeout {puts "Host is known"} } expect { -re "username: " {send "$userid\r"} -re "(P|p)assword: " {send "$password\r"} -re "Warning:" {send "$password\r"} -re "Connection refused" {puts "Host error -> $expect_out(buffer)";exit} -re "Connection closed" {puts "Host error -> $expect_out(buffer)";exit} -re "no address.*" {puts "Host error -> $expect_out(buffer)";exit} timeout {puts "Timeout error. Is device down or unreachable?? ssh_expect";exit} } expect { -re "\[#>]$" {send "term len 0\r"} timeout {puts "Error reading prompt -> $expect_out(buffer)";exit} } expect { -re "\[#>]$" {send "$command\r"} timeout {puts "Error reading prompt -> $expect_out(buffer)";exit} } expect -re "\[#>]$" set output $expect_out(buffer) send "exit\r" puts "$output\r\n"

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  • XML-RPC over SSL with Ruby: end of file reached (EOFError)

    - by Michael Conigliaro
    Hello, I have some very simple Ruby code that is attempting to do XML-RPC over SSL: require 'xmlrpc/client' require 'pp' server = XMLRPC::Client.new2("https://%s:%d/" % [ 'api.ultradns.net', 8755 ]) pp server.call2('UDNS_OpenConnection', 'sponsor', 'username', 'password') The problem is that it always results in the following EOFError exception: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread': end of file reached (EOFError) So it appears that after doing the POST, I don't get anything back. Interestingly, this is the behavior I would expect if I tried to make an HTTP connection on the HTTPS port (or visa versa), and I actually do get the same exact exception if I change the protocol. Everything I've looked at indicates that using "https://" in the URL is enough to enable SSL, but I'm starting wonder if I've missed something. Note that Even though the credentials I'm using in the RPC are made up, I'm expecting to at least get back an XML error page (similar to if you access https://api.ultradns.net:8755/ with a web browser). I've tried running this code on OSX and Linux with the exact same result, so I have to conclude that I'm just doing something wrong here. Does anyone have any examples of doing XML-RPC over SSL with Ruby?

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  • How to connect to Oracle using JRuby & JDBC

    - by Rob
    First approach: bare metal require 'java' require 'rubygems' require "c:/ruby/jruby-1.2.0/lib/ojdbc14.jar" # should be redundant, but tried it anyway odriver = Java::JavaClass.for_name("oracle.jdbc.driver.OracleDriver") puts odriver.java_class url = "jdbc:oracle:thin:@myhost:1521:mydb" puts "About to connect..." con = java.sql.DriverManager.getConnection(url, "myuser", "mypassword"); if con puts " connection good" else puts " connection failed" end The result of the above is: sqltest.rb:4: cannot load Java class oracle.jdbc.driver.OracleDriver (NameError) Second approach: Active Record require 'rubygems' gem 'ActiveRecord-JDBC' require 'jdbc_adapter' require 'active_record' require 'active_record/version' require "c:/ruby/jruby-1.2.0/lib/ojdbc14.jar" # should be redundant... ActiveRecord::Base.establish_connection( :adapter => 'jdbc', :driver => 'oracle.jdbc.driver.OracleDriver', :url => 'jdbc:oracle:thin:@myhost:1521:mydb', :username=>'myuser', :password=>'mypassword' ) ActiveRecord::Base.connection.execute("SELECT * FROM mytable") The result of this is: C:/ruby/jruby-1.2.0/lib/ruby/gems/1.8/gems/activerecord-jdbc-adapter-0.9.1/lib/active_recordconnection_adapters/jdbc_adapter.rb:330:in `initialize': The driver encountered an error: cannot load Java class oracle.jdbc.driver.OracleDriver (RuntimeError) Essentially the same error no matter how I go about it. I'm using JRuby 1.2.0 and I have ojdbc14.jar in my JRuby lib directory Gems: ActiveRecord-JDBC (0.5) activerecord-jdbc-adapter (0.9.1) activerecord (2.2.2) What am I missing? Thanks,

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  • Access denied when trying to access my database.

    - by Sergio Tapia
    Here's my code: <html> <head> </head> <body> <?php $user = mysql_real_escape_string($_GET["u"]); $pass = mysql_real_escape_string($_GET["p"]); $query = "SELECT * FROM usario WHERE username = '$user' AND password = '$pass'"; mysql_connect(localhost, "root", ""); @mysql_select_db("multas") or die( "Unable to select database"); $result=mysql_query($query); if(mysql_numrows($result) > 0){ echo 'si'; } ?> </body> </html> And here's the error I get when I try to run it Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\useraccess.php on line 16

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  • Implement user authentication against remote DB with a Web Service

    - by Juan González
    I'm just starting reasearch about the best way to implement user authentication within my soon-to-be app. This is what I have so far: A desktop (Windows) application on a remote server. That application is accessed locally with a browser (it has a web console and MS SQL Server to store everything). The application is used with local credendials stored in the DB. This is what I'd like to accompllish: Provide access to some information on that SQL Server DB from my app. That access of course must be granted once a user has id himself with valid credentials. This is what I know so far: How to create my PHP web service and query info from a DB using JSON. How to work with AFNetworking libraries to retrieve information. How to display that info on the app. What I don't know is which could be the best method to implement user authentication from iOS. Should I send username and password? Should I send some hash? Is there a way to secure the handshake? I'd for sure appreciate any advise, tip, or recommendation you have from previous experience. I don't want to just implement it but instead I want to do it as good as possible.

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  • Redirecting users after destroy

    - by mathee
    I have 3 models: Questions, Answers, and Profiles (I know, it should be called "Users"). When you view a question Q, I query the database for the answers to Q. (They are linked by id.) In the view, the current user has the option to delete his answer by clicking on the destroy link displayed next to his answer: %table %tr %td Answers: - @answers.each do |a| %tr %td - @provider = Profile.find(a.provider) %i #{h @provider.username} said: %br #{h a.description} %td = link_to 'View full answer', a %td - if a.provider == @profile.id #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :method => :delete} The problem is that when the user clicks on the destroy link, it redirects to the /answers/index. I want it to redirect to /questions/Q. What's the best way to do this? I know that there's a redirect_to method, but I don't know how to implement it when I want to redirect to an action for a different controller. It also needs to remember the question from which the answer is being deleted. I tried passing something like :question_id in link_to as: #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :question_id => @question.id, :method => :delete} In AnswersController#destroy: def destroy @answer = Answer.find(params[:id]) @answer.destroy respond_to do |format| format.html { redirect_to(answers_url) } format.xml { head :ok } end @question = Question.find(params[:question_id]) redirect_to question_path(@question) end The :question_id information is not passed to the destroy method, so I get this error: Couldn't find Question without an ID To confirm, I added a puts call before Question.find, and it returned nil.

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  • How can I use Hibernate Criteria's to query nested tables?

    - by cbmeeks
    I've looked all over SO and Google but I guess I'm not using the right search terms or something. Anyway, say I have three tables: Companies ----------------------------------------- id name user_id Users ----------------------------------------- id username usertype_id UserTypes ----------------------------------------- id typeofuser So ACME would be a company, it would have a user Moe and Moe would be a usertype of Stooge. In SQL, I would do something like: select * from companies c join users u on (u.id = c.user_id) join usertypes ut on (ut.id = u.usertype_id) where ut.typeofuser = 'Stooge' But I can't seem to figure out how to do that in a Criteria. I have tried: Criteria crit = io.getSession().createCriteria(Company.class); List<Company> list = crit.createCriteria("users") .createCriteria("usertypes") .add(Restriction.eq("typeofuser", "Stooge").list(); But I get back way too many records. And the results don't even come close to being accurate. I've also tried: Criteria crit = io.getSession().createCriteria(Company.class); List<Company> list = crit.createAlias("users", "u") .createAlias("u.usertypes", "ut") .add(Restriction.eq("ut.typeofuser", "Stooge").list(); Seems to bring back the exact same result set. I actually have read the user manual. And when I nest only one level deep (ie, searching by users is fine) but when I get two layers deep, I can't quite get it. And the manual is no help. I just can't relate cats and kittens to business objects. Maybe they should use cats, kittens and fleas? :-/ Thanks for any suggestions.

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  • Powershell 2.0 Hang When Run From MsDeploy pre- post- ops using c/

    - by SonOfNun
    I am trying to invoke powershell during the preSync call in a MSDeploy command, but powershell does not exit the process after it has been called. The command (from command line): "tools/MSDeploy/msdeploy.exe" -verb:sync -preSync:runCommand="powershell.exe -NoLogo -NoProfile -NonInteractive -ExecutionPolicy Unrestricted -Command C:/MyInstallPath/deploy.ps1 Set-WebAppOffline Uninstall-Service ",waitInterval=60000 -usechecksum -source:dirPath="build/for-deployment" -dest:wmsvc=BLUEPRINT-X86,username=deployer,password=deployer,dirPath=C:/MyInstallPath I used a hack here (http://therightstuff.de/2010/02/06/How-We-Practice-Continuous-Integration-And-Deployment-With-MSDeploy.aspx) that gets the powershell process and kills it but that didn't work. I also tried taskkill and the sysinternals equivalent, but nothing will kill the process so that MSDeploy errors out. The command is executed, but then just sits there. Any ideas what might be causing powershell to hang like this? I have found a few other similar issues around the web but no answers. Environment is Win 2K3, using Powershell 2.0. UPDATE: Here is a .vbs script I use to invoke my powershell command now. Invoke using 'cscript.exe path/to/script.vbs': Option Explicit Dim oShell, appCmd,oShellExec Set oShell = CreateObject("WScript.Shell") appCmd = "powershell.exe -NoLogo -NoProfile -NonInteractive -ExecutionPolicy Unrestricted -Command ""&{ . c:/development/materialstesting/deploy/web/deploy.ps1; Set-WebAppOffline }"" " Set oShellExec = oShell.Exec(appCmd) oShellExec.StdIn.Close()

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  • Nested hyperlinks in XHTML 1.1 document

    - by Nazgulled
    Hi, I'm doing a simple widget for WordPress that fetches the most recent tweets from the RSS feed provided by Twitter. This widget parses any link posted on a tweet, it also parses mentions (ie: @username) and trending topics (ie: #nowplaying). For these 3 situations, it creates links pointing to some Twitter feature. For instance: "Hi @UserA, check out the song Foo from FooBar that I'm listening, it's awesome. #nowplaying" And it will parse into this: Hi <a href="http://twitter.com/UserA">@UserA</a>, check out the song Foo from FooBar that I'm listening, it's awesome. <a href="http://twitter.com/#search?q=nowplaying">#nowplaying</a> Now now I need to add a global link to the whole message, like this: <a href="http://twitter.com/UserA/statuses/1234567890"> Hi <a href="http://twitter.com/UserA">@UserA</a>, check out the song Foo from FooBar that I'm listening, it's awesome. <a href="http://twitter.com/#search?q=nowplaying">#nowplaying</a> </a> But this code does not validate and it doesn't work anyways (the browsers don't really seem to know what to do with it). Any suggestions how could I fix this?

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  • SQL to CodeIgniter Array Missing Data Issue

    - by SamD
    $query = $this->db->query("SELECT t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit, user.user_id, username, password, email, balance, user.date_added, activation_code, activated FROM user LEFT JOIN (SELECT user_id, SUM(amount_won) AS profit, count(tip_id) AS numberofbets FROM tip GROUP BY user_id) as t1 ON user.user_id = t1.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS seven_profit FROM tip WHERE date_settled > '$seven_daystime' GROUP BY user_id) as t2 ON user.user_id = t2.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS 28profit FROM tip WHERE date_settled > '$twoeight_daystime' GROUP BY user_id) as t3 ON user.user_id = t3.user_id where activated = 1 GROUP BY user.user_id ORDER BY user.date_added DESC"); return $query->result_array(); The query works fine running it in phpMyAdmin and returns complete results (in image attached). However, printing the array in CodeIgniter, it has no value for one field ,seven_profit, where it is there in the SQL query ran in phpMyAdmin, just the discrepancy in this one field, from sql to php array... I just can’t see why, when printing the array, that one field, which should have value of 26, contains nothing? Any ideas? I changed the field name from starting with a number in attempt to fix it, but no difference. I know this is complex and looks horrible, any help or just people coming across something similar would be great to know about, thanks. Sam

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  • Requested operation requires an OLE DB Session object... - Connecting Excel to SQL server via ADO

    - by Frank V
    I'm attempting to take Excel 2003 and connect it to SQL Server 2000 to run a few dynamicly generated SQL Queries which ultimately filling certain cells. I'm attempting to do this via VBA via ADO (I've tried 2.8 to 2.0) but I'm getting an error while setting the ActiveConnection variable which is inside the ADODB.Connection object. I need to resolve this pretty quick... Requested operation requires an OLE DB Session object, which is not supported by the current provider. I'm honestly not sure what this error means and right now I don't care. How can get this connection to succeed so that I can run my queries? Here is my VB code: Dim SQL As String, RetValue As String SQL = " select top 1 DateTimeValue from SrcTable where x='value' " 'Not the real SQL RetValue = "" Dim RS As ADODB.Recordset Dim Con As New ADODB.Connection Dim Cmd As New ADODB.Command Con.ConnectionString = "Provider=sqloledb;DRIVER=SQL Server;Data Source=Server\Instance;Initial Catalog=MyDB_DC;User Id=<UserName>;Password=<Password>;" Con.CommandTimeout = (60 * 30) Set Cmd.ActiveConnection = Con ''Error occurs here. ' I'm not sure if the rest is right. I've just coded it. Can't get past the line above. Cmd.CommandText = SQL Cmd.CommandType = adCmdText Con.Open Set RS = Cmd.Execute() If Not RS.EOF Then RetValue = RS(0).Value Debug.Print "RetValue is: " & RetValue End If Con.Close I imagine something is wrong with the connection string but I've tried over a dozen variations. Now I'm just shooting in the dark.... Note/Update: To make matters more confusing, if I Google for the error quote above, I get a lot of hits back but nothing seems relevant or I'm not sure what information is relevant.... I've got the VBA code in "Sheet1" under "Microsoft Excel Objects." I've done this before but usually put things in a module. Could this make a difference?

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  • Cannot send email in ASP.NET through Godaddy servers.

    - by Jared
    I have an ASP.NET application hosted on Godaddy that I want to send email from. When it runs, I get: Mailbox name not allowed. The server response was: sorry, relaying denied from your location. The important parts of the code and Web.config are below: msg = new MailMessage("[email protected]", email); msg.Subject = "GreekTools Registration"; msg.Body = "You have been invited by your organization to register for the GreekTools recruitment application.<br/><br/>" + url + "<br/><br/>" + "Sincerely,<br/>" + "The GreekTools Team"; msg.IsBodyHtml = true; client = new SmtpClient(); client.Host = "relay-hosting.secureserver.net"; client.Send(msg); <system.net> <mailSettings> <smtp from="[email protected]"> <network host="relay-hosting.secureserver.net" port="25" userName="********" password="*********" /> </smtp> </mailSettings>

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  • svnsync looses revision properties although hook installed

    - by roesslerj
    Hello all! I have a pretty weird problem. We have setup an SVN-Mirror via cronjob (because it needs to go from inside to outside of a firewall, so no post-commit-hook possible) and svnsync. We installed a pre-revprop-hook just as told. Everything seems to work fine, except that it doesn't. E.g. when manually executing the script. # svnsync --non-interactive sync file://<path-to-mirror> --source-username <usr> --source-password <pwd> Committed revision 19817. Copied properties for revision 19817. No error, no complaints. But if checking for the revision properties it says: # svnlook info <path-to-mirror> 0 # svn info -r HEAD file://<path-to-mirror> 2>&1 Path: <root-of-mirror> URL: file://<path-to-mirror> Repository Root: file://<path-to-mirror> Repository UUID: <uid> Revision: 19817 Node Kind: directory Last Changed Rev: 19817 So somehow the author and timestamp information gets lost. But we need that information for our internal processes. Since no error or warning is produced I have absolutely no idea even where to start to look. Everything is local (except for the remote master), so there are no server-logs to look at. Any ideas how I could approach that problem, or even better -- how to solve it? Any ideas appreciated.

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  • Attachment empty/blank when sending mail using phpmailer

    - by chupinette
    Hello! I am using phpmailer class to send email and i am attaching a file to the mail. The email is sent successfully but the attachment which is an sql file is empty which should not be the case. I have tried with an image file, but it seems that every file that i attach is empty. Can anyone help me solve this problem please? $mail = new PHPMailer(); $body = "Reminder"; $mail->IsSMTP(); $mail->Host = "mail.yourdomain.com"; $mail->SMTPDebug = 1; $mail->SMTPAuth = true; $mail->SMTPSecure = "ssl"; $mail->Host = "smtp.gmail.com"; $mail->Port = 465; $mail->Username = "[email protected]"; $mail->Password = "abc"; $mail->SetFrom('[email protected]', 'blbla'); $mail->AddReplyTo("[email protected]","First Last"); $mail->Subject = "Your order has been successfully placed" $mail->MsgHTML($body); $mail->AddAddress("[email protected]","xyz"); $mail->AddAttachment("D:\b2\shop3.sql","shop3.sql"); I have tried to display the size of the file before attaching it, and it actually displays the file size. Can anyone help me please?

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  • Doctrine/symfony: getSqlQuery() output in phpMyAdmin/SQL tab

    - by user248959
    Hi, i have created this query that works OK: $q1 = Doctrine_Query::create() ->from('Usuario u') ->leftJoin('u.AmigoUsuario a ON u.id = a.user2_id OR u.id = a.user1_id') ->where("a.user2_id = ? OR a.user1_id = ?", array($id,$id)) ->andWhere("u.id <> ?", $id) ->andWhere("a.estado LIKE ?", 1); echo $q1->getSqlQuery(); The calling to getSqlQuery outputs this clause: SELECT s.id AS s_id, s.username AS s_username, s.algorithm AS s_algorithm, s.salt AS s_salt, s.password AS s__password, s.is_active AS s__is_active, s.is_super_admin AS s__is_super_admin, s.last_login AS s__last_login, s.email_address AS s__email_address, s.nombre_apellidos AS s__nombre_apellidos, s.sexo AS s__sexo, s.fecha_nac AS s__fecha_nac, s.provincia AS s_provincia, s.localidad AS s_localidad, s.fotografia AS s_fotografia, s.avatar AS s_avatar, s.avatar_mensajes AS s__avatar_mensajes, s.created_at AS s__created_at, s.updated_at AS s__updated_at, a.id AS a__id, a.user1_id AS a__user1_id, a.user2_id AS a__user2_id, a.estado AS a__estado FROM sf_guard_user s LEFT JOIN amigo_usuario a ON ((s.id = a.user2_id OR s.id = a.user1_id)) WHERE ((a.user2_id = ? OR a.user1_id = ?) AND s.id < ? AND a.estado LIKE ?) If i take that clause to phpmyadmin SQL tab i get this error 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? OR a.user1_id = ?) AND s.id < ? AND a.estado LIKE ?) LIMIT 0, 30' at line 1 Why i'm getting this error? Regards Javi

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  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

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  • Datalist itemcommand design?

    - by Surya sasidhar
    hi, in my application i am using datalist to display the images, i put properties of repeatcolumn=4 and reapeatdirection=horizontal. It is displaying good when there r more than or 4 images if there r only one or two or three images the gap between images r too long. if i have only one image the image displayed in datalist in the middle of the datalist. how can i solve this problem. i think you people understand my problem this is my datalist source code... datalist width="100%" <ItemTemplate > <table width="100%" > <tr> <td > <asp:ImageButton ID="imgeFrien" runat ="Server" Width="110px" Height ="100px" CommandName ="Image" CommandArgument ='<%# Eval("userid") %>' ImageUrl ='<%# "~/Userimages/"+ Eval("myimage") %>' /> </td> </tr> <tr> <td > <asp:Label ID="lblFrieNam" runat ="Server" Font-Names ="verdana" Text ='<%# Eval("username") %>'></asp:Label> </td> </tr> </table> </ItemTemplate> </asp:DataList>

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