bean validation model - Page 242

Creating Complex, Secure Web Forms with PHP and HTML_QuickForm2

Add the HTML_QuickForm2 PEAR package to your PHP development for streamlined HTML forms creation and validation.

Creating Complex, Secure Web Forms with PHP and HTML_QuickForm2

Add the HTML_QuickForm2 PEAR package to your PHP development for streamlined HTML forms creation and validation.

Creating Complex, Secure Web Forms with PHP and HTML_QuickForm2

Add the HTML_QuickForm2 PEAR package to your PHP development for streamlined HTML forms creation and validation.

Unobtrusive Maximum Input Lengths with JQuery and FluentValidation

If you use FluentValidation and set a maximum length for a string or a maximum value for a numeric property, JQuery validation is used to show an error message when the user inputs too many characters or a numeric value which is too big. On a recent project we wanted to use input’s maxlength attribute to prevent a user from entering too many characters rather than cure the problem with an error message, and I added this JQuery to add maxlength attributes based on JQuery validation’s data- attributes. $(function () { $("input[data-val-range-max],input[data-val-length-max]").each(function (i, e) { var input = $(e); var maxlength = input.is("[data-val-range-max]") ? input.data("valRangeMax").toString().length : input.data("valLengthMax"); input.attr("maxlength", maxlength); }); }); Presto!

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sequence generators are getting ignored

- by luvfort

I'm getting the following error while saving a object. However similar configuration is working for other model objects in my projects. Any help would be greatly appreciated. @Entity @Table(name = "ENROLLMENT_GROUP_MEMBERSHIPS", schema = "LEAD_ROUTING") public class EnrollmentGroupMembership implements Serializable, Comparable,Auditable { @javax.persistence.SequenceGenerator(name = "enrollmentGroupMemID", sequenceName = "S_ENROLLMENT_GROUP_MEMBERSHIPS") @Id @GeneratedValue(strategy = GenerationType.AUTO, generator = "enrollmentGroupMemID") @Column(name = "ID") private Long id; @ManyToOne() @JoinColumn(name = "TIER_WEIGHT_OID", referencedColumnName = "OID", updatable = false, insertable = false) private TierWeight tierWeight; public EnrollmentGroupMembership() { } } Code: @Entity @Table(name = "TIER_WEIGHT", schema = "LEAD_ROUTING") public class TierWeight implements Serializable, Auditable { @SequenceGenerator(name = "tierSequence",sequenceName = "S_TIER_WEIGHT") @Column(name = "OID") @Id @GeneratedValue(strategy = GenerationType.AUTO, generator = "tierSequence") private Long id; @OneToMany @JoinColumn(name = "TIER_WEIGHT_OID", referencedColumnName = "OID") private Set<EnrollmentGroupMembership> memberships; public TierWeight() { } } The logic layer's code is @Override public void createTier(String tierName, float weight) { TierWeight tier = new TierWeight(); tier.setWeight(weight); tier.setTier(tierName); tierWeightDAO.create(tier); } Similar Many-one configuration is working through out the project. I don't know why this one instance is failing. Any help would be greatly appreciated. The following is the error that I'm getting Caused by: org.hibernate.id.IdentifierGenerationException: ids for this class must be manually assigned before calling save(): edu.apollogrp.d2ec.model.TierWeight at org.hibernate.id.Assigned.generate(Assigned.java:3 3) at org.hibernate.event.def.AbstractSaveEventListener. saveWithGeneratedId(AbstractSaveEventListener.java :99) The log file is telling that the sequence generator tierSequence is not getting created. However other sequence generators are getting created. 2010-06-03 11:24:51,834 DEBUG [org.hibernate.cfg.AnnotationBinder:] Processing annotations of edu.apollogrp.d2ec.model.TierWeight.dateCreated 2010-06-03 11:24:51,834 DEBUG [org.hibernate.cfg.AnnotationBinder:] Processing annotations of edu.apollogrp.d2ec.model.TierWeight.dateCreated 2010-06-03 11:24:51,834 DEBUG [org.hibernate.cfg.Ejb3Column:] Binding column DATE_CREATED unique false ....................................... ....................................... 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.AnnotationBinder:] Processing annotations of edu.apollogrp.d2ec.model.CounselorAvailability.id 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.Ejb3Column:] Binding column OID unique false 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.Ejb3Column:] Binding column OID unique false 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.AnnotationBinder:] id is an id 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.AnnotationBinder:] id is an id 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.AnnotationBinder:] Add sequence generator with name: counselorAvailabilityID 2010-06-03 11:24:51,756 DEBUG [org.hibernate.cfg.AnnotationBinder:] Add sequence generator with name: counselorAvailabilityID While debugging, I see that the org.hibernate.impl.SessionFactoryImpl is returning the "Assigned" identifierGenerator. This is horrible. I've specified the identifierGenerator as "Auto". Please see the above code. As a sidenote, I was trying to debug and seeing how the objects are getting retrieved from the database. Looks like the enrollmentgroupmembership records have the tierweight value populated. However if I look at the tierweight object, it doesn't have the enrollmentgroupmembership records. I'm puzzled. I think these two problems must be related. Maddy.

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MVC Bootstrap: Autocomplete doesn't show properly

- by kicked11

I have a MVC website and it had a searchbox with autocomplete, now I changed the layout using bootstrap. But now the autocomplete isn't been shown correctly anymore. See the picture the suggestions are not shown right. the autocomplete goes through the text. I was fine before I used bootstrap. I am using a SQL server to get the data and this is js file (I'm not good at ajax, i took it from a tutorial I followed) $(function () { var ajaxFormSubmit = function () { var $form = $(this); var options = { url: $form.attr("action"), type: $form.attr("method"), data: $form.serialize() }; $.ajax(options).done(function (data) { var $target = $($form.attr("data-aptitude-target")); var $newHtml = $(data); $target.replaceWith($newHtml); $newHtml.show("slide", 200); }); return false; }; var submitAutocompleteForm = function (event, ui) { var $input = $(this); $input.val(ui.item.label); var $form = $input.parents("form:first"); $form.submit(); }; var createAutocomplete = function () { var $input = $(this); var options = { source: $input.attr("data-aptitude-autocomplete"), select: submitAutocompleteForm }; $input.autocomplete(options); }; $("form[data-aptituder-ajax='true']").submit(ajaxFormSubmit); $("input[data-aptitude-autocomplete]").each(createAutocomplete); }); this is the form in my view <form method="get" action="@Url.Action("Index")" data-aptitude-ajax="true" data-aptitude-target="#testList"> <input type="search" name="searchTerm" data-aptitude-autocomplete="@Url.Action("Autocomplete")" /> <input type="submit" value=Search /> And this is part of the controller of the view public ActionResult Autocomplete(string term) { var model = db.tests .Where(r => term == null || r.name.Contains(term)) .Select(r => new { label = r.name }); return Json(model, JsonRequestBehavior.AllowGet); } // // GET: /Test/ public ActionResult Index(string searchTerm = null) { var model = db.tests .Where(r => searchTerm == null || r.name.StartsWith(searchTerm)); if (Request.IsAjaxRequest()) { return PartialView("_Test", model); } return View(model); } I'm new to ajax as well as bootstrap 3. I got the searchfunction and autocomplete from a tutorial I followed. Anybody any idea on how to fix this, because it worked fine? Thanks in advance!

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JPA entity design / cannot delete entity

- by timaschew

I though its simple what I want, but I cannot find any solution for my problem. I'm using playframework 1.2.3 and it's using Hibernate as JPA. So I think playframework has nothing to do with the problem. I have some classes (I omit the nonrelevant fields) public class User { ... } public class Task { public DataContainer dataContainer; } public class DataContainer { public Session session; public User user; } public class Session { ... } So I have association from Task to DataContainer and from DataContainer to Sesssion and the DataContainer belongs to a User. The DataContainers can have always the same User, but the Session have to be different for each instance. And the DataContainer of a Task have also to be different in each instance. A DataContainer can have a Sesesion or not (it's optinal). I use only unidirectional assoc. It should be sufficient. In other words: Every Task must has one DataContainer. Every DataContainer must has one/the same User and can have one Session. To create a DB schema I use JPA annotations: @Entity public class User extends Model { ... } @Entity public class Task extends Model { @OneToOne(optional = false, cascade = CascadeType.ALL) public DataContainer dataContainer; } @Entity public class DataContainer extends Model { @OneToOne(optional = true, cascade = CascadeType.ALL) public Session session; @ManyToOne(optional = false, cascade = CascadeType.ALL) public User user; } @Entity public class Session extends Model { ... } BTW: Model is a play class and provides the primary id as long type. When I create some for each entity a object and 'connect them', I mean the associations, it works fine. But when I try to delete a Session, I get a constraint violation exception, because a DataContainer still refers to the Session I want to delete. I want that the Session (field) of the DataContainer will be set to null respectively the foreign key (session_id) should be unset in the database. This will be okay, because its optional. I don't know, I think I have multiple problems. Am I using the right annotation @OneToOne ? I found on the internet some additional annotation and attributes: @JoinColumn and a mappedBy attribute for the inverse relationship. But I don't have it, because its not bidirectional. Or is a bidirectional assoc. essentially? Another try was to use @OnDelete(action = OnDeleteAction.CASCADE) the the contraint changed from NO ACTIONs when update or delete to: ADD CONSTRAINT fk4745c17e6a46a56 FOREIGN KEY (session_id) REFERENCES annotation_session (id) MATCH SIMPLE ON UPDATE NO ACTION ON DELETE CASCADE; But in this case, when I delete a session, the DataContainer and User is deleted. That's wrong for me. EDIT: I'm using postgresql 9, the jdbc stuff is included in play, my only db config is db=postgres://app:app@localhost:5432/app

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Multiple OpenSSL vulnerabilities in Sun SPARC Enterprise M-series XCP Firmware

- by RitwikGhoshal

CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2008-5077 Improper Input Validation vulnerability 5.8 OpenSSL in XCP1113 Firmware Sun SPARC Enterprise M3000 SPARC: 14216085 Sun SPARC Enterprise M4000 SPARC: 14216091 Sun SPARC Enterprise M5000 SPARC: 14216093 Sun SPARC Enterprise M8000 SPARC: 14216096 Sun SPARC Enterprise M9000 SPARC: 14216098 CVE-2008-7270 Cryptographic Issues vulnerability 4.3 CVE-2009-0590 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 5.0 CVE-2009-3245 Improper Input Validation vulnerability 10.0 CVE-2010-4180 Cipher suite downgrade vulnerability 4.3 This notification describes vulnerabilities fixed in third-party components that are included in Oracle's product distributions.Information about vulnerabilities affecting Oracle products can be found on Oracle Critical Patch Updates and Security Alerts page.

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Using one data source across multiple views in Kendo UI SPA

- by user3731783

I am trying to build a Kendo UI SPA. I have two views. View 1 (appListView) shows Application Details in a grid and view 2 (activityView) will have a dropdown for application names and a grid that shows the activity for selected application As I am loading all the application details on the loading of view 1, I would like to re-use those details to populate the dropdown on view 2. Please see my code below. Everything works fine but when I go to View 2 it makes a call to the service again to get application details. I would like to use the existing data if it is already loaded and if the uses comes to view 2 directly then it should get application data also. I am not sure what I am missing in the code. View Markup: <script id="appListView" type="text/x-kendo-template"> <h3 data-bind="html: displayName"></h3> <div data-role="grid" data-editable="{'mode':'popup'}" data-bind="source: items" data-columns="[ {'field': 'Name'}, {'field': 'ContactEmail','title':'Contact Email'} ]"> </div> </script> <script id="" type="text\x-kendo-template"> <div> Activity for Application   <input name="AppName" data-role="dropdownlist" data-source="appsModel.items" data-text-field="Name" data-value-field="Id" data-option-label="Choose an application name" style="width:250px;" /> </div> <div id="Activities" data-role="grid" data-bind="source: items" data-auto-bind="false" data-columns="[ {'field': 'Domain','title':'Domain'}, {'field': 'ActivityType','title':'Activity Type'} ]"> </div> </script> js with DataSource and View Model: //data sources var applications = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, serverFiltering : true, transport: { read: { url: '/api/App', dataType: 'json', type:'GET' } } }); var activities = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, transport: { read: { url: '/api/Activity', dataType: 'json', type: 'GET' }, parameterMap: function (data, type) { if (type == "read") { return 'appId=' + $("#AppName").val() ; } } } }); //Models var appsModel = kendo.observable({ items: applications, displayName: 'My Applications' }); var activityModel = kendo.observable({ items: activities, onAppChange: function(t){ $("#Activities").data("kendoGrid").dataSource.read(); }, dispayName: 'Application Activities' }); //views var layout = new kendo.Layout("layout-template"); var appListView = new kendo.View("appListView", { model: appsModel }); var activityView = new kendo.View("activityView", { model: activityModel }); Thank you for taking time to read this long question.

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Is a many-to-many relationship with extra fields the right tool for my job?

- by whichhand

Previously had a go at asking a more specific version of this question, but had trouble articulating what my question was. On reflection that made me doubt if my chosen solution was correct for the problem, so this time I will explain the problem and ask if a) I am on the right track and b) if there is a way around my current brick wall. I am currently building a web interface to enable an existing database to be interrogated by (a small number of) users. Sticking with the analogy from the docs, I have models that look something like this: class Musician(models.Model): first_name = models.CharField(max_length=50) last_name = models.CharField(max_length=50) dob = models.DateField() class Album(models.Model): artist = models.ForeignKey(Musician) name = models.CharField(max_length=100) class Instrument(models.Model): artist = models.ForeignKey(Musician) name = models.CharField(max_length=100) Where I have one central table (Musician) and several tables of associated data that are related by either ForeignKey or OneToOneFields. Users interact with the database by creating filtering criteria to select a subset of Musicians based on data the data on the main or related tables. Likewise, the users can then select what piece of data is used to rank results that are presented to them. The results are then viewed initially as a 2 dimensional table with a single row per Musician with selected data fields (or aggregates) in each column. To give you some idea of scale, the database has ~5,000 Musicians with around 20 fields of related data. Up to here is fine and I have a working implementation. However, it is important that I have the ability for a given user to upload there own annotation data sets (more than one) and then filter and order on these in the same way they can with the existing data. The way I had tried to do this was to add the models: class UserDataSets(models.Model): user = models.ForeignKey(User) name = models.CharField(max_length=100) description = models.CharField(max_length=64) results = models.ManyToManyField(Musician, through='UserData') class UserData(models.Model): artist = models.ForeignKey(Musician) dataset = models.ForeignKey(UserDataSets) score = models.IntegerField() class Meta: unique_together = (("artist", "dataset"),) I have a simple upload mechanism enabling users to upload a data set file that consists of 1 to 1 relationship between a Musician and their "score". Within a given user dataset each artist will be unique, but different datasets are independent from each other and will often contain entries for the same musician. This worked fine for displaying the data, starting from a given artist I can do something like this: artist = Musician.objects.get(pk=1) dataset = UserDataSets.objects.get(pk=5) print artist.userdata_set.get(dataset=dataset.pk) However, this approach fell over when I came to implement the filtering and ordering of query set of musicians based on the data contained in a single user data set. For example, I could easily order the query set based on all of the data in the UserData table like this: artists = Musician.objects.all().order_by(userdata__score) But that does not help me order by the results of a given single user dataset. Likewise I need to be able to filter the query set based on the "scores" from different user data sets (eg find all musicians with a score 5 in dataset1 and < 2 in dataset2). Is there a way of doing this, or am I going about the whole thing wrong?

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New Oracle Cloud support in OEPE

- by gstachni

Oracle Enterprise Pack for Eclipse 12c (12.1.1.1.1) includes updated support for development with the Java Cloud Service. Users can now do iterative development against their Java Cloud Service instance in addition to testing against local and remote WebLogic Server installations. Some details of the cloud tools are below: Templates and wizards to create projects and server configurations for Oracle Java Cloud Service Develop applications to run and deploy to the cloud, including Oracle ADF. Check cloud server runtime and deployment logs in new log analyzers Test applications before deployment with integrated whitelist scans. Whitelist tools support as-you-type validation, project build validation, and on demand scans to highlight coding violations. Errors are reported in application source, the Problems view, and a new Whitelist violations view. Access the Oracle Public Cloud administrative consoles directly from within Eclipse.

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MVC how to implement two different post actions

- by AnonyMouse

I'm developing this really important squirrel application. There is a wizard where squirrels are added to the database. So say there are three screens to this wizard: Squirrel name details Height and weight Nut storage So at each step of the wizard I'm wanting to save the details to the database. The Height and weight view looks like: @model HeightWeightViewModel @{ ViewBag.Title = "Height and weight"; } <h2>Height and weight</h2> @using (Html.BeginForm()) { <h3>Height</h3> <div> @Html.EditorFor(model => model.Squirrel.Height) </div> <h3>Weight</h3> <div> @Html.EditorFor(model => model.Squirrel.Weight) </div> <input type="submit" value="Previous" /> <input type="submit" value="Next" /> } So I'm hoping that Previous and Next buttons will save these details. The Previous button while saving will also take the user to the Squirrel name details page. The Next will save and take the user to the nut storage page. I got the Next button working using: public ActionResult Edit(SquirrelViewModel squirrelViewModel) { _unitOfWork.SaveHeightWeight(squirrelViewModel); return RedirectToAction("Edit", "NutStorage", new { id = squirrelViewModel.Squirrel.Id }); } So the Next button saves the details and sends the user to the NutStorage page. The Previous button does the same as Next but I actually want it to send the user to the first step of the Wizard after saving. I'm not sure how to do this. Would I have another method to post to for Previous? I can't image how to implement this. Maybe I should be using ActionLinks instead of submit buttons but that would not post the details to be saved. Can anyone suggest how to get the previous button to save and send the user to the first page of the wizard while still having the Next functionality working?

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Sonatype rend disponible la version 1.6 de Nexus, son gestionnaire de dépôts Maven en version gratui

Bonjour, Sonatype a mis à disposition en début de semaine une nouvelle vers des éditions Open Source et Professional de Nexus. Parmi les nouveautés pour la version gratuite : Blocage / déblocage automatique de repository distant injoignable Modification du groupe par défaut (retrait du public snapshot) Interface permettant de remonter les problèmes (JIRA) rencontrés sur l'outil Concernant la version payante : 59 corrections de bugs Remplacement de Plexus par Guice (aucun changement impactant du point de vue utilisateur) Ajout de la notion de "target Promotion repository" pour les "Staging Profile" Amélioration des règles de validation du POM (validation du POM ...

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CodeIgniter Error Log Info + Errors

- by fatnjazzy

Hi, IS there a way to save in the log, Info + Errors without debug? Howcome debug level apears with info? If i want to log info "Account id 4345 was deleted by Admin", why do i need to see all of these: DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Hooks Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 URI Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Router Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Output Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Input Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Global POST and COOKIE data sanitized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Loader Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/safe_charge.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/web_fx.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: loadutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: objectsutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: logutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: password_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Database Driver Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 cURL Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Account MX_Controller Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/pending_account_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/proccess_accounts_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/web_fx_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_account_type_spreads.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_accounts.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized Thanks

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Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

- by michael

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Codeigniter: Controller URI with Library

- by Kevin Brown

I have a working controller and library function, but I now need to pass a URI segment to the library for decision making, and I'm stuck. Controller: function survey($method) { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); //Convert the db Object to a row array $data['manager'] = $data['member']->row(); $manager_id = $data['manager']->manager_id; $data['manager'] = $this->home_model->getUser($manager_id); $data['manager'] = $data['manager']->row(); if ($data['manager']->credits == '0') { flashMsg('warning',"You can't complete the assessment until your manager has purchased credit."); redirect('home','location'); } elseif ($data['manager']->test_complete == '3'){ flashMsg('warning',"You already completed the Assessment."); redirect('home','location'); } else{ $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data); } } Library: function survey_form($container) { if($method ==1){ $id = $this->CI->session->userdata('id'); // Setup fields for($i=1;$i<18;$i++){ $fields["a_".$i] = 'Question '.$i; } for($i=1;$i<17;$i++){ $fields["b_".$i] = 'Question '.$i; } $fields["company_name"] = "Company Name"; $fields['company_address'] = "company_address"; $fields['company_phone'] = "company_phone"; $fields['company_state'] = "company_state"; $fields['company_city'] = "company_city"; $fields['company_zip'] = "company_zip"; $fields['job_title'] = "job_title"; $fields['job_type'] = "job_type"; $fields['job_time'] = "job_time"; $fields['department'] = "department"; $fields['supervisor'] = "supervisor"; $fields['vision'] = "vision"; $fields['height'] = "height"; $fields['weight'] = "weight"; $fields['hand_dominance'] = "hand_dominance"; $fields['areas_of_fatigue'] = "areas_of_fatigue"; $fields['injury_review'] = "injury_review"; $fields['job_positive'] = "job_positive"; $fields['risk_factors'] = "risk_factors"; $fields['job_improvement_short'] = "job_improvement_short"; $fields['job_improvement_long'] = "job_improvement_long"; $fields["c_1"] = "Near Lift"; $fields["c_2"] = "Middle Lift"; $fields["c_3"] = "Far Lift"; $this->CI->validation->set_fields($fields); // Set Rules for($i=1;$i<18;$i++){ $rules["a_".$i]= 'hour|integer|max_length[2]'; } for($i=1;$i<17;$i++){ $rules["b_".$i]= 'hour|integer|max_length[2]'; } // Setup form default values $this->CI->validation->set_rules($rules); if ( $this->CI->validation->run() === FALSE ) { // Output any errors $this->CI->validation->output_errors(); } else { // Submit form $this->_submit(); } // Modify form, first load $this->CI->db->from('be_user_profiles'); $this->CI->db->where('user_id' , $id); $user = $this->CI->db->get(); $this->CI->db->from('be_survey'); $this->CI->db->where('user_id' , $id); $survey = $this->CI->db->get(); $user = array_merge($user->row_array(),$survey->row_array()); $this->CI->validation->set_default_value($user); // Display page $data['user'] = $user; $data['header'] = 'Risk Assessment Survey'; $data['page'] = $this->CI->config->item('backendpro_template_public') . 'form_survey'; $this->CI->load->view($container,$data); } else{ redirect('home','location'); } } My library function doesn't know what to do with Method...and I'm confused. Does it have something to do with instances in my library?

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Exception while creating the sub web

In this article you will learn how to resolve security validation exception while creating the sub web.

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Vos applications valident-elles correctement les adresses e-mail ? Retour sur les détails des spécifications

Vos applications valident-elles correctement les adresses e-mail ? Retour sur les détails des spécifications Les adresses e-mail sont au coeur de toutes les applications Web. Et s'il y a bien une seule tâche commune à tous les projets de développement Web, c'est la validation de ces adresses. Si cette validation peut sembler au premier abord simple, facilement accomplie par le test de conformité à une expression rationnelle, beaucoup de développeurs ignorent les détails des spécifications et risquent de rejeter des utilisateurs aux adresses e-mail peu habituelles certes, mais tout à fait conformes. Le problème vient essentiellement du fait que les spécifications...

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Meshing different systems of keys together in XML Schema

- by Tom W

Hello SO, I'd like to ask people's thoughts on an XSD problem I've been pondering. The system I am trying to model is thus: I have a general type that represents some item in a hypothetical model. The type is abstract and will be inherited by all manner of different model objects, so the model is heterogeneous. Furthermore, some types exist only as children of other types. Objects are to be given an identifier, but the scope of uniqueness of this identifier varies. Some objects - we will call them P (for Parent) objects - must have a globally unique identifier. This is straightforward and can use the xs:key schema element. Other objects (we can call them C objects, for Child) are children of a P object and must have an identifier that is unique only in the scope of that parent. For example, object P1 has two children, object C1 and C2, and object P2 has one child, object C3. In this system, the identifiers given could be as follows: P1: 1 (1st P object globally) P2: 2 (2nd P object globally) C1: 1 (1st C object of P1) C2: 2 (2nd C object of P1) C3: 1 (1st C object of P2) I want the identity syntax of every model object to be identical if possible, therefore my first pass at implementing is to define a single type: <xs:complexType name="ModelElement"> <xs:attribute name="IDMode" type="IdentityMode"/> <xs:attribute name="Identifier" type="xs:string"/> </xs:complexType> where the IdentityMode is an enumerated value: <xs:simpleType name="IdentityMode"> <xs:restriction base="xs:string"> <xs:enumeration value="Identified"/> <xs:enumeration value="Indexed"/> <xs:enumeration value="None"/> </xs:restriction> </xs:simpleType> Here "Identified" signifies a global identifier, and "Indexed" indicates an identifier local only to the parent. My question is, how do I enforce these uniqueness conditions using unique, key or other schema elements based on the IdentityMode property of the given subtype of ModelElement?

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Microsoft Releases MVC Upgrade For Building Web Apps

New features include improved Visual Studio tooling support, strongly typed HTML helpers, and enhanced model validation support.

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ASP.Net MVC - Models and User Controls

- by cdotlister

Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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json data not rendered in backbone view

- by user2535706

I have been trying to render the json data to the view by calling the rest api and the code is as follows: var Profile = Backbone.Model.extend({ dataType:'jsonp', defaults: { intuitId: null, email: null, type: null }, }); var ProfileList = Backbone.Collection.extend({ model: Profile, url: '/v1/entities/6414256167329108895' }); var ProfileView = Backbone.View.extend({ el: "#profiles", template: _.template($('#profileTemplate').html()), render: function() { _.each(this.model.models, function(profile) { var profileTemplate = this.template(this.model.toJSON()); $(this.el).append(tprofileTemplate); }, this); return this; } }); var profiles = new ProfileList(); var profilesView = new ProfileView({model: profiles}); profiles.fetch(); profilesView.render(); and the html file is as follows: <!DOCTYPE html> <html> <head> <title>SPA Example</title>  </head> <body class="harmony"> <header> <div class="title">SPA Example</div> </header> <div id="profiles"></div> <script id="profileTemplate" type="text/template"> <div class="profile"> <div class="info"> <div class="intuitId"> <%= intuitId %> </div> <div class="email"> <%= email %> </div> <div class="type"> <%= type %> </div> </div> </div> </script> </body> </html> This gives me an error and the render function isn't invoking properly and the render function is called even before the REST API returns the JSON response. Could anyone please help me to figure out where I went wrong. Any help is highly appreciated Thank you

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Filtered TextBox Extender in Ajax

Advanced TextBox Validation with less Efforts by using Ajax toolkit Control i.e. Filtered TextBox Extender

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My store returns no code id and breaks 404 error. Magento

- by numerical25

I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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