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  • Setting up Django application on lighttpd behind apache reverse proxy

    - by ml256
    I have a Django app at http://some_other_example.com (it will be behind firewall) running on lighttpd server with fastcgi. I need make it available under http://example.com/myapp. It works fine except for redirects - when I login from http://example.com/myapp/login it redirects me to http://example.com instead of http://example.com/myapp. When logging-in from http://some_other_example.com/login it is ok. My configuration: apache2.conf at example.com: ProxyPass /myapp http://some_other_example.com ProxyPassReverse /myapp http://some_other_example.com ProxyHTMLURLMap http://some_other_example.com /myapp <Location /myapp> SetOutputFilter proxy-html ProxyHTMLExtended On ProxyHTMLURLMap / /myapp/ </Location> in settings.py I added USE_X_FORWARDED_HOST = True but it didn't help

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  • WGet a Page that Requires Logging in

    - by Synetech inc.
    I’m trying to figure out a way to use WGET or a similar tool so that I can schedule a web page to be downloaded regularly as a sort of updating log. The problem is that the page requires that I be logged in otherwise I get a different page, generic. Further, the page does not take login information as GET parameters in the URL, it uses POST to log in on the login page and cookies to save the login information that’s read by the regular page. I’m currently using GNU Wget 1.10.2 for Windows. I’ve tried using WGET’s cookie functionality but have had mixed results, usually skewing towards it not working. Can anyone please advise on a way to accomplish this? Thanks a lot.

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  • How to connect to VPN using commands in Linux (Fedora 16)

    - by WarFox
    Usually, I use the network connections icon on the top bar to connect to VPN. The connection is configured properly and it connects well. Configuration screen shot is given below. As you can see I have selected the 'Connect automatically' option. But this option doesn't help in connecting to VPN automatically upon login. This is my university VPN and it uses 'Point-to-Point encryption (MPPE)' for authentication I need to connect to the VPN using command line, so that I can write a script and run it at start up, so the connection is automatically established every time I login. This will also help in connecting to VPN when I login from 'init 3' mode. I depend on this VPN connection for my internet access. Please help me with the required commands.

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  • Cannot log-in in the install of phpmyadmin on Ubuntu

    - by Sylario
    I just installed phpmyadmin and i am trying to login in /phpmyadminpath/setup. I am greeted by an invite similar to an apache protected folder (log/password displayed in a browser pop-up, not an html popup) asking for login pass. I cannot login using system password(root) or mysql passsword(also root) I already have rails app using this mysql, and i checked the mysql password in the config files. I cannot run any mysql command in my console because of the following error : ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) What is wrong with phpmyadmin and mysql?

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  • Building a Student Storage server

    - by DobotJr
    I work for a school district. I've been put in charge of building a storage server for students. A place for them to work off of from school and home. My challenge is getting this to work from home. At school they login, authenticate, and they get a mapped drive to their folder on the server (S:\fileserver\studentname). My question is how can I make this available to students at home? The server is running Windows Server 2003 R1. I've got PHP, Apache, and MySQL working together. My idea is to write a script that will "crawl" through the directory containing all of the student folders, then create an instance of every file and folder in a MySQL DB. Create a login page that will use LDAP for authentication, and once they login to the server from home, they get a page with folders a files tied to their username. Has anyone out there ever put something like this together??

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  • ASP.NET Membership API not working on Win2008 server/IIS7

    - by Program.X
    I have a very odd problem. I have a web app that uses the .NET Membership API to provide login functionality. This works fine on my local dev machine, using WebDev 4.0 server. I'm using .NET 4.0 with some URL Rewriting, but not on the pages where login is required. I have a Windows Server 2008 with IIS7 However, the Membership API seemingly does not work on the server. I have set up remote debugging and the LoginUser.LoggedIn event of the LoginUser control gets fired okay, but the MembershipUser is null. I get no answer about the username/password being invalid so it seems to be recognising it. If I enter an invalid username/password, I get an invalid username/password response. Some code, if it helps: <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="validation-error-list" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend>Account Information</legend> <p> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">Username:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="validation-error" Display="Dynamic" ErrorMessage="User Name is required." ToolTip="User Name is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="validation-error" Display="Dynamic" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="login-action"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" CssClass="submitButton" Text="Log In" ValidationGroup="LoginUserValidationGroup"/> </p> and the code behind: protected void Page_Load(object sender, EventArgs e) { LoginUser.LoginError += new EventHandler(LoginUser_LoginError); LoginUser.LoggedIn += new EventHandler(LoginUser_LoggedIn); } void LoginUser_LoggedIn(object sender, EventArgs e) { // this code gets run so it appears logins work Roles.DeleteCookie(); // this behaviour has been removed for testing - no difference } void LoginUser_LoginError(object sender, EventArgs e) { HtmlGenericControl htmlGenericControl = LoginUser.FindControl("errorMessageSpan") as HtmlGenericControl; if (htmlGenericControl != null) htmlGenericControl.Visible = true; } I have "Fiddled" with the Login form reponse and I get the following Cookie-Set headers: Set-Cookie: ASP.NET_SessionId=lpyyiyjw45jjtuav1gdu4jmg; path=/; HttpOnly Set-Cookie: .ASPXAUTH=A7AE08E071DD20872D6BBBAD9167A709DEE55B352283A7F91E1066FFB1529E5C61FCEDC86E558CEA1A837E79640BE88D1F65F14FA8434AA86407DA3AEED575E0649A1AC319752FBCD39B2A4669B0F869; path=/; HttpOnly Set-Cookie: .ASPXROLES=; expires=Mon, 11-Oct-1999 23:00:00 GMT; path=/; HttpOnly I don't know what is useful here because it is obviously encrypted but I find the .APXROLES cookie having no value interesting. It seems to fail to register the cookie, but passes authentication

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  • Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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  • Spring Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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  • Twitter Bootstrap modal spans, side-by-side divs and "control-group"?

    - by Federico Stango
    I'm trying my best to have a good looking modal login form but for some reasons it seems that no matter how I nest divs, I cannot obtain the proper shape. What I need is a big "lock" image side-by-side with a username/password form. The best I could do adds a horizontal scroller by the modal bottom and shows the input gadgets fairly distant from the image partly hidden on the right side of the modal canvas. Inspecting with FireBug it seems that the spans in row-fluid are ok but the "control-label" and "controls" class adds way too much space on the left by width (for the labels) and margin-left (for the controls). How would you solve it? Am I doing something wrong with divs and classes nesting? This is the current modal without the main wrapper as it gets added by some js code that loads modal contents through ajax: <form class="form-horizontal" id="login" name="login" method="post" action="<?php echo site_url('user/login'); ?>"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button> <h3>Login</h3> </div> <div class="modal-body"> <?php if ( isset($error) ) { ?> <div class="row"> <div class="alert alert-error"> <strong>Warning!</strong> <?php echo $error; ?> </div> </div> <?php } ?> <div class="row-fluid"> <div class="span4"> <img src="skins/frontend/base/images/lock.png" width="96px" height="96px" /> </div> <div class="span8"> <div class="control-group"> <label class="control-label" for="email">Email</label> <div class="controls"><input type="text" placeholder="Type your email" id="email" name="email" /></div> <?php echo form_error('email', '<div id="error_email" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <label class="control-label" for="password">Password</label> <div class="controls"><input type="password" placeholder="Password" id="password" name="password" /></div> <?php echo form_error('password', '<div id="error_password" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <div class="controls"><label class="checkbox inline"><input type="checkbox" id="remember" name="remember" checked="checked" />&nbsp;Remember Me</label></div> </div> </div> </div> </div> <div class="modal-footer"> <button type="submit" class="btn btn-primary">Login</button> </div> </form> Just don't take into account the php code you see... :) Thanks in advance for all the support you can give! Federico

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  • Iphone sdk, How to post data to web server? anybody has example ?

    - by user352385
    Hi, guys, I want to post data to web server, like username and password, on the web server, I used PHP to echo yes or no, I attached all the code. Can anybody help me out, what is wrong with the code. Since it always says incorrect password or username. I tried to test the php code with username and password inside, it is working. So please help me. Thank you. Header file @interface kiksyloginViewController : UIViewController { IBOutlet UITextField *usernameField; IBOutlet UITextField *passwordField; IBOutlet UIButton *loginButton; } @property (nonatomic, retain) UITextField *usernameField; @property (nonatomic, retain) UITextField *passwordField; @property (nonatomic, retain) UIButton *loginButton; (IBAction) login: (id) sender; @end Implementation file #import "kiksyloginViewController.h" @implementation kiksyloginViewController @synthesize usernameField; @synthesize passwordField; @synthesize loginButton; (IBAction) login: (id) sender { NSString *post =[NSString stringWithFormat:@"username=%@&password=%@",usernameField.text, passwordField.text]; NSString *hostStr = @"http://localhost/userlogin.php"; hostStr = [hostStr stringByAppendingString:post]; NSData *dataURL = [NSData dataWithContentsOfURL: [ NSURL URLWithString: hostStr ]]; NSString *serverOutput = [[NSString alloc] initWithData:dataURL encoding: NSASCIIStringEncoding]; if([serverOutput isEqualToString:@"Yes"]){ UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Congrats" message:@"You are authorized " delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil]; [alertsuccess show]; [alertsuccess release]; } else { UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Username or Password Incorrect" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil]; [alertsuccess show]; [alertsuccess release]; } } (void)didReceiveMemoryWarning { // Releases the view if it doesn’t have a superview. [super didReceiveMemoryWarning]; // Release any cached data, images, etc that aren’t in use. } (void)viewDidUnload { // Release any retained subviews of the main view. // e.g. self.myOutlet = nil; } (void)dealloc { [super dealloc]; } @end PHP file <?php //$Container = new Container ; $u = $_GET['username']; $pw =$_GET['password']; $check = "select username, password from user where username='$u' and password='$pw'"; function myDbconn() { mysql_connect("localhost", "root","") or die(); mysql_select_db("test") or die (mysql_error()); } myDbconn(); $login = mysql_query($check) or die (mysql_error()); //$run = DB()-select($check); if (mysql_num_rows($login)==1){ //$row = DB()-fetch($run); //$row = DB()-fetch($login); $row = mysql_fetch_assoc($login); echo 'yes'; exit; } else { echo 'No'; exit; } ?

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  • HttpWebRequest response produces HTTP 422. Why?

    - by Simon
    Hi there. I'm trying to programmatically send a POST-request to a web-server in order to login an then perform other requests that require a login. This is my code: Encoding.UTF8.GetBytes( String.Format( "login={0}&password={1}&authenticity_token={2}", username, password, token)); //Create HTTP-request for login HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create("http://www.xxx.xx/xx/xx"); request.Method = "POST"; request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = data.Length; request.CookieContainer = new CookieContainer(); request.Accept = "application/xml,application/xhtml+xml,text/html; +"q=0.9,text/plain ;q=0.8,image/png,*/*;q=0.5"; request.Referer = "http://www.garzantilinguistica.it/it/session"; request.Headers.Add("Accept-Language", "de-DE"); request.Headers.Add("Origin", "http://www.xxx.xx"); request.UserAgent = "C#"; request.Headers.Add("Accept-Encoding", "gzip, deflate"); After sending the request //Send post request var requestStream = request.GetRequestStream(); requestStream.Write(data, 0, data.Length); requestStream.Flush(); requestStream.Close(); ... I want to get the servers response: //Get Response StreamReader responseStreamReader = new StreamReader( request.GetResponse().GetResponseStream()); //WebException: HTTP 422! string content = responseStreamReader.ReadToEnd(); This piece of code fires the WebException, that tells me the server responded with HTTP 422 (unprocessable entity due to semantic errors) Then I compared (using a TCP/IP sniffers) the requests of my program and the browser (which of course produces a valid POST-request and gets the right response). (1) My program's request: POST /it/session HTTP/1.1 Content-Type: application/x-www-form-urlencoded Accept: application/xml,application/xhtml+xml,text/html;q=0.9,text/plain; q=0.8,image/png,*/*;q=0.5 Referer: http://www.garzantilinguistica.it/it/session Accept-Language: de-DE Origin: http://www.garzantilinguistica.it User-Agent: C# Accept-Encoding: gzip, deflate Host: www.garzantilinguistica.it Content-Length: 111 Expect: 100-continue Connection: Keep-Alive HTTP/1.1 100 Continue [email protected]&password=machivui&authenticity_token=4vLgtwP3nFNg4NeuG4MbUnU7sy4z91Wi8WJXH0POFmg= HTTP/1.1 422 Unprocessable Entity (2) The browser's request: POST /it/session HTTP/1.1 Host: www.garzantilinguistica.it Referer: http://www.garzantilinguistica.it/it/session Accept: application/xml,application/xhtml+xml,text/html;q=0.9, text/plain;q=0.8,image/png,*/*;q=0.5 Accept-Language: de-DE Origin: http://www.garzantilinguistica.it User-Agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; de-DE) AppleWebKit/531.22.7 (KHTML, like Gecko) Version/4.0.5 Safari/531.22.7 Accept-Encoding: gzip, deflate Content-Type: application/x-www-form-urlencoded Cookie: __utma=244184339.652523587.1275208707.1275208707.1275211298.2; __utmb=244184339.20.10.1275211298; __utmc=244184339; __utmz=244184339.1275208707.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); _garzanti2009_session=BAh7CDoPc2Vzc2lvbl9pZCIlZDg4MWZjNjg2YTRhZWE0NDQ0ZTJmMTU2YWY4ZTQ1NGU6EF9jc3JmX3Rva2VuIjFqRWdLdll3dTYwOTVVTEpNZkt6dG9jUCtaZ0o4V0FnV2V5ZnpuREx6QUlZPSIKZmxhc2hJQzonQWN0aW9uQ29udHJvbGxlcjo6Rmxhc2g6OkZsYXNoSGFzaHsGOgplcnJvciIVbG9naW4gbm9uIHZhbGlkbwY6CkB1c2VkewY7CFQ%3D--4200fa769898dd156faa49e457baf660cf068d08 Content-Length: 144 Connection: keep-alive authenticity_token=jEgKvYwu6095ULJMfKztocP%2BZgJ8WAgWeyfznDLzAIY%3D&login=thespider14%40hotmail.com&password=machivui&remember_me=1&commit=Entra HTTP/1.1 302 Found Can someone help to understand which part of the request I am missing or what the main difference between the browser's and my request is? Why am I getting that 422?

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  • Can I get the original page source (vs current DOM) with phantomjs/casperjs?

    - by supercoco
    I am trying to get the original source for a particular web page. The page executes some scripts that modify the DOM as soon as it loads. I would like to get the source before any script or user changes any object in the document. With Chrome or Firefox (and probably most browsers) I can either look at the DOM (debug utility F12) or look at the original source (right-click, view source). The latter is what I want to accomplish. Is it possible to do this with phantomjs/casperjs? Before getting to the page I have to log in. This is working fine with casperjs. If I browse to the page and render the results I know I am on the right page. casper.thenOpen('http://'+customUrl, function(response) { this.page.render('example.png'); // *** Renders correct page (current DOM) *** console.log(this.page.content); // *** Gets current DOM *** casper.download('view-source:'+customUrl, 'b.html', 'GET'); // *** Blank page *** console.log(this.getHTML()); // *** Gets current DOM *** this.debugPage(); // *** Gets current DOM *** utils.dump(response); // *** No BODY *** casper.download('http://'+customUrl, 'a.html', 'GET'); // *** Not logged in ?! *** }); I've tried this.download(url, 'a.html') but it doesn't seem to share the same context since it returns HTML as if I was not logged in, even if I run with cookies casperjs test.casper.js --cookies-file=cookies.txt. I believe I should keep analyzing this option. I have also tried casper.open('view-source:url') instead of casper.open('http://url') but it seems it doesn't recognize the url since I just get a blank page. I have looked at the raw HTTP Response I get from the server with a utility I have and the body of this message (which is HTML) is what I need but when the page loads in the browser the DOM has already been modified. I tried: casper.thenOpen('http://'+url, function(response) { ... } But the response object only contains the headers and some other information but not the body. ¿Any ideas? Here is the full code: phantom.casperTest = true; phantom.cookiesEnabled = true; var utils = require('utils'); var casper = require('casper').create({ clientScripts: [], pageSettings: { loadImages: false, loadPlugins: false, javascriptEnabled: true, webSecurityEnabled: false }, logLevel: "error", verbose: true }); casper.userAgent('Mozilla/5.0 (Macintosh; Intel Mac OS X)'); casper.start('http://www.xxxxxxx.xxx/login'); casper.waitForSelector('input#login', function() { this.evaluate(function(customLogin, customPassword) { document.getElementById("login").value = customLogin; document.getElementById("password").value = customPassword; document.getElementById("button").click(); }, { "customLogin": customLogin, "customPassword": customPassword }); }, function() { console.log('Can't login.'); }, 15000 ); casper.waitForSelector('div#home', function() { console.log('Login successfull.'); }, function() { console.log('Login failed.'); }, 15000 ); casper.thenOpen('http://'+customUrl, function(response) { this.page.render('example.png'); // *** Renders correct page (current DOM) *** console.log(this.page.content); // *** Gets current DOM *** casper.download('view-source:'+customUrl, 'b.html', 'GET'); // *** Blank page *** console.log(this.getHTML()); // *** Gets current DOM *** this.debugPage(); // *** Gets current DOM *** utils.dump(response); // *** No BODY *** casper.download('http://'+customUrl, 'a.html', 'GET'); // *** Not logged in ?! *** });

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  • Facebook iFrame APP not working in IE, works on every other browser

    - by Sean Ashmore
    So im getting a blank page when loading this page within an iFrame on Internet explorer, every other browser works fine.. I have also tried using p3p headers as other people have suggested, but to no avail. <?php require ("connect.php"); require ("config.php"); require ("fb_config.php"); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Login handler</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="css/login.css" type="text/css"> </head> <body> <?//=$user?> <?php if($user == 0) { echo "You are not logged into facebook. Nice try."; }else{ $query = "SELECT id,fb_id,login_ip,login_count,activated,sitestate FROM login WHERE fb_id='".mysql_real_escape_string($user)."'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); if (mysql_num_rows($result) == 0) { $sql = "INSERT INTO login SET id = '', fb_id ='" .mysql_real_escape_string($user). "', name = '" .rand(10000000000000000,99999999999999999999). "', signup =NOW() , password = '" .mysql_real_escape_string($pass). "', state = '0', mail = '" .mysql_real_escape_string($_POST['mail']). "',location='".mysql_real_escape_string($randomlocation)."',location_start='".mysql_real_escape_string($randomlocation)."', signup_ip='".mysql_real_escape_string($_SERVER['REMOTE_ADDR'])."',ref='".mysql_real_escape_string($_POST['ref'])."', activation_id = '" .mysql_real_escape_string($activation_link). "',activated='2', killprotection = '$twodayprot',gender='" .mysql_real_escape_string($_POST["gender"]). "'"; $res = mysql_query($sql); } //if($row['fb_id'] != $user){ //echo "Your facebook ID: $user is NOT in the MW DB."; //exit(); //}else{ if(empty($row['login_ip'])){ $row['login_ip'] = $_SERVER['REMOTE_ADDR']; }else{ $ip_information = explode("-", $row['login_ip']); if (in_array($_SERVER['REMOTE_ADDR'], $ip_information)) { $row['login_ip'] = $row['login_ip']; }else{ $row['login_ip'] = $row['login_ip']."-".$_SERVER['REMOTE_ADDR']; } } $update_login = mysql_query("UPDATE login SET login_count=login_count+'1' WHERE name='".mysql_real_escape_string($_POST['username'])."'") or die(mysql_error()); $_SESSION['user_id'] = $row['id']; $result = mysql_query("UPDATE login SET userip='".mysql_real_escape_string($_SERVER['REMOTE_ADDR'])."',login_ip='".mysql_real_escape_string($row['login_ip'])."',login_count='0' WHERE id='".mysql_real_escape_string($_SESSION['user_id'])."'") or die(mysql_error()); if ($row['sitestate'] == 0){ header("location: home.php"); } elseif ($row['sitestate'] == 2) { header("location: killed.php?id={$row['id']}&encrypted={$row['password']}"); } else { header("location: banned.php?id={$row['id']}&encrypted={$row['password']}"); } }// id check. ?> </body> </html>

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  • ASP.Net MVC 2 is it possible to get the same instance of model(with slight changes) in HttpPost meth

    - by jjjjj
    Hi I have a complex entity User: public class User : BaseEntity { public virtual Taxi Taxi { get; set; } --> That is why i call it "complex" public virtual string Login { get; set; } public virtual string Password { get; set; } } where Taxi is a parent of User (Taxi has-many Users): public class Taxi : BaseEntity { public virtual string Name { get; set; } public virtual string ClientIp { get; set; } } BaseEntity consists of public virtual int Id { get; private set; } The problem occurs while trying to edit User [Authorize] public ActionResult ChangeAccountInfo() { var user = UserRepository.GetUser(User.Identity.Name); return View(user); } My ChangeAccountInfo.aspx <fieldset> <legend>Fields</legend> <% %> <div class="editor-label"> <%: Html.LabelFor(model => model.Login) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Login) %> <%: Html.ValidationMessageFor(model => model.Login) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Password) %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.HiddenFor(model => model.Taxi.Name)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> Post changes: [Authorize] [HttpPost] public ActionResult ChangeAccountInfo(User model) { if (ModelState.IsValid) { UserRepository.UpdateUser(model); return RedirectToAction("ChangeAccountInfoSuccess", "Account"); } return View(model); } But, the (User model) parameter has User.Id == 0 -- User entity had 5 before edit User.Login == "my new login" User.Password == "my new password" User.Taxi.Id == 0 -- User.Taxi entity had 3 before edit User.Taxi.Name == "old hidden name" User.Taxi.ClientIp == null -- User entity had 192.168.0.1 before edit Q: Is it possible not to mark all the fields of an entity (that should be in my UpdateUser) with tag "hidden" but still have them unchanged in my HttpPost method? e.g. not User.Taxi.ClientIp = null, but User.Taxi.ClientIp = 192.168.0.1 I'm using nhibernate, if it matters.

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  • header() function in php : No any redirection!

    - by jasmine
    I have written a very very very simple!! script in php. header redirection not working. 1- encoding : UTF-8 without BOM 2- with adding ob_start() the problem is countiueing. What is wrong in my code; login.php: <?php session_start(); require_once("funcs.php"); db_connection(); $username = $_POST['username']; $password = $_POST['pwd']; $submit = $_POST['login']; if($submit){ if (!filled_out($_POST)) { echo "please fill all fields"; } else{ $query = "SELECT * FROM users WHERE username ='{$username}' AND password ='{$password}'"; $result = mysql_query($query); if(mysql_num_rows($result) == 1){ $found_user = mysql_fetch_array($result); $_SESSION['id'] = $found_user['id']; $_SESSION['username'] = $found_user['username']; $_SESSION['password'] = $found_user['password']; setcookie(session_name(), '', time()+86400, '/'); header("Location: tst.php"); } else{ echo "incorrect username or password"; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org /TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p> <label for="username">Username:</label> <input type="text" name="username" id="username" /> </p> <p> <label for="textfield">Password</label> <input type="password" name="pwd" id="pwd" /> </p> <p> <input name="login" type="submit" id="login" value="Log in" /> </p> </form> </body> </html> <?php db_disconnect();?> and tst.php: <?php session_start(); require_once("funcs.php"); if (!isset($_SESSION['id'])){ header("Location : login.php"); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <table id="structure"> <tr> <td id="navigation">&nbsp; </td> <td id="page"> <?php echo "welcome"."". $_SESSION['username']; ?> </td> </tr> </table> </body> </html> <?php db_disconnect();?> wthit oppening tst.php directly, header() doesnot redirect to login.php

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  • Crop, Edit, and Print Photos in Windows 7 Media Center

    - by DigitalGeekery
    Windows Media Center is a nice application for managing and displaying your personal photos, but you may occasionally need to make some basic edits to your pictures. Today we’ll take a look at how to crop, edit, and print photos right from Windows 7 Media Center. From within the Picture Library in Windows Media Center, choose a photo to work with, right-click and select Picture Details. You can also access this option with a Media Center remote by clicking the “i” button. Note: You’ll notice you have the option to rotate the picture from this menu. It is also available on the next screen.  Rotate a picture Now you’ll see more options on the Picture Details screen. From here you can rotate, Print, or Touch Up, Delete, or Burn a CD/DVD. To rotate the picture, simple select Rotate. Note: If you want your photo saved with the new orientation, you’ll need to select Save from the Touch Up screen that we will look at later in the article.   Each click will rotate the picture 90 degrees clockwise. You’ll see the new orientation of the picture displayed on the Picture Details screen after you have clicked Rotate. Print a picture From the Picture Details screen, select Print. Click Print again. Media Center automatically prints to your default printer, so make sure your desired target printer is set as default. Crop and Edit Photos To edit or crop your photo, select Touch Up. Touch Up options includes, Crop, Contrast, and Red Eye removal. First, we’ll select the Crop button to crop our photo.   You will see a cropping area overlay appear on your photo. Select one of the buttons below to adjust the location, size, and orientation of the area to be cropped. When you’re happy with your selection, click Save. You’ll be prompted to confirm your save. Click Yes to permanently save your edits. You can also apply Contrast or Red Eye adjustments to your photos. There aren’t any advanced settings for these options. You merely toggle the Contrast or Red Eye on or off by selecting the option. Be sure to click Save before exiting to if you’ve made any changes you wish to permanently apply to the photos. This includes rotating the images. While this method is not likely to be replace your favorite image editing software, it does give you the ability to make basic edits and print photos directly from Windows Media Center. With a Media Center remote, you can even do all your edits from the comfort of your recliner. Similar Articles Productive Geek Tips Using Netflix Watchnow in Windows Vista Media Center (Gmedia)Schedule Updates for Windows Media CenterIntegrate Hulu Desktop and Windows Media Center in Windows 7Add Color Coding to Windows 7 Media Center Program GuideIntegrate Boxee with Media Center in Windows 7 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Outlook Connector Upgrade Error Gadfly is a cool Twitter/Silverlight app Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird

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  • Installing SharePoint 2010 in one machine with built in database

    - by sreejukg
    It is very easy to deploy SharePoint 2010 in a single server using the built-in database. Normally one need to choose such installation for evaluation purposes. When installing with default settings, setup installs Microsoft SQL server 2008 express database along with SharePoint. After installing SharePoint, you need to run SharePoint products and technology configuration wizard which will install central admin website and creates the configuration database and content database for SharePoint sites. Limitations 1. You can not perform this installation on a domain controller 2. The maximum size for express edition database is 4 GB SharePoint 2010 only supports 64 bit operating systems. The installation steps are for windows server r2 64 bit enterprise edition. Installation steps The first screen for the installation is as follows As a first step you need to install the s/w prerequisites. Click on the corresponding link Click next, here you have to agree on the license terms. Select the checkbox and then click next. The installation will starts. The progress will be updated in the screen. This may take some time as during this process, there are some components needs to be downloaded from internet. Make sure you are connected to the internet, then only the installation will become a success. If any error occurs, it will display the error, you need to configure in order to continue. If everything ok you will receive the following success page. Click finish to exit the installation window. Now from the first screen, select Install SharePoint server. This will install SharePoint and SQL server 2008 express edition. First you need to enter the product key for SharePoint. Enter the product key and clicks continue. Now you need to accept the license agreement. Select the checkbox and click on continue. Select the installation type you want.   Now click on the standalone button. In production scenario, you need to select the server farm installation. This article only cover the first option, installing server farm is not in the scope of this article. Once you click on the standalone, the installation starts and you can view the progress as below. If any error occurred during installation, you will get the details and link to the log file. Refer log file and fix the corresponding issue and then start the installation again. If installation completes without any error, you will see the below screen. Make sure you selected the check box “Run the SharePoint products Configuration Wizard now” and click close. The SharePoint products configuration wizard starts. Click next; you will get the following warning Click yes and the configuration steps starts. You can view the progress for each step. Once completed the below screen appears to the user. Click finish to complete the installation. Now SharePoint installation is completed. You can navigate to SharePoint central administration website from the administrative tools and start building your portal. Good luck

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  • Understanding HTTP Cookies in Indy 10 for Delphi XE2

    - by Jerry Dodge
    I have been working with Indy 10 HTTP Servers / Clients lately in Delphi XE2, and I need to make sure I'm understanding session management correctly. In the server, I have a "bucket" of sessions, which is a list of objects which each represent a unique session. I don't use username and password to authenticate users, but I rather use a unique API key which is issued to a client, and has an expiration. When a client wishes to connect to the server, it first logs in by calling the "login" command, which is a path like this: http://localhost:1234/login?APIKey=abcdefghij. The server checks this API Key against the database, and if it's valid, it creates a new session in the bucket, issues a new cookie (unique string), and sets the response cookies with Success=Y and Cookie=abcdefghij. This is where I have the question. Assuming the client end has its own method of cookie management, the client will receive this login response back from the server and automatically save the cookies as necessary. Any future request from the client to the server shall automatically send along these cookies, and the client side doesn't have to necessarily worry about setting these cookies when sending requests to the server. Right? PS - I'm asking this question here on programmers.stackexchange.com because I didn't see it fit to ask on stackoverflow.com. If anyone thinks this is appropriate enough for stackoverflow.com, please let me know.

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  • Oracle Access Manager 11.1.2 Certified with E-Business Suite 12

    - by Elke Phelps (Oracle Development)
    I am happy to announce that Oracle Access Manager 11gR2 (11.1.2) is now certified with E-Business Suite Releases 12.0.6 and 12.1. If you are implementing single sign-on for the first time, or are an existing Oracle Access Manager user, you may integrate with Oracle Access Manager 11gR2 using Oracle Access Manager WebGate and Oracle E-Business Suite AccessGate. Supported Architecture and Release Versions Oracle Access Manager 11.1.2 Oracle E-Business Suite Release 12.0.6, 12.1.1+ Oracle Identity Management 11.1.1.5, 11.1.1.6 Oracle Internet Directory 11.1.1.6 Oracle WebLogic Server 10.3.0.5+ What's New In This Oracle Access Manager 11gR2 Integration? Simplified integration: We've simplified the instructions and cut the number of pages, while adding clarity to the steps. Automation of configuration steps:  We've automated some of the required configuration steps. This is the first phase of automation and diagnostics that are part of our roadmap for this integration. Use of default OAM Login page: We are reducing the required troubleshooting by delivering the default OAM Login page for the integration. A custom login page can still be created by using Oracle Access Manager. Use of the Detached Credential collector in a Demilitarized Zone: We have certified the Detached Credential collector as part of a DMZ configuration. This will enhance the security of the underlying Oracle Access Manager and E-Business Suite components, which will now be required only within a company's intranet.   Choosing the Right Architecture Our previously published blog article and support note with single sign-on recommended and certified integration paths has been updated to include Oracle Access Manager 11gR2: Overview of Single Sign-On Integration Options for Oracle E-Business Suite (Note 1388152.1) Other References Integrate with Oracle Access Manager 11gR2 (11.1.2) using Oracle E-Business Suite AccessGate (Note 1484024.1) Overview of Single Sign-On Integration Options for Oracle E-Business Suite (Note 1388152.1) Related Articles Understanding Options for Integrating Oracle Access Manager with E-Business Suite Why Does E-Business Suite Integration with OAM Require Oracle Internet Directory? In-Depth: Using Third-Party Identity Managers with E-Business Suite Release 12

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  • SQL Azure Security: DoS

    - by Herve Roggero
    Since I decided to understand in more depth how SQL Azure works I started to dig into its performance characteristics. So I decided to write an application that allows me to put SQL Azure to the test and compare results with a local SQL Server database. One of the options I added is the ability to issue the same command on multiple threads to get certain performance metrics. That's when I stumbled on an interesting security feature of SQL Azure: its Denial of Service (DoS) detection engine. What this security feature does is that it performs a check on the number of connections being established, and if the rate of connection is too high, SQL Azure blocks all communication from that machine. I am still trying to learn more about this specific feature, but it appears that going to the SQL Azure portal and testing the connection from the portal "resets" the feature and you are allowed to connect again... until you reach the login threashold. In the specific test I was performing, all the logins were successful. I haven't tried to login with an invalid account or password... that will be for next time. On my Linked In group (SQL Server and SQL Azure Security: http://www.linkedin.com/groups?gid=2569994&trk=hb_side_g) Chip Andrews (www.sqlsecurity.com) pointed out that this feature in itself could present an internal threat. In theory, a rogue application could be issuing many login requests from a NATed network, which could potentially prevent any production system from connecting to SQL Azure within the same network. My initial response was that this could indeed be the case. However, while the TCP protocol contains the latest NATed IP address of a machine (which masks the origin of the machine making the SQL request), the TDS protocol itself contains the IP Address of the machine making the initial request; so technically there would be a way for SQL Azure to block only the internal IP address making the rogue requests.  So this warrants further investigation... stay tuned...

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  • Run a startup script with lightdm

    - by cheshirekow
    I have a tablet PC and the graphics driver doesn't support xrandr, so in order to rotate the screen I run a script which changes the Xorg.conf file and then restarts lightdm. I also have a script which uses xsetwacom and xinput to change the rotation of the input devices so that the match the new orientation. I've learned how to get the script to run when I login, but I'd like it to run before I login, so that I don't have to enable auto-login with lightdm. I do need it to run though, or the input (touch and pen) is rotated with respect to the screen, so that when I touch the screen the input is in a completely different area, making it really difficult to use the onscreen keyboard. I've looked at other questions on this site. I've tried putting my script in /etc/Xsession.d but that didn't seem to work. I also tried putting it in /etc/rc.local but I think that is the wrong place, nothing seems to happen. I've also tried googling for lightm script hooks, and various other google terms. Any suggestions? Edit 1: After doing some research, it seems to me that it might not be that I want to run a script with lightdm, but rather with the lighdm greeter (in this case, I think the unity-greeter?). Are there any script-hooks for the unity-greeter?

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  • How to Add Your Gmail Account to Outlook 2013 Using IMAP

    - by Lori Kaufman
    If you use Outlook to check and manage your email, you can easily use it to check your Gmail account as well. You can setup your Gmail account to allow you to synchronize email across multiple machines using email clients instead of a browser. We will show you how to use IMAP in your Gmail account so you can synchronize your Gmail account across multiple machines, and then how to add your Gmail account to Outlook 2013. To setup your Gmail account to use IMAP, sign in to your Gmail account and go to Mail. Click the Settings button in the upper, right corner of the window and select Settings from the drop-down menu. On the Settings screen, click Forwarding and POP/IMAP. Scroll down to the IMAP Access section and select Enable IMAP. Click Save Changes at the bottom of the screen. Close your browser and open Outlook. To begin adding your Gmail account, click the File tab. On the Account Information screen, click Add Account. On the Add Account dialog box, you can choose the E-mail Account option which automatically sets up your Gmail account in Outlook. To do this enter your name, email address, and the password for your Gmail account twice. Click Next. The progress of the setup displays. The automatic process may or may not work. If the automatic process fails, select Manual setup or additional server types, instead of E-mail Account, and click Next. On the Choose Service screen, select POP or IMAP and click Next. On the POP and IMAP Account Settings enter the User, Server, and Logon Information. For the Server Information, select IMAP from the Account Type drop-down list and enter the following for the incoming and outgoing server information: Incoming mail server: imap.googlemail.com Outgoing mail server (SMTP): smtp.googlemail.com Make sure you enter your full email address for the User Name and select Remember password if you want Outlook to automatically log you in when checking email. Click More Settings. On the Internet E-mail Settings dialog box, click the Outgoing Server tab. Select the My outgoing server (SMTP) requires authentication and make sure the Use same settings as my incoming mail server option is selected. While still in the Internet E-mail Settings dialog box, click the Advanced tab. Enter the following information: Incoming server: 993 Incoming server encrypted connection: SSL Outgoing server encrypted connection TLS Outgoing server: 587 NOTE: You need to select the type of encrypted connection for the outgoing server before entering 587 for the Outgoing server (SMTP) port number. If you enter the port number first, the port number will revert back to port 25 when you change the type of encrypted connection. Click OK to accept your changes and close the Internet E-mail Settings dialog box. Click Next. Outlook tests the accounts settings by logging into the incoming mail server and sending a test email message. When the test is finished, click Close. You should see a screen saying “You’re all set!”. Click Finish. Your Gmail address displays in the account list on the left with any other email addresses you have added to Outlook. Click the Inbox to see what’s in your Inbox in your Gmail account. Because you’re using IMAP in your Gmail account and you used IMAP to add the account to Outlook, the messages and folders in Outlook reflect what’s in your Gmail account. Any changes you make to folders and any time you move email messages among folders in Outlook, the same changes are made in your Gmail account, as you will see when you log into your Gmail account in a browser. This works the other way as well. Any changes you make to the structure of your account (folders, etc.) in a browser will be reflected the next time you log into your Gmail account in Outlook.     

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  • How to solve 'Connection refused' errors in SSH connection?

    - by frbry
    I have an Ubuntu Server 10.10 32-bit in my home. I'm making SSH connections to it from my PC via Putty. The problem is, sometimes I'm able to login seamlessly. However, sometimes it gives me an error like this: Network error: Connection refused. Then, I dont't change anything, try to login a few times more, wait a while and try again. Sometimes I can log in, sometimes I cannot. It seems pretty random to me. What can I do to solve this? Edit: And Sometimes, Putty gives Network error: Software caused connection abort error after displaying login as: text. Here is the ping -t output: Pinging 192.168.2.254 with 32 bytes of data: Reply from 192.168.2.254: bytes=32 time=6ms TTL=64 Reply from 192.168.2.254: bytes=32 time=65ms TTL=6 Reply from 192.168.2.254: bytes=32 time=88ms TTL=6 Reply from 192.168.2.254: bytes=32 time=1ms TTL=64 Reply from 192.168.2.254: bytes=32 time=3ms TTL=64 Reply from 192.168.2.254: bytes=32 time=1ms TTL=64 Reply from 192.168.2.254: bytes=32 time=1ms TTL=64 Reply from 192.168.2.254: bytes=32 time=1ms TTL=64 Reply from 192.168.2.254: bytes=32 time=1ms TTL=64

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  • Best depth sorting method for a Top Down 2D game using a 3D physics engine

    - by Alic44
    I've spent many days googling this and still have issues with my game engine I'd like to ask about, which I haven't seen addressed before. I think the problem is that my game is an unusual combination of a completely 2D graphical approach using XNA's SpriteBatch, and a completely 3D engine (the amazing BEPU physics engine) with rotation mostly disabled. In essence, my question is similar to this one (the part about "faux 3D"), but the difference is that in my game, the player as well as every other creature is represented by 3D objects, and they can all jump, pick up other objects, and throw them around. What this means is that sorting by one value, such as a Z position (how far north/south a character is on the screen) won't work, because as soon as a smaller creature jumps on top of a larger creature, or a box, and walks backwards, the moment its z value is less than that other creature, it will appear to be behind the object it is actually standing on. I actually originally solved this problem by splitting every object in the game into physics boxes which MUST have a Y height equal to their Z depth. I then based the depth sorting value on the object's y position (how high it is off the ground) PLUS its z position (how far north or south it is on the screen). The problem with this approach is that it requires all moving objects in the game to be split graphically into chunks which match up with a physical box which has its y dimension equal to its z dimension. Which is stupid. So, I got inspired last night to rewrite with a fresh approach. My new method is a little more complex, but I think a little more sane: every object which needs to be sorted by depth in the game exposes the interface IDepthDrawable and is added to a list owned by the DepthDrawer object. IDepthDrawable contains: public interface IDepthDrawable { Rectangle Bounds { get; } //possibly change this to a class if struct copying of the xna Rectangle type becomes an issue DepthDrawShape DepthShape { get; } void Draw(SpriteBatch spriteBatch); } The Bounds Rectangle of each IDepthDrawable object represents the 2D Axis-Aligned Bounding Box it will take up when drawn to the screen. Anything that doesn't intersect the screen will be culled at this stage and the remaining on-screen IDepthDrawables will be Bounds tested for intersections with each other. This is where I get a little less sure of what I'm doing. Each group of collisions will be added to a list or other collection, and each list will sort itself based on its DepthShape property, which will have access to the object-to-be-drawn's physics information. For starting out, lets assume everything in the game is an axis aligned 3D Box shape. Boxes are pretty easy to sort. Something like: if (depthShape1.Back > depthShape2.Front) //if depthShape1 is in front of depthShape2. //depthShape1 goes on top. else if (depthShape1.Bottom > depthShape2.Top) //if depthShape1 is above depthShape2. //depthShape1 goes on top. //if neither of these are true, depthShape2 must be in front or above. So, by sorting draw order by several different factors from the physics engine, I believe I can get a really correct draw order. My question is, is this a good way of going about this, or is there some tried and true, tested way which is completely different and has somehow completely eluded me on the internets? And, if this does seem like a good way to remake my draw order sorting, what's the right sorting algorithm for reordering the Bounds Rectangle collision lists, and how do you deal with a Bounds Rectangle colliding with two different object which don't collide with eachother. I know these are solved problems, but I've only been programming for a year so any specific input here will be greatly appreciated. Thanks for reading this far, ye who made it -- sorry it was so long!

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  • Move a sphere along the swipe?

    - by gameOne
    I am trying to get a sphere curl based on the swipe. I know this has been asked many times, but still it's yearning to be answered. I have managed to add force on the direction of the swipe and it works near perfect. I also have all the swipe positions stored in a list. Now I would like to know how can the curl be achieved. I believe the the curve in the swipe can be calculated by the Vector dot product If theta is 0, then there is no need to add the swipe. If it is not, then add the curl. Maybe this condition is redundant if I managed to find how to curl the sphere along the swipe position The code that adds the force to sphere based on the swipe direction is as below: using UnityEngine; using System.Collections; using System.Collections.Generic; public class SwipeControl : MonoBehaviour { //First establish some variables private Vector3 fp; //First finger position private Vector3 lp; //Last finger position private Vector3 ip; //some intermediate finger position private float dragDistance; //Distance needed for a swipe to register public float power; private Vector3 footballPos; private bool canShoot = true; private float factor = 40f; private List<Vector3> touchPositions = new List<Vector3>(); void Start(){ dragDistance = Screen.height*20/100; Physics.gravity = new Vector3(0, -20, 0); footballPos = transform.position; } // Update is called once per frame void Update() { //Examine the touch inputs foreach (Touch touch in Input.touches) { /*if (touch.phase == TouchPhase.Began) { fp = touch.position; lp = touch.position; }*/ if (touch.phase == TouchPhase.Moved) { touchPositions.Add(touch.position); } if (touch.phase == TouchPhase.Ended) { fp = touchPositions[0]; lp = touchPositions[touchPositions.Count-1]; ip = touchPositions[touchPositions.Count/2]; //First check if it's actually a drag if (Mathf.Abs(lp.x - fp.x) > dragDistance || Mathf.Abs(lp.y - fp.y) > dragDistance) { //It's a drag //Now check what direction the drag was //First check which axis if (Mathf.Abs(lp.x - fp.x) > Mathf.Abs(lp.y - fp.y)) { //If the horizontal movement is greater than the vertical movement... if ((lp.x>fp.x) && canShoot) //If the movement was to the right) { //Right move float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,10,16))*power); Debug.Log("right "+(lp.x-fp.x));//MOVE RIGHT CODE HERE canShoot = false; //rigidbody.AddForce((new Vector3((lp.x-fp.x)/30,10,16))*power); StartCoroutine(ReturnBall()); } else { //Left move float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,10,16))*power); Debug.Log("left "+(lp.x-fp.x));//MOVE LEFT CODE HERE canShoot = false; //rigidbody.AddForce(new Vector3((lp.x-fp.x)/30,10,16)*power); StartCoroutine(ReturnBall()); } } else { //the vertical movement is greater than the horizontal movement if (lp.y>fp.y) //If the movement was up { //Up move float y = (lp.y-fp.y)/Screen.height*factor; float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,y,16))*power); Debug.Log("up "+(lp.x-fp.x));//MOVE UP CODE HERE canShoot = false; //rigidbody.AddForce(new Vector3((lp.x-fp.x)/30,10,16)*power); StartCoroutine(ReturnBall()); } else { //Down move Debug.Log("down "+lp+" "+fp);//MOVE DOWN CODE HERE } } } else { //It's a tap Debug.Log("none");//TAP CODE HERE } } } } IEnumerator ReturnBall() { yield return new WaitForSeconds(5.0f); rigidbody.velocity = Vector3.zero; rigidbody.angularVelocity = Vector3.zero; transform.position = footballPos; canShoot =true; isKicked = false; } }

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