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• Adding a comma to a resource name in Microsoft Project

  - by John Paul Cook

  Microsoft Project does not allow a comma to be added to a resource name. In healthcare, the norm is to refer to people using the pattern of Name, Title which in my case is John Cook, RN. Not all commas are equal. By substituting a different comma for the one Project doesn’t like, it’s possible to add a comma to a resource name. Figure 1. Error message after trying to add a comma to a resource name in Microsoft Project 2013. The error message refers to “the list separator character” that is commonly...(read more)

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• Internet Explorer 9 At MIX10

  Check out this great Internet Explorer 9 (IE9) video interview from this years MIX10 conference. John Hrvatin is a Lead Microsoft PM on the IE9 Project. Johns a smart guy who patiently answered all my questions about IE9. Thanks John! I highly recommend watching this video to see why IE9 sounds so exciting: In the video, John demos IE9 and openly discusses: IE9 Features and performance HTML5 support Gives a IE9 demo Explains new IE9 JavaScript engine (JIT, Multicore, GPU Powered)...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• Video crashes with 10.10

  - by John Mahon

  I have installed both the 64bit and 32 bit versions of 10.10 on my Compaq Presario PC. I first installed the 64 bit version of the OS.The video often crashed when switching user. It also went haywire occasionally when I visited some web-sites. I read that there may be some problems with the 64 bit OS. So I installed the 32 bit version on another disk. This version seemed even less well behaved. HP's model number for the computer is SR1838NX. The hardware is listed at http://bizsupport1.austin.hp.com/bizsupport/TechSupport/Document.jsp?objectID=c00628274&lang=en&cc=us&contentType=SupportFAQ&prodSeriesId=1841793&prodTypeId=12454&printver=true#A0 I think the important info is that the chip set is "ATI Radeon Xpress 200" and the processor is "Athlon 64 (S) 3700+ 2.2 GHz" Has anyone else had video problems with similar machines? Is there a work around or an update? I have had previous versions of Ubuntu working on this machine and other flavors of Linux as well. Thanks in advance. John

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• Create simple jQuery plugin

  - by ybbest

  In the last post, I have shown you how to add the function to jQuery. In this post, I will show you how to create plugin to achieve this. 1. You need to wrap your code in the following construct, this is because you should not use $ directly as $ is global variable, it could have clash with some other library which also use $.Basically, you can pass in jQuery object into the function, so that $ is made available inside the function. (JavaScript use function to create scope, so you can make sure $ is referred to jQuery inside the function ) (function($){ //Your code goes here. }; })(jQuery); 2. Put your code into the construct above. (function ($) { $.getParameterByName = function (name) { name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]"); var regexS = "[\\?&]" + name + "=([^&#]*)"; var regex = new RegExp(regexS); var results = regex.exec(window.location.search); if (results == null) return ""; else return decodeURIComponent(results[1].replace(/\+/g, " ")); }; })(jQuery); 3. Now you can reference the code into you project and you can call the method in you JavaScript References: Provides scope for variables Variables are scoped at the function level in javascript. This is different to what you might be used to in a language like C# or Java where the variables are scoped to the block. What this means is if you declare a variable inside a loop or an if statement, it will be available to the entire function. If you ever find yourself needing to explicitly scope a variable inside a function you can use an anonymous function to do this. You can actually create an anonymous function and then execute it straight away and all the variables inside will be scoped to the anonymous function: (function() { var myProperty = "hello world"; alert(myProperty); })(); alert(typeof(myProperty)); // undefined How does an anonymous function in JavaScript work? Building Your First jQuery Plugin A Plugin Development Pattern

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• arch openldap authentication failure

  - by nonus25

  I setup the openldap, all look fine but i cant setup authentication, #getent shadow | grep user user:*::::::: tuser:*::::::: tuser2:*::::::: #getent passwd | grep user git:!:999:999:git daemon user:/:/bin/bash user:x:10000:2000:Test User:/home/user/:/bin/zsh tuser:x:10000:2000:Test User:/home/user/:/bin/zsh tuser2:x:10002:2000:Test User:/home/tuser2/:/bin/zsh from root i can login as a one of these users #su - tuser2 su: warning: cannot change directory to /home/tuser2/: No such file or directory 10:24 tuser2@juliet:/root i cant login via ssh also passwd is not working #ldapwhoami -h 10.121.3.10 -D "uid=user,ou=People,dc=xcl,dc=ie" ldap_bind: Server is unwilling to perform (53) additional info: unauthenticated bind (DN with no password) disallowed 10:30 root@juliet:~ #ldapwhoami -h 10.121.3.10 -D "uid=user,ou=People,dc=xcl,dc=ie" -W Enter LDAP Password: ldap_bind: Invalid credentials (49) typed password by me is correct /etc/openldap/slapd.conf access to dn.base="" by * read access to dn.base="cn=Subschema" by * read access to * by self write by users read by anonymous read access to * by dn="uid=root,ou=Roles,dc=xcl,dc=ie" write by users read by anonymous auth access to attrs=userPassword,gecos,description,loginShell by self write access to attrs="userPassword" by dn="uid=root,ou=Roles,dc=xcl,dc=ie" write by anonymous auth by self write by * none access to * by dn="uid=root,ou=Roles,dc=xcl,dc=ie" write by dn="uid=achmiel,ou=People,dc=xcl,dc=ie" write by * search access to attrs=userPassword by self =w by anonymous auth access to * by self write by users read database hdb suffix "dc=xcl,dc=ie" rootdn "cn=root,dc=xcl,dc=ie" rootpw "{SSHA}AM14+..." there are some parts of that conf file /etc/openldap/ldap.conf looks : BASE dc=xcl,dc=ie URI ldap://192.168.10.156/ TLS_REQCERT allow TIMELIMIT 2 so my question is what i am missing that ldap not allow me login by using password ?

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• What does Apache's "Require all granted" really do?

  - by John Crawford

  I've just update my Apache server to Apache/2.4.6 which is running under Ubuntu 13.04. I used to have a vhost file that had the following: <Directory "/home/john/development/foobar/web"> AllowOverride All </Directory> But when I ran that I got a "Forbidden. You don't have permission to access /" After doing a little bit of googling I found out that to get my site working again I needed to add the following line "Require all granted" so that my vhost looked like this: <Directory "/home/john/development/foobar/web"> AllowOverride All Require all granted </Directory> I want to know if this is "safe" and does not bring in any security issues. I read on Apache's page that this "mimics the functionality the was previously provided by the 'Allow from all' and 'Deny from all' directives. This provider can take one of two arguments which are 'granted' or 'denied'. The following examples will grant or deny access to all requests." But it didn't say if this was a security issue of some sort or why we now have to do it when in the past you did not have to.

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• Silverlight Cream for March 21, 2010 -- #816

  - by Dave Campbell

  In this Issue: Michael Washington, John Papa(-2-, -3-, -4-), Jonas Follesø, David Anson, Scott Guthrie, Andrej Tozon, Bill Reiss(-2-), Pete Blois, and Lee. Shoutouts: Frank LaVigne has a Mix10 Session Downloader for us all to use... thanks Frank! Read what Ward Bell has to say about MVVM, Josh Smith’s Way ... it's all good. Robby Ingebretsen posts on his 10 Favorite Open Source Fonts You Can Embed in WPF or Silverlight Mike Harsh posted Slides and Demos from my MIX10 Session . The download link at Drop.io is down for maintenance until Sunday evening, March 21. From SilverlightCream.com: Blend 4: TreeView SelectedItemChanged using MVVM Michael Washington has a post up about doing SelectedItemChanged on a TreeView with MVVM, oh and he's starting out in Blend 4... Silverlight TV 14: Developing for Windows Phone 7 with Silverlight John Papa hit Silverlight TV pretty hard at the beginning of MIX10. This first one is with Mike Harsh talking about WP7. (Hi Mike ... wondered where you'd run off to!), and you can go to the shoutout section to get Mike's session material from MIX as well. Silverlight TV 15: Announcing Silverlight 4 RC at MIX 10 In this next Silverlight TV(15), John Papa and Adam Kinney discuss Silverlight 4RC ... thank goodness it's out, we can all let go of the breath we've been holding in :) Silverlight TV 16: Tim Heuer and Jesse Liberty Talk about Silverlight 4 RC at MIX 10 Silverlight TV 16 has John Papa sharing the spotlight with Jesse Liberty and Tim Heuer ... geez... can you find 3 more kowledgable Silverlight folks to listen to? No? then go listen to this :) Silverlight TV 17: Build a Twitter Client for Windows Phone 7 with Silverlight The latest Silverlight TV has John Papa bringing Mike Harsh back to produce a Twitter Client for WP7. Simulating multitouch on the Windows Phone 7 Emulator Jonas Follesø has a great post up about simulating multi-touch on WP7 using multiple mice ... yeah, you read that right :) Using IValueConverter to create a grouped list of items simply and flexibly David Anson demonstrates grouping items in a ListBox using IValueConverter. I think I can pretty well guarantee I would NOT have thought of doing this.. :) Building a Windows Phone 7 Twitter Application using Silverlight In the MIX10 first-day keynote, Scott Guthrie did File->New Project and built a WP7 Twitter app. He has that up as a tutorial with all sorts of external links including one to the keynote itself. Named and optional parameters in Silverlight 4 Andrej Tozon delves into the optional parameters that are now available to Silverlight developers... pretty cool stuff. Space Rocks game step 4: Inheriting from Sprite Bill Reiss continues with his game development series with this one on inheriting from the Sprite class and centering objects Space Rocks game step 5: Rotating the ship Bill Reiss's episode 5 is on rotating the ship you setup in episode 4. Don't worry about the transforms, Bill gives it all to us :) Labyrinth Sample for Windows Phone Wow... check out the sample Pete Blois did for the Phone... Silverlight coolness :) PathListBox in SL4 – firstlook Lee has a post up on the PathListBox. I think this is going to catch on quick... it's just too cool not to! Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

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• hierachical query to return final row

  - by jeff

  I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

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• Tricky SQL query involving consecutive values

  - by Gabriel

  I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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• Query only the first detail record for each master record

  - by Neal S.

  If I have the following master-detail relationship: owner_tbl auto_tbl --------- -------- owner --- owner auto year And I have the following table data: owner_tbl auto_tbl --------- -------- john john, corvette, 1968 john, prius, 2008 james james, f-150, 2004 james, cadillac, 2002 james, accord, 2009 jeff jeff, tesla, 2010 jeff, hyundai, 1996 Now, I want to perform a query that returns the following result: john, corvette, 1968 jeff, hyundai, 1996 james, cadillac, 2002 The query should join the two tables, and sort all the records on the "year" field, but only return the first detail record for each master record. I know how to join the tables and sort on the "year" field, but it's not clear how (or if) I might be able to only retrieve the first joined record for each owner. Three related questions: Can I perform this kind of query using LINQ-to-SQL? Can I perform the query using T-SQL? Would it be best to just create a stored procedure for the query given its likely complexity?

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• Odd SQL Results

  - by Ryan Burnham

  So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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• How to get only one row for each distinct value in the column ?

  - by Chavdar

  Hi Everybody, I have a question about Access.If for example I have a table with the following data : NAME | ADDRESS John Taylor | 33 Dundas Ave. John Taylor | 55 Shane Ave. John Taylor | 786 Edward St. Ted Charles | 785 Bloor St. Ted Charles | 90 New York Ave. I want to get one record for each person no matter of the address.For example : NAME | ADDRESS John Taylor | 33 Dundas Ave. Ted Charles | 90 New York Ave. Can this be done with queries only ? I tried using DISTINCT, but when I am selecting both columns, the combination is allways unique so I get all the rows. Thank you !

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• c# ListView unable to check a checkbox! Strange problem.

  - by Kurt

  This is a strange problem, I've not added much code as I don't know were to start. I have a listview control in virtual mode, if I filter the listview to show me all people called John, I then see 3 users called John, I then cancel the filter setting all values to null and return all data to the listview, I now have several hundred items in the list but I can only see 30 on screen unless I scroll down the listview. I then use the code below to check a checkbox in each row, all get checked apart from the 3 Johns but if I can see 1 of the 3 Johns in listview without scrolling and then run the code below the visible John is checked. for (int i = 0; i < this._items.Count; i++) { this._items[i].Checked = true; } I have checked the status of the checkbox just before it is checked in the above code and if John is visible then the checkbox believes it is unchecked (false), if it is not visible it belives it is checked (true). So having one visible John on screen the checkbox looks unchecked and running a test proves it is unchecked, for the two Johns I can't see they believe they are checked but if I scroll down so I can see them they aren't. Any ideas? Thanks

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• Objective C - when should "typedef" precede "enum", and when should an enum be named?

  - by Scott Pendleton

  In sample code, I have seen this: typedef enum Ename { Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John} EmployeeName; and this: typedef enum {Bob, Mary, John}; but what compiled successfully for me was this: enum {Bob, Mary, John}; I put that line in a .h file above the @interface line, and then when I #import that .h file into a different class's .m file, methods there can see the enum. So, when are the other variants needed? If I could name the enum something like EmployeeNames, and then, when I type "EmployeeNames" followed by a ".", it would be nice if a list pops up showing what the enum choices are.

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• How to differenciate the data when doing a UNION on 2 SELECTS ?

  - by wiooz

  If I have the following two tables : Employes Bob Gina John Customers Sandra Pete Mom I will do a UNION for having : Everyone Bob Gina John Sandra Pete Mom The question is : In my result, how can I creat a dumn column of differenciate the data from my tables ? Everyone Bob (Emp) Gina (Emp) John (Emp Sandra (Cus) Pete (Cus) Mom (Cus) I want to know from with table the entry is from withouth adding a new column in the database... SELECT Employes.name FROM Employes UNION SELECT Customers.name FROM Customers;

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• Perl script matching a certain patern

  - by kivien

  Assuming the file.txt is as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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• Merging two Python dictionaries, summing the values of matching elements?

  - by jamieb

  Given two dictionaries, like so: q1_sales = {'Bob': 21000, 'Charles': 18000, 'John': 35000, 'Sam': 14000} q2_sales = {'Bob': 22000, 'John': 33000, 'Sam': 23000} What's the most pythonic way to produce this? total_sales = {'Bob': 43000, 'Charles': 18000, 'John': 68000, 'Sam': 37000} Thanks!

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• ruby eval('\1') of gsub possible?

  - by Horace Ho

  I try to replace a sub-str by the content of a valiable where its name matches the sub-str by: >> str = "Hello **name**" => "Hello **name**" >> name = "John" => "John" str.gsub(/\*\*(.*)\*\*/, eval('\1')) # => error! the last line in the code above is a syntax error. and: >> str.gsub(/\*\*(.*)\*\*/, '\1') => "Hello name" >> str.gsub(/\*\*(.*)\*\*/, eval("name")) => "Hello John" what I want is the result of: str.gsub(/\*\*(.*)\*\*/, eval("name")) # => "Hello John" any help will be appreciated. thx!

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• Confused with ECMAScript Language Specification Function Calls section

  - by Ding

  Hi, I am reading ECMAScript Language Specification Function Calls section Can someone rephrase or detailed explains the following sentense for me? The production CallExpression : MemberExpression Arguments is evaluated as follows: Evaluate MemberExpression. let's take this code as an example. var john = { name: 'John', greet: function(person) { alert("Hi " + person + ", my name is " + this.name); } }; john.greet("Mark"); Take above code as an example, what does production CallExpression mean? what is MemberExpression in this case, john.greet? Thanks!

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• How can I print lines that match a pattern in Perl?

  - by kivien

  Assuming the file.txt having just one sentence per line as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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• Class Problem (c++ and prolog)

  - by Joshua Green

  I am using the C++ interface to Prolog (the classes and methods of SWI-cpp.h). For working out a simple backtracking that john likes mary and emma and sara: likes(john, mary). likes(john, emma). likes(john, ashley). I can just do: { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } This works in a separate code, so the syntax is correct. But I am also trying to get this simple backtracking to work within a class: class UserTaskProlog { public: UserTaskProlog(ArRobot* r); ~UserTaskProlog(); protected: int cycles; char* argv[1]; ArRobot* robot; void logTask(); }; This class works fine, with my cycles variable incrementing every robot cycle. However, when I run my main code, I get an Unhandled Exception error message: UserTaskProlog::UserTaskProlog(ArRobot* r) : robotTaskFunc(this, &UserTaskProlog::logTask) { cycles = 0; PlEngine e(argv[0]); PlCall("consult('myFile.pl')"); robot->addSensorInterpTask("UserTaskProlog", 50, &robotTaskFunc); } UserTaskProlog::~UserTaskProlog() { robot->remSensorInterpTask(&robotTaskFunc); // Do I need a destructor here for pl? } void UserTaskProlog::logTask() { cycles++; cout << cycles; { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } } I have my opening and closing brackets for PlFrame. I have my frame, my query, etc... The exact same code that backtracks and prints out mary and emma and sara. What am I missing here that I get an error message? Here is what I think the code should do: I expect mary and emma and sara to be printed out once, every time cycles increments. However, it opens SWI-cpp.h file automatically and points to class PlFrame. What is it trying to tell me? I don't see anything wrong with my PlFrame class declaration. Thanks,

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• Split a line from a para in java

  - by John

  Hi... I am having problem splitting a para into line.... i need to first read a file then split in into lines if i get a . or ! or ? I also need to remove any extra white space... This is wad i've written so far.... try { Scanner line = new Scanner(mFile); mLine = line.nextLine(); String Matrix[]=mLine.split("\\."); for (int i = 0; i < Matrix.length; ++i) { System.out.println(Matrix[i]); } Input: Hi. My name is John. Who are you ? Output: Hi My name is John Who are you

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• Excel code question

  - by karatekid

  I have 2 different excel files(all people and special people) that i want to kick special people from all people. Cant find a way.. if you don't understand check my example: all people special people ---------- -------------- 1-john 1-john 2-jim 2-marry 3-mariah 4-russel 5-marry I want: all people special people ---------- -------------- 1-jim 1-john 2-mariah 2-marry 3-russel

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• Is it possible to use ContainsTable to get results for more than one column?

  - by LockeCJ

  Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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• Graph databases and Php

  - by stagas

  I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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