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  • Chatbot client and class modification

    - by blake
    ChatBot Class Modification: Modify the reply() method of the ChatBot class to recognize additional words and phrases. Part 1: Everyone must complete this section. When the userInput parameter value is: The reply method should return: how do I quit enter quit how do I exit enter quit how do I stop enter quit how do I ____ do you really want to do that how are you I'm fine how ______ I don't know Add two additional words or phrases to recognize and respond to. ChatBot Client Modification: Modify the ChatBot client application to loop until the end-user enters "quit". Here is my service class / ** * Java Chatbot Service class * @author Blake * 3/5/2012 */ /** * Default constructor. */ public class Chatbot { private String name; /** Users name */ private String introbot; /** Name of the Chatbot */ private String reply; /** Replies to the input of the string name and string introbot */ /** * Constructs mutebot object * @param mutebow - returns name of mutebot */ public Chatbot() { name = "MuteBot"; } /** * Changes Name * @param name - new name */ public void setName (String n) { name = n; } /** * Accesses name * @return a brand new name */ public String getName() { return name; } /** * Accesses introbot * @return name of mutebot */ public String introbot() { String intro = "Hello! My name is " + name; return intro; } /** * Accesses replay(String newuserinput) * @return introbot reply to user input */ public String getreply(String newuserinput) { String reply = "I'm just learning to talk"; if (newuserinput.equalsIgnoreCase("What")) reply = "Why do you ask?"; else if (newuserinput.equalsIgnoreCase("Why") ) reply = "Why Not"; else if (newuserinput.equalsIgnoreCase("How")) reply = "I don't know!"; else if (newuserinput.equalsIgnoreCase("Where") ) reply = "Anne Arundel Community College"; else if (newuserinput.equalsIgnoreCase("When")) reply = "Tomorrow"; else if (newuserinput.equalsIgnoreCase("how do I quit")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how do I exit")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how do I stop")) reply = "enter quit"; else if (newuserinput.equalsIgnoreCase("how are you")) reply = "I'm fine"; else if (newuserinput.equalsIgnoreCase("how do you do")) reply = "I am doing well"; else if (newuserinput.equalsIgnoreCase("how do I get out")) reply = "By going through the door"; else if (newuserinput.indexOf("how do I" ) ==0) { String substring = newuserinput.substring(8); reply = "do you really want to do that" + substring; } else if (newuserinput.indexOf("how" ) ==0) { String substring = newuserinput.substring(10); reply = "I don't know" + substring ; } return reply; } } Here is my client/application class /** * Java Chatbot Client class * @author Blake * 3/5/2012 */ import java.util.Scanner; public class ChatbotClient { public static void main(String[] args) { Scanner input = new Scanner(System.in); Chatbot t = new Chatbot(); System.out.print("What is your name? "); String name = input.nextLine(); System.out.println(t.introbot()); System.out.print(name + "> "); String reply = input.nextLine(); System.out.println(t.getName() + "> " + t.getreply(reply)); //while (reply < quit) /*{ quit++ i = i + 1 }*/ } } I don't know what I am doing wrong with this part right here Modify the ChatBot client application to loop until the end-user enters "quit". I am trying to create a while loop which will continue until user says quit.

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  • Trying to sentinel loop this program.

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • Ladder-like word game in Java

    - by sasquatch90
    I've found this question http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game and I would also like to do this kind of program. I've written some code but already have two issues. Here's what I already have : GRID : public class Grid { public Grid(){} public Grid( Element e ){} } ELEMENT : public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){} //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public static void changeState(int s){ } public int getState(){ return state; } public boolean equalLength(){ return true; } public boolean equalValue(){ return true; } @Override public String toString(){ return "["+letter+"]"; } } MAIN: import java.util.Scanner; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); System.out.println("Height: "); while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); Grid[] game = new Grid[height]; for(int i = 1; i <= height; i++) { String s; do { System.out.println("Length " + i + ", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()+1]; Element single = null; String[] temp = null; //issue here temp = s.split(""); System.out.println("s.length: "+s.length()); System.out.println("temp.length: "+temp.length); // for(String str : temp){ System.out.println("str:"+str); } for (int k = 0 ; k < temp.length ; k++) { if( k == 0 ){ single = new Element(temp[k], 2); System.out.println("single1: "+single); } else{ single = new Element(temp[k], 3); System.out.println("single2: "+single); } line[k] = single; } for (Element l : line) { System.out.println("line:"+l); } //issue here game[i] = line; } // for (Grid g : game) { System.out.println(g); } } } And sample output for debug : Height: 3 Length 1, please! A s.length: 1 temp.length: 2 str: str:A single1: [] single2: [A] line:[] line:[A] Here's what I think it should work like. I grab a word from user. Next create Grid element for whole game. Then for each line I create Element[] array called line. I split the given text and here's the first problem. Why string.split() adds a whitespace ? You can see clearly in output that it is added for no reason. How can I get rid of it (now I had to add +1 to the length of line just to run the code). Continuing I'm throwing the splitted text into temporary String array and next from each letter I create Element object and throw it to line array. Apart of this empty space output looks fine. But next problem is with Grid. I've created constructor taking Element as an argument, but still I can't throw line as Grid[] elements because of 'incompatible types'. How can I fix that ? Am I even doing it right ? Maybe I should get rid of line as Element[] and just create Grid[][] ?

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  • How to code a time delay between plotting points in JFreeCharts?

    - by Javajava
    Is there a way to animate the plotting process of an xy-line chart using JFreeCharts? I want to be able to watch the program draw each line segment and connect them. For example, if I paste this into the TextArea, "gtgtaaacaatatatggcg," I want to watch it graph each line segment one by one. Thanks in advance! :) My code is below: import java.util.Scanner; import java.applet.Applet; import java.awt.; import java.awt.event.ActionListener; import java.awt.event.ActionEvent; import org.jfree.chart.; import org.jfree.chart.plot.PlotOrientation; import org.jfree.data.xy.*; public class RandomWalkComplete extends Applet implements ActionListener { Panel panel; TextArea textarea, outputArea; Button move,exit; String thetext; Scanner reader = new Scanner(System.in); String thetext2; Label instructions; int x,y; public void init() { setSize(500,250); //set size of applet instructions=new Label("Paste the gene sequences in the " + "text field and press the graph button."); add(instructions); panel = new Panel(); add(panel); setVisible(true); textarea= new TextArea(10,20); add(textarea); move=new Button("Graph"); move.addActionListener(this); add(move); exit=new Button("Exit"); exit.addActionListener(this); add(exit); } public void actionPerformed(ActionEvent e) { XYSeries series = new XYSeries("DNA Walk",false,true); x= 0; y = 0; series.add(x,y); if(e.getSource() == move) { thetext=textarea.getText(); //the text is the DNA bases pasted thetext=thetext.replaceAll(" ",""); //removes spaces thetext2 = ""; for(int i=0; i<thetext.length(); i++) { char a = thetext.charAt(i); switch (a) { case 'A': case 'a'://moves right x+=1; y+=0; series.add(x,y); break; case 'C': case 'c': //moves up x+=0; y+=1; series.add(x,y); break; case 'G': case 'g': //move left x-=1; y+=0; series.add(x,y); break; case 'T': case 't'://move down x+=0; y-=1; series.add(x,y); break; default: // series.add(0,0); break; } } XYDataset xyDataset = new XYSeriesCollection(series); JFreeChart chart = ChartFactory.createXYLineChart ("DNA Random Walk", "", "", xyDataset, PlotOrientation.VERTICAL, true, true, false); ChartFrame frame1=new ChartFrame("DNA Random Walk",chart); frame1.setVisible(true); frame1.setSize(300,300); } if(e.getSource()==exit) {System.exit(0);} } public void stop(){} }

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  • Trying to sentinel loop this program. [java]

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • Java: How to check the random letters from a-z, out of 10 letters minimum 2 letter should be a vowel

    - by kalandar
    I am writing a program to validate the following scenarios: Scenario 1: I am using the Random class from java.util. The random class will generate 10 letters from a-z and within 10 letter, minimum 2 letters must be a vowels. Scenario 2: When the player 1 and player 2 form a word from A-Z, he will score some points. There will be a score for each letter. I have already assigned the values for A-Z. At the end of the game, the system should display a scores for player 1 and player 2. How do i do it? Please help. I will post my code here. Thanks a lot. =========================================== import java.util.Random; import java.util.Scanner; public class FindYourWords { public static void main(String[] args) { Random rand = new Random(); Scanner userInput = new Scanner(System.in); //==================Player object=============================================== Player playerOne = new Player(); playerOne.wordScore = 0; playerOne.choice = "blah"; playerOne.turn = true; Player playerTwo = new Player(); playerTwo.wordScore = 0; playerTwo.choice = "blah"; playerTwo.turn = false; //================== Alphabet ================================================== String[] newChars = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z" }; //values of the 26 alphabets to be used int [] letterScore = {1,3,3,2,1,4,2,4,1,8,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10}; // to assign score to the player1 and player 2 String[] vowel = { "a", "e", "i", "o", "u" }; // values for vowels int vow=0; System.out.println("FINDYOURWORDS\n"); int[] arrayRandom = new int[10]; //int array for word limiter String[] randomLetter = new String[10]; //storing the letters in newChars into this array //=============================================================================== boolean cont = true; while (cont) { if (playerOne.turn) { System.out.print("Letters of Player 1: "); } else if (!playerOne.turn) { System.out.print("Letters of Player 2: "); } for (int i = 0; i < arrayRandom.length; i++) { //running through the array limiter int r = rand.nextInt(newChars.length); //assigning random nums to the array of letters randomLetter[i] = newChars[r]; System.out.print(randomLetter[i]+ " "); } //input section for player System.out.println(""); System.out.println("Enter your word (or '@' to pass or '!' to quit): "); if (playerOne.turn) { playerOne.choice = userInput.next(); System.out.println(playerOne.turn); playerOne.turn = false; } else if (!playerOne.turn){ playerTwo.choice = userInput.next(); System.out.println(playerOne.turn); playerOne.turn = true; } //System.out.println(choice); String[] wordList = FileUtil.readDictFromFile("words.txt"); //Still dunno what this is for if (playerOne.choice.equals("@")) { playerOne.turn = false; } else if (playerTwo.choice.equals("@")) { playerOne.turn = true; } else if (playerOne.choice.equals("!")) { cont = false; } for (int i = 0; i < wordList.length; i++) { //System.out.println(wordList[i]); if (playerOne.choice.equalsIgnoreCase(wordList[i]) || playerTwo.choice.equalsIgnoreCase(wordList[i])){ } } } }}

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  • Need help in creating test appliaction in Java and passing parameters into a new designed Java API.

    - by Christophe
    Need help, Please!!! By following the protocol, the Request should be built in 5 byte length, including 1 byte for changing Braud rate (Speed), and send request to a RS-232 port. Protocol: --------------- Request for the command processing, with optional extra byte for changing Baud Rate: LGT : length message ( LGT = 5 ) TYPE : 0x06 TO(time out): 0x0000 CMD : (1 byte) 0x02 application update Baud Rate : (1 byte) 0xNN (optional parameter to change baud rate of the Mnt App) where NN can be: 0x00 = No Baud Rate Change (similar to 4-byte command above) 0x09 = Change to 9600 Baud for Application Update speed 0x0A = Change to 19200 Baud for Application Update speed 0x0E = Change to 115200 Baud for Application Update speed All other bytes are not accepted and will result in a status of 0x01. ------------------ I'm trying to test if my code works or not by creating another class (TestApplication.java) and pass the "3 differenr Baut rate" to this CPXAppliaction. the 3 Baud Rate is supposed to input by reading a file.txt. Question: How do you think these code (first half)? please don't warry about the details about the "sending part". I mean, do I need setter/getter for the "speed" parameter pass? I created the demo test class DemoApp.java (input speed by reading a txt file, and pass into CPXAppliaction). how do you think about that code? Many thanks to you guys!! public class CPXApplication extends CPXCommand { private int speed; . public CPXApplication() { speed = 9600; } public CPXApplication(int speedinit) { speed = speedinit; // TODO: where to get the speed? } protected void buildRequest() throws ElitePortException { String trans = ""; // build the full-qualified message following the protocol trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 5); trans = addToRequest(trans, (char) 6); trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 2); switch (speed) { case 9600: trans = addToRequest(trans, (char) 0x09); break; case 19200: trans = addToRequest(trans, (char) 0x0A); break; case 115200: trans = addToRequest(trans, (char) 0x0E); break; default: // TODO: unexpected baud rate. throw(); break; } trans = EncryptBinary(trans); trans = "F0." + trans; wrapRequest(trans); } protected String addToRequest(String req, char c) { return req + c; } protected String addToRequest(String req, String s) { return req + s; } protected String addToRequest(String req) { return req; } public void analyzeResponse() { //.............. } } Here is the demo test code: package com.ingenico.testApp; import com.ingenico.EliteFd.; import java.util.Scanner; import java.io.; class Run { public static void run() { CPXAppliactionUpdate input = new CpXApplicationUpdate(); int lineno = 0; try { FileReader fr = new FileReader("baudRateSpeed.txt"); BufferedReader reader = new BufferedReader(fr); String line = reader.readLine(); Scanner scan = null; while (line != null) { scan = new Scanner(line); String speed; speed = scan.next(); if (lineno == 0) { input.speed = speed; lineno++; } else { input = cpxapplicationupdate(speed, input); } line = reader.readLine(); } reader.close(); } catch (FileNotFoundException e) { System.out.println("Could not find the file"); } catch (IOException e) { System.out.println("Had a problem reading from file"); } } public class DemoApp{ public void main(String args[]) { run(); } } }

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  • I cannot find many android application in "my" market

    - by Josef Sábl
    I just bought HTC Tattoo with Android 1.6 and to my disappointment, there are lots of applications that I cannot find in my market. I use AppBrain, to select and install apps but once I try to install them, there is error message that application does not exist. Same thing is when I try to install using barcode. What is going on? I guess it has something to do with my location (Europe) but I could not find note about this anywhere.

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  • Calculating for leap year [migrated]

    - by Bradley Bauer
    I've written this program using Java in Eclipse. I was able to utilize a formula I found that I explained in the commented out section. Using the for loop I can iterate through each month of the year, which I feel good about in that code, it seems clean and smooth to me. Maybe I could give the variables full names to make everything more readable but I'm just using the formula in its basic essence :) Well my problem is it doesn't calculate correctly for years like 2008... Leap Years. I know that if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) then we have a leap year. Maybe if the year is a leap year I need to subtract a certain amount of days from a certain month. Any solutions, or some direction would be great thanks :) package exercises; public class E28 { /* * Display the first days of each month * Enter the year * Enter first day of the year * * h = (q + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5j) % 7 * * h is the day of the week (0: Saturday, 1: Sunday ......) * q is the day of the month * m is the month (3: March 4: April.... January and Feburary are 13 and 14) * j is the century (year / 100) * k is the year of the century (year %100) * */ public static void main(String[] args) { java.util.Scanner input = new java.util.Scanner(System.in); System.out.print("Enter the year: "); int year = input.nextInt(); int j = year / 100; // Find century for formula int k = year % 100; // Find year of century for formula // Loop iterates 12 times. Guess why. for (int i = 1, m = i; i <= 12; i++) { // Make m = i. So loop processes formula once for each month if (m == 1 || m == 2) m += 12; // Formula requires that Jan and Feb are represented as 13 and 14 else m = i; // if not jan or feb, then set m to i int h = (1 + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5 * j) % 7; // Formula created by a really smart man somewhere // I let the control variable i steer the direction of the formual's m value String day; if (h == 0) day = "Saturday"; else if (h == 1) day = "Sunday"; else if (h == 2) day = "Monday"; else if (h == 3) day = "Tuesday"; else if (h == 4) day = "Wednesday"; else if (h == 5) day = "Thursday"; else day = "Friday"; switch (m) { case 13: System.out.println("January 1, " + year + " is " + day); break; case 14: System.out.println("Feburary 1, " + year + " is " + day); break; case 3: System.out.println("March 1, " + year + " is " + day); break; case 4: System.out.println("April 1, " + year + " is " + day); break; case 5: System.out.println("May 1, " + year + " is " + day); break; case 6: System.out.println("June 1, " + year + " is " + day); break; case 7: System.out.println("July 1, " + year + " is " + day); break; case 8: System.out.println("August 1, " + year + " is " + day); break; case 9: System.out.println("September 1, " + year + " is " + day); break; case 10: System.out.println("October 1, " + year + " is " + day); break; case 11: System.out.println("November 1, " + year + " is " + day); break; case 12: System.out.println("December 1, " + year + " is " + day); break; } } } }

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  • Parsing T-SQL – The easy way

    - by Dave Ballantyne
    Every once in a while, I hit an issue that would require me to interrogate/parse some T-SQL code.  Normally, I would shy away from this and attempt to solve the problem in some other way.  I have written parsers before in the the past using LEX and YACC, and as much fun and awesomeness that path is,  I couldnt justify the time it would take. However, this week I have been faced with just such an issue and at the back of my mind I can remember reading through the SQLServer 2012 feature pack and seeing something called “Microsoft SQL Server 2012 Transact-SQL Language Service “.  This is described there as : “The SQL Server Transact-SQL Language Service is a component based on the .NET Framework which provides parsing validation and IntelliSense services for Transact-SQL for SQL Server 2012, SQL Server 2008 R2, and SQL Server 2008. “ Sounds just what I was after.  Documentation is very scant on this so dont take what follows as best practice or best use, just a practice and a use. Knowing what I was sort of looking for something, I found the relevant assembly in the gac which is the simply named ,’Microsoft.SqlServer.Management.SqlParser’. Even knowing that you wont find much in terms of documentation if you do a web-search, but you will find the MSDN documentation that list the members and methods etc… The “scanner”  class sounded the most appropriate for my needs as that is described as “Scans Transact-SQL searching for individual units of code or tokens.”. After a bit of poking, around the code i ended up with was something like [System.Reflection.Assembly]::LoadWithPartialName("Microsoft.SqlServer.Management.SqlParser") | Out-Null $ParseOptions = New-Object Microsoft.SqlServer.Management.SqlParser.Parser.ParseOptions $ParseOptions.BatchSeparator = 'GO' $Parser = new-object Microsoft.SqlServer.Management.SqlParser.Parser.Scanner($ParseOptions) $Sql = "Create Procedure MyProc as Select top(10) * from dbo.Table" $Parser.SetSource($Sql,0) $Token=[Microsoft.SqlServer.Management.SqlParser.Parser.Tokens]::TOKEN_SET $Start =0 $End = 0 $State =0 $IsEndOfBatch = $false $IsMatched = $false $IsExecAutoParamHelp = $false while(($Token = $Parser.GetNext([ref]$State ,[ref]$Start, [ref]$End, [ref]$IsMatched, [ref]$IsExecAutoParamHelp ))-ne [Microsoft.SqlServer.Management.SqlParser.Parser.Tokens]::EOF) { try{ ($TokenPrs =[Microsoft.SqlServer.Management.SqlParser.Parser.Tokens]$Token) | Out-Null $TokenPrs $Sql.Substring($Start,($end-$Start)+1) }catch{ $TokenPrs = $null } } As you can see , the $Sql variable holds the sql to be parsed , that is pushed into the $Parser object using SetSource,  and then we will use GetNext until the EOF token is returned.  GetNext will also return the Start and End character positions within the source string of the parsed text. This script’s output is : TOKEN_CREATE Create TOKEN_PROCEDURE Procedure TOKEN_ID MyProc TOKEN_AS as TOKEN_SELECT Select TOKEN_TOP top TOKEN_INTEGER 10 TOKEN_FROM from TOKEN_ID dbo TOKEN_TABLE Table note that the ‘(‘, ‘)’  and ‘*’ characters have returned a token type that is not present in the Microsoft.SqlServer.Management.SqlParser.Parser.Tokens Enum that has caused an error which has been caught in the catch block.  Fun, Fun ,Fun , Simple T-SQL Parsing.  Hope this helps someone in the same position,  let me know how you get on.

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  • Why do I get garbage output when printing an int[]?

    - by Kat
    My program is suppose to count the occurrence of each character in a file ignoring upper and lower case. The method I wrote is: public int[] getCharTimes(File textFile) throws FileNotFoundException { Scanner inFile = new Scanner(textFile); int[] lower = new int[26]; char current; int other = 0; while(inFile.hasNext()){ String line = inFile.nextLine(); String line2 = line.toLowerCase(); for (int ch = 0; ch < line2.length(); ch++) { current = line2.charAt(ch); if(current >= 'a' && current <= 'z') lower[current-'a']++; else other++; } } return lower; } And is printed out using: for(int letter = 0; letter < 26; letter++) { System.out.print((char) (letter + 'a')); System.out.println(": " + ts.getCharTimes(file)); } Where ts is a TextStatistic object created earlier in my main method. However when I run my program, instead of printing out the number of how often the character occurs it prints: a: [I@f84386 b: [I@1194a4e c: [I@15d56d5 d: [I@efd552 e: [I@19dfbff f: [I@10b4b2f And I don't know what I'm doing wrong.

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  • user input question

    - by jdbeverly87
    My program checks to test if a word or phrase is a palindrome (reads the same both backward and forward, ex "racecar"). The issue I'm having is after someone enters in "racecar" getting it to actually test. In the below code, I marked where if I type in "racecar" and run, Java returns the correct answer so I know I'm right there. But what am I missing as far as entering it into the console. I think my code is ok, but maybe I have something missing or in the wrong spot? Not really looking for a new answer unless I'm missing something, but if possible perhaps a pro at this moving my code to the correct area bc I'm stuck! `import java.util.*; public class Palindrome { public static void main(String[] args) { String myInput; Scanner in = new Scanner(System.in); System.out.println("Enter a word or phrase: "); **//this asks user for input but doesn't check for whether or not it is a palindrome** myInput = in.nextLine(); in.close(); System.out.println("You entered: " + myInput); } { String s="racecar"; **//I can type a word here and it works but I need** int i; **//I need it to work where I ask for the input** int n=s.length(); String str=""; for(i=n-1;i>=0;i--) str=str+s.charAt(i); if(str.equals(s)) System.out.println(s+ " is a palindrome"); else System.out.println(s+ " is not a palindrome"); } }` I'm new at programming so I'm hoping what I got is ok. I know the palindrome test works I'm just needing helping having it test thru where I'm entering it into the console. Thanks

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  • Sort ArrayList alphabetically

    - by relyt
    I'm trying to find all permutations of a string and sort them alphabetically. This is what I have so far: public class permutations { public static void main(String args[]) { Scanner s = new Scanner(System.in); System.out.print("Enter String: "); String chars = s.next(); findPerms("", chars); } public static void findPerms(String mystr, String chars) { List<String> permsList = new ArrayList<String>(); if (chars.length() <= 1) permsList.add(mystr + chars); //System.out.print(mystr + chars + " "); else for (int i = 0; i < chars.length(); i++) { String newString = chars.substring(0, i) + chars.substring(i + 1); findPerms(mystr + chars.charAt(i), newString); } Collections.sort(permsList); for(int i=0; i<permsList.size(); i++) { System.out.print(permsList.get(i) + " "); } } } IF I enter a string "toys" I get: toys tosy tyos tyso tsoy tsyo otys otsy oyts oyst osty osyt ytos ytso yots yost ysto ysot stoy styo soty soyt syto syot What am I doing wrong. How can I get them in alphabetical order? Thanks!

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  • search data from FileReader in Java

    - by maya
    hi I'm new in java how to read and search data from file (txt) and then display the data in TextArea or Jtable. for example I have file txt contains data and I need to display this data in textarea after I clicked a button, I have used FileReader , and t1 t2 tp are attributes in the file import java.io.FileReader; import java.io.IOException; String t1,t2,tp; Ffile f1= new Ffile(); FileReader fin = new FileReader("test2.txt"); Scanner src = new Scanner(fin); while (src.hasNext()) { t1 = src.next(); textarea.setText(t1); t2 = src.next(); textarea.setText(t2); tp = src.next(); textarea.setText(tp); f1.insert(t1,t2,tp); } fin.close(); also I have used the inputstream DataInputStream dis = null; String dbRecord = null; try { File f = new File("text2.text"); FileInputStream fis = new FileInputStream(f); BufferedInputStream bis = new BufferedInputStream(fis); dis = new DataInputStream while ( (dbRecord = dis.readLine()) != null) { StringTokenizer st = new StringTokenizer(dbRecord, ":"); String t1 = st.nextToken(); String t2 = st.nextToken(); String tp = st.nextToken(); textarea.setText(textarea.getText()+t1); textarea.setText(textarea.getText()+t2); textarea.setText(textarea.getText()+tp); } } catch (IOException e) { // catch io errors from FileInputStream or readLine() System.out.println("Uh oh, got an IOException error: " + e.getMessage()); } finally { } but both of them don't work ,so please any one help me I want to know how to read data and also search it from file and i need to display the data in textarea . thanks in advance

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  • How to create reactive tasks for programming competitions?

    - by directx
    A reactive task is sometimes seen in the IOI programming competition. Unlike batch tasks, reactive solutions take input from another program as well as outputting it. The program typically 'query' the judge program a certain number of times, then output a final answer. An example The client program accepts lines one by one, and simply echoes it back. When it encountered a line with "done", it exists immediately. The client program in Java looks like this: import java.util.*; class Main{ public static void main (String[] args){ Scanner in = new Scanner(System.in); String s; while (!(s=in.nextLine()).equals("done")) System.out.println(s); } } The judge program gives the input and processes output from the client program. In this example, it feeds it a predefined input and checks if the client program has echoed it back correctly. A session might go like this: Judge Client ------------------ Hello Hello World World done I'm having trouble writing the judge program and having it judge the client program. I'd appreciate if someone could write a judge program for my example.

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  • I'm getting an error in my Java code but I can't see whats wrong with it. Help?

    - by Fraz
    The error i'm getting is in the fillPayroll() method in the while loop where it says payroll.add(employee). The error says I can't invoke add() on an array type Person but the Employee class inherits from Person so I thought this would be possible. Can anyone clarify this for me? import java.io.*; import java.util.*; public class Payroll { private int monthlyPay, tax; private Person [] payroll = new Person [1]; //Method adds person to payroll array public void add(Person person) { if(payroll[0] == null) //If array is empty, fill first element with person { payroll[payroll.length-1] = person; } else //Creates copy of payroll with new person added { Person [] newPayroll = new Person [payroll.length+1]; for(int i = 0;i<payroll.length;i++) { newPayroll[i] = payroll[i]; } newPayroll[newPayroll.length] = person; payroll = newPayroll; } } public void fillPayroll() { try { FileReader fromEmployee = new FileReader ("EmployeeData.txt"); Scanner data = new Scanner(fromEmployee); Employee employee = new Employee(); while (data.hasNextLine()) { employee.readData(data.nextLine()); payroll.add(employee); } } catch (FileNotFoundException e) { System.out.println("Error: File Not Found"); } } }

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  • Iterator performance contract (and use on non-collections)

    - by polygenelubricants
    If all that you're doing is a simple one-pass iteration (i.e. only hasNext() and next(), no remove()), are you guaranteed linear time performance and/or amortized constant cost per operation? Is this specified in the Iterator contract anywhere? Are there data structures/Java Collection which cannot be iterated in linear time? java.util.Scanner implements Iterator<String>. A Scanner is hardly a data structure (e.g. remove() makes absolutely no sense). Is this considered a design blunder? Is something like PrimeGenerator implements Iterator<Integer> considered bad design, or is this exactly what Iterator is for? (hasNext() always returns true, next() computes the next number on demand, remove() makes no sense). Similarly, would it have made sense for java.util.Random implements Iterator<Double>? Should a type really implement Iterator if it's effectively only using one-third of its API? (i.e. no remove(), always hasNext())

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  • Java get user details

    - by LC
    I'm new to Java and I have to write a program to get user details which appear like this: Author’s Details **************** Name: J. Beans YOB: 1969 Age: 41 Book Details ************ Title: *Wonderful Java* ISBN: *978 0 470 10554 9* Publisher: *Wiley* This is what I've done but it does not work, can anyone help me to find out the problem ? import java.util.Scanner ; public class UserDetails { public static void main(String args[]) { System scan = new Scanner(System.in); input sname, fname, born, title, isbn, publisher; System.out.print("Please enter author's surname:"); sname = input.nextLine(); System.out.print("Please the initial of author's first name:"); fname = input.nextLine(); System.out.print("Please enter the year the author was born:"); born = input.nextLine(); System.out.print("Please enter the author's book title:"); title = input.nextLine(); System.out.print("Please enter the book's ISBN:"); isbn = input.nextLine(); System.out.print("Please enter the publisher of the book:"); publisher = input.nextLine; System.out.println("Author's detail"); System.out.println("**********************"); System.out.println("Name:" + fname + sname); System.out.println("YOB:" + born); System.out.println("Age" + born); System.out.println("Book Details"); System.out.println("**********************"); System.out.println("Title:" + "*" + title + "*"); System.out.println("ISBN:" + "*" + isbn + "*"); System.out.println("Publisher:" + "*" + publisher + "*"); } }

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  • Register and Resolve Generic Interfaces Unity

    - by user1643791
    I am trying to register some generic interfaces and resolve them . I have the registering function private static void RegisterFolderAssemblies(Type t,string folder) { var scanner = new FolderGenericInterfaceScanner(); var scanned = scanner.Scan(t,folder); // gets the implementations from a specific folder scanned.ForEach(concrete => { if (concrete.BaseType != null || concrete.IsGenericType) { myContainer.RegisterType(t, Type.GetType(concrete.AssemblyQualifiedName), concrete.AssemblyQualifiedName); } }); } which is called by the bootstrapper with RegisterFolderAssemblies(typeof(IConfigurationVerification<>),Environment.CurrentDirectory); The registration seem to go through ok but when I try to Resolve them with Type generic = typeof(IConfigurationVerification<>); Type specific = generic.MakeGenericType(input.Arguments[0].GetType()); var verifications = BootStrap.ResolveAll(specific); The input.Arguments[0] is an object of the type the generic is implemented in I also tried using typeof(IConfigurationVerification<) instead and get the same error . When ResolveAll is public static List<object> ResolveAll(Type t) { return myContainer.ResolveAll(t).ToList(); } I get a ResolutionFailedException with them message "The current type, Infrastructure.Interfaces.IConfigurationVerification`1[Infrastructure.Configuration.IMLogPlayerConfiguration+LoadDefinitions], is an interface and cannot be constructed. Are you missing a type mapping?" Any help will be great. Thanks in advance

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  • Java the little console game won't repeat?

    - by Jony Kale
    Okay, what I have so far is: You enter the game, and write "spin" to the console. Program will enter the while loop. In the while loop, if entered int is -1, return to the back (Set console input back to "", and let the user select what game he would like to play). Problem: Instead of going back, and selecting "spin" again, the program exits? Why is it happening? How can I fix this? private static Scanner console = new Scanner(System.in); private static Spin spin = new Spin(); private static String inputS = ""; private static int inputI = 0; private static String[] gamesArray = new String[] {"spin", "tof"}; private static boolean spinWheel = false; private static boolean tof = false; public static void main (String[] args) { if (inputS.equals("")) { System.out.println("Welcome to the system!"); System.out.print("Please select a game: "); inputS = console.nextLine(); } while (inputS.equals("spin")) { System.out.println("Welcome to the spin game! Please write 1 to spin. and -1 to exit back"); inputI = console.nextInt(); switch (inputI) { case 1: break; case -1: inputI = 0; inputS = ""; break; } } }

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  • Why wont this compile its killing me. (java)

    - by Ryan The Leach
    import java.util.*; public class Caesar { public static void main(String [] args) { final boolean DEBUG = false; System.out.println("Welcome to the Caesar Cypher"); System.out.println("----------------------------"); Scanner keyboard = new Scanner (System.in); System.out.print("Enter a String : "); String plainText = keyboard.nextLine(); System.out.print("Enter an offset: "); int offset = keyboard.nextInt(); String cipherText = ""; for(int i=0;i<plainText.length();i++) { int chVal = plainText.charAt(i); if (DEBUG) {int debugchVal = chVal;} chVal +=offset; if (DEBUG) {System.out.print(chVal + "\t");} while (chVal <32 || chVal > 127) { if (chVal < 32) chVal += 96; if (chVal > 127) chVal -= 96; if(DEBUG) {System.out.print(chVal+" ");} } if (DEBUG) {System.out.println();} char c = (char) chVal; cipherText = cipherText + c; if (DEBUG) {System.out.println(i + "\t" + debugchVal + "\t" + chVal + "\t" + c + "\t" + cipherText);} } System.out.println(cipherText); } }

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  • Returning the element number of the longest string in an array

    - by JohnRoberts
    I'm trying to get the longestS method to take the user-inputted array of strings, then return the element number of the longest string in that array. I got it to the point where I was able to return the number of chars in the longest string, but I don't believe that will work for what I need. My problem is that I keep getting incompatible type errors when trying to figure this out. I don't understand the whole data type thing with strings yet. It's confusing me how I go about return a number of the array yet the array is of strings. The main method is fine, I got stuck on the ???? part. { public static void main(String [] args) { Scanner inp = new Scanner( System.in ); String [] responseArr= new String[4]; for (int i=0; i<4; i++) { System.out.println("Enter string "+(i+1)); responseArr[i] = inp.nextLine(); } int highest=longestS(responseArr); } public static int longestS(String[] values) { int largest=0 for( int i = 1; i < values.length; i++ ) { if ( ????? ) } return largest; } }

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  • ArrayList<Int> Collections.Sort and LineNumberReader Help How to

    - by user1819551
    I have a issue i can't get it to work now let going to the point a explain in the code thanks. This is my class: what I want to do is insert the Integers sort the list and buffer writer in a column with out coma. Now I getting this: [1110018, 1110032, 1110056, 1110059, 1110063, 1110085, 1110096, 1110123, 1110125, 1110185, 1110456, 1110459] I want like this: 111xxxxx 111xxxx xxxx....... I can't do it in single array, have to be in ArrayList. This is my collecting: list.addNumbers(numbers); list.display(); This is my writer: Is buffered coma.write("\n"+list.display()); coma.flush();<br/> Here is my class: public class IdCount {<br/> private ArrayList<Integer> properNumber = new ArrayList<>(); public void addNumbers(Integer numbers) { properNumber.add(numbers); Collections.sort(properNumber); } public String display() { //(I try .toString() Not work) return properNumber.toString(); } My second issue is LineNumberReader: This is my collecting and my writing: try { Reader input = new BufferedReader( new FileReader(inputFile)); try (Scanner in = new Scanner(input)) { while (in.hasNext()) { //(More Code) asp = new LineNumberReader(input); int rom = 0; while (asp.readLine()!=null){ rom++; } System.out.println(rom); coma.write(rom); This one will not write anything an my System Print give me only 12 0 in column.

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  • How to create a list/structure? in JAVA

    - by lox
    i have to create a list of ,let's say 50 people, (in JAVA) and display the list, and i don't really know how to do that. so this is what i have tried to do so far . please correct and complete some of my code . public class Person { String name; String stuff; } public class CreatePerson { public static void ang() { ArrayList<Person> thing=new ArrayList<Person>(); Scanner diskScanner = new Scanner(in); for(int i=0; i<50; i++){ Person pers = new Person(); out.print("name: "); pers.name=diskScanner.nextLine(); out.print("stuff: "); pers.stuff=diskScanner.nextLine(); thing.add(pers); break; } // Display people for (int i=0; i<50; i++) { out.println(??);{ } } }}

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  • FileNotFoundException Java

    - by Troels Hansen
    Hi, I'm trying to make a simple highscore system for a minesweeper game. However i keep getting a file not found exception, and i've tried to use the full path for the file aswell. package minesweeper; import java.io.*; import java.util.*; public class Highscore{ public static void submitHighscore(String difficulty) throws IOException{ int easy = 99999; int normal = 99999; int hard = 99999; //int newScore = (int) MinesweeperView.getTime(); int newScore = 10; File f = new File("Highscores.dat"); if (!f.exists()){ f.createNewFile(); } Scanner input = new Scanner(f); PrintStream output = new PrintStream(f); if (input.hasNextInt()){ easy = input.nextInt(); normal = input.nextInt(); hard = input.nextInt(); } output.flush(); if(difficulty.equals("easy")){ if (easy > newScore){ easy = newScore; } }else if (difficulty.equals("normal")){ if (normal > newScore){ normal = newScore; } }else if (difficulty.equals("hard")){ if (hard > newScore){ hard = newScore; } } output.println(easy); output.println(normal); output.println(hard); } //temporary main method used for debugging public static void main(String[] args) throws IOException { submitHighscore("easy"); } }

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