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  • Samples of Scala and Java code where Scala code looks simpler/has less lines?

    - by Roman
    I need some code samples (and I also really curious about them) of Scala and Java code which show that Scala code is more simple and concise then code written in Java (of course both samples should solve the same problem). If there is only Scala sample with comment like "this is abstract factory in Scala, in Java it will look much more cumbersome" then this is also acceptable. Thanks!

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  • Python - alternative to list.remove(x)?

    - by Seafoid
    Hi, I wish to compare two lists. Generally this is not a problem as I usually use a nested for loop and append the intersection to a new list. In this case, I need to delete the intersection of A and B from A. A = [['ab', 'cd', 'ef', '0', '567'], ['ghy5'], ['pop', 'eye']] B = [['ab'], ['hi'], ['op'], ['ej']] My objective is to compare A and B and delete A intersection B from A, i.e., delete A[0][0] in this case. I tried: def match(): for i in A: for j in i: for k in B: for v in k: if j == v: A.remove(j) list.remove(x) throws a ValueError.

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  • how to compare the values inside a table in sql

    - by Ranjana
    how to compare the values of same table(say for eg: Order table) each and every time the record get inserted , if the record with same values get inserted already in same table i should not insert the new record with same values. how to do that exactly in sql server 2008

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  • What is the most efficient way to handle points / small vectors in JavaScript?

    - by Chris
    Currently I'm creating an web based (= JavaScript) application thata is using a lot of "points" (= small, fixed size vectors). There are basically two obvious ways of representing them: var pointA = [ xValue, yValue ]; and var pointB = { x: xValue, y: yValue }; So translating my point a bit would look like: var pointAtrans = [ pointA[0] + 3, pointA[1] + 4 ]; var pointBtrans = { x: pointB.x + 3, pointB.y + 4 }; Both are easy to handle from a programmer point of view (the object variant is a bit more readable, especially as I'm mostly dealing with 2D data, seldom with 3D and hardly with 4D - but never more. It'll allways fit into x,y,z and w) But my question is now: What is the most efficient way from the language perspective - theoretically and in real implementations? What are the memory requirements? What are the setup costs of an array vs. an object? ... My target browsers are FireFox and the Webkit based ones (Chromium, Safari), but it wouldn't hurt to have a great (= fast) experience under IE and Opera as well...

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  • Error comparing hash to hashed mysql password (output values are equal)

    - by Charlie
    Im trying to compare a hashed password value in a mysql database with the hashed value of an inputted password from a login form. However, when I compare the two values it says they aren't equal. I removed the salt to simply, and then tested what the outputs were and got the same values $password1 = $_POST['password']; $hash = hash('sha256', $password1); ...connect to database, etc... $query = "SELECT * FROM users WHERE username = '$username1'"; $result = mysql_query($query); $userData = mysql_fetch_array($result); if($hash != $userData['password']) //incorrect password { echo $hash."|".$userData['password']; die(); } ...other code... Sample output: 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361| 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361 Any thoughts?

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  • Finding whether a value is equal to the value of any array element in MATLAB

    - by James
    Hi, Can anyone tell me if there is a way (in MATLAB) to check whether a certain value is equal to any of the values stored within another array? The way I intend to use it is to check whether an element index in one matrix is equal to the values stored in another array (where the stored values are the indexes of the elements which meet a certain criteria). So, if the indices of the elements which meet the criteria are stored in the matrix below: criteriacheck = [3 5 6 8 20]; Going through the main array (called array) & checking if the index matches: for i = 1:numel(array) if i == 'Any value stored in criteriacheck' ... "Do this" end Does anyone have an idea of how I might go about this? Thanks in advance

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  • How to match words as if in a dictionary, based on len-1 or len+1? Python

    - by pearbear
    If I have a word 'raqd', how would I use python to have a spellcheck, so to speak, to find the word 'rad' as an option in 'spellcheck'? What I've been trying to do is this: def isbettermatch(keysplit, searchword): i = 0 trues = 0 falses = 0 lensearchwords = len(searchword) keysplits = copy.deepcopy(keysplit) searchwords = copy.deepcopy(searchword) #print keysplit, searchwords if len(keysplits) == len(searchwords)-1: i = 0 while i < len(keysplits): j = 0 while j < lensearchwords: if keysplits[i] == searchwords[j]: trues +=1 searchwords.pop(j) lensearchwords = len(searchwords) elif keysplits[i] != searchwords[j]: falses +=1 j +=1 i +=1 if trues >= len(searchwords)-1: #print "-------------------------------------------------------", keysplits return True keysplit is a list like ['s', 'p', 'o', 'i', 'l'] for example, and the searchword would be a list ['r', 'a', 'q', 'd']. If the function returns True, then it would print the keyword that matches. Ex. 'rad', for the searchword 'raqd'. I need to find all possible matches for the searchword with a single letter addition or deletion. so ex. 'raqd' would have an option to be 'rad', and 'poted' could be 'posted' or 'potted'. Above is what I have tried, but it is not working well at all. Help much appreciated!

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  • Regex vs. string:find() for simple word boundary

    - by user576267
    Say I only need to find out whether a line read from a file contains a word from a finite set of words. One way of doing this is to use a regex like this: .*\y(good|better|best)\y.* Another way of accomplishing this is using a pseudo code like this: if ( (readLine.find("good") != string::npos) || (readLine.find("better") != string::npos) || (readLine.find("best") != string::npos) ) { // line contains a word from a finite set of words. } Which way will have better performance? (i.e. speed and CPU utilization)

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  • Comparing arrays with sql

    - by Nissim
    I want to perform a 'SELECT' statement with a byte array (binary) parameter as a condition. I tried to google it, but didn't find anything useful. In general, I keep information of files in the database. one of the properties is the file's hash (binary). I want to give a hash to the SELECT statement, and get all rows with the same hash value.

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  • Quickest way to compute the number of shared elements between two vectors

    - by shn
    Suppose I have two vectors of the same size vector< pair<float, NodeDataID> > v1, v2; I want to compute how many elements from both v1 and v2 have the same NodeDataID. For example if v1 = {<3.7, 22>, <2.22, 64>, <1.9, 29>, <0.8, 7>}, and v2 = {<1.66, 7>, <0.03, 9>, <5.65, 64>, <4.9, 11>}, then I want to return 2 because there are two elements from v1 and v2 that share the same NodeDataIDs: 7 and 64. What is the quickest way to do that in C++ ? Just for information, note that the type NodeDataIDs is defined as I use boost as: typedef adjacency_list<setS, setS, undirectedS, NodeData, EdgeData> myGraph; typedef myGraph::vertex_descriptor NodeDataID; But it is not important since we can compare two NodeDataID using the operator == (that is, possible to do v1[i].second == v2[j].second)

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  • Perl check for the existence of a value in a regular array

    - by Mel
    I am trying to figure out a way of checking for the existence of a value in an array without iterating through the array. I am reading a file for a parameter. I have a long list of parameters I do not want to deal with. I placed these unwanted parameters in an array @badparams I want to read a new parameter and if it does not exist in @badparams, process it. If it does exist in @badparams, go to the next read.

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  • Comparing the values of two nsstrings

    - by user1776234
    So I have been trying to compare two NSStrings in xcode. However, it is not working. What am I doing wrong? NSString Prog are characters that are xml parsed from mysql char *cStr = "YES"; NSString *str3 = [NSString stringWithUTF8String:cStr]; if ([str3 isEqualToString:prog]) { [switch1 setOn:YES animated:YES]; } else { [switch1 setOn:NO animated:YES]; }

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  • How much does precomputation (matching a series of strings and their permutations with a set number

    - by nipun
    Consider a typical slots machine with n reels(say reel1: a,b,c,d,w1,d,b, ..etc). On play we generate a concatenated string of n objects (like for above, chars) We have a paytable which lists winning strings with payout amounts. The problem is a wild character (list of wilds: w1,w2) which can replace {w1:a,b,c},{w2:a} ..etc. Is it really worthwhile to have all possible winning strings permutations with the wilds precomputed and used or simply at the time of occurance, generate all combinations with the pattern in hand accordingly. I did'nt really see much difference initially, but now if I need to scale the machine to handle 11+ reels with a much higher concentration of wilds than previously, I need to figure out the exact approach for this particular bit. Any ideas will be really appreciated :)

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  • How common are power supply failures in comparison to hard disk failures?

    - by Adrian Grigore
    Hi, My webhost offers two different types of high availability options for dedicated servers: Redundant hard disks (RAID1) Redundant hard disks (RAID1) plus redundant power supply How common is a power supply failure in comparison to hard disk failure? I know it's not possible to know the exact figures without knowing the exact hardware, but ballpark figures are good enough for me at the moment. Thanks, Adrian

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  • define macro in C wont work

    - by Spidfire
    Im trying to make a macro in C that can tell if a char is a hex number ( 0-9 a-z A-Z) #define _hex(x) (((x) >= "0" && (x) <= "9" )||( (x) >= "a" && (x) <= "z") || ((x) >= "A" && (x) <= "Z") ? "true" : "false") this what ive come up with but it wont work with a loop like this char a; for(a = "a" ; a < "z";a++){ printf("%s => %s",a, _hex(a)); } but it gives a error test.c:8: warning: assignment makes integer from pointer without a cast test.c:8: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer test.c:9: warning: comparison between pointer and integer

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  • Cost Comparison Hard Disk Drive to Solid State Drive on Price per Gigabyte - dispelling a myth!

    - by tonyrogerson
    It is often said that Hard Disk Drive storage is significantly cheaper per GiByte than Solid State Devices – this is wholly inaccurate within the database space. People need to look at the cost of the complete solution and not just a single component part in isolation to what is really required to meet the business requirement. Buying a single Hitachi Ultrastar 600GB 3.5” SAS 15Krpm hard disk drive will cost approximately £239.60 (http://scan.co.uk, 22nd March 2012) compared to an OCZ 600GB Z-Drive R4 CM84 PCIe costing £2,316.54 (http://scan.co.uk, 22nd March 2012); I’ve not included FusionIO ioDrive because there is no public pricing available for it – something I never understand and personally when companies do this I immediately think what are they hiding, luckily in FusionIO’s case the product is proven though is expensive compared to OCZ enterprise offerings. On the face of it the single 15Krpm hard disk has a price per GB of £0.39, the SSD £3.86; this is what you will see in the press and this is what sales people will use in comparing the two technologies – do not be fooled by this bullshit people! What is the requirement? The requirement is the database will have a static size of 400GB kept static through archiving so growth and trim will balance the database size, the client requires resilience, there will be several hundred call centre staff querying the database where queries will read a small amount of data but there will be no hot spot in the data so the randomness will come across the entire 400GB of the database, estimates predict that the IOps required will be approximately 4,000IOps at peak times, because it’s a call centre system the IO latency is important and must remain below 5ms per IO. The balance between read and write is 70% read, 30% write. The requirement is now defined and we have three of the most important pieces of the puzzle – space required, estimated IOps and maximum latency per IO. Something to consider with regard SQL Server; write activity requires synchronous IO to the storage media specifically the transaction log; that means the write thread will wait until the IO is completed and hardened off until the thread can continue execution, the requirement has stated that 30% of the system activity will be write so we can expect a high amount of synchronous activity. The hardware solution needs to be defined; two possible solutions: hard disk or solid state based; the real question now is how many hard disks are required to achieve the IO throughput, the latency and resilience, ditto for the solid state. Hard Drive solution On a test on an HP DL380, P410i controller using IOMeter against a single 15Krpm 146GB SAS drive, the throughput given on a transfer size of 8KiB against a 40GiB file on a freshly formatted disk where the partition is the only partition on the disk thus the 40GiB file is on the outer edge of the drive so more sectors can be read before head movement is required: For 100% sequential IO at a queue depth of 16 with 8 worker threads 43,537 IOps at an average latency of 2.93ms (340 MiB/s), for 100% random IO at the same queue depth and worker threads 3,733 IOps at an average latency of 34.06ms (34 MiB/s). The same test was done on the same disk but the test file was 130GiB: For 100% sequential IO at a queue depth of 16 with 8 worker threads 43,537 IOps at an average latency of 2.93ms (340 MiB/s), for 100% random IO at the same queue depth and worker threads 528 IOps at an average latency of 217.49ms (4 MiB/s). From the result it is clear random performance gets worse as the disk fills up – I’m currently writing an article on short stroking which will cover this in detail. Given the work load is random in nature looking at the random performance of the single drive when only 40 GiB of the 146 GB is used gives near the IOps required but the latency is way out. Luckily I have tested 6 x 15Krpm 146GB SAS 15Krpm drives in a RAID 0 using the same test methodology, for the same test above on a 130 GiB for each drive added the performance boost is near linear, for each drive added throughput goes up by 5 MiB/sec, IOps by 700 IOps and latency reducing nearly 50% per drive added (172 ms, 94 ms, 65 ms, 47 ms, 37 ms, 30 ms). This is because the same 130GiB is spread out more as you add drives 130 / 1, 130 / 2, 130 / 3 etc. so implicit short stroking is occurring because there is less file on each drive so less head movement required. The best latency is still 30 ms but we have the IOps required now, but that’s on a 130GiB file and not the 400GiB we need. Some reality check here: a) the drive randomness is more likely to be 50/50 and not a full 100% but the above has highlighted the effect randomness has on the drive and the more a drive fills with data the worse the effect. For argument sake let us assume that for the given workload we need 8 disks to do the job, for resilience reasons we will need 16 because we need to RAID 1+0 them in order to get the throughput and the resilience, RAID 5 would degrade performance. Cost for hard drives: 16 x £239.60 = £3,833.60 For the hard drives we will need disk controllers and a separate external disk array because the likelihood is that the server itself won’t take the drives, a quick spec off DELL for a PowerVault MD1220 which gives the dual pathing with 16 disks 146GB 15Krpm 2.5” disks is priced at £7,438.00, note its probably more once we had two controller cards to sit in the server in, racking etc. Minimum cost taking the DELL quote as an example is therefore: {Cost of Hardware} / {Storage Required} £7,438.60 / 400 = £18.595 per GB £18.59 per GiB is a far cry from the £0.39 we had been told by the salesman and the myth. Yes, the storage array is composed of 16 x 146 disks in RAID 10 (therefore 8 usable) giving an effective usable storage availability of 1168GB but the actual storage requirement is only 400 and the extra disks have had to be purchased to get the  IOps up. Solid State Drive solution A single card significantly exceeds the IOps and latency required, for resilience two will be required. ( £2,316.54 * 2 ) / 400 = £11.58 per GB With the SSD solution only two PCIe sockets are required, no external disk units, no additional controllers, no redundant controllers etc. Conclusion I hope by showing you an example that the myth that hard disk drives are cheaper per GiB than Solid State has now been dispelled - £11.58 per GB for SSD compared to £18.59 for Hard Disk. I’ve not even touched on the running costs, compare the costs of running 18 hard disks, that’s a lot of heat and power compared to two PCIe cards!Just a quick note: I've left a fair amount of information out due to this being a blog! If in doubt, email me :)I'll also deal with the myth that SSD's wear out at a later date as well - that's just way over done still, yes, 5 years ago, but now - no.

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  • New iPad vs. iPad 2–Side by side comparison of hardware specification [Infographic]

    - by Gopinath
    Apple released the 3rd generation of iPad on March 7th with spectacular hardware and software specs. The new iPad is the most advanced tablet available in the market with not much of competition. The closest competitor to the new iPad is not from Android or RIM or Amazon as they are no where close to the standards of the new iPad . But the competitor is none other than previous generation of iPad 2. In order to help you decide which Apple tablet suits your requirements here is an infographic comparing the iPad  with iPad 2

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