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  • Pass errors in Django using HttpResponseRedirect

    - by JPC
    I know that HttpResponseRedirect only takes one parameter, a URL. But there are cases when I want to redirect with an error message to display. I was reading this post: How to pass information using an http redirect (in Django) and there were a lot of good suggestions. I don't really want to use a library that I don't know how works. I don't want to rely on messages which, according to the Django docs, is going to be removed. I thought about using sessions. I also like the idea of passing it in a URL, something like: return HttpResponseRedirect('/someurl/?error=1') and then having some map from error code to message. Is it good practice to have a global map-like structure which hard codes in these error messages or is there a better way? Or should I just use a session EDIT: I got it working using a session. Is that a good practice to put things like this in the session?

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  • Django refresh page if change data by other user

    - by Fran Sobrino
    I have a test django app. In one page the test show the same question to all users. I'd like that when a user answers correctly, send a signal to other active user's browser to refresh to the next question. I have been learning about signals in django I learning work with them but I don't now how send the "refresh signal" to client browser. I think that it can do with a javascript code that check if a certain value (actual question) change and if change reload the page but I don't know this language and the information that I find was confused. Can anybody help me? Many Thanks.

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  • app_label in an abstract Django model

    - by rayan
    Hi all, I'm trying to get an abstract model working in Django and I hit a brick wall trying to set the related_name per the recommendation here: http://docs.djangoproject.com/en/dev/topics/db/models/#be-careful-with-related-name This is what my abstract model looks like: class CommonModel(models.Model): created_on = models.DateTimeField(editable=False) creared_by = models.ForeignKey(User, related_name="%(app_label)s_%(class)s_created", editable=False) updated_on = models.DateTimeField(editable=False) updated_by = models.ForeignKey(User, related_name="%(app_label)s_%(class)s_updated", editable=False) def save(self): if not self.id: self.created_on = datetime.now() self.created_by = user.id self.updated_on = datetime.now() self.updated_by = user.id super(CommonModel, self).save() class Meta: abstract = True My common model is in [project_root]/models.py. It is the parent object of this model, which is located in an app called Feedback [project_root]/feedback/models.py: from django.db import models from mediasharks.models import CommonModel class Feedback(CommonModel): message = models.CharField(max_length=255) request_uri = models.CharField(max_length=255) domain = models.CharField(max_length=255) feedback_type = models.IntegerField() Basically I'm trying to set up a common model so that I'll always be able to tell when and by whom database entries were created. When I run "python manage.py validate" I get this error message: KeyError: 'app_label' Am I missing something here?

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  • Django startup importing causes reverse to happen

    - by nicknack
    This might be an isolated problem, but figured I'd ask in case someone has thoughts on a graceful approach to address it. Here's the setup: -------- views.py -------- from django.http import HttpResponse import shortcuts def mood_dispatcher(request): mood = magic_function_to_guess_my_mood(request) return HttpResponse('Please go to %s' % shortcuts.MOODS.get(mood, somedefault)) ------------ shortcuts.py ------------ MOODS = # expensive load that causes a reverse to happen The issue is that shortcuts.py causes an exception to be thrown when a reverse is attempted before django is done building the urls. However, views.py doesn't yet need to import shortcuts.py (used only when mood_dispatcher is actually called). Obvious initial solutions are: 1) Import shortcuts inline (just not very nice stylistically) 2) Make shortcuts.py build MOODS lazily (just more work) What I ideally would like is to be able to say, at the top of views.py, "import shortcuts except when loading urls"

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  • Django - how to make ImageField/FileField optional?

    - by ilya
    class Product(models.Model): ... image = models.ImageField(upload_to = generate_filename, blank = True) When I use ImageField (blank=True) and do not select image into admin form, exception occures. In django code you can see this: class FieldFile(File): .... def _require_file(self): if not self: raise ValueError("The '%s' attribute has no file associated with it." % self.field.name) def _get_file(self): self._require_file() ... Django trac has ticket #13327 about this problem, but seems it can't be fixed soon. How to make these field optional?

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  • Django: Data corrupted after loading? (possible programmer error)

    - by Rosarch
    I may be loading data the wrong way. excerpt of data.json: { "pk": "1", "model": "myapp.Course", "fields": { "name": "Introduction to Web Design", "requiredFor": [9], "offeringSchool": 1, "pre_reqs": [], "offeredIn": [1, 5, 9] } }, I run python manage.py loaddata -v2 data: Installed 36 object(s) from 1 fixture(s) Then, I go to check the above object using the Django shell: >>> info = Course.objects.filter(id=1) >>> info.get().pre_reqs.all() [<Course: Intermediate Web Programming>] # WRONG! There should be no pre-reqs >>> from django.core import serializers >>> serializers.serialize("json", info) '[{"pk": 1, "model": "Apollo.course", "fields": {"pre_reqs": [11], "offeredIn": [1, 5, 9], "offeringSchool": 1, "name": "Introduction to Web Design", "requiredFor": [9]}}]' The serialized output of the model is not the same as the input that was given to loaddata. The output has a non-empty pre_req list, whereas the input's pre_reqs field is empty. What am I doing wrong?

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  • Sorting related objects in the Django Admin form interface

    - by Carver
    I am looking to sort the related objects that show up when editing an object using the admin form. So for example, I would like to take the following object: class Person(models.Model): first_name = models.CharField( ... ) last_name = models.CharField( ... ) hero = models.ForeignKey( 'self', null=True, blank=True ) and edit the first name, last name and hero using the admin interface. I want to sort the objects as they show up in the drop down by last name, first name (ascending). How do I do that? Context I'm using Django v1.1. I started by looking for help in the django admin docs, but didn't find the solution As you can see in the example, the foreign key is pointing to itself, but I expect it would be the same as pointing to a different model object. Bonus points for being able to filter the related objects, too (eg~ only allow selecting a hero with the same first name)

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  • Django 1.2: Dates in admin forms don't work with Locales (I10N=True)

    - by equalium
    I have an application in Django 1.2. Language is selectable (I18N and Locale = True) When I select the english lang. in the site, the admin works OK. But when I change to any other language this is what happens with date inputs (spanish example): Correctly, the input accepts the spanish format %d/%m/%Y (Even selecting from the calendar, the date inserts as expected). But when I save the form and load it again, the date shows in the english form: %Y-%m-%d The real problem is that when I load the form to change any other text field and try to save it I get an error telling me to enter a valid date, so I have to write all dates again or change the language in the site to use the admin. I haven't specified anything for DATE_INPUT_FORMATS in settings nor have I overridden forms or models. Surely I am missing something but I can't find it. Can anybody give me a hint?

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  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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  • Getting a KeyError in DB backend of django-digest

    - by rtmie
    I have just started to integrate django_digest into my app. As a start I have added the @httpdigest decorator to one of my views. If I try to connect to it I get a KeyError exception thrown in django_digest/backend/db.py . Depending on which db I configure I get a different KeyError in a different location. I am using Django 1.2.1, with MySql (also tested with sqlite). I am using the default values for all the settings options. As far as I can see I have followed all instructions but am struggling all day with this. I am using the repository versions of django-digest and python-digest. Any steer would be greatly appreciated. Tracebacks for sqlite and mysql below: with sqlite: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 248, in __call__ signals.request_finished.send(sender=self.__class__) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/dispatch/dispatcher.py", line 162, in send response = receiver(signal=self, sender=sender, **named) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 16, in close_connection _connection.close() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 186, in close if self.settings_dict['NAME'] != ":memory:": KeyError: 'NAME' with mysql: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 142, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 166, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 80, in get_response response = middleware_method(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/middleware.py", line 13, in process_request if (not self._authenticator.authenticate(request) and File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/__init__.py", line 86, in authenticate partial_digest = self._account_storage.get_partial_digest(digest_response.username) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 97, in get_partial_digest cursor = get_connection().cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/__init__.py", line 75, in cursor cursor = self._cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/mysql/base.py", line 281, in _cursor if settings_dict['USER']: KeyError: 'USER'

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  • Google App Engine with local Django 1.1 gets Intermittent Failures

    - by Jon Watte
    I'm using the Windows Launcher development environment for Google App Engine. I have downloaded Django 1.1.2 source, and un-tarrred the "django" subdirectory to live within my application directory (a peer of app.yaml) At the top of each .py source file, I do this: import settings import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' In my file settings.py (which lives at the root of the app directory, as well), I do this: DEBUG = True TEMPLATE_DIRS = ('html') INSTALLED_APPS = ('filters') import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' from google.appengine.dist import use_library use_library('django', '1.1') from django.template import loader Yes, this looks a bit like overkill, doesn't it? I only use django.template. I don't explicitly use any other part of django. However, intermittently I get one of two errors: 1) Django complains that DJANGO_SETTINGS_MODULE is not defined. 2) Django complains that common.html (a template I'm extending in other templates) doesn't exist. 95% of the time, these errors are not encountered, and they randomly just start happening. Once in that state, the local server seems "wedged" and re-booting it generally fixes it. What's causing this to happen, and what can I do about it? How can I even debug it? Here is the traceback from the error: Traceback (most recent call last): File "C:\code\kwbudget\edit_budget.py", line 34, in get self.response.out.write(t.render(template.Context(values))) File "C:\code\kwbudget\django\template\__init__.py", line 165, in render return self.nodelist.render(context) File "C:\code\kwbudget\django\template\__init__.py", line 784, in render bits.append(self.render_node(node, context)) File "C:\code\kwbudget\django\template\__init__.py", line 797, in render_node return node.render(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 71, in render compiled_parent = self.get_parent(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 66, in get_parent raise TemplateSyntaxError, "Template %r cannot be extended, because it doesn't exist" % parent TemplateSyntaxError: Template u'common.html' cannot be extended, because it doesn't exist And edit_budget.py starts with exactly the lines that I included up top. All templates live in a directory named "html" in my root directory, and "html/common.html" exists. I know the template engine finds them, because I start out with "html/edit_budget.html" which extends common.html. It looks as if the settings module somehow isn't applied (because that's what adds html to the search path for templates).

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  • How can I disable a model field in a django form

    - by jammon
    I have a model like this: class MyModel(models.Model): REGULAR = 1 PREMIUM = 2 STATUS_CHOICES = ((REGULAR, "regular"), (PREMIUM, "premium")) name = models.CharField(max_length=30) status = models.IntegerField(choices = STATUS_CHOICES, default = REGULAR) class MyForm(forms.ModelForm): class Meta: model = models.MyModel In a view I initialize one field and try to make it non-editable: myform = MyForm(initial = {'status': requested_status}) myform.fields['status'].editable = False But the user can still change that field. What's the real way to accomplish what I'm after?

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • django & postgres linux hosting (with SSH access) recommendations

    - by Justin Grant
    We're looking for a good place to host our custom Django app (a fork of OSQA) and its postgresql backend. Requirements include: Linux Python 2.6 or (ideally) Python 2.7 Django 1.2 Postgres 8.4 or later DB backup/restore handled by the hoster, not us OS & dev-platform-stack patching/maintenance handled by the hoster, not us SSH access (so we can pull source code from GitHub, so we can install python eggs, etc.) ability to set up cron jobs (e.g. to send out dail email updates) ability to send up to 10K emails/day good performance (not ganged up with a zillion other sites on one CPU, not starved for RAM) FTP or SCP access to web logs dedicated public IP SSL support Costs under $1000/month for a relatively small site (<5M pageviews/month) Good customer service We already have a prototype site running on EC2 on top of a Bitnami DjangoStack. The problem is that we have to patch the OS, patch postgres, etc. We'd really prefer a platform-as-a-service (PaaS) offering, like Heroku offers for Rails apps, where all we need to worry about is deploying our code instead of worrying about system software patching and maintenance. Google App Engine is closest to what we're looking for, but they don't offer relational DB access (not yet at least). Anyone have a recommendation?

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  • Django running on Apache+WSGI and apache SSL proxying

    - by Lessfoe
    Hi all, I'm trying to rewrite all requests for my Django server running on apache+WSGI ( inside my local network) and configured as the WSGI's wiki how to, except that I set a virtualhost for it. The server which from I want to rewrite requests is another apache server listening on port 80. I can manage it to work well if I don't try to enable SSL connection as the required way to connect. But I need all requests to Django server encrypted with SSL so I generally used this directive to achieve this ( on my public webserver ): Alias /dirname "/var/www/dirname" SSLVerifyClient none SSLOptions +FakeBasicAuth SSLRequireSSL AuthName "stuff name" AuthType Basic AuthUserFile /etc/httpd/djangoserver.passwd require valid-user # redirect all request to django.test:80 RewriteEngine On RewriteRule (.*)$ http://django.test/$1 [P] This configuration works if I try to load a specific page trough the external server from my browser. It is not working clicking my django application urls ( even tough the url seems correct when I put my mouse over). The url my public server is trying to serve use http ( instead of https ) and the directory "dirname" I specified on my apache configuration disappear, so it says that the page was not found. I think it depends on Django and its WSGI handler . Does anybody went trough my same problem? PS: I have already tried to modify the WSGI script . I'm Using Django 1.0.3, Apache 2.2 on a Fedora10 (inside), Apache 2.2 on the public server. Thanks in advance for your help. Fab

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  • 'NoneType' object has no attribute 'day'

    - by Asinox
    Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, thanks guys sorry with my English

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  • django model Form. Include fields from related models

    - by Tom
    Hi. I have a model, called Student, which has some fields, and a OneToOne relationship with user (django.contrib.auth.User). class Student(models.Model): phone = models.CharField(max_length = 25 ) birthdate = models.DateField(null=True) gender = models.CharField(max_length=1,choices = GENDER_CHOICES) city = models.CharField(max_length = 50) personalInfo = models.TextField() user = models.OneToOneField(User,unique=True) Then, I have a ModelForm for that model class StudentForm (forms.ModelForm): class Meta: model = Student Using the fields attribute in class Meta, i've managed to show only some fields in a template. However, can I indicate which user fields to show? Something as: fields =('personalInfo','user.username') is currently not showing anything. Works with only StudentFields though/ Thanks in advance.

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  • Django file uploads - Just can't work it out

    - by phoebebright
    OK I give up - after 5 solid hours trying to get a django form to upload a file, I've checked out all the links in stackoverflow and googled and googled. Why is it so hard, I just want it to work like the admin file upload? So I get that I need code like: if submitForm.is_valid(): handle_uploaded_file(request.FILES['attachment']) obj = submitForm.save() and I can see my file in request.FILES['attachment'] (yes I have enctype set) but what am I supposed to do in handle_uploaded_file? The examples all have a fixed file name but obviously I want to upload the file to the directory I defined in the model, but I can't see where I can find that. def handle_uploaded_file(f): destination = open('fyi.xml', 'wb+') for chunk in f.chunks(): destination.write(chunk) destination.close() Bet I'm going to feel really stupid when someone points out the obvious!

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  • Django database caching

    - by hekevintran
    I have a Django form that uses an integer field to lookup a model object by its primary key. The form has a save() method that uses the model object referred to by the integer field. The model's manager's get() method is called twice, once in the clean method and once in the save() method: class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is the first call to get MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): id_a = self.cleaned_data['id_a'] # here is the second call to get my_model_object = MyModel.objects.get(id=id_a) # do other stuff I wasn't sure whether this hits the database two times or one time so I returned the object itself in the clean method so that I could avoid a second get() call. Does calling get() hit the database two times? Or is the object cached in the thread? class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is my workaround return MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): # looking up the cleaned value returns the model object my_model_object = self.cleaned_data['id_a'] # do other stuff

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  • Datastore query outputting for Django form instance

    - by Jelle
    Hello! I'm using google appengine and Django. I'm using de djangoforms module and wanted to specify the form instance with the information that comes from the query below. userquery = db.GqlQuery("SELECT * FROM User WHERE googleaccount = :1", users.get_current_user()) form = forms.AccountForm(data=request.POST or None,instance=?????) I've found a snippet in a sample app that does this trick, but I can't modify it to work with the query I need. gift = User.get(db.Key.from_path(User.kind(), int(gift_id))) if gift is None: return http.HttpResponseNotFound('No gift exists with that key (%r)' % gift_id) form = RegisterForm(data=request.POST or None, instance=gift) Could anyone help me?

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  • (Django) Trim whitespaces from charField

    - by zardon
    How do I strip whitespaces (trim) from the end of a charField in Django? Here is my Model, as you can see I've tried putting in clean methods but these never get run. I've also tried doing name.strip(), models.charField().strip() but these do not work either. Is there a way to force the charField to trim automatically for me? Thanks. class Employee(models.Model): """(Workers, Staff, etc)""" name = models.CharField(blank=True, null=True, max_length=100) # This never gets run def clean_variable(self): data = self.cleaned_data['variable'].strip() return data def __unicode__(self): return self.name class Meta: verbose_name_plural = 'Employees' # This never gets run either class EmployeesForm(forms.ModelForm): class Meta: model = Employee def clean_description(self): #if not self.cleaned_data['description'].strip(): # raise forms.ValidationError('Your error message here') self.cleaned_data['name'].strip()

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  • Override Django inlineformset_factory has_changed() to always return True

    - by John
    Hi, I am using the django inlineformset_factory function. a = get_object_or_404(ModelA, pk=id) FormSet = inlineformset_factory(ModelA, ModelB) if request.method == 'POST': metaform = FormSet (instance=a, data=request.POST) if metaform.is_valid(): f = metaform.save(commit=False) for instance in f: instance.updated_by = request.user instance.save() else: metaform = FormSet(instance=a) return render_to_response('nodes/form.html', {'form':metaform}) What is happening is that if I change any of the data then everything works ok and all the data gets updated. However if I don't change any of the data then the data is not updated. i.e. only entries which are changed go through the for loop to be saved. I guess this makes sense as there is no point saving data if it has not changed. However I need to go through and save every object in the form regardless of whether it has any changes on not. So my question is how do I override this so that it goes through and saves every record whether it has any changes or not? Hope this makes sense Thanks

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • django forms overwrite data when saved

    - by dana
    If a have a form, with the data from a user, let's say a CV, and i save the data from the form into a database, but i don't want that a CV from the same user to be stored in the database more than once(when edited form instance) I want it to be overwritten every time it is saved by one same user. How can i do it? thanks a lot

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