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• Keyboard problem with ubuntu 13.10 when holding key down

  - by Lachezar Raychev

  I have the fallowing problem after isntalling the new Ubuntu OS. When i press and hold a key, for example "p" it writes one time "p", and while i am holding it the other "pppp" that are written come with a huge delay between each other - like 1 second or more. If i want to hold down backspace to delete a string of 5 letters it takes me like 10 seconds to do it. Is this a reported problem or does anybody has a solution to this problem?

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• Update app.config key value at run time in WPF

  In this article I am going to show how we can update a key value in app.config file in WPF. For this add reference of System.Configuration in your application.

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• host key verification failed from "connect to server" utility

  - by rambo

  I am able to use SSH from terminal but I am not able to use it from "connect to Server.." utility. it is showing the error in the dialog box as below: Cannot display location "sftp://[email protected]:PORT/ "Host key verification failed" why so? from terminal using below command I am able to access the server: ubuntu# ssh -p 2222 [email protected] Description: Ubuntu 10.04.4 LTS Release: 10.04 Codename: lucid any help please. thank you in advance.

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• The Ultimate Key to Success in Search Engine Optimization

  Most of us seem to be under the impression that the only key to success in search engine optimization is building tons of inbound links. And there is no denying that inbound links do play a very important role in determining how well your pages ultimately rank. In fact, most search-engines won't index a page that doesn't have a link from a page they have already indexed.

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• ssh key error - Permission denied (publickey,gssapi-keyex,gssapi-with-mic)

  - by user1963938

  Amazon Ec2 :: Redhat 6. 64 Bit I'm trying to follow the socks5 guidelines (http://www.catonmat.net/blog/linux-socks5-proxy/ ) to open a socks on one of our servers but unfortunately I got suck at step 1 . ssh -N -D 0.0.0.0:1080 localhost I get error Permission denied (publickey,gssapi-keyex,gssapi-with-mic). How do I fix it ? More debug info ssh -v -f -N -D 0.0.0.0:1080 localhost OpenSSH_5.3p1, OpenSSL 1.0.0-fips 29 Mar 2010 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to localhost [127.0.0.1] port 22. debug1: Connection established. debug1: permanently_set_uid: 0/0 debug1: identity file /root/.ssh/identity type -1 debug1: identity file /root/.ssh/id_rsa type -1 debug1: identity file /root/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3 debug1: match: OpenSSH_5.3 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.3 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'localhost' is known and matches the RSA host key. debug1: Found key in /root/.ssh/known_hosts:1 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic debug1: Next authentication method: gssapi-keyex debug1: No valid Key exchange context debug1: Next authentication method: gssapi-with-mic debug1: Unspecified GSS failure. Minor code may provide more information Credentials cache file '/tmp/krb5cc_0' not found debug1: Unspecified GSS failure. Minor code may provide more information Credentials cache file '/tmp/krb5cc_0' not found debug1: Unspecified GSS failure. Minor code may provide more information debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Trying private key: /root/.ssh/identity debug1: Trying private key: /root/.ssh/id_rsa debug1: Trying private key: /root/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey,gssapi-keyex,gssapi-with-mic).

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• Windows Vista claims wireless key is the wrong length

  - by humble coffee

  A family member of mine is house sitting and has been given the details of their wifi. The access point is an Airport Express, it has WEP encryption (I think) and they've been given a passphrase to use. I know it's a passphrase and not the encrypted key as it's an English word. The passphrase is 10 characters long. The problem is that Vista complains that it's not a valid key as it must be a 5 or 13 character non-hex key or a 10 or 26 character hex key. (From what I've read this suggests the encryption is WEP?) I've found a couple of suggested solutions, but I'm not actually at the house at the moment so I wanted to make sure I have a good chance of getting it to work when I'm there but have no internets to ask. Solution 1: Vista needs to be told explicitly what kind of encryption and key is being used. Specify in the connection settings that you are using WEP and that it is a "shared key". Solution2: Try converting the passphrase to hexadecimal using an ASCII-hex converter and entering that.

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• Can SSH into remote server but can't SCP?

  - by ArtfulDodger2012

  I can SSH into remote server just fine using private key authentication with prompt for passphrase. However I'm getting permission denied when I try to SCP a file using the same passphrase. Here's my output: $ scp -v [file] [user]@[remoteserver.com]:/home/[my dir] Executing: program /usr/bin/ssh host [remoteserver.com], user [user], command scp -v -t /home/[my dir] OpenSSH_5.3p1 Debian-3ubuntu7, OpenSSL 0.9.8k 25 Mar 2009 debug1: Reading configuration data /home/[my dir].ssh/config debug1: Applying options for [remoteserver.com] debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to [remoteserver.com] [[remoteserver.com]] port 22. debug1: Connection established. debug1: identity file /home/[user]/.ssh/aws_corp type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3p1 Debian-3ubuntu7 debug1: match: OpenSSH_5.3p1 Debian-3ubuntu7 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.3p1 Debian-3ubuntu7 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host '[remoteserver.com]' is known and matches the RSA host key. debug1: Found key in /home/[my dir]/.ssh/known_hosts:12 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Trying private key: /home/[my dir]/.ssh/aws_corp debug1: PEM_read_PrivateKey failed debug1: read PEM private key done: type <unknown> Enter passphrase for key '/home/[my dir]/.ssh/aws_corp': debug1: read PEM private key done: type RSA Connection closed by [remote server] lost connection I've searched for answers but can't find quite the same problem or am just being thick. Either way any help is much appreciated. Cheers!

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• How to disable the alt-hotkey behavior on gnome terminal?

  - by farleyknight

  This is not just gnome terminal, but pretty much all gnome windows: When you hold the "alt" key, you can press the first letter of one of the menu items. This will let you scroll that menu without clicking on it directly. This is okay on any other window, like say Firefox, but on gnome terminal, it steals the keys I use for emacs!! There is very little chance of me learning a new set key combinations if I can avoid. If I can't isolate this just to gnome terminal, I'm fine with that.

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• iPhone OS: Why is my managedModelObject not complying with Key Value Coding?

  - by nickthedude

  Ok so I'm trying to build this stat tracker for my app and I have built a data model object called statTracker that keeps track of all the stuff I want it to. I can set and retrieve values using the selectors, but if I try and use KVC (ie setValue: forKey: ) everything goes bad and says my StatTracker class is not KVC compliant: valueForUndefinedKey:]: the entity StatTracker is not key value coding-compliant for the key "timesLauched".' 2010-05-18 15:55:08.573 here's the code that is triggering it: NSArray *statTrackerArray = [[NSArray alloc] init]; statTrackerArray = [[CoreDataSingleton sharedCoreDataSingleton] getStatTracker]; NSNumber *number1 = [[NSNumber alloc] init]; number1 = [NSNumber numberWithInt:(1 + [[(StatTracker *)[statTrackerArray objectAtIndex:0] valueForKey:@"timesLauched"] intValue])]; [(StatTracker *)[statTrackerArray objectAtIndex:0] setValue:number1 forKey:@"timesLaunched" ]; NSError *error; if (![[[CoreDataSingleton sharedCoreDataSingleton] managedObjectContext] save:&error]) { NSLog(@"error writing to db"); } Not sure if this is enough code for you folks let me know what you need if you do need more. This would be so sweet if I could use KVC because I could then abstract all this stat tracking stuff into a single method call with a string argument for the value in question. At least that is what I hope to accomplish here. I'm actually now understanding the power of KVC but now I'm just trying to figure out how to make it work. Thanks! Nick

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• Unlock all private keys on Ubuntu, entering password only once at login

  - by conradlee

  I login to Ubuntu 12.04 using a password. Later on, when I use my browser(Chrome), I'm asked for a password to unlock the keychain so that the browser can access my saved credentials for various websites (it's the same password). Also, whenever I use SSH to connect to other computers using my private key, I am prompted for the same password to unlock my private key. How can I make it so that I am asked for my password exactly once per login (given that my login password is the same as the one I use for all my private keys)? Probably someone will try to label this question as a duplicate of this question, this question, or this question. While these questions are similar, none of them explicitly say that there still needs to be a password entered on login, as I am demanding here. As a result, the accepted solutions just say "set your passwords to blank"--I don't want that, it's dangerous! So I am aware of the similar questions, but none of them has received the correct answer yet, because they are slightly different.

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• retrieve value from hashtable with clone of key; C#

  - by Johnny

  I would like to know if there is any possible way to retrieve an item from a hashtable using a key that is identical to the actual key, but a different object. I understand why it is probably not possible, but I would like to see if there is any tricky way to do it. My problem arises from the fact that, being as stupid as I am, I created hashtables with int[] as the keys, with the integer arrays containing indices representing spatial position. I somehow knew that I needed to create a new int[] every time I wanted to add a new entry, but neglected to think that when I generated spatial coordinate arrays later they would be worthless in retrieving the values from my hashtables. Now I am trying to decide whether to rearrange things so that I can store my values in ArrayLists, or whether to search through the list of keys in the Hashtable for the one I need every time I want to get a value, neither of the options being very cool. Unless of course there is a way to get //1 to work like //2! Thanks in advance. static void Main(string[] args) { Hashtable dog = new Hashtable(); //1 int[] man = new int[] { 5 }; dog.Add(man, "hello"); int[] cat = new int[] { 5 }; Console.WriteLine(dog.ContainsKey(cat)); //false //2 int boy = 5; dog.Add(boy, "wtf"); int kitten = 5; Console.WriteLine(dog.ContainsKey(kitten)); //true; }

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• How to figure out which key was pressed on a BlackBerry

  - by Skrud

  What I want: To know when the user has pressed the button that has the number '2' on it, for example. I don't care whether "Alt" or "Shift" has been pressed. The user has pressed a button, and I want to evaluate whether this button has '2' printed on it. Naturally, if I switch devices this key will change. On a Bold 9700/9500 this is the 'E' key. On a Pearl, this is the 'T'/'Y' key. I've managed to get this working in what appears to be a roundabout way, by looking up the keycode of the '2' character with the ALT button enabled and using Keypad.key() to get the actual button: // figure out which key the '2' is on: final int BUTTON_2_KEY = Keypad.key(KeypadUtil.getKeyCode('2', KeypadListener.STATUS_ALT, KeypadUtil.MODE_EN_LOCALE)); protected boolean keyDown(int keycode, int time) { int key = Keypad.key(keycode); if ( key == BUTTON_2_KEY ) { // do something return true; } return super.keyDown(keycode,time); } I can't help but wonder if there is a better way to do this. I've looked at the constants defined in KeypadListener and Keypad but I can't find any constants mapped to the actual buttons on the device. Would any more experienced BlackBerry devs care to lend a helping hand? Thanks!

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• How do you assign commands to keys in Terminal?

  - by NES

  Is there a solution to assign special key combinations to words in terminal use. For example the less command is very usefull and i use i a lot to pipe the output of another process through it. The idea would be to set up special key combinations that are only active in terminal use assigned to write different commands? So pressing CTRL + l in terminal window could write | less or CTRL + G could stand for | grep Note: i just mean adding the letters to commandline not execute the finally. A similar way what's tabcompletion but more specific.

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• android: consume key press, bypassing framework processing

  - by user360024

  What I want android to do: when user presses a single key, have the view respond, but do so without opening a text area and displaying the character associated with the key that was pressed, and without requiring that the Enter key be pressed, and without requiring that the user press Esc to make the text area go away. For example, when user presses "u" (and doesn't press Enter), that means "undo the last action", so the controller and model immediately undo the last action, then the view does an invalidate() and user sees that their last action has been undone. In other words the "u" key press should be silently processed, such that the only visual result is that user's last action has been undone. I've implemented OnKeyListener and provided an onKey() method: the class: public class MyGameView extends View implements OnKeyListener{ in the constructor: //2010jun06, phj: With onKey(), helps let this View consume key presses // before the framework gets a chance to consume the key press. setOnKeyListener((View.OnKeyListener)this); the onKey() method: public boolean onKey(View v, int keyCode, KeyEvent event) { if (keyCode == KeyEvent.KEYCODE_R) { Log.d("BWA", "In onKey received keycode associated with R."); } return true; // meaning the event (key press) has been consumed, so // the framework should not handle this event. } but when user presses "u" key on the emulator keypad, a textarea is opened at the bottom of the screen, the "u" charater is displayed there, and the onKey() method doesn't execute until user presses the Enter key. Is there a way to make android do what I want? Thanks,

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• OpenSSH does not accept public key?

  - by Bob

  I've been trying to solve this for a while, but I'm admittedly quite stumped. I just started up a new server and was setting up OpenSSH to use key-based SSH logins, but I've run into quite a dilemma. All the guides are relatively similar, and I was following them closely (despite having done this once before). I triple checked my work to see if I would notice some obvious screw up - but nothing is apparent. As far as I can tell, I haven't done anything wrong (and I've checked very closely). If it's any help, on my end I'm using Cygwin and the server is running Ubuntu 12.04.1 LTS. Anyways, here is the output (I've removed/censored some parts for privacy (primarily anything with my name, website, or its IP address), but I can assure you that nothing is wrong there): $ ssh user@host -v OpenSSH_5.9p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Connecting to host [ipaddress] port 22. debug1: Connection established. debug1: identity file /home/user/.ssh/id_rsa type 1 debug1: identity file /home/user/.ssh/id_rsa-cert type -1 debug1: identity file /home/user/.ssh/id_dsa type -1 debug1: identity file /home/user/.ssh/id_dsa-cert type -1 debug1: identity file /home/user/.ssh/id_ecdsa type -1 debug1: identity file /home/user/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA 24:68:c3:d8:13:f8:61:94:f2:95:34:d1:e2:6d:e7:d7 debug1: Host 'host' is known and matches the ECDSA host key. debug1: Found key in /home/user/.ssh/known_hosts:2 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /home/user/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /home/user/.ssh/id_dsa debug1: Trying private key: /home/user/.ssh/id_ecdsa debug1: No more authentication methods to try. Permission denied (publickey). What can I do to resolve my problem?

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• Making an SVG DOM JavaScript class

  - by CryptoQuick

  I'm unsatisfied with other JavaScript libraries and frameworks like jQuery, MooTools, and Raphael, because of their inability to support SVG grouping. You'd think it'd be a very simple thing for them to implement. Anyway, I'm trying to make a JavaScript class (using John Resig's class.js script) like this: var El = Class.extend({ el: null, svgNS: "http://www.w3.org/2000/svg", init: function (type) { this.el = document.createElementNS(this.svgNS, type); }, set: function (name, attr) { this.el.setAttributeNS(null, name, attr); }, get: function (el, name) { var attr = this.el.getAttributeNS(null, name); return attr; }, add: function (targEl) { targEl.el.appendChild(this.el); }, remove: function (targEl) { targEl.el.removeChild(this.el); }, setEl: function (docId) { this.el = document.getElementById(docId); } }); I can add elements to the DOM using these statements outside of the class, but storing the element inside the class becomes problematic. Anyone have any creative ideas?

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• Query for model by key

  - by Jason Hall

  What I'm trying to do is query the datastore for a model where the key is not the key of an object I already have. Here's some code: class User(db.Model): partner = db.SelfReferenceProperty() def text_message(self, msg): user = User.get_or_insert(msg.sender) if not user.partner: # user doesn't have a partner, find them one # BUG: this line returns 'user' himself... :( other = db.Query(User).filter('partner =', None).get() if other: # connect users else: # no one to connect to! The idea is to find another User who doesn't have a partner, that isn't the User we already know. I've tried filter('key !=, user.key()), filter('__key__ !=, user.key()) and a couple others, and nothing returns another User who doesn't have a partner. filter('foo !=, user.key()) also returns nothing, for the record.

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• foreign key and index issue

  - by George2

  Hello everyone, I am using SQL Server 2008 Enterprise. I have a table and one of its column is referring to another column in another table (in the same database) as foreign key, here is the related SQL statement, in more details, column [AnotherID] in table [Foo] refers to another table [Goo]'s column [GID] as foreign key. [GID] is primary key and clustered index on table [Goo]. My question is, in this way, if I do not create index on [AnotherID] column on [Foo] explicitly, will there be an index created automatically for [AnotherID] column on [Foo] -- because its foreign key reference column [GID] on table [Goo] already has primary clustered key index? CREATE TABLE [dbo].[Foo]( [ID] [bigint] IDENTITY(1,1) NOT NULL, [AnotherID] [int] NULL, [InsertTime] [datetime] NULL CONSTRAINT DEFAULT (getdate()), CONSTRAINT [PK_Foo] PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] ALTER TABLE [dbo].[Foo] WITH CHECK ADD CONSTRAINT [FK_Foo] FOREIGN KEY([Goo]) REFERENCES [dbo].[Goo] ([GID]) ALTER TABLE [dbo].[Foo] CHECK CONSTRAINT [FK_Foo] thanks in advance, George

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• Referencing surrogate key

  - by Arman

  I have a table that has an autoincrement surrogate key. I want to use it as a foreign key of my other table. The thing is, I cant figure out how I can reference it to that table, because it is nearly impossible to determine what I have to reference(the actual value of the surrogate key). Please be noted that what I am trying to do is adding a tuple/record through my program(outside the dbms). The process is: Add a new record in Table1 and generate an autoincrement key. Update Add a new record in Table2 and reference its foreign key to the primary key of Table1. Update My question is : HOW do I store the foreign key if I didnt know what is it?

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• OS X Terminal: Meta key + alt functionality at the same time

  - by abababa22

  Is there a way to use "alt/option" key as a meta key but still be able to use the key to make some characters which need it? For example in my local keyboard layout: @ is alt-2 \ is alt-shift-7 | is alt-7 etc. So if I set alt as meta key, I can't make those characters. On the other hand using "press esc, release esc, press a key" to make meta key sequences makes my hands hurt. Any emacs users with international keyboards who have solved this, please give any tips you might have! :) edit: It appears that I can set alt as meta key and then add these kind of settings in inputrc: "\e2": "@" This works in bash shell but it still won't work with emacs though, so no good.

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• Parent key of type encoded string?

  - by user246114

  Hi, How do we create a parent key which is an encoded string? Example: class Parent { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String mEncKey; } class Child { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String mEncKey; // In the doc examples, they have Key as the type here. @Persistent @Extension(vendorName="datanucleus", key="gae.parent-pk", value="true") private String mParentEncKey; } yeah I'm not sure how to make mParentEncKey an encoded string type, because the 'key' label is already being used? I would need something like?: key="gae.parent-pk.encoded-pk" not sure - is that possible? Thanks

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• SQL Server PIVOT on key-value table

  - by Zenox

  I have a table that has attributes based on a key-value. Example: CREATE TABLE ObjectAttributes ( int objectId, key nvarchar(64), value nvarchar(512) ) When I select from this I get: objectId key value ---------------------------- 1 Key 1 Value 1 1 Key 2 Value 2 I was wondering if I could use the PIVOT syntax to turn this into: objectId Key 1 Key 2 --------------------------- 1 Value 1 Value 2 I know all of my tables will have the same keys. (Unfortunately I cannot easily change the table structure. This is what is leading me to attempt using PIVOTS). The big issue here though is that pivots require an aggression function to be used. Is there a way to avert this? Am I completely wrong attempting this? Or is there a better solution?

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• Key repeat on Windows

  - by Rolle

  When you hold a key on the keyboard under Windows XP, the keyboard seems to send Key Down, Key Up repeatedly. However I am developing for a device where holding a key generates a "proper" key repeat, that is, lots of Key Down and then one Key Up when you release the button. I want to get the same behaviour under Windows to get our emulator to work as on he device. Is there anyway to acheive this? Do I need to get another keyboard driver? Thanks!

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• sftp and public keys

  - by Lizard

  I am trying to sftp into an a server hosted by someone else. To make sure this worked I did the standard sftp [email protected] i was promted with the password and that worked fine. I am setting up a cron script to send a file once a week so have given them our public key which they claim to have added to their authorized_keys file. I now try sftp [email protected] again and I am still prompted for a password, but now the password doesn't work... Connecting to [email protected]... [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied (publickey,password). Couldn't read packet: Connection reset by peer I did notice however that if I simply pressed enter (no password) it logged me in fine... So here are my questions: Is there a way to check what privatekey/pulbickey pair my sftp connection is using? Is it possible to specify what key pair to use? If all is setup correctly (using correct key pair and added to authorized files) why am I being asked to enter a blank password? Thanks for your help in advance! UPDATE I have just run sftp -vvv [email protected] .... debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-with-mic,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering public key: /root/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Server accepts key: pkalg ssh-rsa blen 277 debug2: input_userauth_pk_ok: SHA1 fp 45:1b:e7:b6:33:41:1c:bb:0f:e3:c1:0f:1b:b0:d5:e4:28:a3:3f:0e debug3: sign_and_send_pubkey debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey,password debug1: Trying private key: /root/.ssh/id_dsa debug3: no such identity: /root/.ssh/id_dsa debug2: we did not send a packet, disable method debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password It seems to suggest that it tries to use the public key... What am I missing?

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• How to Make Your Computer Press a Key Every X Seconds

  - by The Geek

  Have you ever needed to press a key every couple of seconds, or every few minutes? Perhaps you’re playing a video game and you’re waiting for an item, or you’ve got some other reason. Either way, here’s how to make your PC do it automatically. You’ll need to start by downloading and installing AutoHotkey, which is a simple scripting language that allows you to create easy scripts. Once you do that, right-click anywhere and choose New –> AutoHotkey Script. Once you’ve done that, paste the following into the script: #PersistentSetTimer, PressTheKey, 1800000Return HTG Explains: How Hackers Take Over Web Sites with SQL Injection / DDoS Use Your Android Phone to Comparison Shop: 4 Scanner Apps Reviewed How to Run Android Apps on Your Desktop the Easy Way

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