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  • JPA : many-to-many - only one foreign key in the association table

    - by Julien
    Hi, I mapped two classes in a ManyToMany association with these annotations : @Entity @Inheritance(strategy=InheritanceType.TABLE_PER_CLASS) public abstract class TechnicalItem extends GenericBusinessObject implements Resumable{ @SequenceGenerator(name="TECHNICAL_ITEM_ID_GEN", sequenceName="TECHNICAL_ITEM_ID_SEQ") @Id @Column(name = "\"ID\"", nullable = false) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "TECHNICAL_ITEM_ID_GEN") private int id; @ManyToMany(mappedBy = "referencePerformanceItems", fetch=FetchType.LAZY) private List testingRates; } @Entity @DiscriminatorValue("T") public class TestingRate extends Rate { @ManyToMany(fetch=FetchType.LAZY) @JoinTable(name="ecc.\"TESTING_RATE_TECHNICAL_ITEM\"", joinColumns = {@JoinColumn(name = "\"TESTING_RATE_ID\"")}, inverseJoinColumns = {@JoinColumn(name = "\"TECHNICAL_ITEM_ID\"")}) //@ManyToMany(mappedBy = "testingRates", fetch=FetchType.LAZY) private List referencePerformanceItems; } The sql generated for the association table creation is : create table ecc."TESTING_RATE_TECHNICAL_ITEM" ( "TESTING_RATE_ID" int4 not null, "TECHNICAL_ITEM_ID" int4 not null ); alter table ecc."TESTING_RATE_TECHNICAL_ITEM" add constraint FKC5D64DF6A2FE2698 foreign key ("TESTING_RATE_ID") references ecc."RATE"; There is no mention of the second foreign key "TECHNICAL_ITEM_ID" (the second part of the composite foreign key which should be in the association table). Is it a normal behaviour ? What should I do in the mapping if I want my 2 columns are 2 foreign keys referencing the primary keys of my 2 concerned tables. I use a PostGreSQL database and Hibernate as JPA provider. Thanks, Julien

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  • Overwriting lines in file in C

    - by KáGé
    Hi, I'm doing a project on filesystems on a university operating systems course, my C program should simulate a simple filesystem in a human-readable file, so the file should be based on lines, a line will be a "sector". I've learned, that lines must be of the same length to be overwritten, so I'll pad them with ascii zeroes till the end of the line and leave a certain amount of lines of ascii zeroes that can be filled later. Now I'm making a test program to see if it works like I want it to, but it doesnt. The critical part of my code: file = fopen("irasproba_tesztfajl.txt", "r+"); //it is previously loaded with 10 copies of the line I'll print later in reverse order /* this finds the 3rd line */ int count = 0; //how much have we gone yet? char c; while(count != 2) { if((c = fgetc(file)) == '\n') count++; } fflush(file); fprintf(file, "- . , M N B V C X Y Í U Á É L K J H G F D S A Ú O P O I U Z T R E W Q Ó Ü Ö 9 8 7 6 5 4 3 2 1 0\n"); fflush(file); fclose(file); Now it does nothing, the file stays the same. What could be the problem? Thank you.

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  • Rails: Overriding ActiveRecord association method

    - by seaneshbaugh
    Is there a way to override one of the methods provided by an ActiveRecord association? Say for example I have the following typical polymorphic has_many :through association: class Story < ActiveRecord::Base has_many :taggings, :as => :taggable has_many :tags, :through => :taggings, :order => :name end class Tag < ActiveRecord::Base has_many :taggings, :dependent => :destroy has_many :stories, :through => :taggings, :source => :taggable, :source_type => "Story" end As you probably know this adds a whole slew of associated methods to the Story model like tags, tags<<, tags=, tags.empty?, etc. How do I go about overriding one of these methods? Specifically the tags<< method. It's pretty easy to override a normal class methods but I can't seem to find any information on how to override association methods. Doing something like def tags<< *new_tags #do stuff end produces a syntax error when it's called so it's obviously not that simple.

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  • Access violations in strange places when using Windows file dialogs

    - by Robert Oschler
    A long time ago I found out that I was getting access violations in my code due to the use of the Delphi Open File and/or Save File dialogs, which encapsulate the Windows dialogs. I asked some questions on a few forums and I was told that it may have been due to the way some programs add hooks to the shell system that result in DLLs getting injected in every process, some of which can cause havoc with a program. For the record, the programming environment I use is Delphi 6 Professional running on Windows XP 32-bit. At the time I got around it by not using Delphi's Dialog components and instead calling straight into comdlg32.dll. This solved the problem wonderfully. Today I was working with memory mapped files for the first time and sure enough, access violations started cropping up in weird parts of the code. I tried my comdlg32.dll direct calls and this time it didn't help. To isolate the problem as a test I created a list box with the exact same files I was using during testing. These are the exact same test files I was selecting from an Open File dialog and then launching my memory mapped file with. I set things up so that by clicking on a file in the list box, I would use that file in my memory mapped file test instead of calling into a comdlg32.dll dialog function to select a test file. Again, the access violatons vanished. To show you how dramatic a fix it was I went from experiencing an access violation within 1 to 3 trials to none at all. Unfortunately, it's going to bite me later on of course when I do need to use file dialogs. Has anyone else dealt with this issue too and found the real culprit? Did any of you find a solution I could use to fix this problem instead of dancing around it like I am now? Thanks in advance.

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  • PHP File Upload using url parameters

    - by Arthur
    Is there a way to upload a file to server using php and the filename in a parameter (instead using a submit form), something like this: myserver/upload.php?file=c:\example.txt Im using a local server, so i dont have problems with filesize limit or upload function, and i have a code to upload file using a form <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <body> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="fileForm" enctype="multipart/form-data"> File to upload: <table> <tr><td><input name="upfile" type="file"></td></tr> <tr><td><input type="submit" name="submitBtn" value="Upload"></td></tr> </table> </form> <?php if (isset($_POST['submitBtn'])){ // Define the upload location $target_path = "c:\\"; // Create the file name with path $target_path = $target_path . basename( $_FILES['upfile']['name']); // Try to move the file from the temporay directory to the defined. if(move_uploaded_file($_FILES['upfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['upfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } } ?> </body> Thanks for the help

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  • Association Mapping Details confusion?

    - by AaronLS
    I have never understood why the associations in EntityFramework look the way they do in the Mapping Details window. When I select the line between 2 tables for an association, for example FK_ApplicationSectionsNodes_FormItems, it shows this: Association Maps to ApplicationSectionNodes FormItems (key symbol) FormItemId:Int32 <--> FormItemId:int ApplicationSectionNodes (key symbol) NodeId:Int32 <--> (key symbol) NodeId : int Fortunately this one was create automatically for me based on the foreign key constraints in my database, but whenever no constraints exist, I have a hard to creating associations manually(when the database doesn't have a diagram setup) because I don't understand the mapping details for associations. FormItems table has a primary key identity column FormItemId, and ApplicationSectionNodes contains a FormItemId column that is the foreign key and has NodeId as a primary key identity column. What really makes no sense to me is why the association has anything listed about the NodeId, when NodeId doesn't have anything to do with the foreign key relationship? (It's even more confusing with self referencing relationships, but maybe if I could understand the above case I'd have a better handle). CREATE TABLE [dbo].[ApplicationSectionNodes]( [NodeID] [int] IDENTITY(1,1) NOT NULL, [OutlineText] [varchar](5000) NULL, [ParentNodeID] [int] NULL, [FormItemId] [int] NULL, CONSTRAINT [PK_ApplicationSectionNodes] PRIMARY KEY CLUSTERED ( [NodeID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY], CONSTRAINT [UQ_ApplicationSectionNodesFormItemId] UNIQUE NONCLUSTERED ( [FormItemId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[ApplicationSectionNodes] WITH NOCHECK ADD CONSTRAINT [FK_ApplicationSectionNodes_ApplicationSectionNodes] FOREIGN KEY([ParentNodeID]) REFERENCES [dbo].[ApplicationSectionNodes] ([NodeID]) GO ALTER TABLE [dbo].[ApplicationSectionNodes] NOCHECK CONSTRAINT [FK_ApplicationSectionNodes_ApplicationSectionNodes] GO ALTER TABLE [dbo].[ApplicationSectionNodes] WITH NOCHECK ADD CONSTRAINT [FK_ApplicationSectionNodes_FormItems] FOREIGN KEY([FormItemId]) REFERENCES [dbo].[FormItems] ([FormItemId]) GO ALTER TABLE [dbo].[ApplicationSectionNodes] NOCHECK CONSTRAINT [FK_ApplicationSectionNodes_FormItems] GO FormItems Table: CREATE TABLE [dbo].[FormItems]( [FormItemId] [int] IDENTITY(1,1) NOT NULL, [FormItemType] [int] NULL, CONSTRAINT [PK_FormItems] PRIMARY KEY CLUSTERED ( [FormItemId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[FormItems] WITH NOCHECK ADD CONSTRAINT [FK_FormItems_FormItemTypes] FOREIGN KEY([FormItemType]) REFERENCES [dbo].[FormItemTypes] ([FormItemTypeId]) GO ALTER TABLE [dbo].[FormItems] NOCHECK CONSTRAINT [FK_FormItems_FormItemTypes] GO

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  • Rails Association Problem

    - by looloobs
    I am having trouble with this association. I need to get an array of the primaries that belong to the soldiers in a platoon. So once I get all the soldiers in a platoon: @company = Company.find_by_id(1) @platoons = @company.platoons <% @platoons.each do |p| %> <%= p.soldiers.primaries.find(:all,:conditions => ["relationship = ? AND contacted = ?", 'Spouse', 'Yes'])) %> <% end %> * So there is no method for primaries, I assume this is because I am trying to call an association on an array. Soldiers have a platoon_id but primaries do not, they only have the association to soldiers in that platoon. How do I do this? I need it to return an array of Primaries. Thanks in advance! class Soldier < ActiveRecord::Base belongs_to :company belongs_to :platoon has_many :primaries, :dependent => :destroy end class Platoon < ActiveRecord::Base belongs_to :company belongs_to :battalion has_many :soldiers end class Primary < ActiveRecord::Base belongs_to :soldier belongs_to :company end

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  • Conditionaly strip the last line from a text file

    - by fraXis
    Hello, I posted this yesterday on SO, and I received an answer that works great, but I need to change it around and I don't know how. Here is my original message: I need to strip the last line from a text file. I know how to open and save text files in C#, but how would I strip the last line of the text file? The text file will always be different sizes (some have 80 lines, some have 20). Can someone please show me how to do this? Here is the code that someone gave me to do this (which works fine) //Delete the last line from the file. This line could be 8174, 10000, or anything. This is from SO string tempfile = @"C:\junk_temp.txt"; using (StreamReader reader2 = new StreamReader(newfilename)) { using (StreamWriter writer2 = new StreamWriter(tempfile)) { string line = reader2.ReadLine(); while (!reader2.EndOfStream) { writer2.WriteLine(line); line = reader2.ReadLine(); } // by reading ahead, will not write last line to file } } File.Delete(newfilename); File.Move(tempfile, newfilename); File.Delete(tempfile); How would I change this to only delete the last line of the text file if it is a 4 or 5 digit string (such as 8001 or 99999). If it is anything other than that, such as a %, then I don't want to delete the last line. Can someone please modify the above code to do this for me? Thanks so much.

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  • Most efficient way to write over file after reading

    - by Ryan McClure
    I'm reading in some data from a file, manipulating it, and then overwriting it to the same file. Until now, I've been doing it like so: open (my $inFile, $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... close ($inFile); open (my $outFile, $file) or die "Could not open $file: $!"; print $outFile, $retString; close ($inFile); However I realized I can just use the truncate function and open the file for read/write: open (my $inFile, '+<', $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... truncate $inFile, 0; print $inFile $retString; close ($inFile); I don't see any examples of this anywhere. It seems to work well, but am I doing it correctly? Is there a better way to do this?

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  • How to add a has_many association on all models

    - by joshsz
    Right now I have an initializer that does this: ActiveRecord::Base.send :has_many, :notes, :as => :notable ActiveRecord::Base.send :accepts_nested_attributes_for, :notes It builds the association just fine, except when I load a view that uses it, the second load gives me: can't dup NilClass from: /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2184:in `dup' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2184:in `scoped_methods' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2188:in `current_scoped_methods' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2171:in `scoped?' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2439:in `send' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2439:in `initialize' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/reflection.rb:162:in `new' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/reflection.rb:162:in `build_association' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations/association_collection.rb:423:in `build_record' /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations/association_collection.rb:102:in `build' (my app)/controllers/manifests_controller.rb:21:in `show' Any ideas? Am I doing this the wrong way? Interestingly if I move the association onto just the model I'm working with at the moment, I don't get this error. I figure I must be building the global association incorrectly.

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  • PHP unlink OR rewrite own/current file by itself

    - by Email
    Hi Task: Cut or erase a file after first walk-through. i have an install file called "index.php" which creates another php file. <? /* here some code*/ $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = "<?php \n echo 'hallo, *very very long text*'; \n ?>"; fwrite($fh, $stringData); /*herecut"/ /*here some code */ after the creation of the new file this file is called and i intent to erase the filecreation call since it is very long and only needed on first install. i therefor add to the above code echo 'hallo, *very very long text*'; \n ***$new= file_get_contents('index.php'); \n $findme = 'habanot'; $pos = strpos($new, $findme); if ($pos === false) { $marker='herecut';\n $new=strstr($new,$marker);\n $new='<?php \n /*habanot*/\n'.$new;\n $fh = fopen('index.php', 'w') or die 'cant open file'); $stringData = $new; fwrite($fh, $stringData); fclose($fh);*** ?>"; fwrite($fh, $stringData);]} Isnt there an easier way or a function to modify the current file or even "self destroy" a file after first call? Regards

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  • Unable to write to a text file

    - by chrissygormley
    Hello, I am running some tests and need to write to a file. When I run the test's the open = (file, 'r+') does not write to the file. The test script is below: class GetDetailsIP(TestGet): def runTest(self): self.category = ['PTZ'] try: # This run's and return's a value result = self.client.service.Get(self.category) mylogfile = open("test.txt", "r+") print >>mylogfile, result result = ("".join(mylogfile.readlines()[2])) result = str(result.split(':')[1].lstrip("//").split("/")[0]) mylogfile.close() except suds.WebFault, e: assert False except Exception, e: pass finally: if 'result' in locals(): self.assertEquals(result, self.camera_ip) else: assert False When this test run's, no value has been entered into the text file and a value is returned in the variable result. I havw also tried mylogfile.write(result). If the file does not exist is claim's the file does not exist and doesn't create one. Could this be a permission problem where python is not allowed to create a file? I have made sure that all other read's to this file are closed so I the file should not be locked. Can anyone offer any suggestion why this is happening? Thanks

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  • Write to the second line of a PHP file

    - by Woz
    I have a php file that I want to add an include path to on the second line. I need to open the file and inset a line of code on line 2. I have tried a few techniques none of which are working but I think it has something to do with the text I am trying to write and possibly not escaping character correctly as I am not too familiar with file writing. So here is the file I want to write to: $file = $_SERVER['DOCUMENT_ROOT'].'/'.$domaindir.'/test.php'; Here is the piece of text I want to insert into the file: $dbfile = "include('".$_SERVER['DOCUMENT_ROOT']."/".$domaindir."/web_".$dbname.".inc.php');"; Then what I was doing was a string replace but all it did was bump the "session_start();" bit to a newline! Can anyone point me in the direction of a tutorial that might tell me how to insert this into the second line of my php file or indeed if anyone has any ideas? I can say for sure that the path to the PHP file is fully tested so i know its not that the file is not being open or written to. Any ideas would be much appreciated. Thanks in advance.

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  • Truncating a file while it's being used (Linux)

    - by Hobo
    I have a process that's writing a lot of data to stdout, which I'm redirecting to a log file. I'd like to limit the size of the file by occasionally copying the current file to a new name and truncating it. My usual techniques of truncating a file, like cp /dev/null file don't work, presumably because the process is using it. Is there some way I can truncate the file? Or delete it and somehow associate the process' stdout with a new file? FWIW, it's a third party product that I can't modify to change its logging model. EDIT redirecting over the file seems to have the same issue as the copy above - the file returns to its previous size next time it's written to: ls -l sample.log ; echo > sample.log ; ls -l sample.log ; sleep 10 ; ls -l sample.log -rw-rw-r-- 1 user group 1291999 Jun 11 2009 sample.log -rw-rw-r-- 1 user group 1 Jun 11 2009 sample.log -rw-rw-r-- 1 user group 1292311 Jun 11 2009 sample.log

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  • Making Thunar the default file browser without hiding the desktop icons

    - by Manu
    I really dislike Ubuntu's default file browser, nautilus, and decided to opt for a lighter alternative (Thunar or Xfe). I've used the following script to change the default to Thunar, but now all my icons are gone from the desktop ! The files are still there, in /home/myid/Desktop, but they do not appear. Is there a way to show them, or is this a consequence of removing nautilus as the default file browser ? Can I modify the following script* in order to keep the icons ? *copied from https://help.ubuntu.com/...: ## Originally written by aysiu from the Ubuntu Forums ## This is GPL'ed code ## So improve it and re-release it ## Define portion to make Thunar the default if that appears to be the appropriate action makethunardefault() { ## I went with --no-install-recommends because ## I didn't want to bring in a whole lot of junk, ## and Jaunty installs recommended packages by default. echo -e "\nMaking sure Thunar is installed\n" sudo apt-get update && sudo apt-get install thunar --no-install-recommends ## Does it make sense to change to the directory? ## Or should all the individual commands just reference the full path? echo -e "\nChanging to application launcher directory\n" cd /usr/share/applications echo -e "\nMaking backup directory\n" ## Does it make sense to create an entire backup directory? ## Should each file just be backed up in place? sudo mkdir nonautilusplease echo -e "\nModifying folder handler launcher\n" sudo cp nautilus-folder-handler.desktop nonautilusplease/ ## Here I'm using two separate sed commands ## Is there a way to string them together to have one ## sed command make two replacements in a single file? sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-folder-handler.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-folder-handler.desktop echo -e "\nModifying browser launcher\n" sudo cp nautilus-browser.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop --browser/thunar/g' nautilus-browser.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-browser.desktop echo -e "\nModifying computer icon launcher\n" sudo cp nautilus-computer.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-computer.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-computer.desktop echo -e "\nModifying home icon launcher\n" sudo cp nautilus-home.desktop nonautilusplease/ sudo sed -i -n 's/nautilus --no-desktop/thunar/g' nautilus-home.desktop sudo sed -i -n 's/TryExec=nautilus/TryExec=thunar/g' nautilus-home.desktop echo -e "\nModifying general Nautilus launcher\n" sudo cp nautilus.desktop nonautilusplease/ sudo sed -i -n 's/Exec=nautilus/Exec=thunar/g' nautilus.desktop ## This last bit I'm not sure should be included ## See, the only thing that doesn't change to the ## new Thunar default is clicking the files on the desktop, ## because Nautilus is managing the desktop (so technically ## it's not launching a new process when you double-click ## an icon there). ## So this kills the desktop management of icons completely ## Making the desktop pretty useless... would it be better ## to keep Nautilus there instead of nothing? Or go so far ## as to have Xfce manage the desktop in Gnome? echo -e "\nChanging base Nautilus launcher\n" sudo dpkg-divert --divert /usr/bin/nautilus.old --rename /usr/bin/nautilus && sudo ln -s /usr/bin/thunar /usr/bin/nautilus echo -e "\nRemoving Nautilus as desktop manager\n" killall nautilus echo -e "\nThunar is now the default file manager. To return Nautilus to the default, run this script again.\n" } restorenautilusdefault() { echo -e "\nChanging to application launcher directory\n" cd /usr/share/applications echo -e "\nRestoring backup files\n" sudo cp nonautilusplease/nautilus-folder-handler.desktop . sudo cp nonautilusplease/nautilus-browser.desktop . sudo cp nonautilusplease/nautilus-computer.desktop . sudo cp nonautilusplease/nautilus-home.desktop . sudo cp nonautilusplease/nautilus.desktop . echo -e "\nRemoving backup folder\n" sudo rm -r nonautilusplease echo -e "\nRestoring Nautilus launcher\n" sudo rm /usr/bin/nautilus && sudo dpkg-divert --rename --remove /usr/bin/nautilus echo -e "\nMaking Nautilus manage the desktop again\n" nautilus --no-default-window & ## The only change that isn't undone is the installation of Thunar ## Should Thunar be removed? Or just kept in? ## Don't want to load the script with too many questions? } ## Make sure that we exit if any commands do not complete successfully. ## Thanks to nanotube for this little snippet of code from the early ## versions of UbuntuZilla set -o errexit trap 'echo "Previous command did not complete successfully. Exiting."' ERR ## This is the main code ## Is it necessary to put an elseif in here? Or is ## redundant, since the directory pretty much ## either exists or it doesn't? ## Is there a better way to keep track of whether ## the script has been run before? if [[ -e /usr/share/applications/nonautilusplease ]]; then restorenautilusdefault else makethunardefault fi;

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  • Java File URI error ?

    - by Frank
    I need to get a file object online, and I know the file is located at : http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX If I paste it into my browser's url, I'll be able to download this file, now I'm trying to get it with Java, my code looks like this : String File_Url="http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX"; Object myObject=Get_Online_File(new URI(File_Url)); Object Get_Online_File(URI File_Uri) throws IOException { return readObject(new ObjectInputStream(new FileInputStream(new File(File_Uri)))); } public static synchronized Object readObject(ObjectInput in) throws IOException { Object o; ...... return o; } But I got the following error message : java.lang.IllegalArgumentException: URI scheme is not "file" at java.io.File.<init>(File.java:366) Why ? How to fix it ? Frank

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  • C# .Net file in use issue

    - by Dan
    I'm having an issue opening files that have recently been closed by the .Net framework. Basically, what happens is the following: -Read in an XML file using DataSet.ReadXml() -Make some changes to the data -Write out the XML file using DataSet.WriteXml() -Copy the XML file to a new location using File.Copy -FTP the file using a custom control This sequence can intermittently fail either after the WriteXML or the File.Copy with a file in use exception. I'm guessing it could be the Windows write cache not flushing right away. Can anyone confirm that this could be causing my issue? Any solutions to suggest? Thanks, Dan

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  • opening a file attachment from an outlook email using clickonce and a file association

    - by MarkGr
    Hi, I have a clickonce application (VS2010, .NET 4). I have registered a file association (.task), and this all works well. If I double click a file with the .task extension on the desktop the clickonce application opens and can open the file. If I email the file however, and double click the file from within outlook, I get the open/save dialog. If I click open nothing appears to happen. If I save the file I can open it by double clicking on it. Any ideas why the file does not open from within outlook ? Thanks, Mark

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  • How to create a new File in Qt

    - by GG
    Hello friends, I am a Qt beginner and just got stuck with the problem. I am looking for a file SomePath/NewDirectoryA/NewFile.kml ( NewFile.kml will be the only file in NewDirectoryA, having this directory just to maintain semantics in the project ). If SomePath/NewDirectoryA/NewFile.kml exists then I will use it in my code and If it doesn't exist then I have to create it. If this File doesn't exist then this directory also doesn't exist in SomePath. So If only I have to create a file I can use QFile and open it in ReadWrite or WriteOnly mode. But the problem is I have to create the file with the directory itself. I tried with QFile with file name SomePath/NewDirectoryA/NewFile.kml but it didn't worked. Please suggest me a way in which I can create a new file( NewFile.kml ) in a new directory( NewDirectorA ) at a given location( SomePath ).

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  • Bash: Check if file was modified since used in script

    - by Thomas Münz
    I need to check in a script if a file was modified since I read it (another application can modify it in between). According to bash manual there is a "-N" test which should report if a file was modified since last read. I tried it in a small script but it seems like it doesn't work. #!/bin/bash file="test.txt" echo "test" > $file cat $file; if [ -N $file ]; then echo "modified since read"; else echo "not modified since read"; fi I also tried an alternative way by touching another file and using if [ "file1" -nt "file2 ]; but this works only on a seconds accuracy which may under rare conditions not be sufficient. Is there any other bash-inbuilt solution for this problem or I do really need to use diff or md5sum?

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  • Perl, deleting an .xml file created and open with IO::File and XML::Writer?

    - by Sho Minamimoto
    So I'm running through a list of things and have code that creates an .xml file with IO::File called $doc, then I make a new writer with XML::Writer(OUTPUT = $doc). More code runs and I build a big xml file with XML::Writer. Then, near the end of the file, I find out if I need this file at all. If I do need it, I just $writer-end(); $doc-close(); but if I don't need it, what should I enter to just delete all data I've stored/saved and move onto the next file? I tried unlink($docpath) (before and after $doc-close()), the file was not deleted.

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  • How to concatenate multiple lines of log file into single variable in batch file?

    - by psych
    I have a log file containing a stack trace split over a number of lines. I need to read this file into a batch file and remove all of the lines breaks. As a first step, I tried this: if exist "%log_dir%\Log.log" ( for /F "tokens=*" %%a in ("%log_dir%\Log.log") do @echo %%a ) My expectation was that this would echo out each line of the log file. I was then planning to concatenate these lines together and set that value in a variable. However, this code doesn't do what I would expect. I have tried changing the value of the options for delims and tokens, but the only output I can get is the absolute path to the log file and nothing from the contents of this file. How can I set a variable to be equal to the lines of text in a file with the line breaks removed?

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  • How to know the file type of the file which you are forcing the user to download?

    - by Starx
    I am trying to force the user to download a file. For that my script is: $file = "file\this.zip"; header("Cache-Control: public"); header("Content-Description: File Transfer"); header("Content-Disposition: attachment; filename=$file"); header("Content-Type: application/zip"); //This is what I need header("Content-Transfer-Encoding: binary"); readfile($file); The files I am going to upload my not be .zip all the time so I want to know the content type of the image I am going to receive in $file. How to accomplish this

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  • How can I insert a line at the beginning of a file with Perl's Tie::File?

    - by thebourneid
    I'm trying to insert/add a line 'COMMENT DUMMY' at the beginnig of a file as a first row if /PATTERN/ not found. I know how to do this with OPEN CLOSE function. Probably after reading the file it should look something like this: open F, ">", $fn or die "could not open file: $!"; ; print F "COMMENT DUMMY\n", @array; close F; But I have a need to implement this with the use of the Tie::File function and don't know how. use strict; use warnings; use Tie::File; my $fn = 'test.txt'; tie my @lines, 'Tie::File', $fn or die "could not tie file: $!"; untie @lines;

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  • Create Zip File In Windows and Extract Zip File In Linux

    - by Yan Cheng CHEOK
    I had created a zip file (together with directory) under Windows as follow : package sandbox; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.zip.ZipEntry; import java.util.zip.ZipOutputStream; /** * * @author yan-cheng.cheok */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // These are the files to include in the ZIP file String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"}; // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // Create the ZIP file String outFilename = "outfile.zip"; ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename)); // Compress the files for (int i=0; i<filenames.length; i++) { FileInputStream in = new FileInputStream(filenames[i]); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filenames[i])); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); } catch (IOException e) { e.printStackTrace(); } } } The newly created zip file can be extracted without problem under Windows, by using http://www.exampledepot.com/egs/java.util.zip/GetZip.html However, I realize if I extract the newly created zip file under Linux, using http://www.exampledepot.com/egs/java.util.zip/GetZip.html, I will get a file named "MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory. I try to solve the problem by changing the zip file creation code to String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"}; But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)

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