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  • Oracle HCM User Group (OHUG) 2014

    - by CaroleB
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 We Have Your Answers at the Oracle Support Central for Oracle E-Business Suite. Bring your toughest questions to Support Central and meet an Oracle Support expert to get your answers! Don’t miss your opportunity to spend focused time working with a Support Engineer or Manager one-on-one. Support Engineers: Here to Help You Succeed Let us help you solve problems without having to log an SR. We can help you streamline and simplify your daily operations or reduce your risks. We can show you how to maximize up-time and lower your organizations costs through preventative maintenance. Learn about Oracle HCM Cloud, or our new tools and processes that get you answers faster, such as analyzers and patch wizards. Check out the Product Information Centers, Newsletters, and My Oracle Support searches tips and tricks. Stop by and meet a Support Engineer that you may have worked with on a past Service Request. Get an explanation for a product area that you may have more questions on. Oracle Support is ready to help you with the Oracle HCM applications that you rely on to run your business. Support Central: HCM Support Leadership Here for You The Oracle Support Central is open Tuesday through Thursday.  We have a Support Leadership team of managers here to discuss your crucial milestones or your intentions to upgrade or configuring Oracle HCM products. We can provide heightened monitoring and engagement for a successful milestone. We are here for any ad-hoc account reviews that you would like to initiate on your OHUG trip. Location: Las Vegas: Mirage: Montego A Contact: Gregory Clark or Carole Black    /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast- mso-fareast-theme-font:minor-latin; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Plesk Subdomain folder group and permission problem

    - by Jake
    I am working on a dedicated server from some web host. In Plesk 9.5, after creating a subdomain sub.domain.com, with login using main account, plesk automatically creates a folder domain.com/subdomain/sub with user and group of root I want to upload some files (the framework api) in domain.com/subdomain/sub itself instead of domain.com/subdomain/sub/httpdocs but I can't. domain.com/subdomain/sub/httpdocs has user and group of [main account_user] and psaserv respectively Is there a way to modify the user/group of domain.com/subdomain/sub from plesk so that I can upload files inside it? Otherwise, what is the next best solution?

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  • January Winnipeg .NET User Group Event

    - by D'Arcy Lussier
    We’ve had some problems with the Winnipeg .NET UG website, but things are getting sorted out and the site should be back up very shortly. In the meantime, here’s info on our January event and how to register. This is also a Microsoft sponsored event, so we’ll have some great swag to give away. As always, pizza will be provided! When: Wednesday, January 26th Where: 17th Floor Conference Room, Richardson Building Session: Taking your Windows Phone Apps to the Next Level with Tombstoning Speaker: Tyler Doerksen, Imaginet Unlike previous versions of Windows Mobile, Windows Phone 7 does not allow 3rd party applications to run in the background. Because of this your application needs to react to various life cycle events to provide the user with a seamless experience. Luckily Silverlight isolated storage has your back. In this session learn about the app life cycle and what storage patterns you can use to keep your users happy. To register for this event, please visit our registration page here.

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  • Can't read directory owned by my group

    - by Jonathan
    I moved the postgres data directory to a separate partition and it works great. The directory is owned by postgres user and postgres group. d-wx------ 11 postgres postgres 4.0K 2010-06-11 08:28 data/ I added myself to the group > sudo addgroup me postgres > groups me me : me adm dialout cdrom plugdev lpadmin admin sambashare postgres And gave the group read and execute permissions to everything in the directory. sudo chmod -R g+rx ./data d-wxr-x--- 11 postgres postgres 4.0K 2010-06-11 08:28 data/ But I still can not CD or LS the directory. > ls data ls: cannot open directory data: Permission denied What beginner mistake am I making?

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  • E-Business Suite Applications Technology Group (ATG) Advisor Webcast Program – June 2014

    - by LuciaC-Oracle
    Webcast: EBS Patch Wizard Overview Date: Thursday June 12, 2014 at 18:00 UK / 10:00 PST / 11:00 MST / 13:00 EST Topics covered will include: What is Oracle EBS Patch Wizard Tool? Benefits of the Patch Wizard utility Patch Wizard Interface Patch Impact Analysis Details & Registration : Doc ID 1672371.1Direct registration link. Webcast: EBS Proactive Analyzers Overview Date: Thursday June 26, 2014 at 18:00 UK / 10:00 PST / 11:00 MST / 13:00 EST Topics covered will include: What are Oracle Support Analyzers? How to identify the Analyzers available? Short Analyzers Overview Patch Impact Analysis How to use an Analyzer? Details & Registration : Doc ID 1672363.1Direct registration link.If you have any questions about the schedules or if you have a suggestion for an Advisor Webcast to be planned in future, please send an E-Mail to Ruediger Ziegler.

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  • EBS Applications Technology Group (ATG) Advisor Webcast December 2012

    - by LuciaC
    Invitation : Advisor Webcast December 2012 In December 2012 we have scheduled an Advisor Webcast, where we want to give you a closer look into the invalid objects in an E-Business Suite Environment. E-Business Suite - Troubleshooting invalid objectsAgenda : Introduction Activities that generate invalid objects EBS Architecture EBS Patching Concepts Troubleshooting Invalid Objects References EMEA Session : Tuesday December 11th, 2012 at 09:00 AM UK / 10:00 AM CET / 13:30 India / 17:00 Japan / 18:00 Australia Details & Registration : Doc ID 1501696.1Direct link to register in WebExUS Session : Wednesday December 12th, 2012 at 18:00 UK / 19:00 CET / 10:00 AM Pacific / 11:00 AM Mountain/ 01:00 PM Eastern Details & Registration : Doc ID 1501697.1Direct link to register in WebExIf you have any question about the schedules or if you have a suggestion for an Advisor Webcast to be planned in future, please send an E-Mail to Ruediger Ziegler.

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  • Default groups for user in Ubuntu 12.10?

    - by Sukminder
    Installed HP Linux Imaging and Printing by using install script and something crashed. Now I'm only member of my own group and lp. Which are the default groups for users in Ubuntu 12.10? Same as this? And, out of curiosity, is there some place where this information is logged? As i.e. some log file showing which groups my user was on previous boot? And/or is this information ,(which groups are default), documented somewhere? OK Found answer. Adding when I'm able (haven't got enough points and have to wait hours to answer myself).

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  • nagios ldap-group based front end login permission issues

    - by Eleven-Two
    I want to grant users access to the nagios 3 core frontend by using an active directory group ("NagiosWebfrontend" in the code below). The login works fine like this: AuthType Basic AuthName "Nagios Access" AuthBasicProvider ldap AuthzLDAPAuthoritative on AuthLDAPURL "ldap://ip-address:389/OU=user-ou,DC=domain,DC=tld?sAMAccountName?sub?(objectClass=*)" AuthLDAPBindDN CN=LDAP-USER,OU=some-ou,DC=domain,DC=tld AuthLDAPBindPassword the_pass Require ldap-group CN=NagiosWebfrontend,OU=some-ou,DC=domain,DC=tld Unfortunately, every nagios page just shows "It appears as though you do not have permission to view information for any of the services you requested...". I got the hint, that I am missing a contact in nagios configuration which is equal to my login, but creating one with the same name as the domain user had no effect on this issue. However, it would be great to find a solution without manually editing nagios.conf for every new user, so the admins could grant access to nagios by just putting the user to "NagiosWebfrontend" group. What would be the best way to solve it?

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  • How should I group these variables?

    - by stariz77
    I have a shape that will be defined by: char s_type; char color; double height; double width; These variables are scanned in from a request string sent to my server and passed into my printing function, which then prints out the shape. Currently they are just local variables sitting in my main(); however, I was wondering if there would be any advantage in creating a struct containing these variables, and then passing the struct to my printing function? or how else might I improve my program's structure/style, would passing a struct by reference have any kind of performance benefit if there were many requests and therefore many printing function calls? printer(char st, char cr, double ht, double wd); int main() { // Other main functionality. char s_type; char color; double height; double width; sscanf (serv_req, "GET /%c/%c/%lf/%lf", &s_type, &color, &height, &width); printer(s_type, color, height, width); // Other main functionality. return 0; } It seemed "neater" if I had a struct or something that didn't leave me with declarations in the middle of everything else going on in main. I'm interested in structure/style as well as performance. EDIT: didn't mean to put printer declaration inside main.

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  • Using a Group Managed Service Account (gMSA) for a scheduled task

    - by Trevor Sullivan
    Back in Windows Server 2008 R2, when stand-alone Managed Service Accounts (sMSA) were new, they could not be used to execute scheduled tasks. In Windows Server 2012 however, there is a new type of account called the Group Managed Service Account (gMSA). This type of account is supposedly capable of launching scheduled tasks in the task scheduler on clients & member servers inside of a Windows Server 2012 forest/domain functional level. So far, I have: Established a Windows Server 2012 forest/domain Created a Group Managed Service Account (gMSA) Installed the gMSA on a Windows Server 2012 member server And currently I'm having trouble with: Setting a scheduled task to use the gMSA When I attempt to use a gMSA on a scheduled task, I get the error message that says "The object cannot be found" (paraphrased) message. My question is: How do I configure a Scheduled Task to execute using a Group Managed Service Account (gMSA)?

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  • no internet mail group / mail sending and delivery restrictions

    - by Jeff
    I run a win 2k8 a/d server and an win 2k8 exchange 07 server I have a group called 'No Internet Mail', i made it a distribution group. I tried to setup a transport rule on the exchange server that is configured as follows for outgoing: from a member of no internet mail and sent to users outside the organization redirect the message to administrator and send message refused, forwarded to administrator. Please talk to management for external email use. however , when i enable this it forwards everyones emails to me regardless if they are a member of the no internet mail group or not. not sure what im doing wrong, thanks in advanced.

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  • SQL Southwest, Thursday 18th Oct - User Group Meetup and Virtual Meetup

    October's meeting on Thursday 18th will be a virtual meeting which means anyone in the world can attend if they have access to a PC with an internet connection. We are pleased to announce that Grant Fritchey will be giving us 2 sessions. "It really helped us isolate where we were experiencing a bottleneck"- John Q Martin, SQL Server DBA. Get started with SQL Monitor today to solve tricky performance problems - download a free trial

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  • TSQL Challenge 82 - Find elements that uniquely make up a group

    The challenge is to find the Tax Code based on Price. Each sales amount is uniquely made up by the sum of one or more prices. Based on this you should assign the tax code to each price. Keep your database and application development in syncSQL Connect is a Visual Studio add-in that brings your databases into your solution. It then makes it easy to keep your database in sync, and commit to your existing source control system. Find out more.

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  • SQL Server 2008 Audit Change Group

    Auditing your SQL Server instances has become more of a concern these days. SQL Server 2008 introduced a new feature named SQL Server Audit. Enabling this feature can be done in just a few simple steps, but so could disabling this feature. And when it comes to audits, many times you are asked to provide proof that the audit itself has not been tampered with.

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  • php curly braces groups

    - by David
    is there a function or regex or anything to group items by a { and } tag? so it should group items by the opening tag { and the closing tag }. but be careful, there are also groups inside parent groups like so: group { text1 group2 { text2 } } so basically think of it like php, you make an opening tag, you need to close it with a closing tag, curly braces in php's case. i just need it to like substr() each group into an associative array somehow, except I cant figure it out with the whole, "group inside a parent group".

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  • What is the easiest way to get the primary groupName from AD in C#?

    - by madhatter84gn
    I am currently using PrincipalContext and UserPrincipal to return the users primary groupid. How can I take this id and find the actual group name? Also I have code that works correctly to assign the user's primary group, but once I assign them to the group I can not delete them from Domain Users which is the default primary group prior to my change. I have called Save() before trying to remove the domain users group. My requirements state I must add the user to AD then assign their primary group and then remove them as a member of Domain Users.

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  • Linq-to-SQL: How to shape the data with group by?

    - by Cheeso
    I have an example database, it contains tables for Movies, People and Credits. The Movie table contains a Title and an Id. The People table contains a Name and an Id. The Credits table relates Movies to the People that worked on those Movies, in a particular role. The table looks like this: CREATE TABLE [dbo].[Credits] ( [Id] [int] IDENTITY (1, 1) NOT NULL PRIMARY KEY, [PersonId] [int] NOT NULL FOREIGN KEY REFERENCES People(Id), [MovieId] [int] NOT NULL FOREIGN KEY REFERENCES Movies(Id), [Role] [char] (1) NULL In this simple example, the [Role] column is a single character, by my convention either 'A' to indicate the person was an actor on that particular movie, or 'D' for director. I'd like to perform a query on a particular person that returns the person's name, plus a list of all the movies the person has worked on, and the roles in those movies. If I were to serialize it to json, it might look like this: { "name" : "Clint Eastwood", "movies" : [ { "title": "Unforgiven", "roles": ["actor", "director"] }, { "title": "Sands of Iwo Jima", "roles": ["director"] }, { "title": "Dirty Harry", "roles": ["actor"] }, ... ] } How can I write a LINQ-to-SQL query that shapes the output like that? I'm having trouble doing it efficiently. if I use this query: int personId = 10007; var persons = from p in db.People where p.Id == personId select new { name = p.Name, movies = (from m in db.Movies join c in db.Credits on m.Id equals c.MovieId where (c.PersonId == personId) select new { title = m.Title, role = (c.Role=="D"?"director":"actor") }) }; I get something like this: { "name" : "Clint Eastwood", "movies" : [ { "title": "Unforgiven", "role": "actor" }, { "title": "Unforgiven", "role": "director" }, { "title": "Sands of Iwo Jima", "role": "director" }, { "title": "Dirty Harry", "role": "actor" }, ... ] } ...but as you can see there's a duplicate of each movie for which Eastwood played multiple roles. How can I shape the output the way I want?

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  • Sort and Group in LINQ

    - by Jono
    I apologise in advance if this has been answered before; it seems so fundamental to me yet I haven't turned up the answer in any of my searches. I have a list of string tuples, say (P1,P2) I'd like to know if there's a LINQ statement where I could group by P1 (in ascending order), and have that group contain all the P2 values for the group (in descending order). For input: ("A","B"), ("A","C"), ("D","B") I'd like to get two groups: "A" and "D" (in that order, every time) where group "A" contains "C" and "B" (in that order, every time) and group "D" contains, well, "B". Is this possible with the built-in LINQ classes or do I need to iterate the groups and sort them myself? Sounds like hard work~

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  • MySQL break out group clause from subquery

    - by Anton Gildebrand
    Here is my query SELECT COALESCE(js.name,'Lead saknas'), count(j.id) FROM jobs j LEFT JOIN job_sources js ON j.job_source=js.id LEFT JOIN (SELECT * FROM quotes GROUP BY job_id) q ON j.id=q.job_id GROUP BY j.job_source The problem is that it's allowed for each job to have more than one quote. Because of that i group the quotes by job_id. Now sure, this works. But i don't like the solution with a subquery. How can i break out the group clause from the subquery to the main query? I have tried to add q.job_id to the main group clause, both before and after the existing one but don't get the same results.

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  • In a graph, how to find the nearest node to a group of nodes?

    - by Nikola
    Hello, I have an undirected, unweighted graph, which doesn't have to be planar. I also have a subset of graph's nodes (true subset) and I need to find a node not belonging to the subset, with minimum sum of distances to all nodes in the subset. So far, I have implemented breath-first search starting from each node in the subset, and the intersection that occurs first is the node I am looking for. Unfortunately, it is running too slow since the graph contains a large number of nodes. Any advice or comment will be appreciated. Thank you, Nikola

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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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