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  • SQL Server 2008 R2 Cumulative Updates are available

    - by AaronBertrand
    Microsoft has released cumulative updates for SQL Server 2008 R2. SQL Server 2008 R2 SP1 Cumulative Update #8 KB article is http://support.microsoft.com/kb/2723743 Build number is 10.50.2822.0 There are 20 fixes published as of 2012-08-31 This update is relevant for builds between 10.50.2500 and 10.50.2820 Note that the page that lists builds and updates for SP1 seems confused; it currently states that the build is 10.50.2822, while the KB article shows 10.50.2821. The file from the hotfix is 10.50.2822,...(read more)

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  • SQL SERVER – Rename Columnname or Tablename – SQL in Sixty Seconds #032 – Video

    - by pinaldave
    We all make mistakes at some point of time and we all change our opinion. There are quite a lot of people in the world who have changed their name after they have grown up. Some corrected their parent’s mistake and some create new mistake. Well, databases are not protected from such incidents. There are many reasons why developers may want to change the name of the column or table after it was initially created. The goal of this video is not to dwell on the reasons but to learn how we can rename the column and table. Earlier I have written the article on this subject over here: SQL SERVER – How to Rename a Column Name or Table Name. I have revised the same article over here and created this video. There is one very important point to remember that by changing the column name or table name one creates the possibility of errors in the application the columns and tables are used. When any column or table name is changed, the developer should go through every place in the code base, ad-hoc queries, stored procedures, views and any other place where there are possibility of their usage and change them to the new name. If this is one followed up religiously there are quite a lot of changes that application will stop working due to this name change.  One has to remember that changing column name does not change the name of the indexes, constraints etc and they will continue to reference the old name. Though this will not stop the show but will create visual un-comfort as well confusion in many cases. Here is my question back to you – have you changed ever column name or table name in production database (after project going live)? If yes, what was the scenario and need of doing it. After all it is just a name. Let me know what you think of this video. Here is the updated script. USE tempdb GO CREATE TABLE TestTable (ID INT, OldName VARCHAR(20)) GO INSERT INTO TestTable VALUES (1, 'First') GO -- Check the Tabledata SELECT * FROM TestTable GO -- Rename the ColumnName sp_RENAME 'TestTable.OldName', 'NewName', 'Column' GO -- Check the Tabledata SELECT * FROM TestTable GO -- Rename the TableName sp_RENAME 'TestTable', 'NewTable' GO -- Check the Tabledata - Error SELECT * FROM TestTable GO -- Check the Tabledata - New SELECT * FROM NewTable GO -- Cleanup DROP TABLE NewTable GO Related Tips in SQL in Sixty Seconds: SQL SERVER – How to Rename a Column Name or Table Name What would you like to see in the next SQL in Sixty Seconds video? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology, Video Tagged: Excel

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  • Can't remotely connect through SQL Server Management Studio

    - by FAtBalloon
    I have setup a SQL Server 2008 Express instance on a dedicated Windows 2008 Server hosted by 1and1.com. I cannot connect remotely to the server through management studio. I have taken the following steps below and am beyond any further ideas. I have researched the site and cannot figure anything else out so please forgive me if I missed something obvious, but I'm going crazy. Here's the lowdown. The SQL Server instance is running and works perfectly when working locally. In SQL Server Management Studio, I have checked the box "Allow Remote Connections to this Server" I have removed any external hardware firewall settings from the 1and1 admin panel Windows firewall on the server has been disabled, but just for kicks I added an inbound rule that allows for all connections on port 1433. In SQL Native Client configuration, TCP/IP is enabled. I also made sure the "IP1" with the server's IP address had a 0 for dynamic port, but I deleted it and added 1433 in the regular TCP Port field. I also set the "IPALL" TCP Port to 1433. In SQL Native Client configuration, SQL Server Browser is also running and I also tried adding an ALIAS in the I restarted SQL server after I set this value. Doing a "netstat -ano" on the server machine returns a TCP 0.0.0.0:1433 LISTENING UDP 0.0.0.0:1434 LISTENING I do a port scan from my local computer and it says that the port is FILTERED instead of LISTENING. I also tried to connect from Management studio on my local machine and it is throwing a connection error. Tried the following server names with SQL Server and Windows Authentication marked in the database security. ipaddress\SQLEXPRESS,1433 ipaddress\SQLEXPRESS ipaddress ipaddress,1433 tcp:ipaddress\SQLEXPRESS tcp:ipaddress\SQLEXPRESS,1433

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  • The Linux Foundation Store: Linux gets silly

    <b>Cyber Cynic:</b> "...the Linux Foundation, the non-profit organization dedicated to growing Linux, has launched a new Linux merchandise store featuring a line of exclusive and original T-shirts, hats, mugs and other items that reflect "geek culture.""

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  • SQL Server v.Next (Denali) : More on contained databases and "contained users"

    - by AaronBertrand
    One of the reasons for contained databases (see my previous post ) is to allow for a more seamless transition when moving a database from one server to another. One of the biggest complications in doing so is making sure that all of the logins are in place on the new server. Contained databases help solve this issue by creating a new type of user: a database-level user with a password. I want to stress that this is not the same concept as a user without a login , which serves a completely different...(read more)

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  • Feature pack for SQL Server 2005 SP4 - collection of standalone packages

    - by ssqa.net
    With the release of SQL2005Sp4 an additional task is essential for DBAs & Developers to avoid any compatibility issues with existing code agains SP4 instance. Feature pack for SQL Server 2005 SP4 is available to download which contains the standalone packages such as SQLNative Client, ADOMD, OLAPDM etc.... as it states the feature pack are built on latest versions of add-on and backward compatibility contents for SQL Server 2005. The above link provides individual file to download for each environment...(read more)

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  • SQL Server Windows Auth Login sees Domain as untrusted...

    - by Mr Shoubs
    I've had someone set up a domain controller on windows 2008 on one server, and sql server 2008 on another. The domain seems to be working fine, I'm logged on as a domain user on both servers, nothing seems to be a problem there. However, when I try to add a domain user/group to SQL Server Security (e.g. clicking ok from the create login screen) it says it can't find it (even though I've used the search to find the correct account in the first place), when I try to logon (even though I haven't added it yet) it says something about the account being part of an untrusted domain instead of saying I don't have permission to log on. Anyone have any ideas on what is set up incorrectly?

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  • SQL SERVER – Introduction to CUME_DIST – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    This blog post is written in response to the T-SQL Tuesday post of Prox ‘n’ Funx. This is a very interesting subject. By the way Brad Schulz is my favorite guy when it is about blogging. I respect him as well learn a lot from him. Everybody is writing something new his subject, I decided to start SQL Server 2012 analytic functions series. SQL Server 2012 introduces new analytical function CUME_DIST(). This function provides cumulative distribution value. It will be very difficult to explain this in words so I will attempt small example to explain you this function. Instead of creating new table, I will be using AdventureWorks sample database as most of the developer uses that for experiment. Let us fun following query. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, CUME_DIST() OVER(ORDER BY SalesOrderID) AS CDist FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY CDist DESC GO Above query will give us following result. Now let us understand what is the formula behind CUME_DIST and why the values in SalesOrderID = 43670 are 1. Let us take more example and be clear about why the values in SalesOrderID = 43667 are 0.5. Now let us enhence the same example and use PARTITION BY into the OVER clause and see the results. Run following query in SQL Server 2012. USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, CUME_DIST() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) AS CDist FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID DESC, CDist DESC GO Now let us see the result of this query. We are have changed the ORDER BY clause as well partitioning by SalesOrderID. You can see that CUME_DIST() function provides us different results. Additionally now we see value 1 multiple times. As we are using partitioning for each group of SalesOrderID we get the CUME_DIST() value. CUME_DIST() was long awaited Analytical function and I am glad to see it in SQL Server 2012. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Embedded linux Development learning

    - by user1797375
    I come from a windows background and i am proficient with the .net platform. For work, i need to bring up a custom embedded system platform. We have bought the pandaboard ES as the test platform. The application is to stream images over the wifi. If you think about it, we are building something similar to a netgear router - the only difference being when you log into the device it serves images. Because my background is in windows i am not quite sure how to start off with embedded linux development. in reading through various sites i have come to the conclusion that going to linux as development host is the best option. Can some one point to me in the right direction regarding the set up. I have a windows machine that will be used for development purposes. I can either do a virtual box or setup a partition for linux. But the finer details are what throwing me off..what i need to know is 1) once i install linux what other software do I need - Code blocks, 2) what about toolchain 3) How to debug - through serial port ? 4) Is there a way to send the image built directly to the CF card? Thanks

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  • Cumulative Update #1 for SQL Server 2005 SP4

    - by AaronBertrand
    Well, much quicker than I would have suspected, the SQL Server Release Services team has incorporated all of the fixes in 2005 SP3's CU #12 into the first CU for SP4. Thanks to Chris Wood for the heads up. You can get the new Cumulative Update here: KB #2464079 : Cumulative update package 1 for SQL Server 2005 Service Pack 4 The nice round number of build 5000 didn't last long either; this CU will update you from 9.00.5000 to 9.00.5254....(read more)

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  • How can I connect to a Windows server using a Command Line Interface? (CLI)

    - by HopelessN00b
    Especially with the option to install Server Core in Server 2008 and above, connecting to Windows servers over a CLI is increasingly useful ability, if not one that's very widespread amongst Windows administrators. Practically every Windows GUI management tool has an option to connect to a remote computer, but there is no such option present in the built-in Windows CLI (cmd.exe), which gives the initial impression that this might not be possible. Is it possible to remotely management or administer a Windows Server using a CLI? And if so, what options are there to achieve this?

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  • Is SQL Server 2008 R2 a full release of SQL Server?

    - by AaronBertrand
    This has come up in conversations more than once in the past little while - recently on twitter I made the casual comment that later this year, SQL Server 2008 will be "two versions old." Well, not everyone agrees that that is technically true. So, I thought I'd put something out there that isn't limited to 140 characters. There are certainly some valid arguments on both sides, but my opinion - based both on these facts and on my memory that Microsoft has marketed it as such - is that SQL Server...(read more)

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  • Do we really need a thousand Linux distributions?

    - by nebukadnezzar
    Pointed from an answer to a (possibly related) question, I came across this graphic, and I'm shocked how many linux distributions currently exist. However, it seems that most of these distributions are forks of already popular distributions with minimal changes, usually limited to themes, wallpapers, buttons, the kind of stuff most people probably wouldn't see as a reason to fork a Linux distribution. Of course, someone will always say "Opensource is also about the freedom of choice", and while I wholeheartedly agree, I do not believe that this is a valid reason to fork an already perfectly working Distribution into a new one, which might possibly result in less security/stability due to smaller group of developers. There's another problem: Those, who want to switch to Linux, are confronted with a neverending list of Linux distributions, and wonder rightfully which they're supposed to chose (infact, I was facing that problem before I've discovered Ubuntu). There might be (very few) valid reasons to fork a distribution: Specializing on a particular topic (FOSS Only, work-related topic (i.e., for a Hospital), etc) An exceptional architecture, that requires a special set of software Use of non-FOSS, propietary technology, and such But even with these points in mind, it would still seem easier to create a subdistribution with the required changes, such as XUbuntu with XFCE4, KUbuntu with KDE4, Fluxbuntu with Fluxbox, etc. So, why exactly do we need so many distributions?

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  • SQL SERVER – Template Browser – A Very Important and Useful Feature of SSMS

    - by pinaldave
    Let me start today’s blog post with a direction question. How many of you have ever used Template Browser? Template Browser is a very important and useful feature of SQL Server Management Studio (SSMS). Every time when I am talking about SQL Server there is always someone comes up with the question, why there is no step by step procedure included in SSMS for features. Honestly every time I get this question, the question I ask back is How many of you have ever used Template Browser? I think the answer to this question is most of the time either no or we have not heard of the feature. One of the people asked me back – have you ever written about it on your blog? I have not yet written about it. Basically there is nothing much to write about it. It is pretty straight forward feature, like any other feature and it is indeed difficult to elaborate. However, I will try to give a quick introduction to this feature. Templates are like a quick cheat sheet or quick reference. Templates are available to create objects like databases, tables, views, indexes, stored procedures, triggers, statistics, and functions. Templates are also available for Analysis Services as well. The template scripts contain parameters to help you customize the code. You can Replace Template Parameters dialog box to insert values into the script. Additionally users can create new custom templates as well with folder structure. To open a template from Template Explorer Go to View menu >> Template Explorer or type CTRL+ALT+L. You will find a list of categories click on any category and expand the folder structure. For our sample example let us expand Index Folder. In this folder you will notice the various T-SQL Scripts. These scripts can be opened by double click or can be dragged to editor area and modified as needed. Sample template is now available in the query editor area with all the necessary parameter place folder. You can replace the same parameter by typing either CTRL+SHIFT+M or by going to Query Menu >> Specify Values for Template Parameters. In this screen it will show  Specify Values for Template Parameters dialog box, accept the value or replace it with a new value. This will now get your script ready to go. Check it one more time and change the script to fit your requirement. I personally use template explorer for two things. First one is obviously for templates but the hidden one and an important one is for learning new features and T-SQL commands. There is so much to learn and so little time. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology

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  • check_ssh executed from Nagios server returns "Server answer: ", nothing else

    - by phs
    Commmand works on the host I need to monitor (its IP is denoted as $HOSTADDRESS$ here): [root@host ~]# /usr/local/nagios/libexec/check_ssh localhost SSH OK - OpenSSH_4.3 (protocol 2.0) However, on the Nagios server, it does not: root@server:~# /usr/lib/nagios/plugins/check_ssh -H $HOSTADDRESS$ Server answer: I can see that the port is open: root@server:~# /usr/lib/nagios/plugins/check_tcp -H $HOSTADDRESS$ -p 22 TCP OK - 0.123 second response time on port 22|time=0.123277s;;;0.000000;10.000000 And I can verify with telnet: root@server:/etc/nagios3/conf.d# telnet $HOSTADDRESS$ 22 Trying $HOSTADDRESS$... Connected to $HOSTADDRESS$. Escape character is '^]'. After searching the web for two hours and trying different suggestions I am out of ideas. I have several other hosts with similar setup, and they don't have this problem. I have compared the configs and they look the same (I think). I am clearly missing something here.

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  • Linux 2.6.31 Scheduler and Multithreaded Jobs

    - by dsimcha
    I run massively parallel scientific computing jobs on a shared Linux computer with 24 cores. Most of the time my jobs are capable of scaling to 24 cores when nothing else is running on this computer. However, it seems like when even one single-threaded job that isn't mine is running, my 24-thread jobs (which I set for high nice values) only manage to get ~1800% CPU (using Linux notation). Meanwhile, about 500% of the CPU cycles (again, using Linux notation) are idle. Can anyone explain this behavior and what I can do about it to get all of the 23 cores that aren't being used by someone else? Notes: In case it's relevant, I have observed this on slightly different kernel versions, though I can't remember which off the top of my head. The CPU architecture is x64. Is it at all possible that the fact that my 24-core jobs are 32-bit and the other jobs I'm competing w/ are 64-bit is relevant? Edit: One thing I just noticed is that going up to 30 threads seems to alleviate the problem to some degree. It gets me up to ~2100% CPU.

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  • How to subscribe to the free Oracle Linux errata yum repositories

    - by Lenz Grimmer
    Now that updates and errata for Oracle Linux are available for free (both as in beer and freedom), here's a quick HOWTO on how to subscribe your Oracle Linux system to the newly added yum repositories on our public yum server, assuming that you just installed Oracle Linux from scratch, e.g. by using the installation media (ISO images) available from the Oracle Software Delivery Cloud You need to download the appropriate yum repository configuration file from the public yum server and install it in the yum repository directory. For Oracle Linux 6, the process would look as follows: as the root user, run the following command: [root@oraclelinux62 ~]# wget http://public-yum.oracle.com/public-yum-ol6.repo \ -P /etc/yum.repos.d/ --2012-03-23 00:18:25-- http://public-yum.oracle.com/public-yum-ol6.repo Resolving public-yum.oracle.com... 141.146.44.34 Connecting to public-yum.oracle.com|141.146.44.34|:80... connected. HTTP request sent, awaiting response... 200 OK Length: 1461 (1.4K) [text/plain] Saving to: “/etc/yum.repos.d/public-yum-ol6.repo” 100%[=================================================>] 1,461 --.-K/s in 0s 2012-03-23 00:18:26 (37.1 MB/s) - “/etc/yum.repos.d/public-yum-ol6.repo” saved [1461/1461] For Oracle Linux 5, the file name would be public-yum-ol5.repo in the URL above instead. The "_latest" repositories that contain the errata packages are already enabled by default — you can simply pull in all available updates by running "yum update" next: [root@oraclelinux62 ~]# yum update Loaded plugins: refresh-packagekit, security ol6_latest | 1.1 kB 00:00 ol6_latest/primary | 15 MB 00:42 ol6_latest 14643/14643 Setting up Update Process Resolving Dependencies --> Running transaction check ---> Package at.x86_64 0:3.1.10-43.el6 will be updated ---> Package at.x86_64 0:3.1.10-43.el6_2.1 will be an update ---> Package autofs.x86_64 1:5.0.5-39.el6 will be updated ---> Package autofs.x86_64 1:5.0.5-39.el6_2.1 will be an update ---> Package bind-libs.x86_64 32:9.7.3-8.P3.el6 will be updated ---> Package bind-libs.x86_64 32:9.7.3-8.P3.el6_2.2 will be an update ---> Package bind-utils.x86_64 32:9.7.3-8.P3.el6 will be updated ---> Package bind-utils.x86_64 32:9.7.3-8.P3.el6_2.2 will be an update ---> Package cvs.x86_64 0:1.11.23-11.el6_0.1 will be updated ---> Package cvs.x86_64 0:1.11.23-11.el6_2.1 will be an update [...] ---> Package yum.noarch 0:3.2.29-22.0.1.el6 will be updated ---> Package yum.noarch 0:3.2.29-22.0.2.el6_2.2 will be an update ---> Package yum-plugin-security.noarch 0:1.1.30-10.el6 will be updated ---> Package yum-plugin-security.noarch 0:1.1.30-10.0.1.el6 will be an update ---> Package yum-utils.noarch 0:1.1.30-10.el6 will be updated ---> Package yum-utils.noarch 0:1.1.30-10.0.1.el6 will be an update --> Finished Dependency Resolution Dependencies Resolved ===================================================================================== Package Arch Version Repository Size ===================================================================================== Installing: kernel x86_64 2.6.32-220.7.1.el6 ol6_latest 24 M kernel-uek x86_64 2.6.32-300.11.1.el6uek ol6_latest 21 M kernel-uek-devel x86_64 2.6.32-300.11.1.el6uek ol6_latest 6.3 M Updating: at x86_64 3.1.10-43.el6_2.1 ol6_latest 60 k autofs x86_64 1:5.0.5-39.el6_2.1 ol6_latest 470 k bind-libs x86_64 32:9.7.3-8.P3.el6_2.2 ol6_latest 839 k bind-utils x86_64 32:9.7.3-8.P3.el6_2.2 ol6_latest 178 k cvs x86_64 1.11.23-11.el6_2.1 ol6_latest 711 k [...] xulrunner x86_64 10.0.3-1.0.1.el6_2 ol6_latest 12 M yelp x86_64 2.28.1-13.el6_2 ol6_latest 778 k yum noarch 3.2.29-22.0.2.el6_2.2 ol6_latest 987 k yum-plugin-security noarch 1.1.30-10.0.1.el6 ol6_latest 36 k yum-utils noarch 1.1.30-10.0.1.el6 ol6_latest 94 k Transaction Summary ===================================================================================== Install 3 Package(s) Upgrade 96 Package(s) Total download size: 173 M Is this ok [y/N]: y Downloading Packages: (1/99): at-3.1.10-43.el6_2.1.x86_64.rpm | 60 kB 00:00 (2/99): autofs-5.0.5-39.el6_2.1.x86_64.rpm | 470 kB 00:01 (3/99): bind-libs-9.7.3-8.P3.el6_2.2.x86_64.rpm | 839 kB 00:02 (4/99): bind-utils-9.7.3-8.P3.el6_2.2.x86_64.rpm | 178 kB 00:00 [...] (96/99): yelp-2.28.1-13.el6_2.x86_64.rpm | 778 kB 00:02 (97/99): yum-3.2.29-22.0.2.el6_2.2.noarch.rpm | 987 kB 00:03 (98/99): yum-plugin-security-1.1.30-10.0.1.el6.noarch.rpm | 36 kB 00:00 (99/99): yum-utils-1.1.30-10.0.1.el6.noarch.rpm | 94 kB 00:00 ------------------------------------------------------------------------------------- Total 306 kB/s | 173 MB 09:38 warning: rpmts_HdrFromFdno: Header V3 RSA/SHA256 Signature, key ID ec551f03: NOKEY Retrieving key from http://public-yum.oracle.com/RPM-GPG-KEY-oracle-ol6 Importing GPG key 0xEC551F03: Userid: "Oracle OSS group (Open Source Software group) " From : http://public-yum.oracle.com/RPM-GPG-KEY-oracle-ol6 Is this ok [y/N]: y Running rpm_check_debug Running Transaction Test Transaction Test Succeeded Running Transaction Updating : yum-3.2.29-22.0.2.el6_2.2.noarch 1/195 Updating : xorg-x11-server-common-1.10.4-6.el6_2.3.x86_64 2/195 Updating : kernel-uek-headers-2.6.32-300.11.1.el6uek.x86_64 3/195 Updating : 12:dhcp-common-4.1.1-25.P1.el6_2.1.x86_64 4/195 Updating : tzdata-java-2011n-2.el6.noarch 5/195 Updating : tzdata-2011n-2.el6.noarch 6/195 Updating : glibc-common-2.12-1.47.el6_2.9.x86_64 7/195 Updating : glibc-2.12-1.47.el6_2.9.x86_64 8/195 [...] Cleanup : kernel-firmware-2.6.32-220.el6.noarch 191/195 Cleanup : kernel-uek-firmware-2.6.32-300.3.1.el6uek.noarch 192/195 Cleanup : glibc-common-2.12-1.47.el6.x86_64 193/195 Cleanup : glibc-2.12-1.47.el6.x86_64 194/195 Cleanup : tzdata-2011l-4.el6.noarch 195/195 Installed: kernel.x86_64 0:2.6.32-220.7.1.el6 kernel-uek.x86_64 0:2.6.32-300.11.1.el6uek kernel-uek-devel.x86_64 0:2.6.32-300.11.1.el6uek Updated: at.x86_64 0:3.1.10-43.el6_2.1 autofs.x86_64 1:5.0.5-39.el6_2.1 bind-libs.x86_64 32:9.7.3-8.P3.el6_2.2 bind-utils.x86_64 32:9.7.3-8.P3.el6_2.2 cvs.x86_64 0:1.11.23-11.el6_2.1 dhclient.x86_64 12:4.1.1-25.P1.el6_2.1 [...] xorg-x11-server-common.x86_64 0:1.10.4-6.el6_2.3 xulrunner.x86_64 0:10.0.3-1.0.1.el6_2 yelp.x86_64 0:2.28.1-13.el6_2 yum.noarch 0:3.2.29-22.0.2.el6_2.2 yum-plugin-security.noarch 0:1.1.30-10.0.1.el6 yum-utils.noarch 0:1.1.30-10.0.1.el6 Complete! At this point, your system is fully up to date. As the kernel was updated as well, a reboot is the recommended next action. If you want to install the latest release of the Unbreakable Enterprise Kernel Release 2 as well, you need to edit the .repo file and enable the respective yum repository (e.g. "ol6_UEK_latest" for Oracle Linux 6 and "ol5_UEK_latest" for Oracle Linux 5) manually, by setting enabled to "1". The next yum update run will download and install the second release of the Unbreakable Enterprise Kernel, which will be enabled after the next reboot. -Lenz

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  • SQL SERVER – Where Can YOU Get My Books – SQL Server Interview Question and Answers

    - by pinaldave
    Earlier month I released by third book SQL Server Interview Question and Answers. The focus of this book is ‘master the basics’. If you rate yourself 10 out of 10 in SQL Server – this book is not for you but if you want to learn fundamentals or want to refresh your fundamentals this book is for YOU. Earlier I was overwhelmed by love you all have shown to this book on release date leading our three digit inventory to run out of stock. Read detail blog post about the subject over here A Real Story of Book Getting ‘Out of Stock’ to A 25% Discount Story Available. Well, we learn the lesson from the experience and have made sure that the inventory does not run out any more. Since then we are now available on multiple outlets. Pretty much anywhere in USA and India the book is available. Additionally, where ever Amazon ships internationally. I have created dedicated page where I have listed where one can avail this book from Details of SQL Server Interview Question and Answers. Even though I keep on getting common question like – where one can get this book. You can get this book from: USA: Amazon India: Flipkart | IndiaPlaza | Crossword In India now you can walk into any crossword store and ask this book, if they do not have it, you can ask them get one for you. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Best Practices, Pinal Dave, PostADay, SQL, SQL Authority, SQL Documentation, SQL Download, SQL Interview Questions and Answers, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority Author Visit, SQLAuthority Book Review, SQLAuthority News, T SQL, Technology

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  • SQL SERVER – A Puzzle – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value

    - by pinaldave
    Yesterday my friend Vinod Kumar wrote excellent blog post on SQL Server 2012: Using SEQUENCE. I personally enjoyed reading the content on this subject. While I was reading the blog post, I thought of very simple new puzzle. Let us see if we can try to solve it and learn a bit more about Sequence. Here is the script, which I executed. USE TempDB GO -- Create sequence CREATE SEQUENCE dbo.SequenceID AS BIGINT START WITH 3 INCREMENT BY 1 MINVALUE 1 MAXVALUE 5 CYCLE NO CACHE; GO -- Following will return 3 SELECT next value FOR dbo.SequenceID; -- Following will return 4 SELECT next value FOR dbo.SequenceID; -- Following will return 5 SELECT next value FOR dbo.SequenceID; -- Following will return which number SELECT next value FOR dbo.SequenceID; -- Clean up DROP SEQUENCE dbo.SequenceID; GO Above script gave me following resultset. 3 is the starting value and 5 is the maximum value. Once Sequence reaches to maximum value what happens? and WHY? Bonus question: If you use UNION between 2 SELECT statement which uses UNION, it also throws an error. What is the reason behind it? Can you attempt to answer this question without running this code in SQL Server 2012. I am very confident that irrespective of SQL Server version you are running you will have great learning. I will follow up of the answer in comments below. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – DMV to Identify Incremental Statistics – Performance improvements in SQL Server 2014 – Part 3

    - by Pinal Dave
    This is the third part of the series Incremental Statistics. Here is the index of the complete series. What is Incremental Statistics? – Performance improvements in SQL Server 2014 – Part 1 Simple Example of Incremental Statistics – Performance improvements in SQL Server 2014 – Part 2 DMV to Identify Incremental Statistics – Performance improvements in SQL Server 2014 – Part 3 In earlier two parts we have seen what is incremental statistics and its simple example. In this blog post we will be discussing about DMV, which will list all the statistics which are enabled for Incremental Updates. SELECT  OBJECT_NAME(sys.stats.OBJECT_ID) AS TableName, sys.columns.name AS ColumnName, sys.stats.name AS StatisticsName FROM   sys.stats INNER JOIN sys.stats_columns ON sys.stats.OBJECT_ID = sys.stats_columns.OBJECT_ID AND sys.stats.stats_id = sys.stats_columns.stats_id INNER JOIN sys.columns ON sys.stats.OBJECT_ID = sys.columns.OBJECT_ID AND sys.stats_columns.column_id = sys.columns.column_id WHERE   sys.stats.is_incremental = 1 If you run above script in the example displayed, in part 1 and part 2 you will get resultset as following. When you execute the above script, it will list all the statistics in your database which are enabled for Incremental Update. The script is very simple and effective. If you have any further improved script, I request you to post in the comment section and I will post that on blog with due credit. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: SQL Statistics, Statistics

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  • SQL SERVER – SSMS: Database Consistency History Report

    - by Pinal Dave
    Doctor and Database The last place I like to visit is always a hospital. With the monsoon season starting, intermittent rains, it has become sort of a routine to get a cycle of fever every other year (seriously I hate it). So when I visit my doctor, it is always interesting in the way he quizzes me. The routine question of – “How many days have you had this?”, “Is there any pattern?”, “Did you drench in rain?”, “Do you have any other symptom?” and so on. The idea here is that the doctor wants to find any anomaly or a pattern that will guide him to a viral or bacterial type. Most of the time they get it based on experience and sometimes after a battery of tests. So if there is consistent behavior to your problem, there is always a solution out. SQL Server has its way to find if the server data / files are in consistent state using the DBCC commands. Back to SQL Server In real life, Database consistency check is one of the critical operations a DBA generally doesn’t give much priority. Many readers of my blogs have asked many times, how do we know if the database is consistent? How do I read output of DBCC CHECKDB and find if everything is right or not? My common answer to all of them is – look at the bottom of checkdb (or checktable) output and look for below line. CHECKDB found 0 allocation errors and 0 consistency errors in database ‘DatabaseName’. Above is a “good sign” because we are seeing zero allocation and zero consistency error. If you are seeing non-zero errors then there is some problem with the database. Sample output is shown as below: CHECKDB found 0 allocation errors and 2 consistency errors in database ‘DatabaseName’. repair_allow_data_loss is the minimum repair level for the errors found by DBCC CHECKDB (DatabaseName). If we see non-zero error then most of the time (not always) we get repair options depending on the level of corruption. There is risk involved with above option (repair_allow_data_loss), that is – we would lose the data. Sometimes the option would be repair_rebuild which is little safer. Though these options are available, it is important to find the root cause to the problem. In standard report, there is a report which can show the history of checkdb executed for the selected database. Since this is a database level report, we need to right click on database, click Reports, click Standard Reports and then choose “Database Consistency History” report. The information in this report is picked from default trace. If default trace is disabled or there is no checkdb run or information is not there in default trace (because it’s rolled over), we would get report like below. As we can see report says it very clearly: Currently, no execution history of CHECKDB is available or default trace is not enabled. To demonstrate, I have caused corruption in one of the database and did below steps. Run CheckDB so that errors are reported. Fix the corruption by losing the data using repair option Run CheckDB again to check if corruption is cleared. After that I have launched the report and below is what we would see. If you are lazy like me and don’t want to run the report manually for each database then below query would be handy to provide same report for all database. This query is runs behind the scenes by the report. All I have done is remove the filter for database name (at the last – highlighted). DECLARE @curr_tracefilename VARCHAR(500); DECLARE @base_tracefilename VARCHAR(500); DECLARE @indx INT; SELECT @curr_tracefilename = path FROM sys.traces WHERE is_default = 1; SET @curr_tracefilename = REVERSE(@curr_tracefilename); SELECT @indx  = PATINDEX('%\%', @curr_tracefilename) ; SET @curr_tracefilename = REVERSE(@curr_tracefilename); SET @base_tracefilename = LEFT( @curr_tracefilename,LEN(@curr_tracefilename) - @indx) + '\log.trc'; SELECT  SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),36, PATINDEX('%executed%',TEXTData)-36) AS command ,       LoginName ,       StartTime ,       CONVERT(INT,SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%found%',TEXTData) +6,PATINDEX('%errors %',TEXTData)-PATINDEX('%found%',TEXTData)-6)) AS errors ,       CONVERT(INT,SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%repaired%',TEXTData) +9,PATINDEX('%errors.%',TEXTData)-PATINDEX('%repaired%',TEXTData)-9)) repaired ,       SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%time:%',TEXTData)+6,PATINDEX('%hours%',TEXTData)-PATINDEX('%time:%',TEXTData)-6)+':'+SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%hours%',TEXTData) +6,PATINDEX('%minutes%',TEXTData)-PATINDEX('%hours%',TEXTData)-6)+':'+SUBSTRING(CONVERT(NVARCHAR(MAX),TEXTData),PATINDEX('%minutes%',TEXTData) +8,PATINDEX('%seconds.%',TEXTData)-PATINDEX('%minutes%',TEXTData)-8) AS time FROM::fn_trace_gettable( @base_tracefilename, DEFAULT) WHERE EventClass = 22 AND SUBSTRING(TEXTData,36,12) = 'DBCC CHECKDB' -- AND DatabaseName = @DatabaseName; Don’t get worried about the logic above. All it is doing is reading the trace files, parsing below entry and getting out information for underlined words. DBCC CHECKDB (CorruptedDatabase) executed by sa found 2 errors and repaired 0 errors. Elapsed time: 0 hours 0 minutes 0 seconds.  Internal database snapshot has split point LSN = 00000029:00000030:0001 and first LSN = 00000029:00000020:0001. Hopefully now onwards you would run checkdb and understand the importance of it. As responsible DBAs I am sure you are already doing it, let me know how often do you actually run them on you production environment? Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL Tagged: SQL Reports

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  • SQL Server crashes when remote query fails

    - by Hemanshu Bhojak
    Setup: I have a linked server setup on SQL Server 2005 which is pointing to an Oracle DB. The linked server has RPC enabled. Problem: When a query throws an exception on the remote server (Oracle DB) the SQL Server instance crashes. The logs say that the crash was due to some problem with the RPC call. Is there a way in which I can prevent the entire server to collapse but also use RPC over my linked server. EDIT: Event Log SQL Server is terminating because of fatal exception c0000005. This error may be caused by an unhandled Win32 or C++ exception, or by an access violation encountered during exception handling. Check the SQL error log for any related stack dumps or messages. This exception forces SQL Server to shutdown. To recover from this error, restart the server (unless SQLAgent is configured to auto restart). For more information, see Help and Support Center at http://go.microsoft.com/fwlink/events.asp.

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