Search Results

Search found 33911 results on 1357 pages for 'mysql select'.

Page 25/1357 | < Previous Page | 21 22 23 24 25 26 27 28 29 30 31 32  | Next Page >

  • MySQL Select statement Where table1.id != table2.id

    - by Michael
    I have a table of data which has posts, then I have a separate table of data which has deleted posts. What happens when a post is deleted is that it's ID get's added to the deleted table rather than removing the post entry. What is a clean efficient way of selecting all the posts from the posts table without selecting the ones that have their ID in the deleted table

    Read the article

  • PHP mySQL - select unique value that not being used from dirrefent table

    - by apis17
    Updates : Please see below i have table: data +-----------------------+--------------+-----------+ | State | d_country | d_postcode| +-----------------------+--------------+-----------+ | State1 | Country1 | 1111 | | State2 | Country2 | 2222 | | State3 | Country3 | 3333 | | State4 | Country4 | 4444 | +-----------------------+--------------+-----------+ And another table: user +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name1 | Country3 | 3333 | | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | | Name5 | Country6 | 6666 | +-----------------------+--------------+-----------+ What SQL should i use to: Determine the number (count) of country that are not listed on table data. For example u_postcode is not listed in d_postcode is 5555 and 6666. It will return 2. List down name and what country not available in table data yet. Updates I want to use grouping to filter postcode and make Name3 and Name4 as different rows. For example: +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | +-----------------------+--------------+-----------+ Any possible idea?

    Read the article

  • MySQL query pulling from two tables, display in correct fields

    - by Matt Nathanson
    I'm trying to select all fields in two separate tables as long as they're sharing a common ID. //mysql query $result = mysql_query("SELECT * FROM project, links WHERE project.id = links.id and project.id = $clientID") //displaying the link if ($row['url'] != null){ echo "<div class='clientsection' id='links'>Links</div>"; echo "<a class='clientlink' id='link1' href='" . $row['url'] . "'>" . $row['name'] . "</a>"; } else { echo "<a class='clientlink' id='link1' href='" . $row['url'] . "' style='display:none;'>" . $row['name'] . "</a>"; }; As you can see, my tables are "projects", and "links" Each is sharing a common field "id" for reference. It looks as though where both links.id and project.id are equal, it outputs anything, but when there is no links.id associated with a given $clientID the container relative to the $clientID doesn't display at all. Essentially I'm using this to add links dynamically to a specific client in this CMS and if there are no links, I want the container to show up anyway. Hopefully I've expressed myself clearly, any pointers in the right direction are appreciated. Thanks!

    Read the article

  • MySQL, An Ideal Choice for The Cloud

    - by Bertrand Matthelié
    As the world's most popular web database, MySQL has quickly become the leading database for the cloud, with most providers offering MySQL-based services. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Access our Resource Kit to discover: Why MySQL has become the leading database in the cloud, and how it addresses the critical attributes of cloud-based deployments How ISVs rely on MySQL to power their SaaS offerings Best practices to deploy the world’s most popular open source database in public and private clouds Normal 0 false false false EN-US X-NONE X-NONE You will also find out how you can leverage MySQL together with Hadoop and other technologies to unlock the value of Big Data, either on-premise or in the cloud. Access white papers, webinars, case studies and other resources in /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} our Resource Kit now!

    Read the article

  • MySQL PHP | "SELECT FROM table" using "alphanumeric"-UUID. Speed vs. Indexed Integer / Indexed Char

    - by dropson
    At the moment, I select rows from 'table01' using: SELECT * FROM table01 WHERE UUID = 'whatever'; The UUID column is a unique index. I know this isn't the fastest way to select data from the database, but the UUID is the only row-identifier that is available to the front-end. Since I have to select by UUID, and not ID, I need to know what of these two options I should go for, if say the table consists of 100'000 rows. What speed differences would I look at, and would the index for the UUID grow to large, and lag the DB? Get the ID before doing the "big" select 1. $id = "SELECT ID FROM table01 WHERE UUID = '{alphanumeric character}'"; 2. $rows = SELECT * FROM table01 WHERE ID = $id; Or keep it the way it is now, using the UUID. 1. SELECT FROM table01 WHERE UUID '{alphanumeric character}'; Side note: All new rows are created by checking if the system generated uniqueid exists before trying to insert a new row. Keeping the column always unique. The "example" table. CREATE TABLE Table01 ( ID int NOT NULL PRIMARY KEY, UUID char(15), name varchar(100), url varchar(255), `date` datetime ) ENGINE = InnoDB; CREATE UNIQUE INDEX UUID ON Table01 (UUID);

    Read the article

  • mysql left join queries

    - by Mike79
    I have a question about the snippet below. I'm wondering, if the first query doesn't bring any results, would I still get the results for the second query? select * from ( -- first query ) as query1 left join ( -- second query ) as query2 on query1.id=query2.id left join ( -- third query ) as query3 on query1.id=query3.id; Update: what I need is a full join, however, MySQL does not support it, what would be a good way to emulate this?

    Read the article

  • select query related problem

    - by user222585
    i have interest rate and amount in a table where interest rate are ranged in different values like 4.5,4.6,5.2,5.6 etc. i want to get sum of amounts classified by interest rate where interest rate will be separated by .25. for example all amount having interest rate 1.25,1.3,1.4 will be in one group and 1.5,1.67,1.9 will be in another group how can i write the query?

    Read the article

  • How to proceed setting up a secondary mysql linux slave?

    - by Algorist
    I have a mysql database master and slave in production. I want to setup additional mysql slave. There is around 15 Terabyte of data in the database and there are MYISAM and InnoDB tables in the database. I am thinking of below options: Shutdown master database and copy the mysql data folder to secondary slave. Can Innodb tables be copied like this? Run flush table with read lock, scp the file to new slave and unlock the table and this is possible for myisam tables, can I do the same for innodb tables too? Thanks for looking at the question.

    Read the article

  • How to generate the right password format for Apache2 authentication in use with DBD and MySQL 5.1?

    - by Walkman
    I want to authenticate users for a folder from a MySQL 5.1 database with AuthType Basic. The passwords are stored in plain text (they are not really passwords, so doesn't matter). The password format for apache however only allows for SHA1, MD5 on Linux systems as described here. How could I generate the right format with an SQL query ? Seems like apache format is a binary format with a lenght of 20, but the mysql SHA1 function return 40 long. My SQL query is something like this: SELECT CONCAT('{SHA}', BASE64_ENCODE(SHA1(access_key))) FROM user_access_keys INNER JOIN users ON user_access_keys.user_id = users.id WHERE name = %s where base64_encode is a stored function (Mysql 5.1 doesn't have TO_BASE64 yet). This query returns a 61 byte BLOB which is not the same format that apache uses. How could I generate the same format ? You can suggest other method for this too. The point is that I want to authenticate users from a MySQL5.1 database using plain text as password.

    Read the article

  • What could cause sudden crash of a MySQL 5.0.67 installation?

    - by Alex R
    I have an old Ubuntu 8.10 32-bit with MySQL 5.0.67. There's 5.7GB of data in it and it grows by about 100MB every day. About 3 days ago, the MySQL instance begin dying suddenly and quitely (no log entry) during the nightly mysqldump. What could be causing it? Upgrading MySQL is a long-term project for me, unless there happens to be a specific bug in 5.0.67 then I guess I'll just need to reprioritize. I'm hoping somebody might be familiar with this problem since this is a fairly popular version bundled with Ubuntu 8.10. Thanks

    Read the article

  • Searching phpbb's 'topic_title' via MYSQL php, but exact match doesn't work

    - by Mint
    $sql = sprintf("SELECT topic_title FROM `phpbb_topics` WHERE `topic_title` LIKE '%%%s%%' LIMIT 20", mysql_real_escape_string('match this title')); Which I run this query in phpMyAdmin the results are: (correct) match this title match this title 002 But when I run that same MYSQL query in PHP I get: (incorrect) match this title 002 I have also tried MATCH AGAINST with the same result with both php and phpMyAdmin: $sql = "SELECT topic_title FROM phpbb_topics WHERE MATCH (topic_title) AGAINST('match this title' IN BOOLEAN MODE)"; Whats going on? I'v been searching all over the place and have found next to no help :(

    Read the article

  • MySQL query from subquery not working

    - by James Goodwin
    I am trying to return a number based on the count of results from a table and to avoid having to count the results twice in the IF statement I am using a subquery. However I get a syntax error when trying to run the query, the subquery I have tested by itself runs fine. Any ideas what is wrong with the query? The syntax looks correct to me SELECT IF(daily_count>8000,0,IF(daily_count>6000,1,2)) FROM ( SELECT count(*) as daily_count FROM orders201003 WHERE DATE_FORMAT(date_sub(curdate(), INTERVAL 1 DAY),"%d-%m-%y") = DATE_FORMAT(reqDate,"%d-%m-%y") ) q

    Read the article

  • Optimize this MySQL query?

    - by HipHop-opatamus
    The following query takes FOREVER to execute (30+ hrs on a Macbook w/4gig ram) - I'm looking for ways to make it run more efficiently. Any thoughts are appreciated! CREATE TABLE fc AS SELECT threadid, title, body, date, userlogin FROM f WHERE pid NOT IN (SELECT pid FROM ft) ORDER BY date; (table "f" is ~1 Gig / 1,843,000 row, table "ft" is 168mb, 216,000 rows) )

    Read the article

  • Saving commands for later re-use in MySQL?

    - by Zombies
    What would be the equivalant in MySQL for: Saving a command for later reuse. eg: alias command1='select count(*) from sometable;' Where then I simply type command 1 to get the count for SomeTable. Saving just a string, or rather part of a command. eg: select * from sometable where $complex_where_logic$ order by attr1 desc; WHere $complex_where_logic$ is something I wish to save and not have to keep writing out

    Read the article

  • Get Auto Increment value with MySQL query

    - by James Simpson
    I currently have a database with over 6 million rows and growing. I currently do SELECT COUNT(id) FROM table; in order to display the number to my users, but the database is getting large and I have no need to store all of those rows except to be able to show the number. Is there a way to select the auto_increment value to display so that I can clear out most of the rows in the database? Using LAST_INSERT_ID() doesn't seem to work.

    Read the article

  • mysql query optimisation

    - by Bharanikumar
    i have around (1,049,906 total, Query took 0.0005 sec) in my x table , If i simply retrieve trying to retrive the particular field records , Its tooks hardly 6 mins , This is my query SELECT CUSTOMER_CODE FROM X_TBL ; CUSTOMER_CODE = UNIQUE THE ABOVE QUERY TOOK 6MIN , Tel me optimization tips for this , Also in some situation to search customer , i used the CUSTOMER_CODE in like , select CUSTOMER_CODE from X_TBL WHERE CUSTOMER_CODE LIKE "$KEY_WORD%" Regards Bharanikumar

    Read the article

  • MySQL - Order results by relevancy, LEFT JOINS and more

    - by XaviEsteve
    Hi guys, I am trying to get some results ordered by total votes (where client votes count 2 points and other people votes are 1 point). tab_names: +-----------+ | Name | id | +------+----+ | John | 1 | | Paul | 2 | +------+----+ tab_votes: +--------+-----------+ | idname | ip | +--------+-----------+ | 2 | 127.0.0.1 | | 2 | 127.0.0.1 | | 2 | 82.23.5.1 | | 1 | 127.0.0.1 | +--------+-----------+ This is the MySQL query I've got but doesn't work: SELECT * COUNT(v.idname) AS totalvotes, (SELECT COUNT(v.ip) FROM tab_votes WHERE v.ip LIKE '$ip') AS uservotes FROM tab_names n LEFT JOIN tab_votes v ON n.id = v.idname GROUP BY n.name ORDER BY uservotes DESC, totalvotes DESC LIMIT 40

    Read the article

  • MySQL - Using an alias in a subquery with WHERE clause

    - by gaoshan88
    I have a feeling I am completely borking this MySQL query but I'll ask anyway. I am wondering why I get the warning Unknown column 'FOO', and how I can get this query to work properly, in 'where clause' when I run the following: SELECT sample_id as FOO FROM tbl_test WHERE sample_id = 521 AND sample_id IN ( Select sample_id FROM tbl_test WHERE sample_id = FOO GROUP BY sample_id )

    Read the article

  • Can I do this in one Mysql query?

    - by bsandrabr
    Hi I have a table with two columns: column A column B 1 2 1 2 2 1 I want to return total of ones = 3 total of twos = 3 The best I can come up with is two queries like so: SELECT sum( CASE WHEN columnA =1 THEN 1 ELSE 0 END ) + sum(CASE WHEN columnB =1 THEN 1 ELSE 0 END ) SELECT sum( CASE WHEN columnA =2 THEN 1 ELSE 0 END ) + sum(CASE WHEN columnB =2 THEN 1 ELSE 0 END ) Can this be done in one query? Thanks

    Read the article

  • MySql mutliple tables

    - by Chris Harrison
    I've been looking into JOIN, subqueries and other ways of doing this, but I can't work out the best way to do this is... I have a table (ps_category_product): id_product, id_category I want to perform a query on it like: SELECT id_product FROM ps_category_product WHERE id_category='$this_cat' BUT, I only want to perform this query where the ID's are returned by a query on another table (ps_product): id_product, active SELECT id_product FROM ps_product WHERE active='1' Can anyone help me with getting these two queries working together?

    Read the article

  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

    Read the article

  • Open Source Survey: Oracle Products on Top

    - by trond-arne.undheim
    Oracle continues to work with the open source community to bring the most innovative and productive software to market (more). Oracle products received the most votes in several key categories of the 2010 Linux Journal Reader's Choice Awards. With over 12,000 technologists reporting, these product earned top spots: Best Office Suite: OpenOffice.org Best Single Office Program: OpenOffice.org Writer Best Database: MySQL Best Virtualization Solution: VirtualBox "As the leading open source technology and service provider, Oracle continues to work with the community stakeholders to rapidly innovate many open source products for use in fully tested production environments," says Edward Screven, Oracle's chief corporate architect. "Supporting open source is important to Oracle and our customers, and we continue to invest in it." According to a recent report by the Linux Foundation, Oracle is one of the top ten contributors to the Linux Kernel. Oracle also contributes millions of lines of code to these important projects: OpenJDK: 7,002,579 Eclipse: 1,800,000 (#3 in active committers) MySQL: 5,073,113 NetBeans: 7,870,446 JSF: 701,980 Apache MyFaces Trinidad: 1,316,840 Hudson: 1,209,779 OpenOffice.org: 7,500,000

    Read the article

< Previous Page | 21 22 23 24 25 26 27 28 29 30 31 32  | Next Page >