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  • PHP shell_exec() - Run directly, or perform a cron (bash/php) and include MySQL layer?

    - by Jimbo
    Sorry if the title is vague - I wasn't quite sure how to word it! What I'm Doing I'm running a Linux command to output data into a variable, parse the data, and output it as an array. Array values will be displayed on a page using PHP, and this PHP page output is requested via AJAX every 10 seconds so, in effect, the data will be retrieved and displayed/updated every 10 seconds. There could be as many as 10,000 characters being parsed on every request, although this is usually much lower. Alternative Idea I want to know if there is a better* alternative method of retrieving this data every 10 seconds, as multiple users (<10) will be having this command executed automatically for them. A cronjob running on the server could execute either bash or php (which is faster?) to grab the data and store it in a MySQL database. Then, any AJAX calls to the PHP output would return values in the MySQL database rather than making a direct call to execute server code every 10 seconds. Why? I know there are security concerns with running execs directly from PHP, and (I hope this isn't micro-optimisation) I'm worried about CPU usage on the server. The server is running a sempron processor. Yes, they do still exist. Having this only execute when the user is on the page (idea #1) means that the server isn't running code that doesn't need to be run. However, is this slow and insecure? Just in case the type of linux command may be of assistance in determining it's efficiency: shell_exec("transmission-remote $host:$port --auth $username:$password -l"); I'm hoping that there are differences in efficiency and level of security with the two methods I have outlined above, and that this isn't just micro-micro-optimisation. If there are alternative methods that are better*, I'd love to learn about these! :)

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  • chrome extension login security with iframe

    - by Weaver
    I should note, I'm not a chrome extension expert. However, I'm looking for some advice or high level solution to a security concern I have with my chrome extension. I've searched quite a bit but can't seem to find a concrete answer. The situation I have a chrome extension that needs to have the user login to our backend server. However, it was decided for design reasons that the default chrome popup balloon was undesirable. Thus I've used a modal dialog and jquery to make a styled popup that is injected with content scripts. Hence, the popup is injected into the DOM o the page you are visiting. The Problem Everything works, however now that I need to implement login functionality I've noticed a vulnerability: If the site we've injected our popup into knows the password fields ID they could run a script to continuously monitor the password and username field and store that data. Call me paranoid, but I see it as a risk. In fact,I wrote a mockup attack site that can correctly pull the user and password when entered into the given fields. My devised solution I took a look at some other chrome extensions, like Buffer, and noticed what they do is load their popup from their website and, instead, embed an iFrame which contains the popup in it. The popup would interact with the server inside the iframe. My understanding is iframes are subject to same-origin scripting policies as other websites, but I may be mistaken. As such, would doing the same thing be secure? TLDR To simplify, if I embedded an https login form from our server into a given DOM, via a chrome extension, are there security concerns to password sniffing? If this is not the best way to deal with chrome extension logins, do you have suggestions with what is? Perhaps there is a way to declare text fields that javascript can simply not interact with? Not too sure! Thank you so much for your time! I will happily clarify anything required.

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  • Polling a running php cli script

    - by B_
    I want to run a php script from the command line that is always running and constantly updating a variable. I then want any php script that is run in the meantime (probably but not necessarily from the web) to be able to read that variable at any time. Anyone know how I can do this? Thanks.

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  • PHP SASL(PECL) sasl_server_init(app) works with CLI but not with ApacheModule

    - by ZokRadonh
    I have written a simple auth script so that Webusers can type in their username and password and my PHP script verifies them by SASL. The SASL Library is initialized by php function sasl_server_init("phpfoo"). So phpfoo.conf in /etc/sasl2/ is used. phpfoo.conf: pwcheck_method: saslauthd mech_list: PLAIN LOGIN log_level: 9 So the SASL library now tries to connect to saslauthd process by socket. saslauthd command line looks like this: /usr/sbin/saslauthd -r -V -a pam -n 5 So saslauthd uses PAM to authenticate. In the php script I have created sasl connection by sasl_server_new("php", null, "myRealm"); The first argument is the servicename. So PAM uses the file /etc/pam.d/php to see for further authentication information. /etc/pam.d/php: auth required pam_mysql.so try_first_pass=0 config_file=/etc/pam.d/mysqlconf.nss account required pam_permit.so session required pam_permit.so mysqlconf.nss has all information that is needed for a useful MySQL Query to user table. All of this works perfectly when I run the script by command line. php ssasl.php But when I call the same script via webbrowser(php apache module) I get an -20 return code (SASL_NOUSER). In /var/log/messages there is May 18 15:27:12 hostname httpd2-prefork: unable to open Berkeley db /etc/sasldb2: No such file or directory I do not have anything with a Berkeley db for authentication with SASL. I think authentication using /etc/sasldb2 is the default setting. In my opinion it does not read my phpfoo.conf file. For some reason the php-apache-module ignores the parameter in sasl_server_init("phpfoo"). My first thought was that there is a permission issue. So back in shell: su -s /bin/bash wwwrun php ssasl.php "Authentication successful". - No file-permission issue. In the source of the sasl-php-extension we can find: PHP_FUNCTION(sasl_server_init) { char *name; int name_len; if (zend_parse_parameters(1 TSRMLS_CC, "s", &name, &name_len) == FAILURE) { return; } if (sasl_server_init(NULL, name) != SASL_OK) { RETURN_FALSE; } RETURN_TRUE; } This is a simple pass through of the string. Are there any differences between the PHP CLI and PHP ApacheModule version that I am not aware of? Anyway, there are some interesting log entries when I run PHP in CLI mode: May 18 15:44:48 hostname php: SQL engine 'mysql' not supported May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sqlite May 18 15:44:48 hostname php: sql_select option missing May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sql Those lines are followed by lines of saslauthd and PAM which results in authentication success.(I do not get any of them in ApacheModule mode) Looks like that he is trying auxprop pwcheck before saslauthd. I have no other .conf file in /etc/sasl2. When I change the parameter of sasl_server_init to something other then I get the same error in CLI mode as in ApacheModule mode.

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  • Does PHP have job control like bash does?

    - by Andrew
    Hello, does PHP support something like ampersand in bash (forking)? Let's say I wanted to use cURL on 2 web pages concurrently, so script doesn't have to wait before first cURL command finnishes, how could one achieve that in PHP? Something like this in bash: curl www.google.com & curl www.yahoo.com & wait

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  • Problems with CGI wrapper for PHP

    - by user205878
    I'm having a bugger of a time with a CGI wrapper for PHP. I know very little about CGI and PHP as CGI. Here's what I know about the system: Solaris 10 on a 386 Suhosin PHP normally running as CGI, with cgiwrap (http://cgiwrap.sourceforge.net/). I am not able to find an example wrapper.cgi on the server to look at. Shared hosting (virtual host), so I don't have access to Apache config. But the admins are not helpful. Switching hosts is not an option. Options directive cannot be overridden in .htaccess (ExecCGI, for example). .htaccess: AddHandler php-handler .php Action php-handler "/bin/test.cgi" ~/public_html/bin/test.cgi: #!/usr/bin/sh # Without these 2 lines, I get an Internal Server Error echo "Content-type: text/html" echo "" exec "/path/to/php-cgi" 'foo.php'; /bin/foo.php: <?php echo "this is foo.php!"; Output of http://mysite.com/bin/test.cgi: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; Output of http:/ /mysite.com/anypage.php: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; The things I note are: PHP is being executed, as noted by the X-Powered-By ... header. The source of /bin/test.cgi is output in the results. No matter what I put as the second argument of exec, it isn't passed to the php binary. I've tried '-i' to get phpinfo, '-v' to get the version... When I execute test.cgi via the shell, I get the expected results (the argument is passed to php, and it is reflected in the output). Any ideas about how to get this to work? UPDATE It appears that the reason the source of the test.cgi was appearing was due to errors. Anytime fatal error occurred, either within the cgi itself or with the command being executed by exec, it would cause the source of the cgi to appear. Within test.cgi, I can get the proper output with exec "/path/to/php-cgi" -h (I get the same thing as I would from CLI).

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  • PHP WAMP install php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • PHP WAMP instal php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • Custom Glassfish Security Realm does not work (unable to find LoginModule)

    - by ifischer
    I'm trying to get a Custom Security Realm in Glassfish working (i tried 3.0.1 final and 3.1 B33). I read nearly all tutorials about this, but it doesn not work on my System. I'm getting the error Login failed: javax.security.auth.login.LoginException: unable to find LoginModule class: de.company.security.utility.CustomLoginModule when trying to login. Here is what i did: I created a little Maven project, which contains the needed Realm class, CustomRealm, and the corresponding LoginModule, CustomLoginModule. My pom.xml: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mycompany</groupId> <artifactId>CustomJDBCRealm</artifactId> <version>1.0-SNAPSHOT</version> <packaging>jar</packaging> <name>Custom JDBCRealm</name> <url>http://maven.apache.org</url> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> </properties> <dependencies> <dependency> <groupId>org.glassfish.security</groupId> <artifactId>security</artifactId> <version>3.1-b33</version> </dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</artifactId> <configuration> <source>1.6</source> <target>1.6</target> <optimise>true</optimise> <debug>true</debug> <encoding>UTF-8</encoding> </configuration> </plugin> </plugins> </build> </project> My Custom Realm class: package de.company.security.utility; import com.sun.appserv.security.AppservRealm; import com.sun.enterprise.security.auth.realm.BadRealmException; import com.sun.enterprise.security.auth.realm.InvalidOperationException; import com.sun.enterprise.security.auth.realm.NoSuchRealmException; import com.sun.enterprise.security.auth.realm.NoSuchUserException; import java.util.Enumeration; import java.util.Properties; import java.util.Vector; /** * * @author ifischer */ public class CustomRealm extends AppservRealm { Vector<String> groups = new Vector<String>(); private String jaasCtxName; private String startWith; @Override public void init(Properties properties) throws BadRealmException, NoSuchRealmException { jaasCtxName = properties.getProperty("jaas-context", "customRealm"); startWith = properties.getProperty("startWith", "z"); groups.add("dummy"); } @Override public String getAuthType() { return "Custom Realm"; } public String[] authenticate(String username, char[] password) { // if (isValidLogin(username, password)) return (String[]) groups.toArray(); } @Override public Enumeration getGroupNames(String username) throws InvalidOperationException, NoSuchUserException { return groups.elements(); } @Override public String getJAASContext() { return jaasCtxName; } public String getStartWith() { return startWith; } } My LoginModule class: /* * Copyright (c) 2010 ProfitBricks GmbH. All Rights Reserved. */ package de.company.security.utility; import com.sun.appserv.security.AppservPasswordLoginModule; import com.sun.enterprise.security.auth.login.common.LoginException; import java.util.Set; import org.glassfish.security.common.PrincipalImpl; /** * * @author ifischer */ public class CustomLoginModule extends AppservPasswordLoginModule { @Override protected void authenticateUser() throws LoginException { _logger.info("CustomRealm : authenticateUser for " + _username); final CustomRealm realm = (CustomRealm)_currentRealm; if ( (_username == null) || (_username.length() == 0) || !_username.startsWith(realm.getStartWith())) throw new LoginException("Invalid credentials"); String[] grpList = realm.authenticate(_username, getPasswordChar()); if (grpList == null) { throw new LoginException("User not in groups"); } _logger.info("CustomRealm : authenticateUser for " + _username); Set principals = _subject.getPrincipals(); principals.add(new PrincipalImpl(_username)); this.commitUserAuthentication(grpList); } } I compiled this Maven project and copyied the resulting JAR-file to the Glassfish/lib directory. Then i added the Security Realm "customRealm" to my Glassfish with asadmin: asadmin create-auth-realm --classname de.company.security.utility.CustomRealm --property jaas-context=customRealm:startWith=a customRealm I even referenced the LoginModule class for the JAAS context of my Custom Realm, therefore i inserted this into the login.conf of my domain: customRealm { de.company.security.utility.CustomLoginModule required; }; Although this LoginModule SHOULD BE on the Glassfish classpath, as it's classfiled is packaged in the JAR that i put into the Glassfish/lib-dir, it cannot be found when i try to login. For login, i build a really simple JSF-project, which calls the HttpServletRequest-login-method of Servlet 3.0. When trying to login i'm getting the following Exception: 2010-12-24T14:41:31.613+0100|WARNING|glassfish3.0.1| javax.enterprise.system.container.web.com.sun.web.security|_ThreadID=25; _ThreadName=Thread-1;|Web login failed: Login failed: javax.security.auth.login.LoginException: unable to find LoginModule class: de.company.security.utility.CustomLoginModule Anybody got an idea what i can do that Glassfish loads the LoginModule-class?

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  • PHP: Set max_file_uploads for one file rather than php.ini

    - by Jenkz
    Like many variables in PHP using ini_set() on a page doesn't actually work. I've recently upgraded my PHP version and found that my multiple image uploader is now capped. After 3 hours of frustration, I've found that my new PHP install has the new "max_file_uploads" parameter set to "20". So only the first 7 images get uploaded (each is in three sizes, 7*3=21). I can now change my php.ini value of "max_file_uploads" to 300, but I'd rather not do that side wide. Is there any way to set that value just for a single file (upload.php)? Could a .htaccess file be used for this?

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  • Using PHP with the default Mac Apache + PHP installation

    - by Juan Medín
    Hi, I'm starting to unravel the mysteries of PHP and I configured the pre-installed Snow Leopard PHP and activated the Apache server in the system preferences. So far so good: it works if you put a PHP file in your ~/Sites directory. Since I've my projects in a code/projects directory I created a symbolic link from the ~/Sites dir to the code/projects/one-project/php-dir and bang!, a 403 error: access forbidden. I've been changing the permissions of the dirs to 777, but no luck. Is anyone using the default Snow Leoapard configuration for PHP development and if so, how do you link to your codebase? Thanks in advance, Juan

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  • PHP/Javascript - get php variable within javascript

    - by McNabbToSkins
    I have run into an interesting problem. I am currently developing php page and need to access a php variable within the javascript onload. $(document).ready(function() { var temp = <?php $page_id ?> } is this valid? I know that this might seem weird and not be allowed but I am developing a page that has two popup windows. The windows are created using the same view template and there is no way to distinguish between each other. If I stored a hidden value on the page with information unique to the page like so <input type="hidden" value="<?php $page_id ?> id="page_id" /> if there are two views open at the same time there is no way for me to get a unique page id like so var temp = $("#page_id").val(); Because there are two views witht he same input id that is not unique. Long story short is it valid to reference a php variable in the javascript.

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  • Getting php tips and tutorials as daily emails to improve the knowledge in php programming

    - by Sourabh
    Hi Thanks for your time. This question is related to php programming but not a programming question.I have a young team of php (LAMP + javascript) programmers.I want them to learn better coding and keep themselves updated with the latest advancements in web domain. I was thinking if there was any web site which send daily emails about php questions / problems/ solutions to common problems/ tips which will practically help the people to spend 10-15 minutes daily and enjoy the learning.This will also kind of automate the habit of self learning on daily basis. There are lots of PHP forums and php tutorials website, I tried to google but I did not find any website which does what I am looking for. Please let me know if you know such website.If you have any other ideas to achieve the goal are also welcome. -Sourabh

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  • Error with global variable in php not extending to included php file

    - by phileaton
    I have an html file that calls has a php section in the header like so: $page = basename($_SERVER['PHP_SELF']); Now further down in the html file I have a included footer like so: <?php include("footer.php"); ?> In this script I am referencing the $page variable, but it doesn't find it. I tried echoing the variable and nothing happened. When I place the basename() code in the footer.php file though, it handled it fine. I'd like to be efficient with the coding, so how can I get the footer.php file to get that $page variable? Is there a better way to do this than including the $page variable twice?

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  • Editing PHP using PHP (admin center)

    - by Alec Smart
    Hello, Am developing an admin center where I can edit configuration files (written in PHP). I do NOT want to store these values in a mySQL table (for various reasons). So say my config.php has contents like: <?php $option1 = 1; $option2 = 2; $option4 = 5; $option7 = array('test','a','b',c'); ?> Now say in one of the admin pages I will only be changing a few values like option2 or option4 etc. Any ideas on what would be the best way to go about this. I know one option is to read the PHP file completely and write parts of it using REGEX. Any way to make this more efficent? I don't want the config.php file to break because of some error on the user's end. Any ideas on how to ensure that it works?

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • How to directly send *.php.html files to browser without passing throught PHP? (Apache)

    - by Cédric Girard
    Hi, on my Apache/PHP server, file test.php.html is parsed by PHP, while test.html is not. PHPDOC create a lot of *.php.html files, with a XML header wich is a pain for PHP parser, but how to tell Apache not to pass *.php.html file to PHP and just send back the file to browser? My php.conf file <IfModule prefork.c> LoadModule php5_module modules/libphp5.so </IfModule> <IfModule worker.c> LoadModule php5_module modules/libphp5-zts.so </IfModule> AddHandler php5-script .php AddType text/html .php What can I do? Thanks, Bests regards Cédric

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  • Apache 2.0.55/PHP 5.3.5 Hangs

    - by Rushyo
    Recently inherited a Windows 2k3 server running XAMPP, including ancient copies of PHP, MySQL and Apache. I'm attempting to install a second, up-to-date PHP installation on the machine so I can reference that in future instead of XAMPP's old one. Apache starts up with this new PHP installation happily. Unfortunately, when Apache references the new PHP install, whenever I try a view a page (even a non-PHP page) it hangs. The server simply doesn't respond to any HTTP request - it doesn't crash either. It just sits there with the connection open. There are no errors/warnings/notices in either the PHP or Apache logs. I've pretty much ruled out PHP's extensions (by process of systematic elimination) and most of the INI settings. I've tried reinstalling PHP from scratch. The PHP installation is PHP 5.3.5 x86 thread-safe compiled w/ VC6. The Apache installation is Apache 2.0.55. Anyone encountered similar behaviour?

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  • phpMyAdmin causes php-fpm worker to restart (502 Bad Gateway)

    - by rndbit
    I am trying to set up a test site for myself. Everything works fine except phpMyAdmin. php installation loads my test site scripts, they work fine, however trying to load phpMyAdmin i get 502 Bad Gateway error. Judging from logs (that are not too helpful) it seems that php-fpm worker is crashing each time phpmyadmin is being accessed. No clue how or why.. Does anyone have any idea? nginx log: *3 recv() failed (104: Connection reset by peer) while reading response header from upstream, And php-fpm log: [07-Jun-2012 14:19:51] WARNING: [pool www] child 32179 exited on signal 11 (SIGSEGV) after 3.217902 seconds from start [07-Jun-2012 14:19:51] NOTICE: [pool www] child 32351 started My nginx conf: user nginx; worker_processes 1; error_log /var/log/nginx/error.log; pid /var/run/nginx.pid; events { worker_connections 1024; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; access_log /var/log/nginx/access.log main; sendfile on; keepalive_timeout 65; fastcgi_buffers 8 16k; fastcgi_buffer_size 32k; include /etc/nginx/conf.d/*.conf; server { listen 443 ssl; listen 80; server_name testsite.net www.testsite.net; ssl on; ssl_certificate /var/www/html/admin/ssl/certificate.pem; ssl_certificate_key /var/www/html/admin/ssl/privatekey.pem; ssl_session_timeout 1m; ssl_protocols SSLv2 SSLv3 TLSv1; ssl_ciphers HIGH:!aNULL:!MD5:!kEDH; ssl_prefer_server_ciphers on; access_log off; location ~ \.php$ { root /var/www/html; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include /etc/nginx/fastcgi_params; } location / { root /var/www/html; index index.php; } } } php.ini is standard, with cgi.fix_pathinfo=0 php-fpm.conf: include=/etc/php-fpm.d/*.conf [global] pid = /var/run/php-fpm/php-fpm.pid error_log = /var/log/php-fpm/error.log log_level = notice php-fpm.d/www.conf: [www] listen = 127.0.0.1:9000 listen.allowed_clients = 127.0.0.1 user = nginx group = nginx pm = dynamic pm.max_children = 10 pm.start_servers = 1 pm.min_spare_servers = 1 pm.max_spare_servers = 10 slowlog = /var/log/php-fpm/www-slow.log php_flag[display_errors] = on php_admin_value[error_log] = /var/log/php-fpm/www-error.log php_admin_flag[log_errors] = on

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • How should I set up protection for the database against sql injection when all the php scripts are flawed?

    - by Tchalvak
    I've inherited a php web app that is very insecure, with a history of sql injection. I can't fix the scripts immediately, I rather need them to be running to have the website running, and there are too many php scripts to deal with from the php end first. I do, however, have full control over the server and the software on the server, including full control over the mysql database and it's users. Let's estimate it at something like 300 scripts overall, 40 semi-private scripts, and 20 private/secure scripts. So my question is how best to go about securing the data, with the implicit assumption that sql injection from the php side (e.g. somewhere in that list of 300 scripts) is inevitable? My first-draft plan is to create multiple tiers of different permissioned users in the mysql database. In this way I can secure the data & scripts in most need of securing first ("private/secure" category), then the second tier of database tables & scripts ("semi-private"), and finally deal with the security of the rest of the php app overall (with the result of finally securing the database tables that essentially deal with "public" information, e.g. stuff that even just viewing the homepage requires). So, 3 database users (public, semi-private, and secure), with a different user connecting for each of three different groups of scripts (the secure scripts, the semi-private scripts, and the public scripts). In this way, I can prevent all access to "secure" from "public" or from "semi-private", and to "semi-private" from "public". Are there other alternatives that I should look into? If a tiered access system is the way to go, what approaches are best?

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  • Where is php executable on Ubuntu?

    - by user601L
    I have installed apache and php. I know php works as I have tested a simple php file on apache server. I'm writing a simple webserver which should be able to process php files. So what I want to do is once I get a request for a php file, something like 'exec php test.php' and get the output and pass it to the client. As I'm not much into Ubuntu, I don't know where is the php executable (should be in \bin right?) to do it. But there is no php file inside \bin or \usr\bin. When I run 'which php' it shows nothing. How do I do this?

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  • APC on PHP 5.4 does not seem to be installed after installation

    - by Burning the Codeigniter
    I've recently upgraded to PHP 5.4 from 5.3.6, I did the command apt-get upgrade php5 with the custom PHP 5.4 repo which I added to the apt-get repositories, now that I upgraded, I restarted php-fastcgi and php5-fpm the APC does not seem to be installed with it after I did pecl install apc it seems to configure and install with the details below: Configuring for: PHP Api Version: 20090626 Zend Module Api No: 20090626 Zend Extension Api No: 220090626 But in my phpinfo() I get this: PHP API 20100412 PHP Extension 20100525 Zend Extension 220100525 Which I don't understand, how can I configure PECL to install with PHP 5.4 with my version, my installation with apc.so is stored to /usr/lib/php5/20090626/ however in /usr/lib/php5/ I have two PHP versions: 20090626 20100525 How can I remove either one and leave PHP 5.4 and manage it to install apc in the correct PHP version? I'm running Ubuntu 11.04 on my server. I need help on this please.

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