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  • are there any tree libraries/widgets for (n)curses

    - by phatmanace
    Hi - I wondered if there were any tree libraries available for (n)curses. I'm trying to write a component that shows a tree of folders & was curious if there was a prebuilt curses component that could do this. I've checked 'core' curses as well as libraries like CDK - and I can't seem to find anything. If none exists, I'm not averse to building my own - but I can't seem to locate any decent tutorials on doing this, so any help in this regard would also be much appreciated. Thanks, Ace

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  • Binary Tree operator overloading and recursion

    - by furious.snail
    I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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  • Finding the largest subtree in a BST

    - by rakeshr
    Given a binary tree, I want to find out the largest subtree which is a BST in it. Naive approach: I have a naive approach in mind where I visit every node of the tree and pass this node to a isBST function. I will also keep track of the number of nodes in a sub-tree if it is a BST. Is there a better approach than this ?

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  • what is a performance way to 'tree-walking' through my Entity Framework data

    - by Greg
    Hi, I have a Entity Framework design with a few tables that define a "graph". So there can be a large chain of relationships between objects in the few tables via concept of parent/child relationships. What is a performance way to 'tree-walking' through my Entity Framework data? That is I assume I wouldn't want to load the full set of all NODES and RELATIONSHIPS from the database for the purpose of walking the tree, where the end result may only be identifying leaf nodes? Or would this be OK with the way lazy loading may work at the column/parameter level? Else how could I load just the skeleton of the objects and then when needing to refer to any attributes have them lazy load then?

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  • php tree view with check box

    - by Anup Prakash
    hi friends, I am in great trouble. Actually few months before I made a project in which i used tree view structure for providing page accicibility to different user according to their level in the organisation. But now it is not working and my boss is very angry on me. Now their is some problem in code or you can say that was the demo version. So, can any one help me to find the tree structure in php. Its urgent. Thanx to read this message.

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  • Drupal 6 Redirect automatically when selecting deepest item from a hierarchycal tree

    - by liutis
    Drupal 6, Redirect automatically when selecting deepest item from a hierarchycal tree, like: Tree Parent .|Child 1 ....|_Child 1.1 .|_Child 2 Redirect action must occour only on the last items: Child 1.1 and Child 2 Destination of creat different content types, will be defined in js array. But how to send hierarchical select value to, destination add content type? Maybe like redirect_url?tid_value=value123. I have to save all taxonomy path, but it would be enouth to get deepest one tid value. Should i use multipage approuch here? Any solusion?

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  • How to stop expanding an infinite SWT Tree upon pressing "*"

    - by Lóránt Pintér
    I have an SWT Tree in my application that contains an infinite data structure. Upon expanding an item, I generate its children. On Windows though, users can press "*", triggering an "expand all descendants" action, and my application hangs. There are two acceptable behaviors for me when the user presses "*": Expand all children of the selected element, but only to the next level Do nothing In either case, I will still need to be able to expand items as deep as required (by clicking on the [+] icon, or by pressing "+"), so limiting the tree depth is not a solution. Is there another way that I can achieve either of the above without modifying SWT classes?

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  • How to Check all the nodes in tree view with minimum complexity

    - by Vinni
    I need to check/select all the nodes in a tree view with minimum complexity. My tree view has 3 levels and many nodes in it. below is my code: <asp:TreeView ID="TreeView1" runat="server" DataSourceID="XmlDataSource1" ShowCheckBoxes="All" ShowExpandCollapse="true" <DataBindings> <asp:TreeNodeBinding DataMember="Category" TextField="Name" ValueField="Value" /> <asp:TreeNodeBinding DataMember="LeafCategory" TextField="Name" ValueField="Value" /> <asp:TreeNodeBinding DataMember="ChildCategory" TextField="Name" ValueField="Value" /> <asp:TreeNodeBinding DataMember="SubCategory" TextField="Name" ValueField="Value" /> <asp:TreeNodeBinding DataMember="Categories" TextField="Name" ValueField="Value" /> </DataBindings> </asp:TreeView>

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  • Tree View / File View Control for C#

    - by Jason
    I have been looking for a C# tree control for displaying a file system that has the following capabilities: Select a starting directory. I don't always want to start at a "default" top directory level. The ability to grab an event when the user double clicks on a file in the tree. I want to handle opening the file within my application. I have been looking at this C# File Browser. Unfortunately, I have not been able to figure out how to do meet my second need. (If anybody can clear that up for me, I would like that even better.) Thanks for any help.

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  • wxPython TreeCtrl without showing root while still showing arrows

    - by None
    I am making a python tree visualizer using wxPython. It would be used like so: show_tree([ 'A node with no children', ('A node with children', 'A child node', ('A child node with children', 'Another child')) ]) It worked fine but it shows a root with a value of "Tree". I made it so that it would create multiple roots but then learned that I wasn't allowed to do that. I reverted to the original code but used changed it from this: self.tree = wx.TreeCtrl(self) to this: self.tree = wx.TreeCtrl(self, style=wx.TR_HIDE_ROOT). It worked but it didn't show the little arrows on the side so you wouldn't know which nodes had children. Is there any way to hide the root node but keep the arrows. Note: I am on a Mac using Python version 2.5 and wxPython version 2.8.4.0.

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  • Delete an object from a tree

    - by mqpasta
    I have a Find function in order to find an element from a BST private Node Find(ref Node n, int e) { if (n == null) return null; if (n.Element == e) return n; if (e > n.Element) return Find(ref n.Right, e); else return Find(ref n.Left, e); } and I use following code in order to get a node and then set this node to null. Node x = bsTree.Find(1); x = null; bsTree.Print(); supposedly, this node should be deleted from Tree as it is set to null but it still exists in tree. I had done this before but this time missing something and no idea what.

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  • Problem persisting inheritance tree

    - by alaiseca
    I have a problem trying to map an inheritance tree. A simplified version of my model is like this: @MappedSuperclass @Embeddable public class BaseEmbedded implements Serializable { @Column(name="BE_FIELD") private String beField; // Getters and setters follow } @MappedSuperclass @Embeddable public class DerivedEmbedded extends BaseEmbedded { @Column(name="DE_FIELD") private String deField; // Getters and setters follow } @MappedSuperclass public abstract class BaseClass implements Serializable { @Embedded protected BaseEmbedded embedded; public BaseClass() { this.embedded = new BaseEmbedded(); } // Getters and setters follow } @Entity @Table(name="MYTABLE") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING) public class DerivedClass extends BaseClass { @Id @Column(name="ID", nullable=false) private Long id; @Column(name="TYPE", nullable=false, insertable=false, updatable=false) private String type; public DerivedClass() { this.embedded = new DerivedClass(); } // Getters and setters follow } @Entity @DiscriminatorValue("A") public class DerivedClassA extends DerivedClass { @Embeddable public static NestedClassA extends DerivedEmbedded { @Column(name="FIELD_CLASS_A") private String fieldClassA; } public DerivedClassA() { this.embedded = new NestedClassA(); } // Getters and setters follow } @Entity @DiscriminatorValue("B") public class DerivedClassB extends DerivedClass { @Embeddable public static NestedClassB extends DerivedEmbedded { @Column(name="FIELD_CLASS_B") private String fieldClassB; } public DerivedClassB() { this.embedded = new NestedClassB(); } // Getters and setters follow } At Java level, this model is working fine, and I believe is the appropriate one. My problem comes up when it's time to persist an object. At runtime, I can create an object which could be an instance of DerivedClass, DerivedClassA or DerivedClassB. As you can see, each one of the derived classes introduces a new field which only makes sense for that specific derived class. All the classes share the same physical table in the database. If I persist an object of type DerivedClass, I expect fields BE_FIELD, DE_FIELD, ID and TYPE to be persisted with their values and the remaining fields to be null. If I persist an object of type DerivedClass A, I expect those same fields plus the FIELD_CLASS_A field to be persisted with their values and field FIELD_CLASS_B to be null. Something equivalent for an object of type DerivedClassB. Since the @Embedded annotation is at the BaseClass only, Hibernate is only persisting the fields up to that level in the tree. I don't know how to tell Hibernate that I want to persist up to the appropriate level in the tree, depending on the actual type of the embedded property. I cannot have another @Embedded property in the subclasses since this would duplicate data that is already present in the superclass and would also break the Java model. I cannot declare the embedded property to be of a more specific type either, since it's only at runtime when the actual object is created and I don't have a single branch in the hierarchy. Is it possible to solve my problem? Or should I resignate myself to accept that there is no way to persist the Java model as it is? Any help will be greatly appreciated.

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  • Dojo treemodel- adding large number of items

    - by Ashley
    I am trying to add a large number of items (100+) to my tree via ForestStoreModel by calling newItem in a loop. This seems to be quite slow and locks up the browser. Is there any way I can do something similar to grid's beginUpdate & endUpdate? I want to basically 'turn off' my tree, add 100 items in a batch, then 'turn on' my tree. Any ideas? Thanks!

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  • Find node level in a tree

    - by Álvaro G. Vicario
    I have a tree (nested categories) stored as follows: CREATE TABLE `category` ( `category_id` int(10) unsigned NOT NULL AUTO_INCREMENT, `category_name` varchar(100) NOT NULL, `parent_id` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`category_id`), UNIQUE KEY `category_name_UNIQUE` (`category_name`,`parent_id`), KEY `fk_category_category1` (`parent_id`,`category_id`), CONSTRAINT `fk_category_category1` FOREIGN KEY (`parent_id`) REFERENCES `category` (`category_id`) ON DELETE SET NULL ON UPDATE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_spanish_ci I need to feed my client-side language (PHP) with node information (child+parent) so it can build the tree in memory. I can tweak my PHP code but I think the operation would be way simpler if I could just retrieve the rows in such an order that all parents come before their children. I could do that if I knew the level for each node: SELECT category_id, category_name, parent_id FROM category ORDER BY level -- No `level` column so far :( Can you think of a way (view, stored routine or whatever...) to calculate the node level? I guess it's okay if it's not real-time and I need to recalculate it on node modification.

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  • In B-trees which element gets promoted when the node splits

    - by Phenom
    Let's say there is a B-tree of order 8. This means it can have 8 pointers and 7 elements. Say the letters A through G are stored in this B-tree. So this B-tree is just a single node containing 7 elements. Then you try to insert J into the tree. There's no room, so you have to split the node and create a new root node. Which element gets promoted up into the root node?

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  • Are There Specific CSS Selectors Targeting IE10?

    - by kunambi
    Since IE is getting rid of conditional comments in version 10, I'm in dire need to find a "CSS hack" targeting IE10 specifically. NB! It has to be the selector that's getting "hacked" and not the CSS-properties. In Mozilla, you can use: @-moz-document url-prefix() { h1 { color: red; } } While in Webkit, you usually do: @media screen and (-webkit-min-device-pixel-ratio:0) { h1 { color: blue; } } How would I do something similar in IE10? TYIA.

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  • How do I write a regex that ignores strings starting with a particular prefix, and captures everythi

    - by Mark Rogers
    Background: I'm trying to come up with a regex for a rewrite rule that will take anything that does not start with a particular prefix, and add that prefix to it. But urls that already have the prefix should be rejected by the regular expression (because they already have the url). Example: If the prefix is s1 a string like home will capture the home part. But a string like s1/home, will not capture anything. This way I can add the capture group onto the prefix, so that 'home' will become 's1/home'. I've tried (^s1/), but I'm missing something here, because that rejected 'home' for some reason.

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  • How can I correctly display my AVL Tree in LaTex? A solo left-child hangs straight down....

    - by cb
    The below code almost works perfectly, however the child of 9, 7, hangs straight down instead of as a left-child. How can I correct this? \usepackage{tikz} \usepackage{xytree} \begin{tikzpicture}[level/.style={sibling distance=60mm/#1}] \node [circle,draw] {4} child { node [circle,draw] {2} child {node [circle,draw] {1} } child { node [circle,draw]{3} } } child {node [circle,draw] {6} child {node [circle,draw] {5} } child {node [circle,draw] {9} child {node [circle, draw] {7}} } }; \end{tikzpicture}} Thanks, CB

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  • Linux software to maintain old/backup versions of directory tree

    - by Bittrance
    I am replacing an old Linux file server serving NFS and CIFS. For the new server (still serving CIFS and NFS), I would like to have software that automatically and efficiently maintains old revisions of files in parallel trees, so that they can be accessed by users without special tools. I am looking for software that is akin to Time Machine or Flyback, but works well on a server. The dataset is some 10000 files weighing maybe 60 GB. Changes are relatively few, usually less than 100 files changes daily. Using LVM snapshots will not cut it, as the old revisions must reside on a separate set of disks from the live data. Edit: To clarify: keeping old revisions is non-vital addition to the solution, so any suggestion will have to stay in the range of some hundred euros.

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  • Correcting owner/permissions on damaged directory tree in linux

    - by mcs130
    I inadvertently made a backup copy of a directory recursively and forgot the -a (--preserve) switch when doing so. This damaged my backup directory (which contains data we need to access). The directory and all of its child folders and files comprise an installation of an application including postgress DB and solr files. The original copy was used to for a failed re-config attempt. Now I need to use the backup copy to start over, only the ownership of the backup copy is now root across everything and it is no longer usable (processes won't run due to ownership problems I created when I forgot the -a on the cp -r). I've re-installed a clean copy of the application into a 3rd location now (which has the correct owner/perms) and need to copy the owner/perms from this good directory over onto the damaged directory. What is the best way (if even possible) to do this. (I've Googled and seen things from perl scripting to setfacl/getfacl to do this but am unfortunately still confused). Apologies if this seems a dumb question. Thanks.

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  • Subversion all or nothing access to repo tree

    - by Glader
    I'm having some problems setting up access to my Subversion repositories on a Linux server. The problem is that I can only seem to get an all-or-nothing structure going. Either everyone gets read access to everything or noone gets read or write access to anything. The setup: SVN repos are located in /www/svn/repoA,repoB,repoC... Repositories are served by Apache, with Locations defined in etc/httpd/conf.d/subversion.conf as: <Location /svn/repoA> DAV svn SVNPath /var/www/svn/repoA AuthType Basic AuthName "svn repo" AuthUserFile /var/www/svn/svn-auth.conf AuthzSVNAccessFile /var/www/svn/svn-access.conf Require valid-user </Location> <Location /svn/repoB> DAV svn SVNPath /var/www/svn/repoB AuthType Basic AuthName "svn repo" AuthUserFile /var/www/svn/svn-auth.conf AuthzSVNAccessFile /var/www/svn/svn-access.conf Require valid-user </Location> ... svn-access.conf is set up as: [/] * = [/repoA] * = userA = rw [/repoB] * = userB = rw But checking out URL/svn/repoA as userA results in Access Forbidded. Changing it to [/] * = userA = r [/repoA] * = userA = rw [/repoB] * = userB = rw gives userA read access to ALL repositories (including repoB) but only read access to repoA! so in order for userA to get read-write access to repoB i need to add [/] userA = rw which is mental. I also tried changing Require valid-user to Require user userA for repoA in subversion.conf, but that only gave me read access to it. I need a way to default deny everyone access to every repository, giving read/write access only when explicitly defined. Can anyone tell me what I'm doing wrong here? I have spent a couple of hours testing and googling but come up empty, so now I'm doing the post of shame.

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