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• SQL SERVER – Expanding Views – Contest Win Joes 2 Pros Combo (USD 198) – Day 4 of 5

  - by pinaldave

  August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Which of the following key word will force the query to use indexes created on views? a) ENCRYPTION b) SCHEMABINDING c) NOEXPAND d) CHECK OPTION Query Hints: BIG HINT POST Usually, the assumption is that Index on the table will use Index on the table and Index on view will be used by view. However, that is the misconception. It does not happen this way. In fact, if you notice the image, you will find the both of them (table and view) use both the index created on the table. The index created on the view is not used. The reason for the same as listed in BOL. The cost of using the indexed view may exceed the cost of getting the data from the base tables, or the query is so simple that a query against the base tables is fast and easy to find. This often happens when the indexed view is defined on small tables. You can use the NOEXPAND hint if you want to force the query processor to use the indexed view. This may require you to rewrite your query if you don’t initially reference the view explicitly. You can get the actual cost of the query with NOEXPAND and compare it to the actual cost of the query plan that doesn’t reference the view. If they are close, this may give you the confidence that the decision of whether or not to use the indexed view doesn’t matter. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 4. SQL Joes 2 Pros Development Series – Structured Error Handling SQL Joes 2 Pros Development Series – SQL Server Error Messages SQL Joes 2 Pros Development Series – Table-Valued Functions SQL Joes 2 Pros Development Series – Table-Valued Store Procedure Parameters SQL Joes 2 Pros Development Series – Easy Introduction to CHECK Options SQL Joes 2 Pros Development Series – Introduction to Views SQL Joes 2 Pros Development Series – All about SQL Constraints Next Step: Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• SQL SERVER – Introduction to LEAD and LAG – Analytic Functions Introduced in SQL Server 2012

  - by pinaldave

  SQL Server 2012 introduces new analytical function LEAD() and LAG(). This functions accesses data from a subsequent row (for lead) and previous row (for lag) in the same result set without the use of a self-join . It will be very difficult to explain this in words so I will attempt small example to explain you this function. Instead of creating new table, I will be using AdventureWorks sample database as most of the developer uses that for experiment. Let us fun following query. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result. When we look at above resultset it is very clear that LEAD function gives us value which is going to come in next line and LAG function gives us value which was encountered in previous line. If we have to generate the same result without using this function we will have to use self join. In future blog post we will see the same. Let us explore this function a bit more. This function not only provide previous or next line but it can also access any line before or after using offset. Let us fun following query, where LEAD and LAG function accesses the row with offset of 2. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID,2) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID,2) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result. You can see the LEAD and LAG functions  now have interval of  rows when they are returning results. As there is interval of two rows the first two rows in LEAD function and last two rows in LAG function will return NULL value. You can easily replace this NULL Value with any other default value by passing third parameter in LEAD and LAG function. Let us fun following query. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID,2,0) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID,2,0) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result, where NULL are now replaced with value 0. Just like any other analytic function we can easily partition this function as well. Let us see the use of PARTITION BY in this clause. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result, where now the data is partitioned by SalesOrderID and LEAD and LAG functions are returning the appropriate result in that window. As now there are smaller partition in my query, you will see higher presence of NULL. In future blog post we will see how this functions are compared to SELF JOIN. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• SQL SERVER – OVER clause with FIRST _VALUE and LAST_VALUE – Analytic Functions Introduced in SQL Server 2012 – ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING

  - by pinaldave

  Yesterday I had discussed two analytical functions FIRST_VALUE and LAST_VALUE. After reading the blog post I received very interesting question. “Don’t you think there is bug in your first example where FIRST_VALUE is remain same but the LAST_VALUE is changing every line. I think the LAST_VALUE should be the highest value in the windows or set of result.” I find this question very interesting because this is very commonly made mistake. No there is no bug in the code. I think what we need is a bit more explanation. Let me attempt that first. Before you do that I suggest you read yesterday’s blog post as this question is related to that blog post. Now let’s have fun following query: USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: As per the reader’s question the value of the LAST_VALUE function should be always 114 and not increasing as the rows are increased. Let me re-write the above code once again with bit extra T-SQL Syntax. Please pay special attention to the ROW clause which I have added in the above syntax. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Now once again check the result of the above query. The result of both the query is same because in OVER clause the default ROWS selection is always UNBOUNDED PRECEDING AND CURRENT ROW. If you want the maximum value of the windows with OVER clause you need to change the syntax to UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING for ROW clause. Now run following query and pay special attention to ROW clause again. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Here is the resultset of the above query which is what questioner was asking. So in simple word, there is no bug but there is additional syntax needed to add to get your desired answer. The same logic also applies to PARTITION BY clause when used. Here is quick example of how we can further partition the query by SalesOrderDetailID with this new functions. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us windowed resultset on SalesOrderDetailsID as well give us FIRST and LAST value for the windowed resultset. There are lots to discuss for this two functions and we have just explored tip of the iceberg. In future post I will discover it further deep. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• hql equivalent query to this sql query

  - by sateesh

  Select top 1 from <tablename> what is hql query for the above ?

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• Begin Viewing Query Results Before Query Ends

  - by Frank Developer

  OK, so say I have a table with 500K rows, then I ad-hoc query with unsupported indexing which requires a full table scan. I would like to immediately view the first rows returned while the full table scan continues. Then I want to scroll thru the next results. In the meantime, I would like to display the progress of the table scan, example: "SEARCHING.. FOUND 23 OF 500,000 ROWS SO FAR". If I scroll too far ahead, I want to display a message like: "REACHED LAST ROW IN LOOK-AHEAD BUFFER.. QUERY HAS NOT COMPLETED".. Can this be done? Maybe like: spawn/exec, declare scroll cursor, open, fetch, etc.?

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• SQL query mixing aggregated results and single values

  - by Paul Flowerdew

  I have a table with transactions. Each transaction has a transaction ID, and accounting period (AP), and a posting value (PV), as well as other fields. Some of the IDs are duplicated, usually because the transaction was done in error. To give an example, part of the table might look like: ID PV AP 123 100 2 123 -100 5 In this case the transaction was added in AP2 then removed in AP5. Another example would be: ID PV AP 456 100 2 456 -100 5 456 100 8 In the first example, the problem is that if I am analyzing what was spent in AP2, there is a transaction in there which actually shouldn't be taken into account because it was taken out again in AP5. In the second example, the second two transactions shouldn't be taken into account because they cancel each other out. I want to label as many transactions as possible which shouldn't be taken into account as erroneous. To identify these transactions, I want to find the ones with duplicate IDs whose PVs sum to zero (like ID 123 above) or transactions where the PV of the earliest one is equal to sum(PV), as in the second example. This second condition is what is causing me grief. So far I have SELECT * FROM table WHERE table.ID IN (SELECT table.ID FROM table GROUP BY table.ID HAVING COUNT(*) > 1 AND (SUM(table.PV) = 0 OR SUM(table.PV) = <PV of first transaction in each group>)) ORDER BY table.ID; The bit in chevrons is what I'm trying to do and I'm stuck. Can I do it like this or is there some other method I can use in SQL to do this? Edit 1: Btw I forgot to say that I'm using SQL Compact 3.5, in case it matters. Edit 2: I think the code snippet above is a bit misleading. I still want to mark out transactions with duplicate IDs where sum(PV) = 0, as in the first example. But where the PV of the earliest transaction = sum(PV), as in the second example, what I actually want is to keep the earliest transaction and mark out all the others with the same ID. Sorry if that caused confusion. Edit 3: I've been playing with Clodoaldo's solution and have made some progress, but still can't get quite what I want. I'm trying to get the transactions I know for certain to be erroneous. Suppose the following transactions are also in the table: ID PV AP 789 100 2 789 200 5 789 -100 8 In this example sum(PV) < 0 and the earliest PV < sum(PV) so I don't want to mark any of these out. If I modify Clodoaldo's query as follows: select t.* from t left join ( select id, min(ap) as ap, sum(pv) as sum_pv from t group by id having sum(pv) <> 0 ) s on t.id = s.id and t.ap = s.ap and t.pv = s.sum_pv where s.id is null This gives the result ID PV AP 123 100 2 123 -100 5 456 -100 5 456 100 8 789 100 3 789 200 5 789 -100 8 Whilst the first 4 transactions are ok (they would be marked out), the 789 transactions are also there, and I don't want them. But I can't figure out how to modify the query so that they're not included. Any ideas?

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• SQL SERVER – Weekly Series – Memory Lane – #005

  - by pinaldave

  Here is the list of curetted articles of SQLAuthority.com across all these years. Instead of just listing all the articles I have selected a few of my most favorite articles and have listed them here with additional notes below it. Let me know which one of the following is your favorite article from memory lane. 2006 SQL SERVER – Cursor to Kill All Process in Database I indeed wrote this cursor and when I often look back, I wonder how naive I was to write this. The reason for writing this cursor was to free up my database from any existing connection so I can do database operation. This worked fine but there can be a potentially big issue if there was any important transaction was killed by this process. There is another way to to achieve the same thing where we can use ALTER syntax to take database in single user mode. Read more about that over here and here. 2007 Rules of Third Normal Form and Normalization Advantage – 3NF The rules of 3NF are mentioned here Make a separate table for each set of related attributes, and give each table a primary key. If an attribute depends on only part of a multi-valued key, remove it to a separate table If attributes do not contribute to a description of the key, remove them to a separate table. Correct Syntax for Stored Procedure SP Sometime a simple question is the most important question. I often see in industry incorrectly written Stored Procedure. Few writes code after the most outer BEGIN…END and few writes code after the GO Statement. In this brief blog post, I have attempted to explain the same. 2008 Switch Between Result Pan and Query Pan – SQL Shortcut Many times when I am writing query I have to scroll the result displayed in the result set. Most of the developer uses the mouse to switch between and Query Pane and Result Pane. There are few developers who are crazy about Keyboard shortcuts. F6 is the keyword which can be used to switch between query pane and tabs of the result pane. Interesting Observation – Use of Index and Execution Plan Query Optimization is a complex game and it has its own rules. From the example in the article we have discovered that Query Optimizer does not use clustered index to retrieve data, sometime non clustered index provides optimal performance for retrieving Primary Key. When all the rows and columns are selected Primary Key should be used to select data as it provides optimal performance. 2009 Interesting Observation – TOP 100 PERCENT and ORDER BY If you pull up any application or system where there are more than 100 SQL Server Views are created – I am very confident that at one or two places you will notice the scenario wherein View the ORDER BY clause is used with TOP 100 PERCENT. SQL Server 2008 VIEW with ORDER BY clause does not throw an error; moreover, it does not acknowledge the presence of it as well. In this article we have taken three perfect examples and demonstrated which clause we should use when. Comma Separated Values (CSV) from Table Column A Very common question – How to create comma separated values from a table in the database? The answer is also very common if we use XML. Check out this article for quick learning on the same subject. Azure Start Guide – Step by Step Installation Guide Though Azure portal has changed a quite bit since I wrote this article, the concept used in this article are not old. They are still valid and many of the functions are still working as mentioned in the article. I believe this one article will put you on the track to use Azure! Size of Index Table for Each Index – Solution Earlier I have posted a small question on this blog and requested help from readers to participate here and provide a solution. The puzzle was to write a query that will return the size for each index that is on any particular table. We need a query that will return an additional column in the above listed query and it should contain the size of the index. This article presents two of the best solutions from the puzzle. 2010 Well, this week in 2010 was the week of puzzles as I posted three interesting puzzles. Till today I am noticing pretty good interesting in the puzzles. They are tricky but for sure brings a great value if you are a database developer for a long time. I suggest you go over this puzzles and their answers. Did you really know all of the answers? I am confident that reading following three blog post will for sure help you enhance the experience with T-SQL. SQL SERVER – Challenge – Puzzle – Usage of FAST Hint SQL SERVER – Puzzle – Challenge – Error While Converting Money to Decimal SQL SERVER – Challenge – Puzzle – Why does RIGHT JOIN Exists 2011 DVM sys.dm_os_sys_info Column Name Changed in SQL Server 2012 Have you ever faced a situation where something does not work? When you try to fix it - you enjoy fixing it and started to appreciate the breaking changes. Well, this was exactly I felt yesterday. Before I begin my story, I want to candidly state that I do not encourage anybody to use * in the SELECT statement. Now the disclaimer is over – I suggest you read the original story – you will love it! Get Directory Structure using Extended Stored Procedure xp_dirtree Here is the question to you – why would you do something in SQL Server where you can do the same task in command prompt much easily. Well, the answer is sometime there are real use cases when we have to do such thing. This is a similar example where I have demonstrated how in SQL Server 2012 we can use extended stored procedure to retrieve directory structure. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Memory Lane, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• How to prevent recursive windows when connecting to vncserver on localhost

  - by blog.adaptivesoftware.biz

  I have a VNCServer (vino) configured on my Ubuntu 8.10 box. I would like to connect to this server from a vncclient running on this same machine (the reason for doing this strange thing is mentioned below). Understandably, when I connect to a vncserver on the same box, my vncclient shows recursive windows. Is there a way I can connect to the vncserver on the same machine and not have the recursive windows problem? Perhaps if I could start the vncserver on one display and the client on another display then will it work? How can I do something like this? Note - Reason for running vnc client and server on the same machine: When I start our Java Swing unit test suite, a bunch of swing UI's are created and destroyed as the tests run. These windows fly in the foreground making it impossible to work while the test suite is running. I am hoping to start the test suite within a vncclient so that I can continue working while the tests run.

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• Public Facing Recursive DNS Servers - iptables rules

  - by David Schwartz

  We run public-facing recursive DNS servers on Linux machines. We've been used for DNS amplification attacks. Are there any recommended iptables rules that would help mitigate these attacks? The obvious solution is just to limit outbound DNS packets to a certain traffic level. But I was hoping to find something a little bit more clever so that an attack just blocks off traffic to the victim IP address. I've searched for advice and suggestions, but they all seem to be "don't run public-facing recursive name servers". Unfortunately, we are backed into a situation where things that are not easy to change will break if we don't do so, and this is due to decisions made more than a decade ago before these attacks were an issue.

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• linq to xml query returning a list of all child elements

  - by Xience

  I have got an xml document which looks something like this. <Root> <Info>....</Info> <Info>....</Info> <response>....</response> <warning>....</warning> <Info>....</Info> </Root> How can i write a linqToXML query so that it returns me an IEnumerable containing each child element, in this case all five child elements of , so that i could iterate over them. The order of child elements is not definite, neither is number of times the may appear. Thanks in advance

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• SQL query to return a data that both creteria exist in one table

  - by Ali

  Dear all, I have a TWO tables of data with following fields table1=(ITTAG,ITCODE,ITDESC,SUPcode) table2=(ACCODE,ACNAME,ROUTE,SALMAN) this my customer master tables that contains my customer data such as customer code, customer name and so on... Every Route has a supervisor(table1=supcode) and I need to know supervisor name in my table which both supervisor name and code exist in one table. table1 has contain all names separated by ITTAG. for example, supervisor name's ITTAG='K' also salesamn name's ITTAG='S'. ITTAG ITCODE ITDESC SUPCODE ------ ------ ------ ------- S JT JOHN TOMAS TF K WK VIKI KOO NULL NOW THIS IS A RESULT WHICH I WANT ACCODE ACNAME ROUTE SALEMANNAME SUPERVISORNAME ------- ------ ------ ------------ --------------- IMC1010 ABC HOTEL 01 JOHN TOMAS VIKI KOO i hope this this information is sufficient to get the query.. Thanks Ali

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• mySQL - query to combine two tables

  - by W.Gerick

  Hi there, I have two tables. The first one holds information about cities: Locations: locID | locationID | locationName | countryCode | 1 | 2922239 | Berlin | de | 2 | 291074 | Paris | fr | 3 | 295522 | Orlando | us | 3 | 292345 | Tokyo | jp | There is a second table, which holds alternative names for locations. There might be NO alternative name for a location in the Locations table: AlternateNames: altNameID | locationID | alternateName | 1 | 2922239 | Berlino | 2 | 2922239 | Berlina | 3 | 291074 | Parisa | 4 | 291074 | Pariso | 5 | 295522 | Orlandola | 6 | 295522 | Orlandolo | What I would like to get is the locationID, name and the countryCode of a location for a location name search like "Berlin", or "Ber": | locationID | name | countryCode | | 2922239 | Berlin | de | However, if the user searches for "Berlino", I would like to get the alternateName back: | locationID | name | countryCode | | 2922239 | Berlino | de | The "locationName" has a higher priority than the alternateName, if the searchterm matches both. I can't figure out how to build a query to do that. Since the name can come from one of the two tables, it seems quite difficult to me. Any help is really appreciated!

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• SQL - re-arrange a table via query

  - by abelenky

  I have a poorly designed table that I inherited. It looks like: User Field Value ------------------- 1 name Aaron 1 email [email protected] 1 phone 800-555-4545 2 name Mike 2 email [email protected] 2 phone 777-123-4567 (etc, etc) I would love to extract this data via a query in the more sensible format: User Name Email Phone ------------------------------------------- 1 Aaron [email protected] 800-555-4545 2 Mike [email protected] 777-123-4567 I'm a SQL novice, but have tried several queries with variations of Group By, all without anything even close to success. Is there a SQL technique to make this easy?

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• Mysql Error in query statements

  - by Mark Estrada

  Hi All, I am trying to acquaint myself on Mysql syntax. I only have used MSSQL so far. I downloaded the Mysql Query Browser and have installed the Mysql Version 5.1 I wanted to run this line of code in the resultset tab of mysql but I keep on encountering below error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'declare iCtr int' at line 1 declare iCtr int; set iCtr = 1; while iCtr < 1000 begin insert into employee (emp_id,emp_first_name,emp_last_name,status_id) values (iCtr, 'firstName' + iCtr, 'lastName' + iCtr, 1) set iCtr = iCtr + 1; end I just wanted to populate my employees table but I cannot get past the mysql syntax. Any advise please. Thanks

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• SQL Server Query solution cum Suggestion Required

  - by Nirmal

  Hello All... I have a following scenario in my SQL Server 2005 database. zipcodes table has following fields and value (just a sample): zipcode latitude longitude ------- -------- --------- 65201 123.456 456.789 65203 126.546 444.444 and place table has following fields and value : id name zip latitude longitude -- ---- --- -------- --------- 1 abc 65201 NULL NULL 2 def 65202 NULL NULL 3 ghi 65203 NULL NULL 4 jkl 65204 NULL NULL Now, my requirement is like I want to compare my zip codes of place table and update the available latitude and longitude fields from zipcode table. And there are some of the zipcodes which has no entry in zipcode table, so that should remain null. And the major issue is like I have more then 50,00,000 records in my db. So, query should support this feature. I have tried some of the solutions but unfortunately not getting proper output. Any help would be appreciated...

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• mysql query the latest date

  - by user295189

  I am running this query SEL ECT sh.*, u.initials AS initals FROM database1.table1 AS sh JOIN database2.user AS u ON u.userID = sh.userid WHERE id = 123456 AND dts = ( SELECT MAX(dts) from database1.table1 ) ORDER BY sort_by, category In the table1 I have records like this dts status category sort_by 2010-04-29 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:54 Married Marital Status 2 2010-04-28 12:21:15 Smoker Tobbaco 3 2010-04-27 12:20:27 Civil Engineers Occupation 1 2010-04-27 12:20:54 Married Marital Status 2 2010-04-27 12:21:15 Smoker Tobbaco 3 2010-04-26 12:20:27 Civil Engineers Occupation 1 2010-04-26 12:20:54 Married Marital Status 2 2010-04-26 12:21:15 Smoker Tobbaco 3 so if you look at my data, I am choosing the latest entry by category and sort_id. however in some case such as on 29th (2010-04-29 12:20:27) I have only one record. So in this case I want to show occupation for latest and then the rest of them (latest). But currently it displays only one row. Thanks

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• UriBuilder incorrectly encoding Query Parameters value ?

  - by Fred

  Lets consider the following code sample where a path and single parameter are encoded... Parameter name: "param" Parameter value: "foo/bar?aaa=bbb&ccc=ddd" (happens to be a url with query parameters) String test = UriBuilder.fromPath("https://dummy.com"). queryParam("param", "foo/bar?aaa=bbb&ccc=ddd"). build().toURL().toString(); The encoded URL string returned is: "https://dummy.com?param=foo/bar?aaa%3Dbbb&ccc%3Dddd" Is this correct ? Should not the character "&" (and may be even "?") be encoded in the parameter value string ? Would not the URL produced be interpreted as follow: One first parameter, name="param", value = "ar?aaa%3Dbbb" followed by a second parameter, name="ccc%3Dddd", without value.

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• SQL Query - Count column values separately

  - by user575535

  I have a hard time getting a Query to work right. This is the DDL for my Tables CREATE TABLE Agency ( id SERIAL not null, city VARCHAR(200) not null, PRIMARY KEY(id) ); CREATE TABLE Customer ( id SERIAL not null, fullname VARCHAR(200) not null, status VARCHAR(15) not null CHECK(status IN ('new','regular','gold')), agencyID INTEGER not null REFERENCES Agency(id), PRIMARY KEY(id) ); Sample Data from the Tables AGENCY id|'city' 1 |'London' 2 |'Moscow' 3 |'Beijing' CUSTOMER id|'fullname' |'status' |agencyid 1 |'Michael Smith' |'new' |1 2 |'John Doe' |'regular'|1 3 |'Vlad Atanasov' |'new' |2 4 |'Vasili Karasev'|'regular'|2 5 |'Elena Miskova' |'gold' |2 6 |'Kim Yin Lu' |'new' |3 7 |'Hu Jintao' |'regular'|3 8 |'Wen Jiabao' |'regular'|3 I want to produce the following output, but i need to count separately for ('new','regular','gold') 'city' |new_customers|regular_customers|gold_customers 'Moscow' |1 |1 |1 'Beijing'|1 |2 |0 'London' |1 |1 |0

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• What is wrong with mysql query?

  - by bala3569

  I use the following mysql query, DELIMITER $$ DROP PROCEDURE IF EXISTS `allied`.`aboutus_delete`$$ CREATE DEFINER=`allied`@`%` PROCEDURE `aboutus_delete`( IN p_Id int(11) ) BEGIN if exists(select aboutUsId from aboutus where aboutUsId=p_id and isDeleted=0) update aboutus set isDeleted=1 where aboutUsId=p_id else select 'No record to delete' END$$ DELIMITER ; But i get this error when i execute it... Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'update aboutus set isDeleted=1 where aboutUsId=p_id else select 'No record to' at line 6

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• Join Query returns empty result, unexpected result

  - by Abs

  Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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• Query Concatenated Field (using SubSonic)

  - by jwynveen

  Is there a way to query against a concatenated field using MS SQL? For instance, what I want to do is something like: Select FirstName+' '+LastName as FullName from Attendees where FullName like '%Joe Schmoe%' The above doesn't work. What I have found works is: Select * from Attendee where FirstName+' '+LastName like '%Joe Schmoe%' but I can't figure out how to do that using a SubSonic SqlQuery. I have a number of joins and OR statements added dynamically that I don't want to have to write out the sql manually. Any help/ideas?

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• Query a range of date

  - by juniorSE

  Hello Guys, Im trying to query a sort of from - to date. e.g. 20-01-2010 to 20-02-2010. this should include the mentioned dates. i've tried the following queries but none works. select * from [tableName] where date = '20-01-2010' AND date <= '20-02-2010' the date where date is equal to 20-02-2010 does not show. i don't know why. select * from [tableName] where date between '20-01-2010' AND '20-02-2010' the mentioned dates is not included in the results. i want it to be included in the results. please help. thanks in advance! :)

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• Database query optimization

  - by hdx

  Ok my Giant friends once again I seek a little space in your shoulders :P Here is the issue, I have a python script that is fixing some database issues but it is taking way too long, the main update statement is this: cursor.execute("UPDATE jiveuser SET username = '%s' WHERE userid = %d" % (newName,userId)) That is getting called about 9500 times with different newName and userid pairs... Any suggestions on how to speed up the process? Maybe somehow a way where I can do all updates with just one query? Any help will be much appreciated! PS: Postgres is the db being used.

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• Comparing COUNT values within a query?

  - by outsyncof

  I have the following tables in a relation: person(ssn,sex) employment(ssn,workweeksperyear) assume ssn is a key. My assignment was to do this: Given as input the number of weeks per year a person has worked, determine whether there are more males than females who work more weeks than the input value. SELECT COUNT(sex) AS NumMales FROM person WHERE sex = 'Male' AND ssn IN (SELECT ssn FROM employment WHERE workweeksperyear > 48); The above query gets me the number of males for an input value and I could do the same for number of females but how do I compare the 2 results? Any help will be greatly appreciated!

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• complicated sql query !!

  - by user507779

  LookupTable: userid, mobileid, startedate, enddate , owner 1 , 1 , 12-12-2000, 01-01-2001, asd 2 , 2 , 12-12-2000, 01-01-2001, dgs 3 , 3 , 02-01-2001, 01-01-2002, sdg 4 , 4 , 12-12-2000, 01-01-2001, sdg UserInfoTable: userid, firstname, lastname, address 1 , tom , do , test 2 , sam , smith , asds 3 , john , saw , asdasda 4 , peter , winston , near by Mobile: Mobileid, Name , number, imeinumber 1 , apple , 123 , 1111111 2 , nokia , 456 , 2222222 3 , vodafone , 789 , 3333333 CallLogs: id , Mobileid, callednumbers (string), date , totalduration 1 , 1 , 123,123,321 , 13-12-2000 , 30 2 , 1 , 123,123,321 , 14-12-2000 , 30 3 , 2 , 123,123,321 , 13-12-2000 , 30 4 , 2 , 123,123,321 , 14-12-2000 , 30 5 , 3 , 123,123,321 , 13-12-2000 , 30 6 , 3 , 123,123,321 , 14-12-2000 , 30 1 , 1 , 123,123,321 , 13-01-2002 , 30 2 , 1 , 123,123,321 , 14-01-2002 , 30 I want a query which will return me the following: firstname, lastname, mobile.name as mobilename, callednumbers (as concatinated strings from different rows in CallLogs table) and need it for year 2000 example: firstname, lastname, mobilename, callednumbers tom , do , apple , 123,123,321, 123,123,321 sam , smith , nokia , 123,123,321, 123,123,321 peter , winston , apple , 123,123,321, 123,123,321 any help will be highly appreciated...

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