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  • In dual boot PC, the boot/GRUB menu suddenly disappeared (Ubuntu option is not appearing anymore)

    - by iammilind
    I have been using Ubuntu 13.04 as my primary OS for quite sometime on Sony VAIO laptop with other OS being windows 8 (never use it). Till today, everything was fine. In the evening I had shut down my PC and closed the lid; Typically I do this when the shutting down screen is still on. But probably this time it was fatal. When I again restarted my PC, now no menu is appearing for selecting OS and it directly goes for Windows 8. My question is similar to this thread, but I don't have Ubuntu CD as I had installed using pen drive sometime back. Is there any (genuine or workaround) easier way to get back the GRUB menu back in the place? Note that keyboard shortcuts in Sony VAIO is different, here I have an "Assist" menu as well to get those internal options.

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  • PHP-FPM conf location option when compiling php

    - by Danack
    I'm compiling PHP from source. I would like to set the location that PHP-FPM looks for it's config file. Apparently this option should be set via the configure option: --with-fpm-conf=/etc/php/php-fpm.conf According to http://php-fpm.org/wiki/Configuration_File However using this option on PHP5.5.0 gives the error configure: WARNING: unrecognized options: --with-fpm-conf How do I set where PHP-FPM should look for it's conf file when compiling from source?

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  • T-SQL select where and group by date

    - by bconlon
    T-SQL has never been my favorite language, but I need to use it on a fairly regular basis and every time I seem to Google the same things. So if I add it here, it might help others with the same issues, but it will also save me time later as I will know where to look for the answers!! 1. How do I SELECT FROM WHERE to filter on a DateTime column? As it happens this is easy but I always forget. You just put the DATE value in single quotes and in standard format: SELECT StartDate FROM Customer WHERE StartDate >= '2011-01-01' ORDER BY StartDate 2. How do I then GROUP BY and get a count by StartDate? Bit trickier, but you can use the built in DATEADD and DATEDIFF to set the TIME part to midnight, allowing the GROUP BY to have a consistent value to work on: SELECT DATEADD (d, DATEDIFF(d, 0, StartDate),0) [Customer Creation Date], COUNT(*) [Number Of New Customers] FROM Customer WHERE StartDate >= '2011-01-01' GROUP BY DATEADD(d, DATEDIFF(d, 0, StartDate),0) ORDER BY [Customer Creation Date] Note: [Customer Creation Date] and [Number Of New Customers] column alias just provide more readable column headers. 3. Finally, how can you format the DATETIME to only show the DATE part (after all the TIME part is now always midnight)? The built in CONVERT function allows you to convert the DATETIME to a CHAR array using a specific format. The format is a bit arbitrary and needs looking up, but 101 is the U.S. standard mm/dd/yyyy, and 103 is the U.K. standard dd/mm/yyyy. SELECT CONVERT(CHAR(10), DATEADD(d, DATEDIFF(d, 0, StartDate),0), 103) [Customer Creation Date], COUNT(*) [Number Of New Customers] FROM Customer WHERE StartDate >= '2011-01-01' GROUP BY DATEADD(d, DATEDIFF(d, 0, StartDate),0) ORDER BY [Customer Creation Date]  #

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  • osx 10.6 dhcp client-id option

    - by Clustermagnet
    Trying to join a osx machine on a dhcp network which forces certain client IDs. Even if I was to modify the client-id via the network properties, the DHCP server is not accepting this request, since Windows and Apple send this via different options You can set the ClassID in the Network Control Panel in the DHCP Client ID box. The trick lies in setting up your DHCP server to recognize it. Windows XP sends the DHCP class ID via DHCP option 77, and OS X sends it via option 61. You'll have to set your DHCP server to check for option 61, +with an offset of 1 and a length of 9+. That's the tricky bit. So, without modifying the DHCP server... (which does not belong to me), is there anything that can be done on OSX to modify the client-id option to be 77?

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  • Dual monitor display 12.04?

    - by MrMonty
    I have 2 beautiful 27" asus monitors. I started trying out Ubuntu 12.04 and now only one works and thats vga .. Any help here cause I'm stumped. I have a bfg tech nivida Geforce 8800 gt 512mb and I'm trying to fix this. Getting this error Wen i try to configure the xorg file Failed to set MetaMode (1) 'DFP-0: 1280x1024 @1280x1024 +0+0, DFP-1: 1280x1024 @1280x1024 +1280+0' (Mode 2560x1024, id: 50) on X screen 0. ........................................................................................... This is the xorg.conf ....................................................... nvidia-settings: X configuration file generated by nvidia-settings nvidia-settings: version 295.33 (buildd@allspice) Fri Mar 30 15:25:24 UTC 2012 Section "ServerLayout" Removed Option "Xinerama" "1" Removed Option "Xinerama" "0" Removed Option "Xinerama" "1" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "0" EndSection Section "Files" EndSection Section "InputClass" Identifier "Mouse Remap" MatchProduct "Saitek Cyborg R.A.T.7 Mouse" MatchDevicePath "/dev/input/event*" Option "ButtonMapping" "1 2 3 4 5 6 7 8 9 0 0 0 0 0 0" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" # HorizSync source: edid, VertRefresh source: edid Identifier "Monitor1" VendorName "Unknown" ModelName "Ancor Communications Inc VE247" HorizSync 30.0 - 83.0 VertRefresh 50.0 - 76.0 Option "DPMS" EndSection Section "Monitor" # HorizSync source: edid, VertRefresh source: edid Identifier "Monitor0" VendorName "Unknown" ModelName "Ancor Communications Inc VE247" HorizSync 30.0 - 83.0 VertRefresh 50.0 - 76.0 Option "DPMS" EndSection Section "Device" Identifier "Device1" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro FX 1500" BusID "PCI:1:0:0" Screen 1 EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro FX 1500" EndSection Section "Screen" Identifier "Screen1" Device "Device1" Monitor "Monitor1" DefaultDepth 24 Option "TwinView" "0" Option "TwinViewXineramaInfoOrder" "DFP-1" Option "metamodes" "DFP-1: 1280x1024 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "Screen" Removed Option "TwinView" "0" Removed Option "metamodes" "DFP-0: 1280x1024 +0+0" Removed Option "TwinView" "1" Removed Option "metamodes" "DFP-0: 1280x1024 +0+0, DFP-1: 1280x1024 +1280+0" Removed Option "TwinView" "0" Removed Option "metamodes" "DFP-0: 1280x1024 +0+0" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "TwinView" "1" Option "TwinViewXineramaInfoOrder" "DFP-0" Option "metamodes" "DFP-0: 1280x1024 +0+0, DFP-1: 1280x1024 +1280+0; DFP-1: 1280x1024_60 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "Extensions" Option "Composite" "Disable" EndSection FILE ^^^^

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  • An entry-level programmer's best option [on hold]

    - by user134409
    I am facing a puzzle and I am not sure the best way to make a decision. In my spare time besides playing video games I got around to develop some games, nothing fancy, just small projects to get a better grasp at programming. After I finished college and got my BA in Computer Science, I got a job as web developer at a small firm. The next few months were very stressful as I had no previous experience and tried my best to make up for it. But after 6 months my boss told me I was inefficient and not very independent and let me go. To my credit, the help from the senior was very limited, I did learn a lot but I have learned by myself. For example they told me to do a UI in BackboneJS and I took me a while but I got it working (even if it was poorly designed). But I managed to do it all by myself because my senior was very busy and he did not have time even for my questions. Now I have found a new job again in web development but I am very afraid of what is going to happen next. I am afraid because I don't want to take the job and then be fired again after a couple of months, I get the feeling that this will be very bad on my CV, job hopping is like a red flag. They want to hire me but I am aware that they are working with new technologies and maybe I will end up not coping with it. So the question is: Should a entry-level programmer be better off with a starting job in QA, testing and work his way from there? I did learn allot from my first job but it was a moral blow when they decided to fire me. I do have a low self-esteem and I know my skills as a programmer are not that great. But I like programming and want to get better and I want to have a long career in it so that basically my pickle. Thank you in advance for the answers.

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  • Is software support an option for your career?

    - by Maria Sandu
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 If you have a technical background, why should you choose a career in support? We have invited Serban to answer these questions and to give us an overview of one of the biggest technical teams in Oracle Romania. He’s been with Oracle for 7 years leading the local PeopleSoft Financials & Supply Chain Support team. Back in 2013 Serban started building a new support team in Romania – Fusion HCM. His current focus is building a strong support team for Fusion HCM, latest solution for Business HR Professionals from Oracle. The solution is offered both on Premise (customer site installation) but more important as a Cloud offering – SaaS.  So, why should a technical person choose Software Support over other technical areas?  “I think it is mainly because of the high level of technical skills required to provide the best technical solutions to our customers. Oracle Software Support covers complex solutions going from Database or Middleware to a vast area of business applications (basically covering any needs that a large enterprise may have). Working with such software requires very strong skills both technical and functional for the different areas, going from Finance, Supply Chain Management, Manufacturing, Sales to other very specific business processes. Our customers are large enterprises that already have a support layer inside their organization and therefore the Oracle Technical Support Engineers are working with highly specialized staff (DBA’s, System/Application Admins, Implementation Consultants). This is a very important aspect for our engineers because they need to be highly skilled to match our customer’s specialist’s expectations”.  What’s the career path in your team? “Technical Analysts joining our teams have a clear growth path. The main focus is to become a master of the product they will support. I think one need 1 or 2 years to reach a good level of understanding the product and delivering optimal solutions because of the complexity of our products. At a later stage, engineers can choose their professional development areas based on the business needs and preferences and then further grow towards as technical expert or a management role. We have analysts that have more than 15 years of technical expertise and they still learn and grow in technical area. Important fact is, due to the expansion of the Romanian Software support center, there are various management opportunities. So, if you want to leverage your experience and if you want to have people management responsibilities Oracle Software Support is the place to be!”  Our last question to Serban was about the benefits of being part of Oracle Software Support. Here is what he said: “We believe that Oracle delivers “State of the art” Support level to our customers. This is not possible without high investment in our staff. We commit from the start to support any technical analyst that joins us (being junior or very senior) with any training needs they have for their job. We have various technical trainings as well as soft-skills trainings required for a customer facing professional to be successful in his role. Last but not least, we’re aiming to make Oracle Romania SW Support a global center of excellence which means we’re investing a lot in our employees.”  If you’re looking for a job where you can combine your strong technical skills with customer interaction Oracle Software Support is the place to be! Send us your CV at [email protected]. /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Most common parts of a SELECT SQL query?

    - by jnrbsn
    I'm writing a function that generates a SELECT SQL query. (I'm not looking for a tool that already does this.) My function currently takes the following arguments which correspond to different parts of the SELECT query (the base table name is already known): where order fields joins group limit All of these arguments will be optional so that the function generates something like this by default: SELECT * FROM `table_name` I want to order the arguments so that the most often used parts of a SELECT query are first. That way the average call to the function will use as few of the arguments as possible rather than passing a null value or something like that to skip an argument. For example, if someone wanted to use the 1st and 3rd arguments but not the rest, they might have to pass a null value as the 2nd argument in order to skip it. So, for general purpose use, how should I order the arguments? Edit: To be more precise, out of the query parts I listed above, what is the order from most used to least used? Also, I'm not looking for solutions that allow me to not have to specify the order. Edit #2: The "fields" argument will default to "*" (i.e all fields/columns).

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  • I have reinstalled 12.04 and there is no dual boot option

    - by JuP
    Tonight, I have reinstalled Ubuntu 12.4on Win XP pro machine for a 3rd time. (Uninstalled in between.) Oddly enough, this machine had a dual boot between xp pro & ubuntu for several months before we decided to reinstall everything (because of windows). Have you had any problems with the reboot on XP Pro SP3 with all updates & microsoft essentials? I am not getting a choice of which operating system to boot into, it just boots into windows & does not acknowledge ubuntu!

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  • Thunderbird 3 - leave messages on server option

    - by user13834
    I just installed a new Thunderbird 3 on a few computers and immediately saw that i could not find the "leave messages on server" option... can anyone point that out to me ? On my personal pc i upgraded Thunderbird 2 to 3 and there appears the option, but when i create a new account... i can not find the option, can anyone help me with this ... Best regards, Mike.

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  • after BIOS splash, will not boot -- asks me to select an OS, but it just reboots

    - by user92040
    I'm running Linux Mint 13 MATE 64-bit. Everything has been working for several weeks. Yesterday, when I tried to boot up my computer, after the BIOS screen flashes I reach a screen with a black background that reads at the top: GNU GRUB version1.99-21ubuntu3.4 Then there is a box in which I can select from the following lines: Linux Mint 13 MATE 64-bit, 3.2.0-31-generic (/dev/sdb2) Linux Mint 13 MATE 64-bit, 3.2.0-31-generic (/dev/sdb2) -- recovery mode Previous Linux versions Memory test (memtest86+) Memory test (memtest86+, serial console 115200) At the bottom it reads: Use the ? and ? keys to select which entry is highlighed. Press enter to boot the selected OS, 'e' to edit the commands before booting or 'c' for a command-line. I have no idea why it started doing this and, worse, I have no idea how to get out of here. No matter which option I select, I can't get it to boot the OS. If I select either of the first two, it reboots to splash the BIOS and then I'm right back where I started. If I choose "Previous Linux versions" I get essentially the same screen with only two choices (which are the same as the first two choices listed above, Linux 13 MATE and the recovery mode). Again, choosing either one of those results in a reboot. If I try to run either of the memtest options, it reads: error: unknown command 'linux16', Press any key to continue... Then it brings me back to the same screen Can anyone help me please? Intel Core i5-2500 ASUS P8Z68-V LX Intel Motherboard G. Skill Ripjaws series F3-12800CL9D-8GBRL (4GB x2) Plextor 128GB M5S Series SSD

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  • Affordable SEO Service is the Best Option

    Affordable SEO service is the key to a prosperous online marketing business. There are many ways of doing internet marketing but a few most popular methods that seem to be on the rise include Search Engine Optimization, better known as SEO, Pay Per Click or PPC, Website lead Generations, Google AdSense, online newsletters and online magazines. SEO-service is on the rise in the contemporary world.

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  • No upgrade option when booting from USB (12.04)

    - by Ramzi Njeim
    I am trying to upgrade my ubuntu 11.10, i know that it is better to upgrade using a live cd/usb, i booted from the live usb, followed the instructions as usual, but only found three options: Cleen install Install alongside your other operating systems Other The upgrade choice was missing. I even tried installing it after running ubuntu 12.04 from usb, and ended up with the same result. I have a dual boot Ubuntu 11.10 and Windows 7, i think it is only seeing the windows 7 and missing the ubuntu 11.10 partition. Any help ?

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  • What's wrong with this jQuery? It isn't working as intended

    - by Doug Smith
    Using cookies, I want it to remember the colour layout of the page. (So, if they set the gallery one color and the body background another color, it will save that on refresh. But it doesn't seem to be working. jQuery: $(document).ready(function() { if (verifier == 1) { $('body').css('background', $.cookie('test_cookie')); } if (verifier == 2) { $('#gallery').css('background', $.cookie('test_cookie')); } if (verifier == 3) { $('body').css('background', $.cookie('test_cookie')); $('#gallery').css('background', $.cookie('test_cookie')); } $('#set_cookie').click(function() { var color = $('#set_cookie').val(); $.cookie('test_cookie', color); }); $('#set_page').click(function() { $('body').css('background', $.cookie('test_cookie')); var verifier = 1; }); $('#set_gallery').click(function() { $('#gallery').css('background', $.cookie('test_cookie')); var verifier = 2; }); $('#set_both').click(function() { $('body').css('background', $.cookie('test_cookie')); $('#gallery').css('background', $.cookie('test_cookie')); var verifier = 3; }); }); HTML: <p>Please select a background color for either the page's background, the gallery's background, or both.</p> <select id="set_cookie"> <option value="#1d375a" selected="selected">Default</option> <option value="black">Black</option> <option value="blue">Blue</option> <option value="brown">Brown</option> <option value="darkblue">Dark Blue</option> <option value="darkgreen">Dark Green</option> <option value="darkred">Dark Red</option> <option value="fuchsia">Fuchsia</option> <option value="green">Green</option> <option value="grey">Grey</option> <option value="#d3d3d3">Light Grey</option> <option value="#32cd32">Lime Green</option> <option value="#f8b040">Macaroni</option> <option value="#ff7300">Orange</option> <option value="pink">Pink</option> <option value="purple">Purple</option> <option value="red">Red</option> <option value="#0fcce0">Turquoise</option> <option value="white">White</option> <option value="yellow">Yellow</option> </select> <input type="button" id="set_page" value="Page's Background" /><input type="button" id="set_gallery" value="Gallery's Background" /><input type="button" id="set_both" value="Both" /> </div> </div> </body> </html> Thanks so much for the help, I appreciate it. jsFiddle: http://jsfiddle.net/hL6Ye/

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  • Problem with onMouseOut event with select box options (IE)

    - by nik
    Hello All, The problem I am facing with below code is that whenever I try to select any option from the select box, the mouseout event executed (in IE, Mozilla doing gr8) and option disappear. How can one get over this bug. <select name="ed" id="ed" dir="ltr" style="width:200px;overflow:hidden;" onMouseOver="this.style.width='auto'" onMouseOut="this.style.width='200px';"> <option value="1" selected="selected">click here</option> <option value="1">Samuel Jackson</option> <option value="2">David Nalog</option> <option value="3">This one is a real real big name</option> </select>

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  • Using parameterized function calls in SELECT statements. SQL Server

    - by geekzlla
    I have taken over some code from a previous developer and have come across this SQL statement that calls several SQL functions. As you can see, the function calls in the select statement pass a parameter to the function. How does the SQL statement know what value to replace the variable with? For the below sample, how does the query engine know what to replace nDeptID with when it calls, fn_SelDeptName_DeptID(nDeptID) nDeptID IS a column in table Note. SELECT STATEMENT: SELECT nCustomerID AS [Customer ID], nJobID AS [Job ID], dbo.fn_SelDeptName_DeptID(nDeptID) AS Department, nJobTaskID AS JobTaskID, dbo.fn_SelDeptTaskDesc_OpenTask(nJobID, nJobTaskID) AS Task, nStandardNoteID AS StandardNoteID, dbo.fn_SelNoteTypeDesc(nNoteID) AS [Note Type], dbo.fn_SelGPAStandardNote(nStandardNoteID) AS [Standard Note], nEntryDate AS [Entry Date], nUserName as [Added By], nType AS Type, nNote AS Note FROM Note WHERE nJobID = 844261 ORDER BY nJobID, Task, [Entry Date] ====================== Function fn_SelDeptName_DeptID: ALTER FUNCTION [dbo].[fn_SelDeptName_DeptID] (@iDeptID int) RETURNS varchar(25) -- Used by DataCollection for Job Tracking -- if the Deptartment isnt found return an empty string BEGIN -- Return the Department name for the given DeptID. DECLARE @strDeptName varchar(25) IF @iDeptID = 0 SET @strDeptName = '' ELSE BEGIN SET @strDeptName = (SELECT dName FROM Department WHERE dDeptID = @iDeptID) IF (@strDeptName IS NULL) SET @strDeptName = '' END RETURN @strDeptName END ========================== Thanks in advance.

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  • In SQL, why is "select *, count(*) from sentGifts group by whenSent;" ok, but when "*" and "count(*)

    - by Jian Lin
    In SQL, using the table: mysql> select * from sentGifts; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | | 2 | 2010-04-24 | 123 | 4568 | 2010-04-24 01:56:04 | 100 | | 3 | 2010-04-24 | 123 | NULL | NULL | 1 | | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | 2 | | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | 6 | | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | 6 | +--------+------------+--------+------+---------------------+--------+ 7 rows in set (0.00 sec) The following is OK: mysql> select *, count(*) from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+----------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | count(*) | +--------+------------+--------+------+---------------------+--------+----------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | 1 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | 6 | +--------+------------+--------+------+---------------------+--------+----------+ 2 rows in set (0.00 sec) But suppose we want the count(*) to appear as the first column: mysql> select count(*), * from sentGifts group by whenSent; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* from sentGifts group by whenSent' at line 1 it gave an error. Why is it so and what is a way to fix it? I realized that this is ok: mysql> select count(*), whenSent from sentGifts group by whenSent; +----------+------------+ | count(*) | whenSent | +----------+------------+ | 1 | 2010-03-03 | | 6 | 2010-04-24 | +----------+------------+ 2 rows in set (0.00 sec) but what about the one above that gave an error? thanks.

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  • Using parameterized function calls in SELECT statements. MS SQL Server

    - by geekzlla
    I have taken over some code from a previous developer and have come across this SQL statement that calls several SQL functions. As you can see, the function calls in the select statement pass a parameter to the function. How does the SQL statement know what value to replace the variable with? For the below sample, how does the query engine know what to replace nDeptID with when it calls, fn_SelDeptName_DeptID(nDeptID)? nDeptID IS a column in table Note. SELECT STATEMENT: SELECT nCustomerID AS [Customer ID], nJobID AS [Job ID], dbo.fn_SelDeptName_DeptID(nDeptID) AS Department, nJobTaskID AS JobTaskID, dbo.fn_SelDeptTaskDesc_OpenTask(nJobID, nJobTaskID) AS Task, nStandardNoteID AS StandardNoteID, dbo.fn_SelNoteTypeDesc(nNoteID) AS [Note Type], dbo.fn_SelGPAStandardNote(nStandardNoteID) AS [Standard Note], nEntryDate AS [Entry Date], nUserName as [Added By], nType AS Type, nNote AS Note FROM Note WHERE nJobID = 844261 xORDER BY nJobID, Task, [Entry Date] ====================== Function fn_SelDeptName_DeptID: ALTER FUNCTION [dbo].[fn_SelDeptName_DeptID] (@iDeptID int) RETURNS varchar(25) -- Used by DataCollection for Job Tracking -- if the Deptartment isnt found return an empty string BEGIN -- Return the Department name for the given DeptID. DECLARE @strDeptName varchar(25) IF @iDeptID = 0 SET @strDeptName = '' ELSE BEGIN SET @strDeptName = (SELECT dName FROM Department WHERE dDeptID = @iDeptID) IF (@strDeptName IS NULL) SET @strDeptName = '' END RETURN @strDeptName END ========================== Thanks in advance.

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  • javascript get attribution from select

    - by Yongwei Xing
    Hi all <select id="test"> <option attribut="1">test 1</option> <option attribut="2">test 2</option> <option attribut="3">test 3</option> <option attribut="4">test 4</option> <option attribut="5">test 5</option> </select> I want to get the selected item's attribute, is there any simple way to do it. The native javascript is fine. Best Regards,

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  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

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  • Selecting an option by it's value

    - by Ross
    I'm trying to run this jQuery selector: $("#label option[value=\"newLabel\"]") On the following code: <select name="label" id="label"> <option value="1" label="testLabel">testLabel</option> <option value="newLabel" label="New Label">New Label</option> </select> But the selector just won't find it - can anyone spot where I'm going wrong?

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