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  • Python: How to extract xml embedded in a html file?

    - by georgehu
    I have a html file with xml snipped embedded, the source code is pasted in the pastbin: http://pastebin.com/Hy0QaWk8 my task is to extract the text enclosed in the first textarea, which is a xml snippet, from the html. Without any change to the original snippet. I'm able to get it by using the BeautifulSoup, but it changes all the tag names into lower case.

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  • What's the non brute force way to filter a Python dictionary?

    - by Thierry Lam
    I can filter the following dictionary like: data = { 1: {'name': 'stackoverflow', 'traffic': 'high'}, 2: {'name': 'serverfault', 'traffic': 'low'}, 3: {'name': 'superuser', 'traffic': 'low'}, 4: {'name': 'mathoverflow', 'traffic': 'low'}, } traffic = 'low' for k, v in data.items(): if v['traffic'] == traffic: print k, v Is there an alternate way to do the above filtering?

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  • How to replace&add the dataframe element by another dataframe in Python Pandas?

    - by bigbug
    Suppose I have two data frame 'df_a' & 'df_b' , both have the same index structure and columns, but some of the inside data elements are different: >>> df_a sales cogs STK_ID QT 000876 1 100 100 2 100 100 3 100 100 4 100 100 5 100 100 6 100 100 7 100 100 >>> df_b sales cogs STK_ID QT 000876 5 50 50 6 50 50 7 50 50 8 50 50 9 50 50 10 50 50 And now I want to replace the element of df_a by element of df_b which have the same (index, column) coordinate, and attach df_b's elements whose (index, column) coordinate beyond the scope of df_a . Just like add a patch 'df_b' to 'df_a' : >>> df_c = patch(df_a,df_b) sales cogs STK_ID QT 000876 1 100 100 2 100 100 3 100 100 4 100 100 5 50 50 6 50 50 7 50 50 8 50 50 9 50 50 10 50 50 How to write the 'patch(df_a,df_b)' function ?

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  • speed of map() vs. list comprehension vs. numpy vectorized function in python

    - by mcstrother
    I have a function foo(i) that takes an integer and takes a significant amount of time to execute. Will there be a significant performance difference between any of the following ways of initializing 'a': a = [foo(i) for i in xrange(100)] , a = map(foo, range(100)) , and vfoo = numpy.vectorize(foo) vfoo(range(100)) ? (I don't care whether the output is a list or a numpy array). Is there some other better way of doing this? Thanks.

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  • why can't I use "&&" in python to mean 'and'?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong?

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  • Should I be using abstract methods in this Python scenario?

    - by sfjedi
    I'm not sure my approach is good design and I'm hoping I can get a tip. I'm thinking somewhere along the lines of an abstract method, but in this case I want the method to be optional. This is how I'm doing it now... from pymel.core import * class A(object): def __init__(self, *args, **kwargs): if callable(self.createDrivers): self._drivers = self.createDrivers(*args, **kwargs) select(self._drivers) class B(A): def createDrivers(self, *args, **kwargs): c1 = circle(sweep=270)[0] c2 = circle(sweep=180)[0] return c1, c2 b = B() In the above example, I'm just creating 2 circle arcs in PyMEL for Maya, but I fully intend on creating more subclasses that may or may not have a createDrivers method at all! So I want it to be optional and I'm wondering if my approach is—well, if my approach could be improved?

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  • List in a Python class shares the same object over 2 different instances?

    - by zfranciscus
    I created a class: class A: aList = [] now I have function that instantiate this class and add items into the aList. note: there are 2 items for item in items: a = A(); a.aList.append(item); I find that the first A and the second A object has the same number of items in their aList. I would expect that the first A object will have the first item in its list and the second A object will have the second item in its aList. Can anyone explain how this happens ? PS: I manage to solve this problem by moving the aList inside a constructor : def __init__(self): self.aList = []; but I am still curious about this behavior

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  • How do you check the presence of many keys in a Python dictinary?

    - by Thierry Lam
    I have the following dictionary: sites = { 'stackoverflow': 1, 'superuser': 2, 'meta': 3, 'serverfault': 4, 'mathoverflow': 5 } To check if there are more than one key available in the above dictionary, I will do something like: 'stackoverflow' in sites and 'serverfault' in sites The above is maintainable with only 2 key lookups. Is there a better way to handle checking a large number of keys in a very big dictionary?

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  • how to get the parent dir location using python..

    - by zjm1126
    this code is get the templates/blog1/page.html in b.py: path = os.path.join(os.path.dirname(__file__), os.path.join('templates', 'blog1/page.html')) but i want to get the parent dir location: a |---b.py |---templates |--------blog1 |-------page.html and how to get the a location thanks

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  • Why learn Perl, Python, Ruby if the company is using C++, C# or Java as the application language?

    - by szabgab
    I wonder why would a C++, C#, Java developer want to learn a dynamic language? Assuming the company won't switch its main development language from C++/C#/Java to a dynamic one what use is there for a dynamic language? What helper tasks can be done by the dynamic languages faster or better after only a few days of learning than with the static language that you have been using for several years? Update After seeing the first few responses it is clear that there two issues. My main interest would be something that is justifiable to the employer as an expense. That is, I am looking for justifications for the employer to finance the learning of a dynamic language. Aside from the obvious that the employee will have broader view, the employers are usually looking for some "real" benefit.

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  • How to make if-elif-else statement in python more space-saving?

    - by Neverland
    I have a lot of if-elif-else statements in my code if message == '0' or message == '3' or message == '5' or message == '7': ... elif message == '1' or message == '2' or message == '4' or message == '6' or message == '8': ... else: ... Is it possible to format this in a more space-saving way? I tried it this way: if message == '0' or '3' or '5' or '7': ... elif message == '1' or '2' or '4' or '6' or '8': ... else: ... But without success.

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  • In Python, how do I search a flat file for the closest match to a particular numeric value?

    - by kaushik
    have file data of format 3.343445 1 3.54564 1 4.345535 1 2.453454 1 and so on upto 1000 lines and i have number given such as a=2.44443 for the given file i need to find the row number of the numbers in file which is most close to the given number "a" how can i do this i am presently doing by loading whole file into list and comparing each element and finding the closest one any other better faster method? my code:i need to ru this for different file each time around 20000 times so want a fast method p=os.path.join("c:/begpython/wavnk/",str(str(str(save_a[1]).replace('phone','text'))+'.pm')) x=open(p , 'r') for i in range(6): x.readline() j=0 o=[] for line in x: oj=str(str(line).rstrip('\n')).split(' ') o=o+[oj] j=j+1 temp=long(1232332) end_time=save_a[4] for i in range((j-1)): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i

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  • Why are these strings escaping from my regular expression in python?

    - by dohkoxar
    In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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  • Python: Best practice for including a version number in an app?

    - by Ben
    I have a PyQt application that reads and writes data files. I am including a 'version number' in each file written. This is a simple number similar to: 1.2 or something (major and minor versions). I am doing this so that I can change the format of these data files in future versions and then still correctly parse them simply by checking to see what the version is inside the file. My question is what is the best practice for keeping this number stored inside the app itself. I.e. do I just hard-code the app version number into the class that is responsible for reading and writing files? Or should I have some sort of object/variable stored at the top-level of the app and somehow access it from the class responsible for reading and writing these files. If the latter, how do I store it and how do I access it? Thanks.

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  • How to censor IP addresses in a file with Python?

    - by Julio
    Hello everyone. I have a log file containing some Whois entries with relative IP addresses which I want to censor like: 81.190.123.123 in 81.190.xxx.xxx. Is there a way to make such a conversion and rewrite the file contents without modifying the rest? Thank you for the help!

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