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  • Linker error: wants C++ virtual base class destructor

    - by jdmuys
    Hi, I have a link error where the linker complains that my concrete class's destructor is calling its abstract superclass destructor, the code of which is missing. This is using GCC 4.2 on Mac OS X from XCode. I saw http://stackoverflow.com/questions/307352/g-undefined-reference-to-typeinfo but it's not quite the same thing. Here is the linker error message: Undefined symbols: "ConnectionPool::~ConnectionPool()", referenced from: AlwaysConnectedConnectionZPool::~AlwaysConnectedConnectionZPool()in RKConnector.o ld: symbol(s) not found collect2: ld returned 1 exit status Here is the abstract base class declaration: class ConnectionPool { public: static ConnectionPool* newPool(std::string h, short p, std::string u, std::string pw, std::string b); virtual ~ConnectionPool() =0; virtual int keepAlive() =0; virtual int disconnect() =0; virtual sql::Connection * getConnection(char *compression_scheme = NULL) =0; virtual void releaseConnection(sql::Connection * theConnection) =0; }; Here is the concrete class declaration: class AlwaysConnectedConnectionZPool: public ConnectionPool { protected: <snip data members> public: AlwaysConnectedConnectionZPool(std::string h, short p, std::string u, std::string pw, std::string b); virtual ~AlwaysConnectedConnectionZPool(); virtual int keepAlive(); // will make sure the connection doesn't time out. Call regularly virtual int disconnect(); // disconnects/destroys all connections. virtual sql::Connection * getConnection(char *compression_scheme = NULL); virtual void releaseConnection(sql::Connection * theConnection); }; Needless to say, all those members are implemented. Here is the destructor: AlwaysConnectedConnectionZPool::~AlwaysConnectedConnectionZPool() { printf("AlwaysConnectedConnectionZPool destructor call"); // nothing to destruct in fact } and also maybe the factory routine: ConnectionPool* ConnectionPool::newPool(std::string h, short p, std::string u, std::string pw, std::string b) { return new AlwaysConnectedConnectionZPool(h, p, u, pw, b); } I can fix this by artificially making my abstract base class concrete. But I'd rather do something better. Any idea? Thanks

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  • How to manage db connections on server?

    - by simpatico
    I have a severe problem with my database connection in my web application. Since I use a single database connection for the whole application from singleton Database class, if i try concurrent db operations (two users) the database rollsback the transactions. This is my static method used: All threads/servlets call static Database.doSomething(...) methods, which in turn call the the below method. private static /* synchronized*/ Connection getConnection(final boolean autoCommit) throws SQLException { if (con == null) { con = new MyRegistrationBean().getConnection(); } con.setAutoCommit(true); //TODO return con; } What's the recommended way to manage this db connection/s I have, so that I don't incurr in the same problem.

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  • How to populate gridview on button_click after searching from access database?

    - by Usman
    I am creating a form in c#.net . I want to populate the gridview only on button click with entries meeting search criteria. I have tried but on searching ID it works but on searching FirstName it gives error plz check SQL also. My Code behind private void button1_Click(object sender, EventArgs e) { try { string strConn = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=L:/New project/Project/Project/Data.accdb"; string sql = "SELECT * FROM AddressBook WHERE FirstName='" + textBox1.Text.ToString(); OleDbConnection connection = new OleDbConnection(strConn); OleDbDataAdapter dataadapter = new OleDbDataAdapter(sql, connection); DataSet ds = new DataSet(); connection.Open(); dataadapter.Fill(ds, "AddressBook"); connection.Close(); dataGridView1.DataSource = ds; dataGridView1.DataMember = "AddressBook"; } catch (System.Exception err) { this.label27.Visible = true; this.label27.Text = err.Message.ToString(); } }

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  • What To Do If You Get a Virus on Your Computer

    - by Chris Hoffman
    Whether you saw a message saying a virus was detected or your computer seems slow and unreliable, this guide will walk you through the process of dealing with your infection and removing the malware. While many viruses and other types of malware are designed simply to cause chaos, more and more malware is used by organized crime to steal credit card numbers and other sensitive data. Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference

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  • HTG Explains: Live File System vs. Mastered Disc Formats in Windows

    - by Chris Hoffman
    When burning a CD or DVD with Windows, you’ll be asked whether you want to use a Live File System or a Mastered disc format. Each has its own advantages and disadvantages. Windows 7 refers to this as “Like a USB flash drive” or “With a CD/DVD player.” But how exactly can a non-rewritable disc function like a USB flash drive? HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems

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  • SQLite Transaction fills a table BEFORE the transaction is commited

    - by user1500403
    Halo I have a code that creates a datatable (in memory) from a select SQL statement. However I realised that this datatable is filling during the procedure rather as a result of the transaction comit statment, it does the job but its slow. WHat amI doing wrong ? Inalready.Clear() 'clears a dictionary Using connection As New SQLite.SQLiteConnection(conectionString) connection.Open() Dim sqliteTran As SQLite.SQLiteTransaction = connection.BeginTransaction() Try oMainQueryR = "SELECT * FROM detailstable Where name= :name AND Breed= :Breed" Dim cmdSQLite As SQLite.SQLiteCommand = connection.CreateCommand() Dim oAdapter As New SQLite.SQLiteDataAdapter(cmdSQLite) With cmdSQLite .CommandType = CommandType.Text .CommandText = oMainQueryR .Parameters.Add(":name", SqlDbType.VarChar) .Parameters.Add(":Breed", SqlDbType.VarChar) End With Dim c As Long = 0 For Each row As DataRow In list.Rows 'this is the list with 500 names If Inalready.ContainsKey(row.Item("name")) Then Else c = c + 1 Form1.TextBox1.Text = " Fill .... " & c Application.DoEvents() Inalready.Add(row.Item("name"), row.Item("Breed")) cmdSQLite.Parameters(":name").Value = row.Item("name") cmdSQLite.Parameters(":Breed").Value = row.Item("Breed") oAdapter.Fill(newdetailstable) End If Next oAdapter.FillSchema(newdetailstable, SchemaType.Source) Dim z = newdetailstable.Rows.Count 'At this point the newdetailstable is already filled up and I havent even comited the transaction ' sqliteTran.Commit() Catch ex As Exception End Try End Using

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  • problem configure JBoss to work with JNDI(2)

    - by Spiderman
    in continuation to the question from last week: http://stackoverflow.com/questions/2828237/problem-configure-jboss-to-work-with-jndi I'm trying to bind datasource in JBoss and use it in my application. In my struggling, I already managed to avoid the javax.naming.NameNotFoundException by: 1. using in java new InitialContext().lookup(connection); instead of new JndiObjectFactoryBean().setJndiName(connection); 2. changing the connection name from: 'jndi-name' to 'java:jndi-name' Now the problem is that the datasouce that I get from the lookup is null. I created the datsource file: <datasources> <local-tx-datasource> <jndi-name>bilby</jndi-name> <connection-url>jdbc:oracle:myURL</connection-url> <driver-class>oracle.jdbc.OracleDriver </driver-class> <user-name>myUsername</user-name> <password>myPassword</password> <exception-sorter-class- name>org.jboss.resource.adapter.jdbc.vendor.OracleExceptionSorter</exception-sorter-class-name> <metadata> <type-mapping>Oracle9i</type-mapping> </metadata> </local-tx-datasource> </datasources> and put it under \server\default\deploy\oracle-ds.xml I get during runtime the line: 18:37:56,560 INFO [ConnectionFactoryBindingService] Bound ConnectionManager 'jb oss.jca:service=DataSourceBinding,name=bilby' to JNDI name 'java:bilby' So my question is - why do I get null as my datasource???

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  • Hacking Smart Phones

    Rootkits used to show smart phones can be hacked, hijacked and exploited without their owner's knowledge Operating system - Shopping - Consumer Electronics - Communications - Wireless

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  • how to get inbox mails in listview using vb.net?

    - by meenakshi
    I'm trying to collect (yahoo,gmail,hotmail etc.,)inbox mails uding vb.net? i tried this using tcpclient, First i got the tcpclient connection,and get response data from server for (gmail --host-- "pop.gmail.com") got response like "+OK Gpop ready for requests from 122.174.183.249 b15pf3378725rvn.27" second,i'm trying to get response data from server for my username and password it shows message "Unable to read data from the transport connection: An established connection was aborted by the software in your host machine." how can i solve this? Please help me.

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  • Need to get Multiple tables from SqlServer at a time

    - by narmadha
    Hi ,I am working with C#.net,I am using cursor concept in my storedprocedure,While executing it in Sqlserver it is showing Multiple tables,but it is not returning multiple Tables in the code,it is returning only the first table,The following is the code which i have used: DataSet ds = new DataSet("table1"); using (SqlConnection connection = new SqlConnection(connectionstring)) { using (SqlDataAdapter da = new SqlDataAdapter("getworkpersondetails_Orderidwise", connection)) { da.SelectCommand.CommandType = CommandType.StoredProcedure; SqlParameter param; param = new SqlParameter("@OrderId", SqlDbType.Int); param.Value = OrderId; da.SelectCommand.Parameters.Add(param); param = new SqlParameter("@CompanyId", SqlDbType.Int); param.Value = CompanyId; da.SelectCommand.Parameters.Add(param); connection.Open(); da.Fill(ds); connection.Close(); return ds; } }

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  • How To Enable Do Not Track In Every Web Browser

    - by Chris Hoffman
    We’ve covered why “Do Not Track” isn’t a silver bullet that prevents you from being tracked. However, if you don’t like being tracked and want to express that preference to websites, you can enable “Do Not Track” in every browser. To Google’s credit, future versions of Chrome explain exactly what Do Not Track does when you enable it. Remember that, by enabling Do Not Track, you’re just expressing a preference. Websites may or may not obey your preference. Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference

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  • Why do sockets not die when server dies? Why does a socket die when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • How Hot Can It Get? [Video]

    - by Asian Angel
    The coldest temperature possible is zero degrees Kelvin, but how hot do you think it can actually get? Watch as Vsauce discusses the varying levels of temperatures, what happens at those levels, and ends with the hottest possible temperature known to humanity. How Hot Can It Get? [via Geeks are Sexy] Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference

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  • How to connect to the internet via command line or graphical utility given I can't click at the top of the screen?

    - by Ben
    My Ubuntu 12.04 installation has an input problem resulting preventing me from clicking near the top of the screen. That is, there is an unclickable area, circa 60 pixels high and stretching all the way across the screen. I will ask about this in a later question. For now, I would just like to be able to connect to the internet, given this limitation. I am able to access the network connections application by hitting the super key and typing "network connections". There is a LAN and a wireless network available. The network icon in the bar at the top of the screen shows an empty wedge, which I suppose means that wireless is off. I've attached the cable for the Ethernet connection, but it does not seem to have connected automatically. How can I figure out what's going on? (I'll happily edit in the output of any relevant terminal commands.) Thank you.

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  • NSURLConnection shown as leaking in instruments

    - by Gyozo Kudor
    Hello another stupid question regarding leaks and also NSURLConnection. How do i release it? Is it enough if i release in the following 2 methods? (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error (void)connectionDidFinishLoading:(NSURLConnection *)connection Because in instruments it shows me the line where I alloc my connection as the source of leaking. OK I don't get it. After the following code my urlConnection has a retain count of 2. WTF? NSURLConnection *urlConnection = [[NSURLConnection alloc] initWithRequest: urlRequest delegate: self]; This is the line that instruments points me to. I find this very weird.

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  • Persistent connections with pipelining

    - by Summer_More_More_Tea
    Hi: I have a question about the behavior of a browser( especially Firefox ) tackling with persistent connections: Must all the requests sent in one pipelined persistent connection direct to the same server? What about a request specified by user from address bar -- may it reuse an already established persistent connection to send its request or need another connection? Regards.

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  • Server-side application configuration security. Best practices

    - by Andrew Florko
    We publish server-side application to our customer workstation and customer's security guys are concerned about configuration connection strings safety. Connection strings are stored as plain text right now, but as configuration file is not in the public/shared folder we supposed that workstation security itself is enough. What are the ways to improve connection strings security further? It is a big step forward to encrypt password and keep a decryption key on the same workstation? What are the steps we can take to keep connection strings (and alike) information more and more securable? Thank you in advance!

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  • Angry Birds and Star Wars Join Forces for an Awesome New Edition [Plus Wallpaper!]

    - by Asian Angel
    Are you ready for a new version of Angry Birds? Then rejoice, you are less than a month away from an awesome new release of everyone’s favorite bird-slinging, pig smashing game! Prepare for a journey to a galaxy far, far away… From the blog post: From the deserts of Tatooine to the depths of the Death Star – the game and merchandise will feature the Angry Birds characters starring as the iconic heroes of the beloved Saga. In the coming weeks, fans can expect additional new videos, characters, and much more exciting content to be revealed. The game will be available on iOS, Android, Amazon Kindle Fire, Mac, PC, Windows Phone and Windows 8. Here is the first of the promo videos for the new version. Also, make sure to download the first official wallpaper (linked to below)! How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems 7 Ways To Free Up Hard Disk Space On Windows

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  • How to scan for available networks for Blackberry device from application?

    - by amsiddh
    Hi All, Is there any RIM API available which will help to get the list of available network service or only Wi-Fi networks for a device and set selected network access point for any network communications? Is it possible programmatically to disable the Mobile networks like GPRS, WAP, etc? For Ex: When a application is started it should scan for WiFi connections (even if there are no previous WiFi network access points are set on device) and list the available WiFi connection. Then user will select the appropriate WiFi connection to connect for any network communication. Outside the application any internet communication (like browser or any other application) should done through same selected WiFi connection. The scanning for WiFi and setting the connection is almost similar to Blackberry WiFi Setup. If anyone know how to implement this using available RIM API and let me know its possible or not. Please share if anyone have any code snippet related to this. I am looking for OS v4.5, 4.7, and 5.0. Thanks, siddh.

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  • Java Desktop app with Ms Access.

    - by zayar
    My Db connection is error "class not found exception!". I want to show in java jTable with query result.. static Connection databaseConnection()throws ClassNotFoundException{ Connection con=null; File file=new File("PlayDb/PlayIS.mdb"); try{ Class.forName("sun.jdbc.odbc.jdbcodbcDriver"); con =DriverManager.getConnection("jdbc:odbc:Driver="+"{Microsoft Access Driver(*.mdb,*.accdb)};DBQ="+file.getAbsoluteFile()); System.out.print("Success con!!"); } catch(Exception e){ System.out.print("connection fail!!"); e.printStackTrace(); } return con; }

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  • Java and Jasper

    - by bhargava
    Hey Guys, I have integrated Jasper Reports on my netbeans platform and i am able to generate reports using the following code. Map<String, Object> params = new HashMap<String, Object>(); Connection conn = DriverManager.getConnection("databaseUrl", "userid","password"); JasperReport jasperReport = JasperCompileManager.compileReport(reportSource); JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, conn); JasperExportManager.exportReportToHtmlFile(jasperPrint, reportDest); JasperViewer.viewReport(jasperPrint); This stuff works perfect. But not i am trying to integrate Jasper with GWT.I have my server as glass fish server. I am getting the Connection object using the followind code. public static Connection getConnection() { try { String JNDI = "JNDI name"; InitialContext initCtx = new InitialContext(); javax.sql.DataSource ds = (javax.sql.DataSource) initCtx.lookup(JNDI); Connection conn = (Connection) ds.getConnection(); return conn; } catch (Exception ex) { ex.printStackTrace(); } return null; } and then Map params = new HashMap(); JasperReport jasperReport = JasperCompileManager.compileReport(reportSource); JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, getConnection()); JasperExportManager.exportReportToHtmlFile(jasperPrint, reportDest); JasperViewer.viewReport(jasperPrint); but i always get Error.I am implementing this on Server.I am having RPC calls to get this method to work when a button is clicked. Can you please help me how to work on this.(That is to integrate Jasper reports with GWT). I would highly appreciate any explanation with some code as i am just a beginner. Thanks

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  • Evoluent Vertical Mouse - Re-mapping Buttons?

    - by Paul
    I have the Evoluent Vertical Mouse at work and at home. One is wired, the other wireless. Ubuntu maps their buttons differently and it makes me crazy when I switch locations. I use 12.10, but same has applied to every Ubuntu version since 9.10. The wired mouse is as desired: top finger button is left-click, scroll wheel is middle click and scroll, middle finger button is a right-click. On the wireless version, bottom finger button is mapped to right-click and the middle finger button is center-click. I tried tinkering with these instructions, but wound up unable to boot to GUI... had to delete the .conf file to recover: http://denishaine.wordpress.com/2011/12/01/evoluent-mouse-with-ubuntu-11-04-and-11-10/ Help?

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  • Connecting Ubuntu home server to internet via laptop

    - by Gray-Wolfe
    I recently got a spare desktop computer from a relative to play around with and since I've been using Ubuntu for a few years I decided to install Ubuntu Server 12.04 to play around with and learn more. However it doesn't have a wireless card, the wireless adapter had a shipping error and will be awhile, and plugging it into the router is not an option. So I figured I could give it access to the wifi from my laptop(which I switch between Windows and Ubuntu) so I could at least get some things started and set up while I'm waiting for the adapter. However the few guides I can find to do that require a GUI, something lacking on the server version. Could someone tell me how to set this up via the terminal? I would appreciate it.

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  • Why sockets does not die when server dies? Why socket dies when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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