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  • Application lens as default

    - by user24484
    I want to open the Application lens in the Unity Dash as the default lens, since I much more open a programm then searching for a wikipedia article, the weather or anything else the home lens offers. Here How do I show the Applications Lens By Default? and here What are Unity's keyboard and mouse shortcuts? are the same questions, but the suggested answers don't work anymore on Trusty. I know that I can open the application lens with Super + A but I just would like to press Super to open it. An alternative would be to only get online suggestions whe partikular asked for them, but even though I just select the application scope in the filter section I get some useles online results. Btw. I don't want to open the online search results in generall, since I just reactivated them to try it out.

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  • No drivers listed?/How to install all drivers? 12.10

    - by madmike59
    So i go to system settings in Ubuntu 12.10 and i want to install my drivers but under the Additional Drivers, My LAN doesnt work, Doesnt even pick up that im plugged in threw Ethernet cord. I have a GTX 670M with 3Gb GDDR5 for a video card and would like to use that. Just need help, pretty new to Ubuntu. Ok when i looked at that other question i did the sudo lspce -nn and this is what i got madmike@Mike-GT70:~$ sudo lspci -nn 00:00.0 Host bridge [0600]: Intel Corporation 3rd Gen Core processor DRAM Controller [8086:0154] (rev 09) 00:01.0 PCI bridge [0604]: Intel Corporation Xeon E3-1200 v2/3rd Gen Core processor PCI Express Root Port [8086:0151] (rev 09) 00:02.0 VGA compatible controller [0300]: Intel Corporation 3rd Gen Core processor Graphics Controller [8086:0166] (rev 09) 00:14.0 USB controller [0c03]: Intel Corporation 7 Series/C210 Series Chipset Family USB xHCI Host Controller [8086:1e31] (rev 04) 00:16.0 Communication controller [0780]: Intel Corporation 7 Series/C210 Series Chipset Family MEI Controller #1 [8086:1e3a] (rev 04) 00:1a.0 USB controller [0c03]: Intel Corporation 7 Series/C210 Series Chipset Family USB Enhanced Host Controller #2 [8086:1e2d] (rev 04) 00:1b.0 Audio device [0403]: Intel Corporation 7 Series/C210 Series Chipset Family High Definition Audio Controller [8086:1e20] (rev 04) 00:1c.0 PCI bridge [0604]: Intel Corporation 7 Series/C210 Series Chipset Family PCI Express Root Port 1 [8086:1e10] (rev c4) 00:1c.2 PCI bridge [0604]: Intel Corporation 7 Series/C210 Series Chipset Family PCI Express Root Port 3 [8086:1e14] (rev c4) 00:1c.4 PCI bridge [0604]: Intel Corporation 7 Series/C210 Series Chipset Family PCI Express Root Port 5 [8086:1e18] (rev c4) 00:1d.0 USB controller [0c03]: Intel Corporation 7 Series/C210 Series Chipset Family USB Enhanced Host Controller #1 [8086:1e26] (rev 04) 00:1f.0 ISA bridge [0601]: Intel Corporation HM77 Express Chipset LPC Controller [8086:1e57] (rev 04) 00:1f.2 SATA controller [0106]: Intel Corporation 7 Series Chipset Family 6-port SATA Controller [AHCI mode] [8086:1e03] (rev 04) 00:1f.3 SMBus [0c05]: Intel Corporation 7 Series/C210 Series Chipset Family SMBus Controller [8086:1e22] (rev 04) 01:00.0 VGA compatible controller [0300]: NVIDIA Corporation Device [10de:1213] (rev ff) 02:00.0 Ethernet controller [0200]: Atheros Communications Inc. Device [1969:e091] (rev 13) 03:00.0 Network controller [0280]: Intel Corporation Centrino Wireless-N 2230 [8086:0887] (rev c4) 04:00.0 Unassigned class [ff00]: Realtek Semiconductor Co., Ltd. RTS5209 PCI Express Card Reader [10ec:5209] (rev 01) 04:00.1 SD Host controller [0805]: Realtek Semiconductor Co., Ltd. RTS5209 PCI Express Card Reader [10ec:5209] (rev 01) Let me know if you need any more info? sorry it took so long.

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  • How to set up an rsync backup to Ubuntu securely?

    - by ws_e_c421
    I have been following various other tutorials and blog posts on setting up a Ubuntu machine as a backup "server" (I'll call it a server, but it's just running Ubuntu desktop) that I push new files to with rsync. Right now, I am able to connect to the server from my laptop using rsync and ssh with an RSA key that I created and no password prompt when my laptop is connected to my home router that the server is also connected to. I would like to be able to send files from my laptop when I am away from home. Some of the tutorials I have looked at had some brief suggestions about security, but they didn't focus on them. What do I need to do to let my laptop with send files to the server without making it too easy for someone else to hack into the server? Here is what I have done so far: Ran ssh-keygen and ssh-copy-id to create a key pair for my laptop and server. Created a script on the server to write its public ip address to a file, encrypt the file, and upload to an ftp server I have access to (I know I could sign up for a free dynamic DNS account for this part, but since I have the ftp account and don't really need to make the ip publicly accessible I thought this might be better). Here are the things I have seen suggested: Port forwarding: I know I need to assign the server a fixed ip address on the router and then tell the router to forward a port or ports to it. Should I just use port 22 or choose a random port and use that? Turn on the firewall (ufw). Will this do anything, or will my router already block everything except the port I want? Run fail2ban. Are all of those things worth doing? Should I do anything else? Could I set up the server to allow connections with the RSA key only (and not with a password), or will fail2ban provide enough protection against malicious connection attempts? Is it possible to limit the kinds of connections the server allows (e.g. only ssh)? I hope this isn't too many questions. I am pretty new to Ubuntu (but use the shell and bash scripts on OSX). I don't need to have the absolute most secure set up. I'd like something that is reasonably secure without being so complicated that it could easily break in a way that would be hard for me to fix.

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  • How to make facebox popup remain open and the content inside the facebox changes after the submit

    - by Leonardo Dario Perna
    Hi, I'm a jQuery total n00b. In my rails app this what happen: I'm on the homepage, I click this link: <a href='/betas/new' rel='facebox'>Sign up</a> A beautiful facebox popup shows up and render this views and the containing form: # /app/views/invites/new <% form_tag({ :controller => 'registration_code', :action => 'create' }, :id => 'codeForm') do %> <%= text_field_tag :code %> <br /> <%= submit_tag 'Confirm' %> <% end %> I clink on submit and if the code is valid the user is taken on another page in another controller: def create # some stuff redirect_to :controller => 'users', :action => 'type' end Now I would like to render that page INSIDE the SAME popup contains the form, after the submit button is pressed but I have NO IDEA how to do it. I've tried FaceboxRender but this happens: Original version: # /controllers/users_controller def type end If I change it like that nothing happens: # /controllers/users_controller def type respond_to do |format| format.html format.js { render_to_facebox } end end If I change it like that (I know is wrong but I'm a n00b so it's ok :-): # /controllers/users_controller def type respond_to do |format| format.html { render_to_facebox } format.js end end I got this rendered: try { jQuery.facebox("my raw HTML from users/type.html.erb substituted here")'); throw e } Any solutions? THANK YOU SO MUCH!!

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  • Algorithm design, "randomising" timetable schedule in Python although open to other languages.

    - by S1syphus
    Before I start I should add I am a musician and not a native programmer, this was undertook to make my life easier. Here is the situation, at work I'm given a new csv file each which contains a list of sound files, their length, and the minimum total amount of time they must be played. I create a playlist of exactly 60 minutes, from this excel file. Each sample played the by the minimum number of instances, but spread out from each other; so there will never be a period where for where one sound is played twice in a row or in close proximity to itself. Secondly, if the minimum instances of each song has been used, and there is still time with in the 60 min, it needs to fill the remaining time using sounds till 60 minutes is reached, while adhering to above. The smallest duration possible is 15 seconds, and then multiples of 15 seconds. Here is what I came up with in python and the problems I'm having with it, and as one user said its buggy due to the random library used in it. So I'm guessing a total rethink is on the table, here is where I need your help. Whats is the best way to solve the issue, I have had a brief look at things like knapsack and bin packing algorithms, while both are relevant neither are appropriate and maybe a bit beyond me.

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  • Can I use a MIME type declaration to get an HTML file to open in MS Word?

    - by Toph
    Bill James wrote: I was able to render an HTML page with the MIME type set to "application/msword", which caused the browser to spawn Word which imported the html just fine, allowing edits and saving just as if I'd output a real Word doc. That sounds great to me, but I haven't been able to get it to work in any browser (Chrome/FF/Safari/Opera/IE on Win7 running Word 2010 beta). I tried changing the MIME type in the HTTP headers of several pages via Tamper Data to application/msword, and I tried using the http-equiv meta tag <meta http-equiv="Content-type" content="application/msword"> on a local HTML file I tried opening from the browser, but neither appeared to have any effect. I don't really have a clue with regard to HTTP headers and MIME types generally, so - any tips? Many thanks!

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  • apache: cgi links lead to a "you have chosen to open foo.cgi", although scriptalias is set

    - by Xiong Chiamiov
    Following this guide on CentOS 5.2, just getting nagios set up for the first time. The main page shows up just fine, but when I try to view any of the pages that should be generated by a cgi process, firefox prompts me to save the .cgi instead, so apache's obviously not understanding that it needs to run the cgi and get back some html from it. The odd thing is, though, that, as far as I can tell, apache should be running these files as cgi. nagios.conf: # SAMPLE CONFIG SNIPPETS FOR APACHE WEB SERVER # Last Modified: 11-26-2005 # # This file contains examples of entries that need # to be incorporated into your Apache web server # configuration file. Customize the paths, etc. as # needed to fit your system. ScriptAlias /nagios/cgi-bin/ "/usr/lib/nagios/cgi/" # SSLRequireSSL Options +ExecCGI AddHandler cgi-script .cgi AllowOverride None Order allow,deny Allow from all # Order deny,allow # Deny from all # Allow from 127.0.0.1 AuthName "Nagios Access" AuthType Basic AuthUserFile /etc/nagios/htpasswd.users Require valid-user Alias /nagios "/usr/share/nagios/" # SSLRequireSSL DirectoryIndex index.php Options None AllowOverride None Order allow,deny Allow from all # Order deny,allow # Deny from all # Allow from 127.0.0.1 AuthName "Nagios Access" AuthType Basic AuthUserFile /etc/nagios/htpasswd.users Require valid-use Either the ScriptAlias directive or ExecCGI option should be triggering this, but neither of them seems to have any effect. This config file is being parsed by apache, because if I move it out of conf.d, /nagios gives a 404. The .cgi files are indeed in the /nagios/cgi-bin/ directory, so I didn't specify the incorrect directory. Searching seemed to only provide people who had difficulty with permissions, which is not the issue here. This seems to me to be a pretty basic thing, but even with the excellent apache documentation, I'm at a bit of a loss (been using cherokee too much lately :) ).

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  • External XMPP component - Anyone know a Tutorial or Open Source Example please?

    - by gav
    Hi All, I want to run an XMPP server (Openfire) and register an external component to handle the messages it will recieve (using the Whack library). The external component will run my game logic and I will be using XMPP to send player moves to the server and status updates in the other direction. The bonus with XMPP is that we get built in chat for free. The trouble is, although Ignite look fairly established, I can't find a tutorial on how to write, register and debug an External XMPP component written with Whack, there are very few in general for that matter. I am not invested in either the server implementation or the External Component library, java is just my language of choice. If I was to move to Erlang or Scala or something it would have to be a very simple in that language. A single tutorial or example would go a long way here, I just need an basic External XMPP component pretty please! Kind regards, Gavin

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  • How do I make a jQuery POST function open the new page?

    - by ciclistadan
    I know that a submit button in HTML can submit a form which opens the target page, but how do I cause a jQuery ajax call POST information to a new page and display the new page. I am submitting information that is gathered by clicking elements (which toggle a new class) and then all items with this new class are added to an array and POSTed to a new page. I can get it to POST the data but it seems to be working functioning in an ajax non-refreshing manner, not submitting the page and redirecting to the new page. how might I go about doing this? here's the script section: //onload function $(function() { //toggles items to mark them for purchase //add event handler for selecting items $(".line").click(function() { //get the lines item number var item = $(this).toggleClass("select").attr("name"); }); $('#process').click(function() { var items = []; //place selected numbers in a string $('.line.select').each(function(index){ items.push($(this).attr('name')); }); $.ajax({ type: 'POST', url: 'additem.php', data: 'items='+items, success: function(){ $('#menu').hide(function(){ $('#success').fadeIn(); }); } }); }); return false; }); any pointers would be great!! thanks

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  • I have 5 links that open the same modalpopup?

    - by JPJedi
    I have 5 links that are on the same form but I would like them all to reference the same AJAX modalpopup extender. I am basically showing a panel with the same view layout with just different data depending on which link is pressed, showing different match scores from games. The only way I can get it to work is have 5 panels with unique names and each link references its own panel. Can I get all the links to call one panel? Thanks

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  • How to Open a Remote Text File using Server.MapPath in ASP.Net?

    - by NJTechGuy
    This is what I have right now for a file residing on the same server and it works. Dim FILENAME as String = Server.MapPath("Output.txt") Dim objStreamWriter as StreamWriter objStreamWriter = File.CreateText(FILENAME) dr = myCommand.ExecuteReader() While dr.Read() objStreamWriter.WriteLine("{0}|{1}|{2:yyyy-MM-dd}|{3:yyyy-MM-dd}", dr(0), dr(1), dr(2), dr(3)) End While objStreamWriter.Close() I was planning on FTPing the file to another server once done but is there a way to do it on a remote server? i.e create a text file on a remote server and write to it? Did not find any instances of that usage. How to use ServerXMLHTTP to replace Server.MapPath in this instance? Thank you so much for your time.

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  • How can i open Thickbox from a form and feed it with data ?

    - by Mark Dekker
    I have a simple search php script, within that script there is some html and javascript to make a search input field and a button. What i am trying to do is when someone enters a search, and presses submit, thickbox opens, and the results will be displayed in the thickbox. What i have so far is the search field and button, when i press submit, it briefly shows the thickbox, and than is overloaded by the result page, but than with no search results. Here is the code: <form method="get"> <input type="text" name="merk" size=10 style="font-weight: bold; background-color:#D5DF23;">&nbsp;&nbsp; <input type="image" name="merk" class="thickbox" onclick="document.location.href='searcher.php?keepThis=true&TB_iframe=true&height=520&width=800';" src="zoek1.jpg" width="110" alt="Zoek" onMouseOver="this.src='zoek2.jpg'" onMouseOut="this.src='zoek1.jpg'"> </form></input>

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  • Should I Prefer a Closed or Open List<> System?

    - by Tyler Murry
    Hey guys, I've got a class in my project that stores a List< of elements. I'm trying to figure out whether I should allow the user to add to that List directly (e.g. Calling the native add/remove methods) or lock it down by declaring the List private and only allowing a handful of methods I choose to actually alter the List. It's a framework, so I'm trying to design it as robustly as possible, but I also want to keep it as simple and error-free as possible. What's the best practice in this situation? Thanks, Tyler

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  • How can I get the file I have open in vim to display in my iTerm tab

    - by dd
    I can get the vim title to display on my window by doing this: let &titlestring = expand("%:t") . " @ " . hostname() if &term == "screen" set t_ts=^[k set t_fs=^[\ endif if &term == "screen" || &term == "xterm" set title endif But the tabs will say "Default". From the commandline I can do this: echo -ne "\e]1;hello world\a" And that'll show "Hello World" in my tabs. Is there a way to have vim write this stuff to my tab instead of title instead?

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  • Tunnel over HTTPS

    - by ephemient
    At my workplace, the traffic blocker/firewall has been getting progressively worse. I can't connect to my home machine on port 22, and lack of ssh access makes me sad. I was previously able to use SSH by moving it to port 5050, but I think some recent filters now treat this traffic as IM and redirect it through another proxy, maybe. That's my best guess; in any case, my ssh connections now terminate before I get to log in. These days I've been using Ajaxterm over HTTPS, as port 443 is still unmolested, but this is far from ideal. (Sucky terminal emulation, lack of port forwarding, my browser leaks memory at an amazing rate...) I tried setting up mod_proxy_connect on top of mod_ssl, with the idea that I could send a CONNECT localhost:22 HTTP/1.1 request through HTTPS, and then I'd be all set. Sadly, this seems to not work; the HTTPS connection works, up until I finish sending my request; then SSL craps out. It appears as though mod_proxy_connect takes over the whole connection instead of continuing to pipe through mod_ssl, confusing the heck out of the HTTPS client. Is there a way to get this to work? I don't want to do this over plain HTTP, for several reasons: Leaving a big fat open proxy like that just stinks A big fat open proxy is not good over HTTPS either, but with authentication required it feels fine to me HTTP goes through a proxy -- I'm not too concerned about my traffic being sniffed, as it's ssh that'll be going "plaintext" through the tunnel -- but it's a lot more likely to be mangled than HTTPS, which fundamentally cannot be proxied Requirements: Must work over port 443, without disturbing other HTTPS traffic (i.e. I can't just put the ssh server on port 443, because I would no longer be able to serve pages over HTTPS) I have or can write a simple port forwarder client that runs under Windows (or Cygwin) Edit DAG: Tunnelling SSH over HTTP(S) has been pointed out to me, but it doesn't help: at the end of the article, they mention Bug 29744 - CONNECT does not work over existing SSL connection preventing tunnelling over HTTPS, exactly the problem I was running into. At this point, I am probably looking at some CGI script, but I don't want to list that as a requirement if there's better solutions available.

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  • Java multithreaded server - each connection returns data. Processing on main thread?

    - by oliwr
    I am writing a client with an integrated server that should wait indefinitely for new connections - and handle each on a Thread. I want to process the received byte array in a system wide available message handler on the main thread. However, currently the processing is obviously done on the client thread. I've looked at Futures, submit() of ExecutorService, but as I create my Client-Connections within the Server, the data would be returned to the Server thread. How can I return it from there onto the main thread (in a synchronized packet store maybe?) to process it without blocking the server? My current implementation looks like this: public class Server extends Thread { private int port; private ExecutorService threadPool; public Server(int port) { this.port = port; // 50 simultaneous connections threadPool = Executors.newFixedThreadPool(50); } public void run() { try{ ServerSocket listener = new ServerSocket(this.port); System.out.println("Listening on Port " + this.port); Socket connection; while(true){ try { connection = listener.accept(); System.out.println("Accepted client " + connection.getInetAddress()); connection.setSoTimeout(4000); ClientHandler conn_c= new ClientHandler(connection); threadPool.execute(conn_c); } catch (IOException e) { System.out.println("IOException on connection: " + e); } } } catch (IOException e) { System.out.println("IOException on socket listen: " + e); e.printStackTrace(); threadPool.shutdown(); } } } class ClientHandler implements Runnable { private Socket connection; ClientHandler(Socket connection) { this.connection=connection; } @Override public void run() { try { // Read data from the InputStream, buffered int count; byte[] buffer = new byte[8192]; InputStream is = connection.getInputStream(); ByteArrayOutputStream out = new ByteArrayOutputStream(); // While there is data in the stream, read it while ((count = is.read(buffer)) > 0) { out.write(buffer, 0, count); } is.close(); out.close(); System.out.println("Disconnect client " + connection.getInetAddress()); connection.close(); // handle the received data MessageHandler.handle(out.toByteArray()); } catch (IOException e) { System.out.println("IOException on socket read: " + e); e.printStackTrace(); } return; } }

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  • client side application not working as intended while using AsyncSocket

    - by Miraaj
    Hi All, I am using AsyncSocket class in a simple client-server application. As a first step I want that - as soon as connection is established between client and server, client transmit a welcome message - "connected to xyz server" to server and server displays it in textview. //The code in ClientController class is: -(void)awakeFromNib{ NSError *error = nil; if (![connectSocket connectToHost:@"192.168.0.32" onPort:25242 error:&error]) { NSLog(@"Error starting client: %@", error); return; } NSLog(@"xyz chat client started on port %hu",[connectSocket localPort]); } - (void)onSocket:(AsyncSocket *)sock didConnectToHost:(NSString *)host port:(UInt16)port{ [sock writeData:[@"connected to xyz server" dataUsingEncoding:NSUTF8StringEncoding] withTimeout:30.0 tag:0]; } - (void)onSocket:(AsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag{ // some relevant code goes here } - (void)onSocket:(AsyncSocket *)sock didWriteDataWithTag:(long)tag{ NSLog(@"within didWriteDataWithTag:"); // getting this message, means it should have written something to remote socket but // delegate- onSocket:didReadData:withTag: at server side is not getting invoked } // The code in ServerController class is: - (IBAction)startStop:(id)sender{ NSLog(@"startStopAction"); if(!isRunning) { NSError *error = nil; if(![listenSocket acceptOnPort:INPUT_PORT error:&error]) { NSLog(@"Error starting server: %@", error); return; } NSLog(@"Echo server started on port %hu",[listenSocket localPort]); isRunning = YES; [sender setTitle:@"Stop"]; } else { // Stop accepting connections [listenSocket disconnect]; // Stop any client connections int i; for(i = 0; i < [connectedSockets count]; i++) { // Call disconnect on the socket, // which will invoke the onSocketDidDisconnect: method, // which will remove the socket from the list. [[connectedSockets objectAtIndex:i] disconnect]; } NSLog(@"Stopped Echo server"); isRunning = false; [sender setTitle:@"Start"]; } } - (void)onSocket:(AsyncSocket *)sock didAcceptNewSocket:(AsyncSocket *)newSocket{ [connectedSockets addObject:newSocket]; } - (void)onSocket:(AsyncSocket *)sock didConnectToHost:(NSString *)host port:(UInt16)port{ NSLog(@"Accepted client %@:%hu", host, port); // it is getting displayed [sock readDataToData:[AsyncSocket CRLFData] withTimeout:READ_TIMEOUT tag:0]; } - (void)onSocket:(AsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag{ NSString *msgReceived = [[[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding] autorelease]; NSLog(@"msgReceived in didReadData- %@",msgReceived); // it is not getting displayed [outputView insertText:msgReceived]; [sock readDataToData:[AsyncSocket CRLFData] withTimeout:READ_TIMEOUT tag:0]; } Can anyone suggest me where I may be wrong?? Thanks in advance...... Miraaj

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  • How to open child forms positioned within MDI parent in VB.NET?

    - by user961627
    How do we arrange child forms in a parent MDI window? I'm able to call and display a child form from a menu on the parent, but the child pops up outside the parent - I want it to actually be inside the parent. I've checked in C# and VB.Net solutions but they all say pretty much the same, i.e. try to access LayoutMDI, such as here: http://msdn.microsoft.com/en-us/library/x9fhk181.aspx The problem is, where do I access this? When I'm in the code of my MDI parent, Me.LayoutMdi is not recognized. In which part of the application do I put the Me.LayoutMDI code? Edit The Me.LayoutMDI code worked in the parent after all. I'd been trying for a while but don't know where I was going wrong. However, the child continues to pop up out of the parent. Here's an image of how that happens. The broader form in the back is the parent, and the one with the gridview and two buttons is the new child that popped up. I want it to pop up "Docked" within the parent.

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  • Blocking on DBCP connection pool (open and close connnection). Is database connection pooling in OpenEJB pluggable?

    - by topchef
    We use OpenEJB on Tomcat (used to run on JBoss, Weblogic, etc.). While running load tests we experience significant performance problems with handling JMS messages (queues). Problem was localized to blocking on database connection pool getting or releasing connection to the pool. Blocking prevented concurrent MDB instances (threads) from running hence performance suffered 10-fold and worse. The same code used to run on application servers (with their respective connection pool implementations) with no blocking at all. Example of thread blocked: Name: JMS Resource Adapter-worker-23 State: BLOCKED on org.apache.commons.pool.impl.GenericObjectPool@1ea6b4a owned by: JMS Resource Adapter-worker-19 Total blocked: 18,426 Total waited: 0 Stack trace: org.apache.commons.pool.impl.GenericObjectPool.returnObject(GenericObjectPool.java:916) org.apache.commons.dbcp.PoolableConnection.close(PoolableConnection.java:91) - locked org.apache.commons.dbcp.PoolableConnection@1bcba8 org.apache.commons.dbcp.managed.ManagedConnection.close(ManagedConnection.java:147) com.xxxxx.persistence.DbHelper.closeConnection(DbHelper.java:290) .... Couple of questions. I am almost certain that some transactional attributes and properties contribute to this blocking, but MDBs are defined as non-transactional (we use both annotations and ejb-jar.xml). Some EJBs do use container-managed transactions though (and we can observe blocking there as well). Are there any DBCP configurations that may fix blocking? Is DBCP connection pool implementation replaceable in OpenEJB? How easy (difficult) to replace it with another library? Just in case this is how we define data source in OpenEJB (openejb.xml): <Resource id="MyDataSource" type="DataSource"> JdbcDriver oracle.jdbc.driver.OracleDriver JdbcUrl ${oracle.jdbc} UserName ${oracle.user} Password ${oracle.password} JtaManaged true InitialSize 5 MaxActive 30 ValidationQuery SELECT 1 FROM DUAL TestOnBorrow true </Resource>

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  • How do I open android built in downloads app?

    - by user1502829
    So I'm downloading stuff and it gets put into the built in downloads app since thats how the download manager works. I just want to the user to click a button which opens the built in downloads app. Heres my try: btnDownloads.setOnClickListener(new Button.OnClickListener(){ public void onClick(View v) { PackageManager pakMan=MainActivity.context.getPackageManager(); Log.d("bebr", "Making pak"); if(pakMan!=null){ Intent downloadsIntent=new Intent(Intent.ACTION_MAIN).addCategory(Intent.CATEGORY_LAUNCHER).setComponent(new ComponentName("com.android.downloads","com.android.downlods.Downloads")); ResolveInfo resolved=pakMan.resolveActivity(downloadsIntent, PackageManager.MATCH_DEFAULT_ONLY); Log.d("bebr","Resolving"); if(resolved!=null){ Log.d("bebr", "Starting"); startActivity(downloadsIntent); } } } });

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  • How to show/open/bringToFront a Window that is inside the MainMenu.xib File?

    - by 0SX
    This is a stupid question that I should be able to answer myself but I can't seem to get it to work. I have a window inside my MainMenu.xib file that I want to show or bring to front. Right now I have it visible at launch and it works but if I close it with orderOut: and do another instance of it, buttons quit working. How can I reopen the same window that the NSApplication launched at the beginning of the app? I've spent 2+ days trying to figure a way to make it work but no luck. I've even tried to split the window out to it's own xib file but when I do that my methods from the appDelegate fail to respond/work. Any help would be much appreciated. I feel stupid for even asking such a simplistic question. lol Thanks.

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