Search Results

Search found 18661 results on 747 pages for 'linq to mysql'.

Page 259/747 | < Previous Page | 255 256 257 258 259 260 261 262 263 264 265 266  | Next Page >

  • How to prevent negative number in Mysql

    - by Jerry
    Hello guys.. I have data which is starting from 0 in my database. My php will add 1 or -1 to the data depending on the user's input. My problem is that if data is 0 and a user try to subtract 1. The data become 4294967295 which is the maximum value of INT data type. Are there anyways to make the data stays in 0 even when the user asks for -1? Thanks for the reply.. my sql command is like below update board set score=score-1 where team='TeamA' //this would generate 4294967295 if the score is 0.....

    Read the article

  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

    Read the article

  • MySql Not Like Regexp?

    - by KnockKnockWhosThere
    I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

    Read the article

  • PHP/MySQL - an array filter for bots

    - by Mike
    Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

    Read the article

  • MYSQL Query using subquery

    - by Michael Quiles
    Cant get this to work can any one help. List the part number, part description, and on_hand value of each part whose number of units on hand is more than the average number of units onhand for all parts use a subquery? SELECT PART_NUM, DESCRIPTION, SUM(ON_HAND * PRICE) ON_HAND_VALUE FROM PART; WHERE MAX(ON_HAND); (AVG(ON_HAND) > ON_HAND);

    Read the article

  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

    Read the article

  • Sum of a summation in mysql

    - by dames
    I have the following query, in the top select statement (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) works well but in the union I want to find the total of (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) query from the top select statement However my solution seems to be off I need some help please select (sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l UNION select SUM(sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l

    Read the article

  • MySQL LEFT JOIN issue with three WHERE statements

    - by jhat
    I am building a note taking app for myself with tag filtering functions, but am having an issue when trying to grab notes with the tags. The tag filter needs to use AND not IN, because it will help better narrow down what I am looking for. My tables are configured like this: + notes note_id | note_title | note_uid + tags tag_id | tag_title + notes_tags nt_id | nt_note_id | nt_tag_id The notes_tags table keeps track of all notes' tags. I am not worried about returning any information about tags, so here is an example LEFT JOIN I am using currently to only get notes with only 1 tag. SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 This query runs perfect, it grabs all of the notes with that single tag. However, I am having issues "pinpointing" my notes using a query like this: SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 AND nt_tag_id = 11 What am I doing wrong with the syntax?

    Read the article

  • comparing rows on a mysql table

    - by user311324
    Ok here's the deal I got one table with a bunch of client information. Each client makes up to one purchase a year which is represented by an individual row. there's a column for the year and there's a column the contains a unique identifier for each client. What I need to do is to construct a query that takes last year and this year and shows me which clients were here made a purchase last year but not make a purchase this year. I also need to build a query that shows me which clients did not make a purchase last year and the year before last but did make a purchase this year.

    Read the article

  • What's the error in my MySQL statement?

    - by Jim
    The following SQL statement has a syntax error according to phpMyAdmin, but I can't spot what it is. Any ideas? CREATE TABLE allocations( `student_uid` INT unsigned NOT NULL DEFAULT 0, `active` INT unsigned NOT NULL DEFAULT 1, `name` VARCHAR( 255 ) NOT NULL DEFAULT '', `internal_id` VARCHAR( 255 ) DEFAULT '', `tutor_uid` INT NOT NULL DEFAULT 0, `allocater_uid` INT unsigned NOT NULL DEFAULT 0, `time_created` INT NOT NULL DEFAULT 0, `remote_time` FLOAT NOT NULL DEFAULT 0, `next_lesson` VARCHAR NOT NULL DEFAULT -1, PRIMARY KEY ( student_uid ) );

    Read the article

  • Mysql query, need suggestion or solution

    - by Xi Kam
    Can anyone help me, i have two tables and i need records from both the table //////////////////////////////++ Query 1 ++//////////////////////////////////// SELECT SUM(rec_issued) AS issed, regen_id, YEAR(issue_date) AS iYear, MONTH(issue_date) AS iMonth FROM `view_rec_issued` WHERE `regen_id` = 2 GROUP BY YEAR(issue_date) DESC, MONTH(issue_date) DESC ORDER BY issue_date ASC issed regen_id iYear iMonth 424 2 2011 3 4340 2 2011 4 4235 2 2011 5 10570 2 2012 2 4761 2 2012 3 5000 2 2012 4 3700 2 2012 5 3414 2 2012 6 3700 2 2012 7 2992 2 2012 8 995 2 2012 10 ![Result from Query 1][1] //////////////////////////////++ Query 2 ++//////////////////////////////////// SELECT SUM(total_redem) AS redemed, regen_id, YEAR(redemption_date) AS rYear, MONTH(redemption_date) AS rMonth FROM `recredem_month_wise` WHERE `regen_id` = 2 GROUP BY YEAR(redemption_date) DESC, MONTH(redemption_date) DESC order by redemption_date ASC redemed regen_id rYear rMonth 424 2 2011 3 260 2 2011 4 6523 2 2011 5 1070 2 2011 6 200 2 2011 10 500 2 2011 11 9750 2 2012 2 5000 2 2012 3 5500 2 2012 4 3803 2 2012 5 3700 2 2012 7 3000 2 2012 8 ![Result from Query 2][2] But i want it as - issed regen_id iYear iMonth redemed regen_id rYear rMonth 424 2 2011 3 424 2 2011 3 4340 2 2011 4 260 2 2011 4 4235 2 2011 5 6523 2 2011 5 NULL NULL NULL NULL 1070 2 2011 6 NULL NULL NULL NULL 200 2 2011 10 NULL NULL NULL NULL 500 2 2011 11 10570 2 2012 2 9750 2 2012 2 4761 2 2012 3 5000 2 2012 3 5000 2 2012 4 5500 2 2012 4 3700 2 2012 5 3803 2 2012 5 3414 2 2012 6 NULL NULL NULL NULL 3700 2 2012 7 3700 2 2012 7 2992 2 2012 8 3000 2 2012 8 995 2 2012 10 NULL NULL NULL NULL ![I want this output][3] In these table regen_id is unique and i need data as YEAR and MONTH, if in any table not have the records in perticular month and year it should retrieve zero or null. But in every record year and month should equal like this - iYear = rYear and iMonth = rMonth So we can merge both the fields - No need to show year and month twice iYear and rYear = year iMonth and rMonth = month Thank You Please look at this problem.

    Read the article

  • MySQL/PHP Search Efficiency

    - by iMaster
    Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

    Read the article

  • mysql bug database error

    - by user963499
    Why is that when I search a row in my database, it ended up 0 results? In fact, there are rows that meet my search criterion when I view them manually, but the search button doesnt work as it is. Heres how you can see there are rows that have '0000-00-00 00:00:00' in them, but when I used the search feature, it ended up like this: take note that Im entering it in the right field which is 'AcctStopTime'. TIA

    Read the article

  • please suggest mysql query for this

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, or if we use subquery value to main query? but i m not getting how to implement ...please help me. Thanks for helping me alwayz

    Read the article

  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

    Read the article

  • Why my mysql DISTINCT doesn't work ?

    - by belaz
    Hello, Why the two query below return duplicate member_id and not the third ? i need the second query to work with distinct. Anytime i run a GROUP BY, this query is incredibly slow and the resultset doesn't return the same value as distinct (the value is wrong). SELECT member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+ | member_id | +-----------+ | 11333 | | 141831 | | 12013 | | 60821 | | 64980 | +-----------+ my table sample CREATE TABLE `table1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `member_id` int(11) NOT NULL, `s_type_id` int(11) NOT NULL, `created_at` datetime DEFAULT NULL, PRIMARY KEY (`id`), KEY `s_FI_1` (`member_id`), KEY `s_FI_2` (`s_type_id`) ) ENGINE=InnoDB AUTO_INCREMENT=313096 DEFAULT CHARSET=utf8;

    Read the article

  • how to do this in MySql Query??

    - by deep
    ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

    Read the article

  • MySQL - generate numbers for a group of results

    - by FreeIX
    I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

    Read the article

  • PHP mySQL query's and PHP Variables

    - by jon
    I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

    Read the article

< Previous Page | 255 256 257 258 259 260 261 262 263 264 265 266  | Next Page >