Search Results

Search found 26438 results on 1058 pages for 'calendar table'.

Page 26/1058 | < Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >

  • Find mininum unused value in mysql table

    - by splattru
    I have a MySQL table like this: +--------+-------+ + Server + Port + +--------+-------+ + 1 + 27001 + +--------+-------+ + 2 + 27002 + +--------+-------+ + 4 + 27004 + +--------+-------+ How you can see - here was 27003 port - but it was deleted some time ago (just for example). Is there some way to know the minimum value that is not used (higher than 27000 for example) in mysql table? Or there is no way and I need to make an separate table with all ports and column with "used" or "not used" ? Situation explanation: I am creating game hosting website, and I can use auto-increment for ports, but I will have a lot of deleted/unused ports after some time, and I want to use all of them before increasing port range. Thanks for your answers!

    Read the article

  • Is it possible to pass Calendar new date in the bean without listener?

    - by isabsent
    I am trying to pass new date from PrimeFaces p:calendar (placed in p:dataTable column) to the backing bean: <p:column > <p:calendar value="#{bean.date}">` <p:ajax /> </p:calendar> </p:column> It does not update bean.date. Variants with <p:ajax update="@this" event="change"/> <p:ajax update="@this" event="select"/> do not update bean.date too. The only way I have found is using of listener. However, I suppose, there should be a way without listener implementation like for simple facelets: <p:column> <h:inputText value="#{bean.note}" > <f:ajax/> </h:inputText> </p:column> that works fine for me. Does anybody know how to get it working!?

    Read the article

  • how to sort an existing table in greasemonkey ?

    - by user570512
    i'm writing a greasemonkey user.js for a page with a table in it. (table is 100 rows by 18 columns.) now what i want to do is to make it sortable on column. and also have it run in both chrome and firefox. all searches for answers sofar resulted in suggestions to use jquery/dojo or something alike. can i be done without any external code? after all it's just a matter of replacing the row's in a different order, right? or is that a silly thing to say? the thing is that i'm already using dojo for some query needs but since i want it to run in both firefox and chrome, i just copy paste the whole dojo thing in my script.. also, most of the solutions i found sofar seem to be more for use when building a table. not for altering an existing one. any help is appreciated.

    Read the article

  • Operations in table data with javascript

    - by Zangrandi
    I'm working with rails and I don't know javascript. I have a table with a select_tag field and I want to have another field that capture the option selected, multiply for the price captured in another field and display the total. Like this <table> <tr> <td>(select_tag)</td> <td>price</td> <td>total</td> </tr> </table

    Read the article

  • SQL Server dynamic pivot table

    - by user972255
    In SQL Server, I have two tables TableA and TableB, based on these I need to generate a report which is kind of very complex and after doing some research I come to a conclusion that I have to go with SQL Pivot table but I dont have any idea about the SQL Pivot feature so, can anyone please help me on this. Please see the details below: Create table TableA ( ProjectID INT NOT NULL, ControlID INT NOT NULL, ControlCode Varchar(2) NOT NULL, ControlPoint Decimal NULL, ControlScore Decimal NULL, ControlValue Varchar(50) ) Sample Data ------------- ProjectID | ControlID | ControlCode | ControlPoint | ControlScore | ControlValue P001 1 A 30.44 65 Invalid P001 2 C 45.30 85 Valid Create table TableB ( ControlID INT NOT NULL, ControlChildID INT NOT NULL, ControlChildValue Varchar(200) NULL ) Sample Data ------------ ControlID | ControlChildID | ControlChildValue 1 100 Yes 1 101 No 1 102 NA 1 103 Others 2 104 Yes 2 105 SomeValue Output should be in a single row for a given ProjectID with all its Control values first & followed by child control values (based on the ControlCode (i.e.) ControlCode_Child (1, 2, 3...) and it should look like this

    Read the article

  • Tool to automatically combine many large pivot table in many large Excel sheet ?

    - by Sim
    Hi all, We have several Excel files that contains large pivot data table with the same structure For example File A Pivot table (Field A, B, C) File B Pivot table (Field A, B, C) We want to combine them into 1 pivot table (A, B, C). Just want to know which ways we can do it ? Manual way : open a new empty sheet, copy and paste the pivot there and create the pivot again Automatic way : is there some tool that did this ? Thanks

    Read the article

  • open source web application for viewing .ics calendars

    - by aaron
    I need an open source web application that allows users to view .ics calendars I am hosting a calendar with DAViCal, and users can view/edit calendars with their own clients (like Apple iCal or Mozilla Sunbird), but I want a web app that will display the public calendars so people w/o a user account can view the calendar just by visiting a URL. Requirements: Open source web app: something I can host right along with DAViCal Human-readable calendar: i.e. it has a day/week/month view to visualize calendar events

    Read the article

  • SQL SERVER – Finding Different ColumnName From Almost Identitical Tables

    - by pinaldave
    I have mentioned earlier on this blog that I love social media – Facebook and Twitter. I receive so many interesting questions that sometimes I wonder how come I never faced them in my real life scenario. Well, let us see one of the similar situation. Here is one of the questions which I received on my social media handle. “Pinal, I have a large database. I did not develop this database but I have inherited this database. In our database we have many tables but all the tables are in pairs. We have one archive table and one current table. Now here is interesting situation. For a while due to some reason our organization has stopped paying attention to archive data. We did not archive anything for a while. If this was not enough we  even changed the schema of current table but did not change the corresponding archive table. This is now becoming a huge huge problem. We know for sure that in current table we have added few column but we do not know which ones. Is there any way we can figure out what are the new column added in the current table and does not exist in the archive tables? We cannot use any third party tool. Would you please guide us?” Well here is the interesting example of how we can use sys.column catalogue views and get the details of the newly added column. I have previously written about EXCEPT over here which is very similar to MINUS of Oracle. In following example we are going to create two tables. One of the tables has extra column. In our resultset we will get the name of the extra column as we are comparing the catalogue view of the column name. USE AdventureWorks2012 GO CREATE TABLE ArchiveTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100)); CREATE TABLE CurrentTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100), ExtraCol INT); GO -- Columns in ArchiveTable but not in CurrentTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' GO -- Columns in CurrentTable but not in ArchiveTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' GO DROP TABLE ArchiveTable; DROP TABLE CurrentTable; GO The above query will return us following result. I hope this solves the problems. It is not the most elegant solution ever possible but it works. Here is the puzzle back to you – what native T-SQL solution would you have provided in this situation? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

    Read the article

  • CSS: Labels in table columns

    - by hello
    Hello. BACKGROUND: I would like to have small labels in columns of a table. I'm using some implemented parts of HTML5/CSS3 in my project, and this section specifically is for mobile devices. While both facts are not necessarily relevant, the bottom line is that I don't have to support Internet Explorer or even Firefox for that matter (just WebKit). THE PROBLEM With my current CSS approach, the vertical padding of the cell comes from the <span element (set to display: block with top/bottom margins), which contains the "value" of the column. As a result there's no padding when the <span> is empty or missing (no value) and the label is not in place. The "full" coulmns should give you the idea of where I want the labels to be, even if there's no value, and the <span> is not there. I realize that I could use "non-breaking-space", but I would really like to avoid it. I wonder if any of you have a fix / better way to do this? current code is below. Thank you for any help. <!DOCTYPE html> <html lang="en"> <head> <title>ah</title> <style> body { width: 320px; } /* TABLE */ table { width: 100%; border-collapse: collapse; font-family: arial; } th, td { border: 1px solid #ccc; border-width: 0px 0px 1px 1px; } th:last-child, td:last-child { border-right-width: 1px; } tr:first-child th { border-top-width: 1px; background: #efefef; } /* RELEVANT STUFF */ td { padding: 3px; } td sup { display: block; } td span { display: block; margin: 3px 0px; text-align: center; } </style> </head> <body> <table> <tr> <th colspan="3">something</th> </tr> <tr> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span></span></td><!-- No content, just a label --> </tr> </table> </body> </html>

    Read the article

  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

    Read the article

  • How to Navigate Directly From One Table to Another in Word 2013

    - by Lori Kaufman
    Jumping to a specific page in Word is a common task and easy to do using the Find and Replace dialog box. You can also use this same tab to jump from one table directly to the next table in your document. Your cursor does not have to be in a table to jump to the next table. Put the cursor in any paragraph or table and press F5 or use the Ctrl + G keystroke combination to open the Find and Replace dialog box. The Go To tab is automatically selected. Select Table from the Go to what list and click Next. The next table in your document is selected and the Find and Replace dialog box stays open.    

    Read the article

  • calculate business days including holidays

    - by ran
    i need to calculate the business days between two dates. ex : we have holiday(in USA) on july4th. so if my dates are date1 = 07/03/2012 date2 = 07/06/2012 no of business days b/w these dates should be 1 since july4th is holiday. i have a below method to calclulate the business days which will only counts week ends but not holidays. is there any way to calculate holidays also....please help me on this. public static int getWorkingDaysBetweenTwoDates(Date startDate, Date endDate) { Calendar startCal; Calendar endCal; startCal = Calendar.getInstance(); startCal.setTime(startDate); endCal = Calendar.getInstance(); endCal.setTime(endDate); int workDays = 0; //Return 0 if start and end are the same if (startCal.getTimeInMillis() == endCal.getTimeInMillis()) { return 0; } if (startCal.getTimeInMillis() > endCal.getTimeInMillis()) { startCal.setTime(endDate); endCal.setTime(startDate); } do { startCal.add(Calendar.DAY_OF_MONTH, 1); if (startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY && startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY) { ++workDays; } } while (startCal.getTimeInMillis() < endCal.getTimeInMillis()); return workDays; }

    Read the article

  • Subquery using derived table in Hibernate HQL

    - by Vladimir
    I have a Hibernate HQL question. I'd like to write a subquery as a derived table (for performance reasons). Is it possible to do that in HQL? Example: FROM Customer WHERE country.id in (SELECT id FROM (SELECT id FROM Country where type='GREEN') derivedTable) (btw, this is just a sample query so don't give advices on rewriting it, is just the derived table concept I'm interested in) Thanks.

    Read the article

  • ExtJS: Adding table inside a dynamically added tab

    - by esskar
    Hi, i'm fairly new to ExtJS. I adopted some examples and added the functionality to add tabs to a tab-control by clicking on some link. so far so good. now i want to load a ExtJS table into on of the new tabs. the items (rows, columns) are defined in a database on the server side. can you give me some hints how to add the table automatically when the tab is created?

    Read the article

  • SQLite3, "ALTER TABLE" and durability

    - by Bill
    I'd like to run some ALTER TABLE statements on a sqlite3 database. What happens if the user kills the process or the power is cut while the ALTER TABLE is running? Will the database be left in a corrupt intermediate state?

    Read the article

  • Table-Valued Parameter in Stored Procedure and the Entity Framework 4.0

    - by Fabio
    Hi there, I have a stored procedure called 'GetPrices' with a Table-Valued Parameter called 'StoreIDs' and I would like to call it from my Entity Framework. But when I try to add the Stored Procedure to the EDM, i get the following error: The function 'GetPrices' has a parameter 'StoreIDs' at parameter index 2 that has a data type 'table type' which is not supported. The function was excluded. Is there any workaround this? Any thoughts? Fabio

    Read the article

  • Flex: How to most effectively tavere a table column

    - by Maik
    I have a table "template" which is used in various "instances". All instances have checkboxes in the second column (for record-delete). What would be the most effective way of traversing the table and check if at least one checkbox is selected (to enable a "delete" button)? Thanks! Maik

    Read the article

  • table with black outer, but grey inner border

    - by Jan-Frederik Carl
    Hello, I want to create a html table with a 1pt black outer border and the same border around every td. Should look like this (only the borders, of course) link text I use <table border="1" style="border-collapse:collapse; border-color:Black; border-style:solid; border-width:1pt"> As a result I get a black outer, but grey inner borders.

    Read the article

  • mysql create table help with unique

    - by Matt
    I'm trying to create a table, and can't figure out how to assign two columns to be unique.. I know how to alter a table thats already created, but how do you do it in the create.. im after a create if not exist col1 TEXT, col2 TEXT, col3 TEXT unique(col1, col2) ^very rough basic but you get the idea

    Read the article

< Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >