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  • Getting dynamic childs for a parent in SQL

    - by Islam
    I have a table called Categories which contains category_Id and parent_category_Id, so each category can has a child and the child can has a child and so on (it is dynamic). So if i have category A and category A has child B and child B has child C and child C has child D. I want to get all the child tree of A using SQL so when I give this query the id of A its result will be the ids of A's child which is B,C & D.....any ideas. Thanks in regards,

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  • Java Archtecture Decision !!

    - by santiagobasulto
    Hi everybody! I'm developing a medium Java app, and i'm facing a small problem due to my lack of expirience. I've a custom DAO, which gets "Article" objects from the DataBase. I've the Article class, and the DAO has a method called getArticle(int id), this method returns an Article. The Article has a Category object, and i'm using lazy loading. So, when i request for an Article Category (Article a = new Article(); a.getCategory();) the Article class gets the Category from the DAO and then returns it. I'm now thinking to cache it, so when i request multiple times to an Article's category, the database is only queried one time. My question is: where should i put that cache? I can put it on the Article class (in the DTO), or i can put it on the DAO class. What do you say? Thanks!

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  • Java DAO caching

    - by santiagobasulto
    I'm developing a medium Java app, and i'm facing a small problem due to my lack of experience. I've a custom DAO, which gets "Article" objects from the Database. I've the Article class, and the DAO has a method called getArticle(int id), this method returns an Article. The Article has a Category object, and I'm using lazy loading. So, when I request for an article's category (Article a = new Article(); a.getCategory();) the Article class gets the Category from the DAO and then returns it. I'm now thinking to cache it, so when I request multiple times to an article's category, the database is only queried one time. My question is: where should I put that cache? I can put it on the Article class (in the DTO), or I can put it on the DAO class. What do you say?

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  • Is it possible to parameterize a MEF import?

    - by Josh Einstein
    I am relatively new to MEF so I don't fully understand the capabilities. I'm trying to achieve something similar to Unity's InjectionMember. Let's say I have a class that imports MEF parts. For the sake of simplicity, let's take the following class as an example of the exported part. [Export] [PartCreationPolicy(CreationPolicy.NonShared)] public class Logger { public string Category { get; set; } public void Write(string text) { } } public class MyViewModel { [Import] public Logger Log { get; set; } } Now what I'm trying to figure out is if it's possible to specify a value for the Category property at the import. Something like: public class MyViewModel { [MyImportAttribute(Category="MyCategory")] public Logger Log { get; set; } } public class MyOtherViewModel { [MyImportAttribute(Category="MyOtherCategory")] public Logger Log { get; set; } } For the time being, what I'm doing is implementing IPartImportsSatisfiedNotification and setting the Category in code. But obviously I would rather keep everything neatly in one place.

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  • Change post permalink structure on WordPress to use custom taxonomy

    - by TiuTalk
    Hi there! I want to change the post permalink schema on my WordPress 3.0-beta1 to use my new custom taxonomy. Today I can use /%category%/%postname%/ and the /my-category/my-post/ URL, that's nice but I need to use another taxonomy instead "category" one. I tried to use /%acervo%/%postname%/ but my URLs came with %acervo% on the URL instead the name of the "Acevo" (my taxonomy name) wich the post belongs to. I found something related to WP_Rewrite but without sucess...

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  • How do I implement Advanced combobox in CakePHP

    - by skr
    I have implemented combobox in cakephp using following statement - echo $form->select('brand_id',array($brands),null,array(),'Choose Brand'); for brand and input form for category - echo $form->input('category_id',array('type'=>'select',$categories,'empty'=>'Choose Category')); but none of above option allows me to add my text input to brand or category, like say I want to add an input which is not there in the combobox, how should i go about it. Like a link in the combobox or textbox in combobox? -skr

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  • Why NOT use POST method here?

    - by Camran
    I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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  • How could I cache images that I'm pulling from a magento database through ajax?

    - by wes
    Here's script being called through ajax: <?php require_once '../app/Mage.php'; umask(0); /* not Mage::run(); */ Mage::app('default'); $cat_id = ($_POST['cat_id']) ? $_POST['cat_id'] : NULL; try { $category = new Mage_Catalog_Model_Category(); $category->load($cat_id); $collection = $category->getProductCollection(); $output = '<ul>'; foreach ($collection as $product) { $cProduct = Mage::getModel('catalog/product'); $cProduct->load($product->getId()); $output .= '<li><img id="'.$product->getId().'" src="' . (string)Mage::helper('catalog/image')->init($cProduct, 'small_image')->resize(75) . '" class="thumb" /></li>'; } $output .= '</ul>'; echo $output; } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } I'm just passing in the Category ID, which I've tacked onto the navigation links, then doing some work to eventually just pass back all product images in that category. I'm using this on a drag and drop build-a-bracelet type of application, and the amount of images returned is sometimes in the 500s. So it get's pretty held up during transmission, sometimes 10 seconds or so. I know I'd do good by caching them some way, just not sure how to go about it. Any help is much appreciated. Thanks. -Wes

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  • Enity framework not loading relationship even when using include

    - by dilbert789
    I have this code: Category selectedCategory = (from c in DB.Category.Include("SubCategory") join a in DB.Accessory on c.AccCatUID equals a.Category.AccCatUID where a.AccUID == currentAccessory.AccUID select c).FirstOrDefault(); It works fine, selectedCategory gets populated as expected. BUT selectedCategory has a child table 'SubCategory' which does not get loaded even though there is the include there. It is not loaded until I do this: selectedCategory.SubCategory.Load(); Why do I have to call load explicitly in order to load the child table?

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  • How to add condition on multiple-join table

    - by Jean-Philippe
    Hi, I have those two tables: client: id (int) #PK name (varchar) client_category: id (int) #PK client_id (int) category (int) Let's say I have those datas: client: {(1, "JP"), (2, "Simon")} client_category: {(1, 1, 1), (2, 1, 2), (3, 1, 3), (4,2,2)} tl;dr client #1 has category 1, 2, 3 and client #2 has only category 2 I am trying to build a query that would allow me to search multiple categories. For example, I would like to search every clients that has at least category 1 and 2 (would return client #1). How can I achieve that? Thanks!

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  • Display a menu with categories, sub-categories and products - Magento

    - by user390426
    Hi I have been looking to implement a menu system like the following I have 1 category, Cars, with 2 sub-categories, New and Used I’d like to display, on the drop down, the main category and then New, with all the products inside as a list and then Used, with all the products in a list. I have tried using the code in the link provided, but it seemed to include a rollover option, that expanded the menu and the products are not listed below the category. Thanks

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  • How do I add a filter button to this pagination?

    - by ClarkSKent
    Hey, I want to add a button(link), that when clicked will filter the pagination results. I'm new to php (and programming in general) and would like to add a button like 'Automotive' and when clicked it updates the 2 mysql queries in my pagination script, seen here: As you can see, the category automotive is hardcoded in, I want it to be dynamic, so when a link is clicked it places whatever the id or class is in the category part of the query. 1: $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); 2: $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); This is the entire current php pagination script that I am using: <?php //connecting to the database $error = "Could not connect to the database"; mysql_connect('localhost','root','root') or die($error); mysql_select_db('ajax_demo') or die($error); //max displayed per page $per_page = 2; //get start variable $start = $_GET['start']; //count records $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); //count max pages $max_pages = $record_count / $per_page; //may come out as decimal if (!$start) $start = 0; //display data $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); while ($row = mysql_fetch_assoc($get)) { // get data $name = $row['id']; $age = $row['site_name']; echo $name." (".$age.")<br />"; } //setup prev and next variables $prev = $start - $per_page; $next = $start + $per_page; //show prev button if (!($start<=0)) echo "<a href='pagi_test.php?start=$prev'>Prev</a> "; //show page numbers //set variable for first page $i=1; for ($x=0;$x<$record_count;$x=$x+$per_page) { if ($start!=$x) echo " <a href='pagi_test.php?start=$x'>$i</a> "; else echo " <a href='pagi_test.php?start=$x'><b>$i</b></a> "; $i++; } //show next button if (!($start>=$record_count-$per_page)) echo " <a href='pagi_test.php?start=$next'>Next</a>"; ?>

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  • How to Keep the selected value of the select box after Form POST or GET

    - by Rajasekar
    Im trying to implement the search feature in my website. when the search keyword is entered in the textbox, and the category combo is selected, the form will be Posted and the result will be shown on the same page. what i want is to keep the selected category of the combo by default in the form after posted For eg., If i select the category 'Automobiles' in the combo and click search, after form submit, the combo should show the automobiles as default selected option. Please help me. Any help will be appreciated

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  • Rails 3 find all associated records has_many :through

    - by Sergey
    I would like to list all posts that are connected with some specific category. I have: class Post < ActiveRecord::Base has_many :category_posts has_many :categories, :through => :category_posts end class Category < ActiveRecord::Base has_many :category_posts has_many :posts, :through => :category_posts end class CategoryPost < ActiveRecord::Base belongs_to :category belongs_to :post end And I wanna do something like this Post.where(["category.id = ?", params[:category_id]]) It indeed is very simple task, but I don't know what I should be looking for (keywords). It's the same problem like this, but in rails.

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  • NHibernate many-to-many relationship does not update join-table

    - by Davide Vosti
    I'm having trouble saving a many-to-many relationship with nhibernate. I searched and looked at almost every same question in SO and google but nothing works. The single classes are update correctly but nothing is inserted in the join-table. I have 2 classes: Event and Category. The mapping is this: Event: <bag name="Categories" access="field.camelcase-underscore" table="EventCategories" inverse="true" cascade="all-delete-orphan" lazy="true"> <key column="Event"/> <many-to-many class="Category" column="Category"/> </bag> Category: <bag name="Events" table="EventCategories" access="field.camelcase-underscore" cascade="all-delete-orphan" lazy="true" > <key column="Category"/> <many-to-many class="Event" column="Event"/> </bag> I tried to swap every parameter in both mappings but nothing works... Do you know what I'm doing wrong or have a right mapping for this case? Thank you very much!

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  • How can we make a single dimension array to multidimensional Hierarchical ?

    - by Chetan sharma
    I have an single array of Hierarchical categories. Index of the array is the category_id like:: [8846] => Array ( [category_id] => 8846 [title] => Tsting two [description] => Tsting two [subtype] => categories [type] => object [level] => 2 [parent_category] => 8841 [tags] => new [name] => Tsting two ) each value has its parent_category value, I have around 500 elements in the array, what is the best way to make it. Process i followed: krsort categories array, so that all the child categories are at the beginning, then function makeHierarchical() { foreach($this->categories as $guid => $category) { if($category['level'] != 1) $this->multilevel_categories[$category['parent_category']][$guid] = $category; } } but this is not working, it does it only for first level. Can someone point out me the error.

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  • Grails Domain.get() returns null for mongo's ObjectId

    - by Shashank Agrawal
    I'm using grails 2.3.5 with mongodb 3.0.1 and no hibernate installed. I've a domain class which uses mongo's ObjectId. import org.bson.types.ObjectId class Category { ObjectId id String name } And has a record in mongo database: { "_id": ObjectId("53f6c34c33a429240e2ab471"), "name": "art", "version": NumberLong("41") } When I do, Category.get(new ObjectId("53f6c34c33a429240e2ab471")) somewhere in grails app, it returns null but when I do Category.get("53f6c34c33a429240e2ab471") it then actually returns the result. Why, get() method does not process ObjectId type?

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  • Best database (mysql) structure for this case:

    - by robert
    we have three types of data (tables): Book (id,name,author...) ( about 3 million of rows) Category (id,name) ( about 2000 rows) Location (id,name) ( about 10000 rows) A Book must have at least 1 type of Category (up to 3) AND a Book must have only one Location. I need to correlate this data to get this query faster: Select Books where Category = 'cat_id' AND Location = 'loc_id' Select Books where match(name) against ('name of book') AND Location = 'loc_id' Please I need some help. Thanks

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  • Java Architecture Decision !!

    - by santiagobasulto
    Hi everybody! I'm developing a medium Java app, and i'm facing a small problem due to my lack of expirience. I've a custom DAO, which gets "Article" objects from the DataBase. I've the Article class, and the DAO has a method called getArticle(int id), this method returns an Article. The Article has a Category object, and i'm using lazy loading. So, when i request for an Article Category (Article a = new Article(); a.getCategory();) the Article class gets the Category from the DAO and then returns it. I'm now thinking to cache it, so when i request multiple times to an Article's category, the database is only queried one time. My question is: where should i put that cache? I can put it on the Article class (in the DTO), or i can put it on the DAO class. What do you say? Thanks!

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  • Permutation on Rails Routes

    - by Kevin Sylvestre
    I currently have an application that for a set of parameters (location, category, budget, ...) a user can enter a "pretty" URL like: /location/canada/ontario /category/primary /budget/small Resulting in the respective parameters: params[:country] == 'canada' and params[:region] == 'ontario' params[:category] == 'primary' params[:budget] == 'small' I want to allow users to perform searches on multiple parameters at once (with each parameter optional). For example: /location/canada/ontario/category/primary/budget/small I understand that this can be achieved using URL parameters, but for SEO reasons I prefer to add the "pretty" parameters. Is this at all possible without listing all possible combination of routes (I have a large number of search-able fields)? I understand that route "globbing" maybe play a roll, but I am not sure how. Thanks.

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  • Create Clone Without Effecting Results of Original Object

    - by user1655096
    I have a function that when selecting an option, returns results. I want to be able to clone that function and have the ability to return another set of results, without adding the new results to the original object. // shows / hides results based on selection $(".categories-select").live("change" ,function(){ if($(this).val() == 'red'){ $('.red').removeClass('hide'); // toggles red results, sub menus $(this).parent('.controls').find('.sub').removeClass('hide'); } if($(this).val() == 'blue'){ $('.blue').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } if($(this).val() == 'purple'){ $('.purple').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } if($(this).val() == 'orange'){ $('.orange').removeClass('hide'); $(this).parent('.controls').find('.sub').addClass('hide'); } }); // Duplicates category select menu $(".add-color").find(function(){ $(".color-category").clone().removeClass('color-category').appendTo("#we-want-to").find('.sub,').addClass('hide') ; }); $(".add-color-alternate").click(function(){ $(".color-category-alternate").clone().removeClass('color-category-alternate').appendTo("#we-want-to").find('.sub, .results-table').addClass('hide'); });

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  • Ruby complex validation

    - by pcasa
    Have a product that belongs to a category. Want to create a promotion for a short period of time (lets say a week or two), but their can be only one promotion per category during that time. How can I create a custom validation for this? product class belongs_to :categories name:string desc:text reg_price:decimal category_id:integer promo_active:boolean promo_price:decimal promo_start:datetime promo_end:datetime end category class has_many :products name:string end

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  • Pagination links do not work properly - incorrect PHP function??

    - by ClarkSKent
    Hi everyone, I am still trying to figure out how to fix my pagination script to work properly. the problem I am having is when I click any of the pagination number links to go the next page, the new content does not load. literally nothing happens and when looking at the console in Firebug, nothing is sent or loaded. I have on the main page 3 links to filter the content and display it. When any of these links are clicked the results are loaded and displayed along with the associated pagination numbers for that specific content. I believe the problem is coming from the function(generate_pagination.php (seen below)). Here is the main page so you can how I am including and starting the function(I'm new to php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination($sql) ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> This is as mentioned above, where i think the problem persists since I know nothing of the function formats and how to properly incorporate them: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> I thought I might as well through in the jquery if someone wants to see: $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ $(this).attr('data-page', pageNum); Hide_Load(); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Any help would be appreciated on getting the function to work properly. Thank you.

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  • Does the "using" directive provide any benefit?

    - by Adam Drummond
    Is there a programmatic benefit to using a using statement? Notice the difference between this sample: using Application.Data; namespace Application.Web { public class SampleClass { public void SampleMethod() { List<Category> categories = CreateCategoriesData(); Category expected = categories[0]; ... ... } } } And this one: namespace Application.Web { public class SampleClass { public void SampleMethod() { List<Data.Category> categories = CreateCategoriesData(); Data.Category expected = categories[0]; ... ... } } }

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  • Dynamic use of :default_url in Paperclip

    - by dgilperez
    I'm trying to configure Paperclip to provide different missing images based on the instance's category attribute. Every category of the object has its own missing image. This is my first take: EDIT to add full models: class Service < ActiveRecord::Base attr_accessible :logo, :logo_file_name, :logo_content_type, :logo_file_size, :logo_updated_at belongs_to :category, :counter_cache => true has_attached_file :logo, :path => "/:id-:style-:filename", :url => ":s3_eu_url", :default_url => "/logos/:style/#{self.category.name]}.png", :styles => { :large => "600x400>", :medium => "300x200>", :small => "100x75>", :thumb => "60x42>" } end class Category < ActiveRecord::Base attr_accessible nil has_many :services end In my view, image_tag service.logo.url(:thumb) outputs: undefined method `category' for #<Class:0x0000010a731620> Any ideas? EDIT2: A working default_url is :default_url => "/logos/:style/missing.png", SOLUTION: See my own answer below.

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