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  • Keeping values on form after submition

    - by Lina
    Hi, I'm trying to keep the entered data in the form after submitting by using "value=..." I'm getting a compilation error on the following code: <form id="myform"> <input id="hour" type="text" name="hour" value="<%=hour%>" style="width:30px; text-align:center;" /> : <input id="minute" type="text" name="minute" value="<%=minute%>" style="width:30px; text-align:center;" /> <br/> <input type="submit" value="Validate!" /> </form> the error is : Description: An error occurred during the compilation of a resource required to service this request. Please review the following specific error details and modify your source code appropriately. Compiler Error Message: CS0103: The name 'hour' does not exist in the current context any solution? thanks a lot in advance, Lina

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  • jQuery Address - redirect after form submit

    - by Stian
    Hello all, I use jQuery and AJAX to load content from links and forms into a content div. In addition I use the Address plugin to enable the back button and refresh. On the server side I use Java and Spring MVC. Since I'm using jQuery Address and AJAX the only page that is directly loaded is "index.html". Everything else is loaded into a content div, and what page to load is specified in the hash, ie. "index.html#/users/add.html" will load "users/add.html". Now, "users/add.html" contains a form for creating a new user. When the form is submitted and everything went OK, the controller redirects to "users/index.html". The problem is that jQuery Address doesn't know about the redirect, so the url will remain "index.html#/users/add.html". And this is a problem when you refresh the page and then get sent back to the form, instead of the index page. Is there a way to fix this problem? Thanks, Stian

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  • Java login form with database connection

    - by Muhammed Yoosuf
    I am creating a login form in java by having a database connection, and I need 2 open DIFFERENT forms for each user. However, all of the three forms open except for one. The forms I have are, MAinWindow Nursery Primary Secondary ALL THE FORMS OPEN except for the nursery form, when I enter the correct username it displays the Primary form. ANY HELP SOON char[] DBUserArray; DBUserArray=name.toCharArray(); char [] DBPassArray; DBPassArray=pass.toCharArray(); char AdminArray []=AdminUser.toCharArray(); char NurArray []=NurHead.toCharArray(); char[] PriArray =PriHead.toCharArray(); char[] SecArray=SecHead.toCharArray(); char[] input = txtpassword.getPassword(); String user=txtusername.getText(); char [] userString; userString=user.toCharArray(); if(userString.length!=DBUserArray.length && input.length!=DBPassArray.length) { JOptionPane.showMessageDialog(null, "Username and Password Wrong","User Login",JOptionPane.ERROR_MESSAGE); } else { if(userString.length!=AdminArray.length) { if(userString.length!=PriArray.length) { if(userString.length!=NurArray.length) { if(userString.length!=SecArray.length) { } else { new Secondary().setVisible(true); setVisible(false); } } else { new Nursery().setVisible(true); setVisible(false); } } else { new Primary().setVisible(true); setVisible(false); } } else { new MainWindow().setVisible(true); setVisible(false); } }

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  • Iframe form not submittin in IE but working in Firefox

    - by Younes
    I have got a form that posts values to a page in a wizard. When i'm loading this form in a Iframe everything is working fine in Firefox, it will get me to the second step of the wizard and maintains the values i filled in. When im testing this in Internet Explorer i am not getting to the second step, instead of that it returns me to the first step of the wizard with all fields being blank. When i check this in Fiddler i see that im getting a different response when i'm posting the form in the Iframe from Firefox compared to Internet Explorer. How can i make this work for all browsers? What am I doing wrong? This is what i get back from Fiddler: Firefox Post: Ressult Protocol Host URL Body Caching Content-Type Process Comments Custom 1 302 HTTP www.dmg.eu /brugman/budgetplanner/aanmelden.php 0 no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Expires: Thu, 19 Nov 1981 08:52:00 GMT text/html; charset=UTF-8 firefox:6116 Get: # Result Protocol Host URL Body Caching Content-Type Process Comments Custom 2 200 HTTP www.dmg.eu /brugman/budgetplanner/ 40.677 no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Expires: Thu, 19 Nov 1981 08:52:00 GMT text/html; charset=UTF-8 firefox:6116 Internet Explorer Post: Result Protocol Host URL Body Caching Content-Type Process Comments Custom 73 302 HTTP www.dmg.eu /brugman/budgetplanner/aanmelden.php 0 no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Expires: Thu, 19 Nov 1981 08:52:00 GMT text/html; charset=UTF-8 iexplore:536 Get: Result Protocol Host URL Body Caching Content-Type Process Comments Custom 74 302 HTTP www.dmg.eu /brugman/budgetplanner/ 0 no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Expires: Thu, 19 Nov 1981 08:52:00 GMT text/html; charset=UTF-8 iexplore:536 Hope someone knows what the diff is :).

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  • Basic Contact Form in PHP

    - by NessDan
    I'm working on a contact form for my church website. The church has an email already registered (it's POP3) and the hosting company says their mail server is mymail.brinkster.com . With all that information, how can you send the form using mail()? The server won't show PHP errors. The current code looks like this: $headers = 'MIME-Version: 1.0' . "\r\n"; $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n"; $headers .= 'From: *ChurchsEmail*' . "\r\n"; if(mail("*MyEmailHere*", "Setting Up PHP Email", "This would be the body of the email.", $headers)) { echo "The email was successfully sent."; } else { echo "The email was NOT sent."; } All I get back is "The email was NOT sent." So does anyone have any experience setting up an email form like this? My thanks to anyone who can help me out and any efficient ways of doing this, let me know!

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  • How to Open Multiple PopUp windows with JQuery on form submition (popUps should be relative to form

    - by Ole Jak
    I have A form like this: <form> <fieldset class="ui-widget-content ui-corner-all"> <select id="Streams" class="multiselect ui-widget-content ui-corner-all" multiple="multiple" name="Streams[]"> <br /> <option value="35"> Example Name (35)</option> <option value="44"> Example Name (44)</option> <option value="5698"> Example Name (5698)</option> <option value="777"> Example Name (777)</option> <option value="12"> Example Name (12)</option> </select> <br/> <input type="submit" class="ui-state-default ui-corner-all" name="submitForm" id="submitForm" value="Play Stream from selected URL's!"/> </fieldset> </form> in my JS + HTML page I use JQuery. As you can see I allow user to select multiple Items. I want to open on Submit button click as many popup windows as many Items he selected in a list. Each popUp window should open some url like www.example.com/test.php?id=OPTION_SELECTED . So for each of the selected options I ll get a pop up window whith different url. Please Help.

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  • How to Open Multiple PopUp windows with JQuery on form submission (popUps should be relative to form

    - by Ole Jak
    I have A HTML form like this: <form> <fieldset class="ui-widget-content ui-corner-all"> <select id="Streams" class="multiselect ui-widget-content ui-corner-all" multiple="multiple" name="Streams[]"> <option value="35"> Example Name (35)</option> <option value="44"> Example Name (44)</option> <option value="5698"> Example Name (5698)</option> <option value="777"> Example Name (777)</option> <option value="12"> Example Name (12)</option> </select> <input type="submit" class="ui-state-default ui-corner-all" name="submitForm" id="submitForm" value="Play Stream from selected URL's!"/> </fieldset> </form> in my JS + HTML page I use JQuery. As you can see I allow user to select multiple Items. I want to open on Submit button click as many popup windows as many Items he selected in a list. Each popUp window should open some url like www.example.com/test.php?id=OPTION_SELECTED . And here I mean by PopUp Window a real browser window. So for each of the selected options I ll get a pop up window whith diferent url. Please Help.

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  • Do Any Client-Side JavaScript Frameworks Integrate Well With Node.js+Express.js+socket.io.js?

    - by Tom D
    I'm building an webapp using Node.js+Express.js+socket.io.js on the backend. Do any of the popular front-end frameworks (Agility, Angular, Backbone, Closure, Dojo, Ember, GWT, jQuery, Knockback, Knockout, Spine, YUI, etc) integrate well with this backend for "real-time" applications? I want my application to have a very "real-time" feel. Specifically, when a user submits a form I want the information to be sent using web sockets to the backend for validation and (if validation passes) to be updated in the database. Then, the server-side will use web sockets to send a confirmation that the data was saved or some list of errors. I will use the server's response to update the page using JavaScript. I know all this can be done with any of the listed frameworks. I'm interested in features of particular frameworks that will help the framework integrate better with the Node-based backend than the other frameworks.

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  • AJAX contact form in CodeIgniter

    - by Ross
    Few questions: I'm using CI and JQuery AJAX. In my code below, I assemble dataString, which by default, is appended to the URL as a query string. I've changed the AJAX "type" to POST, so my question is - how do I access dataString in my CI app? It would seem I still have to use $name=$this->input->post('name') Which to me, makes setting dataString redundant? -- I've tried searching but can't really find anything concrete. Would it be possible to still make use of CIs validation library and AJAX? if($this->form_validation->run() == FALSE) { // what can i return so that my CI app shows errors? } Normally you would reload the contact form or redirect the user. In an ideal world I would like the error messages to be shown to the user. Jquery: $(document).ready(function($){ $("#submit_btn").click(function(){ var name = $("input#name").val(); var company = $("input#company").val(); var email = $("input#email").val(); var phone = $("input#phone").val(); var message = $("textarea#message").val(); var dataString = 'name=' + name + '&message=' + message + '&return_email=' + email + '&return_phone=' + phone + '&company=' + company; var response = $.ajax({ type: "POST", url: "newsite/contact_ajax/", data: dataString }).responseText; //$('#contact').hide(); //$('#contact').html('<h5>Form submitted! Thank you!</h5><h4>We will be in touch with you soon.</h4>'); //$('#contact').fadeIn('slow'); return false; }); }); hope i've been clear enough - if anyone has a decent example of a CI contact form that would be great. there's mixed stuff on the internet but nothing that hits all the boxes. thanks

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  • Submit form with POST data in Android app

    - by datguywhowanders
    I've been searching the web for a way to do this for about a week now, and I just can't seem to figure it out. I'm trying to implement an app that my college can use to allow users to log in to various services on the campus with ease. The way it works currently is they go to an online portal, select which service they want, fill in their user name and pwd, and click login. The form data is sent via post (it includes several hidden values as well as just the user name and pwd) to the corresponding login script which then signs them in and loads the service. I've been trying to come at the problem in two ways. I first tried a WebView, but it doesn't seem to want to support all of the html that normally makes this form work. I get all of the elements I need, fields for user and pwd as well as a login button, but clicking the button doesn't do anything. I wondered if I needed to add an onclick handler for it, but I can't see how as the button is implemented in the html of the webview not using a separate android element. The other possibility was using the xml widgets to create the form in a nice relative layout, which seems to load faster and looks better on the android screen. I used EditText fields for the input, a spinner widget for the service select, and the button widget for the login. I know how to make the onclick and item select handlers for the button and spinner, respectively, but I can't figure out how to send that data via POST in an intent that would then launch a browser. I can do an intent with the action url, but can't get the POST data to feed into it. Anyone have any suggestions?

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  • unable to use html form post in php

    - by kossibox
    Hello i have an html form and i'm posting data but i'm unable to get the posted data on a php page (same page) can you please help me. thanks in advance <div class="left"> <form name="form_signin" method="post" onsubmit="return signinValid();" > <table> <tr> <td> Email : </td> <td> <input type="text" id="email" length ="40"> </td> </tr> <tr> <td> Mot de Passe : </td> <td> <input type="password" id ="pass" length ="40"> </td> </tr> <tr> <td> &nbsp; </td> <td> <input type="submit" value="Connexion" length ="40"> </td> </tr> </table> </form> <?php include 'includes.php'; include DB_CONNECT_FILE; //session_start(); print_r($_POST); // prints an empty array even if fields are filled $smart->assign('tpl_file',TEMPLATES_DIR.'signin.html'); $smart->display(TEMPLATES_DIR."with_right.html"); include DB_DISCONNECT_FILE; ?>

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  • How can I return JSON from node.js backend to frontend without reloading or re-rendering the page?

    - by poleapple
    I am working with node.js. I want to press a search button, make some rest api calls to another server in the backend and return the json back to the front end, and reload a div in the front end so that I won't have to refresh the page. Now I know I can reload just a div with jQuery or just Javascript dom manipulation. But how do I make it call a method on the server side? I could have a submit button and it will make a post request and I can catch it and make my api calls from there, however from the node.js side, when I return, I will have to render the page again. How do I go about returning JSON from the back end to the front end without re-rendering or refreshing my page? Thanks.

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  • Building a service for a Drupal site to duplicate a node to another Drupal site in a multi-site setu

    - by EricP
    I'm trying to set up one of my Drupal sites to push a node to another Drupal site in a multi-site configuration. It looks like I need to do this with services somehow, but I can't find any tutorials out there and I need at least to be pointed in the right direction. What I believe I need is set up Services on the receiving site to accept a call from the sending site which will be sending the node object via Json or serialized PHP using a Key that was set up on the receiving site. Can anyone show me an example of this working or give me some insight? thanks

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  • how to insert page view of a node in another page in drupal

    - by sprugman
    I have a list of node ids and I want to display the 'page' view of each one. For various reasons, I don't want to do this with views, and don't think I should need a module. Just an API call to theme('node'). Something like: $nids = array(3,4,5); foreach ($nids as $nid) { $node = node_load($nid); $result .= theme('node', $node); } but I'm not getting back the full page view of the node. I added this to my node-[type].tpl.php file: if ($page) print "PAGE MODE "; else print "NOT PAGE "; if ($teaser) print "TEASER MODE "; else print "NOT TEASER "; and got: NOT PAGE NOT TEASER I seem to be in some kind of limbo. I suspect there's an argument that I add to the theme function, but the terms are all so general (theme, teaser, page, node), I'm having trouble with my google-fu.

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  • Form submits but by passing the form validation when button.click is used

    - by Cuty Pie
    I am using form validation plugin as well as html5 attribute=recquired with input type=button or submit and fancybox.when button is clicked ,both validation proceedures work(notification of empty inputs appeare),but instead of this notification ,form is submitted. If I dont use button.click function but use simple submit.then validation works perfectly plugin==http://validatious.org/ javascript function $(document).ready(function() { $('#send').click(function() { $(this).attr("value", 'Applying...'); var id = getParam('ID'); $.ajax({ type:'POST', url:"send.php", data:{option:'catapply', tittle:$('#tittle').val(), aud:aud, con:con, adv:adv, mid:$('#mid').val(), aud2:aud, cid:$('#cid').val(), scid:$('#scname option[selected="saa"]').val(), gtt:$('input[name=gt]:radio:checked').val(), sr:$(":input").serialize() + '&aud=' + aud}, success:function(jd) { $('#' + id).fadeOut("fast", function() { $(this).before("<strong>Success! Your form has been submitted, thanks :)</strong>"); setTimeout("$.fancybox.close()", 1000); }); } }); }); }); AND Html is here <form id="form2" class="validate" style="display: none" > <input type='submit' value='Apply' id="send" class="sendaf validate_any" name="jobforming"/>

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  • jquery form validation, and submit-on-change

    - by Bee
    I want to make all my settings forms across my site confirm that changes are saved, kinda like facebook does if you make changes in a form and then try to navigate away without saving. So I'm disabling the submit button on the forms only enabling if the values change. I then prompt the user to hit save before they leave the page in the case that they do have changes pending. var form = $('form.edit'); if(form.length > 0) { var orig_str = form.serialize(); $(':submit',form).attr('disabled','disabled'); form.on('change keyup', function(){ if(form.serialize() == orig_str) { setConfirmUnload(false); $(':submit',form).attr('disabled','disabled'); } else { setConfirmUnload(true); $(':submit',form).removeAttr('disabled') } }); $('input[type=submit]').click(function(){ setConfirmUnload(false); }); } function setConfirmUnload(on) { window.onbeforeunload = (on) ? unloadMessage : null; } function unloadMessage() { return 'If you navigate away from this page without saving your changes, they will be lost.'; } One of these forms needs some additional validation which I do using jQuery.validate library. e.g. if i wanted to ensure the user can't double submit the form on accident by double clicking on submit or somesuch (the actual validation in question is for a credit-card form and not this simple): $('form').validate({ submitHandler: function(form) { $(':submit', form).attr('disabled','disabled'); form.submit(); } }); Unfortunately both bits are trying to bind to submit button and they're interfering with each other such that the submit button remains disabled no matter what I do and it is impossible to submit the form at all. Is there some way to chain the validations together or something? Or some other way to avoid re-writing the validation code to repeat the "did you change anything in the form" business?

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  • Multiselect tranfer in zend

    - by niriza
    I want to transfer the selected value of Zend_Form_Element_Multiselect to another multiselect element of zend form. I tried this with JQuery it works but when I try to populate the form I get a problem what should I do in my controller. My code look like this: Form: $form['core'] = new Zend_Form_Element_Multiselect('core'); foreach ($results as $row) { $form['core']-addMultiOption($row['id'],$row['competencies']); } $form['core']-setLabel('Core competencies')-setAttrib('id','select1'); $form['core_competency'] = new Zend_Form_Element_Multiselect('core_competency'); foreach ($results as $row) { $form['core_competency']-addMultiOption($row['id'], ''); } $form['core_competency']-setAttrib('id','select2'); $form['subsidiary'] = new Zend_Form_Element_Multiselect('subsidiary'); foreach($results as $row) { $form['subsidiary']-addMultiOption($row['id'],$row['competencies']); } $form['subsidiary']-setLabel('Subsidiary competencies'); $form['subsidiary_competency'] = new Zend_Form_Element_Multiselect('subsidiary_competency'); $form['subsidiary_competency']-addMultiOption('',''); $form['save'] = new Zend_Form_Element_Submit('competencies'); $form['save']-setLabel('Save')-setValue('competencies') -setAttrib('id','competencies-save'); $this-addElements($form); $this-setMethod('post');

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  • What's the best graphics library for node.js for image cropping?

    - by Travis
    I'm creating a website using node.js. I have seen many libraries mentioned that piggy back on top of imagemagick etc. There is a list here: https://github.com/ry/node/wiki/modules#graphics What I'm trying to do is take the image that a user uploads, crop it/size it to certain dimensions the site requires. What is the best/most active script to do this? I'd like one with npm support. Does anyone have actual experience using some of these?

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  • What naming conventions exist for the primary Node.js file?

    - by Tom Dworzanski
    This question has been completely edited in hopes that it will be reopened. The naming of the main Node.js file is something left to the user and and does not seem to be defined by any well established convention. In hopes of finding a good name, I am curious if there are naming conventions in other parts of the Node.js ecosystem that might suggest a name to use. Some names I have seen are: app.js, index.js, main.js, server.js, etc. Please provide only well documented standards in answers.

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  • casting a node to integer

    - by user1708762
    The code gives an error saying that "no operator matches these two operands" in the if comparison statement. I interpret,it should mean that "a node can't be converted/casted into an integer". But, the print statement prints an integer value for w[2] when used with %d format. Why is that happening? Isn't printf casting it? NODE *w=(NODE *)malloc(4*sizeof(NODE)); if(w[2]==0) printf("%d\n",w[2]); The structure of the node is- struct node{ int key; struct node *father; struct node *child[S]; int *ss; int current; };

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  • Optimizing hash lookup & memory performance in Go

    - by Moishe
    As an exercise, I'm implementing HashLife in Go. In brief, HashLife works by memoizing nodes in a quadtree so that once a given node's value in the future has been calculated, it can just be looked up instead of being re-calculated. So eg. if you have a node at the 8x8 level, you remember it by its four children (each at the 2x2 level). So next time you see an 8x8 node, when you calculate the next generation, you first check if you've already seen a node with those same four children. This is extended up through all levels of the quadtree, which gives you some pretty amazing optimizations if eg. you're 10 levels above the leaves. Unsurprisingly, it looks like the perfmance crux of this is the lookup of nodes by child-node values. Currently I have a hashmap of {&upper_left_node,&upper_right_node,&lower_left_node,&lower_right_node} -> node So my lookup function is this: func FindNode(ul, ur, ll, lr *Node) *Node { var node *Node var ok bool nc := NodeChildren{ul, ur, ll, lr} node, ok = NodeMap[nc] if ok { return node } node = &Node{ul, ur, ll, lr, 0, ul.Level + 1, nil} NodeMap[nc] = node return node } What I'm trying to figure out is if the "nc := NodeChildren..." line causes a memory allocation each time the function is called. If it does, can I/should I move the declaration to the global scope and just modify the values each time this function is called? Or is there a more efficient way to do this? Any advice/feedback would be welcome. (even coding style nits; this is literally the first thing I've written in Go so I'd love any feedback)

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  • Printing Infopath form 2010(.xml) in Sharepoint 2010

    - by Surendra J
    Hi Everyone, My question is related to printing an Infopath 2010 form in Sharepoint 2010.I designed an Infopath 2010 form in Infopath Designer 2010 and published it to a form library in Sharepoint 2010.The end user fill the form and store it in .xml format in the document library.Now I would like to print the form filled by the end user? Any Ideas or suggestion about the above scenario?Please consider both browser based forms and normal forms Thanking you in advance.

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  • Changing an HTML Form's Target with jQuery

    - by Rick Strahl
    This is a question that comes up quite frequently: I have a form with several submit or link buttons and one or more of the buttons needs to open a new Window. How do I get several buttons to all post to the right window? If you're building ASP.NET forms you probably know that by default the Web Forms engine sends button clicks back to the server as a POST operation. A server form has a <form> tag which expands to this: <form method="post" action="default.aspx" id="form1"> Now you CAN change the target of the form and point it to a different window or frame, but the problem with that is that it still affects ALL submissions of the current form. If you multiple buttons/links and they need to go to different target windows/frames you can't do it easily through the <form runat="server"> tag. Although this discussion uses ASP.NET WebForms as an example, realistically this is a general HTML problem although likely more common in WebForms due to the single form metaphor it uses. In ASP.NET MVC for example you'd have more options by breaking out each button into separate forms with its own distinct target tag. However, even with that option it's not always possible to break up forms - for example if multiple targets are required but all targets require the same form data to the be posted. A common scenario here is that you might have a button (or link) that you click where you still want some server code to fire but at the end of the request you actually want to display the content in a new window. A common operation where this happens is report generation: You click a button and the server generates a report say in PDF format and you then want to display the PDF result in a new window without killing the content in the current window. Assuming you have other buttons on the same Page that need to post to base window how do you get the button click to go to a new window? Can't  you just use a LinkButton or other Link Control? At first glance you might think an easy way to do this is to use an ASP.NET LinkButton to do this - after all a LinkButton creates a hyper link that CAN accept a target and it also posts back to the server, right? However, there's no Target property, although you can set the target HTML attribute easily enough. Code like this looks reasonable: <asp:LinkButton runat="server" ID="btnNewTarget" Text="New Target" target="_blank" OnClick="bnNewTarget_Click" /> But if you try this you'll find that it doesn't work. Why? Because ASP.NET creates postbacks with JavaScript code that operates on the current window/frame: <a id="btnNewTarget" target="_blank" href="javascript:__doPostBack(&#39;btnNewTarget&#39;,&#39;&#39;)">New Target</a> What happens with a target tag is that before the JavaScript actually executes a new window is opened and the focus shifts to the new window. The new window of course is empty and has no __doPostBack() function nor access to the old document. So when you click the link a new window opens but the window remains blank without content - no server postback actually occurs. Natch that idea. Setting the Form Target for a Button Control or LinkButton So, in order to send Postback link controls and buttons to another window/frame, both require that the target of the form gets changed dynamically when the button or link is clicked. Luckily this is rather easy to do however using a little bit of script code and jQuery. Imagine you have two buttons like this that should go to another window: <asp:LinkButton runat="server" ID="btnNewTarget" Text="New Target" OnClick="ClickHandler" /> <asp:Button runat="server" ID="btnButtonNewTarget" Text="New Target Button" OnClick="ClickHandler" /> ClickHandler in this case is any routine that generates the output you want to display in the new window. Generally this output will not come from the current page markup but is generated externally - like a PDF report or some report generated by another application component or tool. The output generally will be either generated by hand or something that was generated to disk to be displayed with Response.Redirect() or Response.TransmitFile() etc. Here's the dummy handler that just generates some HTML by hand and displays it: protected void ClickHandler(object sender, EventArgs e) { // Perform some operation that generates HTML or Redirects somewhere else Response.Write("Some custom output would be generated here (PDF, non-Page HTML etc.)"); // Make sure this response doesn't display the page content // Call Response.End() or Response.Redirect() Response.End(); } To route this oh so sophisticated output to an alternate window for both the LinkButton and Button Controls, you can use the following simple script code: <script type="text/javascript"> $("#btnButtonNewTarget,#btnNewTarget").click(function () { $("form").attr("target", "_blank"); }); </script> So why does this work where the target attribute did not? The difference here is that the script fires BEFORE the target is changed to the new window. When you put a target attribute on a link or form the target is changed as the very first thing before the link actually executes. IOW, the link literally executes in the new window when it's done this way. By attaching a click handler, though we're not navigating yet so all the operations the script code performs (ie. __doPostBack()) and the collection of Form variables to post to the server all occurs in the current page. By changing the target from within script code the target change fires as part of the form submission process which means it runs in the correct context of the current page. IOW - the input for the POST is from the current page, but the output is routed to a new window/frame. Just what we want in this scenario. Voila you can dynamically route output to the appropriate window.© Rick Strahl, West Wind Technologies, 2005-2011Posted in ASP.NET  HTML  jQuery  

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  • JQuery form sticks with the ajax indicator on and won't submit

    - by Steven Buick
    Hi, I'm using JQuery 1.3 to validate and submit a form to a PHP page which JSON encodes a server response to display on the original form page. I've tried submitting the form without the JQuery part and everything seems to work fine but when I add JQuery it doesn't submit and constantly displays the ajax indicator. Here's my code: $(document).ready(function(){ var options = { target: '#messagebox', url: 'updateregistration.php', type:'POST', beforeSubmit: validatePassword, success: processJson, dataType: 'json' }; $("form:not(.filter) :input:visible:enabled:first").focus(); $("#webmailForm").validate({ errorLabelContainer: "#messagebox", rules: { forename: "required", surname: "required", currentpassword: "required", directemail: { required: true, email: true }, directtelephone: "required" }, messages: { forename: { required: "Please enter your forename" }, directemail: { required: "Please enter your direct e-mail address", email: "Your e-mail address does not appear to be valid(Example: [email protected])" }, surname: { required: "Please enter your surname" }, directtelephone: { required: "Please enter your direct telephone number" }, currentpassword: { required: "Please enter your current password" } } }); $('#webmailForm').submit(function() { $('#ajaxindicator').show(); $(this).ajaxSubmit(options); return false; }); }); function processJson(data) { $("#webmailForm").fadeOut("fast"); $("#messagebox").fadeIn("fast"); $("#messagebox").css({'background-image' : 'url(../images/messageboxbackgroundgreen.png)','border-color':'#009900','border-width':'1px','border-style':'solid'}); var forename=data.forename; var surname=data.surname; var directemail=data.directemail; var directphone=data.directphone; var dateofbirth=data.dateofbirth; var companyname=data.companyname; var fulladdress=data.fulladdress; var telephone=data.telephone; var fax=data.fax; var email=data.email; var website=data.website; var fsanumber=data.fsanumber; var membertype=data.membertype; var network=data.network; $("#messagebox").html('<h3>Registration Update successful!</h3>' + '<p><strong>Member Type:</strong> ' + membertype + '<br>' + '<strong>Forename:</strong> ' + forename + '<br><strong>Surname:</strong> ' + surname + '<br><strong>Direct E-mail:</strong> ' + directemail + '<br><strong>Direct Phone:</strong> ' + directphone + '<br><strong>Date of Birth:</strong> ' + dateofbirth + '<br><strong>Company:</strong> ' + companyname + '<br><strong>Address:</strong> ' + fulladdress + '<br><strong>Telephone:</strong> ' + telephone + '<br><strong>Fax:</strong> ' + fax + '<br><strong>E-mail:</strong> ' + email + '<br><strong>Website:</strong> ' + website + '<br><strong>FSA Number:</strong> ' + fsanumber + '<br><strong>Network:</strong> ' + network + '</p>'); $('#ajaxindicator').hide(); } function validatePassword(){ var clientpassword=$("#clientpassword").val(); var currentpassword=$("#currentpassword").val(); var currentpasswordmd5=hex_md5(currentpassword); if (currentpasswordmd5!=clientpassword){ $("#messagebox").html("You input the wrong current password, please try again."); $('#ajaxindicator').hide(); return false; } } I have a disabled textbox and some hidden ones. Could this be the problem?

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  • php form doesnt submit one of the fields

    - by steve
    i have bought a template that have built in contact form problem is that it submits every thing except "company" name i have spent few hours messing around with it but cant get to work it. if you can point me to some solution i would be greatful thanks in advance this is contact form <form action="php/contact.php" method="post" id="contactform"> <ol> <li> <label for="name">your name <span class="red">*</span></label> <input id="name" name="name" class="text" /> </li> <li> <label for="email">Your email <span class="red">*</span></label> <input id="email" name="email" class="text" /> </li> <li> <label for="company">Company Name</label> <input id="company" name="company" class="text" /> </li> <li> <label for="subject">Subject</label> <input id="subject" name="subject" class="text" /> </li> <li> <label for="message">Message <span class="red">*</span></label> <textarea id="message" name="message" rows="6" cols="50"></textarea> </li> <li class="buttons"> <input type="image" name="imageField" id="imageField" src="images/button.jpg" /> </li> </ol> </form> this is java script <script type="text/javascript"> // <![CDATA[ jQuery(document).ready(function(){ $('#contactform').submit(function(){ var action = $(this).attr('action'); $.post(action, { name: $('#name').val(), email: $('#email').val(), company: $('#company').val(), subject: $('#subject').val(), message: $('#message').val() }, function(data){ $('#contactform #submit').attr('disabled',''); $('.response').remove(); $('#contactform').before('<p class="response">'+data+'</p>'); $('.response').slideDown(); if(data=='Thanks for your message, will contact you soon.') $('#contactform').slideUp(); } ); return false; }); }); // ]]> </script> this is php script if(!$_POST) exit; $email = $_POST['email']; //$error[] = preg_match('/\b[A-Z0-9._%-]+@[A-Z0-9.-]+.[A-Z]{2,4}\b/i', $POST['email']) ? '' : 'INVALID EMAIL ADDRESS'; if(!eregi("^[a-z0-9]+([\.-][a-z0-9]+)" ."@"."([a-z0-9]+([.-][a-z0-9]+))+"."\.[a-z]{2,}"."$",$email )){ $error.="Invalid email address entered"; $errors=1; } if($errors==1) echo $error; else{ $values = array ('name','email','message'); $required = array('name','email','message'); $your_email = "[email protected]"; $email_subject = "New Message: ".$_POST['subject']; $email_content = "new message:\n"; foreach($values as $key => $value){ if(in_array($value,$required)){ if ($key != 'subject' && $key != 'company') { if( empty($_POST[$value]) ) { echo 'Please fill in all required fields, marked with *'; exit; } } $email_content .= $value.': '.$_POST[$value]."\n"; } } if(@mail($your_email,$email_subject,$email_content)) { echo 'Thanks for your message, will contact you soon.'; } else { echo 'ERROR!'; } }

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