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  • How to get Ponter/Reference semantics in Scala.

    - by Lukasz Lew
    In C++ I would just take a pointer (or reference) to arr[idx]. In Scala I find myself creating this class to emulate a pointer semantic. class SetTo (val arr : Array[Double], val idx : Int) { def apply (d : Double) { arr(idx) = d } } Isn't there a simpler way? Doesn't Array class have a method to return some kind of reference to a particular field?

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  • How to find the row ID from datagridview, given a row value?

    - by user361108
    Hi, Can anyone help me please? I have to find the row number from 1 selected array which I stored in one separate array and randomly I'm trying to get the row number from datagridview http://serv8.enterupload.com/i/00246/aewglahmvpr5.jpg In other words: if I know a column value for a given row in a datagridview (e.g. for this row, FirstName == 'Bud'), how can I get the row ID?

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  • Correct use of a "for...in" loop in javascript?

    - by jnkrois
    Hello everybody, before I ask my question I wanted to let everybody know that I appreciate the fact that there's always somebody out there willing to help, and on my end I'll try to give back to the community as much as I can. Thanks Now, I would like to get some pointers as to how to properly take advantage of the "for...in" loop in JavaScript, I already did some research and tried a couple things but it is still not clear to me how to properly use it. Let's say I have a random number of "select" tags in an HTML form, and I don't require the user to select an option for all of them, they can leave some untouched if they want. However I need to know if they selected none or at least one. The way I'm trying to find out if the user selected any of them is by using the "for...in" loop. For example: var allSelected = $("select option:selected"); var totalSelected = $("select option:selected").length; The first variable produces an array of all the selected options. The second variable tells me how many selected options I have in the form (select tags could be more than one and it changes every time). Now, in order to see if any has been selected I loop through each element (selected option), and retrieve the "value" attribute. The default "option" tag has a value="0", so if any selected option returns a value greater than 0, I know at least one option has been selected, however it does not have to be in order, this is my loop so far: for(var i = 0; i < totalSelected; i++){ var eachOption = $(allSelected[i]).val(); var defaultValue = 0; if(eachOption == defaultValue){ ...redirect to another page }else if(eachOption > defaultValue){ ... I display an alert } } My problem here is that as soon as the "if" matches a 0 value, it sends the user to the next page without testing the rest of the elements in the array, and the user could have selected the second or third options. What I really want to do is check all the elements in the array and then take the next action, in my mind this is how I could do it, but I'm not getting it right: var randomValue = 25; for(randomValue in allSelected){ var found = true; var notFound = false if(found){ display an alert }else{ redirect to next page } } This loop or the logic I'm using are flawed (I'm pretty sure), what I want to do is test all the elements in the array against a single variable and take the next action accordingly. I hope this makes some sense to you guys, any help would be appreciated. Thanks, JC

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  • relating to objects inside an object

    - by steve
    Got a problem, I have an an array of objects inside a constructor of a class. I'm trying to use the array to relate to a property in the object but I can't relate to them. lessonObjectsArray(0) = lessonObject1 lessonObjectsArray(1) = lessonObject2 lessonObjectsArray(2) = lessonObject3 the properties of the object "lessonObject1" are lessonName, videoLink, pdfLink I thought it would be tbTest.text = lessonObjectsArray(0).lessonObject1.lessonName just doesnt work

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  • What ia alternative for split in Perl

    - by joe
    a file contains a: b d: e f: a:b:c g: a b c d f:g:h h: d d:dd:d f How to parse this file into lethand side values into one array and right hand side to another array . i tried with split . but i am not able to get it back

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  • Wordpress Custom Post Type adding tags

    - by Nick White
    I am currently working on a Wordpress site I have created some custom Post Types all work fine create the post etc. What I need however is custom taxonomies with some of the custom Post Types, I have set this up and when adding different tags to the taxonomy it works however, when creating a post for a custom post type in the taxonomy block clicking add tag it just does a anchor link to #Member news Category-add Nothing else happens, it's not a big bug but I would however, like to fix this so it is correct for the time I go live Is this a known bug? or is there something I have probably missed when creating the custom post type? register_post_type('member_news', array( 'label' => 'Member News','description' => 'News content submitted by members of RRUKA.','public' => true,'show_ui' => true,'show_in_menu' => true,'capability_type' => 'post','hierarchical' => false,'rewrite' => array('slug' => 'member-news'),'query_var' => true,'has_archive' => true,'exclude_from_search' => false,'menu_position' => 5,'supports' => array('title','editor','excerpt','trackbacks','revisions','thumbnail','author','page-attributes',),'labels' => array ( 'name' => 'Member News', 'singular_name' => 'Member News', 'menu_name' => 'Member News', 'add_new' => 'Add Member News', 'add_new_item' => 'Add New Member News', 'edit' => 'Edit', 'edit_item' => 'Edit Member News', 'new_item' => 'New Member News', 'view' => 'View Member News', 'view_item' => 'View Member News', 'search_items' => 'Search Member News', 'not_found' => 'No Member News Found', 'not_found_in_trash' => 'No Member News Found in Trash', 'parent' => 'Parent Member News', ),) ); Any information on this would be very welcome Thanks in advanced

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  • The fundamentals of Hash tables?

    - by kylex
    I'm quite confused about the basic concepts of a Hash table. If I were to code a hash how would I even begin? What is the difference between a Hash table and just a normal array? Basically if someone answered this question I think all my questions would be answered: If I had 100 randomly generated numbers (as keys), how would I implement a hash table and why would that be advantageous over an array? Psuedo-code or Java would be appreciated as a learning tool...

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  • Rails Routes :requirements

    - by Chris Kilmer
    I want to set a route :requirements on an array that verifies a particular parameter is included in an array: atypes = [:culture, :personality, :communication] map.with_options(:path_prefix = ':atype', :requirements = {:atype = atypes.include?(:atype)}) do |assessment| ... end I haven't been able to find any documentation on how to accomplish this. Any help would be appreciated.

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  • json retrival failed with jquery .each

    - by user545520
    {"paging": {"pageNum":2,"action":"Next","type":"","availableCacheName":"getAllFunds","selectedCacheName":"","showFrom":101,"showTo":200,"totalRec":289,"pageSize":100}, "Data":[{"sourceCodeId":0,"radio_fund":"individua l","availableFunds":[],"fundId":288,"searchName":[],"fundName":"Asian Equity Fund A Class Income","srcFundGrpId":"PGI","firstElement":0,"las tElement":0,"totalElements":0,"pageList":[],"standardExtract":true}] I have json file with above format with two fileds,one paging and one is Data array. I able to retrieve values of paging,but i am not able to retrieve the values of data array with .each function of jquery. Any suggestions or inputs really appreciated.

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  • run jquery on each table

    - by Tommy Arnold
    Below I have some jQuery that runs through each table with the classname = sizetable I would like to execute this: $("#frontshade :radio").click(function() {}); But I'm not sure how to replace the "#frontshade" with the id from the array var table_ids = new Array(); $('.sizetable') .each(function(e){ table_ids[] = $(this).attr('id'); // JQUERY TO EXECUTE ON EACH TABLE $("#frontshade :radio").click(function() {}; // }); Thanks in advance for any answers

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  • PHP: How do I find (Oracle) parameters in a SQL query?

    - by Bartb
    Suppose you have a string: "SELECT * FROM TABLE WHERE column1 = :var1 AND column2 = :var2" Now, how do I get an array with all the variables like so: Array ( [0] => :var1 [1] => :var2 ) I've tried it with PHP's preg_match_all, but I struggle with the regex. $varcount = preg_match_all("/ :.+ /", $sql, $out);

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  • Find closest number in range?

    - by Chris
    What is the best way to find the closes value in a range... for example i have an array with 0, 90, 180, 270, 360.. And a number 46... What is the best way to find 90 in the array? (in actipnscript 3)

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  • LINQ Query to filter DTO

    - by brabone
    I have an array...and I need to exclude all the items in this array of string from the masterList.customField as shown below string[] excludeItem = {"a","b","c"}; CustomDTO[] masterList = service.LoadMasterList(); masterList.Where(c=> masterList.customField NOT IN excludeItem How do I achieve the NOT IN part above?

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  • Missing $ on loop variable

    - by k0re
    Hi, 1 #!/usr/bin/perl 2 use strict; 3 use warnings; 4 5 my @array = qw[a b c]; 6 foreach my($a,$b,$c) (@array) { 7 print "$a , $b , $c\n"; 8 } I receive following error: Missing $ on loop variable What is wrong? I am using: perl v5.10.1 (*) built for x86_64-linux-thread-multi

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  • Fast matrix transposition in Python

    - by psihodelia
    Is there any fast method to make a transposition of a rectangular 2D matrix in Python (non-involving any library import).? Say, if I have an array X=[[1,2,3], [4,5,6]] I need an array Y which should be a transposed version of X, so Y=[[1,4],[2,5],[3,6]].

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  • Type Mismatch using VBScript to create Pivot Table/Chart

    - by Rodricks
    I get Run time error:Type mismatch for the following code: Dim Field Field="Gen8" '''' ============================================================================== EXCEL Sheet '==============Errors -Stacked Chart by Year and Week --ALL WEEKS ''''=================================================== objExcel.ActiveWorkbook.Worksheets.Add SheetNumber = SheetNumber ' add adds in front so sheetnumber stays 1 objExcel.Sheets(SheetNumber).Select objExcel.Sheets(SheetNumber).Activate objExcel.Sheets(SheetNumber).Name = "YRWk" SheetName = "SYS_Product_YRWeeks" '============== strSQLCustomers = "select isnull(AB.Week,D.Week_Num) AS YRWk,ISNULL(AB.UnCorrectable,0) as UE," & _ "isnull(AB.Correctable,0) as CE, isnull(AB.SYS_Product,'" & Field & "'" & _ ") as SYS_Product from AHS_Dates D Left Join (select * from P_tot where " & _ "SYS_Product = '" & Field & "'" & _ " ) AB on AB.Year_=D.Year_ and AB.Week=D.Week_Num order by YRWk" FetchData2.Open strSQLCustomers, openConnection, adOpenStatic, adLockReadOnly If FetchData2.RecordCount > 0 Then **objExcel.ActiveWorkbook.Connections.Add SheetName, "", _ Array(Array( _ "ODBC;DRIVER=SQL Server Native Client 10.0;SERVER=" & sServerIP & ";TimeOut=5000000; Trusted_Connection=Yes;Integrated Security=SSPI;" _ ), Array("DATABASE=" & sDataBaseName & ";")), Array(strSQLCustomers), 2** objExcel.ActiveWorkbook.PivotCaches.Create(SourceType:=xlExternal, SourceData:= _ objExcel.ActiveWorkbook.Connections(SheetName), Version:= _ xlPivotTableVersion14).CreatePivotTable TableDestination:=objExcel.Sheets(SheetNumber).Name & "!R3C7", _ TableName:="PivotTable" & SheetNumber, DefaultVersion:=xlPivotTableVersion14 Set ws = objExcel.ActiveWorkbook.Worksheets(objExcel.Sheets(SheetNumber).Name) objExcel.Cells(3, 7).Select ws.Shapes.AddChart.Select objExcel.ActiveWorkbook.ActiveChart.ChartType = xlAreaStacked objExcel.ActiveWorkbook.ActiveChart.SetSourceData Source:=ws.Range(objExcel.Sheets(SheetNumber).Name & "!$G$3:$I$20") With ws.PivotTables("PivotTable1").PivotFields("SYS_PRoduct") .Orientation = xlColumnField .Position = 1 End With With ws.PivotTables("PivotTable1").PivotFields("YRWk") .Orientation = xlRowField .Position = 1 End With ' With ws.PivotTables("PivotTable1").PivotFields("Year_") ' .Orientation = xlRowField ' .Position = 2 ' End With objExcel.ActiveWorkbook.ActiveChart.ChartTitle.Text = " Errors by Week and Year -ALLWEEKS" ws.PivotTables("PivotTable1").AddDataField ws.PivotTables( _ "PivotTable1").PivotFields("UE"), "Sum of UnCorrectable", xlSum ws.PivotTables("PivotTable1").AddDataField ws.PivotTables( _ "PivotTable1").PivotFields("CE"), "Sum of Correctable", xlSum End If ''MsgBox (FetchData2.RecordCount) FetchData2.Close I have used the same pivot chart + table in other slides. The problem I think is the query length My question: 1.Is there a better way for me to access the query results. Would appreciate the steps if any. 2.If I can make it a procedure how do I modify the pivot chart/table creation. Thanks. The query results with all 52 weeks: Week UE CE SYS_Product(or Field) 1 0 0 Gen8 2 0 0 Gen8 3 0 0 Gen8 4 0 0 Gen8 5 0 0 Gen8 6 0 0 Gen8

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  • Does the List in .NET work the same way as arraylist in Java?

    - by eflles
    When I learned Java, I was told that the arraylist works this way: It creates an array with room for 10 elements. When the 11th element is added, it is created a new list with room for 20 elements, and the 10 elements are copied into the new array. This will repeat as until there are no more elements to add, or to a maximum size. Is the List in .NET constructed the same way?

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  • python count number of times the date has appeared

    - by Rajeev
    From the following array,how to count the dates for the number of times it has occured in the array.The output should be in the following format [date,count] new_dates = [['2012-12-02', 14],['2012-12-03',2],....] Input: dates = [['2012-12-02', 17], ['2012-12-01', 5], ['2012-12-02', 15], ['2012-12-02', 8], ['2012-12-02', 17], ['2012-12-02', 15], ['2012-12-11', 6], ['2012-12-02', 1], ['2012-12-02', 9], ['2012-12-02', 11], ['2012-12-03', 13], ['2012-12-03', 10], ['2012-12-02', 18], ['2012-12-02', 11], ['2012-12-02', 12], ['2012-12-05', 14], ['2012-12-02', 3], ['2012-12-02', 6], ['2012-12-06', 10], ['2012-12-07', 0], ['2012-12-08', 3], ['2012-12-09', 12], ['2012-12-02', 6]]

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