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  • Get the File name without file extension in VIM function.

    - by tr-sugumar
    I want to get the fine name without the file extension in VIM. I wrote the following functions in my .vimrc file for compile and run the Java program. :function! JAVA_RUN() :!javac %^M :endfunction map <F3> :execute JAVA_RUN()<CR> :source $HOME/.vimrc<CR> In side the function how can I get the file name with out the extension.

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  • I want to compile a batch file into an exe using c++, i can get through parsing the batch file and w

    - by Nareshkumar Rao
    Ok, here's the thing, I am creating an application in DevC++ that will read in a batch file. then, one by one parsing it using: system(getline(myfile,line)); After setting everything up, I save the newly created file as "main.cpp". The problem is, I want to compile it into an exe, from my program, for the end user. So basically, I'm asking whether I can compile a C++ file from a C++ Exe..

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  • how to install a file handle in perl class

    - by Haiyuan Zhang
    please looku up the following code first. #! /usr/bin/perl package foo; sub new { my $pkg = shift; my $self = {}; my $self->{_fd} = undef; bless $self, $pkg; return $self; } sub Setfd { my $self = shift; my $fd = shift; $self_->{_fd} = $fd; } sub write { my $self = shift; print $self->{_fd} "hello word"; } my $foo = new foo; My intention is to store a file handle within a class using hash. the file handle is undefined at first, but can be initilized afterwards by calling Setfd function. then write can be called to actually write string "hello word" to a file indicated by the file handle, supposed that the file handle is the result of a success "write" open. but, perl compiler just complains that there are syntax error in the "print" line. can anyone of you tells me what's wrong here? thanks in advance.

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  • Read text file in java

    - by user326091
    Hi, I have a text file. I would like to retrieve the content from one line to another line. For example, the file may be 200K lines. I want to read the content from line 78 to line 2735. Since the file may be very large, I do not want to read the whole content into the memory. thanks Frank

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  • Write to text file using ArrayList

    - by Ugochukwutubelum Chiemenam
    The program is basically about reading from a text file, storing the current data into an ArrayList, then writing data (from user input) into the same text file. Kindly let me know where I am going wrong in this sub-part? The data inside the text file is as follows: abc t1 1900 xyz t2 1700 The compiler is showing an error at the line output.format("%s%s%s%n", public class justTesting { private Scanner input; private Formatter output; private ArrayList<Student> tk = new ArrayList<Student>(); public static void main(String[] args) { justTesting app = new justTesting(); app.create(); app.writeToFile(); } public void create() { Text entry = new Text(); Scanner input = new Scanner(System.in); System.out.printf("%s\n", "Please enter your name, ID, and year: "); while (input.hasNext()) { try { entry.setName(input.next()); entry.setTelNumber(input.next()); entry.setDOB(input.next()); for (int i = 0; i < tk.size(); i++) { output.format("%s%s%s%n", tk.get(i).getName(), tk.get(i) .getTelNumber(), tk.get(i).getDOB()); } } catch (FormatterClosedException fce) { System.err.println("Error writing to file."); return; } catch (NoSuchElementException nsee) { System.err.println("Invalid input. Try again: "); input.nextLine(); } System.out.printf("%s\n", "Please enter your name, ID, and year: "); } } public void writeToFile() { try { output = new Formatter("testing.txt"); } catch (SecurityException se) { System.err .println("You do not have write access permission to this file."); System.exit(1); } catch (FileNotFoundException fnfe) { System.err.println("Error opening or creating file."); System.exit(1); } } }

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  • Best way to laod a large file into arraylist in java

    - by user1730833
    I have a file whose size is about 300mb i want to read the contents line by line and then add it into arraylist. So i have made an object of array list a1 , then reading the file using bufferedreader , after that when i add the lines from file into arraylist it gives an error Exception in thread "main" java.lang.OutOfMemoryError: Java heap space. Please tell me what should be the solution for this.

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  • Perl Script to search and replace in .SQL query file with user inputs

    - by T.Mount
    I have a .SQL file containing a large number of queries. They are being run against a database containing data for multiple states over multiple years. The machine I am running this on can only handle running the queries for one state, in one year, at a time. I am trying to create a Perl script that takes user input for the state abbreviation, the state id number, and the year. It then creates a directory for that state and year. Then it opens the "base" .SQL file and searches and replaces the base state id and year with the user input, and saves this new .SQL file to the created directory. The current script I have (below) stops at open(IN,'<$infile') with "Can't open [filename]" It seems that it is having difficulty finding or opening the .SQL file. I have quadruple-checked to make sure the paths are correct, and I have even tried replacing the $path with an absolute path for the base file. If it was having trouble with creating the new file I'd have more direction, but since it can't find/open the base file I do not know how to proceed. #!/usr/local/bin/perl use Cwd; $path = getcwd(); #Cleans up the path $path =~ s/\\/\//sg; #User inputs print "What is the 2 letter state abbreviation for the state? Ex. 'GA'\n"; $stlet = <>; print "What is the 2 digit state abbreviation for the state? Ex. '13'\n"; $stdig = <>; print "What four-digit year are you doing the calculations for? Ex. '2008'\n"; $year = <>; chomp $stlet; chomp $stdig; chomp $year; #Creates the directory mkdir($stlet); $new = $path."\/".$stlet; mkdir("$new/$year"); $infile = '$path/Base/TABLE_1-26.sql'; $outfile = '$path/$stlet/$year/TABLE_1-26.sql'; open(IN,'<$infile') or die "Can't open $infile: $!\n"; open(OUT,">$infile2") or die "Can't open $outfile: $!\n"; print "Working..."; while (my $search = <IN>) { chomp $search; $search =~ s/WHERE pop.grp = 132008/WHERE pop.grp = $stdig$year/g; print OUT "$search\n"; } close(IN); close(OUT); I know I also probably need to tweak the regular expression some, but I'm trying to take things one at a time. This is my first Perl script, and I haven't really been able to find anything that handles .SQL files like this that I can understand. Thank you!

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  • accessing specific icons from a Multi-Icon (.ico) file

    - by Sagi1981
    Dear community. I would like to know if the following is possible. I have an .ico file, containing several sizes and color depths. However, it also contains some custom made sizes, that are going to be used inside my application. The application accesses the icon trough a resource DLL. (The intention is that the DLL is provided by a third party developer) Is there any way to pinpoint exactly which of the icons in the .ico file to use in my application? Like I want this size to appear here on my GUI etc. For instance, I am making a button in my application, and I would like my custom made 15*32 icon from my .ico file to be displayed on the button. I know this is possible by adding the bitmaps one at a time to the resource DLL, giving each of them a unique name. But it would be easier, if I am able to identify the different contents of the icon file instead. Is it possible in some way to look at the icon file as an array of icons or something like that? Any help is much appreciated. It seems quite hard to find information about this subject on the web. Oh, and I am writing my application in C#, using MFC DLL (from Visual C++ to create my resource DLL)

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  • append text to lines in a CSV file

    - by MichaelMcCabe
    This question seems to have been asked a million times around the web, but I cannot find an answer which will work for me. Basically, I have a CSV file which has a number of columns (say two). The program goes through each row in the CSV file, taking the first column value, then asks the user for the value to be placed in the second column. This is done on a handheld running Windows 6. I am developing using C#. It seems a simple thing to do. But I cant seem to add text to a line. I cant use OleDb, as System.Data.Oledb isnt in the .Net version I am using. I could use another CSV file, and when they complete each line, it writes it to another CSV file. But the problems with that are - The file thats produced at the end needs to contain EVERY line (so what if they pull the batterys out half way). And what if they go back, to continue doing this another time, how will the program know where to start back from.

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  • How do I write a Java text file viewer for big log files

    - by Hannes de Jager
    I am working on a software product with an integrated log file viewer. Problem is, its slow and unstable for really large files because it reads the whole file into memory when you view a log file. I'm wanting to write a new log file viewer that addresses this problem. What are the best practices for writing viewers for large text files? How does editors like notepad++ and VIM acomplish this? I was thinking of using a buffered Bi-directional text stream reader together with Java's TableModel. Am I thinking along the right lines and are such stream implementations available for Java?

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  • Better way to download a binary file?

    - by geoff
    I have a site where a user can download a file. Some files are extremely large (the largest being 323 MB). When I test it to try and download this file I get an out of memory exception. The only way I know to download the file is below. The reason I'm using the code below is because the URL is encoded and I can't let the user link directly to the file. Is there another way to download this file without having to read the whole thing into a byte array? FileStream fs = new FileStream(context.Server.MapPath(url), FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); long numBytes = new FileInfo(context.Server.MapPath(url)).Length; byte[] bytes = br.ReadBytes((int) numBytes); string filename = Path.GetFileName(url); context.Response.Buffer = true; context.Response.Charset = ""; context.Response.Cache.SetCacheability(HttpCacheability.NoCache); context.Response.ContentType = "application/x-rar-compressed"; context.Response.AddHeader("content-disposition", "attachment;filename=" + filename); context.Response.BinaryWrite(bytes); context.Response.Flush(); context.Response.End();

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  • How to change file contents in PHP ?

    - by Misha Moroshko
    I save in a file some info about users (like number of times user passed the login page, last visited time, and so on). I want to read this info from the file, and update it (add 1 to the counter, and change the last visited time). My question is: can I do it without opening the file twice ? I open the first time to read the contents, and then open it again to overwrite the contents with the updated ones. Thanks !

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  • C Writting to a file in Unicode

    - by Lefteris
    Hey all, I am having some problems writting to a file in unicode inside my c program. I am trying to write a unicode Japanese string to a file. When I go to check the file though it is empty. If I try a non-unicode string it works just fine. What am I doing wrong? setlocale(LC_CTYPE, ""); FILE* f; f = _wfopen(COMMON_FILE_PATH,L"w"); fwprintf(f,L"???"); fclose(f);

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  • Zend framework forms, upload file problem

    - by bounce
    Hi, I use Zend forms in my web application. I wonder where Zend puts uploded temp file by default ? I can't find it in server tmp dir. For example if I upload image(1.jpg) via file field, it appears on tmp folder, but as 1.jpg(/tmp/1.jpg). But I need temporary file like /tmp/phpeZApBn. Maybe it is in any other location ? Any help would be appreciated.

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  • Adding text read from a file to an array list in java

    - by user1824856
    I am having trouble putting text read from a file into an array list. My text looks like this: 438;MIA;JFK;10:55;1092;447 638;JFK;MIA;19:45;1092;447 689;ATL;DFW;12:50;732;448 etc... My code looks like this: package filesexample; import java.io.*; import java.io.FileNotFoundException; import java.util.Scanner; import java.util.ArrayList; /** * * @author */ public class FilesExample { /** * @param args the command line arguments */ public static void main(String[] args) throws IOException { File file = new File ("/Schedule.txt"); try { Scanner scanner= new Scanner(file);; while (scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner= new Scanner(line); lineScanner.useDelimiter(";"); while(lineScanner.hasNext()){ String part = lineScanner.next(); System.out.print(part + " "); } System.out.println(); } }catch (FileNotFoundException e){ e.printStackTrace(); } } } Some help on getting started would be much appreciated thank you!

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  • WiX, Conditionally installing a file based on OS

    - by Sam Saffron
    In my WiX project I need to install different content for the same file name, based on the OS. If the OS is Windows 7 then the file needs to have content X. If the OS is Windows Vista the file needs to have content Y. I have thought through a few approaches: Define two components, one with the content for windows 7 and another with the contents for Vista. Run a custom action based on the OS that overwrites the content for Vista if the OS is Windows 7. Define two additional features (window7 config and win vista config) have the components target the same file and install the feature conditionally based on OS. Which is the best approach to take. Any tips, tricks and sample wix to get this going?

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  • How to detect if a form input element of type file is empty

    - by Ankur
    I have some code which reads a file through a form field of type file <input type="file" ... /> I want to give the user another option of providing a url to a file rather than having to upload it as many are already online. How can I detect when this field is empty on the server side. I am using Apache Commons FileUpload FileItemStream item = iter.next(); name = item.getFieldName(); stream = item.openStream(); if(!item.isFormField()){ if(item.toString()!=""){ .... I need to detect when item is empty. The above code doesn't work, nor does using: if(item.equals(null)){ ....

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  • Adobe Illustrator - File Grouping

    - by Gern Blandston
    Is there a way to open multiple AI files (say 3 individual files) and somehow save in a way that I can open the same 3 files simultaneously in the future? I always want the multiple files to open together. Situation: We design products with AI. A single product may have multiple versions. The designer typically creates 1 AI file, then puts all versions of the product in the single file. I need them to put each version in a separate file for an integration project, but this creates more work for them. The solution I'm looking for would allow them to open all the relevant AI file and somehow same them all as a group. Next time, they open the group and all AI files open together. Thank you

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