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  • Code Golf: Code 39 Bar Code

    - by gwell
    The challenge The shortest code by character count to draw an ASCII representation of a Code 39 bar code. Wikipedia article about Code 39: http://en.wikipedia.org/wiki/Code_39 Input The input will be a string of legal characters for Code 39 bar codes. This means 43 characters are valid: 0-9 A-Z (space) and -.$/+%. The * character will not appear in the input as it is used as the start and stop characters. Output Each character encoded in Code 39 bar codes have nine elements, five bars and four spaces. Bars will be represented with # characters, and spaces will be represented with the space character. Three of the nine elements will be wide. The narrow elements will be one character wide, and the wide elements will be three characters wide. A inter-character space of a single space should be added between each character pattern. The pattern should be repeated so that the height of the bar code is eight characters high. The start/stop character * (bWbwBwBwb) would be represented like this: # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # # # ### ### # ^ ^ ^^ ^ ^ ^ ^^^ | | || | | | ||| narrow bar -+ | || | | | ||| wide space ---+ || | | | ||| narrow bar -----+| | | | ||| narrow space ------+ | | | ||| wide bar --------+ | | ||| narrow space ----------+ | ||| wide bar ------------+ ||| narrow space --------------+|| narrow bar ---------------+| inter-character space ----------------+ The start and stop character * will need to be output at the start and end of the bar code. No quiet space will need to be included before or after the bar code. No check digit will need to be calculated. Full ASCII Code39 encoding is not required, just the standard 43 characters. No text needs to be printed below the ASCII bar code representation to identify the output contents. The character # can be replaced with another character of higher density if wanted. Using the full block character U+2588, would allow the bar code to actually scan when printed. Test cases Input: ABC Output: # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # # # ### ### # ### # # # ### # ### # # ### ### ### # # # # # ### ### # Input: 1/3 Output: # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # # # ### ### # ### # # # ### # # # # # ### ### # # # # # ### ### # Input: - $ (minus space dollar) Output: # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # # # ### ### # # # # ### ### # ### # ### # # # # # # # # ### ### # Code count includes input/output (full program).

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  • Adding View extending from SurfaceView to layout gives me a blank screen

    - by JonF
    I'm very new to Android programming, so this is probably something pretty basic. I just have an xml layout with a few buttons. I'm trying to follow the model given by the JetBoy demo, so I'm adding a view to the layout which extends SurfaceView. When this new view is put in my xml layout, I just get a blank screen. Here's the XML layout if it helps. The gameview element is what causes the screen to be blank <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:alwaysDrawnWithCache="true"> <game.test.gameEngine android:id="@+id/gameView" android:layout_width="fill_parent" android:layout_height="fill_parent"/> <Button android:text="Easy" android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/EasyButton"></Button> <Button android:text="Medium" android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/MedButton"></Button> <Button android:text="Hard" android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/HardButton"></Button> <DatePicker android:id="@+id/DatePicker01" android:layout_width="wrap_content" android:layout_height="wrap_content"></DatePicker><Button android:id="@+id/Button04" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Exit"></Button> </LinearLayout>

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  • Newbie: How to set attribute of the relative layout in my case??

    - by Leem
    I would like to divide my screen into 4 equal areas like ?.Each one of the four area is a linear layout. I tried to use relative layout to hold four linear layout like below: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:id="@+id/up_left_area" android:layout_width="wrap_content" android:layout_height="wrap_content" android:background="#ffff66" > <TextView android:id="@+id/label1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="UP LEFT"/> </LinearLayout> <LinearLayout android:id="@+id/up_right_area" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_toRightOf="@id/up_left_area" android:background="#ccffff"> <TextView android:id="@+id/label2" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="UP RIGHT"/> </LinearLayout> <LinearLayout android:id="@+id/down_left_area" android:layout_width="wrap_content" android:layout_height="fill_parent" android:layout_below="@id/up_left_area" android:background="#66cc33" > <TextView android:id="@+id/label3" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="DOWN LEFT"/> </LinearLayout> <LinearLayout android:id="@+id/down_right_area" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_below="@id/up_right_area" android:layout_toRightOf="@id/down_left_area" android:background="#cc6600"> <TextView android:id="@+id/label4" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="DOWN RIGHT"/> </LinearLayout> </RelativeLayout> With the above xml layout code, I do get 4 areas on the screen, but they are not equal sized. How to modify my code to have equal sized 4 areas on the screen like ? ?

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  • jquery mouseover/mouseout

    - by Hulk
    In the following code once the mouse out is done the mouse over again does not work ,what is the work around for this <!DOCTYPE html> <html> <head> <style> /* div { background:#def3ca; margin:3px; width:80px; display:none; float:left; text-align:center; }*/ </style> <script src="http://code.jquery.com/jquery-latest.min.js"></script> </head> <body> <div id="playControls" style="position:absolute; bottom:0px; left:0px; right:0px;color:blue;"> Mouse over me </div> <script> $(document).ready(function() { $("#playControls").mouseover(function () { alert('here'); $("div:eq(0)").show("fast", function () { /* use callee so don't have to name the function */ $(this).next("div").show("fast", arguments.callee); }); }); $("#playControls").mouseout(function () { alert('here'); $("div").hide(2000); }); }); </script> </body> </html>

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  • MkMapView Zoom Level

    - by meetS
    I m using MkMapView with google maps.I succeed to show map view and address with annotation pin.But I want increased zoom level.How Can I Set it programmatically?? (void) showMyAddress { //Hide the keypad MKCoordinateRegion region; MKCoordinateSpan span; span.latitudeDelta=0.2; span.longitudeDelta=0.2; CLLocationCoordinate2D location = [self addressLocation]; region.span=span; region.center=location; if(addAnnotation != nil) { [mapView removeAnnotation:addAnnotation]; [addAnnotation release]; addAnnotation = nil; } addAnnotation = [[AddAnnotation alloc] initWithCoordinate:location ]; [addAnnotation setMTitle:@"abc"]; [addAnnotation setMSubTitle:@"def."] [mapView addAnnotation:addAnnotation]; [mapView setRegion:region animated:TRUE]; [mapView regionThatFits:region]; } -(CLLocationCoordinate2D) addressLocation { NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@&output=csv", [@"abc" stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSStringEncodingConversionAllowLossy error:nil]; NSArray *listItems = [locationString componentsSeparatedByString:@","]; double latitude = 0.0; double longitude = 0.0; if([listItems count] >= 4 && [[listItems objectAtIndex:0] isEqualToString:@"200"]) { latitude = [[listItems objectAtIndex:2] doubleValue]; longitude = [[listItems objectAtIndex:3] doubleValue]; } else { } CLLocationCoordinate2D location; location.latitude = latitude; location.longitude = longitude; return location; }

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  • cannot load JSTL taglib within embedded Jetty server

    - by fthompson
    I am writing a web application that runs within an embedded Jetty instance. When I attempt to execute a JSTL statement, I receive the following exception: org.apache.jasper.JasperException: /index.jsp(1,63) PWC6188: The absolute uri: http://java.sun.com/jsp/jstl/core cannot be resolved in either web.xml or the jar files deployed with this application I have the following jars on the classpath ant-1.6.5.jar ant-1.7.1.jar ant-launcher-1.7.1.jar core-3.1.1.jar jetty-6.1.22.jar jetty-util-6.1.22.jar jsp-2.1-6.1.14.jar jsp-api-2.1.jar jstl-1.2.jar servlet-api-2.5-20081211.jar servlet-api-2.5-6.1.14.jar standard-1.1.2.jar My web.xml looks like this: <?xml version="1.0" encoding="ISO-8859-1"?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee h77p://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <display-name>test</display-name> </web-app> My code looks like this: <%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %> <html> <body> <h2>Hello World!</h2> <%= new java.util.Date() %><br/> ${1+2}<br/> <c:out var="${5+9}"/><br/> </body> </html> I started my embedded Jetty server like this: Server server = new Server(80); WebAppContext context = new WebAppContext("pig-1.0-SNAPSHOT.war","/"); server.addHandler(context); server.start(); I spent the past two days experimenting with various combinations of jar files, web.xml configurations, and tag library declarations, but to no avail. How can I get an embedded Jetty server up and running with full JSTL support?

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  • Calling Matlab's MLApp.MLAppClass.FEval from F#

    - by Matthew
    Matlab provides a COM interface that supports remote execution of arbitrary functions (and code snippets). In particular, it has an Feval method that calls a given Matlab function. The third parameter to this method, pvarArgOut, has COM type VARIANT*, and appears in the Visual Studio F# editor as an argument of type: pvarArgOut: byref<obj> The following code calls interp1, which in Matlab returns a matrix (i.e. 2D double array) result, as is normal for most Matlab functions. let matlab = new MLApp.MLAppClass() let vector_to_array2d (v : vector) = Array2D.init v.Length 1 (fun i j -> v.[i]) let interp1 (xs : vector) (ys : vector) (xi : vector) = let yi : obj = new obj() matlab.Feval("interp1", 1, ref yi, vector_to_array2d xs, vector_to_array2d ys, vector_to_array2d xi) yi :?> float[,] This code compiles fine, but when calling interp1, I get a COM exception: A first chance exception of type 'System.Reflection.TargetInvocationException' occurred in mscorlib.dll A first chance exception of type 'System.Runtime.InteropServices.COMException' occurred in mscorlib.dll An unhandled exception of type 'System.Runtime.InteropServices.COMException' occurred in mscorlib.dll Additional information: Invalid callee. (Exception from HRESULT: 0x80020010 (DISP_E_BADCALLEE)) I get the same error whether initialize yi with a new obj, a new Array2D, or null. How does F# translate VARIANT output arguments?

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  • How do you set tab view to scroll?

    - by DrogoNevets
    I have managed to set up a tabbed view for my app (woo!) and have the following xml for the UI <TabHost xmlns:android="http://schemas.android.com/apk/res/android" android:id="@android:id/tabhost" android:layout_width="fill_parent" android:layout_height="wrap_content"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:padding="5dp"> <TabWidget android:id="@android:id/tabs" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <FrameLayout android:id="@android:id/tabcontent" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </LinearLayout> <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <Spinner android:id="@+id/areaSpinner" android:layout_width="fill_parent" android:layout_height="@dimen/one_row" /> <Spinner android:id="@+id/cragSpinner" android:layout_width="fill_parent" android:layout_height="@dimen/one_row" /> <Spinner android:id="@+id/routeSpinner" android:layout_width="fill_parent" android:layout_height="@dimen/one_row" /> <DatePicker android:id="@+id/dateClimbed" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <Spinner android:id="@+id/styleSpinner" android:layout_width="fill_parent" android:layout_height="@dimen/one_row" /> <Spinner android:id="@+id/detailsSpinner" android:layout_width="fill_parent" android:layout_height="@dimen/one_row" /> <TextView android:id="@+id/climbNotes" android:layout_width="fill_parent" android:layout_height="@dimen/three_row" /> </LinearLayout> yet am seemingly unable to scroll down to see the rest of the form (cuts off at one of the spinners, why is this? and how do i fix it?

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  • Android's EditText is hidden when the virtual keyboard is shown and a SurfaceView is involved

    - by Jan
    I have a simple user interface: an EditText should be located below a SurfaceView. I use a RelativeLayout to arrange these two views. Now, when I tap on the EditText to open the virtual keyboard the SurfaceView slides up but the EditText is hidden and does not show the typed string. To reproduce, use the following layout XML code: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/RelativeLayout01" android:layout_height="fill_parent" android:layout_width="fill_parent"> <SurfaceView android:id="@+id/SurfaceView01" android:layout_width="fill_parent" android:layout_height="wrap_content"> </SurfaceView> <EditText android:id="@+id/EditText01" android:layout_height="wrap_content" android:layout_width="fill_parent" android:layout_alignParentLeft="true" android:layout_alignParentBottom="true" android:selectAllOnFocus="true" android:textStyle="normal" android:singleLine="true"> </EditText> </RelativeLayout> The main Activity class only needs to show the layout. When I start the program and tap the EditText, the virtual keyboard appears but the EditText field is gone. Maybe the RelativeLayout is causing the problems, but I don't know how to reproduce the same layout with another Layout class. Any suggestions are welcome, I really appreciate your help. Thanks. Edit: Here are two screenshots, one showing the EditText at the bottom without virtual keyboard, one with virtual keyboard but with no EditText. It is interesting to note that the SurfaceView and the EditText actually shift upward, the EditText just disappears. BTW this also happens to a button if it is next to the EditText. EditText below a SurfaceView (left); EditText is gone (right)

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  • iTextSharp 5.0 Footer is not displaying

    - by Rick Make
    I am trying to create a simple footer that would display on the bottom of each page of the pdf document. I created a class that inherits from PdfPageEventHelper and it is set properly because the OnEndPage() method is called. But my temporary footer is not displaying. Is there something wrong that I am doing in my OnEndPage() method: public override void OnEndPage(PdfWriter writer, Document document) { base.OnEndPage(writer, document); int pageN = writer.PageNumber; String text = "Page " + pageN + " of "; float len = bf.GetWidthPoint(text, 8); Rectangle pageSize = document.PageSize; cb.SetRGBColorFill(100, 100, 100); cb.BeginText(); cb.SetFontAndSize(bf, 8); cb.SetTextMatrix(pageSize.GetLeft(40), pageSize.GetBottom(30)); cb.ShowText(text); cb.EndText(); cb.AddTemplate(template, pageSize.GetLeft(40) + len, pageSize.GetBottom(30)); cb.BeginText(); cb.SetFontAndSize(bf, 8); cb.ShowTextAligned(PdfContentByte.ALIGN_RIGHT, "Printed On " + PrintTime.ToString(), pageSize.GetRight(40), pageSize.GetBottom(30), 0); cb.EndText(); }

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  • EL syntax error: Expression cannot start with binary operator

    - by auser
    Anyone have any creative ideas for how I can solve this warning? EL syntax error: Expression cannot start with binary operator caused by the following code: String.format("#{myController.deleteItemById(%d)}", getId()) My code looked like this before: "#{myController.deleteItemById(" + getId() + ")}" but this caused eclipse to generate the following warning: EL syntax error: String is not closed UPDATE: @ManagedBean(name = "myController") @ViewScoped public class MyController implements Serializable { private long id; private HtmlPanelGroup panel; public long getId() {return this.id; } private void getPanel() { /// bunch of code for programatically creating a form HtmlCommandButton deleteButton = new HtmlCommandButton(); deleteButton.setId(id); deleteButton.setValue(value); deleteButton.setActionExpression(/* EL expression used here */); } } <?xml version='1.0' encoding='UTF-8' ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets"> <!-- some other elements removed for the sake of clarity --> <h:body> <h:panelGroup binding="#{myController.panel}" /> </h:body> </html>

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  • Help with CSS - getting an element to fill 100% of the remaining vertical space

    - by Jack W-H
    Hi folks I'd consider myself a reasonable standard CSS/XHTML chap but I'm pretty baffled by this. The problem is available here: http://furnace.howcode.com - (note that the site is still in development, most stuff doesn't work, and it's likely to change fairly quickly as it is updated often). Basically I've got a fluid layout that needs to work in the same proportions on any resolution. Here's a screenshot of how the designer invisioned it (I apologise for my Paint-tool anotations): I want the tabs and the search box to STAY at the top of Col2, whilst there should be a scrollable area beneath it where the results are returned. I want NO vertical viewport scrolling, only within the 100%-height area thingy. My problem is this. If you take a look at http://furnace.howcode.com, you'll see that I've got a bit of a problem. I've made a placeholder black-background div which I will turn into the Tabs shortly. However I want the Col2 div to float BENEATH this and fill 100% of the remaining vertical height (i.e. go to the bottom of the screen, nomatter what the resolution is) and Col3 to be in the place where Col2 currently has been put (it normally is there automatically, when Col2 is in the right place!). I hope that makes sense. If you need to me to clarify please just ask. Cheers! Jack

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  • Error converting JSON to .Net object in asp.net

    - by Vinni
    Hello Guys, I am unable to convert JSON string to .net object in asp.net. I am sending JSON string from client to server using hidden field (by keeping the JSON object.Tostring() in hidden field and reading the hidden field value in code behind file) Json string/ Object: [[{"OfferId":"1","OrderValue":"11","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"11","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"11","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"2","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"2","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"67","HostingTypeID":"3"}, {"OfferId":"1","OrderValue":"67","HostingTypeID":"3"}], [{"OfferId":"1","OrderValue":"99","HostingTypeID":"6"}], [{"OfferId":"1","OrderValue":"10","HostingTypeID":"8"}]] .Net Object public class JsonFeaturedOffer { public string OfferId { get; set; } public string OrderValue { get; set; } public string HostingTypeID { get; set; } } Converstion code in code behind file byte[] byteArray = Encoding.ASCII.GetBytes(HdnJsonData.Value); MemoryStream stream = new MemoryStream(byteArray); DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(JsonFeaturedOffer)); object result= serializer.ReadObject(stream); JsonFeaturedOffer jsonObj = result as JsonFeaturedOffer; While converting i am getting following error: Expecting element 'root' from namespace ''.. Encountered 'None' with name '', namespace ''.

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  • Android: HTTPClient

    - by primal
    Hi, I was trying http-cleint tutorials from svn.apache.org. While running the application I am getting the following error in console. [2010-04-30 09:26:36 - HalloAndroid] ActivityManager: java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.MAIN cat=[android.intent.category.LAUNCHER] flg=0x10000000 cmp=com.org.example/.HalloAndroid } from null (pid=-1, uid=-1) requires android.permission.INTERNET I have added android.permission.INTERNET in AndroidManifest.xml. <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.org.example" android:versionCode="1" android:versionName="1.0"> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".HalloAndroid" android:label="@string/app_name" android:permission="android.permission.INTERNET"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-permission android:name="android.permission.INTERNET"></uses-permission> </manifest> The java code in HalloAndroid.java is as follows HttpClient httpclient = new DefaultHttpClient(); HttpGet httpget2 = new HttpGet("http://google.com/"); HttpResponse response2 = null; try { response2 = httpclient.execute(httpget2); } catch (ClientProtocolException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } catch (IOException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } HttpEntity entity = response2.getEntity(); if (entity != null) { long len = entity.getContentLength(); if (len != -1 && len < 2048) { try { Log.d(TAG, EntityUtils.toString(entity)); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } else { // Stream content out } Any help is much appreciated.

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  • Multiple screen support in android?

    - by Yugesh
    In my application have six buttons,the screen size is 4.65" 720p(720X1280 : xhdpi),device take this resolution from normal layout folder.when i run it in device.it display like the image am shown below.how to set this six buttons fit to the screen according to layout width and height.I don't know how to do.Can any one know please help me to solve this problem. My XML coding <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/home_xml" android:layout_width="match_parent" android:layout_height="match_parent" android:background="#ffffff" > <Button android:id="@+id/btn_login" android:layout_width="101dp" android:layout_height="193dp" android:layout_alignParentLeft="true" android:layout_below="@+id/imageView1" android:layout_marginLeft="4dp" android:layout_marginTop="78dp" android:background="@drawable/login_button" /> <Button android:id="@+id/btn_order" android:layout_width="101dp" android:layout_height="wrap_content" android:layout_alignBottom="@+id/btn_login" android:layout_alignTop="@+id/btn_login" android:layout_marginLeft="3dp" android:layout_toRightOf="@+id/btn_login" android:background="@drawable/order_button" /> <Button android:id="@+id/btn_abtus" android:layout_width="101dp" android:layout_height="wrap_content" android:layout_alignBottom="@+id/btn_order" android:layout_alignTop="@+id/btn_order" android:layout_marginLeft="3dp" android:layout_toRightOf="@+id/btn_order" android:background="@drawable/aboutus_button" /> <Button android:id="@+id/btn_outlet" android:layout_width="100dp" android:layout_height="198dp" android:layout_alignLeft="@+id/btn_login" android:layout_alignRight="@+id/btn_login" android:layout_below="@+id/btn_login" android:background="@drawable/outlets_button" /> <Button android:id="@+id/btn_feedback" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignBottom="@+id/btn_outlet" android:layout_alignLeft="@+id/btn_order" android:layout_alignRight="@+id/btn_order" android:layout_alignTop="@+id/btn_outlet" android:background="@drawable/feedback_button" /> <Button android:id="@+id/btn_games" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignBottom="@+id/btn_feedback" android:layout_alignLeft="@+id/btn_abtus" android:layout_alignRight="@+id/btn_abtus" android:layout_alignTop="@+id/btn_feedback" android:background="@drawable/games_button" /> <RelativeLayout android:id="@+id/relativeLayout1" android:layout_width="match_parent" android:layout_height="44dp" android:layout_alignParentRight="true" android:layout_alignParentTop="true" android:background="#98110e" > </RelativeLayout>

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  • Turning XSLT into a simple HTML snippet.

    - by jaasum
    http://drp.ly/yeAex <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/data/tour/entry"> <img src="{filename}"/> <h2>{heading}</h2> {description} </xsl:template> </xsl:stylesheet> Here is the code I am working with. I am a newbie to XSLT and I suppose I am not understanding how it transforms my XML into HTML entirely. This snippet of code I plan on loading via AJAX, so I really all I need it to output is a blank html document consisting only of these three items. I realize I am omitting the xsl:output tag and that is because I really don't understand how I can get this to just simply match that information to my tags in my xml without adding , tags etc. All it outputs is a string of text in an html document.

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  • Avoid extra xmlns:xsi while adding an attribute to XML root

    - by Rakesh kumar
    I am creating an xml file using this code: XmlDocument d = new XmlDocument(); XmlDeclaration xmlDeclaration = d.CreateXmlDeclaration("1.0", "utf-8", null); d.InsertBefore(xmlDeclaration,d.DocumentElement); XmlElement root = d.CreateElement("ITRETURN","ITR","http://incometaxindiaefiling.gov.in/ITR1"); XmlAttribute xsiNs = d.CreateAttribute("xsi:schemaLocation", "http://www.w3.org/2001/XMLSchema-instance"); xsiNs.Value = "http://incometaxindiaefiling.gov.in/main ITRMain10.xsd"; root.SetAttributeNode(xsiNs); //root.SetAttribute("xsi:schemaLocation", "http://www.w3.org/2001/XMLSchema-instance"); root.SetAttribute("xmlns:ITR1FORM", "http://incometaxindiaefiling.gov.in/ITR1"); root.SetAttribute("xmlns:ITR2FORM", "http://incometaxindiaefiling.gov.in/ITR2"); root.SetAttribute("xmlns:ITR3FORM", "http://incometaxindiaefiling.gov.in/ITR3"); root.SetAttribute("xmlns:ITR4FORM", "http://incometaxindiaefiling.gov.in/ITR4"); d.AppendChild(root); d.Save("c://myxml.xml"); and I am getting an output like this <?xml version="1.0" encoding="utf-8" ?> - <!-- Sample XML file generated by XMLSpy v2007 sp2 (http://www.altova.com) --> - <ITRETURN:ITR xsi:schemaLocation="http://incometaxindiaefiling.gov.in/main ITRMain10.xsd" xmlns:ITR1FORM="http://incometaxindiaefiling.gov.in/ITR1" xmlns:ITR2FORM="http://incometaxindiaefiling.gov.in/ITR2" xmlns:ITR3FORM="http://incometaxindiaefiling.gov.in/ITR3" xmlns:ITR4FORM="http://incometaxindiaefiling.gov.in/ITR4" xmlns:xsi="http://incometaxindiaefiling.gov.in/main ITRMain10.xsd" xmlns:ITRETURN="http://incometaxindiaefiling.gov.in/ITR1"> <ITR1FORM:ITR1>root node</ITR1FORM:ITR1> </ITRETURN:ITR> But my requirement is like <ITRETURN:ITR xsi:schemaLocation="http://incometaxindiaefiling.gov.in/main ITRMain10.xsd" xmlns:ITR1FORM="http://incometaxindiaefiling.gov.in/ITR1" xmlns:ITR2FORM="http://incometaxindiaefiling.gov.in/ITR2" xmlns:ITR3FORM="http://incometaxindiaefiling.gov.in/ITR3" xmlns:ITR4FORM="http://incometaxindiaefiling.gov.in/ITR4" xmlns:ITRETURN="http://incometaxindiaefiling.gov.in/main" xmlns:ITRForm="http://incometaxindiaefiling.gov.in/master" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> + <ITR1FORM:ITR1>any value </ITR1FORM:ITR1> </ITRETURN:ITR> What do I need to change in my code to get the desired output?

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  • Delphi app manifest file problems under WinXP and Win7

    - by Ronaldo Junior
    My last question "List service and services status under Win-7" made me start working on a solution that gives my app the admin privileges under Windows Vista onward based on a .manifest file. I was not sure about continue the previous question with this matter since they are not the same so here is another question: My app now works fine under Win 7 whether or not I run it "as admin" because of the manifest file. My manifest file is as follow: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <assembly xmlns="urn:schemas-microsoft-com:asm.v1" manifestVersion="1.0"> <assemblyIdentity version="1.6.0.5" processorArchitecture="X86" name="ServiceMonitorPro" type="win32"/> <description publisher="Powershield Ltd" product="Powershield Service Monitor">Powershield Service Monitor</description> <trustInfo xmlns="urn:schemas-microsoft-com:asm.v2"> <security> <requestedPrivileges> <requestedExecutionLevel level="requireAdministrator" uiAccess="false"/> </requestedPrivileges> </security> </trustInfo> </assembly> When the application runs on windows 7 or Vista, the UAC comes with a dialog like this: How can I replace the "unknow" publisher? The other and bigest problem is, even thou the app runs with no problem under Win7 or Vista, under WinXP it is now crashing with the message: "This application has failed to start because the application configuration is incorrect. Reinstalling the application may fix this problem." Another thing I would like to add: If I add reference (uses clause) to XPMan the app works fine on WinXP but then it my .manifest file makes no diference under Vista or Win7.

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  • Android, sending XML via HTTP POST (SOAP)

    - by Intosia
    Hi, I would like to invoke a webservice via Android. I need to POST some XML to a URL via HTTP. I found this snipped for sending a POST, but i dont know how to include/add the XML data itself. public void postData() { // Create a new HttpClient and Post Header HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://10.10.4.35:53011/"); try { // Add your data List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); nameValuePairs.add(new BasicNameValuePair("Content-Type", "application/soap+xml")); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); // Where/how to add the XML data? // Execute HTTP Post Request HttpResponse response = httpclient.execute(httppost); } catch (ClientProtocolException e) { // TODO Auto-generated catch block } catch (IOException e) { // TODO Auto-generated catch block } } This is the complete POST message that i need to imitate: POST /a8103e90-f1e3-11dd-bfdb-8b1fcff1a110 HTTP/1.1 Host: 10.10.4.35:53011 Content-Type: application/soap+xml Content-Length: 602 <?xml version='1.0' encoding='UTF-8' ?> <s12:Envelope xmlns:s12="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing"> <s12:Header> <wsa:MessageID>urn:uuid:fc061d40-3d63-11df-bfba-62764ccc0e48</wsa:MessageID> <wsa:Action>http://schemas.xmlsoap.org/ws/2004/09/transfer/Get</wsa:Action> <wsa:To>urn:uuid:a8103e90-f1e3-11dd-bfdb-8b1fcff1a110</wsa:To> <wsa:ReplyTo> <wsa:Address>http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous</wsa:Address> </wsa:ReplyTo> </s12:Header> <s12:Body /> </s12:Envelope>

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  • Help: Android paint/canvas issue; drawing smooth curves

    - by Wrapper
    How do I get smooth curves instead of dots or circles, when I draw with my finger on the touch screen, in Android? I am using the following code- public class DrawView extends View implements OnTouchListener { private static final String TAG = "DrawView"; List<Point> points = new ArrayList<Point>(); Paint paint = new Paint(); public DrawView(Context context) { super(context); setFocusable(true); setFocusableInTouchMode(true); this.setOnTouchListener(this); paint.setColor(Color.WHITE); paint.setAntiAlias(true); } @Override public void onDraw(Canvas canvas) { for (Point point : points) { canvas.drawCircle(point.x, point.y, 5, paint); // Log.d(TAG, "Painting: "+point); } } public boolean onTouch(View view, MotionEvent event) { // if(event.getAction() != MotionEvent.ACTION_DOWN) // return super.onTouchEvent(event); Point point = new Point(); point.x = event.getX(); point.y = event.getY(); points.add(point); invalidate(); Log.d(TAG, "point: " + point); return true; } } class Point { float x, y; @Override public String toString() { return x + ", " + y; } }

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  • Using android.view.SurfaceView with a camera on part of the screen

    - by oneself
    Hi, I trying to put together an Android app that will take a picture and process it in some way. I'd like the layout to be similar to Google Goggles. Meaning, camera preview on the top, and some controls on the bottom using portrait orientation. I've built a first version using code sample from here. This works, but I want to add a button on the bottom. I've modified my main.xml to look as follows: <?xml version="1.0" encoding="utf-8"?> <TableLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="150dp" android:stretchColumns="1"> <TableRow> <android.view.SurfaceView xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/preview" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </TableRow> <Button android:id="@+id/snap" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Snap" /> <TableRow> </TableRow> </TableLayout> But when I run this code I get an exception: java.lang.RuntimeException: startPreview failed. When I replace the SurfaceView above with something else, e.g. a TextView, that it displays, but in landscape. How can I get a camera preview on part of the screen using portrait view? Thanks

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  • Android NDK r4 san-angeles problem

    - by Goz
    Hi All, I'm starting to learn the android NDK and I've instantly come up against a problem. I'e built the tool chain (which took a LOT longer than I was expecting!!) and I've compiled the C++ code with no problems and now I'm trying to build the java code. Instantly I come up against a problem. There is a file "main.xml" <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="match_parent" android:layout_height="match_parent" > <TextView android:layout_width="match_parent" android:layout_height="wrap_content" android:text="Hello World, DemoActivity" /> </LinearLayout> and I get the following errors: Description Resource Path Location Type error: Error: String types not allowed (at 'layout_height' with value 'match_parent'). main.xml /DemoActivity/res/layout line 2 Android AAPT Problem error: Error: String types not allowed (at 'layout_height' with value 'match_parent'). main.xml /DemoActivity/res/layout line 2 Android AAPT Problem error: Error: String types not allowed (at 'layout_width' with value 'match_parent'). main.xml /DemoActivity/res/layout line 2 Android AAPT Problem error: Error: String types not allowed (at 'layout_width' with value 'match_parent'). main.xml /DemoActivity/res/layout line 7 Android AAPT Problem error: Error: String types not allowed (at 'layout_width' with value 'match_parent'). main.xml /DemoActivity/res/layout line 7 Android AAPT Problem So I can see the problem lies in the fact that these "match_parent" strings are in there. Anyone know how to fix this?

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  • Replacing instructions in a method's MethodBody

    - by Alix
    Hi, (First of all, this is a very lengthy post, but don't worry: I've already implemented all of it, I'm just asking your opinion.) I'm having trouble implementing the following; I'd appreciate some help: I get a Type as parameter. I define a subclass using reflection. Notice that I don't intend to modify the original type, but create a new one. I create a property per field of the original class, like so: public class OriginalClass { private int x; } public class Subclass : OriginalClass { private int x; public int X { get { return x; } set { x = value; } } } For every method of the superclass, I create an analogous method in the subclass. The method's body must be the same except that I replace the instructions ldfld x with callvirt this.get_X, that is, instead of reading from the field directly I call the get accessor. I'm having trouble with step 4. I know you're not supposed to manipulate code like this, but I really need to. Here's what I've tried: Attempt #1: Use Mono.Cecil. This would allow me to parse the body of the method into human-readable Instructions, and easily replace instructions. However, the original type isn't in a .dll file, so I can't find a way to load it with Mono.Cecil. Writing the type to a .dll, then load it, then modify it and write the new type to disk (which I think is the way you create a type with Mono.Cecil), and then load it seems like a huge overhead. Attempt #2: Use Mono.Reflection. This would also allow me to parse the body into Instructions, but then I have no support for replacing instructions. I've implemented a very ugly and inefficient solution using Mono.Reflection, but it doesn't yet support methods that contain try-catch statements (although I guess I can implement this) and I'm concerned that there may be other scenarios in which it won't work, since I'm using the ILGenerator in a somewhat unusual way. Also, it's very ugly ;). Here's what I've done: private void TransformMethod(MethodInfo methodInfo) { // Create a method with the same signature. ParameterInfo[] paramList = methodInfo.GetParameters(); Type[] args = new Type[paramList.Length]; for (int i = 0; i < args.Length; i++) { args[i] = paramList[i].ParameterType; } MethodBuilder methodBuilder = typeBuilder.DefineMethod( methodInfo.Name, methodInfo.Attributes, methodInfo.ReturnType, args); ILGenerator ilGen = methodBuilder.GetILGenerator(); // Declare the same local variables as in the original method. IList<LocalVariableInfo> locals = methodInfo.GetMethodBody().LocalVariables; foreach (LocalVariableInfo local in locals) { ilGen.DeclareLocal(local.LocalType); } // Get readable instructions. IList<Instruction> instructions = methodInfo.GetInstructions(); // I first need to define labels for every instruction in case I // later find a jump to that instruction. Once the instruction has // been emitted I cannot label it, so I'll need to do it in advance. // Since I'm doing a first pass on the method's body anyway, I could // instead just create labels where they are truly needed, but for // now I'm using this quick fix. Dictionary<int, Label> labels = new Dictionary<int, Label>(); foreach (Instruction instr in instructions) { labels[instr.Offset] = ilGen.DefineLabel(); } foreach (Instruction instr in instructions) { // Mark this instruction with a label, in case there's a branch // instruction that jumps here. ilGen.MarkLabel(labels[instr.Offset]); // If this is the instruction that I want to replace (ldfld x)... if (instr.OpCode == OpCodes.Ldfld) { // ...get the get accessor for the accessed field (get_X()) // (I have the accessors in a dictionary; this isn't relevant), MethodInfo safeReadAccessor = dataMembersSafeAccessors[((FieldInfo) instr.Operand).Name][0]; // ...instead of emitting the original instruction (ldfld x), // emit a call to the get accessor, ilGen.Emit(OpCodes.Callvirt, safeReadAccessor); // Else (it's any other instruction), reemit the instruction, unaltered. } else { Reemit(instr, ilGen, labels); } } } And here comes the horrible, horrible Reemit method: private void Reemit(Instruction instr, ILGenerator ilGen, Dictionary<int, Label> labels) { // If the instruction doesn't have an operand, emit the opcode and return. if (instr.Operand == null) { ilGen.Emit(instr.OpCode); return; } // Else (it has an operand)... // If it's a branch instruction, retrieve the corresponding label (to // which we want to jump), emit the instruction and return. if (instr.OpCode.FlowControl == FlowControl.Branch) { ilGen.Emit(instr.OpCode, labels[Int32.Parse(instr.Operand.ToString())]); return; } // Otherwise, simply emit the instruction. I need to use the right // Emit call, so I need to cast the operand to its type. Type operandType = instr.Operand.GetType(); if (typeof(byte).IsAssignableFrom(operandType)) ilGen.Emit(instr.OpCode, (byte) instr.Operand); else if (typeof(double).IsAssignableFrom(operandType)) ilGen.Emit(instr.OpCode, (double) instr.Operand); else if (typeof(float).IsAssignableFrom(operandType)) ilGen.Emit(instr.OpCode, (float) instr.Operand); else if (typeof(int).IsAssignableFrom(operandType)) ilGen.Emit(instr.OpCode, (int) instr.Operand); ... // you get the idea. This is a pretty long method, all like this. } Branch instructions are a special case because instr.Operand is SByte, but Emit expects an operand of type Label. Hence the need for the Dictionary labels. As you can see, this is pretty horrible. What's more, it doesn't work in all cases, for instance with methods that contain try-catch statements, since I haven't emitted them using methods BeginExceptionBlock, BeginCatchBlock, etc, of ILGenerator. This is getting complicated. I guess I can do it: MethodBody has a list of ExceptionHandlingClause that should contain the necessary information to do this. But I don't like this solution anyway, so I'll save this as a last-resort solution. Attempt #3: Go bare-back and just copy the byte array returned by MethodBody.GetILAsByteArray(), since I only want to replace a single instruction for another single instruction of the same size that produces the exact same result: it loads the same type of object on the stack, etc. So there won't be any labels shifting and everything should work exactly the same. I've done this, replacing specific bytes of the array and then calling MethodBuilder.CreateMethodBody(byte[], int), but I still get the same error with exceptions, and I still need to declare the local variables or I'll get an error... even when I simply copy the method's body and don't change anything. So this is more efficient but I still have to take care of the exceptions, etc. Sigh. Here's the implementation of attempt #3, in case anyone is interested: private void TransformMethod(MethodInfo methodInfo, Dictionary<string, MethodInfo[]> dataMembersSafeAccessors, ModuleBuilder moduleBuilder) { ParameterInfo[] paramList = methodInfo.GetParameters(); Type[] args = new Type[paramList.Length]; for (int i = 0; i < args.Length; i++) { args[i] = paramList[i].ParameterType; } MethodBuilder methodBuilder = typeBuilder.DefineMethod( methodInfo.Name, methodInfo.Attributes, methodInfo.ReturnType, args); ILGenerator ilGen = methodBuilder.GetILGenerator(); IList<LocalVariableInfo> locals = methodInfo.GetMethodBody().LocalVariables; foreach (LocalVariableInfo local in locals) { ilGen.DeclareLocal(local.LocalType); } byte[] rawInstructions = methodInfo.GetMethodBody().GetILAsByteArray(); IList<Instruction> instructions = methodInfo.GetInstructions(); int k = 0; foreach (Instruction instr in instructions) { if (instr.OpCode == OpCodes.Ldfld) { MethodInfo safeReadAccessor = dataMembersSafeAccessors[((FieldInfo) instr.Operand).Name][0]; // Copy the opcode: Callvirt. byte[] bytes = toByteArray(OpCodes.Callvirt.Value); for (int m = 0; m < OpCodes.Callvirt.Size; m++) { rawInstructions[k++] = bytes[put.Length - 1 - m]; } // Copy the operand: the accessor's metadata token. bytes = toByteArray(moduleBuilder.GetMethodToken(safeReadAccessor).Token); for (int m = instr.Size - OpCodes.Ldfld.Size - 1; m >= 0; m--) { rawInstructions[k++] = bytes[m]; } // Skip this instruction (do not replace it). } else { k += instr.Size; } } methodBuilder.CreateMethodBody(rawInstructions, rawInstructions.Length); } private static byte[] toByteArray(int intValue) { byte[] intBytes = BitConverter.GetBytes(intValue); if (BitConverter.IsLittleEndian) Array.Reverse(intBytes); return intBytes; } private static byte[] toByteArray(short shortValue) { byte[] intBytes = BitConverter.GetBytes(shortValue); if (BitConverter.IsLittleEndian) Array.Reverse(intBytes); return intBytes; } (I know it isn't pretty. Sorry. I put it quickly together to see if it would work.) I don't have much hope, but can anyone suggest anything better than this? Sorry about the extremely lengthy post, and thanks.

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  • Weblogic JDBC datasource,java.sql.SQLException: Cannot obtain XAConnection weblogic.common.resourcep

    - by gauravkarnatak
    I am using weblogic JDBC datasource and my DB is oracle 10g,below is the configuration. It used to work fine but suddenly it started giving problem,please see below exception. Weblogic JDBC datasource,java.sql.SQLException: Cannot obtain XAConnection weblogic.common.resourcepool.ResourceLimitException: No resources currently available in pool <?xml version="1.0" encoding="UTF-8"?> <jdbc-data-source xmlns="http://www.bea.com/ns/weblogic/90" xmlns:sec="http://www.bea.com/ns/weblogic/90/security" xmlns:wls="http://www.bea.com/ns/weblogic/90/security/wls" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.bea.com/ns/weblogic/920 http://www.bea.com/ns/weblogic/920.xsd" XL-Reference-DS jdbc:oracle:oci:@abc.COM oracle.jdbc.driver.OracleDriver user DEV_260908 password password dll ocijdbc10 protocol oci oracle.jdbc.V8Compatible true baseDriverClass oracle.jdbc.driver.OracleDriver 1 100 1 true SQL SELECT 1 FROM DUAL DataJndi OnePhaseCommit This exception is coming on dev environment where connected user is only one. I know, this is related to pool max size but I also suspect this could be due to oracle,might be oracle isn't able to create connections. below are my queries Is there any debug/logging parameter to enable datasource logging,so that I can check no of connections acquired,released and unused in logs ? How to check oracle connection limit for a particular user ?

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  • How to add controls to a Tab Layout in Android?

    - by chobo2
    Hi I am following this tutorial http://developer.android.com/intl/de/guide/tutorials/views/hello-tabwidget.html and have completed it. Now I would actually like to add you know some controls to these tabs like textboxes(text edit). How do I do this? I go to my mail.xml using eclipse as my ide and go to layout view and I now get a NullPointerException so I can't even drag stuff onto the layout anymore. Thanks Edit This is what I have <?xml version="1.0" encoding="utf-8"?> <TabHost xmlns:android="http://schemas.android.com/apk/res/android" android:id="@android:id/tabhost" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TabWidget android:id="@android:id/tabs" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <FrameLayout android:id="@android:id/tabcontent" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:id="@+id/textview1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="this is a tab" /> <EditText android:text="" android:id="@+id/EditText01" android:layout_width="wrap_content" android:layout_height="wrap_content" android:password="true"></EditText> </LinearLayout> <TextView android:id="@+id/textview2" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="this is another tab" /> <TextView android:id="@+id/textview3" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="this is a third tab" /> </FrameLayout> </LinearLayout> </TabHost>

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