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  • UIView scaled to thumbprint, what about subviews?

    - by Parad0x13
    I have a UIImageView that I create progmatically right? Works like a charm when I initWithImage and set the parameters for scaling to UIViewContentModeScaleToFill. I can scale all day long and create many different smaller 'thumbprint' sized versions of the UIImageView at whim, HOWEVER when I add subviews to said UIImageView and then try to scale the happy new parent the child subview does not scale! I looked around and found that I should enable the setAutoresizingSubviews boolean of the parentView to true (Which I did) and then call: ChildView.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth; Which I also did... now when I scale the parent view the child also scales but crazy wacked out like and goes all over the place (Not a very good way of putting it) but my point is that I assumed the child would scale proportionally to the parent and stay in the same place (Which it doesn't) My question is how do I set up my code so that when I scale my parent view by 1/4 or w/e to make a thumbprint of the view the children subviews that the parent view owns will scale accordingly and allow the 1/4 sized thumbprint to look just like the full sized view (Just smaller).

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  • Creating an OpenGL FPS camera: I have the position and orientation vectors, now what?

    - by Synthetix
    I have been struggling to create a first person camera in OpenGL ES 2.0 without using gluLookAt(). I grab the camera's orientation vectors (the way it's looking) from the current modelview matrix, and use that to calculate the new forward/backward (Z) translation value. I then calculate the strafe (X) value from the dot product of Z and Y (which is always 1.0). So, I have all the information I need to create a view matrix, but how do I do that without using gluLookAt? Almost all the examples I've seen use gluLookAt, but no such function exists in OpenGL ES 2.0. Besides, one of the moderators on cprogramming.com mentioned that gluLookAt is not appropriate for FPS cameras: http://cboard.cprogramming.com/game-programming/135390-how-properly-move-strafe-yaw-pitch-camera-opengl-glut-using-glulookat.html I am really confused by all the conflicting information I'm getting. I just want to create a first person camera that goes forward (W,S keys), side-to-side (A,D keys) and rotates around its center (Y axis only), Wolfenstein style. Any help on this would be much appreciated!

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  • How to stop an iteration of TextView when click in on one of the TextView?

    - by sgiro
    Hello, i have one doubt. I have an iteration of TextViews, and what i want is when i click in one TextView , i want stop the iteration and open a web, who can i know what TextView as been click on? i have this code: Iterator it = text.iterator(); while(it.hasNext()){ test = it.next(); test.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { //mWebView = (WebView) findViewById(R.id.webview); mWebView.setWebViewClient(new WebViewClient() { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } }); mWebView.getSettings().setJavaScriptEnabled(true); mWebView.loadUrl(url); } }); // condition to stop the iteration when i click on TextView } And what i want is the condition to stop the iteration when i click on the TextView that i want see, i try using some methods that are in the TextView and don't work. Anyone can help me? Thanks and forgive my English

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  • How do IOS know which viewController is being viewed and hence need viewWillAppear to be called

    - by Jim Thio
    How does iOs know? Does each view has a pointer to it's controller? What happened? When we pop a viewController from navigation, does the navigationController arrange which view should be called? For example: If I added: [[BNUtilitiesQuick window] addSubview:[BNUtilitiesQuick searchController].view]; viewWillAppear will be called. However, window doesn't know the viewController. I am passing the view outlet of the controller not the controller. How can iOs 5 knows that it has to call [[BNUtilitiesQuick searchController] viewWillAppear:YES]

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  • Taking screen shot of a SurfaceView in android

    - by Mostafa Imran
    I am using following method to taking screen shot of a particular view which is a SurfaceView. public void takeScreenShot(View surface_view){ // create bitmap screen capture Bitmap bitmap; View v1 = surface_view; v1.setDrawingCacheEnabled(true); bitmap = Bitmap.createBitmap(v1.getDrawingCache()); v1.setDrawingCacheEnabled(false); ByteArrayOutputStream bos = new ByteArrayOutputStream(); bitmap.compress(CompressFormat.PNG, 0, bos); byte[] imageData = bos.toByteArray(); } the problem is its giving me the whole activity screen image. But I need to take screen shot of the particular view. I tried other ways but those give me a black screen as screen shot, some posts says that it requires rooted device. Can any one help me please. I'm in need of this solution. Help me....

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  • photo upload with codeigniter

    I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

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  • Using Django.test.client to check template vars

    - by scott
    I've got a view that I'm trying to test with the Client object. Can I get to the variables I injected into the render_to_response of my view? Example View: def myView(request): if request.method == "POST": # do the search return render_to_response('search.html',{'results':results},context_instance=RequestContext(request)) else: return render_to_response('search.html',context_instance=RequestContext(request) Test: c = Client() response = c.post('/school/search/', {'keyword':'beagles'}) # how do I get to the 'results' variable??

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  • ListView created programmatically - emptyView doesn't show

    - by Yorick
    I've created custom ListView programmatically, and set view to show when ListAdapter is empty but nothing shows on the screen in that case, what can be wrong? public PlayerList(Context context, Activity activity) { super(context); mParent = activity; setOnItemClickListener( new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { ... } }; List<PlayerInfo> players; players = getPlayerList(); // here size of players == 0 setAdapter(new PlayersAdapter(this.getContext(), R.id.player_name, players)); LayoutInflater vi = (LayoutInflater)mParent.getSystemService(Context.LAYOUT_INFLATER_SERVICE); emptyView = vi.inflate(R.layout.empty_view, null); // emptyView is View, and member of PlayerList this.setEmptyView(emptyView); }

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  • Loop results executing twice

    - by ozzysmith
    I creating a simple site with PHP where the users can submit blogs and other users (who are logged in) can post comments on them. I have made a link called "comments" below each blog that when clicked will show / hide all the comments relevant to the specific blog (also if the user is logged in, it will show a form field in which they can submit new comments). So basically each blog will have multiple comments. I have done two different codes for this but they both have the same problem that each comment appears twice (everything else works fine). Could anyone point out why? mysql_select_db ("ooze"); $result = mysql_query ("select * from blog") or die(mysql_error()); $i = 1; while($row = mysql_fetch_array($result)) { echo "<h1>$row[title]</h1>"; echo "<p class ='second'>$row[blog_content]</p> "; echo "<p class='meta'>Posted by .... &nbsp;&bull;&nbsp; $row[date] &nbsp;&bull;&nbsp; <a href='#' onclick=\"toggle_visibility('something$i'); return false\">Comments</a><div id='something$i' style='display: none;'>"; $i++; $a = $row["ID"]; $result2 = mysql_query ("select * from blog, blogcomment where $a=blogID") or die(mysql_error()); while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username]</p><p>said:</p> <p>$sub[comment]</p>"; } if ( isset ($_SESSION["gatekeeper"])) { echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn); //second version of inner loop:// if ( isset ($_SESSION["gatekeeper"])) { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn);

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  • Attempted GCF app for Android

    - by Aaron
    I am new to Android and am trying to create a very basic app that calculates and displays the GCF of two numbers entered by the user. Here is a copy of my GCF.java: package com.example.GCF; import java.util.Arrays; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class GCF extends Activity { private TextView mAnswer; private EditText mA, mB; private Button ok; private String A, B; private int iA, iB; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mA = (EditText) findViewById(R.id.entry); mB = (EditText) findViewById(R.id.entry1); ok = (Button) findViewById(R.id.ok); mAnswer = (TextView) findViewById(R.id.answer1); ok.setOnClickListener(new OnClickListener() { public void onClick(View v) { A = mA.getText().toString(); B = mB.getText().toString(); } }); // the String to int conversion happens here iA = Integer.parseInt(A.trim()); iB = Integer.parseInt(B.trim()); while (iA != iB) { int[] nums={ iA, iB, Math.abs(iA-iB) }; Arrays.sort(nums); iA=nums[0]; iB=nums[1]; } updateDisplay(); } private void updateDisplay() { mAnswer.setText( new StringBuilder().append(iA)); } } Any Suggestions? Thank you!

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  • Getting Top (starting no , Ending no) rows from sqlserver

    - by Krishna Thota
    I'm using Grid view in my asp.net page and I'm fetching data from SQL Server and placing in my grid view. Now my problem is, I'm using paging and placing 50 rows per page in Grid view. I would like to fetch top 50 rows from database in the start up and bind to the Grid View and when i click on next page, then again go to the database and fetch Second Top 50 rows and bind to GV. and this process hasto continue until last row is fetched from Database. Can you tell me How to write Query in achieving this??

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  • Entering to index page?

    - by FullmetalBoy
    // // Post: /Search/Alternativ1/txtBoxTitle) [HttpPost] public ActionResult Alternativ1(int txtBoxTitle) { SokningMedAlternativ1 test= new SokningMedAlternativ1(); if (txtBoxTitel != null) { var codeModel = test.FilteraBokLista(txtBoxTitel); } return View(codeModel); } Problem: I have problem to find a solution to go back to my index page (first page when entering a website for the first time) view if txtBoxTitle has null. My request: How shall I enter to my index page view automatically if txtBoxTitle contains null? // Fullmetalboy

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  • How to refactor models without breaking WPF views?

    - by Tim Murphy
    I've just started learning WPF and like the power of databinding it presents; that is ignoring the complexity and confusion for a noob. My concern is how do you safely refactor your models/viewmodels without breaking the views that use them? Take the following snippet of a view for example: <Grid> <ListView ItemsSource="{Binding Contacts}"> <ListView.View> <GridView> <GridViewColumn Header="First Name" DisplayMemberBinding="{Binding Path=FirstName}"/> <GridViewColumn Header="Last Name" DisplayMemberBinding="{Binding Path=FirstName}"/> <GridViewColumn Header="DOB" DisplayMemberBinding="{Binding Path=DateOfBirth}"/> <GridViewColumn Header="# Pets" DisplayMemberBinding="{Binding Path=NumberOfPets}"/> <GridViewColumn Header="Male" DisplayMemberBinding="{Binding Path=IsMale}"/> </GridView> </ListView.View> </ListView> </Grid> The list is bound to the Contacts property, IList(Of Contact), of the windows DataSource and each of the properties for a Contact is bound to a GridViewColumn. Now if I change the name of the NumberOfPets property in the Contact model to PetCount the view will break. How do I prevent the view breaking?

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  • How can I inherit form and access controls from mother form?

    - by kasia
    Hi, I'm in the middle of writing my project and I have this problem: I try to write a library and I want to use it in my application. In library I have a form with menu strip, tool bar, list view, tree view and etc. Everything in library is protected. In my application I have created the form which inherit form the library. I can change and add new functionality to list view and tree view using designer panel in VS 2008 but I don't have access to menu strip and tool bar, even though they are protected. Why is that so? I will be thankful for some advice.

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  • How hard it will be for the programmer to learn MS SSRS adn SSIS [closed]

    - by user75380
    I have a programming background in php/python/java for 5 years and I know MySQL and PostgreSQL. Currently in our company the MSQL Business Intelligence person is leaving his job in 4 months. I am thinking of trying to go to his place, at least try as I want to move in Business Intelligence field in SSRS and SSIS. I just want to know that is it possible for me to get my head around those things in 4 months because I have no idea how they work and how hard it will be for me to pick up those things. Can I do that? I just want to know from experienced people if I can move towards that field? At least how should I start? In my area there are shortages of person, so once I know the stuff I can get into junior jobs easily but I want to know from experienced people.

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  • will any one solve my GOOGLE ranking Confusion? [on hold]

    - by India SEO Analyst
    Iam handling website www.usamovingandstorage.com and targeting keywords "chicago movers", but my website is on third page. But my website has nice backlink, and recently i removed irrelevant backlinks also. I compared my competitors' websites such as www.ampolmoving.com, www.chicagomovers.com and have no such big backlinks, but they are ranking first page in google. I compared the three websites in www.opensiteexplorer.org. In that my site has good results. Then How is it happened? I need full comparison, why my site is ranking in third page? what are the actions i need to take to rank in first page.

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  • What is the best 3-D technology for the "Online Room Planner" site?

    - by Omega
    The main user-case is: Create the 2D floor plan See the 3D view of the room in colors and in dynamic lighting (switching on and off the lamps) Select the furniture from the large library of predefined samples. Change the color and texture of the furniture samples. Create the photos of the 3D room view from different points. Also user can move and turn the camera in the room and discover the view.

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • Android OnKeyListener

    - by user346665
    Why I can't implement OnKeyListener with parameter View such as on example where parameters are (View v, int keyCode, KeyEvent event) I'm forced to use parameters (DialogInterface dialog, int keyCode, KeyEvent event) but not the View as I want.

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  • How to create a tabbar on clicking a row in table in iphone?

    - by Warrior
    My first view consist of table with 7 rows of data.When i click each row it should navigate to a view with tab bar with 4 tabitems .In this what is the proper approac of creating a tab bar. When should i create it.Should i create in didSelectRowAtIndexPath of the table in first view like this UITabBarController *tabbar=[[UITabBarController alloc] init]; Homepageview* vc1 = [[Homepageview alloc] initWithNibName:@"Homepageview" bundle:nil] ; vc1.tabBarItem.title=@"Home"; vc1.tabBarItem.image = [UIImage imageNamed:@"home.png"]; ShoppingView* vc2 = [[ShoppingView alloc] initWithNibName:@"ShoppingView" bundle:nil]; vc2.tabBarItem.title=@"Shopping"; vc2.tabBarItem.image = [UIImage imageNamed:@"shopping.png"]; Checkout* vc3 = [[Checkout alloc] initWithNibName:@"Checkout" bundle:nil] ; vc3.tabBarItem.title=@"Checkout"; vc3.tabBarItem.image = [UIImage imageNamed:@"checkout1.png"]; Settings *vc4=[[SlSettings alloc] initWithNibName:@"Settings" bundle:nil] ; vc4.tabBarItem.title=@"Settings"; vc4.tabBarItem.image = [UIImage imageNamed:@"setting1.png"]; tabbar.delegate = self; tabbar.viewControllers = [NSArray arrayWithObjects:vc1, vc2, vc3,vc4,nil]; //self.navigationItem.title=@"Snhopping list"; //[tabbar.selectedViewController viewDidAppear:YES]; [self.navigationController pushViewController:tabbar animated:YES]; [vc1 release]; [vc2 release]; [vc3 release]; [vc4 release]; [tabbar release]; Or is there any alternate to do it. If i do it by the above method , when i navigate from the home page view of tabbar to another view then i am not able to get tab bar.Please help me out.Thanks.

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  • Navigating between 2 ViewControllers

    - by Kobe.o4
    Im using Navigation Controller for my ViewControllers,I set my importantViewController as something like this to be its RootView: UINavigationController *navControl = [[UINavigationController alloc] initWithRootViewController: vc]; [self presentModalViewController: navControl animated: YES]; Then, I pushView anotherView the FrontViewController like this: [self.navigationController pushViewController:vc animated:YES]; After a button is pressed in FrontViewController another view will be pushed ViewA but it is connected with another ViewController ViewB the same way as this AGAIN: [self.navigationController pushViewController:vc animated:YES]; (Which I think Im doing wrong when dismissing either of them with [self.navigationController popViewControllerAnimated:YES];) This is an illustration: My problem is, I need to navigate between View A and View B then when I dismiss either of them it will got back to FrontViewController. Like a child of a child View. Thanks.

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  • How to insert additional content to page header from viewpage?

    - by madyalman
    Hi, I am new to asp.net mvc platform. I'm developing with razor template engine in mvc 3. I've created a layout page for all view pages but in some cases I need different page headers for different view pages. For example I have to insert additional script elements to page header to validate data in form pages. I want to know is there any way to add html element to layout page's header from view page? Thanks in advance.

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  • Gridview making a column invisable

    - by flyersun
    Hi I have a grid view which is dynamically generated via C# using a DataSet. I'm passing a row ID field (from the database) to the grid view, as this is required when a user clicks to edit a records. However I don't want the user to be able to view the column. I have tried the following but it doesn’t seem to work? Could anyone suggest a way to hide the column or a better way of attaching the information to the grid view row so it can be used at a later stage. c# DataColumn ColImplantCustomerDetailsID = new DataColumn(); ColImplantCustomerDetailsID.ColumnName = "Implant ID"; ColImplantCustomerDetailsID.DataType = typeof(int); ColImplantCustomerDetailsID.Visable = false; <-- visable doens't work here. asp.net

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  • Is it possible to change the default InputView in MonoTouch?

    - by Pwninstein
    I would like to display a different view than the standard keyboard (a picker control, or a date picker, for example) when a text field becomes first responder (i.e. gets focus). This would be really nice, because currently I'm pushing a custom view which contains my picker control onto the navigation stack where the user chooses an option, and then hits an OK or Cancel button. According to the documentation for UITextField.InputView: Assigning a custom view to this property causes that view to be presented instead. But, It's read only!!! Is there a workaround for this? Do I need to implement a custom UITextField control and somehow override the InputView property? Do I need to call some kind of native function? I'd really love not to have to do either of those things... but if I have to, so be it. Thanks in advance!

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