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  • Adding extra data to a Variable

    - by DogPooOnYourShoe
    Right now, my code plucks out only one value using Mysql. So I thought I might aswell add each found result to a variable, however I dont know how to do this. This must be a very basic question, but I cant find a answer for it echo '<table border="1">'; echo "<tr><td><b>Surname</b></td><td><b>Title/Name</b></td><td><b>Numbers</b></td><td><b>Telephone</b></td><td><b>Edit</b></td><td><b>Del</b></td></tr>\n"; while ($row= mysql_fetch_array($result)) { $Surname = $row["Surname"]; $Title = $row["TitleName"]; $Email = $row["Email"]; $Telephone = $row["Telephone"]; $id = $row["id"]; $MooringNumbers = $row['Number']; $Assignedto['AssignedTo']; } $MooringQuery = "select * FROM mooring WHERE AssignedTo='$id'"; $MooringResult = mysql_query($MooringQuery) or die("Couldn't execute query"); while ($row1= mysql_fetch_array($MooringResult)) { $AssignedTo = $row1["AssignedTo"]; $MooringNumbers = $row1["Number"]; echo '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; }

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  • Processing forms that generate many rows in DB

    - by Zack
    I'm wondering what the best approach to take here is. I've got a form that people use to register for a class and a lot of times the manager of a company will register multiple people for the class at the same time. Presently, they'd have to go through the registration process multiple times and resubmit the form once for every person they want to register. What I want to do is give the user a form that has a single <input/> for one person to register with, along with all the other fields they'll need to fill out (Email, phone number, etc); if they want to add more people, they'll be able to press a button and a new <input/> will be generated. This part I know how to do, but I'm including it to best describe what I'm aiming to do. The part I don't know how to approach is processing that data the form submits, I need some way of making a new row in the Registrant table for every <input/> that's added and include the same contact information (phone, email, etc) as the first row with that row. For the record, I'm using the Django framework for my back-end code. What's the best approach here? Should it just POST the form x times for x people, or is there a less "brute force" way of handling this?

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  • MVC 3, View Model for user registration process. Password validation not working properly

    - by sec_goat
    I am trying to create a user registration page using MVC 3, so that I can better understand the process of how it works, what's going on behind the scenes etc. I am running into some issues when trying to use [Compare] to check to see that the user entered the same password twice. I tried adding the ComparePassword field to my user model first, and found that would not work the way I wanted as I did not have the field in the database, so the obvious answer was to create a View Model using the same information including the ComparePassword field. So I now have created a User model and a RegistrationViewModel, however it appears that the [Compare] on the password is not returning anything, for instance no matter what I put in the two boxes, when I click create it gives no error, which seems to me to mean it was successfully validated. I am not sure what I am doing or not doing to make this work properly. I have tried updating the jQuery.Validate to the newest version as there were some bugs reported in older version, this has not helped my efforts. Below is a wall of code, that is what I am working with. } public class RegistrationViewModel { [Required] [StringLength(15, MinimumLength = 3)] [Display(Name = "User Name")] [RegularExpression(@"(\S)+", ErrorMessage = " White Space is not allowed in User Names")] [ScaffoldColumn(false)] public String Username { get; set; } [Required] [StringLength(15, MinimumLength = 3)] [Display(Name = "First Name")] public String firstName { get; set; } [Required] [StringLength(15, MinimumLength = 3)] [Display(Name = "Last Name")] public String lastName { get; set; } [Required] [Display(Name = "Email")] public String email { get; set; } [Required] [Display(Name = "Password")] [DataType(DataType.Password)] public String password { get; set; } [Required] [DataType(DataType.Password)] [Display(Name = "Re-enter Password")] [Compare("Password", ErrorMessage = "Passwords do not match.")] public String comparePassword { get; set; } }

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  • jQuery ajax response not operating correctly

    - by mmarceau
    Ok this is frustrating... The code below works "correctly" as far as sending the email address to the SaveEmail URL and it gets saved correctly each time I change the drop down. However it only outputs the "Successful" message once, no matter how many times I change the value in the drop down. The "data" that is returned is "Successful". I would like to show the message for a couple seconds, then fade it out. It works correctly the first time I change the drop down, after that the change happens and the value gets saved, but the "Successful" message doesn't display. jQuery code: $('#AgentEmails').change(function() { var NewAddress = $('#AgentEmails').val(); $.post('SaveEmail.aspx', { email: NewAddress }, function(data) { $('#SelectMsg').html("<b>" + data + "</b>").fadeOut(); }); }); HTML code: <select ID='AgentEmails' runat='server'> <option value="[email protected]">TEST</option> </select><span id='SelectMsg'></span> What needs to be changed in my code to make this operate correctly? Thanks for the help.

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  • Best practice on structuring asynchronous mailers (using Sidekiq)

    - by gbdev
    Just wondering what's the best way to go about structuring asynchronous mailers in my Rails app (using Sidekiq)? I have one ActionMailer class with multiple methods/emails... notifier.rb: class Notifier < ActionMailer::Base default from: "\"Company Name\" <[email protected]>" default_url_options[:host] = Rails.env.production? ? 'domain.com' : 'localhost:5000' def welcome_email(user) @user = user mail to: @user.email, subject: "Thanks for signing up!" end ... def password_reset(user) @user = user @edit_password_reset_url = edit_password_reset_url(user.perishable_token) mail to: @user.email, subject: "Password Reset" end end Then for example, the password_reset mail is sent in my User model by doing... user.rb: def deliver_password_reset_instructions! reset_perishable_token! NotifierWorker.perform_async(self) end notifier_worker.rb: class NotifierWorker include Sidekiq::Worker sidekiq_options queue: "mail" def perform(user) Notifier.password_reset(user).deliver end end So I guess I'm wondering a couple things here... Is it possible to define many "perform" actions in one single worker? By doing so I could keep things simple (one notifier/mail worker) as I have it and send many different emails through it. Or should I create many workers? One for each mailer (e.g. WelcomeEmailWorker, PasswordResetWorker, etc) and just assign them all to use the same "mail" queue with Sidekiq. I know it works as it is, but should I break out each of those mail methods (welcome_email, password_reset, etc) into individually mailer classes or is it ok to have them all under one class like Notifier? Really appreciate any advice here. Thanks!

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  • jquery problem in IE working fine in FF

    - by Bharanikumar
    function populate_customer_details(){ $.ajax({ type : 'POST', url : 'populate_customer_details.php', data: { email : $('#txt_email_id').val() }, success : function(data){ if(data=="NOROWSFOUND"){ alert("Sorry, Email ID not exist in our database"); document.getElementById("txt_email_id").focus(); }else{ var val = explode_all_into_arr(data,"|=|"); document.getElementById("FirstName").value = val[0]; document.getElementById("LastName").value = val[1]; document.getElementById("mobilecountrycode").value = parseInt(val[2]); document.getElementById("MobileNo").value = val[3]; document.getElementById("homecountrycode").value = parseInt(val[4]); document.getElementById("HomeNo").value = val[5]; document.getElementById("PaxEmail").value = val[6]; document.getElementById("PaxEmailConf").value = val[6]; } }, }); } This is my snippet purpose is getting the customer details and populate into textfield and combo box , That is Firstname will append into Firstname text field , Secondname will append into Secondname text field , Same like mobilecountrycode (but this is dropdown combo), Some time combo selectedindex work fine, but some time not selecting the value , I am not sure what s problem in that... Nothing works in IE , Also showing object expected error in IE , i have ajax_common.js : in this i added above script , in the page top first i included the jquery.js , Then i include ajax_common.js file, But no idea why this problem. Regards (NOTE i included the jquery.js ) ,

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  • jquery .on() toggle div

    - by lollo
    i'm developing a blog with dynamic content loaded via ajax request and i'm trying to hide/show the "post comment" form, of the article, with a button : <div id="post"> ... <ol id="update" class="timeline"> <!-- comments here --> </ol> <button class="mybutton Bhome">Commenta</button><!-- hide/show button --> <div class="mycomment"><!-- div to hide/show --> <form action="#" method="post"> Nome: <input type="text" size="12" id="name" /><br /> Email: <input type="text" size="12" id="email" /><br /> <textarea rows="10" cols="50" class="mytext" id="commentArea"></textarea><br /> <input type="submit" class="Bhome" value=" Post " /> </form> </div><!-- mycomment --> </div><!-- post --> This jquery code works well but has effect on All the posts... $("div").on("click", ".mybutton", function(e){ $(".mycomment").slideToggle("slow"); e.stopPropagation(); }); I want that only the clicked hide/show button has effect on the related article but f i have more than one article on my page the button with .mybutton class hides or shows all the comment form of all the articles.

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  • multiple-to-one relationship mysql, submissions

    - by Yulia
    Hello, I have the following problem. Basically I have a form with an option to submit up to 3 images. Right now, after each submission it creates 3 records for album table and 3 records for images. I need it to be one record for album and 3 for images, plus to link images to the album. I hope it all makes sense... Here is my structure. TABLE `albums` ( `id` int(11) NOT NULL auto_increment, `title` varchar(50) NOT NULL, `fullname` varchar(40) NOT NULL, `email` varchar(100) NOT NULL, `created_at` datetime NOT NULL, `theme_id` int(11) NOT NULL, `description` int(11) NOT NULL, `vote_cache` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; TABLE `images` ( `id` int(11) NOT NULL auto_increment, `album_id` int(11) NOT NULL, `name` varchar(30) NOT NULL, and my code function create_album($params) { db_connect(); $query = sprintf("INSERT INTO albums set albums.title = '%s', albums.email = '%s', albums.discuss_url = '%s', albums.theme_id = '%s', albums.fullname = '%s', albums.description = '%s', created_at = NOW()", mysql_real_escape_string($params['title']), mysql_real_escape_string($params['email']), mysql_real_escape_string($params['theme_id']), mysql_real_escape_string($params['fullname']), mysql_real_escape_string($params['description']) ); $result = mysql_query($query); if(!$result) { return false; } $album_id = mysql_insert_id(); return $album_id; } if(!is_uploaded_file($_FILES['userfile']['tmp_name'][$i])) { $warning = 'No file uploaded'; } elseif is_valid_file_size($_FILES['userfile']['size'][$i])) { $_POST['album']['theme_id'] = $theme['id']; create_album($_POST['album']); mysql_query("INSERT INTO images(name) VALUES('$newName')"); copy($_FILES['userfile']['tmp_name'][$i], './photos/'.$original_dir.'/' .$newName.'.jpg');

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  • How to best manage multi-frame MovieClips with classes?

    - by Arms
    After switching to AS3, I've been having a hell of a time figuring out the best way to manage MovieClips that have UI elements spread across multiple frames with a single class. An example that I am working on now is a simple email form. I have a MovieClip with two frames: the 1st frame has the form elements (text inputs, submit button) the 2nd frame has a "thank you" message and a button to go back to the first frame (to send another email) In the library I have linked the MovieClip to a custom class (Emailer). My immediate problem is how do I assign a MouseEvent.CLICK event to the button on the 2nd frame? I should note at this point that I am trying to avoid putting code on the timeline (except for stop() calls). This is how I am 'solving' the problem now: Emailer registers an event listener for a frame change ( addEventListener("frame 2", onFrameChange) ) On the 2nd frame of the MovieClip I am calling dispatchEvent(new Event("frame 2")); (I would prefer to not have this code on the frame, but I don't know what else to do) My two complaints with this method are that, first I have calls to addEventListener spread out across different class methods (I would rather have all UI event listeners registered in one method), and second that I have to dispatch those custom "onFrameChange" events. The second complaint grows exponentially for MovieClips that have more than just 2 frames. My so called solution feels makes me feel dirty and makes my brain hurt. I am looking for any advice on what to do differently. Perhaps there's a design pattern I should be looking at? Should I swallow my pride and write timeline code even though the rest of my application is written in class files (and I abhor the Flash IDE code editor)? I absolutely LOVE the event system, and have no problem coding applications with it, but I feel like I'm stuck thinking in terms of AS2 when working with mutl-frame movieclips and code. Any and all help would be greatly appreciated.

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  • Declaring an object of a conditional type with a System.Type

    - by Chapso
    I am attempting to launch a specific form depending on the selected node of a treeview on the doubleclick event. The code I need to use to launch the form is a little bulky becuase I have to ensure that the form is not disposed, and that the form is not already open, before launching a new instance. I'd like to have all of this checking happen in one place at the end of the function, which means that I have to be able to pass the right form type to the code at the end. I'm trying to do this with a System.Type, but that doesn't seem to be working. Could someone point me in the right direction, please? With TreeView.SelectedNode Dim formType As Type Select Case .Text Case "Email to VPs" formType = EmailForm.GetType() Case "Revise Replacers" formType = DedicatedReplacerForm.GetType() Case "Start Email" formType = EmailForm.GetType() End Select Dim form As formType Dim form As formType Try form = CType(.Tag, formType) If Not form.IsDisposed Then form.Activate() Exit Sub End If Catch ex As NullReferenceException 'This will error out the first time it is run as the form has not yet ' been defined. End Try form = New formType form.MdiParent = Me .Tag = form CType(TreeView.SelectedNode.Tag, Form).Show() End With

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  • How to update a row in Android database

    - by Sajan
    Hi all I want to update a row on clicking on update button,but its doesn't work. I have used following code. public void btnUpdate(View v) { handeler.updateData(updateName.getText().toString(), updatePhone .getText().toString(), updateEmail.getText().toString(),id); } public void updateData(String name, String phone, String email, String id) { ContentValues values = new ContentValues(); values.put(COLUMN_FIRST, name); values.put(COLUMN_SECOND, phone); values.put(COLUMN_THIRD, email); database.update(TABLE_NAME, values, id, null); } public void search() { Cursor cursor = handeler.getData(); if (cursor.moveToFirst()) { String phoneNo; phoneNo = updateByPhone.getText().toString(); do { String s1 = cursor.getString(2); if (phoneNo.compareTo(s1) == 0) { id = cursor.getString(0); updateName.setText(cursor.getString(1)); updateEmail.setText(cursor.getString(3)); updatePhone.setText(cursor.getString(2)); } } while (cursor.moveToNext()); } } So if any know please suggest me how to solve it. Thanks

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  • Appending a TR to Table Not Formatting Correctly

    - by TimNguyenBSM
    My PHP script is sending back an array: $currentStatus = ( isset( $status ) ) ? "1" : "0"; $html = "<tr><td>" . $email . "</td><td>" . ( ( $status->type == 0 ) ? "View Only" : ( ( $status->type == 1 ) ? "View & Mark" : "View, Mark & Edit" ) ) . "</td><td>Invited</td></tr>"; echo json_encode( array( $html, $currentStatus ) ); Then my jquery is appending this to the table: ... success: function( result ) { var resultArray = eval( result ); $( "#myTable tr:last").append( resultArray[0] ); ... } Problem is, when it prints, it prints the following extra marks: [email protected]<\/td> View Only<\/td> Invited<\/td><\/tr>","1"] If I only echo the HTML it appends to table just fine, but I cant do that because I need the $currentStatus back too to do something with it. Thanks!

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  • understanding the ORM models in MVC

    - by fayer
    i cant fully understand the ORM models in MVC. so i am using symfony with doctrine. the doctrine models are created. does this mean that i don't have to create any models? are the doctrine models the only models i need? where should i put the code that uses the doctrine models: eg. $phoneIds = array(); $phone1 = new Phonenumber(); $phone1['phonenumber'] = '555 202 7890'; $phone1->save(); $phoneIds[] = $phone1['id']; $phone2 = new Phonenumber(); $phone2['phonenumber'] = '555 100 7890'; $phone2->save(); $phoneIds[] = $phone2['id']; $user = new User(); $user['username'] = 'jwage'; $user['password'] = 'changeme'; $user->save(); $user->link('Phonenumbers', $phoneIds); should this code be in the controller or in another model? and where should i validate these fields (check if it exists in database, that email is email etc)? could someone please shed a light on this. thanks.

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  • Store Business Rules in XML Document, Validate afterwards in Java, how?

    - by JavaPete
    Example XML Rules document: <user> <username> <not-null/> <capitals value="false"/> <max-length value="15"/> </username> <email> <not-null/> <isEmail/> <max-length value="40"/> </email> </user> How do I implement this? I'm starting from scratch, what I currently have is a User-class, and a UserController which saves the User object in de DB (through a Service-layer and Dao-layer), basic Spring MVC. I can't use Spring MVC Validation however in our Model-classes, I have to use an XML document so an Admin can change the rules I think I need a pattern which dynamically builds an algorithm based on what is provided by the XML Rules document, but I can't seem to think of anything other than a massive amount of if-statements. I also have nothing for the parsing yet and I'm not sure how I'm gonna (de)couple it from the actual implementation of the validation-process.

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  • How to get instance of Boxy from within its contents?

    - by Chaaosh
    Hi How can i access the Instance of Boxy within its contents. I have a Link that loads a form in Boxy. Its displaying the boxy popup and its working fine. Now i want to access the instance of the boxy from form submit function. How can i do this. I have the code below. $('a.boxy').boxy({ modal:true, show:true, title:'&nbsp;', closeable:true, center:true, });//boxy link is loading the form <form name="subscribe" > name <input type="text" name="name" value="' /> <br /> email <input type="text" name="email" value="' /><br /> <input type="submit" name="submit" value="subscribe" onclick="submitform()" /> </form> <script> function submitform() { // here i want to access the boxy instance // also here i want to refer it and close it } </script> Kind suggest

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  • Warning ,i can not solving in PHP code

    - by user318068
    hi , in code there Warning Warning: mysql_fetch_array() expects parameter 1 to be resource, string given in C:\xampp\htdocs\Join.php on line 69 but i can not solving where exactly can you help me where the error in this code . <?php 51. include("connect.php"); 53. $email = mysql_query("select MemberEmail from members where MemberID= '$id' "); 54. while ($row = mysql_fetch_array($email)) 55. { 57. $memEmail=$row['MemberEmail']; } 62. $sql = mysql_query("select * from ninvite where recieverMemberEmail ='$memEmail' and viwed= '0' order by RoomID desc"); 64. $num =mysql_num_rows($sql); 67. if ($sql and $num >0 ) { 69. while($row=mysql_fetch_array($sql)) { 71. $sender=$row['SenderMemberID']; 73. $room=$row['RoomID']; 77. $sql2 =mysql_query("select MemberName from members where MemberID ='$sender' "); 78. $sql1 =mysql_query("select RoomName,RoomLogo from rooms where RoomID ='$room' "); 79. while($row=mysql_fetch_array($sql2)) { $mem =$row['MemberName']; } 84. while($rows=mysql_fetch_array($sql1)) { $Ro =$rows['RoomName']; $logo = $rows['RoomLogo']; } 89. ?> Thanks alot

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • Building html structure in php or javascript?

    - by Adam
    I've been doing a lot of ajax calls and using the returned data to build html with javascript. However, I've noticed some people are returning the constructed html in the ajax calls since they're doing it all in php. What is the preferred method? I have a bunch of stuff already using javascript, so I guess I would prefer not changing everything to use just php. But, I'm assuming php would be more "secure."? The following is what I've been doing: $main_frag = $("<div class='order-container'/>"); $contact_frag = $("<div class='group'><div class='line-data'>Name: "+data.name+"</div><div class='line-data'>Email: "+data.email+"</div><div class='line-data'>Phone: "+data.phone+"</div></div>"); $address_frag = $("<div class='group'><div class='line-data'>Address 1: "+data.address_one+"</div><div class='line-data'>Address 2: "+address2+"</div><div class='line-data'>City: "+data.city+"</div><div class='line-data'>Province: "+data.province+"</div><div class='line-data'>Postal Code: "+data.postal+"</div></div>"); etc.. I just want to hear the opinions of the community.

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  • How can you pass an object from the form_for helper to a method?

    - by Alex
    So let's say I have a form which is being sent somewhere strange (and by strange we mean, NOT the default route: <% form_for @form_object, :url => {:controller => 'application', :action => 'form_action_thing'} do |f| %> <%= f.text_field :email %> <%= submit_tag 'Login' %> <% end %> Now let's say that we have the method that accepts it. def form_action_thing User.find(????? :email ?????) end My questions are thus: How does can I make the object @form_object available to the receiving method (in this case, form_action_tag)? I've tried params[:form_object], and I've scoured this site and the API, which I have to post below because SO doesn't believe I'm not a spammer (I'm a new member), as well as Googled as many permutations of this idea as I could think of. Nothing. Sorry if I missed something, i'm really trying. How do I address the object, once I've made it accessible to the method? Not params[:form_object], I'm guessing.

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  • AS3---TypeError: Error #1009: Cannot access a property or method of a null object reference

    - by user571620
    I'm very new to flash and I really have no idea what I'm doing. Thank you in advance. its giving me that error after I click a button to go to another frame. After I get the error, some buttons do not go to its destination and instead it just does nothing. The error is as follows: TypeError: Error #1009: Cannot access a property or method of a null object reference. at wmhssports_fla::MainTimeline/frame39() Here is the code for frame 39: stop(); winter_btn.addEventListener(MouseEvent.CLICK, buttonClick1); function buttonClick1(event:MouseEvent):void{ gotoAndPlay(39); }; spring_btn_boys.addEventListener(MouseEvent.CLICK, buttonClick10); function buttonClick10(event:MouseEvent):void{ gotoAndPlay(114); }; fall_btn_boys.addEventListener(MouseEvent.CLICK, buttonClick11); function buttonClick11(event:MouseEvent):void{ gotoAndPlay(135); }; Edit: I could email the file to someone, if they could look at it for me? Its REALLY sketchy due to my inexperience with flash, but then again its not that big of a clip. email me at: [email protected]

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  • Paypal Sandbox 2014 Non US test account Sign Up proper link

    - by Flood Gravemind
    Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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  • Why ajax doesn't work unless I refresh or use location.href?

    - by Connor Tang
    I am working on a html project, which will eventually package by Phonegap. So I am trying to encode the data from html form to JSON format, then use ajax send to a php file resides on server, and receive the response to do something else. Now I use <a href='login.html'> in my index.html to open the login page. In my login page, I have this <script> $(document).ready(function(e) { $('#loginform').submit(function(){ var jData = { "email": $('#emailLogin').val(), "password": $('#Password').val()}; $.ajax({ url: 'PHP/login.php', type:'POST', data: jData, dataType: 'json', async: false, error: function(xhr,status){ //reload(); location.href='index.html'; alert('Wrong email and password'); }, success: function(data){ if(data[1] == 1){ var Id_user = data[0]; location.href='loginSuccess.html'; } } }); }); }); </script> to send my data to server. But I found that it won't work, it's still in the login page. I tried to enter data and submit again, it's still nothing happen. Until I refresh the login page and enter data again, it can give an error message or go to the loginsuccess page. However, when I use <script> function loadLogin(){ location.href='login.html'; } </script> to open the login page, everything works well. So what cause this? How can I modify this piece of code to make it better?

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • Notification 7 Days Before Payment PHP No Error Message

    - by user1858672
    So I have PHP script running on cron daily. It is suppose to check the date and send an email if it is 7 days before any payments as a reminder. I haven't used PHP in a long time so sorry if the way I did it was ridiculous or something. Thanks a lot. I would say what the problem is but I don't get any error message or anything.. <?php mysqli_connect("xxxxxx", "xxxxxxx", "xxxxxxxxx") or die(mysqli_error()); mysqli_select_db("xxxxxxxxx") or die(mysqli_error()); //Retrieve original payment dates and enter them into an array $result = mysqli_query("SELECT DateCreated FROM UserTable"); $payment_dates = mysqli_fetch_array($result); //Puts original payment date into month-day format $md_payment_dates = substr($payment_dates, 5); //Gets todays date in m-d format and adds 7 days to it $due_date = mktime(0, 0, 0, date("m"), date("d")+7); //Checks if any payment days match today's date. If there are none it script will stop. if (count(preg_grep($due_date, $md_payment_dates)) > 0) { //Retrieves usernames of users that have an invoice due. $users_to_pay = mysqli_fetch_array("SELECT Username IN UserTable WHERE DateCreated = $date"); //Notifies you via email $to = "[email protected]"; $subject = "7 Day Payment Reminder"; $message = "Hi, <br /> The following owe a payment in 7 days : " + $users_to_pay ".<br/> Their payments are due on " + $md_payment_dates " of this year."; mail($to, $subject, $message); exit(); }else{ exit(); } ?>

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  • Handling return value from Web Service Call Wrapper

    - by coffeeaddict
    I created this method below which makes an HTTP call to a 3rd party API. I just want opinions on if I'm handling this the best way. If the call fails, I need to return the ExistsInList bool value only if the response is not null. But in the last return statement, wouldn't I have to essentially do another return selectResponse == null ? false : selectResponse.ExistsInList; to check for null first just like the previous return in the catch? Just seems redundant the way I'm approaching this and I don't know if I really need to check for null again in the final return but I figure yes, because you can't always rely on the response to give you a valid response even if there were no errors picked up. public static bool UserExistsInList(string email, string listID) { SelectRecipientRequest selectRequest = new SelectRecipientRequest(email, listID); SelectRecipientResponse selectResponse = null; try { selectResponse = (SelectRecipientResponse)selectRequest.SendRequest(); } catch (Exception) { return selectResponse == null ? false : selectResponse.ExistsInList; } return selectResponse.ExistsInList; }

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