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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • In java web application, where should i store users photos?

    - by stunaz
    Hello, this questions may be stupid, but i dont really see how to resolve it : lest say that in my application, i have a user. This user edit his profile, and need to edit his avatar. Where should i store the avatar file? first of all i was saving all the files in src\main\webapp\resources , but each time i redeploy that folder empties. so i dedide to place in an other location : c:\wwwdir\resources, but i can't link local resources from remote pages, so i was not able to display any avatar . any idea? advise? link?

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  • A HREF URL won't work

    - by user3586248
    I am trying to get the following link to work. <a href='#' onclick='window.open(" | &ESPP_Info_URL | ");return false;'>Employee Stock Purchase Plan Information</a> Basically the &ESPP_Info_URL variable takes in a url so that the code below looks like... <a onclick="window.open(https://...);return false;" href="#">Employee Stock Purchase Plan Information</a> But when I click the url it just refreshes the page. Does anyone know how to get this to access the link within the window.open function?

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  • c++ - FIFO implementation

    - by Narek
    While implementing a FIFO I have used the following structure: struct Node { T info_; Node* link_; Node(T info, Node* link=0): info_(info), link_(link) {} }; I think this a well known trick for lots of STL containers (for example for List). Is this a good practice? What it means for compiler when you say that Node has a member with a type of it's pointer? Is this a kind of infinite loop? And finally, if this is a bad practice, how I could implement a better FIFO.

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  • Jquery show div on hover then when user hovers out of div hide it help?

    - by user342391
    I have a menu and when I hover one of the links a div shows. I want the user to be able to hover over this div but when the user hovers out of the div (mouseout i think its called) I want it to hide. Imagine a dropdown menu in css, the user hovers over the link and the sub nav is shown, when the user hovers out or away from the link and sub nav the sub nav dissapears. How can this be done with jquery??? this is what I have: $(document).ready(function(){ //when user hovers over plans the mainnavbottom is shown $(".plans").hover( function() { $(".mainnavbottom").show("fast"); }, function(){ $(".mainnavbottom").mouseout.hide("slow"); }); });

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  • Removing exception

    - by Nikhil K
    I have used this code for extracting urls from web page.But in the line of 'foreach' it is showing Object reference not set to an instance of an object exception. What is the problem? how can i correct that? WebClient client = new WebClient(); string url = "http://www.google.co.in/search?hl=en&q=java&start=10&sa=N"; string source = client.DownloadString(url); HtmlDocument doc = new HtmlDocument(); doc.LoadHtml(source); foreach (HtmlNode link in doc.DocumentNode.SelectNodes("//a[@href and @rel='nofollow']")) { Console.WriteLine(link.Attributes["href"].Value); }

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  • Whats the best way of using MVC + ajax (jquery) to load page content, aspx or ascx or both

    - by devzero
    I want to have a menu that when I click replaces the content of a "main" div with content from a mvc view. This works just fine if I use a .aspx page, but any master.page content is then doubled (like the and any css/js). If I do the same but uses a .ascx user control the content is loaded without the extras, but if any browser loads the menu item directly (ie search bot's or someone with JS disabled), the page is displayed without the master.page content. The best solution I've found so far is to create the content as a .ascx page, then have a .aspx page load this if it's called directly from the menu link, while the ajax javascript would modify the link to use only the .ascx. This leads to a lot duplication though, as every user control needs it's own .aspx page. I was wondering if there is any better way of doing this? Could for example the master.page hide everything that's not from the .aspx page if it was called with parameter ?ajax=true?

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  • cakephp links not relative

    - by Dan
    In my layout, I have a menu that I've included as an element, and it contains a link like so.. <? $html->link('New Part Number','/part_numbers/add'); ?> The problem that I have is that cake isn't redirecting correctly and it ends up sending me to "http://localhost/part_numbers/add" instead of "http://localhost/my_client_folder/client_app/part_numbers/add" (I'm building this locally). My cakephp app is stored a few directories below my webroot folder, but I thought cakephp would autodetect how to build the linking no matter where the application was located, right? So do i need to configure the application root folder, or create a route or something? Thanks!

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  • How to add visible menu item from php code (drupal)

    - by uta
    I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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  • Rails subscription limitations

    - by David Lyod
    I have an application with set limits on subscription attributes i/e a user can have five projects for subscription A but have ten for subscription B At present I run a check on there current usage when linking to the create action and if they are over there limit I do not display the link to create a new project. On the view (for the new project ) I again run the check (in a helper) to see if they can create a new project and if they are not I display a message stating so and a little upgrade link. Is this a secure method of stopping a user bypassing there subscription attribute limitations ? What about direct PUT requests etc ?

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  • Won't connect to the database

    - by user1657958
    I'm confused...I'm using the same code in a different document and in there it's not a problem to get a connection to the database. But in the new document it's just not working...(password, username, database name...all is checked and correct) :-/ <?php define ("DB_HOST", "db1234567.db.hello.com"); // set database host define ("DB_USER", "db1234567"); // set database user define ("DB_PASS","password123"); // set database password define ("DB_NAME","db1234567"); // set database name $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection."); $db = mysql_select_db(DB_NAME, $link) or die("Couldn't select database"); ?> In the browser I get this: "Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'db1234567'@'123.123.12.12 (using password: YES) in /homepages/12/1234567/test/test.php on line 8 Couldn't make connection." Would be cool if someone could help me :) I'm not seeing any error... Thx!

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  • jCarousel in drupal

    - by Rohit
    hi i have create a content type in which i have add two field first for image and second for its link. then i have made view in which i have use style as jCarousel. all images are showing and its working fine. but i want to gives the link also on image which i have create in content type. how can i do this. you can check what i want to implement. Please see the bottom image scroll(http://drupalsn.com/ ) how can i do this?

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  • [Javascript] Retrieve a URL of a frame

    - by Ricky
    Hi, guys: If I get a link <a href="/Users/ChangePassword.aspx" target="mainFrame"> in fraTopMenu, what (1) javascript can I add to get the current mainFrame's URL upon clicking the link and (2) append the URL to the querystrings? <frameset rows="60,*" cols="*" frameborder="no" border="0" framespacing="0"> <frame src="/Common/Manager/TopMenu.aspx" name="fraTopMenu" scrolling="no" noresize="noresize" id="fraTopMenu" title="" /> <frameset rows="*" cols="185,*" framespacing="0" frameborder="no" border="0"> <frame src="..." name="leftFrame" id="leftFrame" title="" /> <frame src="..." name="mainFrame" id="mainFrame" title="" /> </frameset> </frameset> Thank you.

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  • Save information from MS crash reporter?

    - by DGentry
    On Windows XP when a process crashes, we get a dialog box with a link: "To view technical information about the error report, click here." The "click here" link brings up a whole lot of information in a window, but no obvious way to save it to a file. Is there a way? It would be very nice to be able to send that data to several different external vendors we're working with. The only other option I see in the dialog box is to send it to Microsoft, but this crash is likely not Microsoft's fault and there is no reason to send it to them.

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  • Help me with Php session vs Header redirect?

    - by python
    I have the following pages: *page1.php <?php if (isset($_GET['link'])) { session_start(); $_session['myvariable'] = 'Hello World'; header('Location: http://' . $_SERVER['SERVER_NAME'] . dirname($_SERVER['REQUEST_URI']) . '/page2.php'); exit; } ?> <a href="<?php print $_SERVER['REQUEST_URI'] . '?link=yes';?>">Click Here</a> *page2.php <?php print 'Here is page two, and my session variable: '; session_start(); print $_session['myvariable']; //This line could not output. exit; ?> When I try output $_session['myvariable'] I did not get the result hello world message. I could not find out the solution to fix it .?

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  • Highlight curret page in jquery

    - by 3gwebtrain
    Hi, I have the 12 html pages. and all this pages are loads when the left navigation bar link clicked. in this, i need to add a class to the current link, which is clicked and loaded the page. i tried with this: $(function(){ $('#container li a').click(function(){ $('#container li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); if(currentPage==pathname){ $(this).addClass('current'); } else{ alert('wrong'); } // alert(pathname+' currentPage: '+currentPage); }) }) it works, but on page load, the class is removed, i don't know why it's happening.. any help?

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  • Paginator (Migration from Cake 1.3 to 2.0

    - by Christian Waschke
    i am struggling with the paginator in cakephp 2.0. While i am trying to migrate my application to 2.0 i cant find any solution to jump directly to the last page. In 1.3 it was quiet to do that from outside like this: echo $this->Html->link(__('Flights'), array('controller' => 'flights', 'action' => 'index','page' => 'last')); but this little trick putting 'page:last' in does not work anymore in 2.0. Of course there is a Paginator function called last, but this would only help if i would be already inside the app. My Problem is to access from an outside link directly the last page of the paginator. Thank you for reading, cdjw

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  • How do I remove line references in generate output in doxygen?

    - by MeThinks
    I want to remove lines look as follows but I still want to return source code browsing Definition at line 377 of file xxx.h. I have tried the following two in the doxygen config file but these just remove cross references on types # If the REFERENCES_RELATION tag is set to YES # then for each documented function all documented entities # called/used by that function will be listed. REFERENCES_RELATION = NO # If the REFERENCES_LINK_SOURCE tag is set to YES (the default) # and SOURCE_BROWSER tag is set to YES, then the hyperlinks from # functions in REFERENCES_RELATION and REFERENCED_BY_RELATION lists will # link to the source code. Otherwise they will link to the documentation. REFERENCES_LINK_SOURCE = NO update: I've just trying setting the following and seems to do the jobs but waiting to confirm if this is the correct way of achieving what I want SOURCE_BROWSER = NO

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  • Preventing SQL injecting in a database class

    - by Josh
    I'm building a database class and thought it'd be a good idea to incorporate some form of SQL injection prevention (duh!). Here's the method that runs a database query: class DB { var $db_host = 'localhost'; var $db_user = 'root'; var $db_passwd = ''; var $db_name = 'whatever'; function query($sql) { $this->result = mysql_query($sql, $this->link); if(!$this->result) { $this->error(mysql_error()); } else { return $this->result; } } } There's more in the class than that but I'm cutting it down just for this. The problem I'm facing is if I just use mysql_real_escape_string($sql, $this->link); then it escapes the entire query and leads to a SQL syntax error. How can I dynamically find the variables that need to be escaped? I want to avoid using mysql_real_escape_string() in my main code blocks, i'd rather have it in a function. Thanks.

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  • removing forward slash in .htaccess

    - by user1083644
    I am using Jobbersbase for my online job portal. In which i have given link to my main webpage page like this http://www.mydomain.com/aboutus.html, but its not working because the link is taking '/' at the end http://www.mydomain.com/aboutus.html/ I tried adding RewriteCond %{REQUEST_FILENAME}\.html -f in .htaccess , if i add that other links doesnt work which has / for example http://www.mydomain.com/jobs/ Now my .htaccess looks like this # AddType x-mapp-php5 .php # AddHandler x-mapp-php5 .php RewriteEngine On RewriteCond %{REQUEST_URI} .*/$ RewriteRule (.*)/$ $1 ErrorDocument 404 /page-unavailable/ <files ~ "\.tpl$"> order deny,allow allow from none deny from all </files> Someone please suggest me how to do it thanks

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  • Locking a detail view if a user is editing the item...

    - by BenTheDesigner
    Hi All I am developing a user manager which must control access to the detail view of editable items. At present, when a user clicks 'edit', the application queries the link table to check if a user is currently editing that page, if not, it allows access to the page and then inserts a record into the link table preventing another user from editing the same page at the same time. My question is what would the best way to handle the removal of records if say a user exists the browser without saving etc, therefore no action to remove the record. I have a couple of ideas but would like other input before I decide. BenTheDesigner

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  • Making successive "jQuery.load()"s in nested pages work

    - by terrestrial
    The main page ("parent.html") has a link that ajaxloads a page ("page1.html") into a div ("targetdiv") in the main page, like so: parent html: $("#targetdiv").html(loading).load('page1.html'); This works fine and "page1.html" is loaded into "targetdiv". The "page1.html" also has a link in it that is supposed to ajaxload another page ("page2.html") into "targetdiv" (onto itself), like so: page1.html: (in "targetdiv") $("#targetdiv").html(loading).load('page2.html'); This does not work; "html(loading)" comes up in "targetdiv" and stays there, "page2.html" is not loaded. If you're sure why this is so, tell me and I'll owe you a beer. All the best... (This page/site is not available on line.)

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  • help with arrays

    - by user267237
    i need help starting this program or a link that will help me with arrays...........Write a program that finds and outputs the minimum element in an array int A[10]

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