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  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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  • bulk insert from Java into Oracle

    - by Will Glass
    I need to insert many small rows rapidly into Oracle. (5 fields). With MySQL, I break the inserts into groups of 100, then use one insert statement for every group of 100 inserts. But with Oracle, user feedback is that the mass inserts (anywhere from 1000-30000) are too slow. Is there a similar trick I can use to speed up the programmatic inserts from Java into Oracle?

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  • In a MySQL SELECT query, can I use my "AS column" in a WHERE specification?

    - by user556352
    In my database I calculate distance between nodes with: SELECT DISTINCT dest.name, AsText(orig.location), AsText(dest.location), round((glength(linestringfromwkb(linestring((orig.location), (dest.location)))))) as distance FROM nodes orig, nodes dest WHERE orig.name='GERP' I would like to add "and distance < dest.visibility" at the end, but am told that distance is an unknown column. Any insight very much appreciated.

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  • What are advantages of using a one-to-one table relationship? (MySQL)

    - by byronh
    What are advantages of using a one-to-one table relationship as opposed to simply storing all the data in one table? I understand and make use of one-to-many, many-to-one, and many-to-many all the time, but implementing a one-to-one relationship seems like a tedious and unnecessary task, especially if you use naming conventions for relating (php) objects to database tables. I couldn't find anything on the net or on this site that could supply a good real-world example of a one-to-one relationship. At first I thought it might be logical to separate 'users', for example, into two tables, one containing public information like an 'about me' for profile pages and one containing private information such as login/password, etc. But why go through all the trouble of using unnecessary JOINS when you can just choose which fields to select from that table anyway? If I'm displaying the user's profile page, obviously I would only SELECT id,username,email,aboutme etc. and not the fields containing their private info. Anyone care to enlighten me with some real-world examples of one-to-one relationships?

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  • Parallel MySQL queries for HTML table - WHILE(x or y)?

    - by Beti Chode
    I'm trying to create a table using PHP. What I need is a table with two columns. So I have an SQL table with 4 fields - primary key id, language, word and definition. The language for each is either Arabic or Russian. I want a table that does the following: | defintion | |____________________| | | | rus1 | arab1 | | rus2 | arab2 | | rus3 | arab3 | | rus4 | | So it divides the list by English word, creates a for each English word, then lists Russian equivalents in the left column and Arabic in the right. However there are often not the same number for both. What I am doing right now is running a WHILE loop in a WHILE loop. The outer loop is running fine but I think I am doing the inner loop wrong. Here is the bulk of the code: $definitions=mysql_query("SELECT DISTINCT definition FROM words") WHILE($row=mysql_fetch_array($definitions) { ECHO '<tr><th colspan="2">' . $row['definition'] . '</th></tr>'; $russian="SELECT * FROM words WHERE language='Russian' AND definition='".$row['definition']."'"; $arabic="SELECT * FROM words WHERE language='Arabic' AND definition='".$row['definition']."'"; WHILE($rus=mysql_fetch_array($russian) or $arb=mysql_fetch_array($arabic)) { ECHO '<tr><td>'.$rus['word'].'</td><td>'.$arb['word'].'</td></tr>'; } } Sadly I am getting soemthing like this: | defintion | |____________________| | | | rus1 | | | rus2 | | | rus3 | | | rus4 | | | | arab1 | | | arab2 | | | arab3 | Not sure what other way I can do this? I tried changing the or to || thinking the different precedence would cause another outcome, but then I get ONLY the Russian column. I'm out of ideas, you guys are my only hope!

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  • What would be the most efficient way to do this search (mysql or text)?

    - by alex
    Suppose I have 500 rows of data, each with a paragraph of text (like this paragraph). That's it.I want to do a search that is not only based on words. (%LIKE%, not FULL_TEXT) What would be faster? SELECT * FROM ...WHERE LIKE "%query%"; This would put load on the database server. Select all. Then, go through each one and do .find = 0 This would put load on the web server. This is a website, and people will be searching frequently.

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  • Is there a way to combine these 3 tables? (mysql)

    - by ggfan
    I'm creating a "flagged" func that flags users, postings, and comments. I am currently using three tables: "flagged_users" "flagged_postings" and "flagged_comments". And in each table, there's: flagged_id, user_id/posting_id/comment_id, reason. Is there a way to combine into just one table? or is 3 tables the best?

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  • Is there something in MySQL like IN but which uses AND instead of OR?

    - by Skatox
    I need a SQL statement to retrieve records where it key (or any column) is in a associate table, for example: documentId termId 4 1 4 2 3 3 5 1 This: SELECT documentId FROM table WHERE termId IN (1,2,3) ...will retrieve any documentid value where the termid value is 1 or 2 or 3. Is there something like this but return documentid values where the termid values are 1 and 2 and 3? Like an IN but with AND.

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  • MySQL query to find the most popular value in a column joined by another value in a second table

    - by Budove
    I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

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  • Completely automated DVD insert-rip-compress-eject workflow

    - by Kevin L.
    (Partially inspired by this question.) Background: I have a PC hidden away behind an HD LCD in custom-built entertainment center. The only visible part of the PC is an external DVD drive, mounted above the Wii. The PC happens to have Windows XP on it; Hackintoshing and Linux might be possible, but I've had issues with drivers for the sound card before. Let's just assume that OS X and Linux are a no-go unless they provide a truly awesome and simple solution for this particular problem. Goal: I would like to have a completely automated workflow for ripping DVDs. Something like this: Push the eject button on the DVD drive, insert the DVD. PC recognizes that this is a video DVD (as opposed to data). PC rips DVD to hard drive. PC finishes ripping, and ejects the DVD tray. PC compresses DVD image into some format that an Xbox 360 can read. PC copies finished compressed video file to a particular folder, so that it can be read into a WMP11 library and seamlessly played by the Xbox 360. PC cleans up all temporary files. Done. The impetus to have this be completely automated is that I’ll never need to switch the TV to the PC’s input and fiddle with the wireless keyboard. That’s just needless user intervention. The UI doesn’t have to be pretty. Nor do I care about speed. And I can probably bridge several of the gaps with some creative Perl use. But it seems likely that many (or all) of the parts should already exist. Any thoughts?

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  • What is causing a Hibernate SQL query exception?

    - by Dark Star1
    Hi all and sorry in advance for this post but I've spent way too much time going around in circles so I'm hoping someone could shed a light on it here for me. I updated a webapp on Tomcat and I'm getting the following error which didn't exist on the previous version. Though I am quite confident that the part of code I modifed isn't to blame as I have tested the app on two different dev servers. The production server is configured thus: CentOS 5.4 virtual server with tomcat 5.5.23 running mysql 5.0.77. The two dev servers are: Windows XP SP2 running tomcat 5.5.23 with mysql 5.1.49 Mac OSX 10.6.6 Running tomcat 6 with mysql 5.1.51 The application was developed using struts (1.1 as far as I can gather) with hibernate 3 as the peristence layer. It only fails on the production server for some reason I can't fathom. I'd like to draw your attention to the java.sql.SQLException near the bottom. After some long searching I found this but because it was posted years ago (about 1 year before development started on this app I'm sure Hibernate has evolved from that version. as I can't find a way of implementing his solution. I use Eclipse Helios as an IDE. Thanks in advance for taking your time to read this, to all who manage to reply. javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) java.lang.Exception: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.dao.GenericDAO.findOne(GenericDAO.java:204) at fr.company.dao.UserDAO.findOneUser(UserDAO.java:146) at fr.company.service.UserPeer.logUser(UserPeer.java:72) at fr.company.action.login.LoginAction.execute(LoginAction.java:127) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) Caused by: org.hibernate.exception.SQLGrammarException: could not execute query at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:65) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43) at org.hibernate.loader.Loader.doList(Loader.java:2153) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2029) at org.hibernate.loader.Loader.list(Loader.java:2024) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:369) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:300) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:153) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1128) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79) at org.hibernate.impl.AbstractQueryImpl.uniqueResult(AbstractQueryImpl.java:749) at fr.company.dao.GenericDAO.findOne(GenericDAO.java:198) ... 26 more Caused by: java.sql.SQLException: Unknown column 'user0_1_.poloSize' in 'field list' at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:2928) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1571) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1666) at com.mysql.jdbc.Connection.execSQL(Connection.java:2994) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:936) at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1030) at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeQuery(NewProxyPreparedStatement.java:76) at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:139) at org.hibernate.loader.Loader.getResultSet(Loader.java:1669) at org.hibernate.loader.Loader.doQuery(Loader.java:662) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224) at org.hibernate.loader.Loader.doList(Loader.java:2150) ... 35 more

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  • Postfixadmin Invalid Query

    - by Jm Cruz
    This is my first time running a postfixadmin, so in my setup.php, I'm getting this error DEBUG INFORMATION: Invalid query: Unknown column 'create_date' in 'mailbox' I'm running it with MySQL. So if i'm right, my guess is that i need to create a column? under mailbox table on the postfix database? but how or whats the right syntax into creating a timedate column? My knowledge with mysql and postfix are very minimal btw. Thanks in advance.

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  • What email server should I choose?

    - by DCC
    I need a secure email server installed in debian-lenny with users in a mysql table. Also users are from multiple domains. Quota should be in mysql or a global variable for all users. What are my options ? THanks in advance for your help.

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  • mysqld_multi stop doesn't seem to work

    - by gravyface
    mysqld_multi stop 1 followed by (repeatedly, a few moments later) mysqld_multi report 1 returns: Reporting MySQL servers MySQL server from group: mysqld1 is running The instances work fine and when I reboot, I have to start the instances to get them to come back up (a separate issue I need to resolve), but the stop command doesn't seem to do anything. It truly doesn't stop the instance because in the instance log file I see this: 120619 11:12:39 mysqld_safe A mysqld process already exists after trying to run start after.

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  • HAProxy + Percona XtraDB Cluster

    - by rottmanj
    I am attempting to setup HAproxy in conjunction with Percona XtraDB Cluster on a series of 3 EC2 instances. I have found a few tutorials online dealing with this specific issue, but I am a bit stuck. Both the Percona servers and the HAproxy servers are running ubuntu 12.04. The HAProxy version is 1.4.18, When I start HAProxy I get the following error: Server pxc-back/db01 is DOWN, reason: Socket error, check duration: 2ms. I am not really sure what the issue could be. I have verified the following: EC2 security groups ports are open Poured over my config files looking for issues. I currently do not see any. Ensured that xinetd was installed Ensured that I am using the correct ip address of the mysql server. Any help with this is greatly appreciated. Here are my current config Load Balancer /etc/haproxy/haproxy.cfg global log 127.0.0.1 local0 log 127.0.0.1 local1 notice maxconn 4096 user haproxy group haproxy debug #quiet daemon defaults log global mode http option tcplog option dontlognull retries 3 option redispatch maxconn 2000 contimeout 5000 clitimeout 50000 srvtimeout 50000 frontend pxc-front bind 0.0.0.0:3307 mode tcp default_backend pxc-back frontend stats-front bind 0.0.0.0:22002 mode http default_backend stats-back backend pxc-back mode tcp balance leastconn option httpchk server db01 10.86.154.105:3306 check port 9200 inter 12000 rise 3 fall 3 backend stats-back mode http balance roundrobin stats uri /haproxy/stats MySql Server /etc/xinetd.d/mysqlchk # default: on # description: mysqlchk service mysqlchk { # this is a config for xinetd, place it in /etc/xinetd.d/ disable = no flags = REUSE socket_type = stream port = 9200 wait = no user = nobody server = /usr/bin/clustercheck log_on_failure += USERID #only_from = 0.0.0.0/0 # recommended to put the IPs that need # to connect exclusively (security purposes) per_source = UNLIMITED } MySql Server /etc/services Added the line mysqlchk 9200/tcp # mysqlchk MySql Server /usr/bin/clustercheck # GNU nano 2.2.6 File: /usr/bin/clustercheck #!/bin/bash # # Script to make a proxy (ie HAProxy) capable of monitoring Percona XtraDB Cluster nodes properly # # Author: Olaf van Zandwijk <[email protected]> # Documentation and download: https://github.com/olafz/percona-clustercheck # # Based on the original script from Unai Rodriguez # MYSQL_USERNAME="testuser" MYSQL_PASSWORD="" ERR_FILE="/dev/null" AVAILABLE_WHEN_DONOR=0 # # Perform the query to check the wsrep_local_state # WSREP_STATUS=`mysql --user=${MYSQL_USERNAME} --password=${MYSQL_PASSWORD} -e "SHOW STATUS LIKE 'wsrep_local_state';" 2>${ERR_FILE} | awk '{if (NR!=1){print $2}}' 2>${ERR_FILE}` if [[ "${WSREP_STATUS}" == "4" ]] || [[ "${WSREP_STATUS}" == "2" && ${AVAILABLE_WHEN_DONOR} == 1 ]] then # Percona XtraDB Cluster node local state is 'Synced' => return HTTP 200 /bin/echo -en "HTTP/1.1 200 OK\r\n" /bin/echo -en "Content-Type: text/plain\r\n" /bin/echo -en "\r\n" /bin/echo -en "Percona XtraDB Cluster Node is synced.\r\n" /bin/echo -en "\r\n" else # Percona XtraDB Cluster node local state is not 'Synced' => return HTTP 503 /bin/echo -en "HTTP/1.1 503 Service Unavailable\r\n" /bin/echo -en "Content-Type: text/plain\r\n" /bin/echo -en "\r\n" /bin/echo -en "Percona XtraDB Cluster Node is not synced.\r\n" /bin/echo -en "\r\n" fi

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  • 'ALTER table' for all tables in a database

    - by BassKozz
    How can I run the following for every table in a database: ALTER table [table_name] type=innodb; I don't want to have to manually run it for each table, but rather run it for all tables in a database. As an aside: If your curious as to why I am running this: http://bugs.mysql.com/bug.php?id=1341 & http://bugs.mysql.com/bug.php?id=1287

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  • Secure LAMP server for production use

    - by WalterJ89
    What is the procedure for securing a Linux, Apache, MySQL, PHP Server (or even Perl) for production use? Other than setting the MySql password and the root password for linux what other (maybe not so obvious) steps should be taken? Also what steps can I take if I was going to be extra paranoid that may not normally be nessasary? this is for a basic single site use but must be secure. Thank you. (sorry if this was asked before)

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  • All password with '$' inside (phpmyadmin) won't work [UTF-8 problem]

    - by Tristan
    Hello, i set up a dedicaced server with a tutorial. I set in PHP : mbstring.language=UTF-8 mbstring.internal_encoding=UTF-8 mbstring.http_input=UTF-8 mbstring.http_output=UTF-8 mbstring.detect_order=auto But each time there is a $ in the password (i have one for the root of mysql + other script) the password won't work. For example, I just removed the $ in the password for a script, and it worked. When i connect @root on mysql via phpmyadmin : don't work When i connect @root via PHP : works What can i do for this problem please ?

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