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  • making a password-only auth with bcrypt and mongoose

    - by user3081123
    I want to create service that let you login only with password. You type a password and if this password exists - you are logged in and if it's not - username is generated and password is encrypted. I'm having some misunderstandings and hope someone would help me to show where I'm mistaken. I guess, it would look somewhat like this in agularjs First we receive a password in login controller. $scope.signup = function() { var user = { password: $scope.password, }; $http.post('/auth/signup', user); }; Send it via http.post and get in in our node server file. We are provided with a compare password bcrypt function userSchema.methods.comparePassword = function(candidatePassword, cb) { bcrypt.compare(candidatePassword, this.password, function(err, isMatch) { if (err) return cb(err); cb(null, isMatch); }); }; So right now we are creating function to catch our http request app.post('/auth/signup', function(req, res, next) { Inside we use a compair password function to realize if such password exists or not yet. So we have to encrypt a password with bcrypt to make a comparison First we hash it same way as in .pre var encPass; bcrypt.genSalt(10, function(err, salt) { if (err) return next(err); bcrypt.hash(req.body.password, salt, function(err, hash) { if (err) return next(err); encPass=hash; )}; )}; We have encrypted password stored in encPass so now we follow to finding a user in database with this password User.findOne({ password: encPass }, function(err, user) { if (user) { //user exists, it means we should pass an ID of this user to a controller to display it in a view. I don't know how. res.send({user.name}) //like this? How should controller receive this? With $http.post? } else { and now if user doesn't exist - we should create it with user ID generated by my function var nUser = new User({ name: generId(), password: req.body.password }); nUser.save(function(err) { if (err) return next(err); )}; )}; )}; Am I doing anything right? I'm pretty new to js and angular. If so - how do I throw a username back at controller? If someone is interested - this service exists for 100+ symbol passphrases so possibility of entering same passphrase as someone else is miserable. And yeah, If someone logged in under 123 password - the other guy will log in as same user if he entered 123 password, but hey, you are warned to make a big passphrase. So I'm confident about the idea and I only need a help with understanding and realization.

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  • Classic asp paging and session state

    - by flavour404
    Hi, Working on a classic asp page that uses paging. The error I am having a problem with is this: Lets say that you have 5 pages returned in your record set and you are on page 2. You leave and come back, you then press the link for page 3, the trouble is your session has timed out. I don't know why this happens but the page is reloaded, but the session check is bypassed and of course when the page attempts to retrieve the record set the session variables are now empty so I am getting a message stating: error near ',' line 1, because now the query is defunct. How do I get around this? Thanks, Ron.

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  • How SEO friendly is this URL ?

    - by The_AlienCoder
    I have this products catalog site.For the sake of SEO, I would have wanted my 'view details' link to look some thing like this ~/products/26-productname or ~/products/26/productname On my machine I'm using a url re-writing module and it works well. Unfortunately My host(shared) does not support url re-writing modules or Aspnet 4.0 for now. So I came up with a workaround that attempts to be SEO friendly Instead of this : ~/Products/details.aspx?id=26 I decided to simply append the product name in the url and i.e ~/Products/details.aspx?product=26-Toshiba Qosmio Notebook So my question is how SEO friendly is such a URL and is my attempt worth anything at all?

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  • How do I theme Form API buttons in Drupal?

    - by larssg
    The default output from Drupal's Form API is: <input id="edit-submit" class="form-submit" type="submit" value="Save" name="op"/> How do I theme that so I get: <button id="edit-submit" class="form-submit" type="submit"> <span>Save</span> </button> I need the inner span-tag so I can use the sliding doors CSS technique. I guess I need to override theme_button($element) from form.inc but my attempts so far have been unsuccessful.

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  • C++: Overload != When == Overloaded

    - by Mark W
    Say I have a class where I overloaded the operator == as such: Class A { ... public: bool operator== (const A &rhs) const; ... }; ... bool A::operator== (const A &rhs) const { .. return isEqual; } I already have the operator == return the proper Boolean value. Now I want to extend this to the simple opposite (!=). I would like to call the overloaded == operator and return the opposite, i.e. something of the nature bool A::operator!= (const A &rhs) const { return !( this == A ); } Is this possible? I know this will not work, but it exemplifies what I would like to have. I would like to keep only one parameter for the call: rhs. Any help would be appreciated, because I could not come up with an answer after several search attempts.

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  • Spring Web Flow

    - by cedric
    hi. I am really having a problem about what to use as an alternative for web flow. I have read that not all functionalities should be handled by web flow. Only those which needs complex xstate management. For those easy stuffs like just login, editing or deleting records what will I use as an alternative for web flow?

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  • JPanel's child components paint/layout problem

    - by Tom Brito
    I'm having a problem that when my frame is shown (after a login dialog) the buttons are not on correct position, then in some miliseconds they go to the right position (the center of the panel with border layout). When I make a SSCCE, it works correct, but when I run my whole code I have this fast-miliseconds delay to the buttons to go to the correct place. Unfortunately, I can't post the whole code, but the method that shows the frame is: public void login(JComponent userView) { centerPanel.removeAll(); centerPanel.add(userView); centerPanel.revalidate(); centerPanel.repaint(); frame.setVisible(true); } What would cause this delay to the panel layout? (I'm running everything in the EDT) -- update In my machine, this SSCCE shows the layout problem in 2 of 10 times I run it: import java.awt.BorderLayout; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.SwingUtilities; public class TEST { public static void main(String[] args) throws Exception { SwingUtilities.invokeAndWait(new Runnable() { @Override public void run() { System.out.println("Debug test..."); JPanel btnPnl = new JPanel(); btnPnl.add(new JButton("TEST")); JFrame f = new JFrame("TEST"); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.getContentPane().setLayout(new BorderLayout()); f.getContentPane().add(btnPnl); f.pack(); f.setSize(800, 600); f.setVisible(true); System.out.println("End debug test!"); } }); } } The button first appers in the up-left, and then it goes to the center. Please, note that I'm understand, not just correct. Is it a java bug? --update OK, so the SSCCE don't show the problem with you that tried till now. Maybe it's my computer performance problem. But this don't answer the question, I still think Java Swing is creating new threads for make the layout behind the scenes.

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  • Remove all user's cookies/sessions when password is reset

    - by Juraj
    I'm interested in improving security of my TurboGears 2.2 application so that when user changes his password, it logs him out from all sessions and he must login again. When user changes password on browser 1, he must relogin on browser 2, too. Experiments show that this is not the case, especially if browser 2 had "remember me" enabled. It's standard quickstarted app using repoze.who. It seems maybe I need to change AuthTktCookiePlugin, but don't see a way to do it without much rewiring.

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  • How do detect that transaction has already been started?

    - by xelurg
    I am using Zend_Db to insert some data inside a transaction. My function starts a transaction and then calls another method that also attempts to start a transaction and of course fails(I am using MySQL5). So, the question is - how do I detect that transaction has already been started? Here is a sample bit of code: try { Zend_Registry::get('database')->beginTransaction(); $totals = self::calculateTotals($Cart); $PaymentInstrument = new PaymentInstrument; $PaymentInstrument->create(); $PaymentInstrument->validate(); $PaymentInstrument->save(); Zend_Registry::get('database')->commit(); return true; } catch(Zend_Exception $e) { Bootstrap::$Log->err($e->getMessage()); Zend_Registry::get('database')->rollBack(); return false; } Inside PaymentInstrument::create there is another beginTransaction statement that produces the exception that says that transaction has already been started.

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  • Is scala functional programming slower than traditional coding?

    - by Fred Haslam
    In one of my first attempts to create functional code, I ran into a performance issue. I started with a common task - multiply the elements of two arrays and sum up the results: var first:Array[Float] ... var second:Array[Float] ... var sum=0f; for(ix<-0 until first.length) sum += first(ix) * second(ix); Here is how I reformed the work: sum = first.zip(second).map{ case (a,b) => a*b }.reduceLeft(_+_) When I benchmarked the two approaches, the second method takes 40 times as long to complete! Why does the second method take so much longer? How can I reform the work to be both speed efficient and use functional programming style?

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  • Help with running crontab from root

    - by user242065
    Im using OSX and having trouble getting a cron job to run. I type the following: $ sudo -i $ crontab -e I then enter: * * * * * root ifconfig en0 down > /dev/null 0 19 * * * root ifconfig en0 down > /dev/null 0 7 * * * root ifconfig en0 up > /dev/null and no success, the first line is for testing. I want it to shut off my internet. The next two lines I plan to leave in, once I get this working. If I type this in to the terminal the internet goes off ifconfig en0 down Why is my cron job not shutting down the internet? FYI: This is a follow up question from http://stackoverflow.com/questions/3027362/how-can-i-write-a-cron-job-that-will-block-my-internet-from-7pm-to-7am-so-i-can most of the comments there are people making fun of me. And a few attempts to solve the problem with out cron jobs.

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  • How to change file contents in PHP ?

    - by Misha Moroshko
    I save in a file some info about users (like number of times user passed the login page, last visited time, and so on). I want to read this info from the file, and update it (add 1 to the counter, and change the last visited time). My question is: can I do it without opening the file twice ? I open the first time to read the contents, and then open it again to overwrite the contents with the updated ones. Thanks !

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  • How secure is .htaccess protected pages

    - by Steven smethurst
    Are there any known flaws with htaccess protected pages? I know they are acceptable to brute force attacks as there is no limit to the amount of times someone can attempt to login. And a user can uploaded and execute a file on the server all bets are off... Anything other .htaccess flaws?

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  • How do I reset the state of a view inside a tabbar?

    - by ABeanSits
    Hello CocoaTouch-Experts! This is a fairly straightforward question though my Googling session gave me nothing. How do I reset the state of a view hierarchy located in a tabbar programmatically? The behavior I want to replicate is when the user tapps on a tab twice. This causes the view located under that tab to return to it's initial state. The tab is "owned" by a UINavigationController and when the user reaches a certain point in the view hierarchy there is a button which I want to connect this behavior to. All my attempts have failed except calling on a method in AppDelegate which kills the view and adds it back to the UITabBarController again. But this does not feel like the right way to go. Thanks in advance. Best regards //Abeansits

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  • Gmail mail server

    - by Neveen
    Hello, I used use Google’s slick interface to get my mail and It’s always going to be here: https://mail.google.com/a/yourdomainhere.com I want to write python script that send mail so i failed to configure server settings smtp = smtplib.SMTP('what is mail server will be?', what is the port) smtp.login('[email protected]', 'pass') Please could any one help me ?? Thanks

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  • drupal open id - how to get details

    - by Arun
    I'm try to use drupal open id module. When i used to login using any provider id(yahoo,google..) the step it goes to registration page of my site. My question is how to populate details of the user to my form without additional burden to the user ?. For ex name,email-id etc. Is there any module associated with it ?

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  • Authenticating users in iPhone app

    - by Myron
    I'm developing an HTTP api for our web application. Initially, the primary consumer of the API will be an iPhone app we're developing, but I'm designing this with future uses in mind (such as mobile apps for other platforms). I'm trying to decide on the best way to authenticate users so they can access their accounts from the iPhone. I've got a design that I think works well, but I'm no security expert, so I figured it would be good to ask for feedback here. The design of the user authentication has 3 primary goals: Good user experience: We want to allow users to enter their credentials once, and remain logged in indefinitely, until they explicitly log out. I would have considered OAuth if not for the fact that the experience from an iPhone app is pretty awful, from what I've heard (i.e. it launches the login form in Safari, then tells the user to return to the app when authentication succeeds). No need to store the user creds with the app: I always hate the idea of having the user's password stored in either plain text or symmetrically encrypted anywhere, so I don't want the app to have to store the password to pass it to the API for future API requests. Security: We definitely don't need the intense security of a banking app, but I'd obviously like this to be secure. Overall, the API is REST-inspired (i.e. treating URLs as resources, and using the HTTP methods and status codes semantically). Each request to the API must include two custom HTTP headers: an API Key (unique to each client app) and a unique device ID. The API requires all requests to be made using HTTPS, so that the headers and body are encrypted. My plan is to have an api_sessions table in my database. It has a unique constraint on the API key and unique device ID (so that a device may only be logged into a single user account through a given app) as well as a foreign key to the users table. The API will have a login endpoint, which receives the username/password and, if they match an account, logs the user in, creating an api_sessions record for the given API key and device id. Future API requests will look up the api_session using the API key and device id, and, if a record is found, treat the request as being logged in under the user account referenced by the api_session record. There will also be a logout API endpoint, which deletes the record from the api_sessions table. Does anyone see any obvious security holes in this?

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  • Configuring log4j at runtime

    - by Neil
    I'm using org.apache.tools.ant.listener.Log4jListener to manage logging with my ant script. The ant script is highly configurable and designed to be run different ways with different parameters and therefore I need to be able to log to files specified at runtime. I have a log4j.properties which specifies a log file to be build.log, and despite my attempts to launch ant redefining properties defined in log4j.properties have been unsuccessful. The build ignores them and continues to write to build.log. I haven't found much support regarding writing to custom files unless it's in Java with their Logger class. Perhaps I'm thinking this through wrong. log4j.properties isn't treated in the same way as a property file in an ant script (hence overrideable from the command line)? Is there a way I can do this intelligently without writing a custom task or something?

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  • iOs receivedData from NSURLConnection is nil

    - by yhl
    I was wondering if anyone could point out why I'm not able to capture a web reply. My NSLog shows that my [NSMutableData receivedData] has a length of 0 the entire run of the connection. The script that I hit when I click my login button returns a string. My NSLog result is pasted below, and after that I've pasted both the .h and .m files that I have. NSLog Result 2012-11-28 23:35:22.083 [12548:c07] Clicked on button_login 2012-11-28 23:35:22.090 [12548:c07] theConnection is succesful 2012-11-28 23:35:22.289 [12548:c07] didReceiveResponse 2012-11-28 23:35:22.290 [12548:c07] didReceiveData 2012-11-28 23:35:22.290 [12548:c07] 0 2012-11-28 23:35:22.290 [12548:c07] connectionDidFinishLoading 2012-11-28 23:35:22.290 [12548:c07] 0 ViewController.h #import <UIKit/UIKit.h> @interface ViewController : UIViewController // Create an Action for the button. - (IBAction)button_login:(id)sender; // Add property declaration. @property (nonatomic,assign) NSMutableData *receivedData; @end ViewController.m #import ViewController.h @interface ViewController () @end @implementation ViewController @synthesize receivedData; - (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { NSLog(@"didReceiveResponse"); [receivedData setLength:0]; } - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { NSLog(@"didReceiveData"); [receivedData appendData:data]; NSLog(@"%d",[receivedData length]); } - (void)connectionDidFinishLoading:(NSURLConnection *)connection { NSLog(@"connectionDidFinishLoading"); NSLog(@"%d",[receivedData length]); } - (IBAction)button_login:(id)sender { NSLog(@"Clicked on button_login"); NSString *loginScriptURL = [NSString stringWithFormat:@"http://www.website.com/app/scripts/login.php?"]; NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:loginScriptURL]]; NSString *postString = [NSString stringWithFormat:@"&paramUsername=user&paramPassword=pass"]; NSData *postData = [postString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; [theRequest setHTTPMethod:@"POST"]; [theRequest setHTTPBody:postData]; // Create the actual connection using the request. NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self]; // Capture the response if (theConnection) { NSLog(@"theConnection is succesful"); } else { NSLog(@"theConnection failed"); } } @end

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