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  • Safari Web Inspector is not updating when I update an element with ajax

    - by Ashley
    I have a checkout page http://www.oipolloi.com/oipolloi/shop/viewbasket.php with multiple ajax calls after certain items update (EG look up postage cost when country is changed, then update discount boxes etc). I've asked for help in the past about the best method of making sure ALL calls have returned before allowing the form to be submitted for payment processing: http://stackoverflow.com/questions/2290372/how-do-i-prevent-form-submission-until-multiple-ajax-calls-have-finished-jquery I was fairly happy that the logic in the finished solution was correct, but I have still been receiving reports that people using Safari are able to submit the form without the ajax calls returning properly. I have tried using the Safari Web Inspector to debug but it seems that when you Inspect Element, then update an element with an ajax call, the Inspector doesn't seem to update. I am updating hidden fields, so it's hard to be able to know whether the problem lies with the DOM not being updated properly, or the Inspector itself. I'm using Safari 4.0.5 on PC and you can reproduce the problem above by looking for a div id="countryFieldsBilling" with Web Inspector. It should contain three hidden fields that are initially empty. You can try to make it update (or not) by choosing a country from the select menu at the bottom of 'Shipping Address' box, and then clicking the 'click to use Shipping Address' link at the top of the 'Billing Address' just below. The behaviour I am seeing is that the country chosen in the shipping select gets copied correctly to the country in the billing select, but the hidden inputs in the Web Inspector do not get updated. When these hidden inputs do not get updated, this causes the problem that Mac Safari users report. If you can let me know either how to get Web Inspector to work properly, or something else I may have missed in the behaviour of Mac Safari that may cause these problems, that would be great. Thanks in advance

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • Servlet doPost() Method setup?

    - by Mark R
    I am interested in creating a web app that uses JSP, Servlets and XML. At the moment I have the following: JSP - Form input. Servlet - Retrieving Form data and sending that data to a java object. Java object (1) - Converts data into XML file....instantiates java object (2). Java object (2) - Sends that file to a database. On the returning side the database will send back another XML file that I will then process using XSLT to display back to the user. Can I place that XSLT code in the orignial Servlets doPost() method? So my doPost()` method would: Retrieve user inputted data from the form on my JSP page. Instantiate a java object to convert that data to XML, in-turn that object will instantiates another object to send the XML file to a database. Converts the resulting XML file sent from the database and displays it for the user. Can one servlet doPost() method handle all of this? If not, how would I set up my application and classes to handle this work flow? Thank you in advance

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • Why NOT use POST method here?

    - by Camran
    I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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  • How to link different Servlet together?

    - by Harry Pham
    First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • how to validate the dropdownlist box values on submit

    - by kumar
    Hello friends, I have validate_excpt on Form Before Submit I am doing this.. on the View I have two dropdown listboxes I am using On Submit I need to check.. If I selet ResolutionCode I need to validat ReasonCode Dropdownlist that It should select if not Pelase select ReasonCode I should Dispaly? Do I need to do this on Submit ButtonClick? or Can I do it on Validate_excpt? Can anybody help me out? <label for="ResolutionCode"> Resolution: <span> <%=Html.DropDownListFor(model => model.ResolutionCode, new SelectList(Model.LookupCodes["C_EXCPT_RESL"], "Key", "Value"))%> </span> </label> <label for="ReasonCode"> Reason: <span><%=Html.DropDownListFor(model => model.ReasonCode, new SelectList(Model.LookupCodes["C_EXCPT_RSN"], "Key", "Value"))%></span> </label> function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; return true; } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg-ID span:last').html('<strong>Update successful.</strong>'); } else { $('#error-msg-ID span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); } $('#error-msg-ID').removeClass('hide'); } $('#exc-').ajaxForm({ target: '#error-msg-ID', beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' });

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  • Pass a model object while using a upload

    - by Dejan.S
    I'm trying to pass my model object along with the file I'm uploading but I'm stuck on how I should that should be done. This is the code I use now [AcceptVerbs(HttpVerbs.Post)] public ActionResult Upload(PageBody pageBody) { foreach (string file in Request.Files) { var hpf = Request.Files[file] as HttpPostedFileBase; if (hpf.ContentLength == 0) continue; string savedFileName = Path.Combine(AppDomain.CurrentDomain.BaseDirectory + "Content/Uploads/", Path.GetFileName(hpf.FileName)); hpf.SaveAs(savedFileName); _pageBody.Pictures.Add(new PageBodyPicture() { Picture = file }); } return View(pageBody); } here is my view code, I got the model.Id but there but it wont pass even if I put just Id to the Upload method. <form action="/Admin/Upload" enctype="multipart/form-data" method="post"> <%= Html.HiddenFor(model => model.Id)%> <input type="file" name="file" id="file" /><br /> <input type="submit" name="submit" value="Upload" /> </form>

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  • Rails Model inheritance in forms

    - by Tiago
    I'm doing a reporting system for my app. I created a model ReportKind for example, but as I can report a lot of stuff, I wanted to make different groups of report kinds. Since they share a lot of behavior, I'm trying to use inheritance. So I have the main model: model ReportKind << ActiveRecord::Base end and created for example: model UserReportKind << ReportKind end In my table report_kinds I've the type column, and until here its all working. My problem is in the forms/controllers. When I do a ReportKind.new, my form is build with the '*report_kind*' prefix. If a get a UserReportKind, even through a ReportKind.find, the form will build the 'user_report_kind' prefix. This mess everything in the controllers, since sometimes I'll have params[:report_kind], sometimes params[:user_report_kind], and so on for every other inheritance I made. Is there anyway to force it to aways use the 'report_kind' prefix? Also I had to force the attribute 'type' in the controller, because it didn't get the value direct from the form, is there a pretty way to do this? Routing was another problem, since it was trying to build routes based in the inherited models names. I overcome that by adding the other models in routes pointing to the same controller.

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  • Is this the intention behavior in JComboBox? How I can avoid this behavior?

    - by Yan Cheng CHEOK
    I realize that if you are having a same selection in JComboBox, using up/down arrow key, will not help you to navigate the selection around. How I can avoid this behavior? See the below screen shoot /* * To change this template, choose Tools | Templates * and open the template in the editor. */ /* * NewJFrame.java * * Created on May 8, 2010, 7:46:28 PM */ package javaapplication26; /** * * @author yccheok */ public class NewJFrame extends javax.swing.JFrame { /** Creates new form NewJFrame */ public NewJFrame() { initComponents(); /* If you are having 3 same strings here. Using, up/down arrow key, * will not move the selection around. */ this.jComboBox1.addItem("Intel"); this.jComboBox1.addItem("Intel"); this.jComboBox1.addItem("Intel"); } /** This method is called from within the constructor to * initialize the form. * WARNING: Do NOT modify this code. The content of this method is * always regenerated by the Form Editor. */ @SuppressWarnings("unchecked") // <editor-fold defaultstate="collapsed" desc="Generated Code"> private void initComponents() { jComboBox1 = new javax.swing.JComboBox(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); jComboBox1.setEditable(true); javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane()); getContentPane().setLayout(layout); layout.setHorizontalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(105, 105, 105) .addComponent(jComboBox1, javax.swing.GroupLayout.PREFERRED_SIZE, 158, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(137, Short.MAX_VALUE)) ); layout.setVerticalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(63, 63, 63) .addComponent(jComboBox1, javax.swing.GroupLayout.PREFERRED_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(217, Short.MAX_VALUE)) ); pack(); }// </editor-fold> /** * @param args the command line arguments */ public static void main(String args[]) { java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new NewJFrame().setVisible(true); } }); } // Variables declaration - do not modify private javax.swing.JComboBox jComboBox1; // End of variables declaration }

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • How can I save an ASP.NET IFRAME from a custom entity's OnSave event, reliably?

    - by Forgotten Semicolon
    I have a custom ASP.NET solution deployed to the ISV directory of an MS Dynamics CRM 4.0 application. We have created a custom entity, whose data entry requires more dynamism than is possible through the form builder within CRM. To accomplish this, we have created an ASP.NET form surfaced through an IFRAME on the entity's main form. Here is how the saving functionality is currently laid out: There is an ASP.NET button control on the page that saves the entity when clicked. This button is hidden by CSS. The button click event is triggered from the CRM OnSave javascript event. The event fires and the entity is saved. Here are the issues: When the app pool is recycled, the first save (or few) may: not save be delayed (ie. the interface doesn't show an update, until the page has been refreshed after a few sec) Save and Close/New may not save For issue 1.1 and 2, what seems to be happening is that while the save event is fired for the custom ASP.NET page, the browser has moved on/refreshed the page, invalidating the request to the server. This results in the save not actually completing. Right now, this is mitigated with a kludge javascript delay loop for a few seconds after calling the button save event, inside the entity OnSave event. Is there any way to have the OnSave event wait for a callback from the IFRAME?

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  • Sending mail through PHP

    - by Angeline Aarthi
    I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

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  • php + MySQL editing table data.

    - by Jacksta
    This question is relating to 2 php scripts. The first script is called pick_modcontact.php where I choose a contact (from a contact book like phone book), then posts to the script show_modcontact.php When I click the submit button on the form on pick.modcontact.php. As a result of submitting the form I am then taken to show_modcontact.php. As the variables are not present the user is directed back to pick_modcontact.php I can not work out how to correct the code so that it will show the results of the script show_modcontact.php This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION['valid'] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST['id']) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION['valid'] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '" . $_POST['id'] . "'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="text" name="id" value="<? echo $_POST['id']; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1"; ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2"; ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3"; ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode"; ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country"; ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email;" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday"; ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html> note for site admin, I am re posting this question with the hope of someone else reading over it. older questions seem to go dead after a while.

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  • Zend Framework/PHPUnit: How to Stub/Mock an object method that connects to a database?

    - by Andrew
    In my Zend Framework project, I have a form that I am testing. In my form, a multi-select element gets its options from a model, which gets the data from the database. public function init() { $this->addElement('select', 'Region_ID', array('multiOptions' => $this->getRegions())); } protected function getRegions() { $mapper = new Model_RegionMapper(); return $mapper->getFormSelectData(); //this method will try to connect to a database (or get another object that will connect to the database) } I tried copying the example in the PHPUnit documentation, but it doesn't seem to be working. public function setUp() { $stub = $this->getMock('Model_RegionMapper'); $stub->expects($this->any()) ->method('getFormSelectData') ->will($this->returnValue(array('testdata'))); } public function testFoo() { //this will fail $form = new My_Form(); } The test fails because it is trying to find a table in the database that doesn't exist. But I don't want it to connect to the database at all. How do I correctly stub/mock this method so that it doesn't call the database?

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  • Initialize child models at model creation

    - by Antoine
    I have a model Entree which belongs to a model Vin, which itself belongs to a model Producteur. On the form for Entree creation/edition, I want to allow the user to define the attributes for parent Vin and Producteur to create them, or retrieve them if they exist (retrieval based on user input). For now I do the following in Entree new and edit actions: @entree = Entree.new @entree.vin = Vin.new @entree.vin.producteur = Producteur.new and use fields_for helper in the form,and that works. But I intend to have much more dependencies with more models, so I want to keep it DRY. I defined a after_initialize callback in Vin model which does the producteur initialization: class Vin < ActiveRecord::Base after_initialize :vin_setup def vin_setup producteur = Producteur.new end end and remove the producteur.new from the controller. However, get an error on new action: undefined method `model_name' for NilClass:Class for the line in the form that says <%= fields_for @entree.vin.producteur do |producteur| %> I guess that means the after_initialize callback doesn't act as I expect it. Is there something I'm missing? Also, I get the same error if I define a after_initialize method in the Vin model instead of definiing a callback.

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  • Compare values in serialized column in Doctrine with Query Builder

    - by ReynierPM
    I'm building a FormType for a Symfony2 project but I need some Query Builder on the field since I need to compare some values with the one stored on DB and show the results. This is what I have: .... ->add('servicio', 'entity', array( 'mapped' => false, 'class' => 'ComunBundle:TipoServicio', 'property' => 'nombre', 'required' => true, 'label' => false, 'expanded' => true, 'multiple' => true, 'query_builder' => function (EntityRepository $er) { return $er->createQueryBuilder('ts') ->where('ts.tipo_usuario = (:tipo)') ->setParameter('tipo', 1); } )) .... But tipo_usuario at DB table is stored as serialized text for example: record1: value1 | a:1:{i:0;s:1:"1";} record2: value2 | a:4:{i:0;s:1:"1";i:1;s:1:"2";i:2;s:1:"3";i:3;s:1:"4";} I'll have two different forms (I don't know how to pass the Request to a form) in the first one I'll only show the first record and for the second one the first and second record for example: First form will show: checkbox: value1 Second form will show: checkbox: value1 checkbox: value2 I achieve this? Any help?

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  • ZendX Jquery Decorator

    - by iJD
    How use partial decorator in Jquery Element I use this code for Form Element: $title = new Zend_Form_Element_Text('title'); $title->setRequired(true) ->setAttrib('class', 'inputbox') ->setLabel('Title'); $title->viewScript = 'RegElement.phtml'; $title->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); But when i use Jquery Element i dont know how implement it: $datePicker = new ZendX_JQuery_Form_Element_DatePicker( "datePicker1", array("label" => "Date:") ); $datePicker->viewScript = 'RegElement.phtml'; $datePicker->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); //views/scripts/RegElement.phtml <li class="row <?php echo $this->class ?>"> <div class="cont-error"> <?php echo $this->formErrors($this->element->getMessages()); ?> </div> <div class="rowfields"> <?php echo $this->formLabel($this->element->getName(), $this->element->getLabel()) ?> <?php echo $this->{$this->element->helper}( $this->element->getName(), $this->element->getValue(), $this->element->getAttribs() ) ?> </div> <div class="hint"><?php echo $this->element->getDescription() ?></div> </li> And display this error: Warning: Exception caught by form: Cannot render jQuery form element without at least one decorator implementing the 'ZendX_JQuery_Form_Decorator_UiWidgetElementMarker' interface. I need display datePicker with same format. but idk how implement this interface. thx for your help.

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  • Rails: Can't set or update tag_list using a text field with acts_as_taggable_on

    - by Josh
    Hey everyone, I'm trying to add tagging to a rails photo gallery system I'm working on. It works from the back-end, but if I try to set or change it in the form view, it doesn't work. I added acts_as_taggable to the photo model and did the migrations. My gallery builder is programmed to add one tag automatically to each photo it creates. This works fine, just as if it were setting it for the console. However, I can't seem to set tags using a text_field in the photo form. Here's the code I added to my photo form: <p> <%= f.label :tag_list %><br /> <%= f.text_field :tag_list %> </p> Now, that's pretty trivial, and since :tag_list supports single-string comma-separated assignment (e.g. tag_list = "this, that, the other" #= ['this', 'that', 'the other']), I don't see why using a text field doesn't work. And to make even less sense, if a tag list has already been populated, the list will still show up in the text field when editing the photo. I just can't seem to commit any changes to the list. The documentation on their github page doesn't appear to give any information on how to set these values from the view. Any ideas? Oh, and I'm using the Rails 3 gem version.

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  • jQuery and AJAX?

    - by Moshe
    I'm making a simple form which has 5 input elements for parts of an address. I use jQuery to build and send an AJAX request to a PHP file on my server. For some reason my jQuery is not properly able to read the values from my input elements. What could be wrong? Here is my jQuery: $('#submitButton').click(function(){ $('#BBRequestBox').html('<img src="images/loading.gif" />'); alert('Info: ' + $('#name').val() + ' ' + $('#street').val() + ' ' + $('#city').val() + ' ' + $('#state').val() + ' ' + $('#zip').val() + ' '); $.ajax({ type: "POST", url: "./bbrequest.php", data: {name: $('#name').val(), street: $('#street').val(), city: $('#city').val(), state: $('#state').val(), zip: $('#zip').val() }, success: function(msg){ $('#BBRequestBox').html('<p>' + msg + '</p>'); }, error: function(XMLHttpRequest, textStatus, errorThrown){ $('#BBRequestBox').html('<p> There\'s been an error: ' + errorThrown + '</p>'); } }); return false; }); Here is my HTML: <form action="#"> <label>Name:</label><input type="text" id="name" class="textbox"/> <label>Street:</label><input type="text" id="street" class="textbox" /> <label>City:</label><input type="text" id="city"class="textbox" /> <label>State:</label><input type="text" id="state" class="textbox"/> <label>Zip:</label><input type="text" id="zip" class="textbox" /> <input type="submit" value="Send Me a Bitachon Builder!" id="submitButton" /> </form>

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  • Drupal: How to make a fieldset dependent using CTools

    - by far
    Hello, I am using Ctools Dependency to make a fieldset hideable. This is part of my code: $form['profile-status'] = array( '#type' => 'radios', '#title' => '', '#options' => array( 'new' => t('Create a new profile.'), 'select' => t('Use an existing profile.'), ), ); $form['select'] = array( '#type' => 'select', '#title' => t('Select a profile'), '#options' => $options, '#process' => array('ctools_dependent_process'), '#dependency' => array('radio:profile-status' => array('select')), ); $form['profile-properties'] = array( '#type' => 'fieldset', '#title' => t('View the profile'), '#process' => array('ctools_dependent_process'), '#dependency' => array('radio:profile-status' => array('select')), '#input' => true, ); In snippet above, There are two elements, one select and one fieldset. Both have #process and #dependency parameters and both point to one field for dependent value. Problem is elements like select or textfield can be hidden easily but it does not work for fieldset. In this support request page, CTools creator has mentioned that '#input' = true is a work around. As you see I added it to code, but it does not work as well. Do you have any suggestion?

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  • Excel 2010 VBA code is stuck when UserForm is shown

    - by Denis
    I've created a UserForm as a progress indicator while a web query (using InternetExplorer object) runs in the background. The code gets triggered as shown below. The progress indicator form is called 'Progerss'. Private Sub Worksheet_Change(ByVal Target As Range) If Target.Row = Range("B2").Row And Target.Column = Range("B2").Column Then Progress.Show vbModeless Range("A4:A65535").ClearContents GetWebData (Range("B2").Value) Progress.Hide End If End Sub What I see with this code is that the progress indicator form pops up when cell B2 changes. I also see that the range of cells in column A gets cleared which tells me that the vbModeless is doing what I want. But then, somewhere within the GetWebData() procedure, things get hung up. As soon as I manually destroy the progress indicator form, the GetWebData() routine finishes and I see the correct results. But if I leave the progress indicator visible, things just get stuck indefinitely. The code below shows what GetWebData() is doing. Private Sub GetWebData(ByVal Symbol As String) Dim IE As New InternetExplorer 'IE.Visible = True IE.navigate MyURL Do DoEvents Loop Until IE.readyState = READYSTATE_COMPLETE Dim Doc As HTMLDocument Set Doc = IE.document Dim Rows As IHTMLElementCollection Set Rows = Doc.getElementsByClassName("financialTable").Item(0).all.tags("tr") Dim r As Long r = 0 For Each Row In Rows Sheet1.Range("A4").Offset(r, 0).Value = Row.Children.Item(0).innerText r = r + 1 Next End Sub Any thoughts?

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